Answer: The enthalpy of the reaction is -1791.31 kJ.
Explanation:
Enthalpy change is the difference between the enthalpies of products and the enthalpies of reactants each multiplied by its stoichiometric coefficients. It is represented by the symbol [tex]Delta H^o_{rxn}[/tex]
[tex]\Delta H^o_{rxn}=\sum (n \times \Delta H^o_{products})-\sum (n \times \Delta H^o_{reactants})[/tex] .....(1)
For the given chemical reaction:
[tex]3MnO_2(s)+4Al(s)\rightarrow 2Al_2O_3(s)+3Mn(s)[/tex]
The expression for the enthalpy change of the reaction will be:
[tex]\Delta H^o_{rxn}=[(2 \times \Delta H^o_f_{(Al_2O_3(s))}) + (3 \times \Delta H^o_f_{(Mn(s))})] - [(3 \times \Delta H^o_f_{(MnO_2(s))}) + (4 \times \Delta H^o_f_{(Al(s))})][/tex]
Taking the standard heat of formation values:
[tex]\Delta H^o_f_{(Al_2O_3(s))}=-1675.7kJ/mol\\\Delta H^o_f_{(Al(s))}=0kJ/mol\\\Delta H^o_f_{(MnO_2(s))}=-520.03kJ/mol\\\Delta H^o_f_{(Mn(s))}=0kJ/mol[/tex]
Plugging values in the above expression:
[tex]\Delta H^o_{rxn}=[(2 \times (-1675.7))+(3 \times 0)] - [(3 \times (-520.03))+(4 \times 0)]\\\\\Delta H^o_{rxn}=-1791.31 kJ[/tex]
Hence, the enthalpy of the reaction is -1791.31 kJ.
the structure of carbon dioxide using dots and crosses
Answer:
on image
Explanation:
help in this please....................
c) because rays contain electrons
Need answer ASAP!!!!
Select the correct answer.
What happens to sodium chloride when it dissolves in water?
© A. Electrons are transferred from sodium atoms to chlorine atoms, forming positive and negative ions.
O B.
Each sodium ion pairs with a chloride ion, and the pair of ions is surrounded by water molecules.
C.
The water molecules attract both the sodium ions and the chloride ions, pulling them together.
© D.
The sodium ions are separated from the chloride ions, and both dissolve separately into the water.
Answer:
I am sure it is D or C. have a nice day
(04.04 LC)
During light-dependent reactions, carbon dioxide is converted to glucose.
True
O False
Answer:
false
Explanation:
it happens in light-independent reactions
can someone answer this please
A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200 joules, what is the approximate final temperature of the water?
Answer:
80.7 °C
Explanation:
Step 1: Given and required data
Mass of water (m): 20.0 gInitial temperature (T₁): 95.0 °CHeat released (Q): -1,200 J (the negative sign is due to it being released)Specific heat capacity of water (c): 4.184 J/g.°CStep 2: Calculate the final temperature of the water
We will use the following expression.
Q = c × m × (T₂ - T₁)
T₂ = Q / c × m + T₁
T₂ = -1,200 J / (4.184 J/g.°C) × 20.0 g + 95.0 °C = 80.7 °C
Answer:
81 C
Explanation:
Answer these two questions, please.
1.Why the melting point and boiling point of [tex]H_{2} O[/tex] are lower than metals?
2.Why the melting point and boiling point of [tex]H_{2} O[/tex] are comparatively higher than other non-metals?
Answer:
neom, sodium bicarbonate
Calculate the standard enthalpy change for the reaction 2A+B⇌2C+2D Use the following data: Substance ΔH∘f (kJ/mol) A -235 B -413 C 193 D -493
Answer:
ΔH = 283kJ/mol
Explanation:
Using Hess's law, the ΔH of a reaction is equal to the sum of ΔH° of products times its coefficient subtracting the sum of ΔH° of reactants times its coefficient. Replacing, for the reaction:
ΔH = 2ΔH°C + 2ΔH°D - (2ΔH°A+ΔH°B)
ΔH = 2*193kJ/mol + 2*-493kJ/mol - (2*-235kJ/mol+ (-413kJ/mol)
ΔH = 283kJ/mol40.*
Which pair of compounds reacts to form a condensation polymer?
A-
CH3COOH and C2H5NH2
B- HCOOH and HOC2H OH
C-HOC6H12OH and HOOCCH.COOH
D- H2NC3H NH2 and HOCH OH
Answer:
C-HOC6H12OH and HOOCCH.COOH
hexane-1,6-diol and propane-1,3-dioic acid
Question 14 of 30
Which of the following elements has 1 valence electron?
The Periodic Table
A. Sodium (Na)
B. Chlorine (CI)
C. Calcium (Ca)
D. Helium (He)
SUBMIT
Answer:
A. Sodium (Na)
Explanation:
The total number of electrons in the outermost principal energy level of an element is called the valence electrons of that element.
Na (11)---→1s2 2s2 2p6 3s1
There 1 electron in the outermost principal energy level of Sodium. So, the number of valence electron of Sodium is 11.
Answer:
Na
Explanation:
I was learning about it recently, that dude's right, it's Sodium
How many atoms are in 9.8 moles of NaCl?
Answer:
a lot but im pretty sure if u just take avogadros number and multiply it by 9.8 u get the answer
Explanation:
There are 5.89 × 10²⁴ atoms in 9.8 moles on NaCl. Details about number of atoms can be found below.
How to calculate number of atoms?The number of atoms of a compound can be calculated by multiplying the number of moles of the substance by Avogadro's number.
no of atoms = no of moles × 6.02 × 10²³
According to this question, there are 9.8 moles of NaCl.
no of atoms = 9.8 × 6.02 × 10²³
no of atoms = 5.896 × 10²⁴
Therefore, there are 5.89 × 10²⁴ atoms in 9.8 moles on NaCl.
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.Write a short paragraph describing how electronegativity and molecular shape determine the polarity of a molecule. In your paragraph, describe why chemists consider relative electronegativity values and not absolute electronegativity values when determining the polarity of a bond. Also explain how a molecule with polar bonds can be non-polar overall
Answer:
See explanation
Explanation:
Electro negativity refers to the ability of an atom in a molecule to attract the shared pair of electrons of a bond closer to itself.
In a molecule, the polarity of bonds is determined by the relative electro negativity of the bonding atoms. If the difference in electro negativity between the atoms in a bond is significant, such a bond is polar in nature e.g H-Cl, H-Br, C-F, etc.
However, the occurrence of polar bonds in a molecule alone does not guarantee the polarity of the molecule. The polarity of a molecule also depends on the shape of the molecule since dipole moment is a vector quantity.
A molecule is polar when the resultant dipole moment which is determined by the shape of the molecule is non zero.
For instance, CO2 contains two polar C-O bonds but the molecule is non polar because the two dipole moments cancel out. Also, symmetrical molecules are nonpolar irrespective of the presence of polar bonds in the molecule.
Use the periodic table to determine the amount of copper and aluminum nitrate formed in the reaction.
Type the correct answer in the box. Express your answer to the correct number of significant figures.
In the reaction,
moles of Cu and
moles of Al(NO3)3 are formed.
Answer:
23, 51
Explanation:
Edmentum/plato
As per the balanced reaction, 2 moles of aluminum metal and 3 moles of copper nitrate gives 2 moles of aluminum nitrate and 3 moles of copper metal. 10 g of Al and 25g of copper nitrate gives 0.08 moles of aluminum nitrate and 0.13 moles of copper.
What is limiting reactant ?A limiting reactant is the reacting species which is not sufficient in amount to complete the reaction. Hence, the limiting reactant determines the yield of the reaction.
The given reaction is written as:
[tex]\rm 3Cu(NO_{3})_{2} + 2Al \rightarrow 2 Al(NO_{3})_{3} + 3Cu[/tex]
2 moles of Al and 3 moles of copper nitrate gives 2 moles of aluminum nitrate and 3 moles of Cu.
Molar mass of copper nitrate = 187.5 g/mol
atomic mass of aluminum = 27 g/mol
then, number of moles in 10 g of Al = 10 g/27 g/mol = 0.37 moles.
number of moles in 25 g of copper nitrate = 25 g/187.5 g/mol = 0.13 moles.
0.37 moles of Al needs 0.5 moles of copper nitrate to react with. Hence, copper nitrate is the limiting reactant.
3 moles of copper nitrate gives 2 moles of aluminum nitrate. Then 0.13 moles will give 2/3rd of 0.13 i e., 0.08 moles of aluminum nitrate. Similarly 0.13 moles copper nitrate gives 0.13 moles of copper metal.
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Your question is incomplete. But your complete question probably was:
10 g of aluminum metal reacts with 25 g of copper nitrate. Use the periodic table to determine the amount of copper and aluminum nitrate formed in the reaction.
In the reaction,
moles of Cu and
moles of Al(NO3)3 are formed.
How much mass does 1 mol of O2 gas have?
O A. 16.00 x 2g
O B. 16.00 x (6.02 x 10^23) g
C. 2 x (6.02 x 10^23) g
D. 16.00 g
Answer:
Option A.
Explanation:
1 mol of anything contains 6.02×10²³ particles.
We know that 1 mol of oxygen gas contains 2 moles of O.
1 mol of oxygen weighs 16 g/mol, the mass for 1 molecule of O.
By the way, the mass for 1 mol of O₂ may be:
Option A → 16 g/mol . 2 mol
32 g
Oyxgen is a dyatomic molecule, that's why we have 2 moles of O.
Another example can be:
1 mol of water (H₂O) contains 2 moles of H and 1 mol of O.
14. Ionic compound is brittle solid but break
apart when hit this property is due to...
A) Dissolved in water
B) Arrangement of similar ions
C) Ions do not move
D) Arrangement of opposite ions
Answer:
A
not sure of answer ndhfhfjfjcjfjfj
I need chemistry help text me at (951) 897-8325 PLEASE
Why don’t scientists use the Bohr model above to explain charge transfer?
Answer:
nsksbsjensnsjeiejensbsksks
How many grams of Lioh are in 1.7 moles?
Answer:
40.7g
Explanation:
so mass = moles × mr( 6.94+16+1)
=1.7 × 23.94
= 40.698
so 3 S.F = 40.7 g
hope this helps :)
existen mas de 10 millones de cmpuestos organicos o inorganicos
so dfhhdjdjjfjfjjdjdjdj
Help a girl out, please!!!!!
Answer:
The answer will be Number C that is positively and part of the nucleus
Answer:
Part C best describes a proton, as it is positively charged and part on the nucleus
What is the equation for the average?
A. Average = (total number of data values) / (sum of all data values)
B. Average = (sum of target data values) / (sum of all data values)
C. Average = (sum of target data values) / (total number of data values)
D. Average = (sum of all data values)/ (total number of data values)
Dacat Selection
The equation for the average, also known as the arithmetic mean, is:
D. Average = (sum of all data values) / (total number of data values)
The average is calculated by adding up all the data values and then dividing the sum by the total number of data values. This equation provides a measure of central tendency that represents the typical value or the "average" value of a set of data.
Option A, (total number of data values) / (sum of all data values), does not represent the correct equation for calculating the average. Dividing the total number of data values by the sum of all data values does not yield the average. This equation would result in a value that is not representative of the data set.
Option B, (sum of target data values) / (sum of all data values), is not the correct equation for calculating the average. This equation suggests finding the average of specific "target" data values rather than considering the entire data set.
Option C, (sum of target data values) / (total number of data values), is also not the correct equation for calculating the average. Similar to option B, this equation suggests finding the average of specific "target" data values rather than considering the entire data set.
Therefore, the correct equation for calculating the average is D. Average = (sum of all data values) / (total number of data values). This equation provides the most accurate representation of the average value of a given data set.
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helo in this please I'm so kunfused
OPTION C is the correct answer.
The photograph below shows the East African Rift Valley in Africa. Which tectonic movement
of Earth’s crust is most likely responsible for this feature?
Answer:
divergence of continental crust
Explanation:
What are the two factors that affect that density of matter ?
Mass and volume are two factors that affect that density of matter!
Question: (02.01 MC) Which state of matter does this image represent?
O Solid
O Liquid
O Gas
O Plasma
Atoms of which pair of elements will form ionic bonds in a compound?
Newton’s Second Law of Motion: The Law of 1. __________(Inertia/Acceleration)
The acceleration of an object is 2. _____________ (directly/inversely)
proportional to the magnitude of the net force acting on it, in the
3. _____________ (same/opposite) direction as the net force, and
4. _____________ (directly/inversely) proportional to the
5. _____________ (mass/weight) of the object.
Answer:
acceleration
inversly
opposite
directly
mass
20 POINTS!!
What is the enthalpy of combustion when 1 mol C6H6(g) completely reacts with oxygen?
2C6H6(g) + 15O2(g) ? 12CO2(g) + 6H2O(g)
Options:
A. - 6339 kJ/mol
B. - 3169 kJ/mol
C. 1268 kJ/mol
D. 6339 KJ/mol
Answer:
-3169
Explanation:
trust the process
-3169 kJ/mol is the enthalpy of combustion when 1 mol [tex]C_6H_6(g)[/tex] completely reacts with oxygen.
Explanation:
Given:
The reaction of combustion of [tex]C_6H_6(g)[/tex] along with enthalpies of formation of the compounds.
To find:
The enthalpy of combustion when 1 mol [tex]C_6H_6(g)[/tex] completely reacts with oxygen.
Solution:
[tex]2C_6H_6(g) + 15O_2(g) \rightarrow 12CO_2(g) + 6H_2O(g)[/tex]
Enthalpy of the reaction:
[tex]\Delta H^o_{rxn}=\sum [\Delta H^o_{f,products}]-\sum [\Delta H^o_{f,reactants}]\\=[12mol\times \Delta H^o_{f.CO_2(g)}+6mol\times \Delta H^o_{f,H_2O(g)}]-[2 mol\times \Delta H^o_{f.C_6H_6(g)}+15\times \Delta H^o_{f,O_2(g)}]\\=[12mol\times (-393.50 kJ/mol)+6mol\times (-241.82 kJ/mol)]-[2mol\times 82.90kJ/mol+15mol\times 0 kJ/mol]\\=-6338.72 kJ[/tex]
[tex]2C_6H_6(g) + 15O_2(g) \rightarrow 12CO_2(g) + 6H_2O(g).\Delta H^o_{rxn}=-6338.72 kJ[/tex]
When 1 mole of [tex]C_6H_6(g)[/tex] reacts with oxygen gas:
[tex]=\frac{\Delta H^o_{rxn}}{\text{2 mol of } C_6H_6}\\=\frac{-6338.72 kJ}{2 mol}\\=-3169.36 kJ/mol\approx -3169 kJ/mol[/tex]
-3169 kJ/mol is the enthalpy of combustion when 1 mol [tex]C_6H_6(g)[/tex] completely reacts with oxygen.
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PLEASE HELP ME PLEASE PLEASE NOW
Answer:
the amount of trials in an experiment
A stream of humid air containing 2.50 mol% H2O(v) and the balance dry air is to be humidified to a water content of 10.0 mole% H20. For this purpose, liquid water is fed through a flowmeter and evaporated into the air stream. The flowmeter reading, R, is 95. The only available calibration data for the flowmeter are two points scribbled on a sheet of paper, indicating that readings R = 15 and R = 50 correspond to flow rates V = 40 m/h and V = 96 m/h, respectively.
Answer: hello your question has some missing data attached below is the missing data
answer:
i) volumetric flow rate = 168 m^3/h = 5932.86 ft^3/h
ii) n = 582.4 Ib mole/hr
Explanation:
Given that the volumetric flow rate is a Linear function of R
V = ∝R + β
where; R1 = 15 , V1 = 40 m/h , R2 = 50, V2 = 96 m/h input values into equation above
40 = 15∝ + β ----- ( 1 )
96 = 50∝ + β ----- ( 2 )
resolve equations 1 and 2 simultaneously
56 = 35∝ + 0
∴ ∝ = 56 / 35 = 1.6
back to equation 1: 40 = 15(1.6) + β ∴ β = 40 - 24 = 16
hence ; V = 1.6(95) + 16 = 168 m^3/h = 5932.86 ft^3/h
lets assume room temperature
density of water = 62.4 Ib/ft^3
molecular weight of water = 18
therefore n = ( 62.4 / 18 ) * 168
= 582.4 Ib mole/hr