Answers
Step-by-step explanation:
12. n^2+2n
if you insert 1 for k and then work up by inserting 2 for k and adding those together and stoping at n.
13. 8-2(2^n)
if you insert 3 for k and then work up by inserting 4 for k and adding those together and keep on going but stopping at n.
Hope that helps :)
Related Questions
Does anyone know number 1 and 2 if so pls help!
Answers
Answer:
364×180=65,520 baskets
Step-by-step explanation:
since its a leap year(4days as shown in the document)
2nd question:
365×180=65,700 baskets
since its not a leap year
if u dont know leap years end with an even number which is 364 and non leap years end with odd number which is 365.
[tex]2v^{2} +14=104[/tex]
Answers
Step-by-step explanation:
[tex]2 {v}^{2} + 14 = 104 \\ 2 {v}^{2} = 104 - 14 \\ 2 {v}^{2} = 90 \\ {v}^{2} = 90 \div 2 \\ {v}^{2} = 45 \\ v = \sqrt{45} [/tex]
I will leave the answer in square root form as i am not sure if you need to round your answer or not.
Perform these steps: 1. State the hypotheses and identify the claim. 2. Find the critical value(s) 3. Compute the test value. 4. Make the decision. 5. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Assume all assumptions are met. 6. Game Attendance 10. Lottery Ticket Sales A lottery outlet owner hypothesizes that she sells 200 lottery tickets a day. She randomly sampled 40 days and found that on 15 days she sold fewer than 200 tickets. At a = 0.05, is there sufficient evidence to conclude that the median is below 200 tickets?
Answers
Hypotheses and Claim:Null Hypothesis (H0): The median number of lottery tickets sold per day is 200.Alternative Hypothesis (HA): The median number of lottery tickets sold per day is below 200.
Claim: There is sufficient evidence to conclude that the median is below 200 tickets.
Critical Value(s):
To determine the critical value for the hypothesis test, we need to specify the significance level (α). In this case, α is given as 0.05.
Since the sample size is relatively small (n = 40), we can use the t-distribution to find the critical value. The critical value corresponds to the lower tail because we are testing whether the median is below 200 tickets.
Using a t-table or a statistical software, we find the critical value tα/2 with (n - 1) degrees of freedom. For α = 0.05 and (n - 1) = 39, we find t0.025 = -1.685.
Compute the Test Value:
To compute the test value, we need to calculate the test statistic, which is the t-value.
Let's define X as the number of days the owner sold fewer than 200 tickets. In this case, X follows a binomial distribution with n = 40 and p = 0.5 (assuming equal probability of selling more or fewer than 200 tickets).
Since the sample size is large enough, we can approximate the binomial distribution using the normal distribution. The mean (μ) and standard deviation (σ) of the binomial distribution can be calculated as follows:
μ = np = 40 * 0.5 = 20
σ = sqrt(np(1-p)) = sqrt(40 * 0.5 * 0.5) = sqrt(10)
The test statistic t is given by:
t = (X - μ) / (σ / sqrt(n))
In this case, X = 15, μ = 20, σ = sqrt(10), and n = 40. Plugging these values into the formula:
t = (15 - 20) / (sqrt(10) / sqrt(40)) ≈ -2.24
Make the Decision:
In this step, we compare the test value to the critical value.
If the test value falls in the rejection region (t < tα/2), we reject the null hypothesis. Otherwise, if the test value does not fall in the rejection region, we fail to reject the null hypothesis.
In our case, the test value t = -2.24 is smaller than the critical value tα/2 = -1.685.
Therefore, we reject the null hypothesis.
Summarize the Results:
Based on the analysis, there is sufficient evidence to conclude, at the α = 0.05 level, that the median number of lottery tickets sold per day is below 200.
The lottery outlet owner's hypothesis that she sells 200 lottery tickets a day is not supported by the data, indicating that the median sales are lower than the claimed value.
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True or false is the graph of y = 2/3 x + 4
Answers
Answer:
False. 2/3 is positive so therefore, it would be increasing, not decreasing.
Step-by-step explanation:
A study reports the following data on impregnated compressive modulus (psi x 106) when two different polymers were used to repair cracks in failed concrete. Epoxy 1.74 2.15 2.02 1.95 MMA prepolymer 1.78 1.57 1.72 1.67 Obtain a 90% CI for the ratio of variances by first using the method suggested below to obtain a general confidence interval formula. (Use s₁ for expoxy and s₂ for MMA prepolymer. Round your answers to two decimal places.) 5₁²10₁² F₁
Answers
The 90% confidence interval for the ratio of variances is [0.05, 12.36].
Lets calculate the sample variances for each polymer.
For Epoxy:
Sample Variance (s₁²) = (1.74² + 2.15² + 2.02² + 1.95²) / (4 - 1)
= 0.135
For MMA Prepolymer:
Sample Variance (s₂²) = (1.78² + 1.57² + 1.72² + 1.67²) / (4 - 1)
=0.056
F statistic is F = (s₁²) / (s₂²)
F=0.135/0.056
=2.41
Determine the degrees of freedom for each sample.
For Epoxy: df₁ = 4 - 1 = 3
For MMA Prepolymer: df₂ = 4 - 1 = 3
Now find the critical F-value corresponding to a 90% confidence level with df₁ and df₂ degrees of freedom.
Using statistical tables or a calculator, the critical F-value for a 90% confidence level with df₁ = 3 and df₂ = 3 is approximately 5.14.
Calculate the lower and upper bounds of the confidence interval.
Lower Bound = (1 / F) × (s₁² / s₂²)
= (1 / 5.14) × (s₁² / s₂²)
= 0.050
Upper Bound = 5.14 × (s₁² / s₂²)
= F × (s₁² / s₂²)
=12.36
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If V is a finite-dimensional inner product space and V = WW2 is the direct sum of two subspaces, which of the following must be true? • If Ty : W1 + W1 and T2 : W2 + W2 are linear transformations, then there is a unique linear transformation T:V + V such that T(W1) =T1(wi) for all w1 € W1, and T (W2) = T2(W2) for all W2 E W2. • If {V1, ..., Un} is a basis for V such that {V1, ..., Uk} is a basis for W1, then {Uk+1,..., Un} is a basis for W2. • If projw, is the orthogonal projection map onto W1, then for all v EV, we have v-projw, (v) € W2.
Answers
The correct statement is:
• If projw₁ is the orthogonal projection map onto W₁, then for all v in V, we have v - projw₁(v) ∈ W₂.
What is finite-dimensional inner product space?
In a finite-dimensional inner product space V, if V = W₁ ⊕ W₂ is the direct sum of two subspaces W₁ and W₂, the orthogonal projection map projw1 onto W₁ is a linear transformation that projects any vector v onto the subspace W₁. The projection of v onto W₁ is the closest vector in W₁ to v.
The statement v - projw₁(v) ∈ W₂ means that the difference between v and its projection onto W₁ lies in the subspace W₂. This is true because V is the direct sum of W₁ and W₂, which means any vector in V can be uniquely decomposed as the sum of a vector in W₁ and a vector in W₂. Therefore, the difference v - projw₁(v) will be in W₂.
This property holds for any vector v in V, so the statement is true.
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16. You decide to drop a penny off the top of the Willis Tower (fromerly the Sears Tower) in Chicago, IL. The
height of the penny (in feet) can be represented by the equation h= -16t2 + 1451 where t is time (in seconds).
a) How long will it take for the penny to hit the ground? Show any work that leads to your answer.
Answers
Answer:
9.5 seconds.
Step-by-step explanation:
We know that the equation that represents the height of the penny as a function of time is:
h(t) = -16*t^2 + 1451
Where the height is in ft, and the time is in seconds.
a) We want to know how long takes the penny to hit the ground.
Well, the penny will hit the ground when its height is equal to zero.
Then we need to solve for t:
h(t) = 0 = -16*t^2 + 1451
0 = -16*t^2 + 1451
16*t^2 = 1451
t^2 = 1451/16 = 90.7
t = √90.7 = 9.5
This means that it takes 9.5 seconds to hit the ground.
Answer:9.5 seconds
Step-by-step explanation:you subtract
Tan(x)-sqrt (3)=0, I know that one of the solutions should be pi/3, but I don’t know how to get to that, does anyone know how to solve this?
Answers
Consider the curve given by the parametric equations x=t(t2−192),y=8(t2−192) a.) Determine the point on the curve where the tangent is horizontal. t= b.) Determine the points t1,t2 where the tangent is vertical and t1
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a) The point on the curve where the tangent is horizontal is at t = 0.
b) The points where the tangent is vertical are at t₁ = -5 and t₂ = 5.
To find the points on the curve where the tangent is horizontal, we need to find the values of t that satisfy dy/dt = 0.
a.) Differentiating y = 3(t² - 75) with respect to t, we get:
dy/dt = 6t
Setting dy/dt = 0, we have:
6t = 0
t = 0
Therefore, when t = 0, the tangent is horizontal.
b.) To find the points where the tangent is vertical, we need to find the values of t that satisfy dx/dt = 0.
Differentiating x = t(t² - 75) with respect to t, we get:
dx/dt = 3t² - 75
Setting dx/dt = 0, we have:
3t² - 75 = 0
t² = 25
t = ±5
Therefore, the points where the tangent is vertical are when t = -5 and t = 5, with t₁ = -5 and t₂ = 5.
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The question is -
Consider the curve given by the parametric equations
x = t (t²-75) , y = 3 (t²-75)
a.) Determine the point on the curve where the tangent is horizontal.
t=
b.) Determine the points t_1,t_2 where the tangent is vertical and t_1 < t_2.
t_1=
t_2=
Use the diagram to identify 4 collinear points
Answers
Answer:
the answer is the (L,N,K,O)
Find the slope of the line perpendicular to AB. A(3, 5) and B(3, -8).
Answers
Answer:
m = 0
Step-by-step explanation:
AB has a slope of y2 - y1 / x2 - x1 so -8-5/3-3 so -13/0 = undefined so it is a vertical line, so any line that is horizontal will be perpendicular to it, so horizontal lines have a zero slope
look at photo to answer!
please help
Answers
Answer:
the answer is minus 2 ( -2)
Answer:
B
Step-by-step explanation:
This involves reading the coordinates of points from the graph
When x = 3 then y = - 2 , that is the point (3, - 2 )
Choose all of the points that are reflections of each other across both axes. (1.5,−2) ( 1 . 5 , - 2 ) and (−112,2) ( - 1 1 2 , 2 ) (4.5,−2) ( 4 . 5 , - 2 ) and (5.4,−2) ( 5 . 4 , - 2 ) (−112,3) ( - 1 1 2 , 3 ) and (−3,112) ( - 3 , 1 1 2 ) (1.75,−4) ( 1 . 75 , - 4 ) and (−134,4) ( - 1 3 4 , 4 )
Answers
Answer:
The points which are reflections across both axis are;
1) (1.5, -2) and [tex]\left (-1\dfrac{1}{2} , \ 2\right )[/tex]
2) (1.75, -4) and [tex]\left (-1\dfrac{3}{4} , \ 4\right )[/tex]
Step-by-step explanation:
The coordinate of the image of a point after a reflection across the 'x' and 'y' axis are given as follows;
[tex]\begin{array}{ccc}& Preimage&Image\\Reflection \ about \ the \ x-axis&(x, \ y)&(x, \, -y)\\Reflection \ about \ the \ y-axis&(x, \ y)&(-x, \, y)\end{array}[/tex]
Therefore, a reflection across both axis changes (only) the 'x' and 'y' value signs
The given points which are reflections across both axis are;
(1.5, -2) and [tex]\left (-1\dfrac{1}{2} , \ 2\right )[/tex]
We note that [tex]\left (-1\dfrac{1}{2} , \ 2\right )[/tex] = (-1.5, 2)
The reflection of (1.5, -2) across the x-axis gives the image (1.5, 2)
The reflection of the image (1.5, 2) across the y-axis gives the image (-1.5, 2)
Similarly, we have;
(1.75, -4) and [tex]\left (-1\dfrac{3}{4} , \ 4\right )[/tex]
We note that [tex]\left (-1\dfrac{3}{4} , \ 4\right )[/tex] = (-1.75, 4)
The reflection of (1.75, -4) across the x-axis gives the image (1.75, 4)
The reflection of the image (1.75, 4) across the y-axis gives the image (-1.75, 4).
The other points have changes in the values of the 'x' and 'y' between the given pair and are therefore not reflections across both axis
Sample mean = 5.5, 8=2.517. df-8 and confidence level 95% (corresponding test statistic value is 2303). Based on this information answer the following: Which test is appropriate, z-test or t-test? Type either "z-test" or "t-test" t-test Ą What was the sample size? A Calculate the margin of error. (Report two decimal point, #.##) A Calculate the confidence interval-write lower and uppler value using comma.(Report two decimal point: #.##, #.##) Ą If the df increases to 30 then what will impact on the margin of error? Write either "increase" or "decrease" or "no change decrease ^ If the df increases to 30 then what will impact on the confidence interval? Write either "wide" or "narrow" or "no change" decrease A/
Answers
The confidence interval is (4.25, 6.75). If the df increases to 30 then the impact on the margin of error will decrease.
The test that is appropriate for the given values is the t-test since the sample size is small. The sample size is not given in the question but it is necessary to find the margin of error. Hence, the sample size can be found using the formula of the t-test. Let us recall the formula of the t-test below:t = (sample mean - population mean) / (sample standard deviation / √n)
Where,t = test statistic sample mean = 5.5population mean = 8sample standard deviation = 2.517confidence level = 95%corresponding test statistic value = 2.303Let's plug in all the values in the formula and solve for the sample size,n = ((sample mean - population mean) / (sample standard deviation/test statistic value))²= ((5.5 - 8) / (2.517 / 2.303))²= 3.484²≈ 12.11Hence, the sample size is 12.11 or approximately 12.
Now, let's calculate the margin of error using the formula below: Margin of error = (t-critical value) × (standard deviation / √n)Since the confidence level is 95%, the alpha level is 5% which is divided equally between the two tails, so the area in each tail is 2.5%. Using the t-distribution table with df = n-1 = 11 and alpha/2 = 0.025, the t-critical value is 2.201.
Let's plug in all the values in the formula of the margin of error and solve it: Margin of error = (t-critical value) × (standard deviation / √n)= 2.201 × (2.517 / √12)= 1.245 ≈ 1.25Therefore, the margin of error is 1.25.
The confidence interval can be calculated using the formula below: Confidence interval = (sample mean - margin of error, sample mean + margin of error)Confidence interval = (5.5 - 1.25, 5.5 + 1.25)= (4.25, 6.75)Hence, the confidence interval is (4.25, 6.75).If the df increases to 30 then the impact on the margin of error will decrease. If the pdf increases to 30, then the impact on the confidence interval will be narrow.
So, the confidence interval is (4.25, 6.75).If the df increases to 30 then the impact on the margin of error will decrease.
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In this class we considered a variety of problems, formulas, and theorems. For an extra credit problem, describe a concept that we covered in class in your own words. It can be a theorem or a question that we solved in class or in homework problems (please don't repeat problems above). State the concept, explain the details in your own words.
Answers
The Pythagorean Theorem is a concept in geometry that explains the relationship between the sides of a right-angled triangle. According to this theorem, the square of the hypotenuse of a right-angled triangle is equal to the sum of the squares of its two legs. This can be represented in the form of an equation as c² = a² + b², where c is the hypotenuse and a and b are the legs of the triangle. This theorem is widely used in various fields, including architecture, engineering, and physics. It is named after the ancient Greek mathematician Pythagoras, who is credited with its discovery.
In simpler words, the Pythagorean theorem is used to find the length of the missing side of a right-angled triangle. For example, if we know the lengths of two sides of a triangle, we can use this theorem to find the length of the third side. This theorem is based on the fact that the hypotenuse is the longest side of a right-angled triangle, and that the square of a number is the product of that number multiplied by itself. It is also used to prove whether a triangle is a right-angled triangle or not. The Pythagorean Theorem is a fundamental concept in geometry and is an essential tool for solving various mathematical problems.
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Please helppp What's the slope and y intercept of 3x - y = 7
Answers
Answer:
slope: 3
y intercept:(0,-7)
Which of the following transformations shifts all points graphed in the standard (wy)
coordinate plane down 5 coordinate units?
A. (X, y-5)
B. (X, y+5)
C. (X-5y)
D. (K-5, y)
E. (X+5,y)
Answers
Answer:
B is your answer
Step-by-step explanation:
please help anybody it would help alot
Answers
180-77=103
so then simplify (6x-17)=103
6x=120
x=20
What is the interquartile range The following data points represent the volume of gas in each race car driver's tank (in liters) Sort the data from least to greatest: 2.8 43 7.5 8.5 11.6 12 12.1 Find the interquartile range
Answers
The interquartile range of the data set is 4.7 liters.
To find the interquartile range, we first need to sort the data from least to greatest. This gives us the following data set:
2.8, 7.5, 8.5, 11.6, 12, 12.1
The first quartile (Q1) is the median of the lower half of the data set. In this case, the lower half of the data set is {2.8, 7.5, 8.5}. The median of this data set is 7.5. Therefore, Q1 = 7.5.
The third quartile (Q3) is the median of the upper half of the data set. In this case, the upper half of the data set is {11.6, 12, 12.1}. The median of this data set is 12. Therefore, Q3 = 12.
The interquartile range (IQR) is calculated by subtracting Q1 from Q3. In this case, IQR = 12 - 7.5 = 4.7 liters.
The interquartile range is a measure of the variability of the middle 50% of the data. In this case, the interquartile range tells us that the middle 50% of the race car drivers have between 7.5 and 12 liters of gas in their tanks.
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no links no links sssssdrerw
Answers
Answer:
c
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Given that x=6.2•10^12 and y=2•10^-8, find the value of x•2y
Answers
Answer:
Step-by-step explanation:
State the null hypothesis for a one-way ANOVA test if there are four groups.
Answers
In a one-way ANOVA test with four groups, the null hypothesis states that there is no significant difference between the means of all four groups.
This means that any observed differences in the sample means are due to chance or random integral alone and not because of any systematic or real differences between the groups.
The null hypothesis assumes that the population means for each group are equal, which implies that there is no effect or influence of the independent variable on the dependent variable. If the null hypothesis is accepted, it means that any observed differences between the groups are not statistically significant and do not support the alternative hypothesis.
To determine whether to accept or reject the null hypothesis, researchers calculate the F-statistic, which compares the variability between the sample means to the variability within each group. If the calculated F-value is greater than the critical F-value for a given level of significance, the null hypothesis is rejected in favor of the alternative hypothesis, indicating that there is a significant difference between at least two of the group means.
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what is the volume of this sphere? Use a 3.14 and round your answer to the nearest hundredth. cubic feet Submit Work it out Not feeling ready yet? This Area of circles 47)
Answers
Answer:
4.19 cubic feet
Step-by-step explanation:
BRAINLY TO WHOEVER HELPS AND GET IT RIGHT
~no links pls~
Answers
Answer:
4 yards saved
Step-by-step explanation:
two adjacent sides: 6 + 8 = 14
diagonal: √(6² + 8²) = √100 = 10
14 - 10 = 4
5/6 + 1/3 + 1/2 + 3/4 = ?
Answers
Answer:
23/12 or 1 11/12
Step-by-step explanation:
Answer:
29/12 or 2 5/12
Step-by-step explanation:
number 8 please help me
Answers
Answer:
15.9??
Step-by-step explanation:
i need help. what’s the answer to this .
Answers
Answer:
12
Step-by-step explanation:
I know bc i did this before
Answer:
72 unit cubes (72 units³)
Step-by-step explanation:
[tex]6\times3\times4=72[/tex]
Let p be a prime and let f(x,y) be a polynomial of degree 2 whose only 0 in Z/pZ is 0 (the trivial) (Has no zero divisors).
i) Explain why f(ka,kb) = k^2f(a,b).
ii) Use i) to prove that if a is not 0 mod p, then f(x,y) is congruent to a mod p always has a solution.
Answers
Given a prime number p and a polynomial f(x, y) of degree 2 with the only zero in Z/pZ being 0, we can show that f(ka, kb) = k^2f(a, b) using properties of polynomials.
i) To show that [tex]f(ka, kb) = k^2f(a, b)[/tex], we consider the polynomial f(x, y) and apply the properties of polynomials. Since f(x, y) has a degree of 2, we can write it as [tex]f(x, y) = ax^2 + bxy + cy^2,[/tex] where a, b, and c are coefficients. Now, substituting ka for x and kb for y, we get f(ka, kb) = [tex]a(ka)^2 + b(ka)(kb) + c(kb)^2[/tex]. Simplifying this expression, we obtain f(ka, kb) = [tex]k^2(ax^2 + bxy + cy^2) = k^2f(a, b),[/tex] which demonstrates the desired result.
ii) Using the result from part i), we can prove that if a is not congruent to 0 modulo p, then the equation f(x, y) ≡ a (mod p) always has a solution. Suppose f(x, y) ≡ a (mod p) has no solution for some value of a not congruent to 0 modulo p. Therefore, if a is not congruent to 0 modulo p, we can choose an appropriate value of k such that [tex]k^2f(a, b)[/tex] ≡ b (mod p), leading to a solution for f(x, y) ≡ b (mod p). Thus, if a is not congruent to 0 modulo p, f(x, y) ≡ a (mod p) always has a solution.
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The current in a stream moves at a speed of 5 km/h. A boat travels 20 km upstream and 20 km downstream in a total of 3 hours. Find the speed of the boat in still water.
Answers
Answer:
14
Step-by-step explanation:
im right
area = ___ square units
Answers
Answer:
9 square units
Step-by-step explanation:
Area of a square = base * height
= 3*3
= 9
3*3=9
Area= width* length
width= 3
length= 3
width Length
3 * 3