0.450 moles of oxygen gas is subjected to a pressure of 3.00 atm and 75 oC.
What is it's volume (in Liters)?

Answers

Answer 1

Use this formula PV=nRT

Rearrange formula , question want V ,so

V=nRT/P

given

P= 3.00 atm

n=0.450 moles

R is ideal gas constant = 0.08206 L atm mol-¹K-¹

T in Kelvin so , (75 + 273)= 348 Kelvin (K)

Then insert all this information given with that rearranged formula V=nRT/P

so, V= (0.45)(0.08206)(348) / 3.00 = 4.284 L

Related Questions

What element needs just a single extra electron to have the same electron configuration as helium?​

Answers

Answer:

Hydrogen

Explanation:

Helium has an atomic number Z = 2, that is, it has 2 protons. Since it is electrically neutral it also has 2 electrons. Thus, the electron configuration of helium is 1s².

Hydrogen has an atomic number Z = 1, that is, it has 1 proton. Since it is electrically neutral it also has 1 electron. Thus, the electron configuration of hydrogen is 1s¹.

If hydrogen gains a single extra electron to form H¹⁻, it acquires the same electron configuration than helium.

HELP 20 POINTS

What is the frequency of an Electromagnetic wave has with wavelength 2.94 x 10^-8 cm?

Answers

The answer is 30.84

g In this equation stands for the Rydberg energy, and stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron from an orbital with to an orbital with . Round your answer to significant digits.

Answers

The complete question is attached to this answer

Answer:

2.75 * 10^-5 m

Explanation:

The energy of the absorbed photon = ΔE

ΔE = - Ry (1/n^2 final - 1/n^2initial)

Given that Ry = 2.18 *10^-18 J

nfinal = 9

ninitial =8

ΔE = - 2.18 *10^-18 (1/9^2- 1/8^2)

ΔE = - 2.18 *10^-18 (0.0123 - 0.0156)

ΔE = 7.194 * 10^-21 J

But

ΔE =hc/λ

h = 6.6 *10^-34Js

c= 3 * 10^8 ms-1

λ= the unknown

λ= hc/ΔE

λ= 6.6 *10^-34 * 3 * 10^8/ 7.194 * 10^-21

λ= 2.75 * 10^-5 m

Which type of energy is the tree changing the light energy into?

Answers

Answer: Chemical energy

Explanation: In this case plants convert light energy (1) into chemical energy, (in molecular bonds), through a process known as photosynthesis. Most of this energy is stored in compounds called carbohydrates. The plants convert a tiny amount of the light they receive into food energy.

Answer:

chemical energy

In this case plants convert light energy into chemical energy, (in molecular bonds), through a process known as photosynthesis. Most of this energy is stored in compounds called carbohydrates. The plants convert a tiny amount of the light they receive into food energy.

Explanation:

A radical is a reactive intermediate with a single ____________ electron, formed by ____________ of a covalent bond. Allylic radicals are stabilized by ____________ , making them ____________ stable than tertiary radicals. A compound that contains an especially weak bond that serves as a source of radicals is called a radical ____________ . Treatment of cyclohexene with N-bromosuccinimide in the presence of light leads to ____________ by ____________ intermediates.

Answers

1. A radical is a reactive intermediate with a single ____________ electron, formed by ____________ of a covalent bond.

1. A: Unpaired, and homolysis

2. Allylic radicals are stabilized by ____________ , making them ____________ stable than tertiary radicals.

2. A: Resonance, and more

3. A compound that contains an especially weak bond that serves as a source of radicals is called a radical ____________ .

3. A: Initiator

4. Treatment of cyclohexene with N-bromosuccinimide in the presence of light leads to ____________ by ____________ intermediates.

4. A: Allylic substitution by radical

Are these synthesis decomposition single replacement or double replacement?

Answers

Answer:

1. Synthesis

2. Decomposition

3. Single replacement

4. Synthesis

5. Decomposition

6. Synthesis

Explanation:

Kind of a hard picture to look at but let me define each chemical reaction:

Synthesis:

a + b ---> ab   In synthesis elements/compounds come together to form new                compounds

Decomposition:

ab ---> a + b   In decomposition a compound breaks down to form 2 elements/compounds

Single replacement:

a + bc ---> b + ac   In a single replacement one element/compound takes the place of another element/compound.

Double replacement

ab + cd ---> ad + bc In a double replacement 2 compounds exchange different elements/compounds.

Now, let's go through the assignment

1. P + O2 --> P4O10  This is a synthesis reaction because the two elements (P and O) came together to form one compound.

2. HgO ---> Hg + O2  This is a decomposition reaction because HgO broke into separate elements Hg and O.

3. Cl2 + NaBr ---> NaCl + Br2  This is a single replacement reaction because chlorine (Cl) replaced the spot of bromine (Br) to bond with sodium (Na).

4.  Mg + O2 ---> MgO  This is a synthesis reaction because two elements (Mg and O) came together to form one compound.

5. Al2O3 ---> Al + O2  This is a decomposition reactions because Al2O3 broke into separate elements Al and O.

6. H2 + N2 ---> NH3  This is a synthesis reaction because two elements (H and N) came together to form one compound.

I hope this helps!!

- Kay :)

Given chemical equations are of  following types which are given in serial order as synthesis,decomposition,replacement,synthesis,decomposition and synthesis reactions respectively.

1. It is a synthesis reaction because the two elements (P and O) came together to form one compound.

2. It is a decomposition reaction because HgO broke into separate elements Hg and O.

3. It is a single replacement reaction because chlorine (Cl) replaced the spot of bromine (Br) to bond with sodium (Na).

4.  It is a synthesis reaction because two elements (Mg and O) came together to form one compound.

5. It is a decomposition reactions because aluminium oxide broke into separate elements Al and O.

6. It is a synthesis reaction because two elements (H and N) came together to form one compound.

Learn more about chemical equation,here:

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#SPJ4

True or False: Most metals are found to occur naturally in their uncombined states.

Answers

Answer:

I think it's true. But I'm not sure

Answer:

True

Explanation:

What statement is not true about the field of science

Answers

Answer:

where are the statements?

Explanation:

the formula of calcium oxide is CaO. What is the formula of the ionic compound containing calium abd sulfate ions

Answers

Answer:

[tex]CaS[/tex]

Explanation:

Hello!

In this case, since calcium's oxidation state when forming ionic bonds is +2 and sulfur's oxidation state when bonding those bonds is -2, for the required formula we write:

[tex]Ca^{2+}S^{2-}[/tex]

Now, since they have the same charge number, we infer the ionic compound formed when they bond is calcium sulfide:

[tex]CaS[/tex]

Best regards!

PLEASE HELP WILL GIVE BRAINLIEST

Answers

Answer:

Coefficients represents no of moles while subscripts represent no of atoms.

Answer:

Coefficients came before formula . Example = 4CO means there are 4 molecules of carbonmonooxide.

Subscripts came after and below the formula . Example = Oxygen gas in which 2 is a subscript which means there are 2 atoms of Oxygen in 1 molecule of Oxygen i.e. oxygen gas

1
MS-LS1-1, MS-LS1-2
Structure and
Function of Cells
-, -
1. Which of the following is not stated in the cell
theory?
A. Cells are the basic unit of structure and
function in all living things.
B. Animal cells are generally more complex
than plant cells.
C. All living things are composed of cells.
D. All cells are produced from other cells.
Ok

Answers

Number b, because nothing mentions that:))

If a system's internal energy increases by 250 kJ after the addition of375 kJ of energy as heat, what was the value ofthe work in the process?
(A) -625 kJ
(B) -125 kJ
(C) 125 kJ
(D) 625 kJ

Answers

Answer:

(B) -125 kJ

Explanation:

Going by the First Law of Thermodynamics it states that"

"A system can do work and increase it's internal energy provided we supply heat."

ΔU= q+w-----------1

where U= the internal heat

           q= the quantity of heat added or removed from the system

            w= the work done

Given

ΔU= 250kJ

q= 375kJ

from equation 1 make w subject of the formula we have

w= ΔU-q

w= 250-350

w= -125kJ

A certain reaction requires 0.250 moles of Na2SO4. How
much sodium sulfate should the chemist weigh out to perform
the reaction?

Answers

The chemist weigh out 35.51 g Na2SO4

Further explanation

Given

0.250 moles of Na2SO4

Required

weight of Na2SO4

Solution

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

Moles of a substance can also be determined from its molecular weight

[tex]\tt mol=\dfrac{mass}{MW}[/tex]

For 0.250 moles of Na2SO4, mass =

[tex]\tt mass=mol\times MW\\\\mass=0.25\times 142,04 g/mol\\\\mass=35.51~g[/tex]

A saturated hydrocarbon having molecular formula CnH2n+2 diffuses through a porous membrane twice as fast as sulphur dioxide. Calculate the volume occupied by the hydrocarbon at27°C and 2atm ?
Help me fast !​

Answers

Answer:

12.3 L

Explanation:

Now we have that the rate of diffusion of the saturated hydrocarbon is R1

Rate of diffusion of sulphur dioxide is R2

Molar mass of hydrocarbon is M1

Molar mass of sulphur dioxide is 64 gmol-1

From Graham's law;

R1/R2 = √64/M1

2/1 =√64/M1

(2/1)^2 = (√64/M1)^2

4/1 = 64/M1

4M1 =64

M1 = 16

To obtain the number of moles of the gas;

(n*12) + (2n + 2) 1 = 16

12n + 2n + 2 = 16

14n + 2 = 16

14n = 16 - 2

n = 14/14

n = 1

Hence the hydrocarbon is CH4

Volume occupied by CH4 at STP = 22.4 L

Hence;

P1 = 1 atm

T1 = 273 K

V1 = 22.4 L

T2 = 300 K

P2 = 2 atm

V2 = ?

P1V1/T1 = P2V2/T2

P1V1T2 = P2V2T1

V2 = P1V1T2/P2T1

V2 = 1 * 22.4 * 300/2 * 273

V2 = 12.3 L

The volume occupied by the hydrocarbon at 27 °C and 2 atm is 12.31 L

Let the hydrocarbon be initially at standard temperature and pressure (STP)

Thus, we can obtain the new volume of the hydrocarbon by using the combined gas equation as illustrated below:

Initial volume (V₁) = STP = 22.4 L Initial pressure (P₁) = STP = 1 atmInitial temperature (T₁) = STP = 273 KFinal temperature (T₂) = 27 °C = 27 + 273 = 300 KFinal pressure (P₂) = 2 atmFinal volume (V₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

(1 × 22.4) / 273 = (2 × V₂) / 300

22.4 / 273 = (2 × V₂) / 300

Cross multiply

273 × 2 × V₂ = 22.4 × 300

546 × V₂ = 6720

Divide both side by 546

V₂ = 6720 / 546

V₂ = 12.31 L

Thus, the volume occupied by the hydrocarbon at 27 °C and 2 atm is 12.31 L

Learn more about gas laws:

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What type of reaction occurs between an element and a compound?

Answers

Answer:

exothermic reaction

Explanation:

because it occurs in the presence of heat

you weigh out 43.9 g of potassium (K). How many moles of potassium did you weigh? How many atoms?

Answers

Answer:

1.12 moles of potassium

6.76x10²³ atoms of potassium

Explanation:

In order to convert g of potassium to moles, we need to use its molar mass (which we can find via the periodic table):

Molar Mass of K = 39.09 g/mol43.9 g K ÷ 39.09 g/mol = 1.12 mol K

Then, to convert moles into atoms, we use Avogadro's number (6.023x10²³ atoms per mole):

1.12 mol K * 6.023x10²³[tex]\frac{atoms}{mol}[/tex] = 6.76x10²³ K atoms

A precipitate of lead chloride is formed when silver chloride is dissolved in a saturated solution of lead chloride due to g

Answers

Answer:

Due to "Common ion effect".

Explanation:

Lead chloride and Silver chloride have an ion in common which is Cl-, when these two solutions are dissolved, more chloride reacts with lead which shifts equilibrium position to the right hence precipitating out.

What's the enthalpy of neutralization and explain briefly how it relates to esterification​

Answers

Answer:

The enthalpy of neutralization and its relation to esterification​ is explained below in details.

Explanation:

The conventional enthalpy variation of neutralization is the enthalpy exchange when extracts of an acid and an alkali respond together under conventional circumstances to generate 1 mole of water. Remark that the enthalpy change of neutralization is always estimated per mole of water produced.

28. After 3 substances are mixed, an odor emits
a. chemical change
b. physical change
c. thermal energy is used
a do​

Answers

Answer:

a. chemical change

Explanation:

A chemical change can cause an odor, however a physical change cannot, and the use of thermal energy will only make an object colder, not give it an odor.

Which of the physical processes below result in the formation of metamorphic rocks

Answers

i dont see any processes below

Answer:

Heat and pressure

Explanation:

got it on study island

Help me as soon as possible I’m gonna dieeee

Answers

I think it’s D I’m not sure .........
I think it’s Boiling point but I’m not sure

Which part of the immune system can be "trained" using vaccines?

Answers

The adaptive immune system, because it is more specific to the foreign substances in the body and adapts to remove or fight them

In a double replacement reaction, the ions of two compounds exchange places in an aqueous solution to form two new compounds.

True

False

Answers

Answer:

true

Explanation:

Answer:

True

Explanation:

In a displacement reaction, more reactive element displaces less reactive element. Whereas in a double displacement reaction there is exchange of ions of two compounds.

. Bob plants some seeds in a small cup. He puts the cup in the light and waters the soil every day. After 4 days, the seedlings emerge from the soil. What can Bob conclude?

answers in the picture I HAVE TO TURN IN THIS AT 10:30 PLEASE HELP ME OUT

Answers

Answer: the first option is correct

Why: the seed is the one doing all the work and no other forces were mentioned after 4 days

The seedlings exerted an upward pushing force on the soil explains why the

seeds emerged from the soil.

Bob watered the soil in which the seed absorbs the water through the coat ,

the seed coat and embryo begins to enlarge and emerge from the soil.

The hydrated enzymes become active thereby increasing metabolic

activities and energy production which is needed for the growth of the plant.

The energy helps the seed exert an upward force on the soil.

Read more on https://brainly.com/question/2515369

Which of the following is NOT a property of sodium


1. Sodium is a reactive METAL


2. Sodium is very SOFT


3. Sodium is a reactive GAS


4. Sodium forms a WHITE coating

Answers

Answer:

3

Explanation:

Sodium is not a gas, it is a Alkali Metal. I recommend studying the sections of the periodic table to help remember what each element should be.

Hope this helps.

Will give brainliest

Answers

I will help you with answering this question.

Complete the statement of equality.

Answers

Answer:

This is not a viable question.

Explanation:

Which force keeps the planets from floating off into space?

Earth’s gravity
the Sun’s gravity
the moon’s gravity
Milky Way’s gravity

Answers

Answer:

Suns gravity

Explanation:

Answer: 2021

B

The Sun's gravity

Explanation: Just took the big test

How many grams are in 2.3 x 1024 formula units of KNO3?

Answers

Answer:

390 g KNO₃

General Formulas and Concepts:Chemistry

Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right Explanation:

Step 1: Define

2.3 × 10²⁴ formula units KNO₃

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g.mol

Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol

Step 3: Convert

[tex]2.3 \cdot 10^{24} \ formula \ units \ KNO_3(\frac{1 \ mol \ KNO_3}{6.022 \cdot 10^{23} \ formula \ units \ KNO_3} )(\frac{101.11 \ g \ KNO_3}{1 \ mol \ KNO_3} )[/tex] = 386.172 g KNO₃

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

386.172 g KNO₃ ≈ 390 g KNO₃

The pressure of a sample of argon gas was increased from 3.89 atm to 8.73 atm at constant temperature. If the final volume of the argon sample was 18.4 L, what was the initial volume of the argon sample? Assume ideal behavior.

Answers

Answer:

41.29 L

Explanation:

The initial volume can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the initial volume

[tex]V_1 = \frac{P_2V_2}{P_1} \\[/tex]

From the question we have

[tex]V_1 = \frac{8.73 \times 18.4}{3.89} = \frac{160.632}{3.89} \\ = 41.293573...[/tex]

We have the final answer as

41.29 L

Hope this helps you

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