5-2(a+3b)/2 When a=4 and b=1.
Hello macelynn190!
[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]
[tex] \huge \tt \frac{5 - 2(a + 3b)}{2} [/tex]
[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]
To solve this question we need to substitute the given values of 'a' & 'b' in the equation & then simplify it.
Given,
a = 4b = 1Now, substitute this in the place of 'a' & 'b'..
[tex]\large \tt \frac{5 - 2(a + 3b)}{2} \\ = \large \underline{\underline{\tt \: \frac{5 - 2((4) + 3(1))}{2} }}[/tex]
Lastly, simplify it...
[tex]\large \tt \: \frac{5 - 2((4) + 3(1))}{2} \\ = \large \tt\frac{5 - 2(4 + 3)}{2} \\ = \large \tt \: \frac{5 - 2(7)}{2} \\ = \large \tt \: \frac{5 - 14}{2} \\ = \large \tt\frac{-9}{2} \\ = \large \boxed{\boxed{ \bf \: -\frac{9}{2}=-4.5}}[/tex]
The answer is -9/2 or -4.5__________________
Hope it'll help you!
ℓu¢αzz ッ
Given info:-
Simplify: 5-2(a+3b)/2. When a=4 and b=1.
[5-2(a+3b)]/2
Now, put a=4 and b=1 (Because this is given in question only)
so,
⇛[5-2{4+3(1)}]/2
⇛[5-2{4+3}]/2
⇛[5-2{7}]/2
⇛[5-2×7]/2
⇛[5-14]/2
⇛-9/2 Ans.
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
7/10 ÷ 3/8
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Change to a mixed number
15 goes into 28 1 time with 13 left over
1 13/15
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Step-by-step explanation:
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Step-by-step explanation:
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Sale kute bhan के lole
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you multiply it
500 x 10 = 5000
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Answer:
Ummm..... I would think 10??
Step-by-step explanation:
I don't really know tho.....
Answer:
10
Step-by-step explanation:
4x = 40
/4 /4
x = 10
Rationalise the denominator of: -7/(√11 - √5)
[tex] \sf \underline{ \red{Solution - }} \\ [/tex]
Given,
[tex] \sf{\quad { \dfrac{-7}{\sqrt{11} - \sqrt{5}} }} \\ [/tex]
The denominator is √11 - √5.
We know that
Rationalising factor of √a-√b is √a+√b.
Therefore, the rationalising factor of √11-√5 is √11+√5.
On rationalising the denominator them
[tex] \longrightarrow \sf{\quad { \dfrac{-7}{\sqrt{11} - \sqrt{5}} \times \dfrac{(\sqrt{11} + \sqrt{5})}{(\sqrt{11} + \sqrt{5})} }} \\ [/tex]
Multiplying (√11 + √5) with both the numerator of the fraction.
[tex] \longrightarrow \sf{\quad { \dfrac{-7(\sqrt{11} + \sqrt{5}) }{(\sqrt{11} - \sqrt{5})(\sqrt{11} + \sqrt{5})} }} \\ [/tex]
Performing multiplication in the numerator and by using identity (a + b)(a - b) = a² - b², solving further in the denominator.
[tex] \longrightarrow \sf{\quad { \dfrac{-7\sqrt{11} -7\sqrt{5}}{(\sqrt{11})^2 - (\sqrt{5})^2} }} \\ [/tex]
Writing the squares of the numbers in the denominator.
[tex] \longrightarrow \sf{\quad { \dfrac{-7\sqrt{11} -7\sqrt{5}}{11 -5} }} \\ [/tex]
Performing subtraction in the denominator.
[tex] \longrightarrow \quad \underline{ \boxed{ \dfrac{ \textbf{ \textsf{-7 }}\sqrt{ \textbf{ \textsf{11 }}} - \textbf{ \textsf{7}}\sqrt{ \textbf{ \textsf{5 }}}}{ \textbf{ \textsf{ 6}}}} } \\ [/tex]
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Answer:
[tex]1,171,862[/tex]
Step-by-step explanation:
Original equation: [tex]5^7 * 15-8-5[/tex]
Remember the PEMDAS rule --> in this case the exponents are first.
[tex]5^7[/tex]= 5*5*5*5*5*5*5 = 78,125
= [tex]78,125*15-8-5[/tex]
The next step to this problem is multiplication because you are starting from left to right and its after the exponents.
= [tex]1,171,875-8-5[/tex]
The last 2 steps is to subtract (from left to right)
= [tex]1,171,867-5[/tex]
= [tex]1,171,862[/tex]
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Answer:
c or d
Step-by-step explanation:
Answer:
D. y = -2x - 10Step-by-step explanation:
Slope- intercept form:
y = mx + bIn the process of solving it was found that:
m = -2 and b = -10The equation therefore is:
y = -2x - 10Correct choice is D