13. Austin rode his bike 10 m/s for two minutes. How far did he travel? A. 200 meters B. 1200 meters C. 1000 meters D. 20 meters​

Answer:

Coulomb's law.

Explanation:

If the distance between two particles is doubled and the force between them is quartered, this is known as Coulomb's law. Coulomb presented a law in which he states that when there is increase occur in distance between two objects, the force between them is decreases so if the distance between two particles or objects is doubled so the force between them is also quartered.

Question:

At a sports event, the car starts from rest. in 5.0 s its acceleration is 5.0 m/s2.  Calculate the distance travelled by car.

Answer:

62.5 metres

Explanation:

Given

[tex]u = 0[/tex] -- Initial Velocity

[tex]a = 5.0m/s^2[/tex] --- acceleration

[tex]t =5.0s[/tex] -- time

Required

Calculate the distance

This question will be solved using the following equation of motion

[tex]S = ut + \frac{1}{2}at^2[/tex]

Where S represents the distance

Substitute values for u, t and a

[tex]S = 0 * 5.0 + \frac{1}{2} * 5.0 * 5.0^2[/tex]

[tex]S = 0 + \frac{1}{2} * 5.0 * 25.0[/tex]

[tex]S = \frac{1}{2} * 5.0 * 25.0[/tex]

[tex]S = \frac{1}{2} * 125.0[/tex]

[tex]S = 62.5m[/tex]

Hence, the distance travelled is 62.5m

Answer:

1m/s

Explanation:

D = 22m

T = 22s

S = 22÷22

= 1 m/s

Answer:

The effects of the Moon's rotation includes;

1) The Moon rotation and revolution gives the appearance of a perfectly still Moon to observers of the Moon from the Earth

2) The Moon has two sides, the near side that continuously faces the Earth and the "back" or far side, which is also known as the dark side of the Moon

The effect of the Moon's revolution

1) The tides in the ocean and water bodies, due to the gravitational forces from the Moon

2) The changes in the observed shape of the Moon due to the amount of Sunlight that is able to be reflected from the Moon as a result of the relative position of the Moon, the Earth and the Sun, at a given point in time

3) Lunar and Solar eclipse, when the Earth and the Moon blocks the light coming from the Sun respectively, due to their combined revolution

Explanation:

The duration of the Moon's orbit round the Earth = 27.322 days

The time it takes the Moon to rotate round its axis = 27 days

The Moon is the closest cosmic body to the Earth.

Answer:

8.5m/s

Explanation:

Using the equation of motion

v² = u² + 2gH

v is the final speed of the diver

u  is the initial speed of the diver

g is the acceleration due to gravity

H is the height of the object

Given the following

V = 1.3m/s

H = 3.60m

g = 9.8m/s²

Required

Initial speed of the diver u

Substitute the given values into the formula:

v² = u² -2gH

1.3² = u²  - 2(9.8)(3.60)

1.69 = u²-70.56

u² = 1.69+70.56

u² = 72.25

u = √72.25

u = 8.5m/s

Hence the diver's speed, in m/s, just before she enters the water is 8.5m/s

Answer:

D.

Explanation:

A compound containing metallic bonds

hope it helps!

Answer:

3.77202

Explanation:81.9 kg×9.8N/kg÷0.0021 Pa ×(1atm/101325)=3.77202

The pressure exerted between her toes and the ground is 3.77 atm.

The stress at a location within a confined fluid or the perpendicular force per unit area are the two definitions of pressure used in the physical sciences. A 42-pound box with an area of 84 square inches at the bottom will apply pressure on a surface equal to the force divided by the surface area.

Given:

An 81.9 kg person stands on her toes. The surface area of her toes in contact with the ground is only 0.00210 m²,

Calculate the pressure on the toe as shown below,

The pressure on the toe = Force of man / area of toe

The pressure on the toe = mass of man × 9.8 / 0.00210

The pressure on the toe = 81.9 × 9.8 / 0.00210

The pressure on the toe = 802.62 / 0.00210

The pressure on the toe = 382200 N/m²

The pressure on the toe = 382200 / 101325 (1 atm = 101325 N / m²)

The pressure on the toe = 3.77 atm,

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Answer:

Hypertonic, isotonic, and hypotonic solutions and their effect on cells. ... There are some different explanations out there. ... Tonicity is a concern for all living things, particularly those that lack rigid cell walls and live in ...

Answer:

False

Explanation:

They had no free oxygen though they has oceans forming and it was very hot and today is much different hope that helps!

Answer:

Acceleration of the car = 2 m/s²

Average velocity of the car =28 m/s

Explanation:

Initial velocity = 20 m/s

Final velocity = 36 m/s

Time taken = 8 s

Acceleration = Δ velocity / time taken

Acceleration = 36-20 / 8 = 16/8 = 2 m/s²

Average velocity of the car =[ Initial velocity + Final velocity ] /2

Average velocity of the car = [ 20+36] / 2 = 28 m/s

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 0.15 × 35

We have the final answer as

Hope this helps you

Answer:

Kinetic energy.

Explanation:

This is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy.

Answer:

Explanation:

time =d/s

therefore, t =8.5/2.8

t=3.02s

If a cell is placed in a hypertonic solution, water will leave the cell, and the cell will shrink. In an isotonic environment, there is no net water movement, so there is no change in the size of the cell. When a cell is placed in a hypotonic environment, water will enter the cell, and the cell will swell.

Answer: They are put in front for defense so so they can block the opponents from getting the ball

Explanation:

Answer:

Heavier football players are usually on the front line because they have a low point in gravity therefore they are able to block the back running players in a better way. And its Newton's second law.

Explanation:

Answer:

5.

Explanation:

From the question given above, the following data were obtained:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =?

Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:

Mechanical advantage = length /height

MA = L/H

With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =.?

MA = 25 / 5

MA = 5

The, the mechanical advantage of the ramp is 5.

Answer:

5.

Explanation:

From the question given above, the following data were obtained:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =?

Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:

Mechanical advantage = length /height

MA = L/H

With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =.?

MA = 25 / 5

MA = 5

The, the mechanical advantage of the ramp is 5.

Answer:

B

Explanation:

Explanation:

distance=16km=16000m

time=0.25hours=1/4hr=15min=900sec

speed=dist./time

=16000/900=160/9=17.777m/s

speed=17.78m/s (rounded)

Answer:

64

Explanation:

Avg. speed = total distance/total time

Avg. speed= 16km/0.25h

Avg. speed= 64km/h

Answer:

It is always constant unlike weight

Answer:

a. Since h = 5.74 m > 5.7 m, the height of the cliff, the block of ice will successfully launch to the top of the cliff.

b. -2.81 m/s²

c. 3.78 s

d. -351.25 N

Explanation:

a. After landing on the flat land above, each block of ice travels 20 meters while slowing to a stop.

For the block of ice to reach the top of the cliff, its maximum height, h should be greater than or equal to 5.7 m. That is, h ≥ 5.7 m.

The maximum height of a projection h, projected with an initial velocity v at an angle Ф is h = v²sin²Ф/2g where g = acceleration due to gravity = 9.8 m/s².

For the block of ice, v = 15 m/s and Ф = 45°. So,

h = v²sin²Ф/2g

= (15 m/s)²sin²45/(2 × 9.8 m/s²)

= 225 (m/s)²(1/√2)²/19.6 m/s²

= 225 (m/s)²(1/2)/19.6 m/s²

= 112.5 (m/s)²/19.6 m/s²

= 5.74 m

Since h = 5.74 m > 5.7 m, the height of the cliff, the block of ice will successfully launch to the top of the cliff.

The graph is in the attachment.

b. What is the rate of acceleration while the blocks slow to a stop?

Using v² = u² + 2as where u = initial horizontal velocity of block = 15m/scos45° = 10.61 m/s, v = final velocity of block = 0 m/s since it stops, a = acceleration and s = distance block moves = 20 m

So, a =  (v² - u²)/2s

substituting the variables into the equation, we have

a =  ((0 m/s)² - (10.61 m/s)²)/2(20 m)

= - 112.57 (m/s)²)/40 m

= -2.81 m/s²

c. How long do the blocks take to slow to a stop?

Using v = u + at where u = initial horizontal velocity of block = 10.61 m/s v = final velocity of block = 0 m/s since it stops, a = acceleration = -2.81 m/s² and t = time it takes block of ice to stop

So, making t subject of the formula,

t = (v - u)/a

substituting the values of the variables, we have

t = ( 0 m/s - 10.61 m/s)/-2.81 m/s²

= -10.61 m/s/-2.81 m/s²

= 3.78 s

d.  What is the amount of friction between the ice and the snowy ground?

The frictional force, f = net force on block of ice

f = ma where  m = mass of bock = 125 kg and a = acceleration of block = -2.81 m/s²

f = ma

= 125 kg(2.81 m/s²)

= -351.25 N

Answer:

The answer is C) II and III only

Explanation:

Answer:

C

Explanation:

I figured it sounded more accurate

Answer: 9.05 s

v = 3 m/s

u = 22 m/s

Deceleration = 2.1 m/s^2

∴ 3 = 22 - 2.1 ( t )

∴ t = 9 .05 s

Answer:

The net and only force acting on the ball thrown up into the air at half of its maximum height is the weight  of the ball

Explanation:

When the ball is rising in the air, the force, F, acting on it is given by the product of the mass, m × acceleration, a

The acceleration of a body thrown in the air = Gravitational acceleration = g = Constant

Therefore;

The force acting on the body thrown in the air F = Constant = m × g (downwards)

The force acting on the ball thrown up into the air at half of its maximum height = The mass of the ball × The acceleration due to gravity = The weight  of the ball.

Answer:

P = 33.6 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 14 [kg]

a = acceleration = 6 [m/s²]

[tex]F = 14*6\\F = 84 [N][/tex]

In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.

[tex]W = F*d[/tex]

where:

W = work [J]

F = force = 84 [N]

d = displaciment = 40 [m]

[tex]W = 84*40\\W = 3360 [J][/tex]

Finally, the power can be calculated by the relationship between the work performed in a given time interval.

[tex]P=W/t\\[/tex]

where:

P = power [W]

W = work = 3360 [J]

t = time = 100 [s]

Now replacing:

[tex]P=3360/100\\P=33.6[W][/tex]

The power is given in watts

Answer:

The value is  [tex]u = 27.93 \ m/s[/tex]

Explanation:

From the question we are told that

   The  mass of the ball is [tex]m = 0.250 \ kg[/tex]

    The radius of the circle is  [tex]r = 0.5 \ m[/tex]

    The force exerted is  [tex]F = 33 \ N[/tex]

    The  speed of the ball on top of the circle is  [tex]v = 13.0 \ m/s[/tex]

Gnerally from the law of energy conservation we have that

     [tex]PE + W = \Delta KE[/tex]

Here PE  is the potential energy of the pitcher which is mathematically represented as

      [tex]PE = m * g * (2 r )[/tex]

=>   [tex]PE = 0.250 * 9.8 * (2 * 0.5 )[/tex]  

=>   [tex]PE = 24.5\ J[/tex]

And  W  is the workdone by the force applied which is mathematically represented as

       [tex]W = F * \pi * r[/tex]

=>    [tex]W = 33 * 3.142 * 0.5[/tex]

=>    [tex]W = 51.84 \ J[/tex]

And   [tex]\Delta KE[/tex] is the change in kinetic energy which is mathematically represented as

       [tex]\Delta KE = \frac{1}{2} * m * (v^2 - u^2 )[/tex]

=>    [tex]\Delta KE = \frac{1}{2} * 0.250 * ( 13^2 - u^2 )[/tex]

=>    [tex]\Delta KE = 0.125 * ( 13^2 - u^2 )[/tex]

=>    [tex]\Delta KE = 21.125 - 0.125u^2[/tex]

So

      [tex]24.5 + 51.84 = 21.125 - 0.125u^2[/tex]

=>    [tex]u = 27.93 \ m/s[/tex]

The velocity of the ball released at the bottom is required.

The velocity of the ball released at the bottom is 24.56 m/s

F = Force = 33 N

r = Radius of loop = 0.5 m

m = Mass of ball = 0.25 kg

u = Initial velocity of ball = 13 m/s

v = Final velocity

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

The energy balance of the system is given by

[tex]F\pi r+mg2r=\dfrac{1}{2}m(v^2-u^2)\\\Rightarrow v=\sqrt{\dfrac{2}{m}(F\pi r+mg2r)+u^2}\\\Rightarrow v=\sqrt{\dfrac{2}{0.25}(33\times \pi\times 0.5+0.25\times 9.81\times 2\times 0.5)+13^2}\\\Rightarrow v=24.56\ \text{m/s}[/tex]

The velocity of the ball released at the bottom is 24.56 m/s.

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Answer:

If you take A0 to be the initial sample of iodine-131, you will be left with. 12⋅A0=A02→ ... m24 hours=12.5%mo=12.5⋅10−2⋅mo

Explanation:

is that what u look for

Sample I-131 decays to 12.5% in 24.21 days.

Half-life, in radioactivity, is the amount of time needed for half of a radioactive sample's atomic nuclei to decay (change spontaneously into other nuclear species by emitting particles and energy), or, alternatively, the amount of time needed for a radioactive material's rate of disintegrations per second to decrease by half.

Give parameters:

Half-life of  the radioactive element I-131:T = 8.07 day

It decays to 12.5% means it decays to 1/8.

According to definition of half-life,

The radioactive element I-131 decays to half in 8.07 days.

So, the radioactive element I-131 decays to 1/8 in 3×8.07 days = 24.21 days.

Hence,  the radioactive element I-131 decays to12.5% in 24.21 days.

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Explanation:

1.Seeds have endosperm which provides nourishment for a new plant, but spores do not have any stored food supplies.

hope it helpful