13500 mL convert to milliliters of mercury

Answer:

There are 95 atoms in mercury phosphate

Explanation:

You just add the atomic number for both elements

Answer:

3

Explanation:

Explanation:

Leopards have 32 teeth, 4 of which are long, pointed canine teeth. Canine teeth are used to kill prey. Other teeth are for cutting flesh and grinding bone

Answer:

At temperatures > 400 °C, CCl4 reacts with H2O over a MgO catalyst to yield HCl and CO2.

Answer:

3O2→ 2O3

Explanation:

by multiplying 2 by 3 we get 6 on both sides

Answer -ˋˏ ༻༺ ˎˊ-

A common use for gravity filtration is for separating anhydrous magnesium sulfate (MgSO4) from an organic solution that it has dried (Figure 1.68b). Anhydrous magnesium sulfate is powdery, and with swirling in an organic solvent creates a fine dispersal of particles like a snow globe.

Answer:

c>b=a

Explanation:

It is important to note that mass does not affect the average motion/energy per molecule, but temperature does. the higher the temperature the faster the particles are. A has the same temperature as B, so they have the same amount of motion. C is warmer than A and B, so the average motion of the particles in beaker C is the largest

Answer:

C. Both depend on how much matter an object has.

Explanation:

weight is the gravitational force acting on an object, so it does vary depending on gravity.

Hope it help and if it its correct please give brainliest  

Stay Safe And Heal thy

Thank You

Glucose is a molecular substance therefore, there are no ionic species in glucose.

Ionic substances dissolve in water to yield ions. Molecular substances do not produce ions in solution. The conductivity of ionic solutions owes to the presence of ions in solutions. Molecular solutions do not conduct electricity due to the absence of ions.

Glucose is a molecular substance hence they are are no ions present hence glucose does not conduct electricity.

Learn more:  https://brainly.com/question/13440572?

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. We can calculate the concentration of CO₂ using Henry's law.

[tex]C = k \times P = \frac{1.65 \times 10^{-3} M }{atm} \times 4.60 atm = 7.59 \times 10^{-3} M[/tex]

We can calculate the mass of CO₂ in 1.1 L considering its molar mass is 44.01 g/mol.

[tex]\frac{7.59 \times 10^{-3} mol}{L} \times 1.1 L \times \frac{44.01 g}{mol} = 0.367 g[/tex]

Now, we will repeat the same procedure for a partial pressure of 1.28 atm.

[tex]C = k \times P = \frac{1.65 \times 10^{-3} M }{atm} \times 1.28 atm = 2.11 \times 10^{-3} M[/tex]

[tex]\frac{2.11 \times 10^{-3} mol}{L} \times 1.1 L \times \frac{44.01 g}{mol} = 0.102 g[/tex]

The mass of CO₂ released will be equal to the difference in the masses at the different pressures.

[tex]m = 0.367 g - 0.102 g = 0.265 g[/tex]

If the partial pressure of CO₂ in a bottle of carbonated water decreases from 4.60 atm to 1.28 atm, the mass of CO₂ released is 0.265 g.

Learn more: https://brainly.com/question/18987224

The partial pressure of CO₂ gas in a bottle of carbonated water is 4.60 atm at 25 ºC. How much CO₂ gas (in g) will be released from 1.1 L of the carbonated water when the partial pressure of CO2 is lowered to 1.28 atm? At 25 ºC, the Henry’s law constant for CO₂ dissolved in water is 1.65 x 10⁻³ M/atm, and the density of water is 1.0 g/cm³.

Answer:

77%

Explanation:

The formula for finding percent change is change/original.

So, you have to do 0.3/0.39

You have to divide this to get 0.769 which can be rounded 0.77

0.77 as a percentage is 77%

So, the percentage mass increase of the carrot is 77%

Answer:

1 would be the answer

protons = atomic # I think

Answer:

hydrogen

Explanation:

hydrogen has the atomic number of 1 which means that hydrogen has one proton and is neutral so it has one electron as well.

[tex]\boxed{\sf °F=\dfrac{9}{5}°C+32}[/tex]

[tex]\\ \sf\longmapsto °F=\dfrac{9}{5}(197)+32[/tex]

[tex]\\ \sf\longmapsto °F=\dfrac{1773}{5}+32[/tex]

[tex]\\ \sf\longmapsto °F=354.6+32[/tex]

[tex]\\ \sf\longmapsto °F=386.6°F[/tex]

[tex]\rule{200pt}{5pt}[/tex]

[tex]\boxed{\sf K=°C+273}[/tex]

[tex]\\ \sf\longmapsto K=197+273[/tex]

[tex]\\ \sf\longmapsto K=470K[/tex]

Answer:

C6H5S^-

Explanation:

This is because you are removing the hydrogen to make it a conjugate base.

The formula for conjugate base of C6H5SH is C6H5S⁻.

Conjugate base is defined as the substance which is formed when an acid liberate its protons.

The acid donate protons and the acid changes into base.

Conjugate acid is defined as the pair of compound that differs by its protons by gaining protons.

Conjugate acid and base are based in acid base theory.

Thus, the formula for conjugate base of C6H5SH is C6H5S⁻.

To learn more about conjugate base, refer to the link below:

https://brainly.com/question/12883745

#SPJ2

Answer:

[tex]\boxed {\boxed {\sf 1.6 \times 10^{24} \ atoms \ Si}}[/tex]

Explanation:

We are asked to find how many atoms are in a sample of 75 grams of silicon.

First, we must convert grams to moles using the molar mass. This is the mass of 1 mole of a substance. The molar mass is found on the Periodic Table because it is equal to the atomic mass, but the units are grams per mole instead of atomic mass units.

Look up the molar mass of silicon.

We convert using dimensional analysis, so we must set up a conversion factor.

[tex]\frac {28.085 \ g \ Si}{1 \ mol \ Si}[/tex]

We are converting 75 grams of silicon to moles, so we multiply by this value.

[tex]75 \ g \ Si*\frac {28.085 \ g \ Si}{1 \ mol \ Si}[/tex]

Flip the conversion factor so the units of grams of silicon cancel.

[tex]75 \ g \ Si*\frac {1 \ mol \ Si}{28.085 \ g \ Si}[/tex]

[tex]75 *\frac {1 \ mol \ Si}{28.085 }[/tex]

[tex]\frac {75}{28.085} \ mol \ Si[/tex]

[tex]2.670464661 \ mol \ Si[/tex]

Next, we convert moles to atoms using Avogadro's Number, or 6.022 ×10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this problem, the particles are atoms of silicon.

Set up another conversion factor, this time with Avogadro's Number.

[tex]\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}[/tex]

Multiply by the number of moles we found.

[tex]2.670464661 \ mol \ Si*\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}[/tex]

The units of moles of silicon cancel.

[tex]2.670464661 *\frac {6.022 \times 10^{23} \ atoms \ Si}{1 }[/tex]

[tex]2.670464661 * {6.022 \times 10^{23} \ atoms \ Si}[/tex]

[tex]1.60815382 \times 10^{24} \ atoms \ Si[/tex]

The original value of grams (75) has 2 significant figures, so our answer must have the same. For the number we found, that is the tenths place. The 0 in the hundredths place tells us to leave the 6 in the tenths place.

[tex]1.6 \times 10^{24} \ atoms \ Si[/tex]

Answer:

D, two of the above, oxygen and hydrogen.

Explanation:

To solve this problem we can either use orbital stuff or common knowledge. Oxygen and hydrogen are known to form O2 and H2, while sodium forms metallic bonds between the atoms.

Answer:

LICL as an Ionic compounds has covalent ability and they are soluble in polar solvent such as CH3COCH3 but they are insoluble in non-polar solvents. Due to their polarity, CH3COCH3 will decreases the electrostatic forces of attraction thereby resulting in free ions in aqueous solution.

Water is the known as a polar solvent that can dissolve an ionic compounds very easy and as a polar solvent, the arrangement of oxygen and hydrogen atoms in water is in bent shape.

Ionic compounds like LICL that is very polar is soluble in the polar solvent water.

Polar solvents like CH3COCH3 will dissolve polar and ionic solutes because of the attraction of the opposite charges on the solvent and solute particles.

Learn more from

https://brainly.com/question/25422160

Explanation:

The volume of the gas is 27 ml

The calculation can be done as follows

The first step is to convert the pressure to atm

convert 2280 tors to atm

760 tors= 1 atm

= 2280/780

= 3 atm

The formula is

PV= nRT

The next step is to write out the parameters

Pressure= 3 atm

Temperature= 21 °C

no of moles= 32.1 mole

volume= ?

(r)constant= 8.314

3 × v= 32.1×8.314×21

3v= 81.080

V= 81.080/3

V= 27 ml

Hence the volume of the gas is 27 ml

Please see the link below for more information

https://brainly.com/question/15568262?referrer=searchResults

Answer:

c

Explanation:

allow plants to absorb water and nutrients from the soil

Answer:

Collision theory states that molecules must collide to react. For most reactions, however, only a small fraction of collisions produce a reaction.

Answer:

Calculate the freezing point of a solution of 3.46 g of a compound,X,in 160 g of benzene. When separate sample of X was vaporised, its density was found 3.27 g/L at 116 c and 773 torr. The freezing point of pure benzen is 5.45 c, and kf is 5 .12 c/m.

Explanation:

First determine molar mass from

P*molar mass = density*R*T

Solve for molar mass. Then

moles = grams/molar mass

Solve for moles

molality = moles/kg solvent

Solve for molality

delta T = Kf*m

Solve for delta T, then convert to freezing point

Answer:

78.125ml

Explanation:

Number of moles in 250ml of 2.5M KCl is (250÷1000)litres×2.5M so we divide these moles by 8M. The answer gotten will be in litres so multiply by 1000 to get it in ml

The predicted concentration of IO₃⁻ needed to start the precipitation titration is 1.703 × 10⁻⁷ M

The dissociation of zinc (II) iodate can be expressed as:

[tex]\mathbf{Zn (IO_3)_2 \to Zn^{2+} + 2IO_3^-}[/tex]

Given that the solubility product constant Ksp value = 3.9 × 10⁻⁶

For the above dissociation,

[tex]\mathbf{Ksp = [Zn^{2+ }] [IO_3^-]^2}[/tex]

Since [tex]\mathbf{ [Zn^{2+ }] = [Zn(NO_3)_2] = 0.229 \ M}[/tex]

∴

[tex]\mathbf{3.9\times 10^{-8} =(0.229) \times [IO_3^-]^2}[/tex]

[tex]\mathbf{ [IO_3^-]^2 = \dfrac{3.9\times 10^{-8} }{(0.229)}}[/tex]

[tex]\mathbf{ [IO_3^-]^2 = 1.703 \times 10^{-7} \ M}[/tex]

Therefore, we can conclude that the initial predicted concentration of IO₃⁻ needed to start the precipitation titration is 1.703 × 10⁻⁷ M

Learn more about solubility product constant here:

https://brainly.com/question/17274813?referrer=searchResults

Answer:

Ba 80.148%. H 1.77% O 18.657%

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

A vessel contains a gaseous mixture of nitrogen and butane. At 126.9 °C (400.1 K) the pressure is due to the mixture is 3.0 atm.

We can calculate the total number of moles using the ideal gas equation.

[tex]P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{3.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.091 mol/L \times V[/tex]

At 0 °C (273.15 K), the pressure due to the gaseous nitrogen is 1.0 atm.

We can calculate the moles of nitrogen using the ideal gas equation.

[tex]P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{1.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.030 mol/L \times V[/tex]

The mole fraction of nitrogen in the mixture is:

[tex]X(N_2) = \frac{0.030 mol/L \times V}{0.091 mol/L \times V} = 0.33[/tex]

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

Learn more: https://brainly.com/question/2060778

The molecules of the two gases will have the same kinetic energy at room temperature.

The average kinetic energy of gaseous molecules can be calculated using the formula:

Kinetic Energy = 3/2RT, where R = constant and T = temperature in Kelvin

This means that the kinetic energy of a gaseous molecule is dependent on the temperature of the molecule only.

In other words, the molecular mass of molecules of gases has no bearing on the kinetic energy of each molecule.

More on kinetic energy of gases can be found here: https://brainly.com/question/999862

Answer:

Add a volume of a solution of known concentration is added to a volume of another solution in order to determine its concentration. Solutions in which a few drops of phenolphthalein have been added turn from colorless to brilliant pink as the solution turns from acidic to basic.

If you want the method:

Method

1) Use a pipette and pipette filler to add 25 cm3 of alkali solution to a clean conical flask.

2) Add a few drops of a suitable indicator and put the conical flask on a white tile.

3) Fill the burette with dilute acid. Flush the tap through to remove any air bubbles. Ensure the burette is vertical.

4) Slowly add the acid from the burette to the conical flask, swirling to mix. (The mixture may at first change colour, and then back again when swirled.)

5) Stop adding the acid when the end-point is reached (when the colour first permanently changes). Note the final volume reading.

6) Repeat steps 1 to 5 until three results are repeatable (in close agreement). Ideally these should lie within 0.10 cm3 of each other.

I hope it helps.

Answer:

To conduct a titration experiment, first fill the burette with an acid or base solution of known concentration. After that, take a burette reading from the top of the miniscus down to the bottom. Then, underneath the burette, place a flask containing an unknown concentration of acid or base. After that, fill the flask halfway with the appropriate indicator and shake it up. Add your titrate to the flask one drop at a time while stirring constantly. Continue to add the titrate until the color change is noticeable. Finally, take one more look at the burette to make sure everything is correct.

Explanation:

Hope it helps:)