Answer:
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s
Explanation:
The given parameters are;
The curvature of the hill, r = 200 m
Due to the velocity, v, the occupants weight = 20% less than the normal weight
The outward force of an object due to centripetal (motion) force is given by the following equation;
[tex]F_c = \dfrac{m \times v^2}{r}[/tex]
Where;
r = The radius of curvature of the hill = 200 m
Given that the weight of the occupants, W = m × g, we have;
[tex]F_c = 0.2 \times W = 0.2 \times m \times g[/tex]
[tex]\therefore 0.2 \times m \times g = \dfrac{m \times v^2}{r}[/tex]
v = √(0.2 × g × r)
By substitution, we have;
v = √(0.2 × 9.81 × 200) ≈ 19.81
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.
The velocity is 19.81 m/sec at which the occupants of the car appear to weigh 20% less than their normal weight and this can be determined by using the formula of centripetal force.
Given :
A car is going over the top of a hill whose curvature approximates a circle of radius 200 m.
The centripetal force acting on the car is given by the formula:
[tex]\rm F_c = \dfrac{mv^2}{r}[/tex] ---- (1)
where m is the mass of a car, v is the velocity of the car and r is the radius of curvature.
Now, it is given that the occupants of the car appear to weigh 20% less than their normal weight that means:
[tex]\rm F_c = 0.2\times W[/tex]
[tex]\rm F_c = 0.2 \times m \times g[/tex] --- (2)
Now, equate equation (1) with equation (2).
[tex]\rm \dfrac{mv^2}{r}=0.2\times m \times g}{}[/tex]
[tex]\rm v = \sqrt{0.2\times g \times r }[/tex]
[tex]\rm v = \sqrt{0.2\times 9.81 \times 200 }[/tex]
v = 19.81 m/sec
The velocity is 19.81 m/sec at which the occupants of the car appear to weigh 20% less than their normal weight.
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2. Heavier football players tend to play on the front line. Why?
What law is it?
Answer: They are put in front for defense so so they can block the opponents from getting the ball
Explanation:
Answer:
Heavier football players are usually on the front line because they have a low point in gravity therefore they are able to block the back running players in a better way. And its Newton's second law.
Explanation:
The photograph shows matter going through a physical change. Which characteristic of the matter changes?
A. shape.
B. shininess.
C. state.
D. type of atoms
Answer:
Possibly shape.
Explanation:
Because it is ripped in half. As you guys and the questioner can see that there is a wiggly strip down the middle. That also cause of a shape change.
I really hope my answer is right ^_^
The characteristic of matter which is undergoing change in the picture is it's shape as it is being teared apart.
What is matter?Matter in chemistry, is defined as any kind of substance that has mass and occupies space that means it has volume .Matter is composed up of atoms which may or not be of same type.
Atoms are further made up of sub atomic particles which are the protons ,neutrons and the electrons .The matter can exist in various states such as solids, liquids and gases depending on the conditions of temperature and pressure.
The states of matter are inter convertible into each other by changing the parameters of temperature and pressure.Matter possesses both particle and wave characteristics.Phase is a form of matter having uniform composition as well as physical properties.
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Why do women typically tend to have slightly greater stability than men?
A.
Women are shorter than men, and shorter people are more stable.
B.
Men have more muscle mass in their lower bodies that makes them stiff and less stable.
C.
Women have lower centers of gravity, and lower centers of gravity provide more stability.
D.
The increased muscle mass in their upper bodies makes their centers of gravity difficult to find.
Please select the best answer from the choices provided.
A
B
C
D
Answer:
C
Explanation:
I figured it sounded more accurate
Which one hits the ground first, a
bullet dropped from a height, or a
bullet fired simultaneously from
the same height?
Answer:
A bullet fired simultaneously from the same height
Explanation:
It will reach the ground first because a greater force is being acted upon it. The first option is only acted on by gravity
A car is traveling with 90km/hr and another car with 20m/s in opposite direction. Calculate the relative velocity.
Answer:
Vba = -20 m/s - 25 m/s = -45 m/s
Vab = 25 m/s + 20 m/s = 45 m/s
Explanation:
Relative Velocity
The relative velocity of object B with respect to object A (Vba) measures the velocity of B in the rest frame of object A.
It's calculated as:
Vba = Vb - Va
The velocity of car B is Vb=-20 m/s and the velocity of car A is Va=90 Km/h.
Converting Va to m/s:
Va = 90 Km/h * 1000/3600 = 25 m/s
Thus, the relative velocity of B with respect to A is:
Vba = -20 m/s - 25 m/s = -45 m/s
And the relative velocity of A with respect to B is:
Vab = 25 m/s + 20 m/s = 45 m/s
A projectile is fired into the air. Three characteristics of its subsequent motion are
1) the horizontal component of velocity
II) the vertical component of velocity
III) the acceleration
Neglecting air resistance, which characteristic(s) change(s) whilst the projectile is in the air.
(1 Point)
I only
Il only
II and III only
I and II only
Answer:
The answer is C) II and III only
Explanation:
True or False? Will mark Brainlest
Answer:
False
Explanation:
They had no free oxygen though they has oceans forming and it was very hot and today is much different hope that helps!
If the same total travel at the speed of 0.05 m/s for 40 seconds, how far would it have gone?
Answer:
Would've traveled 2 miles.
Explanation:
Which of the following is most likely to be a conductor?
OA. Aplastic
OB. A molecule containing only nonmetal atoms
OC. A covalently bonded molecule
D. Acompound containing metallic bonds
Answer:
D.
Explanation:
A compound containing metallic bonds
hope it helps!
Beth moves a 15 N book 20 meters in 10 seconds. How much power was produced?
Answer:
30 Watts
Explanation:
Power = Work/Time
Work = Force*Distance
Power = Force * Distance / Time
Power = 15 N * 20 meters / 10 sec
Power = 30 Watts
what is the velocity for an object at rest?
Answer:
e
Explanation:
An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force.
Answer:
If an object is at rest, it has no velocity - its velocity is zero. More precisely, since velocity is a vector, in this case the velocity would be the null vector.
Explanation: Hope this helps
A go-cart and rider have a mass of 14 kg. If the cart accelerates at 6m/s^2 during a 40 m sprint in 100 seconds, how much power did the cart do? MUST SHOW ALL WORK!!!!!!!!!
Answer:
P = 33.6 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
F = forces [N]
m = mass = 14 [kg]
a = acceleration = 6 [m/s²]
[tex]F = 14*6\\F = 84 [N][/tex]
In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.
[tex]W = F*d[/tex]
where:
W = work [J]
F = force = 84 [N]
d = displaciment = 40 [m]
[tex]W = 84*40\\W = 3360 [J][/tex]
Finally, the power can be calculated by the relationship between the work performed in a given time interval.
[tex]P=W/t\\[/tex]
where:
P = power [W]
W = work = 3360 [J]
t = time = 100 [s]
Now replacing:
[tex]P=3360/100\\P=33.6[W][/tex]
The power is given in watts
n Olympic diver is on a diving platform 3.60 m above the water. To start her dive, she runs off of the platform with a speed of 1.3 m/s in the horizontal direction. What is the diver's speed, in m/s, just before she enters the water
Answer:
8.5m/s
Explanation:
Using the equation of motion
v² = u² + 2gH
v is the final speed of the diver
u is the initial speed of the diver
g is the acceleration due to gravity
H is the height of the object
Given the following
V = 1.3m/s
H = 3.60m
g = 9.8m/s²
Required
Initial speed of the diver u
Substitute the given values into the formula:
v² = u² -2gH
1.3² = u² - 2(9.8)(3.60)
1.69 = u²-70.56
u² = 1.69+70.56
u² = 72.25
u = √72.25
u = 8.5m/s
Hence the diver's speed, in m/s, just before she enters the water is 8.5m/s
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 41.5-gram mass is attached at the 28.5-cm mark, the fulcrum must be moved to the 39.2-cm mark for balance. What is the mass of the meter stick
Answer:
The value is [tex]M = 42.3 \ kg[/tex]
Explanation:
From the question we are told that
The first position of the fulcrum is x = 49.7 cm
The mass attached is [tex]m = 41.5 \ g[/tex]
The position of the attachment is [tex]x_1 = 28.5 \ cm[/tex]
The second position of the fulcrum is [tex]x_2 = 39.2 \ cm[/tex]
Generally the sum of clockwise torque = sum of anti - clockwise torque
So
[tex]CWT = m (x_2 - x_1)[/tex]
Here CWT stands for clockwise torque
[tex]ACWT = M ( x - x_2)[/tex]
So
[tex]m (x_2 - x_1) = M ( x - x_2)[/tex]
=> [tex]41.5 (39.2 - 28.5 ) = M ( 49.7 -39.2 )[/tex]
=> [tex]M = 42.3 \ kg[/tex]
what are the effects of moon rotation and revolution
Answer:
The effects of the Moon's rotation includes;
1) The Moon rotation and revolution gives the appearance of a perfectly still Moon to observers of the Moon from the Earth
2) The Moon has two sides, the near side that continuously faces the Earth and the "back" or far side, which is also known as the dark side of the Moon
The effect of the Moon's revolution
1) The tides in the ocean and water bodies, due to the gravitational forces from the Moon
2) The changes in the observed shape of the Moon due to the amount of Sunlight that is able to be reflected from the Moon as a result of the relative position of the Moon, the Earth and the Sun, at a given point in time
3) Lunar and Solar eclipse, when the Earth and the Moon blocks the light coming from the Sun respectively, due to their combined revolution
Explanation:
The duration of the Moon's orbit round the Earth = 27.322 days
The time it takes the Moon to rotate round its axis = 27 days
The Moon is the closest cosmic body to the Earth.
A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the
ground. How long will it take, in seconds, for the ball to hit the ground?
Answer:
0.73 sExplanation:
The time taken can be found by using the formula
[tex] t = \frac{d}{v} \\ [/tex]
d is the distance
v is the velocity
From the question we have
[tex]t = \frac{3.5}{4.8} \\ = 0.72916...[/tex]
We have the final answer as
0.73 sHope this helps you
3
Question 2 (1 point)
If a runner is racing at a velocity of 1.7 m/s North for 3.0 seconds, how far did they
run?
5.1 m [N]
0.57 m IN)
57 m
51 m[N]
O 1.8 m [N]
Answer:
A, 5.1 m [N]
Explanation:
1.7 times three equals 5.1, and since the runner was running north, the direction was north.
What is the height of a horizontal projectile if it takes 3 seconds to hit the ground?
a
29.4 m
b
3.0 m
C
44.1 m
d
88.3 m
Answer:
B
Explanation:
A softball pitcher rotates a 0.250 kg ball around a vertical circular path of radius 0.5 m before releasing it. The pitcher exerts a 33.0 N force directed parallel to the motion of the ball around the complete circular path. The speed of the ball at the top of the circle is 13.0 m/s. If the ball is released at the bottom of the circle, what is its speed upon release
Answer:
The value is [tex]u = 27.93 \ m/s[/tex]
Explanation:
From the question we are told that
The mass of the ball is [tex]m = 0.250 \ kg[/tex]
The radius of the circle is [tex]r = 0.5 \ m[/tex]
The force exerted is [tex]F = 33 \ N[/tex]
The speed of the ball on top of the circle is [tex]v = 13.0 \ m/s[/tex]
Gnerally from the law of energy conservation we have that
[tex]PE + W = \Delta KE[/tex]
Here PE is the potential energy of the pitcher which is mathematically represented as
[tex]PE = m * g * (2 r )[/tex]
=> [tex]PE = 0.250 * 9.8 * (2 * 0.5 )[/tex]
=> [tex]PE = 24.5\ J[/tex]
And W is the workdone by the force applied which is mathematically represented as
[tex]W = F * \pi * r[/tex]
=> [tex]W = 33 * 3.142 * 0.5[/tex]
=> [tex]W = 51.84 \ J[/tex]
And [tex]\Delta KE[/tex] is the change in kinetic energy which is mathematically represented as
[tex]\Delta KE = \frac{1}{2} * m * (v^2 - u^2 )[/tex]
=> [tex]\Delta KE = \frac{1}{2} * 0.250 * ( 13^2 - u^2 )[/tex]
=> [tex]\Delta KE = 0.125 * ( 13^2 - u^2 )[/tex]
=> [tex]\Delta KE = 21.125 - 0.125u^2[/tex]
So
[tex]24.5 + 51.84 = 21.125 - 0.125u^2[/tex]
=> [tex]u = 27.93 \ m/s[/tex]
The velocity of the ball released at the bottom is required.
The velocity of the ball released at the bottom is 24.56 m/s
F = Force = 33 N
r = Radius of loop = 0.5 m
m = Mass of ball = 0.25 kg
u = Initial velocity of ball = 13 m/s
v = Final velocity
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
The energy balance of the system is given by
[tex]F\pi r+mg2r=\dfrac{1}{2}m(v^2-u^2)\\\Rightarrow v=\sqrt{\dfrac{2}{m}(F\pi r+mg2r)+u^2}\\\Rightarrow v=\sqrt{\dfrac{2}{0.25}(33\times \pi\times 0.5+0.25\times 9.81\times 2\times 0.5)+13^2}\\\Rightarrow v=24.56\ \text{m/s}[/tex]
The velocity of the ball released at the bottom is 24.56 m/s.
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Jerry is pushing a 50-kg box across a moth floor with an acceleration of 0.6 m/s2. What force is he applying to the box? *
83.3 N
0.012 N
0
30 N
Answer:
30 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 50 × 0.6
We have the final answer as
30 NHope this helps you
How long will it take a sample of I-131 to decay to 12.5% assuming it's half-life is 8.07 days?
Answer:
If you take A0 to be the initial sample of iodine-131, you will be left with. 12⋅A0=A02→ ... m24 hours=12.5%mo=12.5⋅10−2⋅mo
Explanation:
is that what u look for
Sample I-131 decays to 12.5% in 24.21 days.
What is half-life?Half-life, in radioactivity, is the amount of time needed for half of a radioactive sample's atomic nuclei to decay (change spontaneously into other nuclear species by emitting particles and energy), or, alternatively, the amount of time needed for a radioactive material's rate of disintegrations per second to decrease by half.
Give parameters:
Half-life of the radioactive element I-131:T = 8.07 day
It decays to 12.5% means it decays to 1/8.
According to definition of half-life,
The radioactive element I-131 decays to half in 8.07 days.
So, the radioactive element I-131 decays to 1/8 in 3×8.07 days = 24.21 days.
Hence, the radioactive element I-131 decays to12.5% in 24.21 days.
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Give one example where friction is useful. Can someone feed me with correct answer pls c:
Answer:
Friction is what holds your shoe to the ground. The friction present on the ice is very little, this is the reason why it is hard to walk on the slippery surface of the ice.
Explanation:
A pinball bangs against a bumper of a pinball machine with a speed of 0.9 m/s. If the ball has a mass of 0.056 kg, what is the ball's kinetic energy?
Question 1 (0.5 points)
Electric circuits provide a path for ___ to flow.
protons
matter
electrons
energy
Electric circuits provide a path for electrons.
The passage of electrons is facilitated by electric circuits.
An electric circuit resembles a roadway consisting of wires over which electrons are transferred.
The force that causes the electrons to travel comes from a battery or another power source. To allow electrons to travel from the source of power to the gadget and back, wires must be run from the source of electricity to the gadget and back.So, Option "C" is the correct answer to the following question.
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what is gravity???☺️
Answer:
Gravity
Explanation:
its an invisible force that pulls objects
toward each other.
hope it helps
A man speeding at 40m/s decides to outrun the cops and starts to accelerate at a rate of 2.5m/s² for 12 seconds. How far did he travel in this time?
Answer:
The distance traveled by the man during the acceleration is 1186.32 meters
Explanation:
The initial velocity of the man = 40 m/s
The added acceleration rate of the man to outrun = 2.5 m/s²
The time of acceleration = 12 seconds
The relevant kinematic equation of motion is given as follows;
s = u·t + 1/2·a·t²
Where;
u = The initial velocity of the car the man is driving = 40 m/s
t = The time of travel during acceleration of the car the man is driving = 12 seconds
a = The acceleration by the man to outrun the cops = 2.5 m/s²
s = The distance traveled by the man during the acceleration
Substituting, gives;
s = 40 × 12 + 1/2 × 9.81 × 12² = 1186.32
The distance traveled by the man during the acceleration = s = 1186.32 m.
mass does not vary from place to place why?
Answer:
It is always constant unlike weight
A ball of mass 0.12kg is hit by a tennis player. The velocity of the ball changes from 0m/ s to 5.0m/s in 0.60s. What is the average resultant force acting on the ball while it is being hit?
A 1.0N B 2.5N C 3.6N D 8.3N
(Please add explanation)
Answer:
A. 1.0NExplanation:
According to Newton's second law
F = ma
m is the mass = 0.12kg
a is the acceleration = v-u/t
a = 5-0/0.6
a = 5/0.6
a = 8.333m/s²
Get the force
F = 0.12 * 8.333
F = 1.0N
Hence the average resultant force acting on the ball while it is being hit is 1.0N
How much would a pair of 0.5 kg shoes weigh on Earth? (Include units in
your answer) *
Answer:
1.1 lbs
Explanation:
To convert kg to lbs you multiply kilograms by 2.2. So 0.5kg × 2.2 equals to 1.1 lbs
what phenomenon reduces the adverse effects and pressure imposed by solar wind on earth?
Answer:
The earths magnetic field
Explanation: