0.9541 grams of nickel (ii) hydroxide will be produced if 30.4 mL of 0.673 M KOH react completely and 1.3764 grams of nickel (ii) hydroxide will be produced if the 17.6 mL of 0.841 M NiCl₂ react completely.
According to the balanced chemical equation,
2KOH (aq) + NiCl₂ (aq) → 2 KCI (aq) + Ni(OH)₂ (S)
a. 2 Moles of KOH = one mole of Ni(OH).
As we know,
Molarity = moles/amount of solution(in liters)
For KOH,
0.675 = moles/0.0304
Moles of KOH = 0.02052.
Moles of Ni(OH) = 0.02052/2
Moles of Ni(OH) = 0.01026
We also know,
Moles = formed mass/molar mass
Molar mass of NiOH = 93 grams/mole
0.01026 = formed mass/93
Formed mass of NiOH = 0.9541 grams.
b. 1 Mole of NiCl₂ = one mole of Ni(OH).
As we know,
Molarity = moles/amount of solution(in liters)
For NiCl₂,
0.841 = moles/0.0176
Moles of NiCl₂ = 0.01480
Moles of Ni(OH) = 0.01480
We also know,
Moles = formed mass/molar mass
Molar mass of NiOH = 93 grams/mole
0.01480 = formed mass/93
Formed mass of NiOH = 1.3764 grams.
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Solid manganese(IV) oxide reacts with the solid aluminum metal to produce solid manganese and solid aluminum oxide. Balance the equation for this reaction (in the lowest multiple integers). What are the formulas for the reactants and products?
1. Balanced equation of the reaction = [tex]3MnO_2(s) + 4Al (s) -- > 2Al_2O_3(s) + 3Mn(s)[/tex]
2. Formulas of reactants
solid manganese (IV) oxide = [tex]MnO_2 (s)[/tex]
solid aluminum metal = [tex]Al(s)[/tex]
solid manganese = [tex]Mn (s)[/tex]
solid aluminum oxide = [tex]Al_2O_3 (s)[/tex]
Balancing chemical equationsA balanced chemical equation agrees with the law of conservation. In other words, the number of participating atoms must balance between the reactants and the products of the same equation.
Formula for solid manganese (IV) oxide = [tex]MnO_2 (s)[/tex]
Formula for solid aluminum metal = [tex]Al(s)[/tex]
Formula for solid manganese = [tex]Mn (s)[/tex]
Formula for solid aluminum oxide = [tex]Al_2O_3 (s)[/tex]
Thus, the balanced equation for the reaction is written as:
[tex]3MnO_2(s) + 4Al (s) -- > 2Al_2O_3(s) + 3Mn(s)[/tex]
One can see from the that the number of atoms of each element in the reactants is equal to the number of atoms of the same elements in the product.
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A 3.627g sample of a new organic material is combusted in a bomb calorimeter. The temp of the calorimeter and contents increases from 25.39 Celcius to 30.14 Celcius. Heat capacity (calorimeter constant) is 45.35 KJ/degree C. What is the heat of combusion per gram of the material.
I tried to work this out and need to know if this is correct:
I'm assuming -Qrxn =C(calorimeter) x Delta T
45.35J/degree C x 4.75 (which is change of T) = -20.67KJ since exothermic.
THen Delta Urxn= Qrxn/g of organic material.: -20.57KJ/g sample x gram sample/3.62g
This would be -5.699KJ/g.
Please let me know if this is correct or where I have made an error.
The heat of combustion per gram of the material is 59.4 kJ/g
What is the heat of combustion per gram?The heat of combustion per gram is the heat that is evolved when a substance is burnt in oxygen under standard condition. We know that combustion is an exothermic process thus it is clear that heat is given out.
Heat evolved = cdT
c = heat capacity
dT = temperature rise of the material
It then follows that;
Heat evolved = 45.35 * 10^3 J/degree C * (30.14 Celcius - 25.39 Celcius )
= 215412.5 J
Then;
heat of combustion per gram = 215412.5 J * 10^-3/3.627g
= 59.4 kJ/g
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10.00 moles of H2(g) react with 5.000 mol of O2(g) to form 10.00 mol of H2O(l) at 25°C and a constant pressure of 1.00 atm. If 683.0 kJ of heat are released during this reaction, and PΔV is equal to -37.00 kJ, then
10.00 moles of H₂(g) react with 5.000 mol of O₂(g) to form 10.00 mol of H₂O(l) at 25°C and a constant pressure of 1.00 atm. If 683.0 kJ of heat are released during this reaction, and PΔV is equal to -37.00 kJ, then ΔE° is 646.00kJ
Energy that is transferred from one body to another as the result of a difference in temperature called as heat
Here given data is
H₂(g) + O₂(g) → H₂O(l)
H₂(g) = 10.00 mole , O₂(g) = 5.000 mol , gives H₂O(l) = 10.00 mol and heat are released during this reaction are 683.0 kJ and PΔV is equal to -37.00 kJ then we have to find ΔE° = ?
ΔH° = 683.0 kJ
ΔE° = heat are released - PΔV
So, ΔE° = 683.0 kJ - 37.00 kJ
= 646.00kJ
And the calculated answer is the ΔE°
So, ΔE° = 646.00kJ
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What is the percent by mass of carbon in Al(CO3)3
The percent by mass of carbon in Al₂(CO₃)₃ is 15.38%.
Mass number(A) of various elements of molecule,
A of Aluminum(Al) = 27
A of Carbon(C) = 12
A of Oxygen(O) = 16
Total molecular mass or molecular weight is the sum of individual atomic masses of each atom in a molecule.
Thus, total molecular mass of molecule Al₂(CO₃)₃ is:
= 27×2 + (12 + 16 × 3)3
= 54 + 180
= 234
Hence, percent % of Carbon = (12×3/ 234)× 100
= (36/ 234 )× 100
= 15.38 %
Thus, the percent by mass of carbon is 15.38 %.
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Liquid octane (CH₂(CH₂)6 CH₂) reacts with gaseous oxygen gas (₂) to produce gaseous carbon dioxide (CO₂) & gaseous water (H₂O). If 85.8g of carbon dioxide is produced from the reaction of 31.98g of octane. & 190.4g of oxygen gas, calculate the percent yield of carbon dioxide.
The percent yield of carbon dioxide is 87%.
The balanced chemical equation for reaction of octane with oxygen,
CH₂(CH₂)₆CH₂+ 12O₂ → 8CO₂ + 8H₂O
We can use the mole concept here,
Mole = Given mass/molar mass.
From the reaction,
1 mole of Octane = 8 moles of carbon dioxide.
Now, moles of octane N,
N = 31.98/114.23
N = 0.2799
Moles of Carbon dioxide = 8 x 0.2799
Moles of Carbon dioxide = 2.239
Mass of CO₂ formed,
2.239 = Mass of CO₂/44
Mass of CO₂ = 98.54 grams/mole.
Percentage yield = theoretical mass/experimental mass x 100
Theoretical mass = 98.54 grams/mole.
Experimental mass = 85.8 grams/mole.
Percentage yield of CO₂ = 85.8/98.54 x 100
Percentage yield of CO₂ = 87%
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List all possible values of the magnetic quantum number ml for a 4p electron.
Answer:
-1, 0, 1
Explanation:
for n = 4
l = 0, 1, 2, 3
p corresponds to 1
so ml of 4p is -1, 0, 1
"What volume of 0.642 M [Molar ]magnesium Chloride (MgCl2, MM 95.21 g/mol) solution would be required to deliver 4.50g of MgCl2?"
Explanation:
n=m/MM
MM of MgCl2=95.2
n=4.5/95.211
M=n/V
0.652=0.0473/V
V=0.0724 L
=72 ml
Write and balance the equation for the decomposition of aluminum chloride into its elements. phase symbols are optional.
Balance the equation for the decomposition of aluminum chloride into its elements is 2AlCl₃ → 2Al + 3Cl₂
Decomposition reactions are processes in which chemical species break up into simpler parts and here given compound is aluminum chloride is hexahydrate is thermally decomposed to alumina by sequential treatment in two dense fluidized bed decomposers the first decomposer being operated at a temperature of about 200° to 400° C and the second at a temperature of about 900° to 1100° C
Here we have to write and balance the equation for the decomposition of aluminum chloride into its elements so balanced equation for aluminum chloride for decomposition is
2AlCl₃ → 2Al + 3Cl₂
2 mole of AlCl₃ gives 2 mole of Al and 3 mole of Cl₂
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write out step by step explanation of the process of fission
A bigger atom fission when a neutron smashes against it, causing it to excite and split into two smaller atoms known as fission products. A chain reaction may be initiated by other neutrons that are also released.
What examples of fission?By dissolving large, heavy atoms, like uranium, into smaller ones, like iodine, cesium, strontium, xenon, and barium, to name just a few, fission produces energy. To create the heavier helium, fusion combines light atoms, such as the two hydrogen isotopes deuterium and tritium.
Why is fusion so important?Nuclear fission fuels the explosion of nuclear weapons and creates energy for nuclear power. Due to the fact that certain compounds known as nuclear fuels undergo fission when impacted by fission neutrons and then break apart, both uses are feasible.
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molar mass of rhodonite mnsio3
The molar mass of rhodonite MnSiO₃ is 131.0 g.
What is the molar mass of a substance?The molar mass of a substance is the mass of 1 mole of that substance.
The molar mass of a compound is obtained from the sum of the product of the number of moles of atoms and the molar masses of the elements in the compound.
The molar mass of rhodonite MnSiO₃ is calculated as follows:
Molar mass of Mn = 55 g
Molar mass of Si = 28 g
Molar mass of O = 16.0 g
Molar mass of MnSiO₃ = 55 + 28 + 16 * 3
Molar mass of MnSiO₃ = 131.0 g
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Alkaline earth metals are found in group 2 and tend to ____ 2 electrons when combined with another element.
Alkaline earth metals are found in group 2 and tend to donate 2 electrons when combined with another element.
What is alkali metal?Alkali metal are those have one electron in their valence shell.It generally found in group 1 in the modern periodic table.Elements in this group involves hydrogen, lithium, sodium, potassium, rubedium, cesium, francium.These type of metal when react with another metal gives one electron in order to make their valence shell free and become stable.That's why their valency is +1.
Now,
What is alkaline earth metal?Alkaline earth metal are those have two electron in their valence shell.It generally found in group 2 in the modern periodic table.Elements in this group involves Beryllium, magnesium, calcium, strontium, barium , radium. These type of metal when react with another metal gives two electron in order to make their valence shell free and become stable.That's why their valency is +2.Now,
As per the given question,
Alkaline earth metals are found in group 2 and tend to donate 2 electrons when combined with another element.
Thus, from the above conclusion we can say that , alkaline earth metals are found in group 2 and tend to donate 2 electrons when combined with another element.
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1. How many grams would 3.07 moles of FeCl3 be?
Answer:
497.97 g
Explanation:
Fe weights 55.845 g
Cl weights 35.453g
1 mole FeCl3 = 55.845 + 3(35.453) = 162.204 g
=> 3.07 moles = 3.07(162.204) = 497.96628 or 497.97 g
How many atoms are there in 10 g of Kr?
From the periodic table, we know that 1 mole of Krypton has a molar mass of 83.798 grams/mole.
So 10 grams would have (10/83.798) which is 0.1193345903 moles.
If we multiply this by Avogadro's number, we get the amount of Krypton atoms in 10 grams.
0.1193345903 x 6.02 x 10^23 = 7.184 x 10^22 atoms
Accounting for significant figures, the answer would be: 7 x 10^22 atoms
Give the percent yield when 28.16 g of CO2 are formed from the reaction of 8.000 moles of C8H18 with 16.00 moles of O2.
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
The percent yield when 28.16 g of [tex]CO_2[/tex] is formed from 8.000 moles [tex]C_8H_1_8[/tex] reaction with 16.00 moles [tex]O_2[/tex] is 6.25%.
Percent yieldThe percent yield of a reaction is given by:
Percent yield = actual yield/theoretical yield x 100%
From the equation of the reaction, the mole ratio of the two reactants is 2:25.
With 8.00 moles [tex]C_8H_1_8[/tex] , 200 moles of [tex]O_2[/tex] should be used. But only 16 moles is available. Thus, [tex]O_2[/tex] is the limiting reactant.
The mole ratio of [tex]O_2[/tex] to [tex]CO_2[/tex] is 25:16.
With 16 moles [tex]O_2[/tex], the moles of [tex]CO_2[/tex] would be:
16 x 16/25 = 10.24 moles
Mass of 10.24 moles [tex]CO_2[/tex] = 10.24 x 44.01
= 450.7 grams
Percent yield of [tex]CO_2[/tex] = 28.16/450.7 x 100
= 6.25%
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hello, can someone please help me with this problem
In order of degreasing Size :
O2- > O > Ne.
Br- > Cl- > F-
Mg > Al > S
what are factors affects the radius of the atom? How many protons are in the nucleus (called the nuclear charge). The number of electron-carrying energy levels (and the number of electrons in the outer energy level). a measure of how many electrons are kept between the nucleus and its outermost electrons (called the shielding effect).The separation between an ion's nucleus and its furthest-reaching electrons is known as the ionic radius. However, the atomic radius measures the separation between an atom's outermost shell and its nucleus.To learn more about : Atomic radius
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If the moxie tank has an initial pressure of 50 atm in the winter what will be the pressure in summer
The pressure of the Moxie's tank in the summer will be 110.5 atm.
The correct option is C.
What is pressure law?According to the pressure law, if the volume remains constant, for a given mass of gas, the pressure applied to the container's sidewalls is directly proportional to the gas's absolute temperature.
Briefing:This law can be expressed mathematically as
P₁/T₁ = P₂/T₂
where
P₁ is the starting pressure.
The final pressure is P₂.
The starting temperature is T₁
The final temperature is T₂
The pressure of the gas increases as its temperature does.
As a result, since summertime temperatures are higher than wintertime temperatures, the pressure within the Moxie's tank will be higher than 50 atm throughout the summer.
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The complete question is -
If the Moxie's tank has an initial pressure of 50 atm in the winter, what will be point the pressure in the summer?
A. 5.88 atm
B. 22.6 atm
C. 110.5 atm
an example of a element would be A. Chlorine gas B. salt C. tap water D. vegetable soup
An example of a element would be chlorine gas
An element is a substance whose atoms all have the same number of protons another way of saying this is that all atoms of a given element have the same number of protons and elements are the simplest chemical forms and thus can not be broken down through chemical reactions and chlorine is a yellow-green gas at room temperature and chlorine has a pungent, irritating odor similar to bleach that is detectable at low concentrations and the density of chlorine gas is approximately 2.5 times greater than air and in the given option only chlorine gas is the element
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A chemistry student needs 65.0 g of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of pentane is 1.10 g-cm^- 3. Calculate the volume of pentane the student should pour out. Be sure your answer has the correct number of significant digits.
The volume of the pentane the student should pour out, given that he needed 65.0 g of it is 59 cm³
How to determine the volumeFrom the definition of density, we can obtain an expression to calculate volume. This is illustrated below:
Density = mass / volume
Cross multiply
Density × volume = mass
Divide both sides by density
Volume = mass / density
With the above formula, we can obtain the volume of the pentane as follow:
Mass of pentane = 65 gramsDensity of pentane = 1.10 g/cm³ Volume of pentane = ?Volume = mass / density
Volume = 65 / 1.10
Volume = 59 cm³
Thus, the volume of the pentane is 59 cm³
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A student in lab needs to make a solution that is 8.00% by mass NaCl. If 145 g of NaCl is available, what mass of solution can
be prepared?
According to the given statement 1812.5 g mass of solution can be prepared.
How is solution formed?When one substance dissolves, or separates into the other, a solution is created. A solute is the name for the material that dissolves to create a solution. A solvents is the material that a solution will dissolve in. Sugar is the solute while water is the solvent in a sugar syrup.
Briefing:8.0% by mass NaCl means 8 g NaCl in a total of 145 g solution. (note it is g of total solution)
Use dimensional analysis:
145 g NaCl x 100 g solution/8 g NaCl
= 1812.5 g solution
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How many grams of Br are in 115 g CaBr₂?
Answer: 95.7 g Br
Explanation: Molecular weight of Ca = 40.78
Molecular weight of Br is 79.9.
Molecular weight of CaBr2 is 192g/mol
115g CaBr2 x 1 mol CaBr/192g = 0.6 x 2 mol Br/1mol CaBr2 = 1.2 mol Br
1.2 mol Br x 79.9g Br/mol Br = 95.7g Br
. What volume of a 15.2 M H3PO4 solution (in mL) do you need to make the following solutions?
a. 3.50 L of a 0.750 M H3PO4 solution
b. 12.5 L of a 0.155 M H3PO4 solution
C.
475 mL of a 1.20 M H3PO4 solution
15.2 M H3PO4 solution (in mL) do you need to make 475 mL of a 1.20 M H3PO4 solution
an H3PO4 solution be created
As a result, you must combine 0.9316 liters (931.6 ml) of water with 0.0684 liters (68.4 ml) of concentrated solution to create 1 liter of 1 M. Solution of phosphoric acid
How can I figure out what a solution's concentration is?
Subtract the solute's mass from the solution's overall volume. C = m/V, where m is the solute's mass and V is the entire volume of the solution, should be written down. To calculate the concentration of your solution, divide the mass and volume quantities you discovered by the corresponding plug-in values.
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You need a 9.0% NaCl solution for an IV drip. If your IV bag can hold 239 grams of total solution, how many grams of NaCl are in the IV bag?
The 12.5 g of NaCl is required to make 9.0% of the NaCl solution.
How the percentage is related to grams in terms of Chemistry?
Both percentages and grams both are units or parameters used to express the concentrations in chemistry.
Given:
The % of NaCl = 9.0% or = 9/10 = 0.9
The weight of the solution = 239 grams
The molar mass of the NaCl = 58.44 g/mol
Here, we use formula = 0.9 = (Mass of the solute*1000)/(Mass of the solvent)
Let us assume the mass of the solute = x = mass in the gram/ molecular mass of the solute.
Now, by using the above formula, we get
X= 0.9*239*58.44/1000
X = 12.5 grams
Hence, 12.5 grams is the answer
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Which of the following is an isotope of Carbon (atomic number 6)?
A 7 protons, 6 neutrons, 8 electrons
B 7 protons, 8 neutrons, 6 electrons
C 8 protons, 6 neutrons, 7 electrons
D 6 protons, 8 neutrons, 7 electrons
Answer:
D
Explanation:
Carbon has atomic number of 6 so it has 6 protons.
The mass of a single barium atom is 2.28×10-22 grams. How many barium atoms would there be in 166 milligrams of barium?
166 milligrams is equal to 0.166 grams.
If 2.28x10^-22 grams is the mass of 1 atom, then 0.166 grams would constitute how many atoms?
The equation we would make is as follows:
2.28x10^-22/1 = 0.166/x
- If we cross multiply and solve for x, we get the answer which is 7.28x10^20 atoms.
The charge on an electrically neutral atom of hydrogen is __.
A +1
B 0
C -1
Answer:
B. 0
Explanation:
The charge on any electrically neutral atom is alway zero.
Calculate the number of grams that would be needed to make 2.50 x 10? mL of 0.754 M KOH. Enter your answer in the provided box.
13. What are the 3 main types of radiation and what does each emit?
Answer:
[tex]\begin{gathered} a)\text{ Alpha Radiation (emits helium atom)} \\ b)\text{ Beta Particle (emits electron)} \\ c)\text{ Gamma Ray (has no charge, nor mass, are by-products of radiation)} \end{gathered}[/tex]Explanation:
The three main radiation types are:
a) Alpha particles
b) Beta Particles
c) Gamma rays
Alpha Particles
Alpha particles are essentially helium atoms. When radiated, the value 4 is subtracted from the parent's molecule mass number while the value 2 is subtracted from the parent's molecule atomic number. Due to their heaviness, they are less penetrative, compared to other radiation types. They are positively charged.
[tex]\alpha^{\text{ }}particle=^4_2He[/tex]Beta Particles
Beta particles are more energetic radiation emission with a charge equal to -1. They are negatively charged. They are high energetic electrons which can be represented generally as follows:
[tex]\beta^{\text{ }}particle=^{_{}0_{}}_{-1}e[/tex]They weigh much more less and have a higher penetrating power when compared to alpha particles
Gamma Rays
These are the lightest and are simply radiation by products. They have more penetrating power than both beta particles and alpha particles. They are neutrally charged. They have no charge nor mass:
[tex]^0_0\gamma\text{ }[/tex]They have low ionizing power
A student poured a liter of liquid water into a jar and then placed a lid on the jar. Compare and contrast the liquid water and the water vapor in the jar to complete the table.
The liquids are less energetic than the gases. They have a definite volume unlike the gases but like the gases, they have no definite shape.
What are the states of matter?Matter is anything that has mass and occupy space. We know that matter is composed of particles. The particles that compose matter are known to differ in the way that they move about. All the particles of each of the states of matter do not have the same amount of energy. Some states of matter have particles that are more energetic than other particles of matter.
Let us note that the liquid state of matter is less energetic then the gaseous state of matter. This is because the particles that compose a gas are always moving at a very high speed. The particles that compose a liquid have lesser energy.
On the other hand, a gas has no definite volume or shape while a liquid does not have a definite shape but it has a definite volume.
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For the reaction of calcium chloride and sodium oxalate, write: a chemical equation that represents the reaction including all appropriate phase labels (e.g. (s), (l), (aq)).
The chemical equation that represents the reaction is NaCl(s) ⇒Na+(aq) + Cl-(aq).
A mixture of sodium sulfate and calcium chloride produces four crystals sodium sulfate calcium chloride sodium chloride and calcium sulfate. Calcium chloride dissolved in water dissociates into ions according to the formula This is an example of a precipitation reaction. This occurs when two aqueous solutions combine to form a precipitate and by-products. It is also usually water-based.
A balanced equation is an equation of a chemical reaction in which the number of atoms and the total charge of each element in the reaction is the same for both reactants and products. In other words, mass and charge are balanced on both sides of the reaction. Widely used as an acid laundry detergent, oxalic acid effectively removes rust and ink stains because it converts most insoluble iron compounds to soluble complex ions.
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What volume of sodium hydroxide (0.167 M) is needed to titrate 18.53 mL of perchloric acid (HClO4 (aq)) with molarity of 0.242 M ? Answer in mL with one decimal place- you do not need to include units in your response.
The volume (in mL) of the 0.167 M sodium hydroxide, NaOH solution needed is 26.9 mL
How to determine the volume of NaOHThe balanced equation for the reaction is given below:
HClO₄ + NaOH —> NaClO₄ + H₂O
The mole of the acid, HClO₄ (nA) = 1The mole of the base, NaOH (nB) = 1The volume of NaOH can be obtained as follow:
Molarity of base, NaOH (Mb) = 0.167 MVolume of acid, HClO₄ (Va) = 18.53 mL Molarity of acid, HClO₄ (Ma) = 0.242 MVolume of base, NaOH (Vb) =?MaVa / MbVb = nA / nB
(0.242 × 18.53) / (0.167 × Vb) = 1
4.48426 / (0.167 × Vb) = 1
Cross multiply
0.167 × Vb = 4.48426
Divide both side by 0.167
Vb = 4.48426 / 0.167
Vb = 26.9 mL
Thus, the volume of the NaOH solution needed is 26.9 mL
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