4(6c+5) - 2(3c - 5) = 120

Answers

Answer 1

Answer:

[tex]c=5[/tex]

Step-by-step explanation:

[tex]4(6c+5)-2(3c-5)=120[/tex]

Use the distributive property to expand the equation:

[tex]4(6c)+4(5)-2(3c)-2(-5)=120\\\\24c+20-6c+10=120[/tex]

Combine like terms to simplify the equation:

[tex]24c-6c+20+10=120\\\\18c+30=120[/tex]

Subtract 30 from both sides:

[tex]18c+30-30=120-30\\\\18c=90[/tex]

Isolate the variable c. Divide both sides by 18:

[tex]\frac{18c}{18}=\frac{90}{18}\\\\ c=5[/tex]

So, c is equal to 5.

:Done


Related Questions

What is wrong with this problem. 2(n +3) = 2n +3

Answers

Steps to solve:

2(n + 3) = 2n + 3

~Distribute left side

2n + 6 = 2n + 3

~Subtract 6 to both sides

2n = 2n - 3

~Subtract 2n to both sides

n = -3

Best of Luck!

Estimate 8.25% sales tax on a $39.89 purchase

Answers

Turn the percentage into a decimal.

8.25% / 100 = 0.0825

Multiply.

39.89 * 0.0825 ≈ $3.29

Subtract.

39.89 + 3.29 = $43.18

Best of Luck!

Answer please quick

Answers

Answer:

1 metric ton is = to 1000 kilograms

WILL GIVE BRAINLY FOR ANSWER!! Please help with this question!!! Given the piecewise function: f(x) = 1/2x + 5, x > 2 6, x = 2 x + 4, x < 2 a. Write f' (f prime) as a piecewise function b. Determine if f is differentiable at x = 2. Give a reason for your answer. Photo is attatched.

Answers

Answer:

A)

[tex]f'(x) = \left\{ \begin{array}{lIl} \frac{1}{2} & \quad x >2 \\ 0& \quad x =2\\1&\quad x<2 \end{array} \right.[/tex]

B) Continuous but not differentiable.

Step-by-step explanation:

So we have the piecewise function:

[tex]f(x) = \left\{ \begin{array}{lIl} \frac{1}{2}x+5 & \quad x >2 \\ 6& \quad x =2\\x +4&\quad x<2 \end{array} \right.[/tex]

A)

To write the differentiated piecewise function, let's differentiate each equation separately. Thus:

1)

[tex]\frac{d}{dx}[\frac{1}{2}x+5}][/tex]

Expand:

[tex]\frac{d}{dx}[\frac{1}{2}x]+\frac{d}{dx}[5][/tex]

The derivative of a linear equation is just the slope. The derivative of a constant is 0. Thus:

[tex]\frac{d}{dx}[\frac{1}{2}x+5}]=\frac{1}{2}[/tex]

2)

[tex]\frac{d}{dx}[6][/tex]

Again, the derivative of a constant is 0. Thus:

[tex]\frac{d}{dx}[6]=0[/tex]

3)

We have:

[tex]\frac{d}{dx}[x+4][/tex]

Expand:

[tex]\frac{d}{dx}[x]+\frac{d}{dx}[4][/tex]

Simplify:

[tex]=1[/tex]

Now, let's substitute our original equations for the differentiated equations. The inequalities will stay the same. Therefore:

[tex]f'(x) = \left\{ \begin{array}{lIl} \frac{1}{2} & \quad x >2 \\ 0& \quad x =2\\1&\quad x<2 \end{array} \right.[/tex]

B)

For a function to be differentiable at a point, the function must be a) continuous at that point, and b) the left and right hand derivatives must be equivalent.

Let's first determine if the function is continuous at the point. Remember that a function is continuous at a point if and only if:

[tex]\lim_{x \to n^-} f(n)= \lim_{x \to n^+}f(n)=f(n)[/tex]

Let's find the left hand limit of f(x) at it approaches 2.

[tex]\lim_{x \to 2^-}f(x)[/tex]

Since it's coming from the left, let's use the third equation:

[tex]\lim_{x \to 2^-}f(x)\\=\lim_{x \to 2^-}(x+4)[/tex]

Direct substitution:

[tex]=(2+4)=6[/tex]

So:

[tex]\lim_{x \to 2^-}f(x)=6[/tex]

Now, let's find the right-hand limit:

[tex]\lim_{x \to 2^+}f(x)[/tex]

Since we're coming from the right, let's use the first equation:

[tex]\lim_{x \to 2^+}(\frac{1}{2}x+5)[/tex]

Direct substitution:

[tex](\frac{1}{2}(2)+5)[/tex]

Multiply and add:

[tex]=6[/tex]

So, both the left and right hand limits are equivalent. Now, find the limit at x=2.  

From the piecewise function, we can see that the value of f(2) is 6.

Therefore, the function is continuous at x=2.

Now, let's determine differentiability at x=2.

For a function to be differentiable at a point, both the right hand and left hand derivatives must be equivalent.

So, let's find the derivative of the function as x approahces 2 from the left and from the right.

From the differentiated piecewise function, we can see that as x approaches 2 from the left, the derivative is 1.

As x approaches 2 from the right, the derivative is 1/2.

Therefore, the right and left hand derivatives are not the same.

Thus, the function is continuous but not differentiable.

What is the slope of the line?

Answers

La pendiente de una recta es la tangente del ángulo que forma la recta con la dirección positiva del eje de abscisas. En funciones no lineales, la razón de cambio varía a lo largo de la curva. La derivada de la función en un punto dado es la pendiente de la línea tangente en dicho punto.

F:V  7w7

Solve the linear equation. 3x = 24 x = ?

Answers

Answer:

3x =24

x = 24 -3

x = 21 (ans)

Answer:

X=8

Step-by-step explanation:

3x=24

divide each side by 3 to isolate x

x=8

The area of a rectangle is at least 10 more than 3 times the width of the rectangle. If the area of the rectangle is at least 250 square units, what are the possible values for the width (w) of the rectangle?

Answers

Answer: 80
Step-by-step explanation:

What is the quotient of 29,596÷28?

Answers

Answer:

√ 96

log

( 7 )

6 ! /3 !

Step-by-step explanation:

ben has bundled cable television and internet service. he pays $89.92 each month for the service. how much will he pay per year for cable and internet

Answers

Answer:

$1,079.04

Step-by-step explanation:

multiply: 89.92x12=1078.04

Joe will rent a car for the weekend. He can choose one of two plans. The first plan has no initial fee but costs $0.80 per mile driven. The second plan has an initial fee of $75 and costs an additional $0.60 per mile driven. How many miles would Joe need to drive for the two plans to cost the same?

Answers

Answer:

375 miles

Step-by-step explanation:

m=miles

I set it up as an equation.                                                    $75+.60m=.80m                      

And solved from there                                                                                                                                                                                                                                                                                

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                                                               

                                                                                                                                                                                                                                               

Answer:

375 miles :D

Step-by-step explanation:

Twice the sum of six "x" and seventy eight.

Answers

Answer:

2(6x+78)

Unless it's the exact number. You hadn't specified what x is.

Acellus
x = [?]°
1040
1170
X
124°
1000
Hint: Sum = (n-2)180

Answers

Since the sum of the interior angles of a polygon of n sides is (n-2)*180 degrees.

Here n=5 (polygon), so that sum is (5-2)*180 degrees, or 3*180 degrees, or 540 degrees.

Adding up the 5 interior angles shown, we get
Sum = (n-2)*180 =540
100 + 117 + 104 + 124 + x = 540 (degrees).
217 + 228 + x = 540 (degrees).
445 + x =540
Thus, x = 540 - 445 degrees, or x = -4 degrees.

Answer is x = -4

Answer:

x = 95°

Step-by-step explanation:

The sum of the interior angles of any polygon is

sum = 180° (n - 2)

Here n = 5, thus

sum = 180° × 3 = 540°

Sum the given angles in the polygon and equate to 540

104° + 117° + 100° + 124° + x = 540°, that is

445° + x = 540° ( subtract 445° from both sides )

x = 95°

What is the value of x?
3
6
10
12

Answers

Answer:

value of x is 6.

please follow me.

Your answer would be B- 6. Hope this helps you!!



What is the molar mass of UF6??

Answers

Answer:

I think it's 352. 02 g/mol

Step-by-step explanation:

googled it :)

Answer:

352.02 g/mol

In chemistry, the molar mass of a chemical compound is defined as the mass of a sample of that compound divided by the amount of substance in that sample, measured in moles.

Find a formula for the inverse of the function. f(x) = e^6x − 9

Answers

Answer:

[tex]f^{-1}(x)=\frac{1}{6}\ln(x+9)[/tex]

Step-by-step explanation:

So we have the function:

[tex]f(x)=e^{6x}-9[/tex]

To solve for the inverse of a function, change f(x) and x, change the f(x) to f⁻¹(x), and solve for it. Therefore:

[tex]x=e^{6f^{-1}(x)}-9[/tex]

Add 9 to both sides:

[tex]x+9=e^{6f^{-1}(x)}[/tex]

Take the natural log of both sides:

[tex]\ln(x+9)=\ln(e^{6f^{-1}(x)})[/tex]

The right side cancels:

[tex]\ln(x+9)=6f^{-1}(x)[/tex]

Divide both sides by 6:

[tex]f^{-1}(x)=\frac{1}{6}\ln(x+9)[/tex]

And we're done!

13w-8w =20 ??????????

Answers

Answer:

w = 4

Step-by-step explanation:

13w-8w =20

Combine like terms

5w = 20

Divide each side by 5

5w/5 = 20/5

w = 4

Answer:

w=4

Step-by-step explanation:

13w-8w=20

5w=20

w=4

The College of Business at Tech is planning to begin an online MBA program. The initial start-up cost for computing equipment, facilities, course development, and staff recruitment and development is $350,000.The college plans to charge tuition of $18,000 per student per year. However, the university administration will charge the college $12,000 per student for the first 100 students enrolled each year for administrative costs and its share of the tuition payments.
a. How many students does the college need to enroll in the first year to break even?
b. If the college can enroll 75 students the first year, how much profit will it make?
c. The college believes it can increase tuition to $24,000, but doing so would reduce enrollment to 35. Should the college consider doing this?

Answers

Answer:

a).To break even

They need to enroll 87 student

B) Profit=$100000

C) yeah they can think of that.

Profit= $70000

Step-by-step explanation:

Initial start up cost = $350000

Cost from adminstrative bodies

= 12000 for first 100 student

= $1200000

Total cost =$1200000+$350

Totral cost =$ 1550000

Tuition cost

= $18000 per student

To break even

The college needs to enroll

1550000/18000= 86.1

They need to enroll 87 student

B) if they enroll 75 students

Adminstrative cost = 12000*75

Adminstrative cost= 900000

Total cost= 350000+900000

Total cost =$ 1250000

Tuition fee= $18000*75

Tuition fee=$ 1350000

Their profit= 1350000-1250000

Profit=$100000

C).if tuition is $24000 and enrollment number= 35

Adminstrative cost = 35*12000

Adminstrative cost = $420000

Total cost= $770000

Tuition fee= $24000*35

Tuition fee= $840000

Profit= $840000-$770000

Profit= $70000

How do you do this question?

Answers

Step-by-step explanation:

F(x) = ∫ₐˣ t⁷ dt

F(x) is the area under f(t) between t=a and t=x.  When x=a, the width of the interval is 0, so the area is zero.

F(6) = 0, so a = 6.

F(x) = ∫₆ˣ t⁷ dt

F(6) = ∫₆⁶ t⁷ dt

F(6) = 0

Given the formula below, solve for x. y - y1 = m(x-x1)

Answers

Answer:

y-3 = 2/9 (x-8)

Step-by-step explanation:

Dimensional analysis: How many atoms are in a kilogram of silver, if there are 6.02 x 10^23 atoms per mole and silver weighs 107.9 grams/mole?

Answers

Answer:

5.58×10²⁴ atoms.

Step-by-step explanation:

From the question given above, the following data were obtained:

1 mole of silver = 107.9 g

Number of atoms in 1 mole of silver = 6.02×10²³ atoms.

Number of atoms in a kilogram of silver =.?

Next, we shall convert 1 kg of silver to grams (g). This can be obtained as follow:

1 kg = 1000g

Therefore, 1 kg of silver is equivalent to 1000g.

Finally, we shall determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:

107.9 g of silver contains 6.02×10²³ atoms.

Therefore, 1000 g of silver will contain = (1000 × 6.02×10²³) / 107.9 = 5.58×10²⁴ atoms.

Thus, a kilogram of silver contains 5.58×10²⁴ atoms.

Use the equation solver to find the value of x that makes the mathematical statement true. -0.5 0.5 0.87 1.5

Answers

Answer:-0.5

Step-by-step explanation:

Find the slope (-4,8) and (-3,-6)

Answers

Answer:

-14

Step-by-step explanation:

[tex] \boxed{gradient = \frac{y1 - y2}{x1 - x2} } [/tex]

Using the above formula, slope

[tex] = \frac{8 - ( - 6)}{ - 4 - ( -3 )} \\ = \frac{8 + 6}{ - 4 + 3} \\ = \frac{14}{ - 1} \\ = - 14[/tex]

1 mile to yards, as a fraction..

Answers

Answer:

[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

Since 3 feet is a yard, one foot is 1/3.

So that is the answer.

Answer:

1/3

1 mile to yards as a fraction would probably be 1/3. I'm not so sure...

Given the set A=(2,5) and B=(5,7,9) find the following: AnB
a
5
b
2.9
n
2,5,7,9
7,9
d

Answers

Greetings from Brasil....

The intersection of two sets is given by the elements that are common - present in both - to the sets.

A = {2; 5}

B = {5; 7; 9}

Element in both sets = 5.... So

A ∩ B = {5}

Is the expression (5 • 2) x equal to the expression 10 x

Answers

Answer:

Yes

Step-by-step explanation:

(5*2)x = 10x

5*2 = 10 so

10x = 10x

They are equal.

Answer:

Yes

Step-by-step explanation:

5 x 2 is 10, and so 5(2)x is 10x

How do you do this question?

Answers

Answer:

y' = -4eˣ sin⁵(eˣ)

Step-by-step explanation:

Part 1 of the Fundamental Theorem of Calculus simply says that the definite integral of a function is equal to the antiderivative evaluated between the limits.

∫ₐᵇ f(x) dx = F(b) − F(a), where F(x) = ∫ f(x) dx.

y = ∫ₑₓ⁰ 4 sin⁵(t) dt

To integrate, use Pythagorean identity.

y = 4 ∫ₑₓ⁰ (1 − cos²(t))² sin(t) dt

Ignoring the limits for the moment, let's say u = cos(t) and du = -sin(t) dt.

y = 4 ∫ (1 − u²)² (-du)

y = -4 ∫ (1 − 2u² + u⁴) du

y = -4 (u − ⅔u³ + ⅕u⁵) + C

y = -4 (cos(t) − ⅔ cos³(t) + ⅕ cos⁵(t)) + C

Evaluate between t = eˣ and t = 0.

y = -4 (cos(0) − ⅔ cos³(0) + ⅕ cos⁵(0)) + C − [-4 (cos(eˣ) − ⅔ cos³(eˣ) + ⅕ cos⁵(eˣ)) + C]

y = -4 (1 − ⅔ + ⅕) + 4 (cos(eˣ) − ⅔ cos³(eˣ) + ⅕ cos⁵(eˣ))

Now take derivative with respect to x.

y' = 0 + 4 (-sin(eˣ) eˣ − 2 cos²(eˣ) (-sin(eˣ) eˣ) + cos⁴(eˣ) (-sin(eˣ) eˣ))

y' = -4eˣ sin(eˣ) (1 − 2 cos²(eˣ) + cos⁴(eˣ))

y' = -4eˣ sin(eˣ) (1 − cos²(eˣ))²

y' = -4eˣ sin⁵(eˣ)

This can be more easily calculated using the Second Fundamental Theorem of Calculus.

Is 815 divisible by 10?

Answers

No.

Here is why:

If you mean equally divided then no because of the little 5 in the ones's place. If that 5 was a 0, it would definitely be divided equally.

Hope this makes sense!

Answer:

no

Step-by-step explanation:

How I do this?
3x+4y=11
X-2y=-3

Answers

Answer:

[tex]\huge\boxed{x=1,\ y=2\to(1,\ 2)}[/tex]

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}3x+4y=11\\x-2y=-3&\text{multiply both sides by (-3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}3x+4y=11\\-3x+6y=9\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\ \ \ \ 10y=20\qquad\text{divide both sides by 10}\\.\qquad\qquad\boxed{y=2}\\\\\text{subtitute it to the second equation:}\\x-2(2)=-3\\x-4=-3\qquad\text{add 4 to both sides}\\\boxed{x=1}[/tex]

Solve for u.
9u+16=7(u+2)
Simplify your answer as much as possible.
U=

Answers

Answer:

u=-1

Step-by-step explanation:

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

u= -1

3n-5=-8(6+5n) in distributive property

Answers

Answer:

n=-1

Step-by-step explanation:

3n-5=-8(6+5n)

3n-5=-48-40n

add 40n to both sides

43n-5=-48

n=-1

Step-by-step explanation:

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