2. Summarize how to use a spring scale to measure a pull and how to use it to apply a push with
a specific force.

Answers

Answer 1

If the spring constant is known, the extension or compression of the spring can be used to calculate the applied force (pull or push) on the spring.

According to Hook's law, the force applied to an elastic material is directly proportional to the extension of the material.

The force applied;

F = kx

where;

k is the spring

The applied force can be in form of push or pull. A push force can result in compression of the spring while a pull force can result in extension of the spring.

If the spring constant is known, the extension or compression of the spring can be used to calculate the applied force (pull or push) on the spring.

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Related Questions

When there is a temperature inversion, you would expect to experience Group of answer choices clouds with extensive vertical development above an inversion aloft. good visibility in the lower levels of the atmosphere and poor visibility above an inversion aloft. an increase in temperature as altitude increases.

Answers

Temperature inversion leads to an increase in temperature as altitude increases.

The term temperature inversion refers to a situation in which a layer of warm air lies over a layer of cool air. This is also referred to as thermal inversion. This occurs when the air below to loose heat rapidly.

One of the effects of temperature inversion is reduction in visibility. So, thermal inversion leads to an increase in temperature as altitude increases.

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1 point
What is the potential energy of a bird flying, if the bird has 1000 J of total
energy and 450 J of kinetic energy? (only put the number, no units or
commas)

Answers

Answer:

the bird has 550J of potential energy

Explanation:

PEtotal=PE+KE

1000J=PE+450J

subtracting the kinetic energy from the total we get:

1000J-450J=PE

550J=PE

one end of a light inextensible string is attached to a tool box of mass 2.5 kg which is lying on a horizontal table. The string passing over a smooth pulley and is tied at the other end to a bag of mass 1.4kg as shown in the diagram
a. If the toolbox on the point of sliding, find the value for μ, the coefficient of friction.
b. Supposing the coefficient of friction between the tool boxe and the table is 0.20, calculate the acceleration of the system and the tension in the string gravity as 10 m per second square​

Answers

Answer:

the answer is A

Explanation:

A swimming pool has dimension of 30m×10m×3m. When it is filled with water , what is the thrust on the bottom and sides

Answers

Answer:

3,900m³

Explanation:

a force that is at rest or moves in at a constant speed and in a constant direction is called a what force

Answers

The question is fishing for "balanced force".

But the description in the question is terrible.

ignore this i put the wrong grade sorry

Answers

Answer:

Oh its fine i am not in college but its still fine

Explanation:

on average, astronauts grow ________ percent in space.

Answers

Answer:

3

Explanation:

Astronauts in space can grow up to 3 percent taller during the time spent living in microgravity, NASA scientists say. That means that a 6-foot-tall (1.8 meters) person could gain as many as 2 inches (5 centimeters) while in orbit.

name the substance that combines with water in photosynthesis

Answers

Answer:

carbon dioxide

Explanation:

its common sense

a helicopter cruises at a constant velocity when the total thrust of the engines is 5,000 N. How much air resistance acts on the jet ??

Answers

Hi there!

[tex]\large\boxed{F_{A} = -5000N}}[/tex]

For an object to be moving at constant velocity:

∑F = 0 (The sum of the forces acting on the object MUST be 0 N)

We can do a summation of forces for this helicopter in the HORIZONTAL direction:

∑Fₓ = Ft (Force of Thrust) + Fa (Force of air resistance) = 0

Thus, if we substitute in the given value for Ft:

Ft = -Fa

5000N = -Fa

Fa = -5000N

As the distance between two objects changes, how does the gravitational force between them change?

Answers

Answer:

Explanation:

The gravitational force = G * m1 * m2 / r^2

That means as the distance increases, r get's bigger and m1 and m2 don't change, the force decreases. Read that sentence carefully. In physics, it is very important to know what goes up and goes down means and especially why.

Find the number of moles in a 28.0g sample of NH3.

PLS URGENTLY

Answers

Answer:

Molar mass of NH3=14+3=17g

[tex]mole = \frac{given \: mass}{molar \: mass} \\ mole = \frac{28}{17} \\ mole = 1.65[/tex]

BRAINLIST

A long-distance runner runs at a constant speed of 4.8 m/s. How long does it take them to run 1.5 km?

Answers

Convert km to meters:

1km = 1000 m

1.5 km x 1000 = 1500 m

1500m / 4.8 m/s = 312.5 seconds

312.5 seconds / 60 seconds per minute =5.2 minutes = 5 minutes 12.5 seconds

What is the potential energy of a 50kg car on top of a 600m hill?

Answers

Answer:

294,000 J

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

PE = 50 × 9.8 × 600 = 294,000

We have the final answer as

294,000 J

Hope this helps you

2. Un niño hace girar con la mano una pelota de hule que se encuentra sujeta mediante un cordón de
0.75 m de longitud. Si la pelota da 0.7 vueltas a cada segundo, entonces,
a) ¿Cuál es el periodo de la pelota?
b) ¿Cuál es la velocidad lineal de la pelota?

Answers

Cuando el niño hace girar 0.7 vueltas por segundo una pelota de hule que se encuentra sujeta mediante un cordón de 0.75 m de longitud, tenemos que:

a) El periodo de la pelota es 1.43 segundos.

b) La velocidad lineal de la pelota es 3.3 m/s.

a) El periodo de la pelota está dado por:

[tex] T = \frac{2\pi}{\omega} [/tex]

En donde:

ω: es la velocidad angular

Dado que la pelota da 0.7 vueltas (revoluciones) cada segundo, la velocidad angular es:

[tex] \omega = \frac{0.7 \:rev}{s}*\frac{2\pi rad}{1 \:rev} = 4.40 rad/s [/tex]

Entonces, el periodo es:

[tex]T = \frac{2\pi}{\omega} = \frac{2\pi}{4.40 rad/s} = 1.43 s[/tex]

b) La velocidad lineal de la pelota se puede calcular usando la siguiente ecuación:

[tex] v = \omega r [/tex]

En donde:

r: es el radio de la circunferencia = longitud del cordón = 0.75 m

[tex]v = \omega r =4.40 rad/s*0.75 m = 3.3 m/s[/tex]

Por lo tanto, la velocidad lineal de la pelota es 3.3 m/s.

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A small ball is attached to one end of a spring that has an unstrained length of 0.201 m. The spring is held by the other end, and the ball is whirled around in a horizontal circle at a speed of 3.41 m/s. The spring remains nearly parallel to the ground during the motion and is observed to stretch by 0.0176 m.

Required:
By how much would the spring stretch if it were attached to the ceiling and the ball allowed to hang straight down, motionless?

Answers

The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

The given parameters;

unstrained length, l₁ = 0.201 mextension of the string, x = 0.0176 mspeed of the ball, v = 3.41 m/s

The radius of the circular path when spring is stretched is calculated as;

R = l₁ + x

R = 0.201 + 0.0176

R = 0.2186 m

The spring constant is calculated as follows;

[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]

The extension of the spring when the ball is allowed to hang straight down, motionless;

[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]

Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

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a soccer ball is kicked at an angle of 35° and it lands on even ground.
A) What angle will produce the same range?
B) Which angle of the two will produce the highest ball?
C) Which angle of the two will produce the ball that is in the air the longest?
D) What angle in this situation would produce the furthest range?

Answers

Hi there!

A)

The angle that will produce the same range is the compliment of 35°.

Thus, kicking the ball at 55° will result in the same range.

We can prove this by using the derived range equation:

[tex]R = \frac{v^2sin2\theta}{g}[/tex]

An angle of 35° yields:

[tex]R = \frac{v^2sin(2*35)}{g} = .939R[/tex]

An angle of 55° yields:

[tex]R = \frac{v^2sin(2*55)}{g} = .939R[/tex]

Both are the same, thus indicating that 55° produces the same range.

B)

The angle of 55° will produce the higher ball because the VERTICAL component of the ball's velocity is greater compared to kicking the ball at 35° degree.

sin(55) > sin(35)

C)

The angle of 55° will result in the ball being in the air the longest because when a ball is in the air (assuming no air resistance), the ball experiences an acceleration due to gravity of -9.8 m/s², causing the vertical velocity to decrease until it eventually reaches 0 m/s at the top of its path. A greater initial vertical velocity means that it will take longer for the ball to fall.

We can prove this using:

vf = vi + at

0 = vy - 9.8t

vy/9.8 = t

Greater vy (vertical component of velocity) ⇒ greater time taken.

D)

The angle that would result in the furthest range is 45°.

We can prove this using calculus. Recall the above range equation:

[tex]R = \frac{v^2sin2\theta}{g}[/tex]

We can take the derivative and use the first-derivative test to find its critical point:

[tex]\frac{dR}{d\theta} = \frac{v^22cos2\theta}{g} = 0[/tex]

Evaluate:

[tex]v^22cos2\theta = 0 \\\\cos2\theta = 0 \\\\2\theta = 90^o\\\\\boxed{\theta = 45^o}[/tex]

A. The angle that will produce the same range as a 35° kick is 53°.

B. The angle that produces the highest ball is 45°.

C. The angle that produces the ball that is in the air the longest is 45°.

D. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.

A. The range of a projectile is the horizontal distance it travels before it hits the ground. The range of a projectile is determined by the initial velocity, the angle of projection, and the acceleration due to gravity.

For a given initial velocity, the range of a projectile is maximized when the angle of projection is 45°. However, if the ground is not level, the range of a projectile can be maximized at other angles.

In the case of a soccer ball kicked at an angle of 35°, the range will be maximized at an angle of 53°. This is because the range of a projectile is maximized when the vertical component of the initial velocity is equal to the horizontal component of the initial velocity.

The angle of 53° is the angle that produces a vertical component of the initial velocity that is equal to the horizontal component of the initial velocity when the ball is kicked at an angle of 35°.

Therefore, the angle that will produce the same range as a 35° kick is 53°.

B. The angle that produces the highest ball is 45°.

C. The angle that produces the ball that is in the air the longest is 45°.

D. The angle that produces the furthest range depends on the initial velocity and the acceleration due to gravity. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.

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A runner slows down after completing a race. Her deceleration is 0.25 m/s2. After 5 s she is travelling at 4 m/s, determine her initial velocity.​

Answers

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

The initial velocity of the runner is 5.25 m/s.

What is deceleration?

You've probably seen that when there's a lot of traffic and there are more bikes blocking us, we tend to slow down the speed of our bikes.

Therefore, deceleration is defined as a reduction in speed as the body moves away from the beginning location. The opposite of acceleration is deceleration.

Given parameters:

Deceleration of the runner: a = 0.25 m/s².

Time interval: t = 5 second.

Final velocity: v = 4 m/s.

We have to find initial velocity of the runner: u = ?

From definition of deceleration, it can be written that:

deceleration = (initial velocity - final velocity) time interval

0.25 = (u -4)/5

u =  5.25 m/s.

Hence, initial velocity of the runner is 5.25 m/s.

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HELP PLZZZZZZ AHHHHH

Answers

Answer: I think it's larger

Explanation:  man im just trying to help you

a
(2) A 800 g block is pushed up an inclined plane (angled at 18°) with a velocity of 11.8 m/s. The first block slides up the
incline a distance of 2.2 m and strikes a second block with a mass of 300 g also moving at 3.4 m/s up the incline.
The two blocks hit and stick together. Determine the following:
(i) The maximum vertical height of the two blocks when they stop.
(ii) The time needed for the blocks to reach the bottom of the incline after the moment of impact.
(u = 0.19)

Answers

this is my attachment answer hope it's helpful to you

please help me please help​

Answers

Answer:

Answer Distance is 5 × 10⁴ km

Explanation:

Gravitational formular

[tex]{ \tt{F = \frac{GMm}{ {r}^{2} } }} \\ [/tex]

F is the gravitational forceG is the universal gravitational constantr is the separation distanceM & m are the masses

For the first case;

[tex]{ \tt{F _{1} = \frac{GMm}{2.5 \times {10}^{4} } }} \\ [/tex]

For the second case;

[tex]{ \tt{F _{2} = \frac{GMm}{r _{2}} }} \\ [/tex]

but F2 = ½F1

Therefore, F1 = 2F2

Hence:

[tex]{ \tt{ \frac{GMm}{2.5 \times {10}^{4} } =2 \times \frac{GMm}{r _{2} } }} \\ \\ { \tt{ \frac{1}{2.5 \times {10}^{4} } = \frac{2}{r _{2} } }} \\ \\ { \tt{r _{2} = 2 \times 2.5 \times {10}^{4} }} \\ \\ { \underline{ \tt{ \: \: r _{2} = 5 \times {10}^{4} \: km \: \: }}}[/tex]

Answer: Distance is 5 × 10⁴ km

Explanation:

Two cars A and B are moving along a straight road in the OPPOSITE direction with velocities of 25 km/h and 40 km/h, respectively. Find the velocity of car B relative to car​

Answers

Answer:

65km/h

Explanation:

Here,

Relative velocity of car moving in different directions with different velocities =Va + Vb

=25+40

=65 km/h

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

cecily is inflating her bicyble tyre with the pump below. when she pushes the plunger down, it is moving against a force appliefd by the air inside the cynlinder. this means that the plunger is doing ___

Answers

Answer:

"work against the force of the air in the tire"

The air in the tire provides a force opposing the force of the air provided by the plunger.

I=24
Q=400C
t=102
Help please

Answers

[tex] \huge \bf༆ Answer ༄[/tex]

The given terms in the question are : -

I = Electric current = 2 Amperes

Q = Charge = 400 Coulombs

We have been given the task to find out time (t)

The formula that can be used to find time is : -

[tex] \sf \: I = \dfrac{ Q}{t}{} [/tex]

Rearrange the formula,

[tex] \sf \: t = \dfrac { Q}{I }[/tex]

Solve for time (t)

[tex] \sf t = \dfrac{400}{2} [/tex]

[tex] \sf t = 200 \: \: sec[/tex]

[tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]

If a statue is made out of wood, which of these words correctly describes the statue?
OA.
wooded
ОВ.
woody
OC.
non-wood
OD.
wooden

Answers

Answer:

Od- Wooden

Explanation:

It would not make sense if it was non-wood because that make it no a wood base product, OC is not right because its not a a plant that produces wood as its structural tissue and thus has a hard stem.   An OA justT o take or get a supply of wood. so its Od

An 8kg mass is placed on a 30 degrees frictionless inclines plane and is attached to a pulley to a hanging mass of 5kg
Calculate which direction will the system flow
B)what is the acceleration
C)the tension in the rope

Answers

Hi there!

We can begin by doing a summation of forces. Let the acceleration be positive in the direction of the DOWNWARD movement of the hanging block.

(A)

The system will flow in the direction of the hanging block's movement downwards.

(B)

Summation of forces of block on incline:

∑F = -M₁gsinФ + T

Summation of forces of hanging block:

∑F = M₂g - T

Sum both summations:

∑F =  -M₁gsinФ + T + M₂g - T

∑F = M₂g -M₁gsinФ

According to Newton's Second Law:

∑F = ma

Thus:

(M₁ + M₂)a = M₂g -M₁gsinФ

[tex]a = \frac{M_2g -M_1gsin\theta}{M_1 + M_2}[/tex]

Plug in the values:

[tex]a = \frac{(5 * 9.8) -(8 * 9.8 * sin30)}{8 + 5} = \large\boxed{0.754 m/s^2}[/tex]

(C)

Calculate the rope's tension using one of the above equations:

∑F₂ = M₂g - T

Rearrange for T:

T = M₂g - m₂a

Plug in values:

T = 5(9.8) - 5(0.754) = 45.23 N

What is the total amount of potential and kinetic energy in a system? *
1 point
A: Electrical energy
B: Heat energy
C: Mechanical energy
D: Nuclear energy

Answers

Answer:

C. Mechanical Energy

Explanation:

The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.

As the temperature of an air mass increases, its atmospheric pressure______. Group of answer choices

Answers

Answer:

its atmospheric pressure decreases

When the temperature of an air mass increases, its atmospheric pressure drops

ok done. Thank to me :>

negatively charged particles of radiation emitted from the decay of radioactive substances are known as

Answers

Answer: beta particles

Explanation:

that's the answer

More potential energy can be stored by moving against the magnetic force closer to a magnet?

Answers

Answer:

if your saying can it? then yes or if you are asking what type of magnetic force  then its fr its actual self magnetic force

Explanation:

How can speed be defined
A) acceleration
B) change in velocity/time
C) distance / time
D) displacement/time

Answers

Answer:

Speed can be defined in (C) distance / time.

I hope this helped at all.

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