15. Find the density of a certain object that has the dimensions 2cm x 6cm x 7cm and a
mass of 42g.
16. What is the volume of a container of liquid that has a density of 120g/ml and a mass
of 17g.
17. If the mass of an object has a mass of 23g and a volume 123ml, what is its density.
“Express your answer in Kg/ml!"
18. What is the volume of a cubed object with a measure of 12cm on one of its sides, if
the mass of that same object is 45g and its density is 240g/cm3?
19. An object with a density of 3g/ml is placed into a body of water. Since the density of
water is 1g/ml, will this object sink or float.

15. Find The Density Of A Certain Object That Has The Dimensions 2cm X 6cm X 7cm And Amass Of 42g.16.

Answers

Answer 1

This question is asking for five different questions about density, mass and volume which can be all summarized with the following definition of density as the degree of compactness of the objects taken into consideration:

[tex]\rho =\frac{m}{V}[/tex]

In such a way, we can proceed as follows:

15. the mass is given as 42 g and the volume can be found by multiplying the given dimensions:

[tex]V=2cm*6cm*7cm=84 cm^3[/tex]

And the density turns out to be:

[tex]\rho =\frac{42g}{84cm^3}=0.5 g/cm^3[/tex]

16. both mass and density are given as 17 g and 120 g/mL respectively, so that we have to solve for the volume as shown below:

[tex]V=\frac{m}{\rho} =\frac{17g}{120g/mL} =0.14 mL[/tex]

17. the mass is given as 23 g and the volume as 123 mL, so that the density is calculated as shown below:

[tex]\rho=\frac{23g}{123 mL} =0.19 g/mL[/tex]

Which can be converted to kg/mL as follows:

[tex]0.19\frac{g}{mL} *\frac{1kg}{1000g}=0.00019 kg/mL[/tex]

18. the mass is given as 45 g and the density as 240 g/cm³, so we can solve for the volume as follows:

[tex]V=\frac{m}{\rho} =\frac{45g}{240g/cm^3}=0.19 cm^3[/tex]

19. In this case, since the water has lower density than the object, we can infer that the latter is heavier than the former, this means that the object will sink according to the Archimedes principle.

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Related Questions

What is the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4 m/s? (Formula: ) 3 J 6 J 12 J 24 J.

Answers

The kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.

HOW TO CALCULATE KINETIC ENERGY:

The kinetic energy of a moving body can be calculated by using the following formula:

K.E = ½mv²

Where;

K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)

According to this question, a toy truck has a mass of 0.75 kg and a velocity of 4 m/s. The kinetic energy is calculated as follows:

K.E = ½ × 0.75 × 4²

K.E = 8 × 0.75

K.E = 6J

Therefore, the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.

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Question 17 (Essay Worth 5 points)
(02.06 HC)
Choose two spheres of Earth which interact when hot springs are formed. Use complete sentences to explain how they interact during this process
X2
= 12 Source
ус
cM
В І
U S XX T
.
Styles
Format
Font
Size
A- A -
Increase Indent

Answers

Answer:

geosphere and hydrosphere

Explanation:

HELPPP PLEASE
1) if the distance between two masses are 15 meters and the masses are 350kg and 492 kg
respectively; what is the magnitude of gravitational force?

Answers

Answer:

-8

5.092×10

Explanation:

given,

distance (d) =15m

mass (M1) =350kg

mass(M2) = 492kg

Gravitational constant (G)=6.67×10^-11

we know,

gravitational force=(Gm1m2)÷d^2

=(6.67×10^-11×350×492)÷15^2

= (1.14857×10^-5)÷225

= 5.092×10^-8

A net force of 79 N causes a mass to accelerate at a rate of 3 m/s2. Determine the mass

Answers

Force= mass x acceleration

79=mass(3)

m=79/3

m=26.3 kg

you serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has how much energy

Answers

Answer:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

When an object is balanced about a pivot, the total clockwise moment must be equal to the total __________ __________. What two words complete this sentence?

Answers

Answer:

When an object is balanced, about a pivot, the total clockwise moment must be equal to the total anticlockwise moment about that pivot.

Hope that helps.

When an object is balanced about a pivot, the total clockwise moment must be equal to the total anticlockwise moment.

What is balancing?

Clockwise involves turning to the right while going in the direction of a clock's hands. The moment is referred to as a clockwise moment if the force acting on a body rotates the body clockwise with regard to the axis of rotation.

On the other hand, the moment is referred to as an anti-clockwise moment if the force rotates the body in the opposite direction. The clock face rule can be used to determine this magnet's polarity.

The face of the loop will display the North Pole if the current is flowing counterclockwise. On the other hand, if the current is moving counterclockwise, the South Pole is visible on the loop's face.

Therefore, the total clockwise and total counterclockwise moments must match when an object is balanced about a pivot.

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Rafiq has heard that continued exposure to light for 10 days can change the colour of some blue dyes used to colour cotton clothing. He decides to test this. He takes a piece of clothing dyed with a blue dye which is suspected to lose colour on such exposure. He cuts the cloth into two pieces.
Which experiment is likely to help him conclude if the dye indeed can change colour?
He should expose, for 10 days-

A. Both pieces under 2 identical lamps.
B. One piece under a lamp; keep the other in darkness.
C. One piece for 5 days and one for 10 days under identical lamps
D. One piece folded and one piece spread out under 2 identical lamps.

Answers

I think the answer is B

Mars is 7.83x10^10m [^10 is an exponent] from planet earth. The planet Earth is 5.98x10^24kg [^24 is an exponent] while Mars has a mass of 6.42x10^23kg [^23 is an exponent]. What is the gravitational attraction between the two planets? G=6.67×10^-11 (-11 is an exponent)​

Answers

Answer:

Approximately [tex]4.18 \times 10^{16}\; \rm N[/tex].

Explanation:

Consider two objects of mass [tex]m_{1}[/tex] and [tex]m_{2}[/tex]. Let [tex]r[/tex] denote the distance between the center of mass of each object. Let [tex]G[/tex] denote the gravitational constant. ([tex]G \approx 6.67 \times 10^{-11}\; {\rm m^{3}\cdot kg^{-1}\cdot s^{-2}}[/tex].)

By Newton's Law of Universal Gravitation, the size of gravitational attraction between these two objects would be:

[tex]\begin{aligned}F &= \frac{G\, m_{1}\, m_{2}}{r^{2}}\end{aligned}[/tex].

In this question, [tex]m_{1} = 5.98\times 10^{24}\; {\rm kg}[/tex] and [tex]m_{2} = 6.24 \times 10^{23}\; {\rm kg}[/tex] are the mass of the two planets. The distance between the two planets is [tex]r = 7.83 \times 10^{10}\; \rm m[/tex] (approximately the same as the distance between the center of mass of planet Earth and the center of mass of Mars.)

Apply Newton's Law of Universal Gravitation to find the size of gravitational attraction between the two planets:

[tex]\begin{aligned}F &= \frac{G\, m_{1}\, m_{2}}{r^{2}} \\ &= \frac{1}{(7.83 \times 10^{10}\; {\rm m})^{2}} \\ &\quad \times (6.67 \times 10^{11}\; {\rm m^{3} \cdot kg^{-1} \cdot s^{-2}}) \\ &\quad \times (5.98 \times 10^{24}\; {\rm kg}) \\ &\quad \times (6.42 \times 10^{23}\; {\rm kg}) \\ &\approx 4.18 \times 10^{16}\; {\rm kg \cdot m \cdot s^{-2}} \end{aligned}[/tex].

Since  [tex]1\; {\rm kg \cdot m \cdot s^{-2}} = 1\; {\rm N}[/tex], the size of gravitational attraction between the two planets would be approximately [tex]4.18 \times 10^{16}\; {\rm N}[/tex].

A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.

Answers

So acceleration of the bike which started from rest, reaches at speed of 7.10 m/s by travelling distance 35.4 m will be 0.712 m/ sec^2.

_____________ is the study of movement in athletes. A. Sports biomechanics B. Posture C. Dynamics D. Anatomy

Answers

Answer:

I believe its A: Sports biomechanics.

is orange orange because its orange or is orange orange because its orange

Answers

Answer:

orange it is lol

Explanation:

Answer:

HELP ORANGE DOESNT LOOK LIKE A WORD ANYMORE

Explanation:

In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the two balls collide, the final momentum of the cue ball is 0.01 kg m/s

Answers

Answer: 0.22

Explanation: Subtract 0.01kg from 0.23kg

1. A block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s. ​

Answers

Answer:

397 j

Explanation:

Because 5.0kg yuh

The kinetic energy of the block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s is 396.9 J.

What is kinetic energy?

A moving item or particle has a certain kind of power called kinetic energy. When an item exerts a net force to perform work, which involves the transfer of energy, the object accelerates and as a result, gains kinetic energy.

The amount of kinetic energy that a moving object or particle possesses is determined by both its mass and rate of motion. Any combination of vibration, axis rotation, translation (or movement along a path from one location to another), and translation are all possible motion types.

Given:

The mass of the block, m = 5 kg,

The horizontal force, F = 80 N,

The velocity of the block, v = 12.6 m / s,

Calculate the kinetic energy by the formula given below,

[tex]KE = 1/2mv^2[/tex]

KE = 1 / 2 × 5 × 12.6²

KE =  1 / 2 × 5 × 158.6

KE = 396.9 J

Therefore, the kinetic energy of the block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s is 396.9 J.

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The complete question is A block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s. ​Find its kinetic energy?

Select the correct answer. What are the directions of an object's velocity and acceleration vectors when the object moves in a circular path with a constant speed? A. The question is meaningless, since the acceleration is zero.
B. The vectors point in opposite directions.
C. Both vectors point in the same direction.
D. The vectors are perpendicular.

Answers

The centripetal acceleration which always  act toward the center of the circle. The vectors are perpendicular. The correct answer for this question, is option D

The speed of an object is always constant in a  circular motion while the object keeps changing direction regularly. The velocity will keep changing because of the change in direction.

Whenever there is a change in velocity, there must be acceleration.

When the object is moving in a circular path with a constant speed, the directions of an object's velocity and acceleration vectors will be perpendicular to each other

The reason is because acceleration is centripetal acceleration which always  act toward the center of the circle.

Therefore, the correct answer for this question, is option D

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the system shown above is released from rest. if friction is negligible, the acceleration of the 4.0 kg block sliding on the table shown above is most nearly

Answers

The acceleration of the first block (4 kg) is -9.8 m/s².

The given parameters:

Mass of the first block, m₁ = 4.0 kgMass of the second block, m₂ = 2.0 kg

The net force on the system of the two blocks is calculated as follows;

[tex]m_2 g - T = m_1 a[/tex]

where;

T is the tension in the connecting string due weight of the first block

[tex]m_2 g - m_1 g = m_1 a\\\\a = \frac{m_2 g - m_1g}{m_1} \\\\a = \frac{g(m_2 - m_1)}{m_1} \\\\a = \frac{9.8(2-4)}{2} \\\\a = -9.8 \ m/s^2[/tex]

Thus, the acceleration of the first block (4 kg) is -9.8 m/s².

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Exert a force on the object, what happens to their state of motion​

Answers

The force might make the object move or bring the object to rest or change in direction of motion

HELP!!!!!!!!!!!!

9. Estimate the change in the thermal energy of water in a pond with a mass of
1000 kg and a specific heat of 4200 J/(kg. C) if the water cools by 1°C.

Answers

Answer:

-4,200,000 J

Explanation:

Why doesn't the skater ever regain his potential energy? ​

Answers

Answer:

Friction

Explanation:

As the skateboarder goes down the ramp, potential energy is converted to kinetic energy. Because of friction, some of the energy in the system is converted to heat energy. Once the kinetic energy is converted to heat, the energy cannot be converted back to the potential or kinetic energy in the system.

The magnetic field 0. 02 m from a wire is 0. 1 T. What is the magnitude of the magnetic field 0. 01 m from the same wire? 0. 01 T 0. 05 T 0. 1 T 0. 2 T.

Answers

The magnitude of the magnetic field 0.01 m from the same wire is 0.2 T.

Given to us:

Magnetic field, [tex]B_1 = 0.1\ T[/tex]

Radius of wire, [tex]R_1 = 0.02\ m[/tex]

To find out the magnitude of the magnetic field 0. 01 m from the same wire, we need to find out current first. we will use the formula,

[tex]B = \dfrac{\mu_oI }{2\pi R},\\\rn\\where,\\B= magnetic\ field\\\mu_o = 4\pi\times 10^{-7} m\cdot kg\cdot s^{-2} A^{-2}\ is\ the\ magnetic\ constant\\I= current\\R= radius\ of\ the\ wire[/tex]

Putting the values,

[tex]B_1 = \dfrac{\mu_oI }{2\pi R_1},\\\rn\\\\0.1= \dfrac{4\times \pi \times 10^{-7}\times I}{2\times \pi\times0.02}\\\\I=10,000\ A[/tex]

Now, for [tex]B_2[/tex]

[tex]B_2 = \dfrac{\mu_oI }{2\pi R_2},\\\rn\\\\B_2= \dfrac{4\times \pi \times 10^{-7}\times 10,000}{2\times \pi\times0.01}\\\\B_2= 0.2\ T[/tex]

Hence, the magnitude of the magnetic field 0. 01 m from the same wire is 0.2 T.

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A 263 g ball of clay falls onto a vertical spring.

The spring constant k = 2.52 N/cm.

The clay sticks to the spring and as the spring compresses a distance of 11.8 cm the clay momentarily comes to rest.
Determine the speed of the clay just before it hit the spring in [m/s]?

Answers

As the spring is compressed, it performs

-1/2 (252 N/m) (0.118 m)² ≈ -1.75 J

of work on the clay, while gravity does

(0.263 kg) (9.80 m/s²) (0.118 m) ≈ 0.304 J

on it. Then the total work W performed on the clay ball is approximately -1.45 J.

By the work-energy theorem, W is equal to the change in the clay ball's kinetic energy ∆K. If v is the speed with which it hits the spring, then

W = ∆K

-1.45 J = 0 - 1/2 mv²

Solve for v :

-1.45 J = -1/2 (0.263 kg) v²

v² ≈ 11.0 m²/s²

v ≈ 3.32 m/s

hi my name is coolboy123hillok

Answers

Answer:

you should change that name

please change your name

Pleaseeeee HELPPPP THIS IS TIMED ALSO,
A book slides along a table and comes to a stop. Explain, in detail, all the forces acting on the book.

Answers

Answer:

Friction, normal force, and weight

Explanation:

If the book slows down, it means that there must be friction acting in the opposite direction of the direction the book is moving in.

Weight is caused by the gravitational pull of the Earth on the book, and normal force is the table pushing the book up because the book is pushing down on the table (3rd law.)

Note that weight and normal force is not the 3rd law action-reaction pair. The pair is the force of the book on the table and the force of the table on the book.

9. How are ecological footprints useful?

Answers


As ecological footprints provide an easily communicable way of measuring the ecological bottom‐line condition for sustainability, it is a useful tool for promoting a sustainable future. It is particularly useful for cities, as it is in cities where the battle for sustainability will be won or lost.

Answer:

This is what the Ecological Footprint does: It measures the biologically productive area needed to provide for everything that people demand from nature: fruits and vegetables, meat, fish, wood, cotton and other fibres, as well as absorption of carbon dioxide from fossil fuel burning and space for buildings and roads.

Why it's useful:

Ecological footprint (EF), measure of the demands made by a person or group of people on global natural resources. It has become one of the most widely used measures of humanity’s effect upon the environment and has been used to highlight both the apparent unsustainability of current practices and the inequalities in resource consumption between and within countries.

If the action force is the swimmer pushing water in the leftward direction, what is the reaction force?

PLEASE ANSWER
CORRECTLY PLS

Answers

According to Newton's Third Law of Motion, to every action, there is an equal and opposite reaction; action and reaction act on different bodies.Here, the action force is in the leftward direction, so the reaction will be in the opposite direction.If the action force is the swimmer pushing water in the leftward direction, then the reaction force is in the rightward direction.And the reaction force will be given by the water on the swimmer.

Answer:

The reaction force is the water pushing the swimmer in the rightward direction.

Hope you could get an idea from here.

Doubt clarification - use comment section.

A textbook is sitting at rest on a desk. Compared to the magnitude of the force of the textbook on the desk, how
would you describe the magnitude of the force of the desk on the book?
o less
O zero
O more
O equal

Answers

Equal because the book is not moving and the forces are balanced/equal

Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. The mass of the eight ball, m2, is 6 g with a velocity of 1 m/s. After the balls collide, they bounce off each other. The number three ball moves off with a velocity of 5 m/s. What is the final velocity and direction of the eight ball? 8. 6 m/s 5. 7 m/s â€"5. 7 m/s â€"8. 6 m/s.

Answers

This question involves the concepts of the law of conservation of momentum and velocity.

The velocity of the eight ball is "5.7 m/s".

According to the law of conservation of momentum:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

m₁ = mass of number three ball = 5 g

m₂ = mass of the eight ball = 6 g

u₁ = velocity of the number three ball = 3 m/s

u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)

v₁ = final velocity of the three number ball = - 5 m/s

v₂ = final velocity of the eight ball = ?

Therefore,

(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)

[tex]v_2=\frac{34\ g.m/s}{6\ g}\\\\[/tex]

v₂ = 5.7 m/s

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A cheetah runs at an average speed of 60mph. find the distance it runs in 30 s

Answers

Answer:60mph means it runs every minute.

Explanation: because it makes sense.

Answer:

  2640 ft, or 1/2 mile

Explanation:

Recognizing that 30 s = 0.5 min, we can convert the units like this.

  distance = speed × time

  distance = (60 mi/h) × (1 h/(60 min)) ×(0.5 min) = 0.5 mi

In feet, that is ...

  (5280 ft/mi)(0.5 mi) = 2640 ft

A cheetah runs 1/2 mile, or 2640 feet in 30 s.

What is the velocity of a dropped object after it has fallen for 3.0 s?

Answers

Answer:

30 m/s.

Explanation:

how are mass, distance and gpe related

Answers

Answer:

It is direct proportionality. The greater the mass, the greater is the gravitational potential energy. The equation for GPE is : GPE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height above the ground. As you can see GPE is directly proportional to mass, and height. KT.

Explanation:

Gravitational potential energy is a function of both the mass of your system and the mass of the thing generating the gravity field around your system.

The relationship is linear, which means that if you multiply or divide one of the masses by some number but leave everything else the same, you multiply or divide the potential energy by the same number. A 3kg mass has three times the gravitation potential energy of a 1kg mass, if placed in the same location.

how to read a micrometer on a clark cm-100 vickers hardness tester

Answers

Answer:

Explanation:

Equipment manufactured by LECO(8 Corporation, St. Joseph, Michigan is warranted free from defect in material

and workmanship for a period of six months from the date of purchase. Equipment not manufactured by LECO is

covered to the extent of warranty provided by the original manufacturer and this warranty does not cover any

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be covered under warranty for a period of thirt days from date of purchase. LECO MAKES NO OTHER

REPRESENTATION OR WARRANTY OF ANY OTHER KIND, EXPRESSED OR IMPLIED, WITH RESPECT TO

THE GOODS SOLD HEREUNDER, WHETHER AS TO MERCHANTABILITY, FITNESS FOR PURPOSE, OR

OTHERWISE.

Expendable items such as crucibles, combustion tubes, chemicals and items of like nature are not covered by

this warranty.

LECO's sole obligation under this warranty shall be to repair or replace any part or parts which, to our

satisfaction, prove to be defective upon return prepaid to LECO Corporation, St. Joseph, Michigan. This

obligation does not include labor to install replacement parts, nor does it cover any failure due to accident, abuse,

neglect, or use in disregard of instructions furnished by LECO. In no event shall damages for defective goods

exceed the purchase price of the goods, and LECO SHALL NOT BE LIABLE FOR INCIDENTAL OR

CONSEQUENTIAL DAMAGES WHATSOEVER.

All claims in regard to the parts or equipment must be made within ten (10) days after Purchaser learns of the

facts upon which the claim is based. Authorization must be obtained from LECO prior to returning any other

parts. This warranty is voided by failure to comply with these notice requirements.

NOTICE

The warranty on LECO equipment remains valid only when genuine LECO replacernent parts are employed.

Since LECO has no control over the quality or purity of consumable products not manufactured by LECO, the

specifications for accuracy of results using LECO instruments are not guaranteed unless genuine LECO

consumables are employed in conjunction with LECO instruments. If purchaser defaults in making payment for

any parts or equipment, this warranty shall be void and shall not apply to such parts and equipment. No late

payment or cure of default in payment shall extend the warranty period provided herein.

LECO Corporation is not responsible for damage to any associated instruments, equipment or apparatus nor wil

LECO be held liable for loss of profit or other special damages resulting from abuse, neglect, or use in disregard

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The instrument should be operated only by technically qualified individuals who have fully read and understand

these instructions. The instrument should be operated only in accordance with these instructions.

The operator should follow all ,of the warnings and cautions set forth in the manual and the operator should follow

and employ all applicable standard laboratory safety procedures.

LECO'" is a registered trademark of the LECO Corporatio

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