F = ma
= 10kg × 2m/s
= 20N
Answer : 20N
Explanation :
F = Force (N)
m = mass (kg)
a = acceleration (m/s)
which number is larger value : 5.6*10^23 or 8.9*10^6
Need Help
Answer:
5.6*10^23. if 10^n is greater, that means its the larger value. hope dis helps
Explanation:
A crate is being pulled down an incline as shown in the figure. With respect to the crate's direction of motion, which of the following forces does only negative work on the crate?
Answer:Fn
Explanation:
tenses of
write=
read=
Answer:
present
Explanation:
read doesn't change but write is in present tense
3) A school bus traveling at 12 m/s has a momentum of 144,000 kg.m/s.
What is the mass of the bus?
Answer:
does this have picture so I can solve
The mass is 12,000
144,000 divided by 12 = 12,000
Momentum = mass × velocity
Brainliest would be appreciated. :)
If 200 ml of a gas at 27 degrees celsius is cooled to -33 degrees Celsius at a constant pressure , the volume will be
A 250ml
B 204ml
C 196ml
D 160ml
Given that,
Volume of gas, V₁ = 200 mL
Initial temperature, T₁ = 27°C
Final temperature, T₂ = -33°C
To find,
New volume of the gas.
Solution,
Initial temperature, T₁ = 27°C = 300 K
Final temperature, T₂ = -33°C = 240 K
Let V₂ is the new volume.
The relation between volume and temperature is given by :
[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\=\dfrac{200\times 240}{300}\\\\=160\ mL[/tex]
Hence, the volume will be 160 mL.
Help i will do anything for this. its a serious grade
Answer: 10 has more potential energy because its longer
1 has less potential energy because its shorter
Explanation:
Potential energy directly depends on height of body as
[tex]\\ \sf\longmapsto P.E=mgh[/tex]
[tex]\\ \sf\longmapsto P\propto h[/tex]
Higher the height higher the potential energy
Object at height 10m has more potential energy.
An object that falls and accelerates solely as a result of gravity is said to be in
(2 points)
A. terminal velocity
B. free fall
C. air resistance
D. terminal acceleration
where is the centre of mass of a system of two particles is situated?
Answer:
In a two particle system, the center of mass lies on the center of the line joining the two particles.
A billiard ball moving at 5 m/s strikes another ball which is initially at rest. After the collision, the first ball moves at a velocity of 4.35 m/s at an angle of 30o below its original motion. Find the velocity and angle of the second ball after the collision. Assume that the collision is perfectly elastic.
Answer:
The velocity of the second ball is approximately 2.588 m/s
The angle direction of the second ball is 75° counterclockwise from the horizontal
Explanation:
The initial velocity of the first billiard ball = 5 m/s
The initial velocity of the billiard ball the first billiard ball strikes = 0 m/s
The final velocity of the first billiard ball = 4.35 m/s
The final direction of motion of the first billiard ball = 30° below its original motion
For perfectly elastic collision, whereby the target is at rest initially, by conservation of momentum, we have;
m₁ × [tex]\underset{v_1}{\rightarrow}[/tex] = m₁·[tex]\underset{v'_1}{\rightarrow}[/tex] + m₂·[tex]\underset{v'_2}{\rightarrow}[/tex]
Which gives;
m₁ × 5·i = m₁·((√3)/2×5·i - 2.5·j) + m₂·[tex]\underset{v'_2}{\rightarrow}[/tex]
∴ m₂·[tex]\underset{v'_2}{\rightarrow}[/tex] = m₁ × 5·i - m₁·((√3)/2×5·i - 2.5·j)
m₂·[tex]\underset{v'_2}{\rightarrow}[/tex] = m₁ × 5·(1 - √3/2)·i + m₁·2.5·j = m₁ × 2.5·(2 - √3)·i + m₁·2.5·j
Therefore, given that the mass of both billiard balls are equal, we have, m₁ = m₂, which gives;
m₂·[tex]\underset{v'_2}{\rightarrow}[/tex] = m₁·[tex]\underset{v'_2}{\rightarrow}[/tex] = m₁ × 2.5·(2 - √3)·i + m₁·2.5·j
∴ [tex]\underset{v'_2}{\rightarrow}[/tex] = 2.5·(2 - √3)·i + 2.5·j
The magnitude of the velocity of the second ball is [tex]\underset{v'_2}{\rightarrow}[/tex] = √((2.5·(2 - √3))² + 2.5²) ≈ 2.588 m/s
The direction of the second ball, θ = arctan(2.5/((2.5·(2 - √3))) = 75° counterclockwise from the horizontal.
A train going 14m/s moves 250 m while accelerating to a stop. What is the train’s deceleration?
Answer:
-0.056 is the deceleration
an object has an mass of 15 kg and is falling at a rate of 2.0 m/s what is the momentum?
Answer:
30 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 15 × 2
We have the final answer as
30 kg.m/sHope this helps you
Can u anser 5,6 on the picture
Answer: Number 6 is Periods
Explanation:
how much force would be needed to move a 100 kg object at the acceleration rate of 2 m/s
Answer: 200 N
Hope this helps! :)
A student releases a marble from the top of a ramp and the marble increases speed steadily and travels 190 cm in 4.10 s what's the marbles final speed
Answer:
The value is [tex]v = 92.68 \ cm/s[/tex]
Explanation:
From the question we are told that
The distance traveled is [tex]d = 190 \ cm = 1.9 \ m[/tex]
The time taken is [tex]t = 4.10 \ s[/tex]
Generally from kinematic equation we have that
[tex]s = ut + \frac{1}{2} at^2[/tex]
Here u is the initial velocity of the marble and the value is [tex]u = 0 \ m/s[/tex]
So
[tex]1.90 = 0* t + \frac{1}{2} a (4.10 )^2[/tex]
=> [tex]1.90 = 0* t + \frac{1}{2} a (4.10 )^2[/tex]
=> [tex]a = 0.226 \ m/s^2[/tex]
Generally from kinematic equations we have that
[tex]v = u + at[/tex]
=> [tex]v = 0 +0.226 * 4.10[/tex]
=> [tex]v =0.9268 \ m/s[/tex]
Converting to cm/s
=> [tex]v =0.9268 * 100[/tex]
=> [tex]v = 92.68 \ cm/s[/tex]
If it requires E joules of energy to raise a mass from the surface of the Earth to an altitude of 6,000 km above the Earth, how much energy is required to raise it from the surface to an altitude of 12,000 km?
Answer:
To raise the mass to an altitude of 12,000 Km 2E joules are required.
Explanation:
Gravitational Potential Energy
It's the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where:
m = mass of the object
h = height with respect to a fixed reference
g = acceleration of gravity, or [tex]9.8 m/s^2[/tex].
If a mass has a height h1, its potential energy is
[tex]U_1=m.g.h_1[/tex]
If a mass has a height h2, its potential energy is
[tex]U_2=m.g.h_2[/tex]
The ratio of both potential energies is:
[tex]\displaystyle \frac{U_2}{U_1}=\frac{m.g.h_2}{m.g.h_1}[/tex]
Simplifying:
[tex]\displaystyle \frac{U_2}{U_1}=\frac{h_2}{h_1}[/tex]
Solving for U2:
[tex]\displaystyle U_2=U_1.\frac{h_2}{h_1}[/tex]
Since U1=E:
[tex]\displaystyle U_2=E.\frac{12,000~Km}{6,000~Km}[/tex]
[tex]U_2 = 2E[/tex]
To raise the mass to an altitude of 12,000 Km 2E joules are required.
4. Bob creates his personal profile collage by drawing his favorite things. This is his ___________.
A. artistic self
B. social self
C. professional self
D. private self
Explain why different types of musical instruments sound different, even though they play the same notes.
There is an accident up the road from your car. You see other cars ahead of you. Who will stop first?
A fully-loaded big rig truck
An empty truck
A midsized van
A small car
Answer:
According to the 2010 U.S. Census, there are approximately 8 million people living in Virginia. This is 2.8 million less than 4 times the population of Nevada.
What is the population of Nevada?
The first step is to on both sides.
The second step is to on both sides.
The population of Nevada is million.
Explanation:
why is physics to study the heat absorbed by the ocean
Answer:
Heat is a source of energy
Explanation:
Just took the test
An electrically charged atom is called an
Answer:
It's called an ion. Excuse me if I'm wrong.
Explanation:
A skier skids to a stop at the bottom of a mountain.
What is the equal and opposite force for the force of the skier's friction pushing on the mountain as
described by Newton's third law?
Answer:
Friction of the mountain on the skier in the opposite direction
Explanation:
answered it on khan academy
Friction of the mountain on the skier in the opposite direction.
What is Newton's third law?A force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions.
Forces result from contact interactions (normal, frictional, tensional, and applied forces are examples of contact forces) and other forces are the result of action-at-a-distance interactions (gravitational, electrical, and magnetic forces).
There are two forces resulting from this interaction - a force on the chair and a force on your body. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.
Therefore, Friction of the mountain on the skier in the opposite direction.
To learn more about Friction, refer to the link:
https://brainly.com/question/13000653
#SPJ6
Question 6 of 15
6
The rate at which work is done is called power.
O A True
O B. False
I believe it’s true?
Answer: A) True, you are correct
==================================================
Explanation:
Power in physics is defined as
power = (change in work)/(change in time)
which shows that power is basically the rate of work done. We can think of it like a speed of sorts.
------------
For example, if you apply 100 joules of work over 2 seconds, then,
power = (100 joules)/(2 seconds)
power = (100/2) joules per second
power = 50 watts
A watt is defined to be a joule per second, and it's often used to measure how much electricity is consumed, but it has broader uses in physics as well.
how many teeth shows signs of decay?
Answer:
what do you mean
Explanation:
can you answer the b. thanks
Answer:
current going into a junction in a circuit is EQUAL TO the current comming out of the junction.
Explanation:
Krichhoff's Current Law
Kirchhoff's current law (1st Law) states that current flowing into a node (or a junction) must be equal to current flowing out of it.
a force of 50 newtons pulls a rope attached to a 150 newton sled across a horizontal surface at a constant velocity of 5 meters per second. The rope is at an angle of 35 degrees above the horizontal. calculate the magnitude of the frictional force acting on the sled? Show all work, including the equation and substitution with units.
Answer:
I don't know the answer I hope you find it tho good luck##
What disease did Isaac Newton barely escape?
Answer:
the great plague
Explanation:
A shopper in a supermarket pushes a cart with a force of 35 N directed parallel to the ground. Find the work done by the shopper on the cart as the shopper moves along a 50.0 m length of aisle.
Answer:
W = 1750 N
Explanation:
Given that,
A shopper in a supermarket pushes a cart with a force of 35 N directed parallel to the ground.
We need to find the work done by the shopper on the cart as the shopper moves along a 50.0 m length.
Let W is the work done. As the force is parallel to the ground, angle between force and distance is 0 degrees.
W = Fd
W = 35 N × 50 m
= 1750 N
So, the work done by the shopper on the cart is 1750 N.
A shopper in a supermarket pushes a loaded 32 kg cart with a horizontal force of 12 N.
a) How far will the cart move in 3.5 s, staring from rest? (Disregard any friction)
b) How far will the cart move in 3.5 s if the shopper places an 85 N child in the cart before pushing?
Answer: A
Explanation:
a snowball thrown at an ice cream truck at Valley Forge in January sticks to the side. Into what form of energy was the mechanical energy changed
Answer:
Thermal Energy
Explanation:
I majored in Physics
When a snowball thrown at an ice cream truck at Valley Forge in January sticks to the side, the mechanical energy was changed into thermal energy.
What is law of conservation of energy?
Energy cannot be created or destroyed, according to the rule of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present.
The law of energy conservation is adhered to by all energy forms. The law of conservation of energy essentially says that all energy is conserved in closed systems, or systems that are isolated from their surroundings.
When a snowball thrown at an ice cream truck at Valley Forge in January, the mechanical energy was changed into thermal energy and the edges of the ice melts and again due to temperature of the surrounding they freezes together and the snowball sticks to the side.
Learn more about energy here:
https://brainly.com/question/1932868
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A 5-kg object is sliding to the right and encountering a friction force that slows it down. The coefficient of friction (μ) between the object and the surface is 0.1. What is the acceleration of the object? Note: There is no applied force here.
Answer:
The friction force is 4.9 N
[tex]a = 0.98\ m/s^2[/tex]
Explanation:
Friction Force
When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration or speed because the friction force opposes motion.
The friction force when an object moves on a horizontal surface is calculated by:
[tex]Fr=\mu N[/tex]
Where [tex]\mu[/tex] is the coefficient of static or kinetics friction and N is the normal force.
If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:
N = W = m.g
Thus, the friction force is:
[tex]Fr=\mu W[/tex]
The object has a mass of m=5 Kg, calculate the weight:
W = 5 * 9.8 = 49 N
It encounters a friction force that slows it down. We are given the coefficient of friction μ = 0.1, thus the friction force is:
Fr=0.1 49 N = 4.9 N
The friction force is 4.9 N
Since the only force acting on the object is the friction force, thus the net force is F = 4.9 N, and the acceleration can be calculated by using the equation of Newton's second law:
F = m.a
Solving for a:
[tex]\displaystyle a = \frac{F}{m}[/tex]
[tex]\displaystyle a = \frac{4.9}{5}[/tex]
[tex]\mathbf{a = 0.98\ m/s^2}[/tex]