5-2y+7y-2-1
It’s needs to be simplified

Answer:

625

Step-by-step explanation:

so we do 500/ 0.6 = 625

Answer:

1 6611/12500

Step-by-step explanation:

1 is the whole number and 6611/12500 is in simplest form :)

Answer:

10 centimeters, I think.

Step-by-step explanation:

Answer:

527 cubic meters

Step-by-step explanation:

The area of the cube would be 7.5^3 and the area of the rectangular prism would be 3.75*3.75*7.5. Then it would be 421.9 + 105.5 and rounded to the whole number the answer would be 527

Answer:

D.68 is greater than 112 because 68 is greater than the benchmark 12, and 112 is less than the benchmark 12.

Her annual property insurance premium is $673.50.

Option A is the correct answer.

Insurance is a means of protection from financial loss in which, in exchange for a fee, a party agrees to compensate another party in the event of a certain loss, damage, or injury. It is a form of risk management, primarily used to hedge against the risk of a contingent or uncertain loss.

here,

We have,

To calculate Sheila annual property insurance premium, we need to determine the appropriate rating based on the type of house and the area where it is located. Aida's house is a brick house in the country,

So we need to use the "Brick" and "Rural" ratings from the table.

The rating for the building is 0.6 per $100 of coverage, so for a value of $95,000, the premium for the building is:

0.6 x $950 = $570

The rating for the contents is 0.69 per $100 of coverage, so for a value of $15,000, the premium for the contents is:

0.69 x $150 = $103.50

The total annual premium is:

$570 + $103.50 = $673.50

Thus,

Her annual property insurance premium is $673.50.

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Answer: 17,160 feet

Step-by-step explanation:

Because I mile = 5280 feet, 3 and 1/4 miles = 3.25 x 5280 = 17160 feet

Answer:

(x+3)

2

=43

BY TAKING SQUARE ROOT ON BOTH SIDES

x + 3 = \sqrt{43}x+3=

43

OR

x + 3 = - \sqrt{43}x+3=−

43

THUS

x = \sqrt{43} - 3x=

43

−3

OR

x = - \sqrt{43} - 3x=−

43

−3

THIS QUADRATIC EQUATION HAS 2 SOLUTIONS SINCE √43 CAN BE A POSITIVE OR A NEGATIVE INTEGER. FOR EXAMPLE, 2^2=4

BUT, (-2)^2=4 Thus. √4=2 or (-2)

After this. Simply shifting the 3 on the LHS to keep 'x' on one side to find its value.

Taking the square root of both sides of the equation (x + 3)² = 43 will result in two solutions for x.

The correct option is C.

A basic quadratic equation, or a second-order polynomial equation with a single variable, is represented by the equation x : ax² + bx + c = 0, where a≠0 for the variable x. As it is a second-order polynomial equation, which is ensured by the algebraic fundamental theorem, it must have at least one solution.

When taking the square root of both sides of the equation (x + 3)² = 43, we get:

x + 3 = ±√43

To solve for x, we can subtract 3 from both sides:

x = -3 ±√43

So there are two solutions for x:

x = -3 + √43

x = -3 - √43

Therefore, the solutions are x = -3 + √43 and x = -3 - √43.

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Answer:

10

For this case what we must do is a division using the following relationship:

Substituting values we have:

Rewriting the fraction we have:

Simplifying we have:

Answer:

The number of times repeated 2/5 for 4 is:

10

Answer: think your not stups ur smart

Step-by-step explanation:

Answer:

I think they should be taught first so that later on they can use it, and also just in case they forget to know how to multiply or divide they can sorta use addition and subtract for it.

Another reason is that it is easier and since they are teaching it to younger kids it would be helpful to start off a bit easy.

Step-by-step explanation:

I hope it helps, sorry if it doesn’t!

Muffin<3

[tex]\boxed{y}=\cfrac{1}{2}x-4\\\\ y=-2x+1 \end{cases}\qquad \qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{\stackrel{\boxed{y}}{\cfrac{1}{2}x-4}~~ = ~~-2x+1} \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left( \cfrac{1}{2}x-4 \right)~~ = ~~2(-2x+1)}\implies x-8=-4x+2\implies 5x-8=2[/tex]

[tex]5x=10\implies x=\cfrac{10}{5}\implies \blacktriangleright x=2 \blacktriangleleft \\\\\\ \stackrel{\textit{we know that}}{y==\cfrac{1}{2}x-4}\implies y=\cfrac{1}{2}(2)-4\implies \blacktriangleright y = -3 \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (2~~,~~-3)~\hfill[/tex]

[tex]\\ \tt\longrightarrow y+2>5[/tex]

[tex]\\ \tt\longrightarrow y>5-2[/tex]

[tex]\\ \tt\longrightarrow y>3[/tex]

[tex]\\ \tt\longrightarrow y\in (3,\infty)[/tex]

Graph attached

Answer:

see attached diagram

Step-by-step explanation:

y + 2 > 5

Subtract 2 from both sides:

⇒ y > 3

Graphing inequalities

< or > : dashed line to show that the line is not included in the region.

≤ or ≥ : solid line to show that the line is included in the region.

Draw a horizontal dashed line at y = 3 and shade above the line.

Number line

≤ or ≥ : closed circle

< or > : open circle

Draw an open circle at 3 and shade to the right.

Answer:

13 is a solution.

Step-by-step explanation:

[tex]7w = 94 \\ \frac{7w}{7} = \frac{94}{7} \\ w = 13.42 \\ [/tex]

13.42 ≈ 13

Answer:

The revenue equation  is y=2.6x,

cost equation is y=x+2000

When the company makes profit only when  revenue > cost

Lets frame inequality using revenue > cost

Replace the revenue equation and cost equation

Now solve the inequality for x

Subtract 1x from both sides

Divide both sides by 1.6

The company makes profit when x is greater than 1250

Step-by-step explanation:

Answer:

Greater than 1250

x > 1250

Step-by-step explanation:

Base on  the revenue equation and cost equation , we can infer that the company make a profit when x > 1250

Important Given Information:

The revenue equation  is [tex]y=2.6x[/tex]

Cost equation is [tex]y = x+2000[/tex]

When the company makes profit only when: [tex]revenue > cost[/tex]

Let's frame inequality using: [tex]revenue > cost[/tex]

Replace the revenue equation and cost equation

[tex]Revenue > Cost: 2.6x > + 2000[/tex]

Now Let's solve the inequality for x

[tex]2.6x > 1x + 2000[/tex]

[tex]2.6x - 1x > 2000[/tex]        [tex][2.6x-1x=1.6x][/tex]

[tex]1.6x > 2000[/tex]

Divide both sides by 1.6 ( what you do on one side do to the other)

[tex]\frac{1.6x}{1.6}=\frac{2000}{1.6}[/tex]

[tex]x >1250[/tex]

Hence, the company makes profit when x is greater than 1250

[RevyBreeze]

Answer:

It would be m = -2

Step-by-step explanation:

For this line slope would be negative because it is going down. It is going 2 down 1 across. Since it is rise over run it would be -2/1.

Answer:

4/5x + 7

Step-by-step explanation:

the slope-intercept form is y = ax+b

a is the slope, to figure it out the line is perpendicular to y = -5/4x+11/4

There is a rule said if two lines are perpendiculars, the multiplication of their slopes = -1, so -5/4 * a = 1, solve for a = 4/5

b is the intercept to get it use the point (0,7)

so y = 4/5x+b, 7 = 4/5 * 0 + b,  then b = 7

Answer: The slope would be 2/3. The parallel slope would be 2/3. the parallel intercept is -4

Step-by-step explanation: I how this helps!

Answer:

$7.25 + $4.25 + 6.00 = $17.50

Step-by-step explanation:

7.25 + 4.25= 11.50 + 6.00= 17.50

Answer:

13 quarters must be tails.

Step-by-step explanation:

Number of quarters = 40% of 50 coins

Number of quarters = 40/100 * 50 = 20 coins which are quarters.

35% of these 20 quarters on heads. We can proceed in 2 ways from here.

We can actually find the number of quarters that are on heads.

35/100 * 20 = 7 quarters are showing heads.

Since the other quarters must be tails 20 - 7 = 13 quarters must be tails.

The other way to do it is to realize that if 35% of the coins are heads, 65% of the coins must be tails 20 * 65/100 = 13 which is a bit more direct.

Answer:

B

Step-by-step explanation:

First you put that then multiply inside of that then you cross over percent than boom there's your awnser your welcome

The inequality that represents all values of x for which the product  is defined is x ≥ 0

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. It is used most often to compare two numbers on the number line by their size.

Given is an expression, we need to determine the all values of x for which the product is defined,

The product is √4x · √x+2

We must meet both conditions:

(4x) ≥ 0 and (x+2) ≥ 0

So, 4x ≥ 0

x ≥ 0

And,   x ≥ -2 [subtract 2 from both sides.]

So, we can say the condition should be x ≥ 0

Hence, the inequality that represents all values of x for which the product  is defined is x ≥ 0

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Answer:

Please see the analysis

The p-value that would be associated with the two-tail hypothesis test is 0.03.

A statistical hypothesis test is a method of statistical inference used to decide whether the data at hand sufficiently support a particular hypothesis. Hypothesis testing allows us to make probabilistic statements about population parameters.

The mean will be 2.587

The standard deviation will be 0.467

By two tail test,

The p-value is 0.03

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Step-by-step explanation:

similar triangles.

all angles are the same in both triangles.

and the ratio of the lengths of a pair of corresponding sides in both triangles is the same for all corresponding side pairs.

so,

21 / 1.4 = height / 1 = height = 15

the building is 15.00 meters tall.

Answer:

See below for all the cube roots

Step-by-step explanation:

DeMoivre's Theorem

Let [tex]z=r(cos\theta+isin\theta)[/tex] be a complex number in polar form, where [tex]n[/tex] is an integer and [tex]n\geq1[/tex]. If [tex]z^n=r^n(cos\theta+isin\theta)^n[/tex], then [tex]z^n=r^n(cos(n\theta)+isin(n\theta))[/tex].

Nth Root of a Complex Number

If [tex]n[/tex] is any positive integer, the nth roots of [tex]z=rcis\theta[/tex] are given by [tex]\sqrt[n]{rcis\theta}=(rcis\theta)^{\frac{1}{n}}[/tex] where the nth roots are found with the formulas:

for  [tex]k=0,1,2,...\:,n-1[/tex]

Calculation

[tex]z=27(cos330^\circ+isin330^\circ)\\\\\sqrt[3]{z} =\sqrt[3]{27(cos330^\circ+isin330^\circ)}\\\\z^{\frac{1}{3}} =(27(cos330^\circ+isin330^\circ))^{\frac{1}{3}}\\\\z^{\frac{1}{3}} =27^{\frac{1}{3}}(cos(\frac{1}{3}\cdot330^\circ)+isin(\frac{1}{3}\cdot330^\circ))\\\\z^{\frac{1}{3}} =3(cos110^\circ+isin110^\circ)[/tex]

First cube root where k=2

[tex]\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(2)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ+720^\circ}{3})\biggr]\\3\biggr[cis(\frac{1050^\circ}{3})\biggr]\\3\biggr[cis(350^\circ)\biggr]\\3\biggr[cos(350^\circ)+isin(350^\circ)\biggr][/tex]

Second cube root where k=1

[tex]\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(1)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ+360^\circ}{3})\biggr]\\3\biggr[cis(\frac{690^\circ}{3})\biggr]\\3\biggr[cis(230^\circ)\biggr]\\3\biggr[cos(230^\circ)+isin(230^\circ)\biggr][/tex]

Third cube root where k=0

[tex]\sqrt[3]{27}\biggr[cis(\frac{330^\circ+360^\circ(0)}{3})\biggr]\\3\biggr[cis(\frac{330^\circ}{3})\biggr]\\3\biggr[cis(110^\circ)\biggr]\\3\biggr[cos(110^\circ)+isin(110^\circ)\biggr][/tex]

Answer:

How to find the area in terms of pi?

Answer: First divide the circumference by Pi to give the diameter of the circle (27 divided by 3.14 = 8.59...). Now halve the diameter to give the radius (8.59 divided by 2 is 4.29...). Now use Pi*r^2 to find the area of the circle (Pi times 4.29^2 = 58.0 cm^2 to 1 decimal place)

Step-by-step explanation: