A 0.100 g sample of phosphoric acid (H3PO4, MW 99.0 g/mol), a tri-protic acid, requires 35.0 mL of a NaOH solution for neutralization. What is the molarity of the NaOH solution

Answers

Answer 1

Answer:

0.0866 M

Explanation:

answer key

Answer 2

The molarity of the NaOH solution has been 0.0865 M.

The neutralization reaction of the Phosphoric acid and NaOH results in the formation of sodium phosphate and water.

The balanced chemical equation can be given as;

[tex]\rm H_3PO_4\;+\;3\;NaOH\;\rightarrow\;Na_3PO_4\;+\;3\;H_2O[/tex]

Thus for the neutralization of 1 mole of Phosphoric acid, 3 moles of NaOH has been used.

The moles of phosphoric acid in 0.100 grams sample:

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of phosphoric acid = [tex]\rm \dfrac{0.100}{99}[/tex]

Moles of phosphoric acid = 0.001 mol

For the neutralization of 0.001 moles of NaOH:

1-mole Phosphoric acid = 3 moles NaOH

0.001-mole Phosphoric acid =0.003 moles of NaOH.

The molarity of the NaOH solution:

Molarity = [tex]\rm \dfrac{moles}{Volume\;(L)}[/tex]

Molarity of NaOH = [tex]\rm \dfrac{0.003}{0.035}[/tex]

Molarity of NaOH = 0.0865 M

The molarity of the NaOH solution has been 0.0865 M.

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Hey mate.....

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This is ur answer.....

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help Plz

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Consider: How does the process of inquiry usually begin?

Recognize: What happens if a hypothesis is not supported?

Answers

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When gathering data, whether qualitative or quantitative, we can use several tools, such as: surveys, focus groups, interviews, and questionnaires. To help organize data, we can use charts and graphs to help visualize what's going on, such as bar graphs, frequency charts, picture graphs, and line graphs.

If your hypothesis is supported, you might think of ways to refine your hypothesis and test those. Either way, the process of experimentation often leads to whole new questions to explore. The possibilities are infinite, and the search for knowledge is never-ending.

The scientific method is a process that helps answer questions based on observations, carefully planned experiments and deductive reasoning. All scientific inquiry begins with the identification of a problem or question to be answered based on observation.

If the initial hypothesis is not supported, you can go back to the drawing board and hypothesize a new answer to the question and a new way to test it. ... Either way, the process of experimentation often leads to whole new questions to explore. The possibilities are infinite, and the search for knowledge is never-ending.

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Explanation:

Convert –26 degree Celsius temperature into kelvin .​

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calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units

Answers

Answer:

21.2 gm

Explanation:

calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units

butane is the hydrocarbon C4H10  

in combustion, we react hydrocarbons with O2 to form CO2 and H2O

so

C4H10  + O2---------------->  CO2 + H2O

BALANCE

2C4H10 + 1302--------> 8CO2 + 10 H2O

the molar mass of CO2 is 12 + 16X2 = 44

64.1 gm of CO2 is

64.1/44 = 1.46 MOLES OF  CO2,

FOR EVERY 8 MOLES OF CO2 WE NEED 2 MOLES OF BUTANE  IT IS A

8:2 OR 4:1 RATIO.  THE MOLES OF C4H10 ARE 1/4 THE MOLES OF CO2

SO

THE MOLES OF C4H10 H10 ARE 1.46/4 =0.365 MOLES

THE MOLAR MASS OF BUTANE IS 58.12

0.365 MOLES OF C4H10 HAS A MASS OF 0.365 X 58.12 = 21.2 gm

Calculate the normality of a solution made by diluting 12 g of H3PO4 with water to produce 250.0 mL of solution.

Answers

The  normality of a solution made by diluting 12 g of H3PO4 with water to produce 250.0 mL of solution is 1.47 eq/L.

The normality of a solution is;

N = Mass of solute in grams/volume of solution in litres × Equivalent weight

Mass of solute =  12 g

volume of solution =  250.0 mL or 0.25 L

Equivalent weight = Molar mass of H3PO4/n

n = Number of hydrogen ions in H3PO4

Equivalent weight = 98 g/mol/3 = 32.7

Substituting values;

N = 12/0.25 ×  32.7

N = 1.47 eq/L

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How many cobalt atoms are in 2 moles of cobalt?

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That means that one mole of cobalt weighs 58.9332 grams (58.9332 g/mol). Based on that information, to convert 2 moles of cobalt to grams, we multiply 2 moles of cobalt by 58.9332.

12.04428152 x [tex]10^{23}[/tex] cobalt atoms are in 2 moles of cobalt.

What are moles?

A mole is defined as 6.02214076 ×[tex]10^{23}[/tex]

of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

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12.04428152 x [tex]10^{23}[/tex]

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Count the following atoms​
NEED ANSWER ASAP ​

Answers

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Answers

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