1. Explain home a dial test indicator (DTI) reading is adjusted when the gange is not positioned at right angle to the contact surface.​

Answer: Febreze was initially not successful because it was marketed as an air freshener. At the time, people did not think their homes smelled bad, so they did not see the need for an air freshener.

Explanation:

The magnitude of the electric force between the two corks is approximately 4.16 × 10^10 Newtons

We may apply Coulomb's law to determine the strength of the electric force between the two charged corks. According to Coulomb's law, the electric force between two point charges is inversely proportional to the square of the distance between them and directly proportional to the product of their charges.

Coulomb's law is expressed as F = (k * |q1 * q2|) / r2.

Where: |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges. F is the strength of the electric force, and k is the electrostatic constant (about 9 109 N m2/C2).

In this instance, the first cork's charge, |q1|, is +9.0, and the second cork's charge, |q2|, is -3.2. They are separated by r, which is 0.17.

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a) The ratio of the slit separation to the slit width is 2.  

b) There are four bright fringes within the first side peak.

a) The ratio of the slit separation to the slit width is 2. This is because the second side peak of the diffraction envelope is located at an angle of

2λ/d, where λ = wavelength of light and d = slit width.

The diffraction minima coincide with the two-slit interference maxima, which are located at angles of λ/d.

Therefore, the ratio of the slit separation to the slit width is 2.

(b) There are four bright fringes within the first side peak. This is because the first side peak of the diffraction envelope is located at an angle of

λ/d, where λ = wavelength of light and d = slit width.

The diffraction minima coincide with the two-slit interference maxima, which are located at angles of λ/d.

Therefore, there are 4 bright fringes within the first side peak.

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Answer: The centripetal force acting on the car is 4752 Newtons

Explanation:

The formula for centripetal force (F) is:

[tex]F = m * v^2 / r[/tex]

where:

m is the mass,

v is the velocity, and

r is the radius.

Given that the mass (m) of the car is 990 kg, the velocity (v) of the car is 12 m/s, and the radius (r) of the curve is 30 m, we can substitute these values into the formula:

[tex]F = 990 kg * (12 m/s)^2 / 30 m[/tex]

Solving this gives:

[tex]F = 990 kg * 144 m^2/s^2 / 30 m[/tex]

This simplifies to:

[tex]F = 4752 N[/tex]

Therefore, the centripetal force acting on the car is 4752 Newtons.

The aforementioned statement, "Measurements must be conducted carefully to ensure that all factors—aside from the variable—are the same,” is true. Controlling for all variables besides the variable of interest is crucial when performing scientific experiments or taking measurements.

By doing so, it is possible to make sure that any observed changes or impacts are caused by the variable being monitored and not by any confounding variables.

Researchers can isolate the effects of the particular variable they are examining by maintaining the status quo for all other factors. By keeping all other conditions constant, researchers can isolate the impact of the specific variable they are studying.

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The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.

To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.

In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.

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Complete question:

A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?

A) These vectors should be drawn with the appropriate scale and labeled. The resulting vector is obtained by adding the two vectors head-to-tail. The tail of the crosswind vector should be connected to the head of the aircraft velocity vector.

B) R ≈ √68125 m/s ≈ 260.98 m/s

C)θ ≈ arctan(0.3)

θ ≈ 16.7°

D)The magnitude of the resultant vector is approximately 260.98 m/s. The direction of the resultant vector is approximately 16.7° south of west.

a) To draw the vector diagram, we represent the velocity of the aircraft as a vector pointing southwest with a magnitude of 250 m/s. We also represent the crosswind as a vector pointing east with a magnitude of 75 m/s. These vectors should be drawn with the appropriate scale and labeled. The resulting vector is obtained by adding the two vectors head-to-tail. The tail of the crosswind vector should be connected to the head of the aircraft velocity vector. The resulting vector represents the resultant velocity.

b) To calculate the magnitude of the resultant vector, we can use the Pythagorean theorem. Let's denote the magnitude of the resultant vector as R. The magnitude of the aircraft velocity vector is 250 m/s, and the magnitude of the crosswind vector is 75 m/s. Therefore,

R^2 = (250 m/s)^2 + (75 m/s)^2

R^2 = 62500 m^2/s^2 + 5625 m^2/s^2

R^2 = 68125 m^2/s^2

Taking the square root of both sides, we find:

R ≈ √68125 m/s ≈ 260.98 m/s

c) To calculate the angle to the resultant, we can use trigonometry. Let's denote the angle between the resultant vector and the southwest direction as θ. We can use the inverse tangent function:

tan(θ) = (75 m/s) / (250 m/s)

θ ≈ arctan(0.3)

θ ≈ 16.7°

d) The magnitude of the resultant vector is approximately 260.98 m/s. The direction of the resultant vector is approximately 16.7° south of west.

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Answer:

The ambient temperature is 35°C.

It takes 15 minutes to cool the substance from 40°C to 35°C.

Explanation:

Using Newton's Law of Cooling to answer the given problem.

[tex]\boxed{\left\begin{array}{ccc}\text{\underline{Newton's Law of Cooling:}}\\\\ \frac{dT}{dt} =-k(T-T_a)\end{array}\right}[/tex]

Given:

The time it takes to cool from 50°C to 45°C = 3 minutes

The time it takes to cool from 45°C to 40°C = 5 minutes

Find:

Time ambient temperature and the time it takes to cool the substance from 40°C to 35°C

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

(1) - Using first initial condition:

[tex]\text{Avg temp =} \ \frac{50+45}{2}=\boxed{47.5 \textdegree C}\\\\\Longrightarrow \frac{50-45}{3}=-k(47.5-T_a) \\\\\Longrightarrow \boxed{ \frac{5}{3}=-k(47.5-T_a)}[/tex]

(2) - Using the second initial condition:

[tex]\text{Avg temp =} \ \frac{45+40}{2}=\boxed{42.5 \textdegree C}\\\\\Longrightarrow \frac{45-40}{5}=-k(42.5-T_a) \\\\\Longrightarrow \boxed{1=-k(42.5-T_a)}[/tex]

(3) - Now we have a system of equations.

[tex]\left \{ \frac{5}{3}=-k(47.5-T_a)}} \atop {1=-k(42.5-T_a)}}} \right.[/tex]

(4) - Solve the system by dividing the top equation by the bottom equation.

[tex]\Longrightarrow \frac{\frac{5}{3}=-k(47.5-T_a)}{1=-k(42.5-T_a)} \\\\\Longrightarrow\frac{5}{3}=\frac{47.5-T_a}{42.5-T_a}\\ \\ \Longrightarrow 5(42.5-T_a)=3(47.5-T_a)\\\\\Longrightarrow 212.5-5T_a=142.5-3T_a\\\\\Longrightarrow 2T_a=70\\\\\therefore \boxed{T_a=35 \textdegree C}[/tex]

Thus, the ambient temperature is 35°C.

(5) - Find the value of "k" using either of the two previous equations

[tex]1=-k(42.5-T_a)\\\\\Longrightarrow 1=-k(42.5-35)\\\\\Longrightarrow 1=-7.5k\\\\\Longrightarrow \boxed{ k \approx -0.133}[/tex]

(6) - Now finding "dt"

[tex]\text{Avg temp =} \ \frac{40+35}{2}=\boxed{37.5 \textdegree C}\\\\\Longrightarrow \frac{40-35}{dt}=0.133(37.5-35) \\\\\Longrightarrow \frac{5}{dt}=0.3325\\\\\therefore \boxed{dt \approx15 \ min}[/tex]

Thus, it take 15 minutes to cool the substance from 40°C to 35°C.

Answer:

I don't actually know, but it has to do with the research they id

Explanation:

to seem precise

Answer:A word equation uses words to represent the reactants and products in a chemical reaction. A formula equation uses chemical symbols or formulas, but does not reveal the ratios of the products and reactants.

Explanation: example of a word equation: Synthesis, magnesium + chlorine → magnesium chloride.

Example of a formula equation:CH4(g) + O2(g) → CO2(g) + H2O(g)

Answer: The increase in the need for energy is causing significant environmental damage in several ways like fossil fuels, land use, deforestation, water use, and Air and water pollution

Explanation:

The increase in the need for energy is causing significant environmental damage in several ways like in fossil fuels from where the majority of our energy comes from non-renewable sources such as coal, oil, and gas, which release harmful greenhouse gases into the atmosphere when burned, contributing to climate change and global warming.

Land use and deforestation increase the production of biofuels and the construction of power plants requires a significant amount of land, leading to deforestation and habitat loss.

Water uses in energy production consume vast amounts of water, leading to water scarcity and ecosystem degradation

Air and water pollution in the production and transportation of energy and the disposal of waste from energy production result in air and water pollution that harm both humans and wildlife.

To address these issues, we must focus on reducing our energy consumption, promoting renewable energy sources, and implementing energy-efficient practices. Here are several solutions to this ongoing problem:

Promote Renewable Energy: Increase the use of renewable energy sources such as solar, wind, and hydropower, which are cleaner and less harmful to the environment than fossil fuels.

Improve Energy Efficiency: Encourage energy-efficient practices such as using LED lights, insulating buildings, and using energy-efficient appliances, which can significantly reduce energy consumption.

Encourage Conservation: Promote energy conservation, such as turning off lights when not in use, using public transportation, and carpooling, to reduce the need for energy production.

Develop Sustainable Infrastructure: Create sustainable infrastructure such as green buildings and eco-friendly transportation, which reduces the need for energy production and minimizes environmental impact.

Implement Environmental Policies: Governments can implement environmental policies that encourage energy conservation and the use of renewable energy sources, such as incentives for renewable energy and carbon taxes on fossil fuels.

Promote Education: Educate the public on the importance of energy conservation and the benefits of renewable energy, which can lead to behavior change and a reduction in energy consumption.

In conclusion, the increase in the need for energy is causing significant environmental damage, but there are several solutions to this ongoing problem. By promoting renewable energy, improving energy efficiency, encouraging conservation, developing sustainable infrastructure, implementing environmental policies, and promoting education, we can minimize our impact on the environment while still meeting our energy needs.

Answer:

340 kg

Explanation:

F = ma

Rearranging the equation to solve for mass (m):

m = F/a

Substituting the given values:

m = 850 N / 2.5 m/s^2

m = 340 kg

Answer:

0.000025 m³

Explanation:

The volume of water displaced by the cylinder is equal to the volume of the cylinder itself. To find the volume of the cylinder, we need to subtract the initial volume of water in the measuring flask (200 ml) from the final volume of water with the immersed cylinder (225 ml).

Volume of displaced water = final volume - initial volume

Volume of displaced water = 225 ml - 200 ml

Volume of displaced water = 25 ml

We now need to convert this volume from milliliters (ml) to cubic meters (m³). We can use the conversion factor that 1 m³ = 1,000,000 ml:

Volume of displaced water = 25 ml ÷ 1,000,000

Volume of displaced water = 0.000025 m³

Therefore, the volume of displaced water is 0.000025 m³.

Change of state due to cooling is due to the removal of thermal energy from a substance. A substance changes states, such as from a gas to a liquid or from a liquid to a solid, when its particles lose kinetic energy as it loses heat and moves more slowly. Eventually, the particles reorganize into a more ordered form with less energy. The term "solidification" or "freezing" refers to this process.

The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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Given that the original force is 10 newtons, the new force when the distance is doubled would be 2.5 newtons. Option A

Based on Newton's law of  gravitation, the force of gravity between two objects is inversely proportional to the square of the distance between them.

What this means is that if the distance between two objects is doubled, the force of gravity between them is reduced by a factor of four.

In this case, the distance between the two objects is doubled, so the force of gravity between them is reduced from 10 newtons to 2.5 newtons.

We can calculate it by saying 10 N / 4 = 2.5 N.

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Answer: A.

2.5 newtons

Explanation: edmentum

Answer:

to shorten the answer

or it's like a code because scientists already know what it means

The buoyant force exerted by the water on the cylinder is 0.2 N.

To find the buoyancy force exerted by water on the cylinder, we need to understand the concept of buoyancy and Archimedes' principle.

Archimedes' principle states that the buoyant force acting on an object immersed in a fluid is equal to the weight of the fluid displaced by the object. The buoyant force opposes the weight of the object and is responsible for the apparent loss of weight when an object is submerged in a fluid.

In this experiment, the weight of the cylinder (Wac) is 4 N. When the cylinder is immersed in water, the apparent weight of the cylinder (Wap) is 3.8 N. The difference between these two weights is the buoyant force exerted by the water on the cylinder.

Buoyant force (B) = Wac - Wap

B = 4 N - 3.8 N

B = 0.2 N

Therefore, the buoyant force exerted by the water on the cylinder is 0.2 N.

This means that the upward force exerted by the water on the cylinder is 0.2 N, opposing the downward force of gravity. The buoyant force depends on the volume of the fluid displaced by the object. In this case, the weight of the displaced water is equal to the buoyant force, as stated by Archimedes' principle.

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I have observed and experienced behaviors that are learned as a result of environmental influences, and I can furnish examples to support this assertion.

Recycling serves as a noteworthy instance. During my childhood, I acquired the habit of recycling owing to the teachings and guidance of my parents and educators, which became firmly established in me.

Water conservation serves as another illustration. Having experienced repeated droughts in my locale, I developed a sense of awareness about the utilization of water and inculcated practices such as shutting off the tap while brushing my teeth.

My daily habits have been influenced by the environmental elements in my surroundings and have now become ingrained in my routine.

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The three basic rules for the electric charge are like charges repel each other, unlike charges attract each other and the charges in the system are constant. The unit of charge is coulomb (C).

Electric charge is of two types and they are positive and negative charges. The negative charge is free electrons and the positive charges are the holes in the conductors. The basic rules are, two positive charges repel each other and two negative charges repel each other and they are called like charges.

One positive and one negative charge attract each other and hence they are unlike charges. The attractional force and repulsion force increase with a decrease in the distance of separation. The charges remain constant in the system and it is called as law of conservation of charges in the system.

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The expression; R vector=A vector - B vector shows that R² = A² + B² - 2ABcosθ.

Start by expanding the square of R:

R² = (A - B)²

Use the difference of squares factorization to expand this:

R² = (A - B)(A + B)

Now distribute the terms on the right-hand side:

R² = A² + AB - AB - B²

Combine like terms on the right-hand side:

R² = A² + B² - 2AB

Finally, use the cosine rule to express the magnitude of R in terms of the magnitudes of A and B and the angle between them:

R² = A² + B² - 2ABcosθ

Therefore, it is shown that R² = A² + B² - 2ABcosθ.

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A motional emf is emf = Blvsinθ, where B is the magnetic field and l is the length of the rod and v is the velocity.

By considering two cases:

1) The angle between the rod and the magnetic field, the magnetic field is separated into two components. The perpendicular component is defined by the length and velocity and the other component lying inside it. The emf is produced by the perpendicular component and the magnitude of the magnetic field is B(perpendicular) = Bsinθ. The emf is

          ε = Bvlsin(θ).

2) In the second case, the component of velocity produces the emf, and the perpendicular component is defined by the length and magnetic field. The perpendicular component of velocity, V(perpendicular) = v sinθ. The emf is,

        ε = Bvlsin (θ).

Hence, it is proved that B, v, and l are not mutually perpendicular to each other.

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Answer:

average speed = 50km/hr

average velocity =0

Explanation:

the average speed equals to average of these two speeds as the distance covered in both the cases are same.

average speed = (40+60)/2= 50km/hr

as the train returns to the same point the displacement is zero,

hence the average velocity is zero.

The average speed of the train is 50 km/hr.

The average velocity of the train is zero.

Speed of the train when it travels from the first station, v₁ = 40 km/hr

Speed of the train when it returns to the first station, v₂ = 60 km/hr

The expression for the average speed of the train is given by,

Average speed = (v₁ + v₂)/2

Average speed = (40 + 60)/2

Average speed = 100/2

Average speed = 50 km/hr

Since, the train travels from the first station, reaches the second station and then it again returns back to the first station, the total displacement covered by the train will become zero.

s = 0

Therefore, the average velocity of the train is also zero.

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Answer: Coulomb's law states that the force between two charged particles is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, it can be represented as:

F = k(q1q2)/r^2

where F is the force, q1 and q2 are the charges of the particles, r is the distance between them, and k is the Coulomb's constant.

In the before scenario, both charges are positive (+q and +q), so they repel each other and the force between them is positive.

In the after scenario, one charge is positive (+q) and the other is negative (-q), so they attract each other and the force between them is negative.

Therefore, the correct answer is option C: The magnitude of the force is the same, but it changes from repulsive to attractive. The magnitude of the force is not affected by the sign of the charges, only the direction of the force changes.

Explanation: :)

The strongest predictor of adopting a regular exercise program is self-efficacy. Thus, Option B is correct.

      One of the best determinants of starting a regular exercise regimen is self-efficacy. Self-efficacy is a person's belief in their ability to successfully undertake a given habit, in this case, exercising on a regular basis.

People who have high self-efficacy feel they can overcome obstacles to exercise, such as a lack of time or motivation, and are more likely to persist in an exercise program.

While body mass index, self-esteem, and athleticism can all have an impact on exercise habits, self-efficacy has been proven to be an especially powerful predictor.

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The normal force experienced by the box is 277N, which is answer choice D.

To solve this problem, we need to use trigonometry and Newton's laws of motion. Let's start by drawing a diagram of the situation. We have a box that weighs 450N and is being pulled at an angle of 38 degrees along a level floor. The force applied by the rope is 260N, and we want to find the normal force experienced by the box. First, let's resolve the force applied by the rope into its horizontal and vertical components. The horizontal component of the force is Fcos(38), where F is the force applied by the rope. The vertical component of the force is Fsin(38). We can use these components to calculate the net force acting on the box in the horizontal and vertical directions. In the horizontal direction, the net force is zero because the box is moving at a constant speed. Therefore, the horizontal component of the force applied by the rope must be equal in magnitude and opposite in direction to the force of friction acting on the box. We can calculate the force of friction using the equation Ffriction = coefficient of friction * normal force, where the coefficient of friction is a constant that depends on the materials in contact and the normal force is the force exerted by the floor on the box in a direction perpendicular to the surface. Since the box is not accelerating horizontally, we know that Ffriction = Fcos(38), so we can solve for the normal force:
Ffriction = coefficient of friction * normal force
Fcos(38) = coefficient of friction * normal force
normal force = Fcos(38) / coefficient of friction
Now we just need to find the coefficient of friction. Since the box is not accelerating vertically, we know that the net force in the vertical direction is zero. Therefore, the vertical component of the force applied by the rope must be equal in magnitude to the weight of the box plus the normal force. We can write this as:
Fsin(38) = 450N + normal force
Solving for normal force, we get:
normal force = Fsin(38) - 450N
Now we can substitute this expression for normal force into the equation we derived earlier:
normal force = (Fcos(38) / coefficient of friction) - 450N
We can solve for coefficient of friction by setting the two expressions for normal force equal to each other and solving for coefficient of friction:
Fsin(38) - 450N = (Fcos(38) / coefficient of friction) - 450N
coefficient of friction = Fcos(38) / Fsin(38)
Substituting the given values, we get:
coefficient of friction = 260N * cos(38) / (260N * sin(38))
coefficient of friction = cos(38) / sin(38)
Now we can substitute this expression for coefficient of friction into the expression we derived earlier for normal force:
normal force = (Fcos(38) / coefficient of friction) - 450N
normal force = (260N * cos(38) / (cos(38) / sin(38))) - 450N
normal force = 277N
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The football left the kicker's foot with an initial vertical speed of 19.62 m/s.

The initial vertical velocity of a football kicked straight up into the air can be calculated using the kinematic equation:
v_f = v_i + a*t
where v_f is the final velocity (0 m/s in this case, as the football stops at its highest point before falling), v_i is the initial velocity (which we want to find), a is the acceleration due to gravity (-9.81 m/s^2, negative because it acts downward), and t is the time taken to reach the highest point.
First, we need to determine the time taken to reach the highest point, which is half of the total time (4 seconds):
t = 4 seconds / 2 = 2 seconds
Now we can substitute the values into the equation:
0 m/s = v_i - 9.81 m/s^2 * 2 seconds
Rearrange the equation to solve for v_i:
v_i = 9.81 m/s^2 * 2 seconds = 19.62 m/s
Therefore, the football left the kicker's foot with an initial vertical speed of 19.62 m/s.

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The sensation of feeling cold after coming out of a swimming pool can be attributed to evaporation, conduction, individual sensitivity.

The several factors are

Firstly, water conducts heat away from the body more efficiently than air. When you are in the pool, the water absorbs heat from your body, causing you to lose heat through conduction. This lowers your body temperature, and when you step out of the water into the air, the temperature difference between your body and the surrounding environment can feel more pronounced, resulting in a sensation of coldness.

Secondly, evaporation plays a role in cooling down the body. As water evaporates from your skin's surface, it takes heat away from your body, creating a cooling effect. When you exit the pool, the moisture on your skin evaporates more rapidly in the drier air, further intensifying the cooling sensation.

Additionally, wet clothing can contribute to the feeling of coldness. Wet fabric against the skin facilitates heat transfer and can make you feel colder than if you were dry.

The perception of coldness after swimming can also be influenced by personal factors such as individual sensitivity to temperature changes, the duration of time spent in the water, and the temperature of the pool itself.

To mitigate the feeling of coldness after swimming, it is advisable to dry off and change into dry clothing promptly. Wrapping yourself in a towel or using a robe can help retain body heat. Additionally, engaging in light physical activity or seeking warmer sheltered areas can help generate body heat and alleviate the sensation of coldness.

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The height of the object, given that the potential energy of the object doubled will be double (option D)

First, we shall list out the given parameters. Details below:

Potential energy is given as:

PE = mgh

Keeping mg constant, we have

PE₁ / h₁ = PE₂ / h₂

Inputting the given parameters, we have

P / h = 2P / h₂

Cross multiply

P × h₂ = h × 2P

Divide both sides by P

h₂ = (h × 2P) / P

h₂ = h × 2

h₂ = 2h

Thus, we can conclude that the new height of the object will also double (option D)

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