Answer:
She will have kinetic energy at the bottom of the hill=45700 J
Explanation:
We are given that
Mass, m=60 kg
Speed, v=10 m/s
Height, h=150 m
Length of slope, d=650 m
Frictional force, f=70 N
We have to find the kinetic energy she will have at the bottom of the hill.
Kinetic energy at the bottom of the hill
=Initial kinetic energy+ mgh-fd
Substitute the values
Kinetic energy at the bottom of the hill
=[tex]\frac{1}{2}(60)(10)^2+60\times 9.8\times 150-70\times 650[/tex]
=[tex]45700J[/tex]
Hence, she will have kinetic energy at the bottom of the hill=45700 J
A 75 kg refrigerator is located on the 70th floor of skyscraper (300 meters above ground). What is the potential energy of the refrigerator. (PE=MGH(G=9.8M/S²)
Answer:
220,500 Joules
Explanation:
PE = (75 kg) x (9.8 [tex]m/s^{2}[/tex]) x (300 m)
PE = (735) x (300)
PE = 220,500 Joules
Answer:
googli moogli
Explanation:
A children's roller coaster is released from the top of a track. If its maximum speed at ground level is 3 m/s, find the height it was released from.
Answer:
h = 0.46 m
Explanation:
According to the law of conservation of energy:
Potential Energy Lost by Roller Coaster = Kinetic Energy Gained by Roller Coaster
[tex]mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\h = \frac{v^2}{2g}[/tex]
where,
h = height = ?
v = speed at bottom = 3 m/s
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]h = \frac{(3\ m/s)^2}{(2)(9.81\ m/s^2)}[/tex]
h = 0.46 m
Which of the following statements are true about covalent bonding between two atoms? Select all that apply.
A. Electrons are shared.
B. The electronegativities of the two atoms are close to each other.
C. The two atoms can be of the same element.
D. Electrons transfer from one atom to the other.
Answer:
A and C
Explanation:
Covalent bonding involves sharing by the atoms involved
Statements that can be considered as true statement about covalent bonding between two atoms are:
A. Electrons are shared.
B. The electronegativities of the two atoms are close to each other.
C. The two atoms can be of the same element.
Covalent bond can be regarded as chemical bond in which electrons pairs are been shared between atoms, these atoms can be of the same element.These electron pairs are called pairs or bonding pairs.Therefore, option A,B,C are correct.
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Weathering of rocks can occur in many ways. In the western United States, strong winds can erode huge rock formations by blowing millions of tiny grains of sand at these rocks. Which term accurately describes this type of weathering?
Answer: physical or mechanical weathering
Explanation:
Mechanical weathering which is also referred to as the physical weathering occurs when a rock is broken down into smaller pieces. In this case, there will be a physical change of the rock but its composition will not change.
Some examples include ice freezing and expansion of the cracks in the rock, Smstrong winds that carrycpieces of sand which then sandblast surfaces, moving water which causes abrasion etc.
A 0.2 kg hockey puck is sliding along the ice with an initial velocity of -10 m/s when a player strikes with his stick, causing it to reverse it's direction and giving it a velocity of +25 m/s. The impulse the stick applies to the puck is most nearly
I = 7 N-s
Explanation:
Impulse is defined as
I = ∆p = m(vf - vi)
We are given
m = 0.2 kg
vi = -10 m/s (to the left)
vf = +25 m/s (to the right)
Therefore, the impulse imparted on the puck is
I = (0.2 kg)[25 m/s - (-10 m/s)]
= (0.2 kg)(35 m/s)
= 7 N-s
A 10.-kilogram object falls freely for a distance of 6.0 meters near Earth's
surface. Which of the following is closest the total kinetic energy gained by
the object as it falls?
A. 60. J
B. 590 J
C. 720 J
D. 1200 J
Given :
A 10.-kilogram object falls freely for a distance of 6.0 meters near Earth's
surface.
To Find :
The total kinetic energy gained by the object as it falls.
Solution :
Since, only conservative force i.e gravity is applied on the object.
So, its total energy is constant.
Total kinetic energy gained = Total potential energy gained
K.E = mgh ( Here, g is acceleration due to gravity = 9.8 m/s² )
K.E = 10 × 9.8 × 6 J
K.E = 588 J
Hence, this is the required solution.
The kinetic energy of an object is proportional to the product of its mass and the square of the velocity of the object.
The kinetic energy of the object is 588 J. Option B shows the kinetic energy of the object.
What is kinetic energy?The kinetic energy of an object is defined as the energy that it possesses due to the motion of the object.
Given that the mass m of the object is 10 kg and it falls from the height h of 6 meters near the earth's surface. The object falls vertically, so the gravitational acceleration is applied to it.
The potential energy of the object is given below.
[tex]PE = mgh[/tex]
[tex]PE = 10 \times 9.8 \times 6[/tex]
[tex]PE = 588 \;\rm J[/tex]
The total force applied to the object is due to gravity only. Hence the total energy of the object will be constant. Thus the kinetic energy of the object will be equivalent to the potential energy of the object.
Hence we can conclude that the kinetic energy of the object is 588 J. Option B shows the kinetic energy of the object.
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Charges of +3 µC and –5 µC are 2 mm from each other. The –5 µC charge is replaced with a +5 µC charge.
How will the electrical force between the charges compare with the original force?
same force, but in the opposite direction
same force, but in the same direction
greater force, but in the opposite direction
greater force, but in the same direction
Answer: same force in opposite direction.
Explanation: Charges of opposite sign attracts each other and charges with same sign repel each other. Because only sign of negative charge changes, and absolute value of charge remains same, value of force is same but is in opposite direction.
Answer:
A) same force, but in the opposite direction
Explanation:
he's right
Transformar las siguientes unidades al Sistema Internacional: 30 km/h ; 37 Dm ; 750 g ; 4x10-6 km2 ; 7500 cm ; 600000 cm2 ; 520700000 mm3 ; 3,4 años.
Answer:
a) 3.0 10⁴ m / s, b) 3.7 10¹ m, c) 0.750 kg, d) 4 10¹² m², e) 75 m, f) 60 m²
g) 5.207 10³ m², e) 4.847 10⁷ s
Explanation:
The international system (SI) of measurements has as fundamental units the meter for length, the second for time and kilogram for mass.
Let's reduce the different magnitudes to the SI system
a) 30 km / h (1000m / 1 km) (1 h / 3600 s) = 3.0 10⁴ m / s
b) 37 Dm (10 m / 1 Dm) = 3.7 10¹ m
c) 750 g (1 kg / 10,000 g) = 0.750 kg
d) 4 10⁶ km² (1000 m / 1km) ² = 4 10¹² m²
e) 7500 cm (1 m / 100 cm) = 75 m
f) 600000 cm² (1m / 10² cm) ² = 60 m²
g) 520700000 mm³ (1 m / 10³ mm) ³ = 5.20700000 109/10 ^ 6
= 5.207 10³ m²
e) 3.4 years (l65 days / 1 yr) (24 h / 1 day) (3600 s / 1h) = 4.847 10⁷ s
I will mark you as brainliest
pls ans
a) Name the graph?
b) In first 2 s the object is said to be in ______________ motion.
(uniform motion / uniform acceleration)
c) The portion BC of the graph represents which type of motion?
d) Find out acceleration in first 2 s?
I don't know♀ what is your favorite song
If there are 1,600 meters in a mile, find the speed of sound in this experiment in units of "miles / hour"
Answer:
v = 771.75 mile / h
Explanation:
The speed of sound is v = 343 m / s at T= 20C
the transformation ratios are
1 mile = 1600 m
1 h = 3600 s
Let's reduce
v = 343 m / s (1 mile / 1600 m) (3600 s / 1 h)
v = 771.75 mile / h
A truck starts from rest with an acceleration of 0.3 m/ S^2 find its speed in km/h when it has moves through 150 m
Answer:
v = 34.128 km/hr
Explanation:
Given that,
The initial speed of a truck, u = 0
Acceleration of the truck, a = 0.3 m/s²
Distance moved, d = 150 m
Let the final speed of the truck is v. Using third equation of motion i.e.
[tex]v^2-u^2=2ad\\\\v=\sqrt{u^2+2ad}[/tex]
Put all the values,
[tex]v=\sqrt{0^2+2\times 0.3\times 150}\\\\v=9.48\ m/s[/tex]
or
v = 34.128 km/h
So, the final speed of the truck is equal to 34.128 km/h.
it took 50 joules to push a shopping cart 5 meters.with what face was the shopping cart pushed?
can someone please help me answer this question ?
Answer:
b 60 N force
Explanation:
The change in the momentum is given by the force•distance from the attached point. We don't have any distance, but apparently, the stick forces are being applied in each quarter of the stick, so let's use fractions of 4 to solve it:
150 N:
150•1/4 = 37.5
30 N:
30•2/4 = 30•1/2 = 15
60 N:
60•3/4 = 45
40 N:
40•4/4 = 40•1 = 40
A 8.25-N force is applied to a 2.50 kg object to accelerate it rightwards. The object
encounters 2.19 N of friction. Determine the acceleration of the object. (Neglect air
resistance.)
Answer:
Explanation:
Use F - f = ma since we are on a flat surface. We are given the applied Force as 8.25, the frictional force as 2.19, and a mass of 2.50. Filling in:
8.25 - 2.19 = 2.50a. Doing the subtraction on the left gives us:
6.06 = 2.50a and we divide to 3 sig figs to get
a = 2.42 m/s/s
4. What are 3 things that you can think of doing, that would reduce
your electricity bill?
what 3 words or 3 phrases that would help you remember the steps to Covalent and Ionic bonding?
Answer:
non metals and non metals=covalent bond
metals and non metals =ionic bond
transfer all the valence electron to form ionic bond
share valence electron to form covalent bond
The magnetic field 0.100 m from a
wire is 4.20 x 10-5 T. What is the field
0.200 m from the wire (twice as far)?
[?] *10^[?]T
Answer:
Your answer is given below:
Explanation:
A powerful motorcycle can produce an acceleration of 3.00 m/s2 while traveling at 106.0 km/h. At that speed, the forces resisting motion, including friction and air resistance, total 432.0 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What is the magnitude of the force that motorcycle exerts backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 241 kg
Answer:
"1155 N" is the appropriate solution.
Explanation:
Given:
Acceleration,
[tex]a=3 \ m/s^2[/tex]
Forces resisting motion,
[tex]F_f=432 \ N[/tex]
Mass,
[tex]m = 241 \ kg[/tex]
By using Newton's second law, we get
⇒ [tex]F-F_f=ma[/tex]
Or,
⇒ [tex]F=ma+F_f[/tex]
By putting the values, we get
⇒ [tex]=(3\times 241)+432[/tex]
⇒ [tex]=723+432[/tex]
⇒ [tex]=1155 \ N[/tex]
What happens to the mass number of an atom when the
number of neutrons in the nucleus of that atom increases?
if molecule gains heat energy it converts liquid to gas
Answer:
Actually, the substance is the one that changes from liquid to gas.
The molecule just gains energy which overcomes the attraction force between it and neighboring molecule.
what came first the chicken or the egg
Answer:
The Egg
Explanation:
personally the Chicken who would lay the egg would have to come from an Egg itself, then It would have to grow up and then Produce an egg that will produce a chicken and so on.
What happens to the wavelength of a wave if the frequency quadruples, but the wave is in the same medium?
A. The wavelength will go down to half the original amount.
B. The wavelength will go down to one-fourth of the original amount.
C. The wavelength will be quadruple.
D. The wavelength will double.
Answer:
I think C? I'm not sure totally though...
Explanation:
A 20 ohm and 60 ohm light bulb are put in series together which one would be brighter?
Answer:
The 60 Ohm bulb would be brighter than the 20 Ohm bulb.
Explanation:
Hi there!
Ohm's Law: [tex]V=IR[/tex] where V is voltage, I is current and R is resistance
Power equation: [tex]P=VR[/tex]
The greater the power of a bulb, the brighter it is.
The bulbs are connected in series, meaning the the current travelling through each will be the same. Plug Ohm's law into the power equation so we just have I and R:
[tex]P=I^2R[/tex]
Because the current stays the same, the bulb with greater resistance will have greater power, hence being brighter. Therefore, the 60 Ohm bulb would be brighter than the 20 Ohm bulb.
I hope this helps!
Answer:
The 60 Ohm bulb would be brighter than the 20 Ohm bulb.
Explanation:
Hi there!
Ohm's Law: V=IRV=IR where V is voltage, I is current and R is resistance
Power equation: P=VRP=VR
The greater the power of a bulb, the brighter it is.
The bulbs are connected in series, meaning the the current travelling through each will be the same. Plug Ohm's law into the power equation so we just have I and R:
P=2RP=I
2
R
Because the current stays the same, the bulb with greater resistance will have greater power, hence being brighter. Therefore, the 60 Ohm bulb would be brighter than the 20 Ohm bulb.
I hope this helps!
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A toy mouse has a mass of 2 kg and kinetic energy of 25 J. What is its speed?
A. 4 m/s
B. 3 m/s
C. 6 m/s
D. 5 m/s
Answer:
D 5m/s
Explanation:
Calcium is combined with Nitrogen in a chemical reaction. The formula of the compound created, Calcium Nitride, is
Answerrrrrrrrrrrrrrrrrt
Calcium is a 2+ ion which would be written as Ca^2+
Nitrogen is a 3- ion which is written as N^3-
When combined to create Calcium Nitrate it is Ca3N2
See picture:
A rocket blasts off from Earth with an initial
acceleration of 18.2 m/s2. A 75.0 kg astronaut
is inside. What is the normal force of the
astronaut's chair on the astronaut?
S
[?]N
Explanation:
apparent apparent weight is how hard astronaut pushes against it which is the normal force
n m a y + mgm open parenthesis y + and close parenthesis and = m open parenthesis a y + and so i need the acceleration of the astronaut since initial velocity is 0 and yby over l 45 m per second over 15 x 30.0 m m per second squared
Explain why a kangaroo can jump higher as it's speed increases
Answer:
See explanation
Explanation:
The ability of the Kangaroo to jump higher is due to the stretching of its tendons as its speed increases.
As the tendons are being stretched more and more, the elastic potential energy increases with each increasing stretch.
This elastic potential energy is translated into gravitational potential energy hence the Kangaroo jumps higher as it's speed increases.
The kangaroo can jump higher as it's speed increases due to the ability of its tendons to stretch more and more.
The jumping of kangaroo can be related with the concept of spring force and spring potential energy. The spring force is given as,
F = kx
And spring elastic potential energy is,
[tex]U=\dfrac{1}{2}kx^{2}[/tex]
In both the cases, k is the spring constant and x is the stretching distance.
When kangaroo try to jump, the tendons provide extra flexibility to jump higher due to the more stretching. Here, the value of x increases. As value of x increases, ultimately more acceleration is provided to increase its speed.As the tendons are being stretched more and more, the elastic potential energy increases with each increasing stretch.
This elastic potential energy is translated into gravitational potential energy hence the Kangaroo jumps higher as it's speed increases.
Thus, we can conclude that the kangaroo can jump higher as it's speed increases due to the ability of its tendons to stretch more and more, such that more energy conversion of energy takes place.
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A car starts from rest and goes due east reaching a speed of 40 m/s What additional information is needed in order to calculate the acceleration of the car?
O A. the total distance traveled by the car
B. the total time of the car's motion
Cthe car's mass
O D. the car's initial velocity
Answer:leter B the answer
Explanation:
The additional information is needed in order to calculate the acceleration of the car is the total time of the car's motion.
What is acceleration?The acceleration of an object is the rate of change of velocity with time.
a = Δv/t
where;
Δ v is change in velocity = final velocity - initial velocityt is the time of motionWhen the change in velocity of the object and time of motion is known, the acceleration of the object can be determined.
Thus, the additional information is needed in order to calculate the acceleration of the car is the total time of the car's motion.
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8× +5+9×+3 how can I solve this
Answer:
collect like terms then add=>8x+9x+5+3
=>8x+9x+5+3=>17x+8
A 32.0 kg cart is at rest on a frictionless, horizontal surface. The cart experiences an unbalaced force, causing the cart to accelarate at a rate of +5 m/s2.
Calculate the time it takes for the cart to travel 200 meters.
Answer:
t = 8.94 s
Explanation:
We will use the second equation of motion to calculate the time taken by the cart:
[tex]s = v_it + \frac{1}{2} at^2[/tex]
where,
s = distance = 200 m
vi = initial speed = 0 m/s
t = time taken = ?
a = acceleration = 5 m/s²
Therefore,
[tex]200\ m = (0\ m/s)(t)+\frac{1}{2}(5\ m/s^2)t^2\\\\t^2 = \frac{(200\ m)(2)}{5\ m/s^2}\\\\t = \sqrt{80\ s^s}[/tex]
t = 8.94 s