The expected life span of a star with a low stellar mass, a relatively cool temperature, and dim relative brightness is 10,000 to 200,000 million years and is therefore denoted as option D.
What is a Star?This is referred to as an astronomical object comprising a luminous spheroid of plasma held together by its gravity an d they are usually visible at night.
We should also note that stars with a high stellar mass burn burn their fuel at a much faster rate and can shine for just millions of years while on the other hand stars with a low stellar mass burn burn their fuel at a much slower rate and can shine for just billions of years.
This therefore means that the expected life span of a star with a low stellar mass and dim relative brightness will most likely be between 10,000 to 200,000 million years hence why option D was chosen.
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Why is i0 10 12 W m2 used as a reference intensity for intensity level?
Since I0 is the lowest sound intensity that a person with normal hearing can detect, it is chosen as the reference point. Given that log10 1 = 0, the decibel level of a sound with an intensity of 10–12 W/m2 is = 0 dB. In other words, the human hearing threshold is zero decibels.
The reference value I0 is 10–12 W/m2, which corresponds to the threshold of hearing intensity at 1000 Hz. The Sound Intensity Level, or SIL for short, is the intensity decibel scale. The related sign, like in our text, is LI.
Much more frequently than sound intensities in watts per square meter, sound intensity levels are expressed in decibels (dB). Both the scientific literature and the public media use decibels as their preferred measurement unit. The rationale behind this decision of units has to do with how we hear. There is a reference intensity, I0 = 1012 W/m2. The lowest or threshold intensity of sound that a person with normal hearing can perceive at a frequency of 1000 Hz is specifically known as I0. The degree of sound intensity is not the same as the intensity. is a unitless quantity that informs you of the sound level in relation to a predefined standard (1012 W/m2, in this case), as it is defined in terms of a ratio.
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A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision.
The final velocity of the red-blue carts system is 5 cm/s.
What is the final speed of the two carts after collision?
The final speed of the two carts, that is the red cart and the blue cart system after the collision is calculated by applying the principle of conservation of linear momentum.
Pi = Pf
m₁u₁ + m₂u₂ = v ( m₁ + m₂ )
where;
m₁ is mass of the red cartm₂ is the mass of the blue cartu₁ is initial velocity of the red cartu₂ is the initial velocity of the blue cartv is the final velocity of the two carts after the collisionm₁u₁ + 0 = v ( m₁ + m₂ )
m₁u₁ = v ( m₁ + m₂ )
v = ( m₁u₁ ) / ( m₁ + m₂ )
The final velocity of the red-blue carts system is calculated as;
v = ( 50 kg cm/s ) / ( 5 kg + 5kg )
v = 5 cm/s
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The complete question is below:
A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision. What is the final velocity of the two carts system after the collision if the mass of the blue cart is 5 kg.
The seatback must be adjusted far enough for your __________ to rest on the top of the steering wheel when your arm is comfortably extended.
The seatback must be adjusted far enough for your wrist to rest on the top of the steering wheel when your arm is comfortably extended.
What is the motion of steering wheel?The majority of modern automobiles, compact trucks, and SUVs have a rack and pinion steering. This transforms the steering wheel's rotational action into the linear motion which rotates the wheels and directs your course. A steering pinion, a circular gear, is used in the system to lock teeth on a rod (the rack).
What kind of basic device is a steering wheel?The basic device at work in steering, doorknobs, turbines, and bicycle wheels is a wheel and axle. An inclined plane wound around a cylinder is known as a screw.
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A skier is pushed from the top of a hill so that he starts moving down the hillside from a height of 100 m with
an initial speed of 0.434 m/s. After traveling 80.4 m, he reaches the bottom of the valley. Due to inertia, he
then continues 70.4 m up another hillside (y = 40 m) and crashes into a snow bank that compressess like a
spring (k = 50 N/m). What is the skiers speed as he crashes into the snow bank? How far does the snow
compress? Assume that you can neglect friction.
Speed as the skier crashes into the snow bank: 0.434 m/s
Distance the snow compresses: 1.544 m
The speed of the skier as he crashes into the snow bank is the initial speed since there is no acceleration due to the lack of friction. The distance the snow compresses is calculated using the following equation:
compression = (mass x velocity2) / (2 x spring constant)
Therefore, compression = (75 kg x 0.4342) / (2 x 50 N/m) = 1.544 m
A car at rest with respect to a building can be in motion with respect to another observer. True/False. Please explain your answer
A boy exerts a force of 225 N on a lever (Links to an external site.) to raise a 1250 N rock a distance (Links to an external site.) of 0.13 m. If the lever is frictionless, how far did the boy have to move his end of the lever
If the lever is frictionless, to raise the rock a distance of 0.13 m, then the boy has to move the lever to 0.72 m.
An external force that acts upon an object results in a motion of the object, then it is called a work done upon the object by that force.
Given that the external force on a lever is 225 N and on a rock is 1250 N. The distance of motion by the rock is 0.13 m.
Hence the work done by the lever will be equivalent to the work done by the rock to move a particular distance.
Work (Lever) = Work (Rock)
F(lever) x D (lever) = F (rock) x D (rock)
225x D(lever)= 1250 x0.13
D(lever) is 0.72 m
Hence we can conclude that the distance of the motion by the lever is 0.72 m.
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3. An air bubble of radius r rises steadily through
a liquid of density p at the rate of v. Neglecting
density of air, find the coefficient of viscosity of
liquid.
The coefficient of viscosity of a liquid can be determined from the motion of a bubble rising or falling through the liquid.
What is viscosity?
Viscosity basically is the measure of a fluid's resistance to flow. It is a measure of a fluid's internal friction, which is caused by the attraction of molecules in the fluid. Viscosity is an important physical property of fluids, as it affects the fluid's flow characteristics.
The equation for the coefficient of viscosity is given by:
2/9 r2 ρg/v.
where,
r = radius of bubble
ρ = density of liquid
g = acceleration due to gravity
v = velocity of bubble
Therefore, to calculate the coefficient of viscosity of a liquid, we need to know the radius of the bubble, the density of the liquid, the acceleration due to gravity, and the velocity of the bubble.
Hence, the coefficient of viscosity of liquid is 2/9 r2 ρg/v.
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Why are dynamic flexibility tests not used as often as?
Dynamic flexibility tests are not used as often as static flexibility tests because dynamic flexibility tests involve more subjective measurements.
Static flexibility tests are more common in comparison to dynamic tests because static flexibility tests are easier to replicate. It is difficult to standardize motion-based tests such as dynamic flexibility tests between various subjects, while static flexibility tests are simple and easy to standardize it is because the metrics are fixed and not open to interpretation.
Since, dynamic flexibility tests are hard to perform because they measure the amount of stress on a muscle that is in motion. And it is difficult to assess this among multiple people and to get an accurate picture. That is why these tests are not used as often as static flexibility tests.
"
Complete question
Why are dynamic flexibility tests not used as often as static flexibility tests?
"
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A typical spectrophotometer has a path length (the distance light travels through a sample) of 1 cm. Light travels at approximately 3.0 x 108 m/s in vacuum. How long does it take (in ns) for light to travel 1.0 cm
The time taken is 3.33 ns for light to travel 1.0 cm in a spectrophotometer.
What is time?
Time is defined as a scalar quantity that describes the progression of events in the universe. It is often considered to be the fourth dimension of spacetime, along with the three dimensions of space. Time is closely related to the concepts of causality, or the relationship between cause and effect, and is considered to be a fundamental aspect of the physical universe.
The distance light travels in 1 cm is equal to 1 cm x 10^-2 m. To find out how long it takes for light to travel this distance, we can use the formula:
time = distance / speed
Where distance is the distance light travels (1.0 cm x 10^-2 m), and speed is the speed of light in vacuum (3.0 x 108 m/s).
time = (1.0 cm x 10^-2 m) / (3.0 x 108 m/s)
time = 3.33 x 10^-10 s
To convert this time to nanoseconds (ns), we can multiply the time in seconds by 1 billion (10^9):
time = 3.33 x 10^-10 s x 10^9 ns/s
time = 3.33 ns
Therefore, the time taken is approximately 3.33 ns for light to travel 1.0 cm in a spectrophotometer.
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Caffeine dosage causes a change in the time to finish a maze and it isn't possible for that the time to finish a maze could cause a change in
caffeine dosage.
Caffeine dosage and time to finish a maze are independent variables, meaning that a change in one does not cause a change in the other. It is possible that caffeine dosage may have an effect on the time it takes to finish a maze, but the time it takes to finish a maze would not cause a change in caffeine dosage.
Caffeine Maze Time ImpactCaffeine is a stimulant that can affect the central nervous system and can have a range of effects on the body, including increased alertness, focus, and energy. When it comes to completing a maze, the time it takes to finish it could be affected by the person's level of alertness, focus, and energy. Therefore, if a person ingests a certain dosage of caffeine, it could affect the time it takes for them to finish the maze because of the effect caffeine has on the body.
On the other hand, the time it takes to finish a maze does not affect the caffeine dosage, in other words, caffeine dosage is an independent variable, it does not depend on other variables, and does not change based on the time it takes to complete a maze. It is determined by the amount of caffeine consumed.
So, in short, caffeine dosage can have an effect on the time it takes to finish a maze, but the time it takes to finish a maze does not have an effect on caffeine dosage.
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Describe how you would find absolute pressure in a car tire if you had a barometer and a tire pump with an air
pressure gauge
The absolute pressure in a car tire can found by following method:
Pressure is the force per unit area applied toward a course perpendicular to the outer layer of an item. To keep it precise, it is an amount of force following up on a unit area. The SI unit for pressure is measured in Pascals (Pa). Other non-SI units are bar and PSI. There are two types of references to quantify pressure,
Gauge Pressure
Absolute Pressure
The most well-known pressure reference is Gauge Pressure which is connoted by a ‘g’ after the pressure unit, for example, 33 psi g. It is the pressure relative to barometric or atmospheric pressure; it is positive for pressures above atmospheric pressure and negative for pressures that are below atmospheric pressure. An Absolute pressure estimation is one that is alluded to as a perfect or an ideal vacuum. The best illustration of an absolute referenced pressure is the calculation of Barometric pressure. To deliver an absolute pressure sensor, one strategy is for a maker to seal a high vacuum behind the detecting diaphragm.Formula of Absolute pressure is given by:
p(a) = p(g) + p(atm)
Where ,
p(a) is absolute pressure,
p(g) is gauge pressure and
P(atm) is atmospheric pressure
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Draw conclusions: Objects falling through air are slowed by the force of air resistance. Which objects were slowed the most by air resistance
Due to this air resistance, Galileo discovered that heavier or more dense things fall more quickly than less dense ones. Together, a brick and a feather fell. The feather falls more slowly due to air resistance.
Descending against air resistance an object often experiences some air resistance as it falls through the air. The leading surface of the object collides with air molecules, creating air resistance. Several variables affect how much air resistance the object really experiences.
Therefore, heavier things fall quicker than lighter ones because the force of gravity acting on them is greater. As a result, heavier objects accelerate at faster speeds until the force of air resistance acts on them.
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A cylindrical bucket of liquid (density rho) is rotated about its symmetry axis, which is vertical. If the angular velocity is ω, show that the pressure at a distance r from the rotation axis is P=P 0+ 21rhoω 2r 2where P 0 is the pressure at r=0,
Answer:
To derive the formula for the pressure at a distance r from the rotation axis, you can use the principle of hydrostatic equilibrium. This states that the pressure at a point in a fluid is equal in all directions and the net force on a fluid element is equal to zero.
Consider a small cylindrical element of fluid at a distance r from the rotation axis, as shown in the diagram below. The dimensions of the element are dr in the radial direction, 2πr in the circumferential direction, and h in the vertical direction. The weight of the element is equal to the product of its volume, density, and the acceleration due to gravity: W = (2πr)(dr)(h)(ρ)(g). The pressure at the top and bottom faces of the element is P + dP, where P is the pressure at the point and dP is a small change in pressure. The forces acting on the element are the weight of the element, the pressure force at the top face, and the pressure force at the bottom face.
[asy]
unitsize(2cm);
pair P1, P2, P3, P4;
P1 = (0,0);
P2 = (1,0);
P3 = (1,1);
P4 = (0,1);
draw((-0.5,0)--(1.5,0));
draw((0,-0.5)--(0,1.5));
draw(P1--P2--P3--P4--cycle);
draw((0.5,0)--(0.5,1));
draw((0.25,0)--(0.25,1));
draw((0.75,0)--(0.75,1));
label("$r$", (0.5,1.5), red);
label("$
Anxiety disorders can become a pathological disorder when feelings of apprehension and fear __________.
a. are recurrent for less than six months
b. are inherited due to genetics
c. become excessive, uncontrollable, and affect daily life
d. are controllable but excessive
please select the best answer from the choices provided a b c d
When feelings of anxiety and worry become excessive, out of control, and interfere with daily life, they can develop into pathological diseases called anxiety disorders. So the correct option is (c).
Anxiety disorders are characterized by feelings of apprehension and fear, which are normal human emotions. However, when these feelings become excessive, uncontrollable, and affect daily life, they can be considered a pathological disorder. Anxiety disorders can affect a person's ability to perform daily activities, such as work or school, and can also cause physical symptoms such as insomnia, muscle tension, and fatigue. These disorders can be recurrent, but they need to be excessive, uncontrollable, and affect daily life in order to be considered pathological.
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Two small objects carry the same amount of charge, and the magnitude of the electric force exerted by one object on the other is 0.10 N when they are held 30 mm apart. If the force magnitude increases when the objects are released and free to move, are the objects of the same charge or opposite charge?
The objects must be of opposite charge because the electric force of attraction between them increases when they are released and free to move.
This means that the electric force must be a repulsive force that pushes the objects away from each other. Opposite charges attract and as charges repel, the objects must be of opposite charge for the electric force to increase when the objects are released and free to move.
Therefore when two small objects carry the same amount of charge, the magnitude of the electric force exerted by one object on the other is 0.10 N when they are held 30 mm apart. If the force magnitude increases when the objects are released and free to move, then we can say that they are opposite charges.
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humans taste food mostly because of:
Answer:
taste buds
Explanation:
very sensitive microscopic hairs called microvilli. The tiny hairs send messages to the brain about how something tastes, so you know if it's sweet, sour, bitter, or salty
How much work is done by gravity to cause a 12.0 kg stone to drop from a height of 22.0 m to a height of 3.00 m?
Answer:
Work done is 2280 Joules.
Explanation:
Work done can be found using the formula
[tex]W=Fs\\[/tex]
where:
W is work done ( in Joules)
F is force ( in Newtons)
s is displacement ( in Meters)
Assuming we are on Earth, we can find the force acting on the object using the mass with the following:
Mass × 10 = Force
12.0 × 10 = 120N
Moreover, we can find displacement by simply subtracting the final distance from the starting distance:
22.0m - 3.00m = 19.0m
Therefore,
[tex]W = Fs[/tex]
[tex]W = 120N[/tex] × [tex]19m[/tex]
[tex]W= 2280J[/tex]
A block is resting on an slope. (Figure 3) Which of the following forces act on the block? Check all that apply. O weight O static friction O normal force O kinetic friction O force of push
The correct option is A, B, and C. A block resting on a slope is Weight, static friction, and Normal force.
Static friction is a force that continues an item at relaxation. Static friction definition can be written as: The friction skilled while individuals try to move a desk-bound object on a surface, without surely triggering any relative movement between the frame and the surface on which it's miles.
Static friction is a form of friction force that acts on a body when there's no relative motion between the object and the surface. So, it can act even if the frame is in motion however there should be no relative motion.
A pressure acting on an item is said to be a static force if it no longer exchanges the scale, function, or route of that precise object. The pressure implemented to a structure acts as a load to that precise structure, that is why static force is likewise called a static load.
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Complete Question:
A block is resting on a slope. (Figure 3) Which of the following forces act on the block?
Check all that apply.
A). Weight
B). Static friction
C). Normal force
D). Kinetic friction
E). Force of push
Two unequal masses are dropped simultaneously from the same height. The two masses will experience the same change in
(A) acceleration
(B) kinetic energy
(C) potential energy
(D) velocity
When two unequal masses are dropped simultaneously from the same height, then both masses will experience the same change in D: velocity.
Velocity is the prime indicator of the position and the rapidity of the object. It can be described as the distance covered by an object in a unit of time. It means that velocity is the displacement of the object in unit time. When in the case where two objects with unequal masses are dropped simultaneously from the same height, both masses will attain the same change in velocity.
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PLEASE HELP!!! Which phase change occurs when steam is cooled to 100°C?
condensation
boiling
sublimation
evaporation
The amount of energy needed to change a liquid into a gas, without changing its temperature, is known as the __________.
heat of sublimation
heat of fusion
specific heat
heat of vaporization
In which phase change are hydrogen bonds formed?
boiling
sublimation
evaporation
freezing
The specific heat of a substance is 0.215 J/g°C. How much energy is required to raise the temperature of 20 g of the substance from 72°C to 88°C?
68.8 J
323.4 J
4.3 J
3.4 J
The first question is asking which phase change occurs when steam is cooled to 100°C. The answer is condensation.
The second question is asking for the term that refers to the amount of energy needed to change a liquid into a gas, without changing its temperature. The answer is heat of vaporization.
The third question is asking in which phase change hydrogen bonds are formed. The answer is freezing.
The fourth question is asking for the amount of energy required to raise the temperature of 20 g of a substance from 72°C to 88°C, given that the specific heat of the substance is 0.215 J/g°C. To solve this problem, you can use the formula Q = m * c * delta T, where Q is the energy required, m is the mass of the substance, c is the specific heat, and delta T is the change in temperature. Plugging in the given values, you get Q = 20 g * 0.215 J/g°C * (88°C - 72°C) = 68.8 J. Therefore, the answer is 68.8 J.
Bird bones have air pockets in them to reduce their weight. This also gives them an average density significantly less than that of the bones of other animals. Suppose an ornithologist weighs a bird bone in air and in water and finds its mass is 47.0 g47.0 g and its apparent mass when submerged is 3.60 g3.60 g (the bone is watertight). What mass of water is displaced
The mass of water displaced when the mass of bird bone in water and air is given, is calculated to be 43.4 g.
Given that,
Weight of bird bone in air = True weight = 47 g
Apparent weight of the bird bone when submerged = 3.6 g
The equation for apparent weight is known to be,
Apparent weight = True weight - Buoyant force
Making Buoyant force as subject, we have,
Buoyant force = 47 g - 3.6 g = 43.4 g
F b = mw × g = (m wat - m air)× g
mw = m wat - m air = 47 g - 3.6 g = 43.4 g
Thus, the mass of the water displaced is 43.4 g.
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4. A railcar of mass m and speed v collides and sticks to another identical, stationary railcar. The speed of the center of mass of the two-railcar system will be
The required speed of the centre of mass of the two-railcar system after the collision will be half as much as it was before the collision.
One of the railroads has zero motion prior to the collision. Following it, both railroads move at the same speed. By the conservation of the total momentum of the system, we have,
m vi = m vf + m vf
m vi = 2 m vf
vi = 2 vf
vf = 1/2 vi
vf is the velocity after collision
vi is the velocity before collision
Thus, the speed of the railroad together after the collision is calculated to be half of that before collision.
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You bought a can of apricot jam. The contents marked as: net weight: 500g and volume: 400ml is the statement correct?why? and what is the mass of the jam you bought? calculate the density of jam in g/cm
The statement is not correct the mass of the jam is 500g and the density of the jam is 0.125gm/cm³
How to calculate the density?The statement is not correct because mass and volume cannot be used together to describe the contents of a can. Mass is a measure of how much matter is in an object and volume is a measure of the amount of space taken up by an object. So, in this case, the can of apricot jam should just be marked with the net weight in grams.The mass of the jam you bought is 500g.To calculate the density of the jam, we need to divide the mass by the volume. The density of the jam is 500g/400ml = 1.25g/ml. To put this in g/cm3, we need to divide the density by 1000, which gives us 1.25g/ml = 0.125g/cm3.To learn more about density refer to:
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A voltage vL(t)=10cos(2000πt) is applied to a 100-mH inductance.
A)Find the complex impedance of the inductance.
The complex impedance of the 100 mH inductance when a voltage vL(t) = 10cos(2000πt) is applied to it is: j200Ω.
What is inductance?
Inductance is a property of an electrical component that describes the ability of the component to store energy in a magnetic field when electric current passes through it.
Inductance is measured in units of henrys (H). When current flows through a component with inductance, it creates a magnetic field around the component that resists changes to the current. This resistance to changes in current is called inductive reactance and is measured in units of ohms.
The complex impedance of an inductor is given by Z = jωL, where ω is the angular frequency and L is the inductance.
Therefore, the complex impedance of the 100 mH inductance when a voltage vL(t) = 10cos(2000πt) is applied to it is:
Z = j(2000π) (100 x 10-3) = j(2π) (100 x 10-3) = j200Ω
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An object is experiencing an acceleration of 12 m/s2 while traveling in a circle of radius 5. 0 m. What is its velocity?
The velocity of the object is 7.74m/s
Though it may sound sophisticated, velocity is simply the rate at which an object's location changes with regard to a frame of reference and time. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction.
We are given that,
Acceleration = 12m/s²
Radius = r = 5.0m
Velocity = v = ?
The velocity of the object can be calculated by the formula ,
a = v²/r
v = √ar
v = √12m/s²× 5m
v = √60m²/s²
v= 7.74m/s
Thus , the velocity of the object would be 7.74m/s.
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A truck with mass of 3,250 kg traveling with a velocity of 25.0 m/s hits a car at rest. After the collision, the truck moves with a velocity of 19.0 m/s. The car has a mass of 2,820 kg. If the two vehicles do not stick together, how fast is the car moving after the collision?
Answer:
6.9 m/s
Explanation:
This is a conservation of momentum problem, so the total momentum before the collision must equal the total momentum after the collision.
P = mv
m1v1 + m2v2 (before) = m1v1 + m2v2 (after)
(3250kg)(25.0 m/s) + (2820 kg)(0m/s) = (3250 kg)(19.0 m/s) + (2820 kg)(v2)
Now you can solve for the v of the car after the collision:
81250 kg·m/s + 0 = 61750 kg·m/s + (2820 kg)v2
19500 kg·m/s = (2820 kg)v2
v2 = 19500 kg·m/s / 2820 kg = 6.9 m/s
Will day and night on Earth be different if the planet did not rotate?
What is the shape of a baseball field called?
Each base is at the intersection of a square-shaped infield in baseball. 8100 square feet, 900 square yards, or 90 × 90 square feet make up the space.
How would you describe a baseball field?Nine players occupy the diamond-shaped field that is used for baseball. There are two main areas of the field: the infield and the outfield. Four infielders and two core players cover the infield. Three outfielders cover the outfield.
In a letter dated May 26, James Cannon expressed shock that the "diamond" form is referred to as a rhombus. A baseball diamond, he pointed out, is essentially a square.
The elevated dirt area in the middle of the infield known as the hill—also known as the pitcher's mound—is where the pitcher throws. The pitcher's rubber is located directly behind the middle of the mound and is what they use to prepare and throw the ball.
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Is acceleration greater going up or down a ramp?
The acceleration which is acting on the object which is moving on the ramp is same for both the motion whether is going upwards or moving downwards.
Rolling motion happens when an object roll over from a ramp or any other sloppy surface whether it is rough or smooth. many forces act on it at the same moment. also in many forces rolling tangential force and gravitational force is also acting on it at the same moment. in which the gravitational force is acting on it at a bigger pace and plays an important role in rolling of the object from the ramp or any other sloppy surface. here we can see that the only force that is making impact on the object is the gravitational force. Hence, by this information we consider that the acceleration which is acting on the object which is moving on the ramp is same for both the motion whether is going upwards or moving downwards.
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A car is travelling along a horizontal road in an easterly direction. The car has a mass of 2300 kg and the drag force (friction) acting on the car is a constant 5000 N to the west.
The car is initially travelling at a speed of 10 m s‒1 and 20 s later is travelling at a speed of 14 m s‒1.
What is the gravitational force on the car?
What is the vertical normal (support/reaction) force acting on the car?
What is the horizontal force on the cars tyres from the road?
The gravitational force on the car is 23000 N, the vertical normal (support/reaction) force acting on the car is 0 N, and the horizontal force on the car's tyres from the road is 5460 N.
Mass of the car, m = 2300 kg
Force acting on the car, F = 5000 N
The initial speed of the car, u = 10 m/s
The final speed of the car, v = 14 m/s
Time, t = 20 s
The gravitational force on the car is calculated by the formula given as
F = mg
F = 2300 × 10
F = 23000 N
Now, as there is no vertical movement in the car therefore the vertical force acting on the car is 0 N.
The horizontal force on the car's tyres from the road
= force acting on the car + net force on the car
= 5000 + ma
= 5000 + 2300 × (v-u)/t
= 5000 + 2300 × (14 - 10)/20
= 5000 + 2300 × 4/20
= 5000 + 460
= 5460 N
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