1 is the additive identity of any real number True or False​

Answers

Answer 1

Answer:

False

Step-by-step explanation:

It is False. 1 is the identity element for multiplication, because if you multiply any number by 1, the number doesn’t change. Identity elements are specific to each operation (addition, multiplication, etc.). So while 1 is the identity element for multiplication, it is NOT the identity element for addition.


Related Questions

Rene’s driveway is a rectangle 45 feet long by 20 feet wide. What is the area of the driveway?

Answers

Answer:

25 this is a write answer

The area of a rectangle is found by multiplying length times width. In this case it would be 20 ft. times 15 ft. which equals 300 square feet Make sure you answer in SQUARE feet.

How to find unique prime factorization of 10 factorial.

Answers

How to find th unique prime factorization of 10 factorial

A rectangular pool 12 meters by 8 meters is surrounded by a walkway of width x meters. At what
value of x will the area of the walkway equal the area of the pool?
Explain. (don’t send file)

Answers

X=3

x is the width of the sidewalk
The outside dimensions of the walkway are 12 + 2x by 8 + 2x
The total area is (12 + 2x)(8 + 2x)
The total area minus the area of the pool should be equal to the area of the pool

Hoped this helped!

When raising a power to a power you________ the exponents.

Answers

Answer:

Multiply

Step-by-step explanation:

To raise a power to a power means to raise one exponent to another. Whether the exponents are real, imaginary, monomials or polynomials, to simplify these problems, all we have to do is multiply the exponents together.

- BRAINLIEST answerer

ANSWER CORRECT FOR BRAINLIEST

Answers

Answer:

3 2 /5 ×3

change 3 2 /5 into an improper fraction

then you will get 17 /5

after that you say 17/5 ×3/1

=(17×3)/ (5x1)

=51/5 (51÷5)

=10.2/ 10 1/5

Solution:

[tex]3 \frac{2}{5} \times 3 \\ = \frac{17}{5} \times 3 \\ = \frac{51}{5} \\ = 10 \frac{1}{5} [/tex]

Answer:

[tex]10 \frac{1}{5} [/tex]

Hope it helps.

Do comment if you have any query.

Write the equation of the line with two given points

(-12, 14) and (6,-1)

Answers

The answer is y= -5/8x + 2 1/4

read sddddddddd

dxfcgvhbjnkml,

Answers

Answer:

1/5

Step-by-step explanation:

rise = 2 ft

run = 10 ft

slope = rise/run = 2/10 = 1/5

Answer: 1/5

Answer:

1/5

Step-by-step explanation:

The slope is the rise over the run

Y / x

2/10

1/5

A plane flies from San Francisco to New York City at 600 miles per hour and returns along the same route at 400 miles per hour. What is the average flying speed for the entire route (in miles per hour)

Answers

Answer: 500 i think

Step-by-step explanation:

59 divided by 4=? PLEASE HELP!

Answers

Answer:

14.75

Step-by-step explanation:

56/4 = 14, 3/4 = .75

add them together

Answer: 14.75

Step-by-step explanation: yeah its 14.75  but if you want to simplify it, then its 14.8

Write an equation in slope intercept form for the line that has a slope of 1/4 and passes through the point (0, -2)

Answers

Step-by-step explanation:

the general slope intercept formula is

y = ax + b

a is the slope of the line.

b is the y-intercept (the point, where the line crosses the y-axis, meaning the y value when x=0).

we get b by using the point coordinates in the equation and solve for b :

-2 = (1/4)×0 + b

b = -2 (as expected)

the full line equation is

y = (1/4)x - 2

Find all of the rational zeros of the function. ​f(​x)=x ​4 −3x ​3 −6x ​2 +6x+8 ​

Answers

Answer:

The "possible" rational zeros are:

±

1

,

±

2

,

±

4

,

±

8

The actual zeros are:

1

,

4

,

±

2

Explanation:

f

(

x

)

=

x

4

3

x

3

6

x

2

+

6

x

+

8

By the rational root theorem, any rational zeros of

f

(

x

)

are expressible in the form

p

q

for integers

p

,

q

with

p

a divisor of the constant term

8

and

q

a divisor of the coefficient

1

of the leading term.

That means that the only possible rational zeros are:

±

1

,

±

2

,

±

4

,

±

8

We find:

f

(

1

)

=

1

+

3

6

6

+

8

=

0

So

x

=

1

is a zero and

(

x

+

1

)

a factor:

x

4

3

x

3

6

x

2

+

6

x

+

8

=

(

x

+

1

)

(

x

3

4

x

2

2

x

+

8

)

Notice that the ratio between the first and second terms of the remaining cubic is the same as that between the third and fourth terms. So this cubic will factor by grouping:

x

3

4

x

2

2

x

+

8

=

(

x

3

4

x

2

)

(

2

x

8

)

x

3

4

x

2

2

x

+

8

=

x

2

(

x

4

)

2

(

x

4

)

x

3

4

x

2

2

x

+

8

=

(

x

2

2

)

(

x

4

)

Finally we can factor the quadratic as a difference of squares:

x

2

2

=

x

2

(

2

)

2

=

(

x

2

)

(

x

+

2

)

So the zeros are:

1

,

4

,

±

2

illustrated Go Math solution to the problem of 4x as many spaniels as retrievers and there are 30 dogs, how many are spaniels

Answers

Answer:

24 spaniels

Step-by-step explanation:

4 many spaniels as retriever means that if you put the dogs in the correct order, every 5 animals you will have one retriever and 4 spaniels, then one retriever and four more spaniels. That is, there are groups of 5 dogs with that ratio. If there are 30 dogs, you can make 6 of these groups. It means that you have 24 spaniels and 6 retrievers.

Unit 4 linear equations homework 9 parallel and perpendicular lines (day1) activity
Directions if segments AB and CD are parallel,perpendicular, or neither

Answers

The lines that are parallel continuously have equal distances from each

other and perpendicular lines form 90° angle at their intersection.

The correct responses are;

Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular, ⊥Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel. ║Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neitherSegment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular, ⊥Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular, ⊥Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neitherThe equations are parallel, ║The equations are perpendicular, ⊥The equations are perpendicular, ⊥The equations are neither parallel or perpendicular

Reasons:

Segment [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular

[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel where; Slope of [tex]\overline{AB}[/tex] = Slope of [tex]\overline{CD}[/tex]

[tex]\displaystyle \overline{AB} \ and \ \overline{CD} \ are \ perpendicular\ where; \ Slope \ of \ \overline{AB} = -\frac{1}{Slope \ of \ \overline{CD}}[/tex]

[tex]1. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{\frac{13 - 3}{-2 - 0}} = \frac{10}{-2} = -5[/tex]

[tex]\geq \displaystyle Slope \ of \ \overline{CD} = \frac{3 - 0}{10 - (-5)} = \frac{1}{5}[/tex]

[tex]\displaystyle \mathbf{Slope \ of \ \overline{AB}} = -\frac{1}{Slope \ of \ \overline{CD}}[/tex], [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular

[tex]2. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{\frac{7- 1}{3 - (-6)}} = \frac{6}{9} =\frac{2}{3}[/tex]

[tex]\geq \displaystyle Slope \ of \ \overline{CD} = \frac{-5 - (-1)}{-6 - 0} = \frac{-4}{-6}=\frac{2}{3}[/tex]

Slope of [tex]\mathbf{\overline{AB}}[/tex] = Slope of [tex]\overline{CD}[/tex] , [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel

[tex]3. \ \displaystyle Slope \ of \ \overline{AB} = \mathbf{ \frac{2- 4}{-6 - (-2)} = \frac{-2}{-4}} =\frac{1}{2}[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \frac{11 - (-7)}{-1 - 5} = \frac{18}{-6}=-3[/tex]

[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neither parallel or perpendicular

[tex]4. \ \displaystyle Slope \ of \ \overline{AB} = \frac{8- 3}{-3 - 2} = \frac{5}{-5} =-1[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \frac{6 - 2}{-4 - (-8)} = \frac{4}{4}=1[/tex]

[tex]\displaystyle Slope \ of \ \overline{AB} = \mathbf{-\frac{1}{Slope \ of \ \overline{CD}}}[/tex], [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are perpendicular

[tex]5. \ \displaystyle Slope \ of \ \overline{AB} = \frac{-1 - 2}{-8 - (-4)} = \frac{-3}{-4} =\frac{3}{4}[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \mathbf{\frac{-3 - 6}{0 - 12}} = \frac{-9}{-12}=\frac{3}{4}[/tex]

Slope of [tex]\overline{AB}[/tex] = Slope of [tex]\overline{CD}[/tex] , [tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are parallel

[tex]6. \ \displaystyle Slope \ of \ \overline{AB} = \frac{5 - (-1)}{6 - 3} = \frac{6}{3} =2[/tex]

[tex]\displaystyle Slope \ of \ \overline{CD} = \mathbf{\frac{-5 - 7}{2 - (-4)}} = \frac{-12}{6}=-2[/tex]

[tex]\overline{AB}[/tex] and [tex]\overline{CD}[/tex] are neither parallel or perpendicular

Directions: To determine if the equations are parallel or perpendicular

Solution:

The equations are parallel if when expressed in the form, y = m·x  + c, the value of m are equal

The equations are perpendicular, when we have;

[tex]\displaystyle The \ value \ of \ \mathbf{m} \ in \ one \ equation = -\frac{1}{The \ value \ of \ \mathbf{m} \ in \ the \ other\ equation }[/tex]

7. First equation

3·x + 2·y = 6

Therefore; [tex]\displaystyle y = -\frac{3}{2} \cdot x + 3[/tex]

Second equation; [tex]\displaystyle y = \mathbf{-\frac{3}{2} \cdot x + 5}[/tex]

The value of m which is the coefficient of x are both equal to [tex]\displaystyle -\frac{3}{2}[/tex]

Therefore, the equations are parallel

8.  Equation 1; 3·y = 4·x + 15

Therefore;

[tex]\displaystyle y = \frac{4}{3} \cdot x + 5[/tex]

Equation 2; 9·x + 12·y = 12

[tex]\displaystyle y = -\frac{9}{12} \cdot x + 1 = 1 - \frac{3}{4} \cdot x[/tex]

The slope of the equation 2 is the negative inverse of the slope of equation 1, therefore, the equations are perpendicular

9. Equation 1: 8·x - 2·y = 4

Therefore;

y = 4·x - 2

Equation 2: x + 4·y = -12

Therefore;

[tex]\displaystyle y = -\frac{1}{4} \cdot x - 3[/tex]

The slope of the equation 2 is the negative inverse of the slope of equation 1, therefore, the equations are perpendicular.

10. Equation 1: 3·x + 2·y = 10

Therefore;

[tex]\displaystyle y = -\frac{3}{2} \cdot x - 5[/tex]

Equation 2: 2·x + 3·y = -3

[tex]\displaystyle y = -\frac{2}{3} \cdot x -1[/tex]

The slopes of the equation 1 and 2 are not equal, and are not  the negative inverse of each other, therefore, the equations are neither parallel nor perpendicular.

Learn more about parallel and perpendicular lines here:

https://brainly.com/question/7197064

Question 8
The original price of a snowblower is $950. A sign states that all snowblowers are 20% off the original price. Find the sale price of the
snowblower.

Answers

Answer:

$760

Step-by-step explanation:

950 x 0.8 = 760

Mr. Johnston spends 2/3 of every year in Florida how many months does he spend in Florida each year

Answers

Answer:

8 months

Step-by-step explanation:

12/3 = 4, 1/3 is 4 so 1/3 + 1/3 = 2/3 or 8

How do you graph an equation using x and y intercepts.

Answers

Answer:

I'm going to use the following as an example.

[tex]2x + 4y = 8[/tex]

To find the y-intercept, set x equal to 0 then solve for y.

[tex]2(0) + 4y = 8[/tex]

two times zero is zero, so we have the following equation.

[tex]4y = 8[/tex]

Solve for y

[tex] \frac{4y}{4} = \frac{8}{4} \\ y = 2[/tex]

Your first point you will graph is (0, 2).

Now solve for the x intercept. To do this, set y = 0.

[tex]2x + 4(0) = 8[/tex]

4(0) = 0, so you can remove it, and solve for x.

[tex]2x = 8[/tex]

[tex] \frac{2x}{2} = \frac{8}{2} \\ x = 4[/tex]

Now the next point you have is (4, 0). plot that point. Connect the two points with a line and you are done.

What’s the algebraic expression for this

tn tv
1. 1
2. 3
3. 6
4. 10
5. 15

Someone plz help me

Answers

Answer:

1 3 6 10 15

Step-by-step explanation:

brainliest plz

2x+3y=5x-y solutions

Answers

Question:

[tex]2 \times + 3y = 5x - y[/tex]

Solution:

[tex]2 \times + 3y = 5x - y

[/tex] Move the variables to the left

[tex]2 \times + 3y - 5 \times + y = 0[/tex]

Collect like terms

[tex] - 3 \times + 4y = 0[/tex]

Change the signs

Answer:

[tex]3 \times - 4y = 0[/tex]

Q8. the distance between two villages is 12875km. Express the distance in standard form.​

Answers

Answer:

1.2875 × 10^4

Step-by-step explanation:

I'll mark brainliest for the first correct answer

Answers

Area of circle = A = πr2 = π × 42 ≈ 50.26548 yard²

- BRAINLIEST answerer

2. Draw 3 different polygons that have only 2 lines of symmetry

Answers

Answer:

Hello. The answer is : rectangle, rhombus

I cant think of a third one as yet.

Pls help I will put brainlist if u help me told nd thank u

Answers

Answer:

17+7=24

Step-by-step explanation:

I hope this help you

Answer

10

Step-by-step explanation:

Subtract 7 from both sides of the equation.

n=17−7

Subtract 7 from 17.

n=10

BRAINLIEST?

helppp,no links or spam

Answers

Answer: 6.45 x 10^10

Step-by-step explanation:

Because 10^5 and 10^4 both have 10, we can add the exponents to get 10^9.

Multiplying 7.5 and 8.6 gets you

7.5 * 8.6 = 64.5

We can move the decimal up a place to get 6.45 and add another power to 10^9 to get 10^10

Your final answer should be 6.45 x 10^10

Answer:

C 6.45x 10 to the power of 10

Step-by-step explanation:

10 to the power of 5 is 100,000. 7.5x100,000 is 750,000.

10 to the power of 4 is 10,000.

10,000x8.6 is 86k

now we do 750,000x86,000 which is 64,500,000,000

10 to the power of 10 is 10 billion times 6.45 is 64,500,000,000

What is the value of x

Answers

Answer:

12

Step-by-step explanation:

We know the hypotenuse and legs of 45° right triangle have ratio:

h ÷ l = √2 ÷ 1

Substitute given values and find x:

x ÷ 6√2 = √2x = 6√2 × √2 x = 12

please help and show work

Answers

[tex]x=0=>0^{5} +32 = ( 0 +2 ) ^ 5[/tex]

P/s:    [tex]0^5+32=32 , (0+2)^5=2^5 =32[/tex]

[tex]x=-2=> (-2)^5 + 32 = ( -2 +2 )^5[/tex]

P/s:    [tex](-2)^5 +32 = -32+32=0, (-2+2)^5=0^5=0[/tex]

ok done. Thank to me :>

How many times does it intersect on the graph? y=x^2+3x-2, y-x=4

Answers

it intersects twice :)

A glass cube of side length 5cm has a mass of 306.25g.
Calculate the density of the glass in glcm3.
You must show you working’s

Answers

Answer:

2.45 g/cm3

Step-by-step explanation:

It's a cube, so all the side lengths are the same. It's volume is [tex](5cm)^3[/tex] = [tex]125 cm^3[/tex].

At this point, we apply the definition of density [tex]\rho = \frac mV[/tex] where m is the mass and V the volume.[tex]\rho = \frac{306.25g}{125 cm^3} = 2.45 g/cm^3[/tex]

a garden snail moves 1/6 foot in 1/3 hours. Find the speed of the snail in feet per hour

Answers

(1/6)/(1/3)
1/6 x 3/1
1/6 x 3
3/6
1/2

3/6 = 1/2 fph = .5fph

2. Select all of the trips that would take 4 hours. a. Drive 40 miles per hour between Gotham City and Smallville, which are 160 miles apart. Take a plane going 900 kilometers per hour from Town A to Town Z. which are 3,600 kilometers apart. c Walk 3.2 miles per hour to the grocery store, which is 8 miles away.​

Answers

Answer:

i think the answer is 50 if not im sorry if there is another go for that one.

Step-by-step explanation:

(3x-6)/(x^2+2) what is the answer

Answers

If you are asking to simplify the answer is
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