Answer:
12583.2 J or 12.5832 KJ
Explanation:
Work done can be expressed as force multiplied by displacement, or
W = Fs
In this case, we can calculate the force by using F = mg.
m is the mass, 214 kg, and g is gravitational acceleration, which is 9.8 m/s/s.
So, we Calculate 214 * 9.8 to get 2097.2
The displacement is 6m.
So, by doing W = Fs, we get
2097.2 * 6 = 12583.2 Joules
A frog jumps as is moves. what is the relation between its maximum height and maximum range
The relation between a frog's maximum height and maximum range is that when the frog jumps at an angle of 45°, its maximum height is half of the horizontal range.
What are the maximum height and maximum range?The maximum height refers to the maximum vertical distance that an object can travel.
The maximum range is the maximum horizontal distance that an object can travel.
The maximum height, H that the projectile reaches when the range, R, is at its greatest is H = Rmax /4.
R = 4Hcot is the relationship between the horizontal range and maximum height.
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Please need help ASAP, ASAP
If force is doubled, acceleration will also be doubled.
Newton’s second law of motion, unlike the first law of motion, pertains to the behaviour of objects for which all existing forces are unbalanced. The second law of motion is more quantitative and is used extensively to calculate what happens in situations involving a force.It states that: Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body. This means that as the force acting upon an object is increased, the acceleration of the object is increased.In this given question, force is doubled. We know that force is directly proportional to acceleration. As we increase the force on an object the acceleration increases proportionally. Therefore, if you double the force you double the acceleration.
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The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration.
The magnitude of the constant acceleration of the ball is 9.7 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the constant acceleration of the ball, we use the formula below.
Formula:
a = (v-u)/t................. Equation 1From the question,
Given:
a = Acceleration,v = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 33 m/su = 0 m/s t = 3.4 secondsSubstitute these values into equation 1
a = (33-0)/3.4a = 9.7 m/s²Hence, the acceleration is 9.7 m/s².
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How do you add sound waves?
The addition of two sound waves produces a new wave of higher amplitude if their compressions and refractions line up. It is also known as constructive interference.
What is interference?Interference can be described as a phenomenon in which two waves combine by adding at every single point in space and time, to form a resultant wave of greater or lower amplitude.
Constructive and destructive interference occurs in the interaction of waves that are correlated with each other because they come from the same source.
When two sound waves propagate in the same direction in phase with each other, their amplitude gets added, and the resultant wave is produced from constructive interference.
When two waves interfere with each other and have a displacement in the opposite direction. When a crest of a wave meets the trough of another wave, the waves undergo destructive interference.
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A graph of v(t) is shown for a world-class track sprinter in a 100 -m race. (See figure below. For each answer, enter a number.)
(a) What is his average velocity (in m / s ) for the first 4 s} ?
______ m/ s
(b) What is his instantaneous velocity (in m / s ) at t=6 s ?
______ m / s
(c) What is his average acceleration (in m / s²) between 0 and 4s?
________m / s²
(d) What is his time (in s) for the race?
______ s
a) The average velocity at 4s is 12 m/s
b) The instantaneous velocity at t= 6s is 12 m/s
c) The average acceleration is; 12 - 0/ 4 - 0 n= 3 m/s^2
d) The time for the race is 10 s
What is the velocity time graph?We know that the velocity time graph is the kind of set up that has two axis and we can be able to use it to be read off the velocity of the acceleration of the object. I would want us to recall that the acceleration is the rate of change of the velocity of the object with time.
Now we have that;
The graph for the velocity of the object can be obtained by looking at the image that has been shown and then we read off the points that are on the graph. The vertical axis shows the velocity of the graph while the horizontal axis shows the time that is covered in the graph.
The acceleration would be the ratio of the change in the velocity to the change in the time of the object.
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A box is dropped out of a moving airplane. The airplane is traveling at 50m/s East. The box is dropped from rest with respect to the airplane. The box travels a vertical distance of 40 m before landing on a trampoline. The airplane continues traveling at a constant speed after the box is dropped and the wind resistance on the falling box is negligible
The horizontal distance travelled by the box is 143 m.
What is the horizontal distance travelled by the box?
The horizontal distance travelled by the box is calculated by determining the time of motion of the box and the horizontal velocity of the airplane.
The time of motion of the box from the vertical height in which it was dropped is calculated as follows;
h = vt + ¹/₂gt²
where;
v is the initial vertical velocity of the box = 0t is the time of motion of the boxg is acceleration due to gravityh is the height of fall of the boxh = 0 + ¹/₂gt²
t = √ ( 2h / g )
t = √ ( 2 x 40 / 9.8 )
t = 2.86 seconds
The horizontal distance travelled by the box is calculated as follows;
d = Vₓ t
where
Vₓ is the horizontal velocity of the airplanet is the time of motiond = ( 50 m/s ) x ( 2.86 s )
d = 143 m
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The complete question is below;
A box is dropped out of a moving airplane. The airplane is traveling at 50m/s East. The box is dropped from rest with respect to the airplane. The box travels a vertical distance of 40 m before landing on a trampoline. The airplane continues traveling at a constant speed after the box is dropped and the wind resistance on the falling box is negligible. Find the horizontal distance travelled by the box.
A horse trots past you and then a fencepost that is 36m away from you. It takes the horse 11.0 sec to make this trot. What is the average velocity of the horse?
As the horse trots a fencepost that is 36m away from you in 11.0 second, the average velocity of the horse is 3.27 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
A horse trots past you and then a fencepost that is 36m away from you.
Time taken to make this trot = 11.0 second.
Hence, the average velocity of the horse is = total distance travelled/time interval
= 36/11.0 m/s
= 3.27 m/s.
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As shown in the picture above, an ice skater is skating at a constant speed in a circle. Is she accelerating? Explain your answer and draw the direction of the velocity in point A, B, C, and D.
Yes, the skater is accelerating.
Acceleration is a change in speed OR direction OR both. Since she's skating in a circle, her direction is constantly changing, so she is accelerating.
At A, her velocity points down.
At B, her velocity points right.
At C, her velocity points up.
At D, her velocity points left.
A single movable pulley is used to lift 4000N load to the height of 50 cm. If the efficiency of the pulley is 75%, Calculate effort distance,effort applied,output work and mechanical advantage.
Since the efficiency of the pulley is 75% and the single movable pulley is used to lift 4000N load to the height of 50 cm, the effort distance, effort applied, output work and mechanical advantage are as follows:
Effort Distance = 50 cm
Effort Applied = 5333.33 N
Output work = 2000 J
Mechanical Advantage = 0.75.
When a single movable pulley is used to lift a load, the effort applied is equal to the weight of the load being lifted, and the effort distance is the distance the effort is applied.
Load (output force) = 4000 N
Height lifted = 50 cm = 0.5 m
Efficiency of the pulley = 75%
Given the above information, we can calculate the effort applied, output work, and mechanical advantage as follows:
Effort applied (input force) = Load ÷ Efficiency
= 4000 N ÷ 0.75
= 5333.33 N
Output work = Load x Height lifted
= 4000 N x 0.5 m
= 2000 J
Effort distance = Height lifted
= 50 cm
Mechanical advantage = Load ÷ Effort applied
= 4000 N ÷ 5333.33 N
= 0.75
It is worth noting that pulley efficiency is the ratio of output work to the input work. And since the efficiency of the pulley is 75% so the input work is greater than the output work, which means some of the energy is wasted in overcoming friction and other losses.
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Exercise 24.28
For the capacitor network shown in (Figure 1), the potential difference across ab is 48 V.
Part A
Find the total charge stored in this network.
Express your answer with the appropriate units.
Q = ___ ____
Part B
Find the charge on the 150nF capacitor.
Express your answer with the appropriate units.
Q₁ = 7.2uC
Part C
Find the charge on the120nF capacitor.
Express your answer with the appropriate units.
Q₂ = 5.76 uC
Part D
Find the total energy stored in the network.
Express your answer with the appropriate units.
U = ____ ____
Part E
Find the energy stored in the 150nF capacitor.
Express your answer with the appropriate units.
U₁ = ______
Part F
Find the energy stored in the 120nF capacitor.
Express your answer with the appropriate units.
U₂= _____
Part G
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₁= ____
Part H
Find the potential difference across the 150nF capacitor.
Express your answer with the appropriate units.
V₂ = ____
The evaluation of the capacitor (in series) network is as follows;
Part A
Q = 3.2 μC
Part B
Q₁ = 3.2 μC
Part C
Q₂ = 3.2 μC
Part D
U = 76.8 μJ
Part E
U₁ = 34 2/15 μJ
Part F
U₂ = 53 1/3 μJ
Part G
V₁ = 21 1/3 V
Part H
V₂ = 26 2/3 V
What is a capacitor?A capacitor consists of pairs of conductors separated by insulators. Capacitors are used to store electric charge.
The specified parameters are;
The voltage across ab = 48 V
The capacitance of the first capacitor, C₁ = 150 nF
Capacitance of the second capacitor, C₂ = 120 nF
Part A
The total charge in a capacitor network can be found as follows;
[tex]C_{eq} = \left(\dfrac{1}{150} + \dfrac{1}{120} \right)^{-1} nF = \left(\dfrac{3}{200} \right)^{-1}nF[/tex]
[tex]C_{eq} =\left(\dfrac{3}{200} \right)^{-1}nF=66\frac{2}{3} \, nF[/tex]
[tex]Q_{eq} = C_{eq}\times V_{ab}[/tex]
Therefore;
[tex]Q_{eq}[/tex] = 66 2/3 nF × 48 V = 3,200 × 10⁻⁹ C = 3.2 μC
The total charge in the circuit is 3.2 μCPart B
The charge in the 150 nF capacitor is obtained from the formula for the charge in a capacitor; Q = C × V as follows;
Q = C₁V₁ = C₂V₂
The charge in the capacitors, C₁ and C₂ are the same as the total charge of 3.2 μC
The charge, Q₁ on the 150 nF capacitor, C₁ is therefore, 3.2 nC
Q₁ = 3.2 nCPart C
The capacitors, C₁ and C₂ are in series, therefore, the charge in each capacitor is equivalent to the charge in the circuit, which is 3.2 μC.
Therefore, the charge, Q₂, in the 120 nF capacitor, C₂ is 3.2 μC
Q₂ = 3.2 μF
Part D
The total energy stored in the network can be obtained using the formula;
U = (1/2)·C·V²
Where;
U = The energy in the capacitor
C = The equivalent capacitance of the network = 66 2/3 nF
V = The voltage
Therefore;
[tex]U = \dfrac{1}{2} \times C_{eq}\times V^2[/tex]
[tex]U = \dfrac{1}{2} \times 66\frac{2}{3} \times 10^{-9}\times 48^2 = 76.8[/tex]
The total energy in the circuit, U = 76.8 μJPart E
The energy stored in the 150 nF capacitor is found as follows;
[tex]Q_{eq}[/tex] = Q₁ = C₁ × V₁
V₁ = [tex]Q_{eq}[/tex] ÷ C₁
Therefore;
V₁ = 3.2 μC ÷ 150 nF = [tex]21\frac{1}{3}[/tex] V
U₁ = 0.5×C₁×V₁²
U₁ = 0.5 × 150×10⁻⁹ × [tex]\left(21\frac{1}{3} \right)^2[/tex] = 34[tex]\frac{2}{15}[/tex] μJPart F
The energy stored in the 120 nF capacitor, U₂, can be found as follows;
V₂ = 3.2 μC ÷ 120 nF = [tex]26\frac{2}{3}[/tex] V
U₂ = 0.5 × 150 nF × [tex]\left(26\frac{2}{3} \, V\right)^2[/tex] = [tex]53\frac{1}{3}\, \mathrm{ \mu J}[/tex]
The energy in the 120 nF capacitor is; U₂ = 53 1/3 μJPart G;
The potential difference across the 150 nF, obtained in Part E, is 21 1/3 V
V₁ = 21 1/3 VPart H
The potential difference across the 120 nF, obtained in part F, is 26 2/3 V
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when a resistor is connected to a battery, current flows through the resistor. If the voltage of the battery is doubled, the current will be?
Resistors limits the current/amps but keep the voltage the same.
What happens if you connect the resistor to the battery?You don't want to attach them together with a wire since there would be too much current loose through, such that the battery heats up till it blows or something.
Current is directly corresponding to voltage; a doubling of the voltage will double the current. But the current is also inversely comparable to the resistance; a doubling of the resistance will halve the current.
So we can conclude that Resistance residue is the same, but power becomes four times i.e. multiplication. If the current is I and the voltage is V,
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The same resultant force acts on objects 1 and 2. Object 1 accelerates at 2m/s² and Object 2 accelerates at 5m/s². Which object has the greater mass?
Answer:
Object 1
Explanation:
Newton's 2nd Law: F = ma, therefore m = F/a
This shows that mass is inversely proportional to acceleration. Because the resultant force (F) is held constant in this problem, the lower the acceleration, the greater the mass. Therefore, the object that accelerates at 2 m/s² has the greater mass. In other words, if the net force on both objects is the same, the object with the slower acceleration has the greater mass.
How much force is necessary to raise a 150n crate up a ramp to a 4m loading dock if 600 j or work are performed
Answer:
To solve this problem, you can use the formula for work, which is work = force x distance. In this case, the distance the crate is moved is the height of the loading dock, or 4 meters. The amount of work performed is given as 600 joules. So, you can set up the equation like this:
600 joules = force x 4 meters
To solve for the force, you can divide both sides of the equation by 4 meters:
600 joules / 4 meters = force x 4 meters / 4 meters
This simplifies to:
150 newtons = force
So, the force necessary to raise the 150-newton crate up the ramp to the 4-meter loading dock is 150 newtons.
Taylor has set this fitness goal: I will go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. What is MOST likely TRUE about this goal?
Since Taylor has set this fitness goal: I will go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. The option that MOST likely TRUE about this goal is option A:It is a short-term goal.
What is the fitness goal about?A short-term goal is a goal that can be achieved within a relatively short period of time, usually less than a year. In this case, the goal is to go to the YMCA and lift weights for 30 minutes every other day for the entire month of January.
In this case, Taylor's goal is to go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. This goal is specific, as it clearly states what Taylor wants to accomplish, and it is measurable.
This goal can be achieved within the month of January and it's a specific, measurable and time-bound goal, which are characteristics of short-term goals.
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See full question below
Taylor has set this fitness goal: I will go to the YMCA and lift weights for 30 minutes every other day for the entire month of January. What is MOST likely TRUE about this goal?
It is a short-term goal.
It is a long-term goal.
It is an unrealistic goal.
It is a mental health goal.
Answer:it’s a short-term goal
Explanation:
because it’s only for the month of January she will be doing this goal.
Determine the parallel and perpendicular components of the force of gravity for a 369 N object on a 28.4 degree incline
The parallel component of the force of gravity is the net force. The perpendicular component of the force of gravity is directed opposite the normal force and as such balances the normal force.
What is the perpendicular component of the force of gravity?In order to balance the normal force, the perpendicular component of gravity is pointed in the opposite direction. No other force can counteract the parallel component of the gravitational force.
What is the parallel component of the force of gravity?The presence of an imbalanced force will then cause the object to accelerate downward along the inclined plane. This acceleration is brought on by the parallel part of the gravitational force. The net force is a parallel part of the gravitational force.
Steps for Calculating the Force of Gravity on an Object Falling from an Inclined Plane: Determine the inclined plane's angle in the first step.Determine the object's mass on the inclined plane in step two.Determine and compute the gravitational force acting on the item.Determine and compute the parallel and perpendicular forces acting on the object.Formulas to Calculate the Force of Gravity on an Object Falling Down an Inclined Plane using Vocabularyincline plane: a wedged angle.Force of Gravitation the downward-moving gravitational force.Force that is parallel to the inclined plane's face is referred to as the perpendicular force.The force that is parallel to the inclined plane's face is known as the parallel force.Equation for Gravitational Force: The gravitational force is equal to the product of an object's mass and its gravitational acceleration.FGravity=m×g
where m is the object's mass and g is gravity's acceleration, which is 9.8 m/s2. In this case, the negative indicates that the force is downward-directed.
Equation for Perpendicular Force: The Perpendicular Force is equal to the gravitational force multiplied by the cosine of the angle of the inclined plane.FParallel=FGravity×Cos(Θ)
Equation for the Parallel Force: The Parallel Force is equal to the gravitational force multiplied by the sine of the inclined plane's angle.FParallel=FGravity×Sin(Θ)
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On what basis is it considered that the universe is expanding?
There is strong evidence to support the idea that the universe is expanding. One of the main pieces of evidence for this is the observation of the cosmic microwave background radiation, which is a faint glow of microwave radiation that permeates the entire universe. This radiation is thought to be a residual heat left over from the Big Bang, the event that is believed to have marked the beginning of the universe.
The cosmic microwave background radiation has a very even temperature throughout the universe, but if the universe were not expanding, we would expect to see some regions that are slightly hotter or cooler than others due to differences in density. However, measurements of the cosmic microwave background radiation show that it has a very uniform temperature, which suggests that the universe must be expanding in order to even out any temperature differences that may have existed in the past.
Other evidence for the expansion of the universe includes the observation of supernovae in distant galaxies, which are explosions of massive stars that can be used to measure the distances to those galaxies. These measurements have shown that the most distant galaxies are moving away from us at a speed that is proportional to their distance, which is consistent with the expansion of the universe.
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What is meant by half life ?
The four conducting cylinders shown in the figure are all made of the same material, though they differ in length and/or diameter. They are connected to four different batteries, which supply the necessary voltages to give the circuits the same current, I.
Rank the four voltages. V₁, V₂, V₃, and V₄. in order of decreasing value. Rank from largest to smallest. To rank items as equivalent, overlap them.
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The ranking of the voltages, V₁, V₂, V₃, and V₄ in the order of decreasing voltage value is; V₂ > V₃ > V₁ > V₄
What is the voltage of an electric circuit?A voltage is the difference in potential or pressure that pushes or causes the flow of electric current in a circuit or conducting loop.
The current flowing through the circuit can be found using the following formula;
[tex]I=\dfrac{V}{R}[/tex]
The formula for conductivity is presented as follows;
[tex]\sigma =\dfrac{l}{R\times A}[/tex]
Where;
σ = The conductivity of the material
l = The length
R = The resistance to electricity
A = The cross-sectional area of the conductor
Therefore;
[tex]R=\dfrac{V}{I}[/tex]
[tex]R=\dfrac{l}{A\times \sigma}[/tex]
[tex]\dfrac{V}{I} =\dfrac{l}{A\times \sigma}[/tex]
[tex]V=\dfrac{l \times I}{A\times \sigma}[/tex]
Based on the dimensions of the cylinders, obtained from a similar question, we get;
[tex]V_1=\dfrac{3\cdot L \times I}{\pi \cdot D^2\times \sigma} = 3\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}[/tex]
[tex]V_2= \dfrac{2\cdot L \times I}{\pi \cdot \dfrac{D^2}{4} \times \sigma} = \dfrac{8\cdot L \times I}{\pi \cdot D^2\times \sigma} = 8\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}[/tex]
[tex]V_3=\dfrac{L \times I}{\pi \cdot \dfrac{D^2}{4} \times \sigma} =\dfrac{4\cdot L \times I}{\pi \cdot D^2\times \sigma}= 4\times \dfrac{L \times I}{\pi \cdot D^2\times \sigma}[/tex]
[tex]V_4=\dfrac{L \times I}{\pi \cdot D^2\times \sigma} = 1\times \dfrac{ L \times I}{\pi \cdot D^2\times \sigma}[/tex]
Therefore;
V₁ = 3·V₄
V₂ = 8·V₄
V₃ = 4·V₄
The rank of the voltages in the order of decreasing value is therefore;
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In a particular crash test, an automobile of mass 1759 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 12 m/s and 2.2 m/s, respectively. If the collision lasts for 0.11 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s. Calculate the magnitude of the average force exerted on the automobile during the collision. Answer in units of N.
Based on the data provided about the collision;
the magnitude of the impulse due to the collision is 21105.8 kg.m/sthe magnitude of the average force exerted on the automobile during the collision is 191870.91 NWhat is the magnitude of the impulse due to the collision of the vehicle with the wall?The magnitude of the impulse due to the collision of the vehicle with the wall is calculated using the formula of the impulse on an object given below as follows:
Impulse = change in momentum
Change in momentum = m(v - u)
where;
m is mass
v is the final velocity
u is the initial velocity
Impulse = 1759 (12 - 22)
Impulse = 21105.8 kg.m/s
The average force on the automobile will be:
Force = impulse/time
Force = 21105.8 / 0.11
Force = 191870.91 N
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with what speed will a clock have to be moving in order to run at a rest that is one half the rate of clock at rest
The speed at which a clock would have to be moving in order to run at half the rate of a clock at rest depends on the theory of relativity that you are using.
What is the clock speed about?In special relativity, time dilation is the phenomenon where time appears to pass differently for objects in motion relative to an observer at rest.
According to the theory, time appears to slow down for an object as it approaches the speed of light. The rate at which time appears to pass for an object is given by the equation:
T' = T / [tex]\sqrt{(1 - (v^2 / c^2))}[/tex]
Where T is the time as measured by an observer at rest, T' is the time as measured by an observer moving relative to the object, v is the velocity of the object, and c is the speed of light.
In addition, this is a theoretical scenario, practically in order to measure time dilation in a laboratory, it is required a very high precision of measurements, that are currently not possible.
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How does the horizontal velocity of a projectile affect the velocity at which it falls?
A. faster horizontal objects fall slower
B. slower horizontal objects fall slower
C. No horizontal motion means the object will not fall
D. Horizontal motion does not have an effect on how an object will fall
A particle which is moving in a straight line with a velocity of 15m/s accelerates uniformly for 3.0s, increasing its velocity to 45m/s. What distance does it travel while accelerating
The distance travel while accelerating is 90m
The initial velocity of the particle is 15m/s and the final velocity is 45m/s, so the change in velocity is 45m/s - 15m/s = 30m/s. The particle accelerates uniformly for 3.0s, so the acceleration is 30m/s / 3.0s >>30/3=10 that is 10m/s^2.
The distance traveled during the acceleration is equal to the average velocity times the time elapsed, so the distance traveled is (15m/s + 45m/s)/2 * 3.0s = (15+45)/2*3= 90m .
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A man lifts various loads with the same lever. The distance of the applied force from the fulcrum is 2.00 m and the distance from the fulcrum to the load is 0.500 m. A graph of resistance force vs. effort force is shown. What is the mechanical advantage of the lever? What is the ideal mechanical advantage of the lever? What is the efficiency of the lever? Show your work.
The mechanical advantage of the lever is 3.5.
The ideal mechanical advantage of the lever is 4
The efficiency of the lever is 87.5 %.
What is the mechanical advantage of the lever?The mechanical advantage of the lever is the ratio of the load overcame by the lever to the effort applied by the lever.
M.A = Load / Effort
From the graph we will find the change in load to change in effort is calculated as;
M.A = ( 160 N - 20 N ) / ( 50 N - 10 N )
M.A = 3.5
The ideal mechanical advantage of the lever is calculated as follows;
I.M.A = distance travelled by effort / distance travelled by load
I.M.A = ( 2 m ) / ( 0. 5 m )
I.M.A = 4
The efficiency of the lever is calculated as follows;
E = M.A / I.M.A x 100%
E = ( 3.5 / 4 ) x 100%
E = 87.5 %
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Based on the image shown, write the number that corresponds to the term or phrase. Assume that the electrons flow counterclockwise from 3 to 2 to 1, from 5 to 4 to 5, and to 3.
Anode:
3
Cathode:
Electrolytes:
1
Salt bridge:
5
Electrode where oxidation occurs:
4
The reaction that takes place in this cell is
✔ spontaneous
.
Based on the image shown, the numbers that correspond to the term or phrase assuming that the electrons flow counterclockwise from 3 to 2 to 1, from 5 to 4 to 5, and to 3 are:
Anode: 3Cathode: 1Salt bridge: 4Electrolytes: 5Electrode where oxidation occurs: anodeThe reaction that takes place in this cell is spontaneousWhat are electrochemical cells?Electrochemical cells are cells that convert chemical energy to electrical energy.
The components of an electrochemical cell are:
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n experimental vehicle starts from rest (0 = 0) at = 0 and accelerates at a rate given by
= (7m/s
3
). What is (a) its velocity and (2) its displacement 2 later?
The velocity of the experimental vehicle after 2 seconds is 14 m/s.
The displacement of the experimental vehicle after 2 seconds is 14 m.
What is the velocity and displacement of the experimental vehicle?The velocity of the experimental vehicle is the speed of the in a given direction starting from rest.
The velocity, v, of the experimental vehicle after 2 seconds is calculated using the formula below:
v = u + at
where;
u is the initial velocity = 0 m/s
a is the acceleration = 7 m/s²
t is time = 2 seconds
v = 0 + 7 * 2
v = 14 m/s
The displacement, s, of the vehicle is calculated below as follows:
v² = u² + 2as
14² = 0² + 2 * 7 * s
s = 196 / 14
s = 14 m
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8. Jane rides a sled down a slope of angle θ at constant speed v. Determine the coefficient of kinetic friction between the sled and the slope. Neglect air resistance.
(A) μ=gsinθ (B) μ=mgcosθ (C) μ=tanθ (D) μ=gcosθ
Answer:ssssw
Explanation:
Read the following poem by Lola Ridge. Then, respond to the prompt that follows.
Wild Ducks
By Lola Ridge
That was a great night we spied upon
See-sawing home,
Singing a hot sweet song to the super-stars
Shuffling off behind the smoke-haze …
Fog-horns sentimentalizing on the river …
Lights dwindling to shining slits
In the wet asphalt …
Purring lights …red and green and golden-whiskered …
Digging daintily pointed claws in the soft mud …
…But you did not know …
As the trains made golden augers
Boring in the darkness …
How my heart kept racing out along the rails,
As a spider runs along a thread
And hauls him in again
To some drawing point …
You did not know
How wild ducks' wings
Itch at dawn …
How at dawn the necks of wild ducks
Arch to the sun
And new-mown air
Trickles sweet in their gullets.
In a well-written paragraph of 5–7 sentences, analyze the ambiguous nature of "Wild Ducks." Your response should include:
an explanation of your interpretation of the poem's meaning
evidence from the poem (PReP) that supports your interpretation
an explanation of how another reader could interpret the poem differently
evidence from the poem to support an alternative interpretation
Due to the possibility of misinterpretation, the poem "Wild Duck" can be read as either the speaker leaving her lover or the lover leaving her.
What does the poem discuss?Lola Ridge's poem "Wild Duck" allows for more than one interpretation of the speaker's meaning. As a result, it is ambiguous. The ambiguity of the poem can be examined, and the following response to the prompt:
You could say that according to your interpretation of the poem, the speaker is telling us about a night when she bid her lover farewell.
You could argue that the metaphor comparing the speaker to wild ducks and the speaker's statement that her heart "races along the train rails" are examples from the poem that support your claim.
You could argue that a different reading would imply that the speaker is the one being dumped by her lover.
You could cite the second stanza, which is not included here, where the speaker claims that the "known you" have emptied her soul, as proof for your claim.
But it's crucial to remember that the first interpretation appears to be the most plausible one. The metaphor involving the wild duck and the personification of the heart that runs on rails are quite clear, even though the poem does leave some room for ambiguity. The person who wants to leave someone behind is the speaker.
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8. If the m<5 is 63°, find the
measure of <3.
The statement indicates that angle 3 seems to have a 117 degree measurement.
Short answer: What is measure?Compare of an untold amount with a fixed quantity that is known or A attribute of an item or event is measured when a number is assigned to it so that it may be compared to other things or occurrences.
Briefing:An angle is the figure produced by two photons that must intersect at a shared terminal in geometry. The symbol should indicate an angle.
The sum of the two degrees is 180 degrees but since radius 5 is 63 degrees.
Angle 3 is therefore = 180 - 63 = 117 degrees.
Consequently, angle 3 has a measure of 117 degrees.
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Corn plants and milkweed plants grow in the same area. Over several years, the milkweed plants have taken over the field and the corn plants no longer have space to grow.
This best demonstrates which type of an interaction between the plants?
cooperation
parasitism
commensalism
competition
The interaction between the Corn plants and milkweed plants demonstrates as competition.
What is competition in Plants community?Competition is typically considered to refer to the detrimental consequences that neighbors' presence has on a plant's fitness or growth, typically through lowering the resources available.
In addition to resources, disturbance, herbivory, and mutualisms, competition can be a significant factor in controlling plant populations. The resource involved is depending on the species and the region, as all plants require a few fundamental ingredients.
As corn plants and milkweed plants grow in the same area, the interaction between the Corn plants and milkweed plants demonstrates competition.
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The monster wants to make himself known to the family in the cottage in chapters 9-12 of Frankenstein. He decides he can't do that until he masters something. What skill
must he master?
A. How to dress properly
B. Language
C. The rules of etiquette
D. Music
Answer:
c
Explanation: