A] 1 N2 + 3 H2 → 2 NH3

1. How many moles and grams of ammonia can be made from 6.3 moles of H2 ?

2. How many moles and particles of ammonia can be made from 2.5 moles of N2 ?

3. How many moles is 425 g of ammonia? How many moles and grams of N2 are needed to make it?

4. How many moles and grams and liters of H2 are needed to make 10 moles of ammonia?

The weight percent of each element in the compound. is given below.

The mass percent of C = 24%

The mass percent of H = 4%

The mass percent of Cl = 50%

The mass percent of N = 9.8%

The Mass percent of oxygen = 12.2%

The following formula is used to calculate the mass of each component element in a sample of the compound:

The weight of C:

In 1 mole of CO2, there is 1 mole of carbon.

In 0.138 g of CO2, there will be:

0.138 g / 44 g * 12 g = 0.0368 g

H's mass:

1 mole of H2O contains 2 moles of hydrogen.

0.0566 g of H2O will contain the following quantity of H:

0.0566 g / 18 * 2 * 1 = 0.00628 g

volume of Cl;

In 1 mole of AgCl, there is 1 mole of Cl.

In 0.251 g of AgCl, the mass of Cl will be:

0.251 g / 143.5 g * 35.5 g = 0.0621 g

N's mass:

In 1 mole of NH3, there is 1 mole of N.

In 0.251 g of NH3, the mass of N will be:

0.0238g / 17.0 g * 14 g = 0.0196 g

Each element's mass percentage will be:

Mass proportion of C:

mass percent is equal to 0.0368/0.15 * 100.

24% mass percent

Mass proportion of H:

mass percent is equal to 0.00628/0.15 * 100%.

4% mass percent

Cl mass percentage;

Mass proportion of Cl:

mass percent is equal to 0.0621/0.125 * 100%.

50% mass percentage

N mass percentage:

Mass percent is equal to 0.0196/0.2*100%.

9.8% mass percent

Oxygen mass percentage equals 100 minus (24 + 4 + 50 + 9.8)

oxygen mass percentage: 12.2%

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Answer:

Once a density has been calculated the tool will also display two conversion scales for a range of mass and volume values

Explanation:

The density of this particular liquid is [tex]5833 kg/ m^3[/tex].

Density is defined as mass per unit volume. It is a standard mechanical quantity. The most frequently used symbol for density is ρ (rho), D can also be used which is a Latin letter.

It can be expressed as

[tex]\rho ={\frac {m}{V}}\\\\\rho = density \\m = mass\\V = volume[/tex]

Density is expressed in [tex]kg/m^3[/tex] , mass in kg and volume in [tex]m^3[/tex]

For above given information,

Mass= 350 g= 0.350kg

Volume= 60ml = 0.00006 [tex]m^3[/tex] ([tex]1ml= 1/10^6 m^3[/tex])

So, Density= 0.350/0.00006 = [tex]5833 kg/m^3[/tex]

Thus, the density of this particular liquid is [tex]5833 kg/ m^3[/tex].

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Answer:

D. 1s²2s²2p 3s²3p6

Explanation:

The most chemically stable electron configuration is typically the one that has a full valence shell, which means that the outermost electron shell is completely filled with electrons. In this case, the electron configuration with a full valence shell is 1s²2s²2p 3s²3p6. This configuration is often called the "noble gas" configuration, because it is similar to the electron configuration of a noble gas, such as neon or argon, which are extremely stable and unreactive.

Given a mass of 14 g and a volume of 28 ml, the density in g/ml is

0.5 grams per cubic centimeter.

What is density in g/ml?

Density is the mass of a substance in relation to its volume. Despite the fact that the Latin letter ρ can also be used, the symbol for density that is utilized the most frequently is. The size of how tightly a cloth is packed together is called density. it's far characterized as the mass predictable with unit amount.

ρ = m/V, where m denotes the item's mass, V denotes its quantity, and m denotes its density.

According to the given question:

A material substance's density is defined as its mass per unit volume. D is density, M is mass, and V is volume, therefore the formula for density is d = M/V.

d = M/V :

- 14/28= 1/2 = 0.5 grams per cubic centimeter.

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her new network is $80.20 billion

One mole of diatomic oxygen weighs 32 grams and it contains 6.02 × 10²³ oxygen molecules. Similarly 55 grams of Fe contains 6.02 × 10²³  Fe atoms.

One mole or 27 g of Al contains 6.02 × 10²³ molecules. Hence, 3 molecules of Al weighs 1.34 × 10⁻²² g. Similarly 4 molecules of Fe weighs 1.26  × 10⁻²² g.

One mole of  every substance contains 6.02 × 10²³  atoms or molecules. This number is called Avogadro number. Hence the mass of an element or molecule containing Avogadro number of atoms is called its molar mass or atomic mass of element.

The molar mass of O₂ = 32 g/mol

Hence, number of molecules in 32 g of oxygen gas =  6.02 × 10²³

The atomic mass of Fe = 55 g

Hence, the number of molecules  =  6.02 × 10²³

One mole or 27 g of Al contains  6.02 × 10²³  molecules. Hence,  mass of 3 molecules =  (27 × 3 )/ 6.02 × 10²³  = 1.34 × 10⁻²² g

One mole or 19 g of F contains 6.02 × 10²³  molecules. Thus, mass of 4 molecules of F = (19 × 4)/ 6.02 × 10²³   = 1.26  × 10⁻²² g.

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One dose of antiacid A will neutralize more stomach acid (0.019 mol) than one dose of antacid B (0.01 mol).

Stomach acid is HCl. The reaction of HCl with each of the active ingredients of the antiacids is expressed in the following equations:

[tex]3HCl + Al(OH)_3 --- > AlCl_3 + 3H_2O[/tex].......................Eqn 1

[tex]2HCl +CaCO_3 --- > CaCl_2 + H_2O + CO_2[/tex]...................Eqn 2

In equation 1, the mole ratio of stomach acid to [tex]Al(OH)_3[/tex] is 3:1.

Mole of 0.50 g  [tex]Al(OH)_3[/tex] = 0.5/78 = 0.0064 mol

The equivalent amount of stomach acid to be neutralized = 0.0064 x 3 = 0.0192  mol

In equation 2, the mole ratio of stomach acid to [tex]CaCO_3[/tex] is 2:1.

Mole of 0.50 g  [tex]CaCO_3[/tex] = 0.5/100 = 0.005

The equivalent amount of stomach acid to be neutralized = 0.005 x 2 = 0.01 mol.

Thus, one dose of antiacid A will neutralize more stomach acid (0.019 mol) than one dose of antacid B (0.01 mol).

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Answer:

Orientation in space.

Explanation:

I had a similar question.

Answer:

Explanation:

In this figure, the six electronic structures represent the electron configurations of six different elements: Li, Be, B, C, N, and O. The correct electron configurations are shown in green, and the incorrect ones are shown in red.

In the electron configuration for Li (top left), the fault is that the 2s orbital is not completely filled. The correct electron configuration for Li should have two electrons in the 1s orbital and one electron in the 2s orbital.

In the electron configuration for Be (top center), the fault is that the 2s orbital is not completely filled. The correct electron configuration for Be should have two electrons in the 1s orbital and two electrons in the 2s orbital.

In the electron configuration for B (top right), the fault is that the 2s orbital is not completely filled. The correct electron configuration for B should have two electrons in the 1s orbital, two electrons in the 2s orbital, and three electrons in the 2p orbital.

In the electron configuration for C (bottom left), the fault is that the 2p orbital is not completely filled. The correct electron configuration for C should have two electrons in the 1s orbital, two electrons in the 2s orbital, and four electrons in the 2p orbital.

In the electron configuration for N (bottom center), the fault is that the 2p orbital is not completely filled. The correct electron configuration for N should have two electrons in the 1s orbital, two electrons in the 2s orbital, and five electrons in the 2p orbital.

In the electron configuration for O (bottom right), the fault is that the 2p orbital is not completely filled. The correct electron configuration for O should have two electrons in the 1s orbital, two electrons in the 2s orbital, and six electrons in the 2p orbital.

I hope this helps! Let me know if you have any questions or need further clarification.

In balanced chemical reaction of silver nitrate and calcium chloride the amount of the 0.005 moles of silver chloride and 0.0025 moles of calcium nitrate.

In balanced chemical reaction

2AgNO₃(aq) + CaCl₂ (aq) ⇒ 2AgCl(s) + Ca(NO₃)₂(aq)

Given :

Silver nitrate = 1.00 M

Calcium chloride = 0.100 M

In a reaction 25 moles of each reactant is mixed.

Silver nitrate = 1.00 M x25 ml /1000

Silver nitrate moles in 25 ml = 0.025

Calcium chloride = 0.100 M x 25 ml/1000

calcium chloride moles in 25 ml = 0.0025

∵ 0.0025 ml of silver nitrate requires 0.0125 moles of calcium chloride. So limiting reagent is calcium chloride.

CaCl₂      ⇒       2AgCl(s)         +       Ca(NO₃)₂

1 mole      ⇒       2 moles                   1 moles

0.0025    ⇒       0.005                      0.0025

Hence, concentration of the product depend on the limiting reagent.

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Initially the sample will be in solid form and finally it will in gaseous form.

What is melting point ?

A substance's melting point is the temperature at which it transforms from a solid into a liquid. The equilibrium between the solid and liquid phases exists at the melting point. A substance's melting point is dependent on pressure, and it is typically expressed at a standard pressure such 1 atmosphere or 100 kPa.

Melting point of nitrogen =63.15K

Boiling point of nitrogen = 77.355K

Below 63.15K it is in solid form and above this it will be in liquid form.

Below 77.355K it is in liquid form and above this it will be in gaseous form.

Initially it is 59K means in solid form.

And finally it is 129K means in gaseous form.

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The sample will first take on a solid form before transitioning to gaseous form.

What do melting and boiling points mean?

The temperature at which a substance's solid and liquid phases are in equilibrium is known as its melting point. The temperature at which a substance's vapour pressure equals the atmospheric pressure is known as the boiling point of that material.

Physical and chemical changes can cause matter to transform into different forms, but no matter what happens, matter is always conserved. There is no creation or destruction of matter; the amount of matter is the same before and after the transformation. The Law of Conservation of Mass is the name given to this idea.

Nitrogen's melting point is 63.15 K and its boiling point is 77.355K. It is solid at temperatures below 63.15K and liquid at temperatures beyond this. It has a liquid state below 77.355K and a gaseous state above this.

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Answer:

Hope this help you i try my best :)

The Order of the reaction is zero. The rate law for the reaction is rate = k[CH₃CH₂OH]⁰.  The rate constant for the reaction is 4.0 x 10⁻⁶ Ms⁻¹. the final presure is 0.8 atm.

The order of the reaction is zero. The plot on tye left is a straight line, indicating that the rate is decreasing in[ ethanol] is constant as [ ethanol ] changes. Therefore the rate of the reaction does not depend on the[ethanol] because of the order of the reaction is zero the rate law for the reaction became  rate = k[CH₃CH₂OH]⁰.

The rate constant can be calculate as follows:

rate = k = - Δ [ethanol] = - (0.0020-0.0100) mol/L

                      Δt                        2000s

rate = 4.0 x 10⁻⁶ Ms⁻¹

The final pressure is 0.080 its twice the original pressure because the product represent twice as many moles of gas as reactant

your question is incomplete but most probably your full question attached below

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Answer:

To find the mass of the solute in the solution, we first need to convert the percent to a decimal by dividing by 100. Since the percent is 4%, we can divide by 100 to get 0.04.

Next, we can multiply the decimal value by the total mass of the solute to find the mass of the solute in the solution. In this case, the total mass of the solute is 200g, so we can multiply 0.04 by 200g to get:

0.04 * 200g = 8g

Therefore, the mass of the solute in the solution is 8g.

The mass percent of each element is:

mass percent of C is 24%

mass percent of H is 4%

mass percent of Cl is 50%

mass percent of N is 9.8%

Mass percent of oxygen is 12.2%

The mass of each of the constituent elements in a sample of the compound is determined as follows:

mass of C:

1 mole of C is present in 1 mole of CO₂

The mass of C in 0.138 g of CO₂ will be:

0.138 g / 44 g * 12 g = 0.0368 g

mass of H:

2 moles of H are present in 1 mole of H₂O

The mass of H present in 0.0566 g H₂O will be:

0.0566 g / 18 * 2 * 1 = 0.00628 g

mass of Cl;

1 mole of Cl is present in 1 mole of AgCl

The mass of Cl in 0.251 g of AgCl will be:

0.251 g / 143.5 g * 35.5 g = 0.0621 g

mass of N:

1 mole of N is present in 1 mole of NH₃

The mass of N in 0.251 g of NH₃ will be:

0.0238g / 17.0 g * 14 g = 0.0196 g

Mass percent of each element will be:

mass percent of C:

mass percent = 0.0368/0.15 * 100

mass percent = 24%

mass percent of H:

mass percent = 0.00628 / 0.15 * 100%

mass percent = 4%

mass percent of Cl;

mass percent of Cl:

mass percent = 0.0621 / 0.125 * 100%

mass percent = 50%

mass percent of N:

mass percent = 0.0196 / 0.2 * 100%

mass percent = 9.8%

Mass percent of oxygen = 100 - (24 + 4 + 50 + 9.8)

Mass percent of oxygen = 12.2%

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In water, a highly soluble sodium hydroxide compound dissociates to give sodium ion and hydroxide ion as an example of an Arrhenius base.

To enhance the concentration of hydroxide ions, NaOH entirely dissolves in aqueous solution to give hydroxide ion and sodium ion. The Arrhenius theory, proposed in 1887 by the Swedish scientist Svante Arrhenius, states that acids dissolve in water to produce electrically charged atoms or molecules known as ions, one of which is a hydrogen ion (H+), and that bases ionize in water to produce hydroxide ions (OH). As a result, water is a material that dissociates in water to create H+ ions. It also meets the definition of a material that dissociates in water to create OH ions.

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BaSO4 (s) + Cu(NO3)2 (aq)  and KCl (s) + Mg3(PO4)2 (s) is the product of given precipitation reactions.

Ba(NO3)2 (aq) + CuSO4 (aq) → BaSO4 (s) + Cu(NO3)2 (aq)

 K3 PO4 (aq) + MgCl2 (aq) → KCl (s) + Mg3(PO4)2 (s)

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True. Electrolysis can be used to resolve hydrogenation pathways at palladium surfaces in a membrane reactor. It uses electro catalytic palladium membrane reactor.

Palladium surface membrane reactors use electricity to hydrogenate organic molecules at ambient temperature and pressure. These reaction conditions position ePMRs as a sustainable alternative to thermochemical hydrogenation which requires high-temperature and high-pressure reaction conditions. The electro catalytic palladium membrane reactor uses electrolysis and a hydrogen-selective palladium membrane to deliver reactive hydrogen to a catalyst surface in an adjacent compartment for reaction with an organic substrate. This process forms the requisite metal-hydride surface for hydrogenation chemistry but at ambient temperature and pressure and without a H2 source.

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The pair of coordination isomers is [Ni(NH3)3Br]Cl and [Ni(NH3)3Cl]Br.

A coordination complex is made up of a central atom or ion, which is usually metallic and is known as the coordination centre, and a ring of bound molecules or ions, which are known as ligands or complexing agents. Coordination complexes are found in many metal-containing compounds, particularly those containing transition metals.

The coordination sphere is made up of the central atom or ion and all ligands. The first coordination sphere is made up of the central atoms or ions and the donor atoms. The coordination number is the number of donor atoms attached to the central atom or ion. The most common coordination numbers are 2, 4, and 6, in particular.

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( I underlined the important part the rest is extra info that can help you understand)

Answer

Lithium is a metal (Alkali metal) it will donate one of its electrons to fluoride so then it becomes positively charged (cation).

(atoms are neutral because protons (p+) and electrons (e-) are equal taking one electron from an atom will make it positive)

Flouride is a nonmetal so it will accept the electron from lithium so then it becomes negatively charged (anion)

lithium is in group 1 so its charge is +1
Flouride is in group 17 so its charge is -1

both cancel each other so there are no subscripts

To solve this, we must be knowing each and every concept related to bond enery and enthalpy o formation. Therefore, the correct option is option C among all the given options.

Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances. Internal energy is the sum of all kinds of energy that the particles of a matter can possess, for example translational energy. Rotational energy.

Bond energy is directly proportional to the bond strength. since the bond enthalpy of H-F is the highest among all the given bond energy. H-F has the largest enthalpy of formation.

Therefore, the correct option is option C.

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Answer:

.675

Explanation:

when going down on the chart you move the decimal point to the left however many times you go down

As a result, aluminum interacts with oxygen gas to form aluminum oxide, which results in the chemical reaction 4Al+3O22Al2O3. oxygen gas.

At room temperature, oxygen is a gas that lacks all other flavors, smells, and colors. Molecular oxygen can be found in nature. To create dioxygen, often known as O2, two oxygen atoms form a covalent double bond. As a molecule, oxygen is typically present.

The reactive gas oxygen (O2) has no color or smell. A little under 21% of the oxygen is made up of it, which is the most common feature in the earth's crust and is primarily found in oxides, silica, and carbonates.

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The answer is D. moles x molar mass.

Number of moles divided by molecular weight equals the substance's mass.Since the question states that glucose has a molecular weight of 180.16, plugging in our calculations shows that we require 180.16 x 1.5 = 270.24 g of sugar.

There are numerous instruments available for determining mass in various settings.The utilization the gravitational interaction between things is one of them, along with balances and scales, measuring transducers, vibrating tubes sensors, Newtonian weight measurement devices, and balances and scales.

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Answer:

less the number of electrons

Explanation:

electrons have a negative charge

The no. of electrons needed are 3 for the following half-equation is balanced using the lowest possible whole numbers is NO three− +4H + +e − →2H 2 O+NO.

The oxidation numbers for nitrogen has been assigned.

+5N O three− +4H + +e → 2H 2 O+ +2N O

This is a discount 1/2 of equation. All atoms are balanced.

We stability prices via way of means of including the proper quantity of electrons.

NO three− +4H + +3e − →2H 2 O+NO

This is a balanced discount 1/2 of-reaction.

Thus, the quantity of electrons required to stability the equation is three.

Hence, the best choice is 3 .

The balancing steps are proven below:Some nitrogen in nitrate anion is oxidized from +three to +five in nitrate anion.Oxidation 1/2 of-reaction: NO−2(aq)→NO−three(aq)+2e−2OH−(aq)+NO−2(aq)→NO−three(aq)+2e−2OH−(aq)+NO−2(aq)→NO−three(aq)+2e−+H2O(l).

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