Answer:
405
Explanation:
If the car stops at 45m/s in 9 seconds then it took the car 405 meters to stop
How many volts would it take to push 1 amp through a resistance of 1 ohm?
Answer:
[tex]1\; \rm V[/tex].
Explanation:
Ohm's Law give the following relationship between the potential [tex]V[/tex] across a conductor, the electrical resistance [tex]R[/tex] of that conductor, and the current [tex]I[/tex] through that conductor:
[tex]V = I \, R[/tex].
It is given that the current through this conductor is [tex]I = 1\; {\rm A}[/tex], and that the electrical resistance of this conductor is [tex]R = 1\; \rm \Omega[/tex].
Note, that the unit of electrical resistance Ohm is a composite unit; [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex] (volts per ampere.)
Substitute the value of [tex]I[/tex] and [tex]R[/tex] into the equation [tex]V = I \, R[/tex] from Ohm's Law to find the potential across this conductor:
[tex]\begin{aligned}V &= I \, R \\ &= 1\; {\rm A} \times 1\; {\rm \Omega} \\ &= 1\; {\rm A} \times 1\; {\rm V \cdot A^{-1}} \\ &= 1\; {\rm V}\end{aligned}[/tex].
how does the function of the parts of the system contribute to its function as a whole
plsss help i need it rn i’ll give brainliest
A car drives 84 meters forward. It's displacement and distance would be the same?
Answer:
Yes.
Explanation:
Displacement is a vector quantity, meaning it has to be a straight graph jointing from starting point to final point and has a direction as well as magnitude and it can also be negative as well as positive and zero.
Displacement is also changes in position (points) of distance. A distance is scalar quantity meaning it only has magnitude and does not have direction. Since distance is scalar quantity, it cannot be negative. Also graph of distance can be a curve graph or any graph.
So when does displacement equal to distance? If an object is moving in straight path or line in one/fixed direction, both displacement and distance are same.
Because if a distance is a straight path and the displacement is simply a straight line (or ray) jointing from starting point to end point, both distance and displacement are both straight path or rays. Since distance and displacement have same graph, we can conclude that both are same in values.
If we go by calculus, given x = 2t as example of straight graph where x stands for position and t stands for time. We can find the displacement from b to a by using the following formulas:
Displacement
[tex]\displaystyle \large{s=\int\limits^b_a {v} \, dt}[/tex]
Distance
[tex]\displaystyle \large{l=\int\limits^b_a {|v|} \, dt}[/tex]
v stands for velocity which we can find from:
Velocity
[tex]\displaystyle \large{v=\frac{dx}{dt}}[/tex]
If you have learnt calculus, first, differentiate x = 2t with respect to t.
[tex]\displaystyle \large{v=2}[/tex]
Then substitute v = 2 in s and l to find find if both displacement and distance are equal in straight path.
Displacement
[tex]\displaystyle \large{s=\int\limits^b_a {2} \, dt}\\\displaystyle \large{s=[2t]\limits^b_a}\\\displaystyle \large{s=2b-2a = 2(b-a)}[/tex]
Distance
[tex]\displaystyle \large{l=\int\limits^b_a {|2|} \, dt}\\\displaystyle \large{l=\int\limits^b_a {2} \, dt}\\\displaystyle \large{l=[2t]\limits^b_a}\\\displaystyle \large{l=2b-2a=2(b-a)}[/tex]
Since both displacement and distance are equal when integrating on straight graph, we can conclude that an object moving in straight fixed point has same distance and displacement.
If you walk at an average speed of 5 km/h for 30 minutes, how
far will you walk? (Write your answer with Sl unit.
A 40 N block is resting on a rough inclined plane. The static friction between the block and the plane is ____ N.
The static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].
The given parameters:
Weight of the block, W = 40 NThe normal reaction on the rough surface due to weight of the block is calculated as follows;
[tex]F_n = 40 \ N[/tex]
The static friction between the block and the plane is calculated as follows;
[tex]F_s = \mu_s F_n[/tex]
where;
[tex]\mu_s[/tex] is coefficient of static frictionThus, the static friction between the block and the plane is [tex]40(\mu_s) \ N[/tex].
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The Sun has a mass of 1.99 x 10^30kg [^30 is an exponent] and is 1.5 x 10^11m [^11 is an exponent] from the earth. The planet Earth is 5.98 x 10^24kg [^24 is an exponent]. What is the gravitational attraction between the sun and the earth? G=6.67×10^-11 (-11 is an exponent)
Answer:
F = G M m / R^2 = 6.67E-11 * 1.99E30 * 5.98E24 / (1.5E11)^2
F = 6.67 * 1.99 * 5.98 / 2.25 E21 Newtons
F = 3.53E22 N
Alistar places a 6.4 kg block on an incline plane that is 23 degrees above the horizontal. The block starts from rest, and in 2.2 seconds, travels 1.4 meters. What is the force of friction on the block?
fh= 6.4×23
fh=147.2
fv=2.2×1.4
fv=3.08
f=147.2+3.08
f=150.28
The force of friction on the block is 20.798 N.
What is acceleration?Acceleration is the rate at which speed and direction of velocity vary over time. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given parameters:
Mass of the block: m = 6.4 kg.
Angle of inclination = 23°
Hence, Magnitude force acting along the motion = mg sin23°
= 6.4 × 9.8 × sin23° N
= 24.51 N.
The block travels 1.4 meters in 2.2 seconds. Acceleration = (2×1.4)/2.2² m/s²
= 0.58 m/s²
Hence, the force of friction on the block is = F - ma
= 24.51 N - 6.4×0.58 N
= 20.798 N
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Two boats race in the water. One turns around to head back in the other direction to complete the race, but it collides into the boat that was now directly in front. What forces may have been a part of the collision? Describe them in detail.
The two forces involved in this collision are the colliding force and the reaction force which are equal in magnitude but opposite in direction.
According to Newton's third law, action and reaction are equal and opposite. This law is very important in describing head - on collisions between objects and is particularly apt in describing the collision between the two boats.
In this collision, two forces are important these are the action and the reaction. The action is the colliding force which the boat that was hit experiences. The reaction force is the force that this boat experiences as a result of hitting the boat in front of it. The both forces are equal in magnitude but opposite in direction.
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What net force is needed to increase the velocity of a 5 kg object by 3 m/s over the course of 2.5 seconds?
Hi there!
Recall Newton's Second Law:
[tex]\large\boxed{\Sigma F = ma}[/tex]
∑F = net force (N)
m = mass (kg)
a = acceleration (m/s²)
We must begin by solving for the acceleration using the following:
a = Δv/t
In this instance:
Δv = 3 m/s
t = 2.5 sec
a = 3/2.5 = 1.2 m/s²
Now, plug this value along with the mass into the equation for net force:
[tex]\Sigma F = 5(1.2) = \boxed{6 N}}[/tex]
Answer:
[tex]\boxed {\boxed {\sf 6 \ Newtons}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration. The mass of the object is 5 kilograms, but the acceleration is unknown.
We can find acceleration using the following formula:
[tex]a= \frac{ \Delta v}{t}[/tex]
The velocity of the object increases by 3 meters per second. It accelerates in 2.5 seconds.
Δv= 3 m/s t= 2.5 sSubstitute the values into the formula.
[tex]a= \frac{3 \ m/s}{2.5 \ s}[/tex]
[tex]a= 1.2 \ m/s/s = 1.2 \ m/s^2[/tex]
Now we know the mass and acceleration.
m= 5 kg a= 1.2 m/s²Substitute the values into the force formula.
[tex]F=ma[/tex]
[tex]F= (5 \ kg)(1.2 \ m/s^2)[/tex]
[tex]F= 6 \ kg*m/s^2[/tex]
Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 6 kilogram meters per second squared is equal to 6 Newtons.
[tex]F= 6 \ N[/tex]
Two parents are having a child The father has freckles which are a dominant trait The mother does not have trecktes Find the possibility of the chad having tracks.
Answer:
2:3
Explanation:
mathqway
Which of the following elements is more reactive than the others
Answer:
Sulfur
Selenium
Nitrogen
Oxygen
Explanation:
Sulfur is the most reactive out of the four and Oxygen is the least reactive out of the four.
I'll give brainlest
*the first pic is for Alberto and second for the mouse*
Question 1
Alberto created a graph to illustrate his trip. Answer the questions below.
A. How does Alberto's motion change at point B?
B. What is Alberto's speed from point C to point D?
C. What happens at point D? (1 point)
Question 2
Answer the question below about Smokey The Mouse.
A. Use inertia to explain how a balanced force will affect his motion. (Newton's 1st Law)
B. What are two ways Smoky can increase his speed? (Use Newton's 2nd Law to help you)
C. What is an example of an action and reaction at work in this picture? (Use Newton's 3rd Law to help you)
Answer:
The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.
At point B, Alberto's distance covered increases with time, equal distance is covered in equal time interval. The speed increases uniformly. At the point C to D, the distance covered with time remains the same. At the point D, equal distance is no longer covered in equal time intervals.
According to the law of inertia, an object will remain at rest or in a state of uniform motion unless it is acted upon by an unbalanced force. This means that smokey mouse will continue moving uniformly unless a force acts on it.
From Newton's second law; F = ma and a = F/m. F = force , m= mass, a = acceleration. This implies that smokey mouse can increase its speed by;
Increasing the force acting on the mouse
Decreasing the mass of the mouse
Action and reaction is encountered as the mouse is walking. The mouse exerts a force on the ground and the ground exerts an equal and opposite reaction force on the mouse.
Explanation:
give answer or fight me
Answer:
translucent
Explanation:
Hope this helps! Pls give brainliest! Also, please sub to Kgirl633 on yt.
What do protoplanets eventually grow into?
Answer:
a planet
Explanation:
If planetesimals, objects that combined to form protoplanets, were to collide head on in the early solar nebula, they would shatter to the point where they would be unable to grow into a larger size, a protoplanet. A protoplanet is a massive object that will eventually become a planet.
What would be the impact on the environment if an artificial virus that attacked and destroyer chloroplast in plant cells was accidentally released by a research company?
Answer:Yes
Explanation:Because the virus is so dangerous
Why do magnets move objects in different ways?
Answer:
Magnets have two poles, called north and south. The like poles are attracted to unlike poles, but like poles repel each other. For example, the north pole of one magnet is attracted to the south pole of another. ... To make objects move with a magnet attach a piece of metal, or another magnet, to it.
Send right answers plzzzz plz
Answer:
I think A
Explanation:
You plug your microwave into an outlet and then you heat up a piece of pizza in it. This is an example of an...
Microwave Radiation????????????
Ali kicks a soccer ball upward at 45° angle
with an initial speed of 32 m/s. What
expression should Ahmed use to calculate
the magnitude of the ball's initial velocity
the horizontal direction?
Select one:
a. 32 sin(45°) m/s
b. 32 cos(45°) m/s
c. 32 tan(45°) m/s
d. 45 m/s
Answer:
the answer is 32sin(45°)m/s
If a planet has an eccentricity of 0.92 and a distance of the major axis is 5,000,000 km, then what is the distance between foci?(1 point)
460,000,000 km
0.00000018 km
4,600,000 km
5,000,000 km
Answer:
it’s the third option: 4,600,000 km
Explanation:
just took the test and that was correct
-
In the balanced equation, 4KO2 + 2CO2 = 2K2CO3 + 302, which two chem-
icals have a molar ratio of 1:1?
The two chemical compounds having a molar ratio of 1 : 1 is CO₂ and K₂CO₃
4KO₂ + 2CO₂ —> 2K₂CO₃ + 3O₂
4 : 2 : 2 : 3
From the balanced equation above, the coefficients are 4, 2, 2, 3
A careful observation of the equation shows that CO₂ and K₂CO₃ exist in ratio 2 : 2 which can be simplified as 1 : 1
Therefore, we can conclude that CO₂ and K₂CO₃ has molar ratio of 1 : 1
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Your friend has a rubber band stretched between two fingers. When you pluck the rubber band, it vibrates and makes sound. What would you have to do to make the sound a higher pitch?
To make a higher pitch, stretch the rubber band more.
To make a higher pitch, pluck the rubber band less hard.
To make a higher pitch, stretch the rubber band less.
To make a higher pitch, pluck the rubber band harder.
Answer:
I think it is To make a higher pitch, stretch the rubber band more
Explanation:
I'm not too sure. Sry if u got it wrong
Answer:
To make a higher pitch ,pluck the rubber band more
What is the current in a 120V circuit if the resistance is 20Ω?
We have: [tex]I=\frac{U}{R}=\frac{120}{20}=6A[/tex]
ok done. Thank to me :>
Answer:
The Current is 6 Ampere.
Step-by-step explanation:
Given :
[tex]\small\red\bull[/tex] Voltage = 120V[tex]\small\red\bull[/tex] Resistance = 20ΩTo Find :
[tex]\small\red\bull[/tex] CurrentUsing Formula :
[tex] \star{\small{\underline{\boxed{\sf{ I = \dfrac{V}{R}}}}}}[/tex]
[tex]\small\blue\star[/tex] I = Current[tex]\small\blue\star[/tex] V = Voltage[tex]\small\blue\star[/tex] R = ResistanceSolution :
Substituting all the given values in the formula to find Current :
[tex]{\dashrightarrow{\pmb{\sf{ I = \dfrac{V}{R}}}}}[/tex]
[tex]{\dashrightarrow{\sf{ Current = \dfrac{Voltage}{Resistance}}}}[/tex]
[tex]{\dashrightarrow{\sf{ Current = \dfrac{120}{20}}}}[/tex]
[tex]{\dashrightarrow{\sf{ Current = \cancel{\dfrac{120}{20}}}}}[/tex]
[tex]{\dashrightarrow{\sf{ Current = 6A}}}[/tex]
[tex]{\star{\underline{\boxed{\sf{\red{ Current = 6A}}}}}}[/tex]
Hence, the Current is 6 Ampere.
[tex]\rule{300}{1.5}[/tex]
What size resistor would produce a 3 amp current flow with a 12 volt battery?
Resistance = volts / amps
Resistance = 12 volts / 3 amps
Resistance = 4 Ohms
Answer: 4 Ohms
In an action-reaction pair
a. action force is exerted first
b. action force and the reaction force are equal in magnitude and act in the same direction.
c. action force and the reaction force are contact forces only.
d. action force and the reaction force act on two different objects.
Answer:
d. action force and the reaction force act on two different objects.
Hope you could understand.
If you have any query, feel free to ask.
In an action-reaction pair, action force and the reaction force act on two different objects.
What is Newton's Third Law of Motion?Newton's Third Law of Motion states that "For every action, there is an equal and opposite reaction, action and reaction act on two different bodies."
It means that equal force are act on reaction force that is it is also known as reciprocal law of motion.
When considering the options,
The first option is incorrect because action and reaction forces act simultaneously.The second option is also false because they act in opposite direction.The third option is wrong because for action-reaction force, physical contact is not necessary.So, In an action-reaction pair, action force and the reaction force act on two different objects. Thus, Option B is the correct answer.
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A rectangular room twice as long as it is wide would contain 145 square feet more if each side were one foA rectangular room twice as long as it is wide would contain 145 square feet more if each side were one foot longer. What is the length of the room
The length of the room is 96 ft.
Let L be the length of the room and W be the width of the room.
Since the length is twice its width, L = 2W.
Its area A = LW
= 2W × W
= 2W²
If each side were increased by 1 foot, then its new area is A' = (L + 1)(W + 1)
= (2W + 1)(W + 1)
= 2W² + 3W + 1
Since the room would contain 145 ft more if each side were increased by 1 foot, then its new area is A' = A + 145 = 2W² + 3W + 1
2W² + 145 = 2W² + 3W + 1
145 = 3W + 1
3W = 145 - 1
3W = 144
W = 144/3
W = 48 ft.
Since its length L = 2W, substituting W = 48 into the equation, we have
L = 2(48)
L = 96 ft
So, the length of the room is 96 ft.
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What is the anomalous expansivity of water
Answer:
The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense. The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph.
Explanation:do you want me to explain it more??
A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000 J of additional energy. If 3666.67 J of this energy must be used to overcome friction, what is the final speed of the car
The final speed of the car at the given conditions is 30.1 m/s.
The given parameters:
Mass of the car, m = 1700 kgVelocity of the car, v = 21 m/sTime of motion, t = 10 sAdditional energy provided by the engine, E₁ = 22,000 JEnergy used in overcoming friction, E₂ = 3,666.67 JThe change in the energy applied to the car is calculated as;
[tex]\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J[/tex]
The final speed of the car is calculated as follows;
[tex]\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s[/tex]
Thus, the final speed of the car at the given conditions is 30.1 m/s.
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A plane flies from New York to LA at a constant speed of 800 km an hour how long will it take the plane to fly to 4,200 kilometers
Answer:
3.5 hours
Explanation:
the graph is tied to the reading
here is the reading for the question
students in a physics class observing the race note that each runner maintains the same acceleration from the start ofthe 8.0 second interval until they each reach the finish line where each of the runners slows to a stop. Two students inthe class make the following claims about the runners’ accelerations from the start of the 8.0 second interval until bothrunners are at rest.
Student 1:“Runner A has a positive acceleration until reaching the finish line and then a negative acceleration aftercrossing the finish line in order to “undo” all of the positive velocity she gained. Since Runner B neverhad any positive acceleration, she doesn’t need any negative acceleration to slow to a stop; heracceleration will be zero the whole time.”
Student 2:“But negative values mean away south in this case – how could runner A be turning around? I think bothrunners must have positive accelerations the whole time since they are always moving north.”
For part (c), do not simple repeat the students’ arguments in your answers.
here are the questions:
i.Which aspects of student 1’s reasoning, if any, are correct? Explain your answer.
ii.Which aspects of student 1’s reasoning, if any, are incorrect? Explain your answer.
iii.Which aspects of student 2’s reasoning, if any, are correct? Explain your answer.
iv.Which aspects of student 2’s reasoning, if any, are incorrect? Explain your answer
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