2. Which of the following contributions did Louie De Broglie do for electronic structure of matter? A. determined the speed of electron of hydrogen atom B. proposed a theory that electrons showed characteristics similar to light C. provided mathematical operation for the characteristics of light D. recorded the movement of proton in the nucleus of an atom

❤️​

Answer:

They take the form of heat, I think thats it but I cant see if you put down any answers

Explanation:

Answer:a

Explanation:

they form hear

Answer: Im not entirly sure but I think It's D all the above. I think all but B because I never really heard of that but if you look in our history I think that happen im not sure I would wait untill you know that somone knows for sure.

Explanation:

Answer:

Question 1 is "need them to survive"

Explanation:

vital means necessary or needed

The meaning of the word vital in this passage is "need them to survive". Therefore, option D is correct.

The process by which plants convert carbon dioxide, water, and sunshine into oxygen and sugar-based energy is known as photosynthesis. Chloroplasts, which house the chlorophyll in plants, are where photosynthesis occurs. The thylakoid membrane, a third inner membrane that creates long folds inside the chloroplast and is bordered by a double membrane, is present inside chloroplasts.

Photosynthesis is very important for the survival of organisms because they get energy from photosynthesis. Life on earth is impossible without this process.

The meaning of the word vital in this passage is "need them to survive". Therefore, option D is correct.

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Answer:

In this problem basically we will use directions to find displacement and distance .

(Keep in mind that displacement is vector while distance is scalar quantity)  

And then we will use displacement and distance to find average velocity and average speed.

Explanation:

Answer:

Small particles of dust and pollution in the air can contribute to (and sometimes even enhance) these colors, but the primary cause of a blue sky and orange/red sunsets or sunrises is scattering by the gas molecules that make up our atmosphere. Large particles of pollution or dust scatter light in a way that changes much less for different colors.

Explanation:

Answer:

340

Explanation:

Sorry I don't know how to do this one yet, I just found the answer in a textbook.

The angle that vector a makes with the +x axis is closest to 23.

The direction of a vector is represented tangent of angle equal to the ratio of the y component and the x component of the vector quantity.

tangent of angle = y/x

angle = tan⁻¹ (-2.3/5.3)

angle = 23.46°

Thus, the angle that vector makes with +x is 23.

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Total liquid: 73 + 25 = 98 ml

Percent juice = (25/98) x 100 = 25.5 %

Answer:

B. . by consuming plants or other animals

Answer:

Explanation:

Ignoring air resistance the time to rise will equal the time to fall and initial velocity will be the same magnitude as final velocity just before impact.

v = at

v = 9.8(3.1)

v = 30.38

v = 30 m/s

max height can be found knowing the velocity is zero at the top of its flight.

v² = u² + 2as

s = (v² - u²) / 2a

s = (0.00² - 30.38²) / (2(-9.8))

s =  47.089

s = 47 m

A stomp rocket takes 3.1 seconds to reach its maximum height then the initial velocity is given as v = 30 m/s and maximum height is 47.089 m.

Velocity is defined as rate of change of position with respect to time.

SI unit of velocity is m/sec. Velocity is a vector quantity.

Given that in the question time taken by rocket to reach maximum height is 3.1 sec. Ignoring air resistance the time to rise will equal the time to fall and initial velocity will be the same magnitude as final velocity just before impact.

v = at

v = 9.8(3.1)

v = 30.38

v = 30 m/s

Max height can be found knowing the velocity is zero at the top of its flight.

v² = u² + 2as

s = (v² - u²) / 2a

s = (0.00² - 30.38²) / (2(-9.8))

s =  47.089

s = 47 m

So, the initial velocity is given as v = 30 m/s and maximum height is 47.089 m.

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Answer:

The answer is ciliary body and focus the pupil. In addition, the ciliary body is a portion of the eye that contains the ciliary muscle that reins the shape of the lens and the ciliary epithelium that yields the aqueous humor. The ciliary body is a share of the uvea which is the layer of tissue that transports oxygen and nutrients to the eye nerves while the pupil is a hole positioned in the midpoint of the iris of the eye that permits light to foray the retina. It looks black since light rays incoming the pupil are moreover engrossed by the tissues in the eye openly or engrossed after diffuse reflections in the eye that typically miss leaving the fine pupil

Explanation:

Answer:the eye has many parts that must work together in order to produce clear vision

Explanation: correct on my test

From Young's single slit experiment, the distance away from the wall will be 1.068 m

Given that 587.9 nm of wavelength of light passes through a single slit 0.73 mm wide, it creates a diffraction pattern.

From the question, the following parameters are given:

The wavelength of the light λ  =  587.9 nm

The width of the slit a = 0.73 mm

Fringe width X = 0.86 mm

The distance away from the wall D = ?

The fringe width is related to the wavelength  of the light source by the equation:

X = Dλ ÷ a

Substitute all the parameters into the formula

0.83 × [tex]10^{-3}[/tex] = 587.9 × [tex]10^{-9}[/tex] D ÷ 0.73 ×

Cross multiply

587.9 × [tex]10^{-9}[/tex] D = 6.278 × [tex]10^{-7}[/tex]

make D the subject of the formula

D = 6.278 × [tex]10^{-7}[/tex] ÷  587.9 × [tex]10^{-9}[/tex]

D = 1.068 m

Therefore, the distance away from the wall is 1.068 m

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If the first minimum is [tex]0.86 mm[/tex] from the central maximum, the distance away is 1.07 meters.

Given the data in the question;

From Thomas Young's single slit experiment:

[tex]\frac{a*y}{L} = m * \lambda[/tex]    

Where a is the width of the slit, y is first minimum, L is the distance, m is the order number and λ is the wavelength.

We substitute our values into the equation

[tex]\frac{0.00073m\ *\ 0.00086m}{L} = 1\ *\ ( 5.879*10^{-7}m)\\\\\frac{0.0000006278m^2}{L} = 5.879*10^{-7}m\\\\L = \frac{0.0000006278m^2}{5.879*10^{-7}m} \\\\L = 1.07m[/tex]

Therefore, if the first minimum is [tex]0.86 mm[/tex] from the central maximum, the distance away is 1.07 meters.

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Answer:

all are harmful to the body

The force constant k of the spring, if The oscillation of the 2 kg mass of spring is described by x = 3.0 cos (4.0 t) is 32 N / m.

Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.

Newton is a unit of force used by physicists that is part of the International System (SI). The force required to move a body weighing one kilogram one meter per second is known as a newton.

Given:

The mass of the block, m = 2 kg,

The oscillation of spring, x  = 3 cos 4t,

Calculate the omega  by comparing the standard equation given below,

[tex]x = A cos \omega t[/tex]

ω = 4

Calculate the spring constant by the formula given below,

[tex]\omega = \sqrt{\frac{k}{m} }[/tex]

4² = k / 2

k = 32 N / m

Therefore, the force constant k of the spring, if The oscillation of the 2 kg mass of spring is described by x = 3.0 cos (4.0 t) is 32 N / m.

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Answer: 38 weeks (266 days) from the date of conception.

Explanation: www.momjunction.com/pregnancy-due-date-calculator/

The units of the constant of proportionality between pressure and volume in alphabetical order are

1. Celsius (°C)

2. Fahrenheit (°F)

3. Kelvin (K)

The units for R, that is, the ideal gas constant are

1. J K⁻¹ mol⁻¹

2. L atm K⁻¹ mol⁻¹

We will start by completing the Boyle's Law stated

Boyle's Law states the volume and pressure of a gas are inversely proportional, provided that the temperature remains constant.

This means temperature is the constant of proportionality.

Now, we will name the three units of the constant of proportionality, that is, temperature. The units are

1. Degree Celsius (°C)

2. Degree Fahrenheit (°F)

3. Kelvin (K)

2. In the ideal gas equation (PV/nT=R), R represents the ideal gas constant.

The units for R, that is, the ideal gas constant are

1. J K⁻¹ mol⁻¹

2. L atm K⁻¹ mol⁻¹

Hence,

The units of the constant of proportionality between pressure and volume in alphabetical order are

1. Celsius (°C)

2. Fahrenheit (°F)

3. Kelvin (K)

The units for R, that is, the ideal gas constant are

1. J K⁻¹ mol⁻¹

2. L atm K⁻¹ mol⁻¹

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Answer:

D. Greater than mg​

Explanation:

According to Newton’s second law of motion, the net force equals mass times acceleration. We are going to use a free body diagram (force diagram) to show that the equation of the motion is given by

T – mg = – ma

Thereby,

T = mg – ma

and the answer is: (d)

D. Greater than mg​

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(hopet his helps can I pls have brainlist  (crown)☺️)

Answer: A , D & F

Explanation:

Answer:

Force = mass × acceleration.

Answer:

All organisms begin their lives as single cells.Overtime,these organisms grow and take on the characteristics of their species...All organisms grow,and different parts of organisms may grow at different rates.Organisims made out of only one cell

may change little during their lives, but they do grow

Explanation:

brainlest me please

The rolling disk's initial angular momentum is mR√[2(gR + v²)]/2

Using the law of conservation of energy, the initial mechanical energy E of the disk equals its final mechanical energy E' as it climbs the step.

So, E = E'

1/2Iω + 1/2mv² + mgh = 1/2Iω' + 1/2mv'² + mgh'

where I = rotational inertia of disk = 1/2mR² where m = mass of disk and R = radius of disk, ω = initial angular speed of disk, v = initial velocity of disk, h = initial height of disk = 0 m, ω' = final angular speed of disk = 0 rad/s (assumung it stops at the top of the step), v' = final velocity of disk = 0 m/s (assumung it stops at the top of the step), and h' = final height of disk = R/2.

Substituting the values of the variables into the equation, we have

1/2Iω² + 1/2mv² + mgh = 1/2Iω'² + 1/2mv'² + mgh'

1/2(1/2mR² )ω² + 1/2mv² + mg(0) = 1/2I(0)² + 1/2m(0)² + mgR/2

mR²ω²/4 + 1/2mv² + 0 = 0 + 0 + mgR/2

mR²ω²/4 + 1/2mv² = mgR/2

R²ω²/4 = gR/2 + 1/2v²

R²ω²/4 = (gR + v²)/2

ω² = 2(gR + v²)/R²

ω² = √[2(gR + v²)/R²]

ω = √[2(gR + v²)]/R

Since angular momentum L = Iω, the rolling disk's initial angular momentum is

L = 1/2mR² ×√[2(gR + v²)]/R

L = mR√[2(gR + v²)]/2

the rolling disk's initial angular momentum is mR√[2(gR + v²)]/2

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Answer:

The speed of sound varies with the material in which the waves travel.

Explanation:

knowledge and research

It can be concluded as per the given table that the speed of sound varies with the material in which the waves travel. The correct option is A.

Speed is the pace at which an object's position changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.

It has a dimension of time-distance. As a result, the fundamental unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the metre per second (m/s) is the SI unit of speed.

According to the given table, it can be inferred that the material in which the waves travel affects the speed of sound.

Thus, the correct option is A.

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(a) The height of the roller coaster at 120,000 potential energy is 122.45 m.

(b) The velocity of the roller coaster at 0 J kinetic energy is 0.

(c) The height of the roller coaster at 60,000 potential energy is 61.23 m.

(d) The velocity of the roller coaster at 60,000 J kinetic energy is 34.64 m/s.

(e) The height of the roller coaster at 40,000 potential energy is 40.82 m.

(f) The velocity of the roller coaster at 80,000 J kinetic energy is 40 m/s.

The given parameters:

When the kinetic energy = 0 and potential energy = 120,000 J

The height of the roller coaster is calculated as follows;

P.E = mgh

[tex]h = \frac{P.E}{mg}\\\\h = \frac{120,000}{100 \times 9.8} \\\\h = 122.45 \ m[/tex]

Since the kinetic energy = 0, the velocity of the roller coaster = 0

When the potential energy, P.E = 60,000 J, the kinetic energy, K.E is calculated as;

P.E + K.E = M.A

P.E + K.E = 120,000

60,000 + K.E = 120,000

K.E = 120,000 - 60,000

K.E = 60,000 J

The height of the roller coaster at 60,000 potential energy is calculated as follows;

[tex]h = \frac{P.E}{mg} \\\\h = \frac{60,000}{100 \times 9.8} \\\\h =61.23 \ m[/tex]

The velocity of the roller coaster at 60,000 J kinetic energy is calculated as follows;

[tex]K.E = \frac{1}{2} mv^2\\\\v^2 = \frac{2K.E}{m} \\\\v = \sqrt{ \frac{2K.E}{m}} \\\\v = \sqrt{ \frac{2\times 60,000}{100}}\\\\v = 34.64 \ m/s[/tex]

When the potential energy, P.E = 40,000 J, the kinetic energy, K.E is calculated as;

P.E + K.E = M.A

40,000 + K.E = 120,000

K.E = 120,000 - 40,000

K.E = 80,000

The height of the roller coaster at 40,000 potential energy is calculated as follows;

[tex]h = \frac{P.E}{mg} \\\\h = \frac{40,000}{100 \times 9.8} \\\\h = 40.82 \ m[/tex]

The velocity of the roller coaster at 80,000 J kinetic energy is calculated as follows;

[tex]v = \sqrt{\frac{2K.E}{m} } \\\\v = \sqrt{\frac{2\times 80,000}{100} } \\\\v = 40 \ m/s[/tex]

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Answer:

Explanation:

F = ma

a = F/m

a = mBg / (mB + mA)

a = 3.5(9.8)/(3.5 + 3.4)

a = 4.971014...

a = 5.0 m/s²

If you want to use individual Free Body Diagrams

mass A will have downward weight and upward normal forces equal at mAg

and a horizontal force of string tension T

F = ma

T = mAa

mass B will have a downward force of mBg and an upward force of T

mBg - T = mBa

substitute for T

mBg - mAa = mBa

mBg = a(mB + mA)

a = mBg / (mB + mA)   which is identical to the above answer.

Answer:

No

Explanation:

Changing momentum of any kind requires work. Work is a force acting over a distance. While holding the weights at arms length and spinning will create a force (centripetal), there is no radial distance change incurred. Releasing the weights will reduce the force to zero, still no work done and no change in angular momentum.

If he was holding the weights at arms length while spinning and he pull his hands to his chest, there now exists both the centripetal force and a distance in the direction of that force (inward radial) this work will result in an increase in angular velocity as moment of inertia has decreased with the work done.

No, the skater doesn't succeed in changing his angular velocity.

The final angular velocity of the skater is determined by applying the principle of conservation of angular momentum as shown below;

Li = Lf

[tex]Ii\omega _i = I_f \omega _f[/tex]

where;

When the skater holds the weight, the momnet of inertia of both arms is the same. Also when the skater drops the weight, the moment of inertia of both arms is still the same. Thus, at any instant, the moment of inertia of the two arms is the same.

To change the angular speed, the initial and final moment of inertia of the two arms must be different. Thus, the skater doesn't succeed in changing his angular velocity.

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Answer:

A

Explanation:

a.

The object's speed at 2.20 m below balcony level is 8.74 m/s

Let the balcony level be 0 m and the height above the balcony level be positive and height below the balcony level negative.

Using the principle of conservation of energy, the total energy at a vertical height of 1.89 m above the balcony level equals the total mechanical energy when the object is 2.20 m below the balcony level and

So, E = E'

U + K + f = U' + K' + f'

where U = initial potential energy at 1.89 m = mgh, K = initial kinetic energy at 1.89 m = 0 J(since it is released from rest), f = energy loss at 1.89 m = 0 J, U' = final potential energy at 2.20 m below balcony level = mgh', K = final kinetic energy at 2.20 m = 1/2mv², f' = energy loss at 1.89 m = 10%U = 0.10mgh(since 10% of the initial energy is lost).

So,

U + K + f = U' + K' + f'

mgh + 0 + 0 = mgh' + 1/2mv² + 0.10mgh

mgh = mgh' + 1/2mv² + 0.10mgh

Dividing through by m, we have

gh = gh' + 1/2v² + 0.10gh

So, gh -  0.10gh = gh' + 1/2v²

0.90gh = gh' + 1/2v²

1/2v² = 0.90gh - gh'

1/2v² = g(0.90h - h')

v² = 2g(0.90h - h')

Taking square-root of both sides, we have

v = √[2g(0.90h - h')]

where v = velocity of object at 2.20 m below balcony level, h = height above the balcony level = 1.89 m, h' = height below the balcony level = -2.20 m and  g = acceleration due to gravity = 9.8 m/s²

Substituting the values of the variables into the equation, we have

v = √[2g(0.90h - h')]

v = √[2 × 9.8 m/s²{0.90 × 1.89 m - (-2.20 m)}]

v = √[2 × 9.8 m/s²(1.701 m + 2.20 m)]

v = √[2 × 9.8 m/s²(3.901 m)]

v = √[76.4596 m²/s²]

v = 8.74 m/s

So, the object's speed at 2.20 m below balcony level is 8.74 m/s

b.

Yes it does matter when we apply 10% loss before V calculations

We need to apply the 10 % loss before V calculations because this would give us a proper value for V since the energy is lost before V is obtained.

So, yes it does matter when we apply 10% loss before V calculations

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Hi there!

We can use the following equation to find the frequency of each harmonic:

[tex]f_n = \frac{n}{2L} \sqrt{\frac{T}{\lambda}}[/tex]

n = nth harmonic

L = length of string (m)

T = Tension of string (N)

λ = linear density (kg/m)

Begin by converting the linear mass density to kg:

2.00g /m · 1 kg / 1000g = 0.002 kg/m

Now, we can use the equation to find the first three harmonics.

First harmonic:

[tex]f_1 = \frac{1}{2(0.6)} \sqrt{\frac{50}{0.002}} = \boxed{131.76 Hz}[/tex]

Second harmonic:

[tex]f_2 = \frac{2}{2(0.6)} \sqrt{\frac{50}{0.002}} = \boxed{263.52Hz}[/tex]

Third harmonic:

[tex]f_3 = \frac{3}{2(0.6)} \sqrt{\frac{50}{0.002}} = \boxed{395.28Hz}[/tex]

Explanation:

Fgravity = G*(mass1*mass2)/D²

so, if you double one of the masses, what does that do to our equation ?

Fgravitynew = G*(2*mass1*mass2)/D²

due to the commutative property of multiplication

Fgravitynew = 2* G*(mass1*mass2)/D² = 2* Fgravity

so, the correct answer will be 2×45 = 90 units.