I haven't done these in some time, so I'm not sure if they are 100% right.
1) 6.3 moles of H2( 2 mol of NH3 / 3 mol of H2)= 4.2 mol of NH3
6.3 moles of H2( 2 mol of NH3/ 3 mol of H2)(17.04 g of NH3/1 mol NH3)= 71.57 g of NH3
2) 2.5 moles of N2(2 mol of NH3/1 mol of N2)= 5 moles of NH3
2.25 moles of N2(2 mol of NH3/ 1 mol of N2)(6.02x10^23 particles/ 1 mol of NH3)= 3.01x10^24 particles of NH3
3) 425 g of NH3(1 mol of NH3/17.04 g NH3)= 24.9 moles of NH3
425 g of NH3(1 mol of NH3/17.04 g of NH3)(1 mol of N2/2 mol of NH3)(28.02 g of N2/1 mol N2)= 349 g of N2
425 g of NH3(1 mol of NH3/17.04 g of NH3)(1 mol of N2/2 mol of NH3)= 12.5 mol of N2
4) 10 moles NH3(3 moles of H2/2 moles of NH3)= 15 moles H2
10 moles NH3(3 mol of H2/2 mol of NH3)(2.02 g of H2/1 mol of H2)= 30.3 g of H2
30.3 g = .0303 liters of H2
Which of the following electron configurations represents the most chemically stable atom?
a. 1s²2s²2p³
c. 1s22s22p 3s²3p64s²3d5
d. 1s²2s²2p 3s23p6
b. 1s²2s²2p 3s²3p5
Answer:
D. 1s²2s²2p 3s²3p6
Explanation:
The most chemically stable electron configuration is typically the one that has a full valence shell, which means that the outermost electron shell is completely filled with electrons. In this case, the electron configuration with a full valence shell is 1s²2s²2p 3s²3p6. This configuration is often called the "noble gas" configuration, because it is similar to the electron configuration of a noble gas, such as neon or argon, which are extremely stable and unreactive.
aluminum metal reacts with oxygen gas. assuming the reactants are ordered as written, the coefficients when this reaction is completed and balanced are
As a result, aluminum interacts with oxygen gas to form aluminum oxide, which results in the chemical reaction 4Al+3O22Al2O3. oxygen gas.
O2, or just O, is oxygen gas?At room temperature, oxygen is a gas that lacks all other flavors, smells, and colors. Molecular oxygen can be found in nature. To create dioxygen, often known as O2, two oxygen atoms form a covalent double bond. As a molecule, oxygen is typically present.
Is the gas oxygen (O2)?The reactive gas oxygen (O2) has no color or smell. A little under 21% of the oxygen is made up of it, which is the most common feature in the earth's crust and is primarily found in oxides, silica, and carbonates.
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Suppose that a certain fortunate person has a net worth of $77.0 billion ($ 7.70×1010 ). If her stock has a good year and gains $3.20 billion ( 3.20×109 ) in value, what is her new net worth?
Express your answer to three digits.
her new network is $80.20 billion
The active ingredient in one does of antacid A is 0.50g Al(OH)3. the active ingredient in one does of antacid B is 0.50g CaCO3. Would one does of antacid A or B neutralize more stomach acid? Explain your choice, and show a calculation to support your answer.
One dose of antiacid A will neutralize more stomach acid (0.019 mol) than one dose of antacid B (0.01 mol).
Stoichiometric problemStomach acid is HCl. The reaction of HCl with each of the active ingredients of the antiacids is expressed in the following equations:
[tex]3HCl + Al(OH)_3 --- > AlCl_3 + 3H_2O[/tex].......................Eqn 1
[tex]2HCl +CaCO_3 --- > CaCl_2 + H_2O + CO_2[/tex]...................Eqn 2
In equation 1, the mole ratio of stomach acid to [tex]Al(OH)_3[/tex] is 3:1.
Mole of 0.50 g [tex]Al(OH)_3[/tex] = 0.5/78 = 0.0064 mol
The equivalent amount of stomach acid to be neutralized = 0.0064 x 3 = 0.0192 mol
In equation 2, the mole ratio of stomach acid to [tex]CaCO_3[/tex] is 2:1.
Mole of 0.50 g [tex]CaCO_3[/tex] = 0.5/100 = 0.005
The equivalent amount of stomach acid to be neutralized = 0.005 x 2 = 0.01 mol.
Thus, one dose of antiacid A will neutralize more stomach acid (0.019 mol) than one dose of antacid B (0.01 mol).
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Three blocks of equal volume are completely submerged into water. The blocks made of different materials: aluminum, iron and lead. Which of the following is the correct statement about the buoyant force on each block? (Paluminum = 2700 kg/m', Pion = 7800 kg/m, Plead = 11300 - kg/m) (A) Faluminum > Fire > Fland (B) Faluminum < Firon Flead (D) Faluminum = Fire = Fiend (E) Faluminum > Fire
a sample of nitrogen at a pressure of 1.00 atm and a temperature of 59.0 k is heated at constant pressure to a temperature of 129 k. which of the following are true?
Initially the sample will be in solid form and finally it will in gaseous form.
What is melting point ?
A substance's melting point is the temperature at which it transforms from a solid into a liquid. The equilibrium between the solid and liquid phases exists at the melting point. A substance's melting point is dependent on pressure, and it is typically expressed at a standard pressure such 1 atmosphere or 100 kPa.
Melting point of nitrogen =63.15K
Boiling point of nitrogen = 77.355K
Below 63.15K it is in solid form and above this it will be in liquid form.
Below 77.355K it is in liquid form and above this it will be in gaseous form.
Initially it is 59K means in solid form.
And finally it is 129K means in gaseous form.
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The sample will first take on a solid form before transitioning to gaseous form.
What do melting and boiling points mean?
The temperature at which a substance's solid and liquid phases are in equilibrium is known as its melting point. The temperature at which a substance's vapour pressure equals the atmospheric pressure is known as the boiling point of that material.
Physical and chemical changes can cause matter to transform into different forms, but no matter what happens, matter is always conserved. There is no creation or destruction of matter; the amount of matter is the same before and after the transformation. The Law of Conservation of Mass is the name given to this idea.
Nitrogen's melting point is 63.15 K and its boiling point is 77.355K. It is solid at temperatures below 63.15K and liquid at temperatures beyond this. It has a liquid state below 77.355K and a gaseous state above this.
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Convert 6.75 CM toMM
Answer:
.675
Explanation:
when going down on the chart you move the decimal point to the left however many times you go down
An organic compound (CaHbNcOdCle) was synthesized and a sample of it was analyzed and found to contain only C, H, N, O, and Cl. It was observed that when a 0.150-g sample of the compound was burned, it produced 0.138 g CO2 and 0.0566 g H2O. All the nitrogen in a different 0.200-g sample of the compound was converted to NH3, which found to weigh 0.0238 g. Finally, the chlorine in a 0.125-g sample of the compound was converted to Cl- and by reacting it with AgNO3, all the chlorine was recovered as AgCl. The AgCl, when dried, was found to weigh 0.251 g. Calculate
the weight percent of each element in the compound.
The weight percent of each element in the compound. is given below.
The mass percent of C = 24%
The mass percent of H = 4%
The mass percent of Cl = 50%
The mass percent of N = 9.8%
The Mass percent of oxygen = 12.2%
The weight percent of the element in the compound?The following formula is used to calculate the mass of each component element in a sample of the compound:
The weight of C:
In 1 mole of CO2, there is 1 mole of carbon.
In 0.138 g of CO2, there will be:
0.138 g / 44 g * 12 g = 0.0368 g
H's mass:
1 mole of H2O contains 2 moles of hydrogen.
0.0566 g of H2O will contain the following quantity of H:
0.0566 g / 18 * 2 * 1 = 0.00628 g
volume of Cl;
In 1 mole of AgCl, there is 1 mole of Cl.
In 0.251 g of AgCl, the mass of Cl will be:
0.251 g / 143.5 g * 35.5 g = 0.0621 g
N's mass:
In 1 mole of NH3, there is 1 mole of N.
In 0.251 g of NH3, the mass of N will be:
0.0238g / 17.0 g * 14 g = 0.0196 g
Each element's mass percentage will be:
Mass proportion of C:
mass percent is equal to 0.0368/0.15 * 100.
24% mass percent
Mass proportion of H:
mass percent is equal to 0.00628/0.15 * 100%.
4% mass percent
Cl mass percentage;
Mass proportion of Cl:
mass percent is equal to 0.0621/0.125 * 100%.
50% mass percentage
N mass percentage:
Mass percent is equal to 0.0196/0.2*100%.
9.8% mass percent
Oxygen mass percentage equals 100 minus (24 + 4 + 50 + 9.8)
oxygen mass percentage: 12.2%
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HIGH SCHOOL CHEMISTRY #8-15
PLEASE HELP!!
One mole of diatomic oxygen weighs 32 grams and it contains 6.02 × 10²³ oxygen molecules. Similarly 55 grams of Fe contains 6.02 × 10²³ Fe atoms.
One mole or 27 g of Al contains 6.02 × 10²³ molecules. Hence, 3 molecules of Al weighs 1.34 × 10⁻²² g. Similarly 4 molecules of Fe weighs 1.26 × 10⁻²² g.
What is Avogadro number?One mole of every substance contains 6.02 × 10²³ atoms or molecules. This number is called Avogadro number. Hence the mass of an element or molecule containing Avogadro number of atoms is called its molar mass or atomic mass of element.
The molar mass of O₂ = 32 g/mol
Hence, number of molecules in 32 g of oxygen gas = 6.02 × 10²³
The atomic mass of Fe = 55 g
Hence, the number of molecules = 6.02 × 10²³
One mole or 27 g of Al contains 6.02 × 10²³ molecules. Hence, mass of 3 molecules = (27 × 3 )/ 6.02 × 10²³ = 1.34 × 10⁻²² g
One mole or 19 g of F contains 6.02 × 10²³ molecules. Thus, mass of 4 molecules of F = (19 × 4)/ 6.02 × 10²³ = 1.26 × 10⁻²² g.
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Which of the following is the Arrhenius Theory of acids and bases? O An acid dissociates in water to form Hydrogen ions (H^+) and a base dissociates in water to produce Hydroxide ions (OH^-). O An acid is a proton donor and a base is a proton acceptor. O Acids are substances with a very high pH (greater than 10) and bases are substances with a very low pH (less than 3). O None of the above.
In water, a highly soluble sodium hydroxide compound dissociates to give sodium ion and hydroxide ion as an example of an Arrhenius base.
To enhance the concentration of hydroxide ions, NaOH entirely dissolves in aqueous solution to give hydroxide ion and sodium ion. The Arrhenius theory, proposed in 1887 by the Swedish scientist Svante Arrhenius, states that acids dissolve in water to produce electrically charged atoms or molecules known as ions, one of which is a hydrogen ion (H+), and that bases ionize in water to produce hydroxide ions (OH). As a result, water is a material that dissociates in water to create H+ ions. It also meets the definition of a material that dissociates in water to create OH ions.
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Complete and balance the given precipitation reactions, including the physical states of the products as predicted by the solubility rules.
Ba(NO3)2 (aq)+ CuSO4(aq)-------->
K3 PO4 (aq)+ MgCl2 (aq)----------->
BaSO4 (s) + Cu(NO3)2 (aq) and KCl (s) + Mg3(PO4)2 (s) is the product of given precipitation reactions.
What is precipitation reactions ?Precipitation is the process of changing a dissolved substance from a super-saturated solution to an insoluble solid in an aqueous solution. Precipitate refers to the produced solid.The Ba2+ ions from the barium nitrate solution would react with the SO42- ions from the copper sulfate solution to form BaSO4, a white solid precipitate. The Cu2+ ions from the copper sulfate solution would react with the NO3- ions from the barium nitrate solution to form Cu(NO3)2, a blue solutionBa(NO3)2 (aq) + CuSO4 (aq) → BaSO4 (s) + Cu(NO3)2 (aq)
The K+ ions from the potassium phosphate solution would react with the Cl- ions from the magnesium chloride solution to form KCl, a white solid precipitate. At the same time, the Mg2+ ions from the magnesium chloride solution would react with the PO43- ions from the potassium phosphate solution to form Mg3(PO4)2K3 PO4 (aq) + MgCl2 (aq) → KCl (s) + Mg3(PO4)2 (s)
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what is the concentration of solution if absorbance is 0.02 explain
Given a mass of 14 g and a volume of 28 ml, calculate the density. g/ml (note: insert the numerical answer in standard form with the correct number of significant figures.)
Given a mass of 14 g and a volume of 28 ml, the density in g/ml is
0.5 grams per cubic centimeter.
What is density in g/ml?
Density is the mass of a substance in relation to its volume. Despite the fact that the Latin letter ρ can also be used, the symbol for density that is utilized the most frequently is. The size of how tightly a cloth is packed together is called density. it's far characterized as the mass predictable with unit amount.
ρ = m/V, where m denotes the item's mass, V denotes its quantity, and m denotes its density.
According to the given question:
A material substance's density is defined as its mass per unit volume. D is density, M is mass, and V is volume, therefore the formula for density is d = M/V.
d = M/V :
- 14/28= 1/2 = 0.5 grams per cubic centimeter.
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Sixty milliliters of a particular liquid has a mass of 350g. What is its density?
Answer:
Once a density has been calculated the tool will also display two conversion scales for a range of mass and volume values
Explanation:
The density of this particular liquid is [tex]5833 kg/ m^3[/tex].
What is Density?Density is defined as mass per unit volume. It is a standard mechanical quantity. The most frequently used symbol for density is ρ (rho), D can also be used which is a Latin letter.
It can be expressed as
[tex]\rho ={\frac {m}{V}}\\\\\rho = density \\m = mass\\V = volume[/tex]
Density is expressed in [tex]kg/m^3[/tex] , mass in kg and volume in [tex]m^3[/tex]
For above given information,
Mass= 350 g= 0.350kg
Volume= 60ml = 0.00006 [tex]m^3[/tex] ([tex]1ml= 1/10^6 m^3[/tex])
So, Density= 0.350/0.00006 = [tex]5833 kg/m^3[/tex]
Thus, the density of this particular liquid is [tex]5833 kg/ m^3[/tex].
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Which of the following compounds would have the largest enthalpy of formation? The bond energies are given in parentheses. a. H-H (436 kJ/mol) b. H-Cl (431 kJ/mol) c. H-F (567 kJ/mol) d. H-I (299 kJ/mol) e. H-Br (366 kJ/mol)
To solve this, we must be knowing each and every concept related to bond enery and enthalpy o formation. Therefore, the correct option is option C among all the given options.
What is Enthalpy?Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances. Internal energy is the sum of all kinds of energy that the particles of a matter can possess, for example translational energy. Rotational energy.
Bond energy is directly proportional to the bond strength. since the bond enthalpy of H-F is the highest among all the given bond energy. H-F has the largest enthalpy of formation.
Therefore, the correct option is option C.
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Explain how the ionic bond is formed in Lithium Fluoride.
( I underlined the important part the rest is extra info that can help you understand)
Answer
Lithium is a metal (Alkali metal) it will donate one of its electrons to fluoride so then it becomes positively charged (cation).
(atoms are neutral because protons (p+) and electrons (e-) are equal taking one electron from an atom will make it positive)
Flouride is a nonmetal so it will accept the electron from lithium so then it becomes negatively charged (anion)
lithium is in group 1 so its charge is +1
Flouride is in group 17 so its charge is -1
both cancel each other so there are no subscripts
In a second experiment, which is performed at a much higher temperature, a sample of ethanol gas and a
copper catalyst are placed in a rigid, empty 1.0 L flask. The temperature of the flask is held constant, and the
initial concentration of the ethanol gas is 0.0100 M. The ethanol begins to decompose according to the
chemical reaction represented below. CH3CH2OH(g) æCuæà CH3CHO(g) + H2(g)
The concentration of ethanol gas over time is used to create the three graphs below.
(c) Given that the reaction order is zero, one, or two, use the information in the graphs to respond to the
following
(i) Determine the order of the reaction with respect to ethanol. Justify your answer.
The order of the reaction is zero. The plot on the left is a straight 1 point is earned for the correct
line, indicating that the rate of decrease in [ethanol] is constant as choice with a valid justification. [ethanol] changes. Therefore the rate of reaction does not depend
on [ethanol].
(ii) Write the rate law for the reaction
(iii) Determine the rate constant for the reaction, including units
(d) The pressure in the flask at the beginning of the experiment is 0.40 atm. If the ethanol completely
decomposes, what is the final pressure in the flask?
Answer:
Hope this help you i try my best :)
The Order of the reaction is zero. The rate law for the reaction is rate = k[CH₃CH₂OH]⁰. The rate constant for the reaction is 4.0 x 10⁻⁶ Ms⁻¹. the final presure is 0.8 atm.
The order of the reaction is zero. The plot on tye left is a straight line, indicating that the rate is decreasing in[ ethanol] is constant as [ ethanol ] changes. Therefore the rate of the reaction does not depend on the[ethanol] because of the order of the reaction is zero the rate law for the reaction became rate = k[CH₃CH₂OH]⁰.
The rate constant can be calculate as follows:
rate = k = - Δ [ethanol] = - (0.0020-0.0100) mol/L
Δt 2000s
rate = 4.0 x 10⁻⁶ Ms⁻¹
The final pressure is 0.080 its twice the original pressure because the product represent twice as many moles of gas as reactant
your question is incomplete but most probably your full question attached below
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The positive ions carries a number of positive charges………..the number of given electrons
Answer:
less the number of electrons
Explanation:
electrons have a negative charge
What is a stem cell?
The first the principal quantum number consider what property of an electrons?
a) direction of spin
b) orientation in space
c) distance from the nucleus
Answer:
Orientation in space.
Explanation:
I had a similar question.
electrolysis can be used to resolve hydrogenation pathways at palladium surfaces in a membrane reactor. t/f
True. Electrolysis can be used to resolve hydrogenation pathways at palladium surfaces in a membrane reactor. It uses electro catalytic palladium membrane reactor.
Palladium surface membrane reactors use electricity to hydrogenate organic molecules at ambient temperature and pressure. These reaction conditions position ePMRs as a sustainable alternative to thermochemical hydrogenation which requires high-temperature and high-pressure reaction conditions. The electro catalytic palladium membrane reactor uses electrolysis and a hydrogen-selective palladium membrane to deliver reactive hydrogen to a catalyst surface in an adjacent compartment for reaction with an organic substrate. This process forms the requisite metal-hydride surface for hydrogenation chemistry but at ambient temperature and pressure and without a H2 source.
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How many mL of 0.500 M Nal would be required to make a 0.0410 M
solution of Nal when diluted to 275.0 mL with water?
If the percent (mass/mass) for a solute is 4% akd the mass of the solute is 200g, what is the mass of the solute in the solution?
Answer:
To find the mass of the solute in the solution, we first need to convert the percent to a decimal by dividing by 100. Since the percent is 4%, we can divide by 100 to get 0.04.
Next, we can multiply the decimal value by the total mass of the solute to find the mass of the solute in the solution. In this case, the total mass of the solute is 200g, so we can multiply 0.04 by 200g to get:
0.04 * 200g = 8g
Therefore, the mass of the solute in the solution is 8g.
What would the answer be?
Which one of the following options give the correct procedure to calculate the mass of a substance if number of moles are given? A moles / molar mass B. molar mass /mole C none of them D. moles x molar mass
The answer is D. moles x molar mass.
How do we determine a substance's mass?
Number of moles divided by molecular weight equals the substance's mass.Since the question states that glucose has a molecular weight of 180.16, plugging in our calculations shows that we require 180.16 x 1.5 = 270.24 g of sugar.
What are the three methods for determining mass?There are numerous instruments available for determining mass in various settings.The utilization the gravitational interaction between things is one of them, along with balances and scales, measuring transducers, vibrating tubes sensors, Newtonian weight measurement devices, and balances and scales.
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How many electrons are needed when the following half-equation is balanced using the lowest possible whole numbers? no3 (aq) h (aq) - -> no(g)
The no. of electrons needed are 3 for the following half-equation is balanced using the lowest possible whole numbers is NO three− +4H + +e − →2H 2 O+NO.
The oxidation numbers for nitrogen has been assigned.
+5N O three− +4H + +e → 2H 2 O+ +2N O
This is a discount 1/2 of equation. All atoms are balanced.
We stability prices via way of means of including the proper quantity of electrons.
NO three− +4H + +3e − →2H 2 O+NO
This is a balanced discount 1/2 of-reaction.
Thus, the quantity of electrons required to stability the equation is three.
Hence, the best choice is 3 .
The balancing steps are proven below:Some nitrogen in nitrate anion is oxidized from +three to +five in nitrate anion.Oxidation 1/2 of-reaction: NO−2(aq)→NO−three(aq)+2e−2OH−(aq)+NO−2(aq)→NO−three(aq)+2e−2OH−(aq)+NO−2(aq)→NO−three(aq)+2e−+H2O(l).
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2AgNO3(aq) +CaCl2(aq)--> 2AgCl(s) + Ca(NO3)2(aq) You have a 1.00 M solution of silver nitrate and a 0.100 M solution of calcium chloride. Following the above reaction, you react 25.00 mL of each solution. What is the theoretical yield of solid? (Note: MW of AgCl = 143.32 g/mol)
In balanced chemical reaction of silver nitrate and calcium chloride the amount of the 0.005 moles of silver chloride and 0.0025 moles of calcium nitrate.
In balanced chemical reaction
2AgNO₃(aq) + CaCl₂ (aq) ⇒ 2AgCl(s) + Ca(NO₃)₂(aq)
Given :
Silver nitrate = 1.00 M
Calcium chloride = 0.100 M
In a reaction 25 moles of each reactant is mixed.
Silver nitrate = 1.00 M x25 ml /1000
Silver nitrate moles in 25 ml = 0.025
Calcium chloride = 0.100 M x 25 ml/1000
calcium chloride moles in 25 ml = 0.0025
∵ 0.0025 ml of silver nitrate requires 0.0125 moles of calcium chloride. So limiting reagent is calcium chloride.
CaCl₂ ⇒ 2AgCl(s) + Ca(NO₃)₂
1 mole ⇒ 2 moles 1 moles
0.0025 ⇒ 0.005 0.0025
Hence, concentration of the product depend on the limiting reagent.
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From the following pairs of coordination complexes, identify which are pairs of coordination isomers. Select all that apply.
Group of answer choices Na2[NiCl2Br2] and Na2[NiBr2Cl2]
[Ni(NH3)3Br]Cl and [Ni(NH3)3Cl]Br
[Ni(NH3)3(H2O)]SO4 and [Ni(NH3)2(H2O)2]SO4
The pair of coordination isomers is [Ni(NH3)3Br]Cl and [Ni(NH3)3Cl]Br.
A coordination complex is made up of a central atom or ion, which is usually metallic and is known as the coordination centre, and a ring of bound molecules or ions, which are known as ligands or complexing agents. Coordination complexes are found in many metal-containing compounds, particularly those containing transition metals.
The coordination sphere is made up of the central atom or ion and all ligands. The first coordination sphere is made up of the central atoms or ions and the donor atoms. The coordination number is the number of donor atoms attached to the central atom or ion. The most common coordination numbers are 2, 4, and 6, in particular.
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An organic compound (CaHbNcOdCle) was synthesized and a sample of it was analyzed and found to contain only C, H, N, O, and Cl. It was observed that when a 0.150-g sample of the compound was burned, it produced 0.138 g CO2 and 0.0566 g H2O. All the nitrogen in a different 0.200-g sample of the compound was converted to NH3, which found to weigh 0.0238 g. Finally, the chlorine in a 0.125-g sample of the compound was converted to Cl- and by reacting it with AgNO3, all the chlorine was recovered as AgCl. The AgCl, when dried, was found to weigh 0.251 g. Calculate the weight percent of each element in the compound.
The mass percent of each element is:
mass percent of C is 24%
mass percent of H is 4%
mass percent of Cl is 50%
mass percent of N is 9.8%
Mass percent of oxygen is 12.2%
What is the mass of each of the constituent elements in a sample of the compound?The mass of each of the constituent elements in a sample of the compound is determined as follows:
mass of C:
1 mole of C is present in 1 mole of CO₂
The mass of C in 0.138 g of CO₂ will be:
0.138 g / 44 g * 12 g = 0.0368 g
mass of H:
2 moles of H are present in 1 mole of H₂O
The mass of H present in 0.0566 g H₂O will be:
0.0566 g / 18 * 2 * 1 = 0.00628 g
mass of Cl;
1 mole of Cl is present in 1 mole of AgCl
The mass of Cl in 0.251 g of AgCl will be:
0.251 g / 143.5 g * 35.5 g = 0.0621 g
mass of N:
1 mole of N is present in 1 mole of NH₃
The mass of N in 0.251 g of NH₃ will be:
0.0238g / 17.0 g * 14 g = 0.0196 g
Mass percent of each element will be:
mass percent of C:
mass percent = 0.0368/0.15 * 100
mass percent = 24%
mass percent of H:
mass percent = 0.00628 / 0.15 * 100%
mass percent = 4%
mass percent of Cl;
mass percent of Cl:
mass percent = 0.0621 / 0.125 * 100%
mass percent = 50%
mass percent of N:
mass percent = 0.0196 / 0.2 * 100%
mass percent = 9.8%
Mass percent of oxygen = 100 - (24 + 4 + 50 + 9.8)
Mass percent of oxygen = 12.2%
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Please, help me with this question !! Thank you so much.
Translation in the picture:
Among the 6 electronic structures, there is only one that is correct, in 5 that remain, each one has one fault, then directly to the figure, make a round around each fault (I've circled it, but I don't know how to explain it simply most), and give a simple explanation of what is the fault. (Answer in English)
Answer:
Explanation:
In this figure, the six electronic structures represent the electron configurations of six different elements: Li, Be, B, C, N, and O. The correct electron configurations are shown in green, and the incorrect ones are shown in red.
In the electron configuration for Li (top left), the fault is that the 2s orbital is not completely filled. The correct electron configuration for Li should have two electrons in the 1s orbital and one electron in the 2s orbital.
In the electron configuration for Be (top center), the fault is that the 2s orbital is not completely filled. The correct electron configuration for Be should have two electrons in the 1s orbital and two electrons in the 2s orbital.
In the electron configuration for B (top right), the fault is that the 2s orbital is not completely filled. The correct electron configuration for B should have two electrons in the 1s orbital, two electrons in the 2s orbital, and three electrons in the 2p orbital.
In the electron configuration for C (bottom left), the fault is that the 2p orbital is not completely filled. The correct electron configuration for C should have two electrons in the 1s orbital, two electrons in the 2s orbital, and four electrons in the 2p orbital.
In the electron configuration for N (bottom center), the fault is that the 2p orbital is not completely filled. The correct electron configuration for N should have two electrons in the 1s orbital, two electrons in the 2s orbital, and five electrons in the 2p orbital.
In the electron configuration for O (bottom right), the fault is that the 2p orbital is not completely filled. The correct electron configuration for O should have two electrons in the 1s orbital, two electrons in the 2s orbital, and six electrons in the 2p orbital.
I hope this helps! Let me know if you have any questions or need further clarification.