1. Professor Cramer determines a final grade based on attendance, two papers, three major tests, and a final exam. Each of these activities has a total of 100 possible points. However, the activities carry different weights. Attendance is worth 3%, each paper is worth 6%, each test is worth 19%, and the final is worth 28%.

(a) What is the average for a student with 81 on attendance, 62 on the first paper, 86 on the second paper, 78 on test 1, 68 on test 2, 68 on test 3, and 87 on the final exam? (Round your answer to one decimal place.)

(b) Compute the average for a student with the above scores on the papers, tests, and final exam, but with a score of only 17 on attendance. (Round your answer to one decimal place.

Answers

Answer 1

Answer:

Ur final grade will go down if you are looking for answers buddy! :)

Step-by-step explanation:

Answer 2

a) The average for a student with the given scores is 76.3 (rounded to one decimal place).

b) The average for a student with the given scores, but with a score of only 17 on attendance, is 74.4 (rounded to one decimal place).

Here, we have,

To calculate the average for the given scores, taking into account the different weights of each component, we can use the following steps:

(a) Average with the given scores:

To calculate the average with the given scores, we multiply each score by its respective weight, then sum up the results.

Here's the calculation:

Average = (Attendance * 0.03) + (First Paper * 0.06) + (Second Paper * 0.06) + (Test 1 * 0.19) + (Test 2 * 0.19) + (Test 3 * 0.19) + (Final Exam * 0.28)

Substituting the given scores:

Average = (81 * 0.03) + (62 * 0.06) + (86 * 0.06) + (78 * 0.19) + (68 * 0.19) + (68 * 0.19) + (87 * 0.28)

Average = 2.43 + 3.72 + 5.16 + 14.82 + 12.92 + 12.92 + 24.36

Average = 76.33

Therefore, the average for a student with the given scores is 76.3 (rounded to one decimal place).

(b) Average with a score of 17 on attendance:

Using the same calculation method as above, substituting the attendance score:

Average = (17 * 0.03) + (62 * 0.06) + (86 * 0.06) + (78 * 0.19) + (68 * 0.19) + (68 * 0.19) + (87 * 0.28)

Average = 0.51 + 3.72 + 5.16 + 14.82 + 12.92 + 12.92 + 24.36

Average = 74.41

Therefore, the average for a student with the given scores, but with a score of only 17 on attendance, is 74.4 (rounded to one decimal place).

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Step-by-step explanation:

Common Sense

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Answer:

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