12. A lathe mounted on wooden skids is to be slid down a pair of planks placed against the back of a truck.
(a) If the coefficient of friction is 0.28, what angle should the planks make with the ground in order for the lathe to slide down at constant velocity?
(b) When the planks are at this angle, will the lathe start to slide down of its own accord?

Answers

Answer 1

(a) The angle the planks make with the ground in order for the lathe to slide down at constant velocity is 90⁰.

(b) Yes, at this angle the lathe will start sliding at constant velocity because of the sharp steepness.

The given parameters:

coefficient of friction, μ = 0.28

The net force on the wooden skids is calculated as follows;

[tex]\Sigma F = 0\\\\F - \mu mg cos\theta = 0\\\\ma - \mu mg cos\theta = 0\\\\ma = \mu mg cos \theta \\\\a = \mu g cos\theta\\\\at \ constant \ velocity , \ a = 0\\\\0 = \mu g cos \theta\\\\cos \theta = 0\\\\\theta = 90 ^0[/tex]

Yes, at this angle the lathe will start sliding at constant velocity because of the sharp steepness.

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Related Questions

Do two indentical objects become statically charged when you rub them together? Explain why they do or do not.

Answers

Answer:

Yes, they do. When two different materials are rubbed together, there is a transfer of electrons from one material to the other material. This causes one object to become positively charged and the other object to become negatively charged.

Explanation:

hope this helps

A 300 g ball swings in a vertical circle at the end of a 1.3-m-long string. When the ball is at the bottom of the circle, the tension in the string is 13 N.
What is the speed of the ball at that point?

Answers

Answer:

0.23N for the speed

at the bottom of the circle

How long will it take a projectile to hit the ground if it is launched at 4.2 m/s off a 12.6 m high platform?

Answers

Answer: 3

Explanation:

I think you are supposed to divided in those problems? I'm not sure but if you aren't then please let me know. The equation I did was:

12.6 / 4.2 = 3

Hope this helps!! :)

Can we get less ads please i don’t like this

Answers

I hope we can! I dont like the ads either! they are horrible on these appsn

If the force to stretch a spring is given as k = (100N/m), then what is the potential energy of the spring if it is stretched 1 meters from rest?

Answers

Answer:

50 Joules

Explanation:

What size resistor would produce a 3 amp current flow with a 12 volt battery?

Answers

Resistance = volts / amps

Resistance = 12 volts / 3 amps

Resistance = 4 Ohms

Answer: 4 Ohms

A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of mc001-1. Jpg 6. 67 inches 10. 47 inches 20. 94 inches 62. 8 inches.

Answers

The approximate length of the arc intersected by the central angle is 20.94 inches.

The given parameters:

Radius of the circle, r = 10 inchesCentral angle, [tex]\theta = \frac{2\pi }{3} \ rad[/tex]

The approximate length of the arc intersected by the central angle is calculated as follows;

S = rθ

where;

S is the length of the arc

Substitute the given parameters and solve for the length of the arc

[tex]S = 10 \ in \times \frac{2\pi }{3} \\\\S = 20.94 \ inches[/tex]

Thus, the approximate length of the arc intersected by the central angle is 20.94 inches.

Your question is not complete, find the complete question below:

A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of [tex]\frac{2\pi}{3}[/tex].

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A racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction). It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/a to the left (-x direction).what is the magnitude of the racquetball's change in momentum?

Answers

The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

mass m  = 42g = 42/1000 = 0.042kg

initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

Change in momentum = 0.042 x 7 - ( 0.042 x - 7)

Change in momentum = 0.294 + 0.294

Change in momentum = 0.588 kgm/s

Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

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HELP!!!
Which of the following statements is true about magnets?

A. The molecules of the atom are unaligned
B. The orientation of atoms does not affect a magnet
C. The north pole is stronger than the south pole
D. The molecules of the atom are all aligned

Giving brainliest to the correct answer! (If both are correct I'll give whoever answered correctly 1st brainliest!)

Answers

Answer:

Explanation:

A is not correct. That means that D is since they offer exactly the opposite meanings.  

C is rubbish. One pole could not be stronger than the other. Heaven help us if touched the stronger pole.

B the very point of a magnet is that it does matter how the atoms are orientated.

the probe used in a medical ultrasound examination emits sound waves in air that have a wavelength of 0.12 mm.

Answers

Answer:

IF GOD IS TEIIING YOU SOMETHING JUST DO IT

Explanation:

A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. The number zero is above the red tick mark. Assume each tick mark represents 1 cm. Calculate the total displacement if a toy car starts at 0, moves 5 cm to the left, then 8 cm to the right, and then 3 cm to the left. The car moves cm, so there is no displacement.

Answers

The total displacement of the toy car at the given positions is 0.

The given parameters;

First displacement of the car, = 5 cm leftSecond displacement of the car, = 8 cm rightThird displacement of the car, = 3 cm to the left

The total displacement of the car is calculated as follows;

Let the left direction be "negative direction"Let the right direction be "positive direction"

[tex]\Delta x = - \ 5\ cm \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0[/tex]

Thus, the total displacement of the toy car at the given positions is 0.

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Answer:0

Explanation:

A rectangular room twice as long as it is wide would contain 145 square feet more if each side were one foA rectangular room twice as long as it is wide would contain 145 square feet more if each side were one foot longer. What is the length of the room

Answers

The length of the room is 96 ft.

Let L be the length of the room and W be the width of the room.

Since the length is twice its width, L = 2W.

Its area A = LW

= 2W × W

= 2W²

If each side were increased by 1 foot, then its new area is A' = (L + 1)(W + 1)

= (2W + 1)(W + 1)

= 2W² + 3W + 1

Since the room would contain 145 ft more if each side were increased by 1 foot, then its new area is A' = A + 145 = 2W² + 3W + 1

2W² + 145 = 2W² + 3W + 1

145 = 3W + 1

3W = 145 - 1

3W = 144

W = 144/3

W = 48 ft.

Since its length L = 2W, substituting W = 48 into the equation, we have

L = 2(48)

L = 96 ft

So, the length of the room is 96 ft.

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If a 35 kg box collides with a stationary 120 kg box with a force of 90 N, what must
be true of the magnitude of the reaction force?

Answers

Answer:

yes , true the magnitude of the reaction force.

explain maximum and minimum thermometer working(answer only for points will be reported)​

Answers

Explanation:

Six’s Maximum and Minimum thermometer is a U shaped parallel tube made up of glass. One side registers the maximum temperature and the other side records the minimum temperature.The bend at the bottom of the thermometer contains mercury which moves up or down based on the expansion and contraction of alcohol.When the temperature rises, the alcohol expands and pushes the mercury up the maximum column. This also pushes the mercury down in the minimum column.Similarly, when the temperature falls, the alcohol contracts and pulls the mercury up in the minimum column resulting in a fall of mercury in the maximum column.The steel indexes are located on the surface of mercury. They move along with the flow of mercury up and down.When the temperature reaches its maximum and minimum limits, the metal indexes remain at that place. This helps in recording the maximum and minimum temperatures of the day.

**BRAINLIEST** How does the Combining Vinegar and Baking Soda table represent the law of conservation of matter when baking soda and vinegar are combined?

Answers

Basically your liquid will go over the line because you are adding more mass. the balloon will inflate because  of mass filling it.  Part 1  I noticed that there was a change from the original line.   part 2  Some mass is lost. The bubbles are the gas leaving. The balloon increases in size because of the mass. The cup got heavier when I added the vinegar.

Gas leaving caused the bubbles.

pls answer this question is due today​

Answers

Answers:Speed for section A = 15 km per hourSpeed for section B = 0 km per hourSpeed for section C = 60 km per hourSpeed for section D = 40 km per hour

=============================================

Explanation:

To compute the speed, we divide the distance traveled over the time duration.

For instance, if a car goes 100 km in 5 hours, then its speed is 100/5 = 20 km per hour.

-----------------

For section A, the car travels 30 km over the course of 2 hours (since 11:00-9:00 = 2:00)

speed = distance/time = (30 km)/(2 hrs) = 15 km/hr

-----------------

We don't need to do any computations for section B. It's a flat horizontal line, so the speed is zero. There's no change in distance, so the car is stationary for this 1 hour period.

You could say speed = distance/time = 0/1 = 0 km/hr if you wanted.

-----------------

For section C, its change in distance is 60-30 = 30 km and the change in time is 0.5 hour (because it spans from 12:00 to 12:30)

So, speed = distance/time = (30 km)/(0.5 hr) = 60 km/hr

The steeper slope of section C, compared to section A, means the car is going faster.

-----------------

Section D spans from 12:30 to 14:00. This is a time period of 14:00-12:30 = 1:30 = 1.5 hours. The change in distance is 60 km

(60 km)/(1.5 hrs) = 40 km/hr

The speed of the car during section D is 40 km per hour.

Side note: if you were talking about velocities instead of speeds, then section D would have a negative velocity of -40 km/hr to indicate the car is going the opposite direction (compared to sections A and C). However, speed is always nonnegative.

The function of the liver in the metabolism of amino acids is to

Answers

Answer:

Produce energy, or make carbohydrates or fats.

Explanation:

Alistar places a 6.4 kg block on an incline plane that is 23 degrees above the horizontal. The block starts from rest, and in 2.2 seconds, travels 1.4 meters. What is the force of friction on the block?

Answers

fh= 6.4×23

fh=147.2

fv=2.2×1.4

fv=3.08

f=147.2+3.08

f=150.28

The force of friction on the block is 20.798 N.

What is acceleration?

Acceleration is the rate at which speed and direction of velocity vary over time. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Mass of the  block: m = 6.4 kg.

Angle of inclination = 23°

Hence, Magnitude force acting along the motion = mg sin23°

= 6.4 × 9.8 × sin23° N

= 24.51 N.

The block travels 1.4 meters in 2.2 seconds. Acceleration = (2×1.4)/2.2² m/s²

= 0.58 m/s²

Hence,  the force of friction on the block is = F - ma

= 24.51 N - 6.4×0.58 N

= 20.798 N

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Ali kicks a soccer ball upward at 45° angle
with an initial speed of 32 m/s. What
expression should Ahmed use to calculate
the magnitude of the ball's initial velocity
the horizontal direction?

Select one:
a. 32 sin(45°) m/s

b. 32 cos(45°) m/s

c. 32 tan(45°) m/s

d. 45 m/s

Answers

Answer:

the answer is 32sin(45°)m/s

A bicycle accelerates from rest to 6m/s in a distance of 50m, calculate the acceleration

Answers

50x6=300 this is the answer I think

The acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].

We know that acceleration is the change in velocity divided by the change in time. In this case, the bicycle is accelerating from rest to a velocity of 6 m/s. The change in time is the time it takes the bicycle to travel 50 m.

We can use the following equation to find the acceleration:

a = (v2 - v1) / t

where:

a is the acceleration

v2 is the final velocity (6 m/s)

v1 is the initial velocity (0 m/s)

t is the time

Plugging in the values from the problem, we get:

a = (6 m/s - 0 m/s) / 50 s

= 0.12 m/[tex]s^{2}[/tex].

Therefore, the acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].

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A balloon is rubbed against a sweater. Which of the following describes the result of this interaction?(1 point)
The outer shell electrons move from the balloon to the sweater.

The fibers of the sweater lose electrons.

The balloon becomes positively charged.

The free electrons in the balloon decreases.

Answers

Answer:

The fibers of the sweater lose electrons.

If you walk at an average speed of 5 km/h for 30 minutes, how
far will you walk? (Write your answer with Sl unit.

Answers

Time= s/v

Speed =5km/h
Time=30min
Distance is required
Distance=time*speed
30min*5km/h=600m

A 40 N block is resting on a rough inclined plane. The static friction between the block and the plane is ____ N.​

Answers

The static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].

The given parameters:

Weight of the block, W = 40 N

The normal reaction on the rough surface due to weight of the block is calculated as follows;

[tex]F_n = 40 \ N[/tex]

The static friction between the block and the plane is calculated as follows;

[tex]F_s = \mu_s F_n[/tex]

where;

[tex]\mu_s[/tex] is coefficient of static friction

Thus, the static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].

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a car travels at a constant speed of 20m/s and yet it does not have a constant velocity. explain how this could be

Answers

Answer:

HOPE THIS HELPS!!

Explanation:

Velocity is speed as well as distance mentioned.

The car is traveling at a constant speed of 20m/s but it may not be traveling in any particular direction. It would be taking many turns (left and right) or it would be moving in a circular manner.

So,it is at constant speed but not constant velocity.

1. Apply a constant force of 50 N directed to the right of the 50 kg Box. (2 pts)
Hypothesis:?
Conclusion: ?

Answers

As the box is moving with a constant velocity, the two forces acting on the box are canceling each other.

Then   friction force = 80 Newtons              but in the opposite direction.

Friction force =  Mu  * Normal force exerted by ground  =  Mu * weight of box

So we find Mu.

Mu = coefficient of friction between box and horizontal surface

          = Force of friction / weight  =  80 / 50 * 9.81 = 0.163

When an identical box is placed on top, the force of friction is

      = Mu * total weight = 0.163 * (50+50) * 9.81 = 159.9 Newtons

yvonne van gennip of the netherlands ice skated 10.0 km with an average speed of 10.8 m/s. suppose vang ennip crosses the finish line at her average speed and takes a huge boquet of flowers handed to her by a fan. as a result her speed drops t o10.01 m/s. if van gennip’s mass is 63.0 kg what is the mass of the boquet?

Answers

By conservation of momentum, we will find that the mass is 4.97 kg.

So in the original system, we have two objects, the bouquet of flowers of mass M that is not moving and Yvonne, which has a mass of 63 kg and a speed of 10.8 m/s.

Then the total momentum of this system is:

P = (63kg)*(10.8m/s) + M*(0 m/s) = 680.4 kg*m/s.

Remember the conservation of momentum, thus, the final momentum must be equal to the above one.

In the final situation, Yvonne and the bouquet move together with a speed of 10.01 m/s,

Then the final momentum is:

P' = (63kg + M)*(10.01 m/s)

And that must be equal to the initial momentum, then we have the equation:

(63kg + M)*(10.01 m/s) = 680.4 kg*m/s.

630.63kg*m/s + M*10.01 m/s = 680.4 kg*m/s.

M*10.01 m/s = 680.4 kg*m/s - 630.63kg*m/s = 49.77 kg*m/s

M = (49.77 kg*m/s)/(10.01 m/s) = 4.97 kg

So the mass of the bouquet is 4.97 kg

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A plane flies from New York to LA at a constant speed of 800 km an hour how long will it take the plane to fly to 4,200 kilometers

Answers

Answer:

3.5 hours

Explanation:

Jeremiah rides his bicycle 4 miles in 30 minutes. If he maintains this rate, how far will he ride in 3 hours?

Answers

Answer:

24 miles.

Explanation:

3 hours=180 minutes

180÷30=6

6x4=24

In an action-reaction pair
a. action force is exerted first

b. action force and the reaction force are equal in magnitude and act in the same direction.

c. action force and the reaction force are contact forces only.

d. action force and the reaction force act on two different objects.

Answers

In an action-reaction pair, action force and th reaction force act on two different objects.Newton's Third Law of Motion states, "To every action, there is an equal and opposite reaction; action and reaction act on two different bodies."The first option is incorrect because action and reaction forces act simultaneously.The second option is also false because they act in opposite direction.The third option is wrong because for action-reaction force, physical contact is not necessary.

Answer:

d. action force and the reaction force act on two different objects.

Hope you could understand.

If you have any query, feel free to ask.

In an action-reaction pair, action force and the reaction force act on two different objects.

What is Newton's Third Law of Motion?

Newton's Third Law of Motion states that "For every action, there is an equal and opposite reaction, action and reaction act on two different bodies."

It means that equal force are act on reaction force that is it is also known as reciprocal law of motion.

When considering the options,

The first option is incorrect because action and reaction forces act simultaneously.The second option is also false because they act in opposite direction.The third option is wrong because for action-reaction force, physical contact is not necessary.

So, In an action-reaction pair, action force and the reaction force act on two different objects. Thus, Option B is the correct answer.

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Twins Bo and Joe have a combined mass of 200 kg and are zooming along at 10 m/s in a 100 kg amusement park bumper car. They bump into Melinda’s car, which is sitting still. Melinda has a mass of 25 kg and is also in a 100 kg car. After the collision, the twins continue moving with a speed of 4.12 m/s.
a. What is the initial momentum of the system?
b. What must be the final momentum of the system?
c. How fast is Melinda’s car bumped across the floor?

Answers

The speed with which Melinda’s car is bumped across the floor is 14 ms-1.

Total mass of the twins and the car = 300 Kg

Initial velocity of the twins car =  10 m/s

Total mass of Melinda and her car = 125 Kg

Initial velocity of Melinda's car = 0 m/s (at rest)

Final velocity of the twins car =  4.12 m/s

Final velocity of Melinda's car = ?

Initial momentum of the system = (300 × 10) + (125 × 0) = 3000 Kgms-1

Final momentum of the system = (300 × 4.12) + (125 × x) = (1236 + 125x) Kgms-1

Using the principle of conservation of linear momentum;

Total momentum before collision = Total momentum after collision

m1u1 + m2u2 = m2v1 + m2v2

(300 × 10) + (125 × 0) = (300 × 4.12) + (125 × x)

3000 = 1236 + 125x

x =  3000 -  1236 /125

x = 14 ms-1

The speed with which Melinda’s car is bumped across the floor is 14 ms-1.

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