{[(3x+8)+6(2.5x-3)]}

Answers

Answer 1

Answer: The answer is 18x + 26

Step-by-step explanation:

What I did was simplify the Expression of (3x+8)+6(2.5x-3) then combine the terms and last evaluate the Expression.


Related Questions

the oblique pyramid has a square base with an edge length of 5 cm. the height of the pyramid is 7 cm. an oblique pyramid has a square base with an edge length of 5 centimeters. the height of the pyramid is 7 centimeters. what is the volume of the pyramid? 11two-thirds cm3 43three-fourths cm3 58one-third cm3 87one-half cm3

Answers

The volume of a square base pyramid with edge length of 5 cm and height of 7 cm is 58. 33 cm³

Volume of a pyramid

The volume of a pyramid is decribe as follows:

volume of a pyramid = 1 / 3 Bh

where

B = base areah = height of the pyramid

Therefore,

B = 5² = 25 cm²

volume of the pyramid = 1 / 3 × 25 × 7

volume of the pyramid = 175 / 3

volume of the pyramid = 58.3333333333

volume of the pyramid = 58. 33 cm³

learn more on pyramid here:https://brainly.com/question/3399922

Answer:

C. 58 1/3 cm^3

Step-by-step explanation:

helpppppppppppppppppppppppppppppppppppppppppppppppppp plessssssssssss
screenshot

Answers

Answer:

2.511 square kilometers

Which of the following is a function equivalent
[tex]f(x) = 4 {(1.8)}^{2x} [/tex]

a.
[tex]f(x) = 4 {(3.24)}^{x} [/tex]
b.
[tex]f(x) = 4(3.24x)[/tex]
c.
[tex]f(x) = {12.96}^{x} [/tex]
d.
[tex]f(x) = {51.84}^{x} [/tex]

Answers

Answer:

The correct result would be f(x) = 4(3.24)x.

Step-by-step explanation:

What is the solution to the equation? square root -2x-5-4=x A. -7 and -3 B. 3 and 7 C. -3 D. 7

Answers

Answer:

3

Step-by-step explanation:

step1 Isolate the square root on the left hand side

    Original equation

    √2x-5-4 = -x

    Isolate

    √2x-5 = 4-x

step2 eliminate the radical on the left hand side

    Raise both sides to the second power

    (√2x-5)2 = (4-x)2

    After squaring

    2x-5 = x2-8x+16

step3 Solve the quadratic equation

    Rearranged equation

    x2  - 10x  + 21 = 0

    This equation has two rational roots:

      {x1, x2}={7, 3}

step4 Check that the first solution is correct

    Original equation, root isolated

    √2x-5 = 4-x

    Plug in 7 for  x  

     √2•(7)-5 = 4-(7)

     Simplify

     √9 = -3

     Solution does not check

     3 ≠ -3

step5 Check that the second solution is correct

    Original equation, root isolated

    √2x-5 = 4-x

    Plug in 3 for  x  

     √2•(3)-5 = 4-(3)

     Simplify

     √1 = 1

     Solution checks !!

    Solution is:

     x = 3

Answer:

-3

Step-by-step explanation: i got it right on my test

passes through (1,4) and is parallel to the line y=2x-3

Answers

Answer:

y = 2x + 2

Step-by-step explanation:

Slope = 2

y-intercept: 4 - (2)(1) = 2

Which of the following statements must be true based on the diagram below.please help

Answers

Answer:

A: ST is a segment bisector

Step-by-step explanation:

ST is a segment bisector. Point S cuts in between segment QP. While Point T cuts between segment PO.

pls helpppppppppppppppppp meeeeeee marking BRAINLIEST!

Answers

i believe the answer should be A.


What is the value of x?
x= 12
x = 14
x = 22
x = 24

Answers

The answer is x = 12

the cost of a new laptop is $750 which genorates a sales tax of$37.50 what is the sales tax rate

Answers

Answer:

5%

Step-by-step explanation:

To find the sales tax rate, you would divide the tax by the cost to see the percentage of the tax.

$750 / $37.50= 0.05

The answer is 5%

Hope this helps

Can someone help me with number 8?

Answers

Answer:  18.55 ft/s

Step-by-step explanation:

Rate of change = change in distance ÷ change in time

                          =  (3126 ft - 1735 ft) ÷ (120 s - 45 s)

                         = 1391 ft ÷ 75 s

                         ≈ 18.55 ft/s

∴ the rate of change is 18.55 ft/s.

You are selling tickets to your school musical. Student tickets cost $2 and general admission tickets are $3. You sell 17 tickets and collect $42 how many of each type of ticket did you sell?

Answers

Answer:

9 student tickets and 8 general admission tickets

Step-by-step explanation:

Let the number of student tickets is s and general admission tickets - g.

Set equations and solve:

s + g = 172s + 3g = 42

Double the first equation and subtract from the second to eliminate s:

2s + 3g - 2s - 2g = 42 - 2*17g = 8

Find s:

s = 17 - 8 = 9

Let the student tickerts and general tickets be x and y respectively

x+y=17=>x=17-y2x+3y=42--(2)

From (1) put in (2)

2(17-y)+3y=4234+y=42y=8

And

x=17-8=9

PLEASE HELP IT’S DUE TMR

Answers

Answer:

a = 5/3 (1 1/3)

b = 16/3 (5 1/3)

c = 42/5 (8 2/5)

d = 20/9 (2 2/9)

Step-by-step explanation:

Can I have brainliest pls?

What is the value of 6(9+2)/h when g = 6 and h = 4?​

Answers

Answer: 12

Plug 6 and 4 into the problem-

6(6 + 2)/4

6(8)/4

48/4 = 12

Hey there!

6(g + 2) / h

= 6(6 + 2) / 4

= 6(8) / 4

= 8(6) / 4

= 8 + 8 + 8 + 8 + 8 + 8 / 4

= 16 + 16 + 16 / 4

= 32 + 16 / 4

= 48 / 4

= 48 ÷ 4 / 4 ÷ 4

= 12 / 1

= 12 ÷ 1

= 12


Therefore, your answer is: 12


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)


Find the solution of the system of equations.
2.x + 4y = -14
– 2y = 9

Answers

Answer:

x = 4, y = -9/2 (-4.5)

Step-by-step explanation:

Using the second equation, we can divide both sides by -2 and get

y = 9/-2

y = -9/2

Then, we plug this y value into the first equation and get:

x + 4(-9/2) = -14

Simplify:

x - 18 = -14

x = 4

Please help!!

9.(05.02)
Solve the following system of equations: (5 points)
x - 2y = 5
2x - 4y = 10

Infinitely many solutions

No solutions

(0, 0)

(5, 10)

Answers

Answer:

Infinite solutions

Step-by-step explanation:

If you look at the equation, you will see that if you multiply everything by two (On the 1st equation), you get the 2nd equation. This means that the lines are the same, so infinite solutions.

Step-by-step explanation:

infinitely many solutions :)

Given that in isosceles △ABC , base BC¯¯¯¯¯, BE¯¯¯¯¯⊥AC¯¯¯¯¯, and CF¯¯¯¯¯⊥AB¯¯¯¯¯, which of the following proves that BE¯¯¯¯¯≅CF¯¯¯¯¯?

1. Isosc. △ABC, base BC¯¯¯¯¯ (Given)
2. AB¯¯¯¯¯≅BC¯¯¯¯¯ (Def. of Isosc. △)
3. BE¯¯¯¯¯⊥AC¯¯¯¯¯, CF¯¯¯¯¯⊥AB¯¯¯¯¯ (Given)
4. ∠BEA and ∠CFA are Supplementary Angles (Def. of ⊥)
5. AB¯¯¯¯¯≅BC¯¯¯¯¯ (Supp. ∠s ≅ Thm.)
6. ∠A≅∠A (Reflex. Prop. of≅)
7. △ABE≅△ACF (SAS Steps 1, 6, 5)
8. BE¯¯¯¯¯≅CF¯¯¯¯¯ (CPCTC)

1. Isosc. △ABC, base BC¯¯¯¯¯ (Given)
2. AB¯¯¯¯¯≅BC¯¯¯¯¯ (Def. of Isosc. △)
3. BE¯¯¯¯¯⊥AC¯¯¯¯¯, CF¯¯¯¯¯⊥AB¯¯¯¯¯ (Given)
4. ∠BEC and ∠CFB are Supplementary Angles (Def. of ⊥)
5. AC¯¯¯¯¯≅BC¯¯¯¯¯ (Supp. ∠s ≅ Thm.)
6. ∠A≅∠B (Sym. Prop. of≅)
7. △ABE≅△ACF (SAS Steps 1, 6, 5)
8. BE¯¯¯¯¯≅CF¯¯¯¯¯ (CPCTC)

1. Isosc. △ABC, base BC¯¯¯¯¯ (Given)
2. AB¯¯¯¯¯≅AC¯¯¯¯¯ (Def. of Isosc. △)
3. BE¯¯¯¯¯⊥AC¯¯¯¯¯, CF¯¯¯¯¯⊥AB¯¯¯¯¯ (Given)
4. m∠BEA=m∠CFA=90∘ (Def. of ⊥)
5. ∠BEA≅∠CFA (Rt. ∠s ≅ Thm.)
6. ∠A≅∠A (Reflex. Prop. of≅)
7. △ABE≅△ACF (AAS Steps 5, 6, 1)
8. BE¯¯¯¯¯≅CF¯¯¯¯¯ (CPCTC)

1. Isosc. △ABC, base BC¯¯¯¯¯ (Given)
2. AB¯¯¯¯¯≅AC¯¯¯¯¯ (Def. of Isosc. △)
3. BE¯¯¯¯¯⊥AC¯¯¯¯¯, CF¯¯¯¯¯⊥AB¯¯¯¯¯ (Given)
4. m∠BEC=m∠CFB=90∘ (Def. of ⊥)
5. ∠BEC≅∠CFB (Rt. ∠s ≅ Thm.)
6. ∠A≅∠B (Sym. Prop. of≅)
7. △ABE≅△ACF (AAS Steps 5, 6, 1)
8. BE¯¯¯¯¯≅CF¯¯¯¯¯ (CPCTC)

Answers

The correct proof that proves that BE ≅ CF is the proof in option C. (see attachment).

Recall the following:

An isosceles triangles has two sides that are congruent and a base.AAS Congruence Theorem proves that two triangles are congruent if they possess two pairs of congruent sides and a pair of non-included congruent sides.All corresponding parts of two congruent triangles are equal in measure to each other, based on the CPCTC Theorem.

The isosceles triangle ABC given is shown in the image attached below.

To prove that, BE ≅ CF, establish the fact that △ABE ≅ △ACF by the AAS Congruence Theorem.

Since △ABE ≅ △ACF, therefore BE ≅ CF by the CPCTC Theorem.

Thus, the correct proof that proves that BE ≅ CF is the proof in option C. (see attachment).

Learn more about AAS Congruence Theorem on:

https://brainly.com/question/3168048

PLEASE PROVIDE A PICTURE graph the solution to this system of inequalities in this coordinate plane. 3у > 2х + 12
2x +y < -5

Answers

Answer:

The double shaded region

May I please receive help?

Answers

They are perpendicular

BRAINLIEST!!! +10 POINTS!!! REAL ANSWERS ONLY PLEASE!!!

Answers

Answer:

plus ten points huh i only see five

Step-by-step explanation:

Answer:

|-x| + 3

Step-by-step explanation:

I say that because -x will be turned into positive x and then add the 3, and you will get the answer.

Convert 62 miles to hour to feet to second​

Answers

62 Miles per Hour =

90.933333 Feet per Second

(rounded to 8 digits)

Which of the following numbers are rational, but NOT integers?

Select one or more:

a.√33
b.8.4
c.3/4
d.0

Answers

Answer:

0

Step-by-step explanation:

Zero is a rational number, and we know that the integer 0 can be written in any one of the following forms. ... Thus, 0 can be written as, where a/b = 0, where a = 0 and b is any non-zero integer. Hence, 0 is a rational number and not an integer.

On a drawing of a model airplane, the scale used is 1 in.:3 ft. How many feet would 4.5 inches represent?

A. 13.5 feet
B. 6.5 feet
C. 1.5 feet
D. 4.5 feet

Answers

Answer:

13.5

Step-by-step explanation:

4.5*3=13.5

3 time 4.5 is 12+1.5 so it’s A lol

Your mother bought 2 kilograms of chicken and 3 kilograms of pork to consume in week. How many kilograms of chicken and pork did your family consume in a month?​

Answers

Answer:

20?.... seems right to me.

Step-by-step explanation:

9514 1404 393

Answer:

  20 kg

Step-by-step explanation:

The mass of the chicken and pork for 1 week is (2 kg) +(3 kg) = 5 kg.

Normally, we think of a month as 4 weeks.

  (4 wk)(5 kg/wk) = 20 kg

If pork and chicken are consumed at the same rate for 4 weeks, the family will consume 20 kg of pork and chicken.

_____

If we consider a year to be 52 weeks (it is actually 1 or 2 days longer), then the number of weeks in an average month is ...

  52/12 = 4 1/3 weeks/month

Multiplying that value by 5 kg/week will give 21 2/3 kg per month.

__

The answer depends on the assumption you make about weeks in a month.

Solve for x. PLEASE GIVE EXPLAINED WORK FOR IT

Answers

Answer:

x = 9

Step-by-step explanation:

7x - 25 = 4x + 2 (vertical angles)

7x - 4x = 2 + 25

3x = 27

x = 27/3

x = 9

4(9) + 2 = 38 degrees

Please help with this math problem ASAP!! I will mark brainliest! :)

Answers

Answer:

y=4 x=6

Step-by-step explanation:

you said asap do i dont have time to explain

Convert the mixed numbers to improper fractions:1. 5 6/72. 8 3/9

Answers

1. 5x72+6 over 72 = 366/72
2. 8x9+3 over 9. = 75/9

Ig1000+log342........​

Answers

Answer:

5.53

Step-by-step explanation:

We know that lg 1000=3.

And using the calculator, we know that lg 342=2.53

State the reason for statement #5.
PLEASE ANSWER FAST

Answers

1. Given

2. Given

3. Alternate Interior Angles

4. Reflexive Property

5. SAS

Hope this helps!! :)

If AM = x + 8 and MB= 6x – 2, find MB.

Answers

Answer:

10

Step-by-step explanation:

Firstly, AM=x+8

or, A=x+8-M......eqn (i)

MB=6x-2

or, B=6x-2-M......eqn (ii)

Now,

from eqn (i) and (ii)

x+8-M=6x-2-M

or, 8+2=6x-x-M+M

or, 10=5x

or, 10÷5=x

therefore, x=2

Again,

MB=6x-2

=6×2-2

=12-2

=10

is it correct

please mark me as BRAINLIEST


[tex]Simplify: \frac{ 5×(25)^{n+1} - 25 × (5)^{2n}}{5×(5)^{2n+3 }- (25)^{n+1​}} \\ [/tex]
Need help please"....."​

Answers

[tex] \green{\large\underline{\sf{Solution-}}}[/tex]

Given expression is

[tex]\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } [/tex]

can be rewritten as

[tex]\rm \:  =  \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} } [/tex]

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\ [/tex]

And

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\ [/tex]

So, using this identity, we

[tex]\rm \:  =  \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} } [/tex]

can be further rewritten as

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{25 - 1} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{24} [/tex]

[tex]\rm \:  =  \: \dfrac{1}{6} [/tex]

Hence,

[tex]\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}[/tex]

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