(03.06 MC)
How is an emulsion different from a solution?
The components are mixed unevenly instead of evenly within the emulsion.
Insoluble instead of soluble particles are suspended within the emulsion.
Two liquids that normally are not mixable are mixed in the emulsion.
The components of an emulsion are single elements or compounds instead of a
mixture of compounds.

Answer: helium

Explanation:

The noble gas that is not neon and has a mass less than 30 is helium.

A noble gas is a group of chemical elements that are odorless, colorless, and non-reactive under normal conditions. They are located in Group 18 (VIII A) of the periodic table and include helium, neon, argon, krypton, xenon, and radon.

In conclusion, helium is a noble gas that is not neon and has a mass less than 30. It is an important element in science, medicine, and industry, and it has many unique properties that make it useful for a wide range of applications.

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0.00486 g of magnesium will react with an excess of hydrochloric acid to produce 500 mL of H2 (g) at STP.

The ideal gas is the virtual gas that chemists and students dream of because it would be much simpler if there weren't some kind of intermolecular force that would complicate the simple law of the ideal gas. An ideal gas is essentially a point cloud moving with constant random linear motion. Its behavior is described by the assumptions described in the kinetic molecular theory of gases. This ideal gas definition contrasts with the non-ideal gas definition. This is because this equation describes how gases actually behave.

The ideal gas law states that the product of pressure and volume in a gram molecule of an ideal gas is equal to the product of the gas's absolute temperature and the universal gas constant.

PV = nRT

Where, n = number of moles.

P = Pressure (1 atm)

T = Temperature (273 K)

V = Volume (0.5 L)

R = Ideal gas constant (8.314J/K⋅mol)

Now, substitute the values:

1 × 0.5 = n × 8.314 × 273

n = 0.00022 moles

Mg + 2HCl → MgCl₂ + H₂

The mole ratio of Mg and H₂ is 1:1 for the given reaction

Hence the number of moles for Mg will be same as H₂, which is 0.00022 moles.

For the mass of Mg:

m = n × Mm

Where, m = mass

n = number of moles (0.00022 moles)

Mm = molar mass (24.3 g/moles)

m = 0.00486 g

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The organic product formed when 1−hexyne is treated with the H₂O, H₂SO₄ and HgSO₄ is 2 - hexanone.

The reaction of the 1−hexyne is treated with the H₂O, H₂SO₄ and HgSO₄ is given as :

CH₃- CH₂ - CH₂ - CH₂ - C ≡ CH   + H₂O / H₂SO₄ / HgSO₄ ----->

1 - hexyne                                                    CH₃- CH₂ - CH₂ - CH₂ - CO - CH₃  

                                                                                     2 - hexanone

Thus, the when the 1 - hexyne react with the   H₂O, H₂SO₄ and HgSO₄ is 2 - hexanone the product is formed is known as the 2 - hexanone.    the above is the reaction for the formation of 2 - hexanone.

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The values of ΔS for water, the surroundings and the universe for the evaporation of water from an open pan at 25°C are positive, negative and positive respectively.

The process involves conversion of water in the liquid state to water in the gaseous state.

H₂O(l)→H₂O (g)

The entropy of a gas is more than that of the entropy of a liquid. Therefore ΔS of water is positive.

In this process, energy from the surroundings needs to be suppiled in order for the conversion of liquid to gas. So, entropy of surroundings decreases. i.e ΔS of surroundings is negative.

The process is spontaneous which means that it obeys the second law of thermodynamics i.e the increase in entropy of  liquid water is larger than the decrease in entropy of the surroundings. Therefore, ΔS universe is positive.

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A chemical equation is balanced correctly is CH3CH2OH(aq) . The compound is represented by X is CH3CH2OH(aq).

The chemical formula for ethanol, which is an alcohol, is C2H5OH, where C, H, and O stand for carbon, hydrogen, & oxygen atoms, respectively.The colorless, clear liquid ethanol has a similar appearance to water and is totally miscible with it.

You virtually ever consider ethanol, CH3CH2OH, to be acidic because of how weakly basic it is.An ethoxide ion is created when the hydrogen-oxygen link dissociates to release an hydrogen ion:This has almost nothing to recommend it.

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2Li2S + Sn(SO4)2 → 2Li2(SO4) + SnS2 is Balanced chemical equation.

What is Balanced chemical equation?

A balanced chemical equation is a chemical reaction that has equal numbers of moles of chemical substances both in the reactant and the product side.

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides.

In a balanced chemical equation, the mass and the change are both equal.

From the missing image that is attached below, we can see that the picture depicts that we have:

The reactant side:

3 molecules of CH₄ and 3 molecules of N₂Cl₄

The product side:

3 molecules of CCl₄, 3 molecules of N₂ and 6 molecules of H₂

Therefore, the balanced chemical equation for the reaction is:

3CH₄ + 3 N₂Cl₄ → 3 CCl₄ + 3N₂ + 6H₂

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The amount of heat required to convert of water to steam is40.79 kJ/mol. The energy needed to turn 62.6 g of water into steam at 100°C is 141.86 kJ.

The equation is used to represent the formula for determining the necessary quantity of heat; as a result, 141.86 kJ of heat are needed to turn 62.6 g of water into steam at 100°C. Each material has a unique molar heat of vaporization. Kilojoules per mole (kJ/mol) are the units used to measure the molar heat of vaporization. The unit J/g is occasionally employed. In that situation, the term "molar" is dropped in favor of "the heat of vaporization."

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The molar mass of the unknown gas in the 500 mL flask at stp is 89.7 g/mol

We'll begin by calculating the number of mole of the gas that occupied 500 mL at stp.

Recall at stp:

22400 mL = 1 mole of the gas

Therefore,

500 mL = 500 / 22400 = 0.0223 mole of gas.

Finally, we shall determine the molar mass of the gas. This can be obtained as follow:

Mass of gas = 2 g

mole of gas = 0.0223 mole

Molar mass of gas =?

Molar mass = mass / mole

Molar mass of gas = 2 / 0.0223

Molar mass of gas = 89.7 g/mol

Therefore, the molar mass of the unknown gas is 89.7 g/mol

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Friction provides the traction you need to walk without slipping. Friction helps in most cases. However, they also offer great resistance to applications. Additionally, about 20% of a car's engine power is used to overcome the frictional forces of moving parts. Let's take a look at some of these factors in the next section. All four types of friction are different from each other. Static friction, for example, is the friction that acts between surfaces when they are at rest against each other. In contrast, sliding friction is the resistance that occurs when two bodies slide over each other.

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To solve such this we must know the concept of chemical reaction. Therefore, the rate of reaction increases as the concentration of HCl increases.

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

The rate of reaction depends on the number of collisions among the reactants and their orientation. As the number of concentration of reactants  increases, the number of collisions increases and the rate of reaction also increases.

Therefore, the rate of reaction increases as the concentration of HCl increases.

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The manganese content of the original sample is approximately 5.09%.

To determine the manganese content of the original sample, we need to know the atomic weight of manganese and the molecular weights of manganese(III) nitrate and manganese(III) sulfide.

Manganese has an atomic weight of 54.94 g/mol.

Manganese (III) nitrate has a molecular weight of 158.03 g/mol Manganese (III) sulfide has a molecular weight of 160.13 g/mol

The first step is to calculate the weight of manganese in manganese(III) nitrate.

0.2876 g manganese (III) sulfide ÷ 160.13 g/mol manganese (III) sulfide = 0.0018 g manganese

The manganese weight of the original sample can then be determined from the manganese weight of manganese(III) sulfide.

0.0018 g manganese ÷ 0.2876 g manganese (III) sulfide = 0.0626 g manganese per 1.2354 g sample

Finally, the weight of manganese in the sample can be used to calculate the percentage of manganese in the sample.

(0.0626 g manganese ÷ 1.2354 g sample) × 100% = 5.09% manganese

Therefore, the manganese content of the original sample is approximately 5.09%.

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Answer:

ionic

Explanation:

Since Ca is a metal and O is a non-metal, the bond is ionic.

0.034 mol of carbon dioxide gas, are there in 0.667 L.

We can assume that the volume of one mole of any gas is 22.4 L we know that the pressure of the gas is 1 atmosphere and that the temperature of a gas is 0C

This type is called standard temperature and pressure (STP).

This can be calculated by using the formula in which we can find the moles:

PV =nRT------(1)

Where P is the pressure

V is volume

T is the temperature in Kelvin

R is the ideal gas constant consistent with the units of volume and pressure.

0.667 L x 1 mol/22.4 L = 0.034 mol

And 0.667 liters of CO2 or any other gas at STP would contain 0.034 moles.

If the gas was at some other temperature or pressure, assuming they were “moderate,” you could calculate the number of moles by solving the following formula for n.

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The balanced chemical equation for the combustion of C4H10 is C4H10 + 6O2 → 4CO2 + 5H2O.

So,

The moles of C4H10 consumed in the reaction is 42.62 g / (58.12 g/mol) = 0.732 mol.

The moles of CO2 produced in the reaction is 87.85 g / (44.01 g/mol) = 1.99 mol.

The percent yield of the reaction is (1.99 mol CO2 / 0.732 mol C4H10) x 100% = 271.7%.

Define Combustion?

Combustion is a chemical reaction between a fuel and an oxidizer where heat and light energy is released. It is also referred to as burning. In the case of fossil fuels, the fuel is mainly hydrocarbons and the oxidizer is the oxygen in the air. The reaction is exothermic and produces water, carbon dioxide, and other byproducts.

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The end point in a titration of a 25.00 mL aq H₂SO₄ was reached by addition of 33. 87 ml of 0.4500 m NaOH. The molarity of H₂SO₄ is 0.3048 M.

The balanced chemical reaction is given as,

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

For exact neutralization of Va(mL) of an acid having Molarity Mₐ and basicity Nₐ by V(b) ml of a base having molarity M(b) and acidity N(b).

N(a) M(a) V(a) = N(b) M(b) V(b)

For H₂SOy basicity ,n(a) = 2

For NaOH acidity n(b) = 1

Va (H₂SO₄) = 25.00 mL

Vb (NaOH) = 37.87 mL

Mb (NaOH) = 0.4500M 

Ma (H2S04) = ?

Substitute the values to get the value of Ma,

2 × Ma × 25 mL = 1 × 0.4500 M × 33.87 mL

⇒ Ma = (1 × 0.4500 M × 33.87 mL) ÷ 50

⇒ Ma = 0.3048 M

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Therefore, if you utilise water, you must have a barometer that is 13.534 times the length of a mercury barometer, which may be longer than 11 metres.

Additionally, mercury can reach the same temperature of the atmosphere more quickly than water since it has a lower specific heat than water and is a better heat conductor.

What is Barometer?

Barometer, a tool for calculating atmospheric pressure. A barometer can also be used to determine height because air pressure varies with elevation above or below sea level. Mercury and aneroid barometers are the two primary varieties.

A mercury column whose height can be precisely measured is balanced by atmospheric pressure in a mercury barometer. Mercury barometers are frequently adjusted for the local gravity value and the surrounding temperature in order to boost their accuracy.

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Answer:

This is ez 123 me no eleglesh

Explanation:bn

The final volume is 15.3 mL,  the concentration of solution ,He will accomplish this by gradually adding distilled water to the mixture according to law of equivalence-until it reaches a particular final volume.

According to law of equivalence-

where  is initial concentration,  is the final concentration,  is the initial volume and  is the final volume.

Here  = 7.27 M,  = 12.6 mL,  = 6.00 M

So, the final volume is 15.3 mL

The law of equivalence , equivalents of one material will always be equal to the equivalents of the other when two substances react, and the equivalents concentration of any product will always be equal to that of the concentration.

The complete question is:

A chemist must dilute 12.6mL of 7.27 M aqueous sodium nitrate (NaNO3) solution until the concentration falls to 6.00 M.He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Be sure your answer has the correct number of significant digits.

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The mass per cent of Zn in the mixture is 22%.

Mass percent is a means to describe a component in a specific combination or to convey a concentration. The mass percentage used to describe the solution composition indicates the mass of solute contained in a given mass of solution. The solute's concentration is specified in terms of mass or moles. The mass percent of a solution is calculated by multiplying the grams of solute per gram of solution by 100 to get the percentage.

mass of the mixture = 3.0 g

moles of ZnO in the mixture = 0.010 mol

mass of ZnO in the mixture =  moles × molar mass

= 0.010 mol × 81.38 g/mol

= 0.8138 g

now mass percent of ZnO in the mixture = mass of (ZnO/Total mass) × 100.

27%

now, 81.38 g of ZnO contains = 65.38 g of Zinc.

0.8138 g of ZnO contains = (65.38 / 81.38) × 0.813 g

= 0.6538 g.

so, mass % of Zn in the mixture = (Mass of Zn/ Total Mass) × 100

                                                    = (0.6538 g /3 g) × 100

                                                    = 22%

Hence, the mass percent of Zn in the mixture is 22%.

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Answer: To determine the volume of 1.60 x 10^-3 M HCl that is needed to neutralize 14.5 mL of a saturated Ca(OH)2 solution, we can first calculate the number of moles of Ca(OH)2 that are present in the solution. We can do this by using the solubility of Ca(OH)2 in water (0.185 g/100.0 mL) and the volume of the solution (14.5 mL):

0.185 g Ca(OH)2 / 100.0 mL * 14.5 mL = 0.026975 g Ca(OH)2

Next, we can use the molar mass of Ca(OH)2 (74.1 g/mol) to convert the mass of Ca(OH)2 to moles:

0.026975 g Ca(OH)2 / 74.1 g/mol = 0.003634 mol Ca(OH)2

Since the reaction between HCl and Ca(OH)2 is a 1:1 mole ratio, we can then determine the number of moles of HCl that are needed to neutralize the Ca(OH)2 by dividing the number of moles of Ca(OH)2 by 1:

0.003634 mol Ca(OH)2 / 1 = 0.003634 mol HCl

Finally, we can use the concentration of the HCl solution (1.60 x 10^-3 M) and the number of moles of HCl that are needed to determine the volume of HCl that is required:

0.003634 mol HCl / (1.60 x 10^-3 M) = 0.0230 L HCl

Therefore, 0.0230 L (or 23.0 mL) of 1.60 x 10^-3 M HCl is needed to neutralize 14.5 mL of a saturated Ca(OH)2 solution.

According to the ideal gas law, the relationship between the pressure, volume, and temperature of a gas is given by the equation PV = nRT, where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas in Kelvin.

If we have 2.9 L of gas at a pressure of 5.0 atm and a temperature of 50.0 °C, we can calculate the temperature of the gas if we decrease the volume of the gas to 2.4 and decrease the pressure to 3.0 atm by rearranging the ideal gas law equation as follows:

T = (PV) / (nR)

In this equation, T represents the temperature of the gas, P represents the pressure of the gas, V represents the volume of the gas, n represents the number of moles of gas, and R represents the ideal gas constant.

Plugging in the values from the problem into the equation, we get:

T = (5.0 atm * 2.9 L) / (n * 0.08206 L*atm / mol*K)

T = (14.5 L*atm) / (n * 0.08206 L*atm / mol*K)

T = (14.5 L*atm) / (n * 0.08206 L*atm / mol*K)

T = 177.2 K

Therefore, if we have 2.9 L of gas at a pressure of 5.0 atm and a temperature of 50.0 °C, and we decrease the volume of the gas to 2.4 and decrease the pressure to 3.0 atm, the temperature of the gas will be 177.2 K.

if your isolated product has succinimide present, the key feature should be present in the ir spectrum of your product is in the IR spectra should show a prominent peak at around 1700 cm⁻¹,

These chemicals have several uses. The succinimides ethosuximide, phensuximide, and methosuximide are among the drugs used as anticonvulsants. Succinimide is also used in various assays to create covalent bonds between peptide or protein chains and polymers.

Succinimide inhibits voltage-dependent calcium leakage in thalamic neurons by acting on calcium T channels. Any gastrointestinal "vomiting, nausea, or abdominal discomfort." or central nervous system are side effects of ethosuximide (lethargy, dizziness, ataxia).

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In de Morceau's nomenclature scheme, the smaller atom appears first.

Nomenclature is an organism name system used in biological classification. Genus and species names, two Latinized nouns drawn from numerous sources, serve as indicators of the species to which the creature belongs.

On August 26, 1743, Antoine-Laurent Lavoisier was born in Paris, France. He was a well-known French chemist and a key player in the 18th century chemical revolution. In addition to co-creating the current system for identifying chemical compounds, he established an experiment-based explanation of the chemical reactivity of oxygen.

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Answer:

water

Explanation:

The energy that is contained in the candies is 7.2 cal/g.

We know that the calorimeter is a device that can be used to measure the amount of energy that is contained in a substance. We can see that in this case, we have ben told that the the observed temperature increase is 2.62 ∘C. If the heat capacity of the calorimeter is 48.10 kJ⋅K−1.

We now have the heat or the energy that is contained in the candy as;

H = cdT

c = heat capacity of the calorimeter

dT = The temperature change

Hence;

H = 48.10 kJ⋅K−1 *  2.62 ∘C

H = 126 kJ or 30.11 cal

The nutritional Calories are there per gram of the candy;

30.11 cal/4.20 g

= 7.2 cal/g

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Answer:-Science have researched more facts and cool things about it-It would have more facts and things to learn-The quality would be better and more understandingI just tried 3 quick ideas I hope it can help a bit

Explanation:

Answer:

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The density of the balls, given the masses and volume of each balls did not change

To Know if there is a change or not, we shall determine the density of both lead balls. Details below:

For the small ball

Density = mass / volume

Density of small ball = 1017 / 90

Density of small ball = 11.3 g/cm³

For the larger ball

Density = mass / volume

Density of larger ball = 2825 / 250

Density of larger ball = 11.3 g/cm³

From the above calculations, we obtained:

Thus, we can conclude that the density of the lead balls did not change

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The catalytic cofactors of the pyruvate dehydrogenase complex are TPP, lipoic acid, and flavin adenine dinucleotide (FAD).

What is lipoic acid?

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The nuclear charge for Ze is 3e and effective nuclear charge is 1.26e  and for the quantum number is 2.

What is ionization energy for an atom?

The ionisation energy is a metric indicating an element's capacity to engage in chemical processes that call for the donation of electrons or the production of ions. It is also often correlated with the type of chemical bonding that occurs when elements combine to form compounds.

I= 13.1×10²Z (eff)/n²

Zeff = √I×n²/13.1ₓ10²

for lithium I = 520.2

Z²eff = 520.2×4/13.1×10²=1.56

Zeff= 1.26 e

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