1. What is the direction of the induced current in the front side of the coil?
a. Left
b. Right
c. Up
d. down


2. in what direction is the magnet moving?
a. Away
b. Toward
c. Up
d. Down

Answer:

Newton's First Law

Explanation:

As you had already mentioned the explanation about the querry you have,

I accept the reasons you have mentioned.

Definitely an upward force will balances the downward force on the skydiver, And the unbalanced force pulls the skydiver towards ground was the Gravitational force. As there is no any other acceleration, the velocity of the skydiver towards the ground is 9.8.

The skydiver's motion can vary in different views like,

1. A person in the plane view is a parabolic path.

2. A person from the ground view is straight line path.

So, the skydiver's motion varies according to the observer view.

date: 09-10-2022

Answer: A

Explanation: yes

The direction of the net force acting on an object defines the direction of its acceleration. The acceleration of the plane is 8.75 m/s².

Any procedure where the velocity varies exists directed to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This exists because velocity exists both a speed and a direction.

The initial speed of a plane is [tex]$v_{i s}[/tex] = 300 m/s

Distance covered by plane is s = 4 km = 4000m

The final speed of the plane is [tex]$$v_{f s}[/tex] = 400 m/s

The acceleration of the plane.

Using kinematical equation v²[tex]{ }_{f s}[/tex] = v²[tex]{ }_{\text {is }}[/tex] + 2as

Substitute known values in the above equation, we get

400² = 300² + 2 a(4000)

simplifying the above equation, we get

400² -300² = 8000 a

a = 70000/8000

= 8.75 m/s²

Therefore, the acceleration of the plane is 8.75 m/s².

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Answer:

If the mass is doubled, then acceleration will be halved.

Explanation:

That situation is described by Newton's Second Law of Motion. F is force, m is mass and a is acceleration. The math behind this is quite simple. If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.

According to Newton's Second law of Motion, the acceleration of the mass spring system will be halved if the mass of the spring system is doubled.

Newton's second law of motion states that when an external net force is applied on an object, the acceleration of the object is proportional to the net force which is applied on the object, and it also occurs in the same direction as the direction of applied force. The acceleration of an object is inversely proportional to the net force applied and acceleration is inversely proportional to the mass of the object.

This situation can be best described by Newton's Second Law of Motion. The second law of motion can be expressed by the equation:

F = m × a

where, F is force,

m is mass, and

a is acceleration

Mass of an object is inversely proportional to the acceleration of the body. If the mass of the spring system is doubled then the acceleration of the object will be reduced to half.

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Answer:

44 ohms.

Explanation:

R for V (according to Ohm's law). This second formula is more frequently used in practice to calculate resistive heating, whereas the first formula has other, more general applications. As we might infer from the equation, the units of watts also correspond to amperes2 x ohms (A2 x Ω).

Answer:

Oxygen gas is two oxygen atoms bonded together, O2. Water, is one oxygen atom bonded to two different hydrogen atoms, H2O

Explanation:

A missile is moving 1810 m/s at a 20.0 angle. it needs to hit a target 19,500 m away in a 32.0 direction in 9.20 s. The acceleration that the engine must deliver is 112 meters per second.

The term "acceleration" refers to the rate of change in the object's velocity in relation to time, and it is measured in meters per second (m/s). In most contexts, meters per second squared is the unit of measurement for acceleration.

Let us start by thinking about the component that is horizontal in the x direction.

The length of travel in a plane horizontal to the starting point.

x = 19,500 cos 32.0° m

Using the second equation of motion to determine acceleration along the horizontal axis in order to:

[tex]x = ut + 1/2at^2[/tex]

[tex]19,500 * (cos 32.0^0 = 0 + (1810* cos 20.0^o) *9.20+ 0.5*a *9.20^2[/tex]

a = 21.01 m/s²

The same may be said for the vertical direction.

The distance traveled in the upward and downward directions combined.

Y is the velocity in the vertical direction, and it is equal to 19,500 in 32.0° m.

u= 1810 sin 20.0° m/s

t = 9.20 s

For the purpose of determining acceleration along the vertical axis by using the second equation of motion, For the purpose of determining acceleration along the vertical axis by using the second equation of motion

[tex]y = ut +1/2at^2[/tex]

19,500 sin 32.0° = 0 + (1810 sin 20.0^o)* 9.20 + 0.5*a* 9.20^2

a = 109.6 m/s^2

The resultant acceleration

[tex]a^2 = (21.01)^2 + (109.6)^2[/tex]

a = 112 m/s²

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The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort. Use Newton's second law to determine the friction force on the block.

The work-kinetic energy theorem can be used to provide a solution to this issue. Start by calculating how far the block will travel up the ramp. The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort.

You can use a free body diagram and Newton's second law to calculate the frictional force on the block. The frictional energy is calculated as the frictional force multiplied by the distance the block travels up the ramp.

The distance climbed up the ramp will also affect how much the gravitational potential energy changes. You can now generate kinetic energy.

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The efficiency of the engine is 60%.

The efficiency of a heat engine describes the amount of input energy converted into useful work.

It also entails the amount of useful work done by the engine. The greater the amount of useful work done by the engine, the greater the efficiency of the engine.

The efficiency of an engine ranges from 0 to 100%.

If there four stages in the energy conversion cycle, and 10% energy is wasted in each cycle, the total energy wasted in the four cycles is calculated as;

Total wasted energy = 4 x 10% = 40%

Efficiency of the engine = Useful energy = 100% - 40% = 60%

Thus, the efficiency of the engine is the useful work done by the engine.

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Answer: The Earth's gravity is too strong.

Explanation: I don't have a full understanding, but probably the Earth is too strong. If you push yourself up, it'll feel difficult.

A dragster gets to a speed of 112 m/s over a distance of 300 m from the rest, then the acceleration will be 20.9 m/s².

The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.

According to the question, the given values are :

Final velocity, v = 112 m/s.

Initial velocity, u = 0 m/s

Distance, s = 300 m.

Use the equation of motion,

v² - u² = 2as

112 ² - 0 = 2 (a)(300)

a = 12544/600

a = 20.9 m/s².

Hence, the acceleration of the dragster will be 20.9 m/s².

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The final vertical velocity of the soccer ball is 20 m/s.

We need to know about the projectile motion to solve this problem. The projectile motion is known as parabolic motion and the velocity is divided by 2 axes.

vox = vo cosA

voy = vo sinA

where vox is initial velocity of x axis, voy is initial vertical velocity, vo is initial velocity and A is the angle.

From the question above, the given parameters are

vox = 15 m/s

h = 40 m

x = 60 m.

The time taken of horizontal motion will be

x = vox . t

60 = 15 . t

t = 4 s

By using the uniform motion, where vty = 0 m/s and time taken to reach the peak is half of total time. Hence

vty = voy - gt

0 = voy - 10.(1/2 . 4)

voy = 20 m/s

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The force needed to accelerate a car at 5 m / s² that has a mass of 3,000 kg is 15 KN

F = m a

F = Force

m = Mass

a = Acceleration

m = 3000 kg

a = 5 m / s²

F = 3000 * 5

F = 15000 N

F = 15 KN

According to Newton's second law of motion, the force is equal to the rate of change of momentum of the object.

Therefore, the acceleration of the car is 15 KN

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Answer:

9.8 seconds

Explanation:

Power = work / time

work = F * d     =   200kg ( 9.81 m/s^2 ) * 4 m = 7818 J

800 W = 7818 J / t       t = ~ 9.8 seconds

Answer:

6.3 m

Explanation:

Work = force   X    distance

 600 = 95   x   d

d = 600/95 = 6.3 m

In order the weight feels tripled, the elevator should be moving upward with acceleration 2g m/s² or two times of gravitational acceleration.

The free body diagram is shown on the attached picture.

The scale will read the normal force.

Suppose the elevator is moving upward. Using the Newton's second law of motion:

∑F = m.a

N - w = ma

N = mg + ma

Suppose the elevator is moving downward.

w - N = ma

N = w - ma

N = mg - ma

Where:

m = mass

a = acceleration

g = gravitational acceleration

From the above 2 cases, in order the scale to read the measured weight higher than its actual weight, N should be greater than w, or N = mg + ma, or the elevator should be moving upward.

The weight feels tripled means N = 3 mg.

Hence,

3 mg = mg + ma

a = 3g - g = 2g

Therefore, in order the weight feels tripled, the elevator should be moving upward with acceleration 2g m/s²

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Answer:

V = a t

t1 = 15 / 9.8 = 1.53 sec       time to reach 0 speed

t2 = t1 = 1.53 sec        time to reach point thrown

t3 = 5 - 2 * 1.53 = 1.94 sec    time to fall height of cliff

H = V0 t - 1/2 g t^2       time to fall height of cliff   (if V0 positive)

V0 = -15 m/s since it will return to thrown height with speed thrown up

Signs chosen must be consistent

H = -15 * 1.94 - 1/2 9.8 * 1.94^2 = -47.5 m where H is height of cliff

The

k=4 n/m, A=0.09 m, and m=0.617 kg.

1) T = m/n square root of 2 pi T = 2.466 sec

2) where w = 3.4606 rad/s and w = square root of k/m

Vmax = A*w = 0.311 m/s 3) a max = A*w*w  

 a max =7.389 m/s square

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The radius of the cylinder is 0.43 cm while the uncertainty is 0.04. This can likely be expressed as 0.43 +/- 0.04 cm

Absolute uncertainty or error is the difference between measured value of a quantity and the actual value.

Given an expression for the volume of a cylinder to be

V = πr²h

Where

From the formula, make radius r the subject of the formula and calculate the radius

V = πr²h

r² = V/πh

r = √(V/πh)

r = √12/21π

r = √12/65.97

r = √0.18

r = 0.43 cm

The uncertainty Δr will be

Δr/r = (ΔV/V + Δh/h) × 2

Δr/0.43 = (0.5/12 + 0.1/21) × 2

Δr/0.43 = (0.0417 + 0.0048) × 2

Δr/0.43 = 0.093

Δr = 0.093 × 0.43

Δr = 0.0399

Δr = 0.04

Therefore, the radius of the cylinder is 0.43 +/- 0.04 cm

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The answer is true!!!!!!!!!!!

Answer:

Explanation:

(I) Electrical energy into sound energy. (ii) Heat energy into kinetic energy (or mechanical energy). (iii) Chemical energy into kinetic energy (or mechanical energy). (iv) Chemical energy into heat energy

Answer:

it is defined as the study of living things and their environment

The speed of the car when the load is dropped in it is 10.90 m/s.

Using the data given above:

Mass of the railroad car, m₁ =  12100kg

Mass of the load, m₂ =  4790kg

It can be assumed as the speed of the car, u₁ = 10 m/s

So, it is at rest, u₂ = 0

Here we assume the speed of the car be v

Using law of conservation of energy

Thus:

m1v1 + m2v2 = (m1v1)/ (m1 + m2)

= 12100*10 / 12100 + 4790

121000/16890

= 7.16 m/s

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If the resultant force acting on the van is 1500 Newtons, then the magnitude of Force X would be 1500 Newtons as X is the only horizontal force opposing the motion of the van.

Newton's Second Law states that the resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem statement If the resultant force acting on the van is 1500 Newtons, then we have to find the magnitude of Force X,

The magnitude of the Force X = 1500 Newtons

Thus, the magnitude of the force X would be 1500 as it is the only force acting on the van.

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Answer:

.12 * .12 = .0144        counterclockwise torque

.06 * .18 + W * .03 = .0108 + .03 W        clockwise torque

W = (.0144 - .0108) / .03 = .12 N     as requested

(.12 + .06 + .12) N = .30 N       total weight supported by thread

C) Suppose now rod supported at middle

.12 * .15 = .018 N      counterclockwise torque

.06 * .15 = .009 N     clockwise torque

Obviously the thread must be moved closer (left) to .12 weight to increase the clockwise torque (other weights are in the middle of the rod

An object has a mass of 10 kg and is pushed with a force of 2 N the object acceleration is  0.2m/s².

Given;

m = 10 kg

F = 2N

by using Newton's second law of motion that is the formula of force

F = ma

a =  F/m

a = 2/10

a = 0.2m/s²

An object is said to accelerate when its velocity changes. A change in the speed of an object can be an increase or decrease in speed or a change in  direction of motion. Some examples of acceleration are a falling  apple, the moon orbiting  the Earth, or  a car stopping at a traffic light. Using these examples, we can understand that when  a moving object changes direction or increases or decreases speed, acceleration occurs.

The  unit of acceleration is  meter per second per second (m/s2).

There are 2 types of acceleration

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Answer:

The extension of an elastic object when a force is applied, such as a spring, is described by Hooke's law: force = spring constant × extension.

The velocity of the cyclist when he grabs the branch is 36.1 m/s.

The final velocity of the cyclist is calculated as follows;

The final vertical velocity of the cyclist will be smaller than the initial vertical velocity due to opposing force of gravity.

Final vertical velocity of the cyclist, Vy = vi - vi sinθ

Vy = 32.25 - 32.25 sin(30)

Vy = 16.13 m/s

The final horizontal velocity will be constant.

Vx(final) = Vx(initial)

Vx = 32.25 m/s

Resultant final velocity = √Vx² + Vy²

Resultant final velocity = √(32.25² + 16.13²)

Resultant final velocity = 36.1 m/s

Thus, the final velocity of the cyclist will change when he grabs the overhanging tree branch.

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The Average speed is 42.44 km/h ,the distance between cities is 99.02kmSpeed is the rate at which something or someone is moving.

The average speed of an object can be determined if you know the distance traveled and the time it took. Distance times speed is how speed is computed. In order to compute the units for speed, you must be aware of the units for both distance and time. Given that the distance in this example is measured in metres (m) and the duration is recorded in seconds, the units will be metres per second (m/s) For the purpose of calculating the other two, we require the other two (time, speed, or distance). To determine how long it will take to complete a journey, for example, information about the distance and speed of travel is needed.

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