simplify. (x+2)(x-1)-2(x+1)
Answer: x²-x-4
Explanation:
Here, we are going to use the FOIL method to simplify.
FirstOuter Inner Last--------------------------------------------------------------------------------------
Given
(x+2)(x-1)-2(x+1)
Expand parenthesis
= x²-x+2x-2-2x-2
Put like terms together
= x²-(x-2x+2x)-(2+2)
Combine like terms
= x²-x-4
Hope this helps!! :)
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Answer:
x² - x - 4
Explanation:
Multiply the parentheses
x² - x + 2x - 2 - 2 (x + 1)
Distribute -2 through the parentheses
- 2 (x + 1)
Since two opposites add up to zero, remove them from the expression
x² - x - 2 - 2
Calculate the difference
x² - x - 4
3.9. How long will a boy sitting near the window of a train travelling at 36km/h see a train passing by in the opposite direction with a speed of 18km/h. The length of the slow-moving train is 90 m.
Answer:
please give me brainlist and follow
Explanation:
Given:
The speed of the train ,which the boy is observing(t) = 18 km/hr
[ Now , to convert km/hr into m/s we have to multiply by 5/18 ]
So,
speed of the observed train = 18× 5/18
☞ 05 m/s
Also, The speed of the train in which the boy is sitting is(s) = 36 km/hr
Speed in m/s will be = 36 × 5/18
☞ 10 m/s
Also, The Length of the Train = 90m
Therefore:.
The speed of the train is given (expressed) by
= > speed \: = \frac{distance}{time}=>speed=
time
distance
= > time \: = \frac{distance}{Velocity }=>time=
Velocity
distance
Where,
velocity = Realtive velocity of both trains
Distance = Length of the train
So, The above mentioned formulae can also be written as :
= > time = \frac{length}{relative \: velocity}=>time=
relativevelocity
length
Here,
Relative velocity will be :
☞. s -(-t)
☞. 10 -(-5)
☞.15 m/s = Relative velocity
Now , Finally putting the values in the formulae respectively
■ Time = 90/15
■ Time = 6 sec [Answer]
The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave?
SOLVE IT COMPLETELY
The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave ?
Answer:-Given:-Velocity (V) = 40 m/s
Wavelength [tex] (\lambda) [/tex] = 80 cm = 0.8 m
To Find:-The frequency (F) of the wave.
Solution:-We know,
[tex] \bf V \: = \: F \: × \: \lambda [/tex]
40 = F × 0.8
F = [tex] \frac{40}{0.8} [/tex]
F = 50
The frequency of the wave is 50 Hz. [Answer]A capacitor is constructed of two large, identical, parallel metal plates separated by a small distance d
a. True
b. False
why do substance takes long to condense than freezing?
A 2.5 V battery is connected to a small light
bulb with a resistance of 4.8 Ω .
What is the current in the bulb?
Answer in units of A.
Answer: I=0.52 A
Explanation:
Given
Voltage is [tex]2.5\ V[/tex]
Resistance [tex]R=4.8\ \Omega[/tex]
Current is given by
[tex]I=\dfrac{V}{R}[/tex]
[tex]\Rightarrow I=\dfrac{2.5}{4.8}=0.52\ A[/tex]
What is the velocity of an object that travels 200 meters in 20 seconds?
Answer:
10m/s
Explanation:
velocity=displacement/time
=200/20
=10m/s
A 1,500-kg truck has a net force of 4,200 N acting on it. What is the truck’s acceleration?
Answer:
Acceleration = 2.8 m/s²
Explanation:
Given the following data;
Mass = 1500 kg
Net force = 4200 Newton
To find the truck's acceleration;
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
[tex] Acceleration = \frac {Net \; force}{mass} [/tex]
Substituting into the formula, we have;
[tex] Acceleration = \frac {4200}{1500} [/tex]
Acceleration = 2.8 m/s²
Current I flows along the positive z-direction in the inner conductor of a long coaxial cable and returns through the outer conductor. The inner conductor has radius a, and the inner and outer radii of the outer conductor are b and c, respectively. (a) Determine the magnetic field in each of the following regions: 0 ≤ r ≤ a, a ≤ r ≤ b, b ≤ r ≤ c, and r ≥ c. (b) Plot the magnitude of H as a function of r over the range from r = 0 to r = 10 cm, given that I = 10 A, a = 2 cm, b = 4 cm, and c = 5 c
Answer:
A) determine magnetic fields
For 0 ≤ r ≤ a
Magnetic field = ∅ [tex]\frac{rI}{2\pi a^2}[/tex]
For a ≤ r ≤ b
Magnetic field = ∅ [tex]\frac{I}{2\pi r}[/tex]
For b ≤ r ≤ c
Magnetic field in the region = ∅ [tex]\frac{I}{2\pi r} [ c^2 - r^2 / c^2-b^2 ][/tex]
For r ≥ c
magnetic filed in the region = 0
B ) attached below
Explanation:
A) Determine the magnetic field in the following regions
i) For 0 ≤ r ≤ a
Magnetic field = ∅ [tex]\frac{rI}{2\pi a^2}[/tex]
attached below is the detailed solution
ii) For a ≤ r ≤ b
Magnetic field = ∅ [tex]\frac{I}{2\pi r}[/tex]
attached below is the detailed solution
iii) For b ≤ r ≤ c
Magnetic field in the region = ∅ [tex]\frac{I}{2\pi r} [ c^2 - r^2 / c^2-b^2 ][/tex]
attached below is the detailed solution
iv) For r ≥ c
magnetic filed in the region = 0 and this is because the net current enclosed in the region = 0
A system consists of two particles. Which of the following scenarios would the force on each particle increase the most? If multiple scenarios would increase it by the same amount, select all that apply.
Group of answer choices
Doubling the distance between the particles.
Halving the distance between the particles.
Doubling one charge.
Doubling both charges
Doubling one charge, halving the other.
Halving one charge.
halving both charges.
Answer:
c
Explanation:
An object is placed at one of the two focal points of a thin converging lens. Where will its image form?
A. the other focal point of the lens
B. in the middle of the lens
C. an infinite distance from the lens
D. the same position as the object
Answer:
C. an infinite distance from the lens
Explanation:
There are five distinct cases of image formation in a convex lens depending upon the position of an object:
1. When the object is placed at an infinite distance from the lens, its real image is formed at the focal point.
2. When the object is placed before the center of curvature of the lens, its real image is formed between the center of curvature and the focal point.
3. When the object is placed at the center of curvature of the lens, its real image is formed at the center of curvature.
4. When the object is placed between the center of curvature and the focal length of the lens, its real image is formed behind the center of curvature.
5. When the object is placed at the focal point of the lens, its virtual image is formed at infinity.
Hence, from point 5 the answer is:
C. an infinite distance from the lens
1pt The process by which rock minerals are changed by natural processes into new substances is known as:
O A. erosion.
O B. chemical weathering.
O C. sedimentation.
O D. mechanical weathering.
The process by which rock minerals are changed by natural processes into new substances is known as chemical weathering. Option A is correct.
What is weathering?The breakdown or dissolution of rocks and minerals on the Earth's surface is referred to as weathering.
Weathering is the erosion or disintegration of rocks, building materials, etc., induced by chemical interactions dissolved in it rather than by mechanical processes.
Water, ice, acids, salts, plants, animals, and temperature variations are all weathering agents.
Chemical weathering is the process by which rock minerals are transformed into new compounds by natural processes.
Hence, option A is correct.
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Aluminum has a shear strength of 210 megapascals. When you bend aluminum foil around an edge (i.e., the edge of the box) and pull, you are effectively applying a shear force along the bent edge of the foil. If a roll of household aluminum foil is 30.0 centimeters wide and its thickness is approximately 15.0 micrometers, how much shear force is needed to pull off a sheet
Answer:
The answer is "[tex]945\ N[/tex]"
Explanation:
Aluminum has 210 megapascals of tensile resistance. They choose a shear force only at bent foil edge to bend aluminum foil over an edge (that is the edge of its box) to pull them. When a roll of aluminium domestic foil is 30 cm in width and about 15.0 micrometers.
[tex]\to 0.000015 \times 0.300 = 0.0000045\\\\\to 210000000 = \frac{F}{0.0000045}\\\\\to F=210000000 \times 0.0000045\\\\\to F = 945\ N[/tex]
What is the speed of a 1.57 N bullet traveling with a total momentum equal to 131 Kg.m/s?
Answer:
https://web.njit.edu/~binchen/phys111/LectureNotes/Physics111_lecture08.pdf
Explanation:it's 38 slides so look at the more bottom ones and there will be your question and answer
An astrophysicist mounts two thin lenses along a single optical axis (the lenses are at right angles to the line connecting them, and they appear concentric when viewed from either end). The lenses are identical, each with a positive (converging) focal length of 15.2 cm. They are separated by a distance of 40.2 cm. Lens 1 is to the left of Lens 2. In order to evaluate the lens combination as a single optical instrument, the teacher places an object 30.0 cm in front of (to the left of) Lens 1.
Required:
a. What is the final image's distance (in cm) from Lens 2? (Omit any sign that may result from your calculation.)
b. Where is the final image located?
c. What is the overall magnification of the lens pair, considered as a single optical instrument?
Answer:
1 / i + 1 / o = 1 / f thin lens equations
i = o f / (o - f) rearranging
Lens 1: object = 30 cm f = 15.2 cm
i1 = 30 * 15.2 / (30 - 15.2) = 30.8 cm
o2 = 40.2 - 30/8 = 9.4 cm distance of image 1 from lens 2
i2 = 9.4 * 15.2 / (9.4 - 15.2) = - 24.6 cm
The final image is 24.6 cm to the left of lens 2
The first image is inverted
The second image is erect (as seen from the first image)
So the final image is inverted
M = m1 * m2 = (-30.8 / 30) * (24.6 / 9.4) = -2.69
It can be deduced that the final image's distance from Lens 2 will be 30.8 cm.
How to calculate the distanceBy using the Lens formula, the distance will be calculated thus:
1/v + 1/u = 1/15.2
1/v + 1/30.0 = 1/15.2
v = 30.8cm
In this case, the image formed will be to the right.
Lastly, the overall magnification of the lens pair will be:
M = (30.8/30.0)[(-28.4/40.7 - 30.8)]
M = -2.94.
In conclusion, the magnification is -2.94.
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Research DNA phenotyping and make a list of pros and cons. What are its possible advantages? What might go wrong? Would it change investigations for the better, or create unfair bias? Think about how this technology would impact forensics, law enforcement, and the public in general. List at least three arguments for and three arguments against it. (1 sentence/phrase each)
Answer:
Pros of DNA phenotyping:
-Phenotypical characteristics can be predicted such as eye color, hair color, skin pigmentation, and many more.
-predict ancestry of an organism
-Use to find criminals
Cons of DNA phenotyping:
-Some phenotypical traits could not be predicted
- Invading privacy
This technology will surely help forensics, law enforcement as it helps track down unknown perpetrators of crime.
3 arguments for it:
- accurate in narrow down researches
- finding biological ancestry
3 arguments against it
It violates the privacy policy of an individual
Racial discrimination is done of public
Equality policies are not followed by it.
The continuous changing of rocks from one kind to another is called:
Question 5 options:
Metamorphosis
Extrusion
The carbon cycle
The rock cycle
The continuous changing of rocks from one kind to another is called as the Rock cycle. So, the correct option is D.
What is Rock cycle?The rock cycle is defined as the change of rocks from one form to another as molten magma cools down and becomes an igneous rock which then breaks down into sediments and again forms sedimentary rocks under great pressure. The same rock that can become a metamorphic rock when subjected to great heat and pressure.
Every rock type is altered when it is forced out of its equilibrium conditions. Rock cycle is explained as the chain of processes which produce and transform the rock types in Earth's crust.
Thus, the continuous changing of rocks from one kind to another is called as the Rock cycle. So, the correct option is D.
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A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from the impact: one travels in the air and the other in the concrete, and they are 0.70 ss apart. The speed of sound in air is 343 m/sm/s, and in concrete is 3000 m/sm/s. Part A How far away did the impact occur
Answer:
271.095 m
Explanation:
✓ Let speed of sound in air that was given as (343 m/s) be represented as (Vi)
✓( speed of sound in concrete that was given as (3000 m/s ) be debited as (Vc)
✓ Let the distance travelled by the sound = s
✓duration of Time that exist between heard of sounds = 0.70s
But we know that
Time = (Distance / Speed)
✓Time it takes the sound to travel through air= s/vi = s/343
✓Time it takes the sound to travel through concrete= s/vc = s/3000
✓ (s/343) - (s/3000) = 0.70
Finding LCM and simplify
[(3000s - 343s)]/1029000 = 0.70
2657s /1029000 = 0.70
Making " s" subject of the formula
s= (1029000 × 0.70)/2657
s=720300/ 2657
s= 271.095 m
Hence, The impact took place at a distance of 271.095 m away from the person.
The light waves transfer their oscillations and energy to other object in what way?
The frequency of the light waves physically causes the object to move
The energy of the light wave transfers to the electrons of the material which causes them to gain that energy
The wavelength of the light changes the velocity of the atoms in the material
The amplitude of the light will affect how much of it shines on the object
Answer: b the energy of light...
Explanation:
The two uniform, slender rods B1and B2, each of mass 2kg, are pinned together at P, and then B1is suspended from a pin at O. (This arrangement is called a double pendulum.) The counterclockwise couple C0, having moment 150????⋅m, is applied to B2beginning at t=0. Find the angular accelerations of B1and B2upon application of the couple, and the force exerted on B2at P.
Answer:
hello the diagram relating to this question is attached below
a) angular accelerations : B1 = 180 rad/sec, B2 = 1080 rad/sec
b) Force exerted on B2 at P = 39.2 N
Explanation:
Given data:
Co = 150 N-m ,
a) Determine the angular accelerations of B1 and B2 when couple is applied
at point P ; Co = I* ∝B2'
150 = ( (2*0.5^2) / 3 ) * ∝B2
∴ ∝B2' = 900 rad/sec
hence angular acceleration of B2 = ∝B2' + ∝B1 = 900 + 180 = 1080 rad/sec
at point 0 ; Co = Inet * ∝B1
150 = [ (2*0.5^2) / 3 + (2*0.5^2) / 3 + (2*0.5^2) ] * ∝B1
∴ ∝B1 = 180 rad/sec
hence angular acceleration of B1 = 180 rad/sec
b) Determine the force exerted on B2 at P
T2 = mB1g + T1 -------- ( 1 )
where ; T1 = mB2g ( at point p )
= 2 * 9.81 = 19.6 N
back to equation 1
T2 = (2 * 9.8 ) + 19.6 = 39.2 N
Al, Bo, Cy, Di, Ed, and Fred assumed different positions in the room as shown in the image below. Their reflections are marked in red with the apostrophe.
Check all the reflections Ed can see
Answer:
A<L BO DI ED
Explanation:
a. Draw four rays parallel to the optical axis of your mirror. Two above the optic axis and two below it.
b. Trace the rays all the way to the surface of the spherical cap.
c. Draw a normal to the surface of the mirror at each of the four points where the rays touch the mirror.
Answer:
f = q
Explanation:
In the attachment we can see a diagram of the parallel rays.
The dotted line represents the normal to the mirror surface
These rays when reflected using the constructor equation
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
where p and q are the distance to the object and the image respectively.
Since the rays are parallel P = inf
1 / f = 1 / inf + 1 / q
f = q
this means that all the rays focus on one focal point.
What is the wavelength associated with 0.113kg ball traveling with velocity of 43 m/s?
Answer:
Wavelength = [tex]1.36\times 10^{-34}\ m[/tex]
Explanation:
Given that,
The mass of a ball, m = 0.113 kg
Velocity of the ball, v = 43 m/s
We need to find the wavelength of the ball. It can be calculated by applying the De-Broglie concept. So,
[tex]\lambda=\dfrac{h}{mv}[/tex]
Put all the values,
[tex]\lambda=\dfrac{6.63\times 10^{-34}}{0.113\times 43}\\\\=1.36\times 10^{-34}\ m[/tex]
So, the wavelength of the ball is equal to [tex]1.36\times 10^{-34}\ m[/tex].
1. What is the relationship between electricity and magnetism?
Answer:
Electricity and magnetism are two related phenomena produced by the electromagnetic force. Together, they form electromagnetism. A moving electric charge generates a magnetic field. A magnetic field induces electric charge movement, producing an electric current.
A graph of a wave is shown if the frequency f is 8.0 Hz what is the waves speed
Answer:
C
[tex]6 = \frac{3}{2} \lambda \\ wavelength : \: \lambda = 4 \: m \\ from \: wave \: equation \\ v = f\lambda \\ v = 8 \times 4 \\ v = 24 \: {ms}^{ - 1} [/tex]
The speed of the waves will be = [tex]24\dfrac{m}{s}[/tex]
Given data is frequency f = 8.0 Hz
What will be the speed of the wave?As we know that the speed of the wave is given by the formula below
[tex]V=f\times \lambda[/tex]
Since
[tex]6=2 \lambda[/tex]
[tex]\lambda =3m[/tex]
now
[tex]V=8\times3[/tex]
[tex]V=24m[/tex]
The speed of the waves will be = [tex]24\dfrac{m}{s}[/tex]
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Groups of organs that work together to complete a series of takes are called:
A: Skeletal System
B: Organ System
C: Muscular System
A group of organs working together comprises an organ system, B.
A sinusoidal electromagnetic wave is propagating in a vacuum in the z-direction. Part A If at a particular instant and at a certain point in space the electric field is in the x-direction and has a magnitude of 4.70 V/mV/m, what is the magnitude of the magnetic field of the wave at this same point in space and instant in time
Answer:
the magnitude of the magnetic field is 1.23 × 10⁻⁸ T { in the +y direction }
Explanation:
Given the data in the question;
the relation between the electric field and the magnetic field in an electromagnetic wave can be written as follows;
c = E₀/B₀
where c is speed of light, E₀ is the amplitude of the electric field and B₀ is the amplitude of the magnetic field.
given that; E₀ = 4.70 V/m, we know that; speed of light c = 3 × 10⁸ m/s
so from our relation; c = E₀/B₀
B₀ = E₀/c
we substitute
B₀ = 4.70 / 3 × 10⁸
B₀ = 1.23 × 10⁻⁸ T { in the +y direction }
Therefore, the magnitude of the magnetic field is 1.23 × 10⁻⁸ T { in the +y direction }
An ampere is measured in
Seconds
Hours
Answer:
Seconds
Explanation:
Hope it helps you in your learning process.
The rate of flow of charge (per second) through a conductor is called electric current.
S. I unit of electric current is Ampere (named after French Physicist Andre Marie Ampere)
In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested traveling at close to the speed of light. Suppose you wish to visit the red giant star Betelgeuse, which is 430 lyly away, and that you want your 20,000 kgkg rocket to move so fast that you age only 36 years during the round trip.
A. How fast (v) must the rocket travel relative to earth?
B. How much energy is needed to accelerate the rocket to this speed?
C. How many times larger is this energy than the total energy used by the United States in the year 2000, which was roughly 1.0 x 10^20 J?
Answer:
a) [tex]v=0.999124c[/tex]
b) [tex]E=7.566*10^{22}[/tex]
c) [tex]E_a=760 times\ larger[/tex]
Explanation:
From the question we are told that
Distance to Betelgeuse [tex]d_b=430ly[/tex]
Mass of Rocket [tex]M_r=20000[/tex]
Total Time in years traveled [tex]T_d=36years[/tex]
Total energy used by the United States in the year 2000 [tex]E_{2000}=1.0*10^20[/tex]
Generally the equation of speed of rocket v mathematically given by
[tex]v=\frac{2d}{\triangle t}[/tex]
[tex]v=860ly/ \triangle t[/tex]
where
[tex]\triangle t=\frac{\triangle t'}{(\sqrt{1-860/ \triangle t)^2}}[/tex]
[tex]\triangle t=\frac{36}{(\sqrt{1-860/ \triangle t)^2}}[/tex]
[tex]\triangle t=\sqrt{(860)^2+(36)^2}[/tex]
[tex]\triangle t=860.7532[/tex]
Therefore
[tex]v=\frac{860ly}{ 860.7532}[/tex]
[tex]v=0.999124c[/tex]
b)
Generally the equation of the energy E required to attain prior speed mathematically given by
[tex]E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2[/tex]
[tex]E=7.566*10^{22}[/tex]
c)Generally the equation of the energy [tex]E_a[/tex] required to accelerate the rocket mathematically given by
[tex]E_a=\frac{E}{E_{2000}}[/tex]
[tex]E_a=\frac{7.566*10^{22}}{1.0*10^{20}}[/tex]
[tex]E_a=760 times\ larger[/tex]
Which object had the greatest average speed?
A
B
C
D