Atom A will have a greater share of electrons and will have a slight negative charge according to Polar Covalent bond
What is Polar Covalent Bond ?
A specific type of covalent link is known as a polar bond. It is also the point at which an ionic bond and a pure covalent bond begin to form, according to another definition. A polar covalent bond, on the other hand, is a link that exists between two atoms and is made up of electrons that are scattered unevenly if we want to define it more precisely. The molecules have a tendency to have an electrical dipole moment in which the two ends are slightly positive or negative as a result of this state.
The many forms of covalent bonding are mostly determined by the electronegativity of the material. The propensity of an atom to draw a shared pair of electrons to itself is known as electronegativity. It is a trend and has no units. Polar covalent bonds are those created between two atoms in molecules with an electronegative difference.
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A 500 kg car is traveling Northbound towards Rosamond at a rate of 30 m/s. A 2000kg truck is traveling southbound toward LA at 25 m/s. What is the net momentum if North is the positive direction?
The net momentum if North is the positive direction is 20,000Kgm/s.
What is momentum?Momentum can simply be defined as the product of the mass of a particle and its velocity.
Momentum is a vector quantity that possesses a magnitude and a direction.
The Formula of momentum is given below:
Momentum, p = m * v
where;
m is the mass and v is the velocity of the body.
S.I. unit of momentum is kgm/s.
We have the given data as follows:
m1 = 500 kg
v1 = 30 m/s
m2 = 200 kg
v2= 25 m/s
Momentum = m1v1 + m2v2
= (500 * 30) + (200 * 25)
= 15000 + 5000
= 20,000 kgm/s
Momentum = 20,000Kgm/s.
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an empty graduated cylinder weighs 26.145 g when the cylinder contains 48.3 of an unknown liquid it weighs 65.055 g. what is the density of the unknown liquid? put answer in correct significant figures
The density of the unknown liquid 1.88kg/m³
The density of a liquid is a measure of how heavy it is for the amount measured and if you weigh equal amounts or volumes of two different liquids, the liquid that weighs more is more dense and if a liquid that is less dense than water is gently added to the surface of the water, it will float on the water
Here given data is cylinder weighs 26.145 g and when the cylinder contains 48.3 of an unknown liquid and it weighs 65.055 g then we have to find density of the unknown liquid = ?
So density = mass/volume
cylinder weighs + liquid weighs = 91.2g
Density = 91.2g/48.3
Density = 1.88kg/m³
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Sierra Charter School:
Part 3 Directions: Watch the video: How to calculate Oxidation Numbers Intro Video and take notes throughout the video here and from those notes, write a summary.
An oxidation number is a number assigned to an atom that allows chemists to keep track of how many electrons are available for transfer and whether a particular reactant is being oxidized or reduced in a reaction.
Determine if the substance in question is an element. An unbonded free atom always has an oxidation number of 0. An oxidation number is a number assigned to a compound or element to indicate the number of electrons that have been lost or gained. A negative number indicates that an electron was gained and a positive number indicates that an electron was lost.
Determine if the substance in question is an ion. Aeon has an oxidation number corresponding to the charge. This applies to both ions that are not bonded to other elements and ions, which are part of the ionic compound. The oxidation number explains the ability of elements or compounds that provides or obtain electrons during a chemical reaction.
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How many grams of Fe2O3 can form from 22.4g of O2
74.5 gram of Fe₂O₃ is formed from 22.4 g of O2
The balanced equation of the reaction is
4 Fe + 3 O₂ → 2 Fe₂O₃
4 moles of Fe and 3 moles of O₂ gives 2 moles of Fe₂O₃
Number of moles in 22.4g of O₂ = Given mass / molar mass [Molar mass of O₂ = 32]
= 22.4 / 32
= 0.7 moles
We know that, 3 moles of oxygen form 2 moles of Fe₂O₃
0.7 moles of O₂ form [(2/3) * 0.7] = 0.47 moles of Fe₂O₃
Thus, mass of Fe₂O₃ = number of moles * molar mass [Molar mass of Fe₂O₃ = 159.69]
= 0.47 * 159.69
= 74.5 grams of Fe₂O₃
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Can water stay liquid below zero degrees Celsius?
Water cannot stay liquid below zero degree Celsius (0°C) because it freezes at 0°C.
What is freezing point?Freezing point is the temperature at which a liquid freezes, and the solid and liquid phases are in equilibrium.
Different liquids have different freezing points. Water as a liquid has a freezing point of 0 °C. This means that water in a liquid state will begin to turn solid (ice) at that temperature.
For example;
Ethanol has a freezing point of -114.1 °CMercury has a freezing point of -38.83 °CIn accordance with this question, water cannot stay liquid below a temperature of 0°C because it has a freezing point of 0°C.
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What electrons participate in chemical bonding?
Answer:
valence electrons
Explanation:
they are the electrons that are in the outermost shell
Which of the following is an example of water in a liquid state?
A. ice
B. Steam
C. Snow
D. Rain
i need help with chemistry equation
Answer:
12.1 grams and 77.8%
Explanation:
(Note: in this answer, sig figs are rounded in the end, not along the way) The molar ratio of calcium sulfate to calcium hydroxide is 1:1
there are 6.56 grams of calcium hydroxide, so the number of moles is the number of grams / the molar mass, which is (6.56 grams) / (74.093 g/mole)
=0.08854 moles of calcium hydroxide
Theoretically, 0.08854 moles of calcium hydroxide would make 0.08854 moles of calcium sulfate.
To find the number of grams of calcium sulfate, multiply the number of moles by the molar mass, which is .08854 * 136.14 = 12.054 grams, or
12.05 grams
The percentage yield of calcium sulfate is just the actual yield / predicted yield, which is 9.37/12.05 which is 0.7776, or 77.8%
Following the procedure of this experiment, you determined that your 1.000g sample of a fruit drink powder contained 6.04E-5 moles of acidic protons. Of these acidic protons, 2.00E-5 moles were due to VC. The rest were due to an acid H2B in the sample. Calculate: a) Moles of acidic protons due to H2B in the fruit drink sample b) Moles of H2B in the fruit drink sample
a.) 4.04E-5 moles of acidic protons
b.) 2.02E-5 mole of H2B in the fruit drink
What are protons?A proton can be defined as a stable subatomic particle with symbol p , H⁺, or ¹H⁺ that has a positive electric charge of +1 e elementary charge.
The mole with its symbol mol, is the unit of amount of substance in the International System of Units. The quantity amount of substance is a measure of how many elementary entities of a given substance are in an object or sample.
The formula for the number of moles formula is expressed as follows;
Number of moles = Mass of substance / Mass of one mole.
n = m/M
from the given above, we have that
mass of sample = 1.00g
a.) Moles of acidic protons due to H2B in the fruit drink sample will be
6.04E-5 moles of acidic protons - 2.00E-5 moles were due to VC
= 4.04E-5 moles of acidic protons.
b.) Moles of H2B in the fruit drink sample = 2.02E-5 mole of H2B in the fruit drink
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(02.03 LC)
Which physical evidence supports the evolution of Earth due to deposition?
Concave shape of Wave Rock is the physical evidence that supports the evolution of Earth due to deposition.
Concave shape of Wave RockThe concave shape of Wave Rock is nice physical evidence of deposition in the Earth's evolution. It is a 2.7-billion-year-old land structure that served as the foundation for the formation of the Australian continent.
What is Wave Rock?A naturally occurring rock formation that resembles a tall, breaking ocean wave is called Wave Rock. The "wave" is roughly 110 m (360 ft) long and 15 m (49 ft) tall. It makes up the north side of the isolated hill known as "Hyden Rock."
Since Wave Rock is made of much tougher material from its surroundings, the weathering lowered the surrounding terrain while the bedrock remained to serve as a witness for the past.
The structure of Wave Rock was created by the weathering of the surrounding area, and this is exactly what proves the deposition part. Wave Rock was below the ground because of the deposition of the material around it over time.
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Complete Question
Which physical evidence supports the evolution of Earth due to deposition?
A) Red color of Thor's Hammer
B) Concave shape of Wave Rock
C) Streaks on the face of Wave Rock
D) Broader tip than base of Thor's Hammer
I need help understanding this is not a test but study material
Explanation:
The law of conservation of mass:
In a chemical reaction, the mass is neither created nor destroyed. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.
------------------
According to this task, the statement that demonstrates the law of conservation of mass is:
Answer: there are 10 aluminum (Al) atoms represented on each side of the equation.
Avogadro's number is the number of
Avogadro's number is number of elementary entities (atoms or molecules) comprising one mole of a given substance.
What is the Avogadro's number?Avogadro's number is the number of atoms present in 12 grams of isotopically pure carbon-12, being 6.02214076 × 10²³.
It is the number of elementary entities (atoms or molecules) comprising one mole of a given substance.
The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction.
Therefore, it can be simply said that Avogadro's number is the number of units in one mole of a substance.
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helppppppppppddjeoeps
Answer:
D.) mole, 6.022 x 10²³
Explanation:
Avogadro's Number is a ratio which states that there are 6.022 x 10²³ particles per every one mole.
Arrange these acids according to their expected pKą values. (Highest to lowest)
CH₂CH₂COOH
CI2CHCOOH
CICH₂COOH
CICH₂CH₂COOH
A 9.6 g object is placed in a graduatedcylinder displacing the volume from 10.0 mLto 13.2 mL.The volume of this object is 3.2 mL.What is its density in g/mL?Round your answer to the appropriatenumber of significant figures.[?] g/mL
ANSWER
T
EXPLANATION
Given that;
The mass of the object is 9.6 grams
The volume of the object is 3.2mL
Follow the steps below to find the density of the object
[tex]\text{ Density = }\frac{\text{ mass}}{\text{ volume}}[/tex]Substitute the given data into the formula above
Convert the volume of the object to cm^3
Recall, that 1mL is equivalent to 1cm^3
Hence, 3.2mL is 3.2 cm^3
[tex]\begin{gathered} \text{ Density= }\frac{\text{ 9.6}}{\text{ 3.2}} \\ \text{ Density = 3.00g/cm}^3 \end{gathered}[/tex]Therefore, the density of the object is 3.00 g/mL
balance the equation c3h8o3+o2- co2+h2o
Balanced equation of C3H8O3 + O2 = CO2 + H2O is 2C3H8O3 + 7O2 → 6CO2 + 8H2O
How To Balance C3H8O3 + O2 = CO2 + H2O ?
Balance the equation C3H8O3 + O2 = CO2 + H2O using the algebraic method.
Label Each Compound With a VariableaC3H8O3 + bO2 = cCO2 + dH2O
Create a System of EquationsC: 3a + 0b = 1c + 0d
H: 8a + 0b = 0c + 2d
O: 3a + 2b = 2c + 1d
Use substitution, gauss elimination3a - 1c = 0
8a - 2d = 0
3a + 2b - 2c - 1d = 0
Simplify the result to get the lowest, whole integer values.a = 2 (C3H8O3)
b = 7 (O2)
c = 6 (CO2)
d = 8 (H2O)
Substitute Coefficients and Verify Result2C3H8O3 + 7O2 = 6CO2 + 8H2O
Reactants Products
C 6 6
H 16 16
O 20 20
Since there is an equal number of each element in the reactants and products of 2C3H8O3 + 7O2 = 6CO2 + 8H2O, the equation is balanced.
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describe how to use Le Chateliers principle to predict the possible ways a chemical system can respond to changes
According to Le Châtelier's principle, if a dynamic equilibrium is disturbed by changing the conditions, the equilibrium position will move to compensate for the change and restore the equilibrium.
What is meant by Le Chatelier's Principle?Le Chatelier's Principle states that "a system at equilibrium will modify itself in such a way to minimize the effect of that change made in it" when external stress is applied by changing concentration, pressure, or temperature.
Change in Concentration:
A + B ⇆ C
In order to counteract the impact of the additional reactant added, the equilibrium will shift forward and produce more product when the concentration of reactants (A or B) is increased. Or it will react in the opposite way if product (C) is added.
Change in Pressure:
A + B ⇆ C
Because there is a decrease in volume at the product side, if pressure is applied to this equilibrium, the equilibrium will shift in the direction of forwarding motion (1 mole as compared to reactants which are 2 moles). If the pressure drops, the opposite situation will be seen.
Change in Temperature:
A + B ⇆ C + Heat
The heat produced in this exothermic reaction (heat is evolved) is on the product side. The equilibrium will shift in the opposite direction as the temperature rises. A drop in temperature will cause the equilibrium to move forward.
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A chemist reacts 10.5 g of Ag with 7.5 g of s in the reaction from the previous question what is the percent yield of a chemist actually obtains 9.8 g of ag2s
If 10.5 g of Ag and 7.5 g of S are reacted and 9.8 g of [tex]Ag_2S[/tex] is obtained, the percent yield of the reaction would be 81.4%
Percent yieldAg and S react to form [tex]Ag_2S[/tex] as follows:
[tex]2Ag + S -- > Ag_2S[/tex]
The mole ratio of Ag to S is 2:1.
10.5 g of Ag = 10.5/108
= 0.0972 moles
7.5 g of S = 7.5/32
= 0.2344 moles
In other words, Ag is limiting in availability.
The mole ratio of Ag to [tex]Ag_2S[/tex] = 2:1
0.0972 Ag is equivalent to 0.0972/2 = 0.0486 moles of [tex]Ag_2S[/tex]
0.0486 moles [tex]Ag_2S[/tex] weighs = 0.0486 x 247.8
= 12.04 grams
percent yield of [tex]Ag_2S[/tex] = 9.8/12.04 x 100%
= 81.4%
The percent yield of [tex]Ag_2S[/tex] that the chemist actually obtained is 81.4%.
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A certain reaction has an activation energy of 36.11 kJ/mol.
At what Kelvin temperature will the reaction proceed 4.50
times faster than it did at 315 K?
Kelvin temperature will the reaction proceed 4.50 times faster than it did at 315 K is 293K
Temperature is the degree of hotness or coldness of an object
Here given data is certain reaction has an activation energy of 36.11 kJ/mol and reaction proceed 4.50 times faster than it did at 315 K and we have to find kelvin temperature = ?
Then, we have to use the arrhenius equation and set k1 = 1 and k2 = 4.50 because rate = k[A] so as long as concentration of reactants doesn't vary, rate is proportional to k
ln (k₂/k₁) = Ea/R(1/T₁ - 1/T₂)
k₂ = 4.50
k₁ = 1
Ea = 36.11 J/mole
R = 8.314 J/mol⁻k
T ₁= 315 K
T₂ = ?
ln(4.50/1) = 36.11/8.314 (1/314 - 1/T₂)
1.50 = 4.343 (1/315 - 1/T₂)
1.50 = 0.013 - 4.343/T₂
-1.48 = - 4.343/T₂
T₂ = 293 K
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Using the equations
-
N₂ (g) + 3 H2 (g) → 2 NH3 (g) AH = -91.8 kJ/mol
C(s) + 2 H₂ (g) → CH4 (g) AH° = -74.9 kJ/mol
H₂ (g) + 2 C(s) + N₂ (g) → 2 HCN (g) AH° = 270.3 kJ/mol
Determine the enthalpy (in kJ/mol) for the reaction
CH4 (g) + NH3 (g) → HCN (g) + 3 H₂ (g).
According to the given data The enthalpy for the reaction, ΔH rxn is 255.95 kJ/mol.
What is enthalpy ?Enthalpy is a characteristic or state function which resembles energy; it has the same dimensions as energy and is thus measured in joules or ergs. The value of enthalpy is entirely determined by the temperature, pressure, and content of the system, not on the history.
Briefing:Calculate the change in enthalpy for the reaction
CH₄(g) + NH₃(g) → HCN(g) +3H₂(g)
From the given reactions
Reaction 1: N₂(g) + 3H₂(g) → 2NH₃(g) Change in enthalpy: -91.8 kJ/mol
Reaction 2: C(s, graphite) + 2H₂(g) → CH₄(g) Change in enthalpy: -74.9 kJ/mol
Reaction 3: H₂(g) +2C(s, graphite) +N₂(g) → 2HCN (g) Change in enthalpy: +270.3 kJ/mol
Reactions 1 and 2 to get reaction 4 and 5 respectively
Reaction 4: 2NH₃(g) → N₂(g) + 3H₂(g) ΔHo : 91.8 kJ/mol
Reaction 5: CH₄(g) → C(s, graphite) + 2H₂(g) ΔHo : 74.9 kJ/mol
Now, multiply reactions 4 and 3 by half (1/2) to get 6 and 7 respectively
Reaction 6: NH₃(g) → ¹/₂N₂(g) + ³/₂H₂(g) ΔHo : 45.9 kJ/mol
Reaction 7: ¹/₂H₂(g) +C(s, graphite) +¹/₂N₂(g) → HCN (g) ΔHo : +135.15 kJ/mol
Now,
Add reactions 5, 6, and 7 together
Reaction 5: CH₄(g) → C(s, graphite) + 2H₂(g) ΔHo : 74.9 kJ/mol
Reaction 6: NH₃(g) → ¹/₂N₂(g) + ³/₂H₂(g) ΔHo : 45.9 kJ/mol
Reaction 7: ¹/₂H₂(g) +C(s, graphite) +¹/₂N₂(g) → HCN(g) ΔHo : +135.15 kJ/mol
----------------------------------------------------------------------------------------------------------
CH₄(g) + NH₃(g) → HCN(g) + 3H₂(g) ΔH rxn = 255.95 kJ/mol
The enthalpy for the reaction, ΔH rxn is 255.95 kJ/mol
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How many grams of copper(II) chloride are needed to produce 42.8 g copper(II) phosphate in the presence of excess sodium phosphate?
Taking into account the reaction stoichiometry, 45.35 grams of copper(II) chloride are needed to produce 42.8 g copper(II) phosphate in the presence of excess sodium phosphate.
Reaction stoichiometryIn first place, the balanced reaction is:
3 CuCl₂ + 2 Na₃PO₄ → Cu₃(PO₄)₂ + 6 NaCl
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
CuCl₂: 3 molesNa₃PO₄: 2 molesCu₃(PO₄)₂: 1 moleNaCl: 6 molesThe molar mass of the compounds is:
CuCl₂: 134.44 g/moleNa₃PO₄: 164 g/moleCu₃(PO₄)₂: 380.62 g/moleNaCl: 58.44 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
CuCl₂: 3 moles ×134.44 g/mole= 403.32 gramsNa₃PO₄: 2 moles ×164 g/mole= 328 gramsCu₃(PO₄)₂: 1 mole ×380.62 g/mole= 380.62 gramsNaCl: 6 moles ×58.44 g/mole= 350.64 gramsMass of CuCl₂ requiredThe following rule of three can be applied: if by reaction stoichiometry 380.62 grams of Cu₃(PO₄)₂ are produced by 403.32 grams of CuCl₂, 42.8 grams of Cu₃(PO₄)₂ are produced by how much mass of CuCl₂?
mass of CuCl₂= (42.8 grams of Cu₃(PO₄)₂× 403.32 grams of CuCl₂) ÷380.62 grams of Cu₃(PO₄)₂
mass of CuCl₂= 45.35 grams
Finally, 45.35 grams of CuCl₂ is required to produce 42.8 g copper(II) phosphate.
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Carbon disulfide (CS2) reacts with excess chlorine (Cl2) to produce carbon tetrachloride (CCl4) and disulfur dichloride (S2Cl2). If 73.5 g of CS2 yields 86.3 g of CCl4, what is the percent yield?
The percent yield is 85.16%
Percent yield is the percent ratio of the weight of the product obtained to the theoretical yield and we calculate the percent yield by dividing the experimental yield by the theoretical yield and multiplying the result by 100 to express the final answer in %
Here given data is carbon disulfide (CS₂) reacts with excess chlorine (Cl₂) to produce carbon tetrachloride (CCl₄) and disulfur dichloride (S₂Cl₂) if 73.5 g of CS₂ yields 86.3 g of CCl₄ means reaction is
CS₂ + Cl₂ → CCl₄ + S₂Cl₂
And here weight are given CS₂ = 73.5 g and CCl₄ = 86.3 g
So, % yield = ratio of the weight
% yield = 73.5 g/86.3 g×100
% yield = 85.16%
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Fill in the blank.
7.95×10^7 = [?]×10^6
Answer: 79.5
Explanation: Every positive exponent moves the decimal one place to the right. So if you are multiplying by one less decimal to get the same answer your starting number would have to be one place greater to the right.
If your exponents are negative numbers the decimal moves one place per each number to the left. You'll learn that later. Math is a blast! Enjoy it!
Is this the right answer to this question....?
Which of these is an example of active transport?
A: Transport of Na+ from a place of low concentration to a place of higher concentration
Transport of Na+ from a place of low concentration to a place of higher concentration. This is the right answer.
The sodium-potassium pump is the most common and well-known example of active transport. At the cell membrane, the sodium-potassium pump moves 3 sodium ions out of the cell and two potassium ions into the cell per ATP. Examples of active transport include the uptake of glucose in the human intestine and the uptake of minerals and ions into the root hair cells of plants.
One of the greatest examples of active transport is the movement of calcium ions out of cardiomyocytes. Cells secrete proteins such as enzymes, antibodies, and various other peptide hormones. Amino acids are transported across the intestinal mucosa of the human intestine. The movement of ions or molecules across cell membranes to regions of a higher concentration is assisted by enzymes and requires energy.
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what is percentage of volume of a phenol (c6,h5,oh) in a solution containing of 25.5ml of phenol in 495ml of ethanol (ch3,ch2,oh)?
Molecular mass of Phenol = 94 g/mol
Ethanol = 46 g/mol
Weight of Phenol Taken = 25.5 g
Ethanol = 495 g
Total Weight = 495 + 25.5 = 520.5 g
So moles of phenol = 25.5 94 = 0.27
mole of ethanol = 495 / 46 = 10.76
1. Mole fraction of phenol = 0.27 / (10.76 + 0.27) = 0.27 / 11.03 = 0.0244
2. Mass % of phenol = mass of phenol / total mass x 100
25.5 / x 10.5 = 4.9 %
3. Molar concentration of phenol = mol Phenol/mass of solvent (kg)
the solvent is ethanol => Because presents an exceedingly high amount
0.27 / 495 X 1000 m = 0.54m
4. Molarity = moles of phenol/ vol of solution (in liter)
Density of solution = 0.938 g/mL 44
Mass of solution = 520.5 g
Volume of Solution = Mass / Density = 520.5 / 0.938 = 554.9 or 555 ml
Molarity = (0.27 / 555)X 1000 = 0.48 M.
Phenol has unique properties and is not classified as alcohol. They are highly acidic because the aromatic ring is tightly bound to oxygen and the bond between oxygen and hydrogen is relatively loose.
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Why does adding elements such as carbon to flexible metals make the material stronger?
Answer: Carbon strengthens iron by distorting its crystal lattice. This distortion is similar in effect to work hardening.
which species has 18 electrons
Answer:
Argon - Ar has 18 electrons
An ion that has 18 electrons is a potassium ion.
Hope this helps!
Explanation:
i need help with chemistry equation
From the mole ratio and the masses of reactants:
The maximum amount in grams of ammonia (NH₃ ) that can be formed is 2.83 gThe formula of the limiting reagent is N₂.The amount of the excess reagent that remains after the reaction is complete is 3.65 grams.What is the maximum amount of the product that can be formed?The maximum amount of the product that can be formed is calculated from the equation of reaction as follows:
3H₂ (g) + N₂ (g) ---> NH₃ (g)The mole ratio of hydrogen to nitrogen is 3 : 1
From the given data:
4.67 grams of hydrogen gas are allowed to react with 4.67 grams of nitrogen.
The moles of the reactants is determined as follows:
Moles of hydrogen = 4.65/2 = 2.325 moles
Moles of nitrogen = 4.67/28 = 0.1667 moles
Hence, the limiting reagent is nitrogen while the excess reagent is hydrogen.
The maximum moles of ammonia (NH₃ ) that can be formed = 0.1667 moles.
mass of ammonia formed = 0.1667 * 17 grams
mass of ammonia formed = 2.83 g
The moles of the excess reagent remaining after the reaction is complete = 2.325 - (0.1667 * 3) = 1.825
moles of the excess reagent remaining = 1.835 moles
mass of the excess reagent remaining = 1.825 * 2
mass of the excess reagent remaining = 3.65 grams
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Balance the following Equation:
A LI₂CO3 (s) + B HCI (aq) -> C LICI (aq) + D H₂O (1) + E CO₂ (g)
a) A = 1; B = 1; C = 1; D = 1; E = 1
b) A= 1; B = 1; C = 2, D = 1; E = 1
c) A= 1, B2, C = 2; D = 1; E = 1
d) A=2; B = 1;, C = 1; D = 2; E = 1
Answer:
C is the answer
Explanation:
Li2CO3 + HCl - - - - - - -> LiCl + H2O + CO2
Li. Li. H. Li. H. H. C
C Cl. Cl. O. O. O
O. O. O
2 Li ------>1Li so we put 2 in front LiCl on the right side to make 2Li---->2Li.
1H------->2H so we put 2 in front HCl on left side to make
Li2CO3 + 2HCl - - - - - - -> 2LiCl + H2O + CO2
Cl₂(g) + F₂(g) 2CIF(g)
Draw Lewis structures for all reactant and product molecules.
Lewis structures for all reactant and product molecules and the show the bonding relationship between atoms of a molecule and the lone pairs of electrons in the molecule
Lewis structure for the reactants and product molecules can be drawn by following the octet rule and considering covalent bonding between the bonded atoms
Here given reaction is
Cl₂(g) + F₂(g) → 2CIF(g)
And lewis structure of reactant means Cl₂(g) + F₂(g) in Cl₂(g) one chlrine has three lone pair attached and another clorine also three lone pair attached whereas F₂(g) also has three pair of lone pair are attached and product means CIF(g) has Cl has three lone pair and F also has three lone pair attached
Lewis structures for all reactant and product molecules are given below
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