A 1.41-kg block slides across a rough surface such that it slows down with an acceleration of 1.10 m/s2. What is the coefficient of kinetic friction between the block and the surface

Answers

Answer 1

The coefficient of kinetic friction between the block and the surface is 0.11.

The coefficient of kinetic friction can be found using the equation:

friction = force of friction = coefficient of kinetic friction * normal force

The normal force is equal to the weight of the object, which can be calculated as weight = mass * acceleration due to gravity

The force of friction can be calculated using the equation:

friction = force of friction = coefficient of kinetic friction * weight

The coefficient of kinetic friction can be found by rearranging the equation and substituting the known values:

coefficient of kinetic friction = friction / weight

= (1.10 m/s2) / (1.41 kg * 9.8 m/s2)

= 0.11

So, the coefficient of kinetic friction between the block and the surface is 0.11.

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Related Questions

PLEASE HELP!!! Which phase change occurs when steam is cooled to 100°C?
condensation
boiling
sublimation
evaporation

The amount of energy needed to change a liquid into a gas, without changing its temperature, is known as the __________.
heat of sublimation
heat of fusion
specific heat
heat of vaporization

In which phase change are hydrogen bonds formed?
boiling
sublimation
evaporation
freezing

The specific heat of a substance is 0.215 J/g°C. How much energy is required to raise the temperature of 20 g of the substance from 72°C to 88°C?
68.8 J
323.4 J
4.3 J
3.4 J

Answers

The first question is asking which phase change occurs when steam is cooled to 100°C. The answer is condensation.

The second question is asking for the term that refers to the amount of energy needed to change a liquid into a gas, without changing its temperature. The answer is heat of vaporization.

The third question is asking in which phase change hydrogen bonds are formed. The answer is freezing.

The fourth question is asking for the amount of energy required to raise the temperature of 20 g of a substance from 72°C to 88°C, given that the specific heat of the substance is 0.215 J/g°C. To solve this problem, you can use the formula Q = m * c * delta T, where Q is the energy required, m is the mass of the substance, c is the specific heat, and delta T is the change in temperature. Plugging in the given values, you get Q = 20 g * 0.215 J/g°C * (88°C - 72°C) = 68.8 J. Therefore, the answer is 68.8 J.

Two small objects carry the same amount of charge, and the magnitude of the electric force exerted by one object on the other is 0.10 N when they are held 30 mm apart. If the force magnitude increases when the objects are released and free to move, are the objects of the same charge or opposite charge?

Answers

The objects must be of opposite charge because the electric force of attraction between them increases when they are released and free to move.

This means that the electric force must be a repulsive force that pushes the objects away from each other. Opposite charges attract and as charges repel, the objects must be of opposite charge for the electric force to increase when the objects are released and free to move.

Therefore when two small objects carry the same amount of charge, the magnitude of the electric force exerted by one object on the other is 0.10 N when they are held 30 mm apart. If the force magnitude increases when the objects are released and free to move, then we can say that they are opposite charges.

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A block-spring system vibrating on a frictionless, horizontal surface with an amplitude of 6.0 cm has a total energy of 12 J. If the block is replaced by one having twice the mass of the original block and the amplitude of the motion is again 6.0 cm, what is the energy of the more massive system

Answers

In this spring-mass system, the total energy equals the elastic potential energy at the moment the mass is temporarily at rest at x = A = 6 cm (i.e., at the extreme ends of the simple harmonic motion).

Thus, E kA2 2 and we see that as long as the spring constant k and the amplitude A remain unchanged,

the total energy is unchanged. Hence, the energy is still 12 J.

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What is the relationship between the mass of an object and the amount of thermal energy an object has?

Answers

The greater the mass of an object, the more particles there are in the sample and the more thermal energy it possesses at the same temperature. Assume you have some boiling hot water at 100 degrees Celsius to demonstrate this concept.

What is thermal energy and what are some examples?

Thermal energy is shown by boiling water on a stove. Thermal energy is created when the atoms and molecules of a material vibrate faster as the temperature rises.

What is an example of a mass?

Mass is best defined as the quantity of matter contained in any item or body. Everything in our environment has mass. For example, a table, a chair, your bed, a football, a glass, and even air has mass. That being said, all objects are light or heavy because of their mass.

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where does sound travel faster(the desert or the forest)?

Answers

Answer:

forest

Explanation:

cause of the echo

Answer:

forest

Explanation:

very spacious enough to make echo

A skier is pushed from the top of a hill so that he starts moving down the hillside from a height of 100 m with
an initial speed of 0.434 m/s. After traveling 80.4 m, he reaches the bottom of the valley. Due to inertia, he
then continues 70.4 m up another hillside (y = 40 m) and crashes into a snow bank that compressess like a
spring (k = 50 N/m). What is the skiers speed as he crashes into the snow bank? How far does the snow
compress? Assume that you can neglect friction.

Answers

Speed as the skier crashes into the snow bank: 0.434 m/s

Distance the snow compresses: 1.544 m

The speed of the skier as he crashes into the snow bank is the initial speed since there is no acceleration due to the lack of friction. The distance the snow compresses is calculated using the following equation:

compression = (mass x velocity2) / (2 x spring constant)

Therefore, compression = (75 kg x 0.4342) / (2 x 50 N/m) = 1.544 m

1 pts What is the work required to raise a 25.0 kg object from the surface of the Earth to a height of 3.33 m

Answers

The work required to raise a 25.0 kg object from the surface of the earth to a height of 3.33 m

Formula: F = 25.0, D = 3.33, and W =?

W = F x D

Putting values together equals 25.0 x 3.33 W = 83.25 j.

Work = force times distance, or W = Fd.

F = W/d for force

Distance: W/F = d

W = work, F = force, and D = distance.

The integral of such a force applied over a displacement distance is referred to as "work." When one engages in work, they are doing something that requires them to use their strength or force.

When energy is transferred to an item, it is considered to have undergone work in science.

The integral of such a force applied over a displacement distance is referred to as work. When one engages in work, they are doing something that requires them to use their strength or force.

When energy is transferred to an item, it is considered to have undergone work in science.

The physics formula for work

The physics equation or formula is:

W = Fd

Work (force times distance)

For force, F = W/d.

Distance: W/F = d

The scalar dot product of force and displacement also yields work.

FDCos = W

Work-related SI unit :

Joule is the SI unit of work (J). The work performed by a force of one newton operating over a distance of one meter is defined as one joule in this context. kgm2s-2 is the SI base unit of work.

Work can be defined as the quantity of energy that a force transfers. Calculate work Another name for physics is the joule calculator. Work is represented by the letter "W."

Work is defined as a motion that is caused by a resisting force and is quantified by the force's product into the motion component that is resolved in the force's direction. The size of it is ML2T-2.

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4. A railcar of mass m and speed v collides and sticks to another identical, stationary railcar. The speed of the center of mass of the two-railcar system will be

Answers

The required speed of the centre of mass of the two-railcar system after the collision will be half as much as it was before the collision.

One of the railroads has zero motion prior to the collision. Following it, both railroads move at the same speed. By the conservation of the total momentum of the system, we have,

m vi = m vf + m vf

m vi = 2 m vf

vi = 2 vf

vf = 1/2 vi

vf is the velocity after collision

vi is the velocity before collision

Thus, the speed of the railroad together after the collision is calculated to be half of that before collision.

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Burning coal yields about 30 X 106 J of energy per kilogram of coal burned. Assuming that the coal power plant is 30% efficient, how much coal has to be burned to light that light bulb for one day

Answers

1 kilogramme of coal can provide 8 kWh of heat, hence power output here =30x8x10e6/1day =30x8x10e6x24 hours=2.7e15 joules

what is coal used for ?

In the United States, coal is largely utilised as a fuel to create electricity. Bituminous coal, subbituminous coal, or lignite are burnt in coal-fired power plants. The heat generated by coal combustion is utilised to turn water into high-pressure steam, which powers a turbine and generates electricity. According to the US Energy Information Administration, coal-fired power stations provided around 23% of all energy in the United States in 2019.

Steel may also be made from certain kinds of bituminous coal. Coal used to make steel must have a high carbon content while being low in moisture, ash, sulphur, and phosphorus. Metallurgical coal is coal that fits certain requirements.

1 kilogramme of coal can provide 8 kWh of heat, hence power output here =30x8x10e6/1day =30x8x10e6x24 hours=2.7e15 joules

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A rope of length L is attached to a support at point C. A person of mass m, sits on a ledge at position Aholding the other end of the rope so that its horizontal and taut, as shown above. The person then dropsoff the ledge and swings down the rope toward position B on the lower ledge where an object withmass m₂ is at rest. At position B the person grabs hold of the object and simultaneously lets go of therope. The person and object then land together in the lake at point D, which is a vertical distance Lbelow position B. Air resistance and mass of the rope are negligible. Derive expressions for each of thefollowing in terms of m₁, m₂, L, and g.

Answers

Insignificant are air resistance and rope mass. Point C on a support is where a rope of length L is fastened.

What is meant by mass?As a measure of inertia, which is a characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body.The amount of matter that makes up any object or body is best referred to as its mass. All of the objects we perceive have mass. There is mass in objects like tables, chairs, beds, footballs, glasses, and even air. As a result, every object has a mass, which determines whether it is light or heavy.The amount of matter in a thing is measured by its mass.

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Select the correct answer from each drop-down menu. steel is an alloy of . one of the main reasons steel is used more widely than iron is because it’s than iron.

Answers

Steel is an alloy of iron and carbon. One of the main reasons steel is used more widely than iron is that it’s stronger than iron.

Steel, unlike other forms of iron, is strengthened by the addition of carbon, making it more resistant to fracture. Additional components are possible or even expected. To prevent corrosion and oxidation, stainless steels typically contain an extra 11% chromium. Steel's low price and high tensile strength make it a popular material for many different types of construction, as well as for transportation, manufacturing, and defense. Cast iron is the primary component of steel. It can crystallize in either a body-centered cubic or a face-centered cubic form, depending on the temperature. Steel and cast iron are characterized by a wide variety of properties due to the interaction of iron's various allotropes with the alloying elements, most notably carbon.

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At t = 0, a wheel rotating about a fixed axis at a constant angular acceleration of -0.40 rad/s2 has an angular velocity of 1.5 rad/s and an angular position of 2.3 rad. what is the angular position of the wheel at t = 2.0 s?

Answers

At t = 0, the wheel has an angular position of 2.3 rad and an angular velocity of 1.5 rad/s.

Since the wheel is rotating about a fixed axis at a constant angular acceleration of -0.40 rad/s2, we can use the equation for angular position to calculate the wheel's angular position at t = 2.0 s.

Angular position = initial angular position + (initial angular velocity × time) + (1/2 ×angular acceleration ×time²)

Angular position at t = 2.0 s = 2.3 rad + (1.5 rad/s × 2.0 s) + (1/2 ×-0.40 rad/s2 × (2.0 s)²)

Angular position at t = 2.0 s = 2.3 rad + 3.0 rad + -1.6 rad

Angular position at t = 2.0 s = 3.7 rad

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an object with mass m is dropped from rest, one model for its speed v after t seconds, taking air resistance into account, is

Answers

The required lim t → ∝ v(t) when an object is dropped from rest is calculated to be mg/c.

Given that,

An object with mass m is dropped from rest and taking air resistance into account.

The velocity as a function of time is,

v(t) = (m g)/c [ 1 - e^-(ct/m)]

v(t) = (m g)/c [ 1 - 1/e^(ct/m)]

lim t → ∝ v(t) = (m g)/c [ 1 - 1/∝]

lim t → ∝ v(t) = (m g)/c ( 1 - 0)

lim t → ∝ v(t) = (m g)/c

Thus, the required lim t → ∝ v(t) when an object is dropped from rest is calculated to be mg/c.

The question is incomplete. The complete question is 'v = mg c (1 − e−ct/m) where g is the acceleration due to gravity and c is a positive constant describing air resistance. (a) Calculate lim t→∞ v.'

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A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision.

Answers

The final velocity of the red-blue carts system is 5 cm/s.

What is the final speed of the two carts after collision?

The final speed of the two carts, that is the red cart and the blue cart system after the collision is calculated by applying the principle of conservation of linear momentum.

Pi = Pf

m₁u₁ + m₂u₂ = v ( m₁ + m₂ )

where;

m₁ is mass of the red cartm₂ is the mass of the blue cartu₁ is initial velocity of the red cartu₂ is the initial velocity of the blue cartv is the final velocity of the two carts after the collision

m₁u₁ + 0 = v ( m₁ + m₂ )

m₁u₁ = v ( m₁ + m₂ )

v = ( m₁u₁ ) / ( m₁ + m₂ )

The final velocity of the red-blue carts system is calculated as;

v = ( 50 kg cm/s ) / ( 5 kg + 5kg )

v = 5 cm/s

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The complete question is below:

A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision. What is the final velocity of the two carts system after the collision if the mass of the blue cart is 5 kg.

Select the correct answer. a heat engine has a cold reservoir of 250 k and a hot reservoir of 715 k. what is the maximum efficiency of the engine?
a. 65.0%
b. 60.8%
c. 73.6%
d. 58.6%
e. 69.1%

Answers

The maximum efficiency of the engine is a. 65.0%

The maximum efficiency of the heat engine is given by the Carnot efficiency, which is defined as:

Efficiency = (1 - (T cold / T hot)) * 100%

Where T cold is the temperature of the cold reservoir and T hot is the temperature of the hot reservoir.

Plugging in the given temperatures, we get:

Efficiency = (1 - (250 / 715)) * 100% = 65.0%.

So the answer is a. 65.0%.

So, using the temperatures given in the question:

Efficiency = 1 - (250 K/ 715 K) = 1 - 0.349 = 0.651 or 65.1%

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When a rubber rod is rubbed with wool, the rod becomes negatively charged. What can you conclude about the magnitude of the wool's charge after the rubbing process

Answers

The wool must start out negatively charged before becoming positively charged after donating its electrons to the rubber rod.

What happens when wool is rubbed on a rubber rod?

A rubber rod becomes negatively charged when wool is brushed against it, and the magnitude of the charge on the wool is equal to the charge on the rod. By applying the same amount of negative charge to the rod, the wool becomes positively charged.

Why does a polythene rod become negatively charged when it is brushed against wool?

Electrons generate energy while rubbing a polythene rod with a duster because of the friction. When they have enough energy, electrons can escape from an atom and "rub off" onto a polythene rod.

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humans taste food mostly because of:

Answers

Answer:

taste buds

Explanation:

very sensitive microscopic hairs called microvilli. The tiny hairs send messages to the brain about how something tastes, so you know if it's sweet, sour, bitter, or salty

Why is i0 10 12 W m2 used as a reference intensity for intensity level?

Answers

Since I0 is the lowest sound intensity that a person with normal hearing can detect, it is chosen as the reference point. Given that log10 1 = 0, the decibel level of a sound with an intensity of 10–12 W/m2 is = 0 dB. In other words, the human hearing threshold is zero decibels.

The reference value I0 is 10–12 W/m2, which corresponds to the threshold of hearing intensity at 1000 Hz. The Sound Intensity Level, or SIL for short, is the intensity decibel scale. The related sign, like in our text, is LI.

Much more frequently than sound intensities in watts per square meter, sound intensity levels are expressed in decibels (dB). Both the scientific literature and the public media use decibels as their preferred measurement unit. The rationale behind this decision of units has to do with how we hear. There is a reference intensity, I0 = 1012 W/m2. The lowest or threshold intensity of sound that a person with normal hearing can perceive at a frequency of 1000 Hz is specifically known as I0. The degree of sound intensity is not the same as the intensity. is a unitless quantity that informs you of the sound level in relation to a predefined standard (1012 W/m2, in this case), as it is defined in terms of a ratio.

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Select the correct answer. A boy is pushing a chair by applying a force of 5 newtons. His mother helps him push it faster by applying an additional force of 7 newtons in the same direction. What is the net force acting on the chair

Answers

Answer:

The net force is now 12

Explanation:

The boy is applying a force of 5 newtons + his mother is helping him to apply 7 newtons = 12 newtons.

A car at rest with respect to a building can be in motion with respect to another observer. True/False. Please explain your answer

Answers

The given statement is true because an object at rest with respect to one object can be in motion with respect to another motion

if the crumple zone exerts +200,000 N of force on the wall, how much force will the wall exert on the crumple zone?

Answers

Answer: -200,000N

(To be more specific, 200,000N in the opposite direction)

Explanation:

By Newton's 3rd law (Action reaction pair)

The crumple zone exerts a force on the wall, the wall will exert an equal but opposite force on the wall.

Same magnitude -> 200,000N

Opposite direction-> Include a negative sign as force is a vector which depends on both magnitude and direction.

During a magic trick, a magician twirled a ball on a string horizontally at a constant rate. He then doubled the length of the string but maintained the rate at which the ball rotated. Which of the following factors remained constant? A angular velocity B centripetal acceleration с centripetal force

Answers

Correct option is C, Centripetal force remains constant.

Centripetal Force -

Any force that changes the direction of motion toward the center of a circular motion is known as a centripetal force. The part of the force that produces the centripetal force is the part that is perpendicular to the velocity.

A net force that keeps an object moving in a circular motion is known as a centripetal force.

Centripetal force has the formula =mv2r. The newton or kgms2 is the measure of force.

A centripetal force is applied to any item travelling in a circle (or along a circular path). In other words, the object is being physically pushed or pulled in the direction of the circle's center. This is the necessary centripetal force.

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Light demonstrates the characteristics of _______________. particles only waves only both photons and particles both waves and particles

Answers

Both the features of waves and particles can be seen in light.only photons and particles only photons and particles, only waves.

Photons are they both waves and particles?

Both a wave as well as a particle description of light are possible.The dual character of light has been highlighted in particular by two investigations.When we consider that light is composed of tiny particles, we refer to those particles as "photons."

What are waves and particles both?

The following is the image for 'photons & particles combining waves and particles'.While electromagnetic radiation behaves both like a wave and a particle at the same time, it propagates according to linear wave equations and can only be released or absorbed in discrete pieces.

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Draw conclusions: Objects falling through air are slowed by the force of air resistance. Which objects were slowed the most by air resistance

Answers

Due to this air resistance, Galileo discovered that heavier or more dense things fall more quickly than less dense ones. Together, a brick and a feather fell. The feather falls more slowly due to air resistance.

Descending against air resistance an object often experiences some air resistance as it falls through the air. The leading surface of the object collides with air molecules, creating air resistance. Several variables affect how much air resistance the object really experiences.

Therefore, heavier things fall quicker than lighter ones because the force of gravity acting on them is greater. As a result, heavier objects accelerate at faster speeds until the force of air resistance acts on them.

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A boy exerts a force of 225 N on a lever (Links to an external site.) to raise a 1250 N rock a distance (Links to an external site.) of 0.13 m. If the lever is frictionless, how far did the boy have to move his end of the lever

Answers

If the lever is frictionless, to raise the rock a distance of 0.13 m, then the boy has to move the lever to 0.72 m.

An external force that acts upon an object results in a motion of the object, then it is called a work done upon the object by that force.

Given that the external force on a lever is 225 N and on a rock is 1250 N. The distance of motion by the rock is 0.13 m.

Hence the work done by the lever will be equivalent to the work done by the rock to move a particular distance.

Work (Lever) = Work (Rock)

F(lever) x D (lever) = F (rock) x D (rock)

225x D(lever)= 1250 x0.13

D(lever) is 0.72 m

Hence we can conclude that the distance of the motion by the lever is 0.72 m.

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What details can you add to your model of sound? model being a slinky

Answers

Answer:

I really hope this helps

Explanation:

The set of spectral lines that we see in a star's spectrum depends on the star's (a) atomic structure. (b) chemical composition. (c) rotation rate.

Answers

The set of spectral lines that we see in a star's spectrum depends on the star's (b) chemical composition, (d) temperature.

The spectral lines of a star are determined by its chemical composition and temperature. These properties determine the number and type of atoms present in the star's atmosphere. Each type of atom has its own unique set of spectral lines, and the temperature of the star determines the energy level of the atoms, which affects the wavelengths of the spectral lines emitted. The rotation rate and atomic structure of a star do not affect the set of spectral lines we see in its spectrum.

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Calculate the rotational kinetic energy of a 12-kg motorcycle wheel if its angular velocity is 120 rad/s and its inner radius is 0.280 m and outer radius 0.330 m.

Answers

According to the question the rotational kinetic energy of a 12-kg motorcycle wheel is 809.14 J

What does rotational kinetic energy?

The SI unit for rotational kinetic energy is the joule (J). The rotating kinetic energy formula has a similar structure to a translational kinetic energy equation. Kinetic energy is created by spinning objects around an axis. This type of energy is influenced by the object's mass, weight, and center of mass angle with respect to the axis.

Given data -

Mass = 12-kg

Angular velocity (ω) -120rad/s

inner radius = 0.280 m

outer radius = 0.330 m.

By using the formula

I = ½*M (r1² + r2²)

I = ½ *(12) * (0.2802 + 0.3302)

I = 1.1238 Kgm2

K.E = ½*Iω2

K.E = ½ * (1.1238)*(120)2

K.E = 809.14 J

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A typical spectrophotometer has a path length (the distance light travels through a sample) of 1 cm. Light travels at approximately 3.0 x 108 m/s in vacuum. How long does it take (in ns) for light to travel 1.0 cm

Answers

The time taken is 3.33 ns for light to travel 1.0 cm in a spectrophotometer.

What is time?

Time is defined as a scalar quantity that describes the progression of events in the universe. It is often considered to be the fourth dimension of spacetime, along with the three dimensions of space. Time is closely related to the concepts of causality, or the relationship between cause and effect, and is considered to be a fundamental aspect of the physical universe.

The distance light travels in 1 cm is equal to 1 cm x 10^-2 m. To find out how long it takes for light to travel this distance, we can use the formula:

time = distance / speed

Where distance is the distance light travels (1.0 cm x 10^-2 m), and speed is the speed of light in vacuum (3.0 x 108 m/s).

time = (1.0 cm x 10^-2 m) / (3.0 x 108 m/s)

time = 3.33 x 10^-10 s

To convert this time to nanoseconds (ns), we can multiply the time in seconds by 1 billion (10^9):

time = 3.33 x 10^-10 s x 10^9 ns/s

time = 3.33 ns

Therefore, the time taken is approximately 3.33 ns for light to travel 1.0 cm in a spectrophotometer.

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Gravity on the surface of the moon is only 1 6 as strong as gravity on the Earth. What is the weight of a 35 kg object on the Earth

Answers

Answer:

Weight of a 35kg object on Earth is 350N, while it is 56N on the Moon.

Explanation:

The conversion of mass (kg) to weight (N) on Earth is 1kg to 10N.
Thus, the weight of a 35kg mass on Earth is
35kg × 10 = 350N

On the Moon, conversion of mass to weight is 1kg to 1.6N.
Thus, the weight of a 35kg mass on the Moon is
35kg × 1.6 = 56N


Remember, mass remains constant regardless of location, while weight depends on the strength of the gravitational field.

Other Questions
Crestive17. Match the definition with the correct word.compliant; manageabletractablecanvassbeatificplacid What do the Elgin Marbles represent? system, the consequence of the mechanical discoveries of the time. Four great inventions altered [changed] the-Passing to manufacturers, we find here the all-prominent fact to be the substitution of the factory for the domesticcharacter of the cotton manufacture; the spinning jenny, patentedHargreaves in 1770; the water-frame, invented by***Arkwright the year before; Crompton's mule [spinning machine] introduced in 1779, and the self-acting mule, firstinvented by Kelly in 1792, but not brought into use till Roberts improved it in 1825. None of these by themselves wouldhave revolutionized the industry. But in 1769-the year in which Napoleon and Wellington were born-James Watt tookout his patent for the steam-engine. Sixteen years later it was applied to the cotton manufacture. In 1785 Boulton andWatt made an engine for a cotton-mill at Papplewick in Notts, and in the same year Arkwright's patent expired. Thesefatal todid not come into use fortwo facts taken together mark the introduction of the factory system. But the most famous invention of all, and the mostseveral years, and till the powerloom was introduced the workman was hardly injured. At first, in fact, machinery raisedthe wages of spinners and weavers owing to the great prosperity it brought to the trade. In fifteen years the cotton tradetrebled [tripled] itself; from 1788 to 1803 has been called "its golden age;" for, before the power-loom but after theintroduction of the mule [spinning machine] and other mechanical improvements by which for the first time yarnsufficiently fine for muslin [a fabric] and a variety of other fabrics was spun, the demand became such that "old barns,cart-houses, out-buildings of all descriptions were repaired, windows broke through the old blank walls, and all fitted upfor loom-shops; new weavers' cottages with loom-shops arose in every direction, every family bringing home weeklyfrom 40 to 120 shillings per week." At a later date, the condition of the workman was very different. Meanwhile, the ironindustry had been equally revolutionized by the invention of smelting by pit-coal brought into use between 1740 and1750, and by the application in 1788 of the steam-engine to blast furnaces. In the eight years which followed this latterdate, the amount of iron manufactured nearly doubled itself....ventilation is greater than the loss from death orwounds in any wars in which the country has been engaged in modern times. That of the 43,000 cases of widowhood,and 112,000 cases of destitute orphanage relieved from the poor's rates in England and Wales alone, it appears that thegreatest proportion of deaths of the heads of families occurred from the above specified and other removable causes;that their ages were under 45 years; that is to say, 13 years below the natural probabilities of life as shown by theexperience of the whole population of Sweden.... _____ is the information that helps managers determine how to do better than others. Denise is comparing a salaried job offer for $1,500 a week to a wage of $55 per hour. Which equation would help her find the "break-even point" where each offer would be equal?A. 1500 = 55 + 2HB. 150010 = 55HC. 1500 = 55HD. 1500H = 55(40)E. 1500-H= 55 x 8 Jupiter is about 5. 2 Astronomical Units (AU) from the Sun. Neptune is about 30. 1 AU from the sun. How many times as far from the Sun is Neptune as Jupiter? First answer gets brainliest What percentage of wealth belonged to the wealthiest 1 percent of US citizens? (5b + 16)(b + 32)What is the value of b ? b = Which of the following statements about effective global leadership are NOT true? A. In collectivist cultures, employees typically value their autonomy, and are unlikely to be motivated by fringe benefits and training provided by the employer. B. High power distance implies that people would be more motivated by teamwork and relations with peers. C. High masculinity suggests that most people would be more comfortable with the traditional division of work and roles; in a more feminine culture, the boundaries could be looser, motivating people through more flexible roles and work networks. D. The higher the level of "masculinity" (such as in Japan and Mexico), the more motivated employees were by being given opportunities for high pay, personal accomplishment, and job advancement. E. Traditional Chinese management style focuses on human-centredness, family-centredness, and centralisation of power. Dilate the line shown by a scale factor of 1/4 with the center as (-3,9). Graph the dilated line How did federal government respond to the Georgia Assemblys expulsion of its African American members during Reconstruction?What is the difference between the Emancipation Proclamation and the 13th Amendment? While assessing the airway patency of a client after a bomb blast, the nurse suspects severe brain injury and gives a score of 7 using the Glasgow Coma Scale (GCS). Which intervention is most appropriate for the client Can someone answer one of my questions for once 50 pts What is the slope of the line that passes through the points (1, 6) and (13, 2)? Write your answer in simplest form. 1vNextSummarizing Literature: Mastery TestNothing can describe the confusion of thought which I felt when I sank into the water. Though I swam very well, I could not deliver myself from the wavesso as to draw breath, till that wave having driven me, or rather carried me, a vast way on towards the shore, and having spent itself, went back, and left meupon the land almost dry, but half dead with the water I took in. I had so much presence of mind, as well as breath left, that seeing myself nearer themainland than I expected, I got upon my feet, and endeavored to make on towards the land as fast as I could before another wave should return and take meup again. However, I soon found ityvas impossible to avoid it for I saw the sea come after me as high as a great hill, and as furious as an enemy, which I hadno means or strength to contend with my business was to hold my breath, and raise myself upon the water if I could. By swimming, I could preserve mybreathing, and pilot myself towards the shore, if possible. My greatest concern now being that the sea, as it would carry me a great way towards the shorewhen it came on, might not carry me back again with it when it gave back towards the sea.The wave that came upon me again buried me at once twenty or thirty feet deep in its own body. I could feel myself carried with a mighty force andswitness towards the shore a very great way, but I held my breath, and assisted myself to swim still forward with all my might. I was ready to burst withholding my breath, when, as I felt myself rising up, so, to my immediate relief, I found my head and hands shoot out above the surface of the water. Though itwas not two seconds of time that I could keep myself so, yet it relieved me gready, gave me breath, and new courage. I was covered again with water a goodwhile, but not so long but I held it out and finding the water had spent itself, and began to return, I struck forward against the return of the waves, and feltground again with my feet. I stood still a few moments to recover breath, and till the waters went from me, and then took to my heels and ran with whatstrength I had further towards the shore. But neither would this deliver me from the fury of the sea, which came pouring in after me again; and twice more Iwas litted up by the waves and carried forward as before, the shore being very flat.The last time of these two had well-nigh been fatal to me, for the sea having hurried me along as before, landed me, or rather dashed me, against a piece1from Robinson Crusoeby Daniel DefoeSelect ALL the correct answers.Which two statements should be included in a summary of the passage?DCrusoe scales a grassy cliff and watches the waves at a safe distance.DWhen a wave crashes him against a rock, Crusoe fears the worstCrusoe is afraid he will be pulled further out to sea by the strong currentBecause of rough and powerful waves, Crusoe struggles to get to shore.The sea repeatedly batters Crusoe, but he does not give up hope for survival.0000Submit TestTools In what ways were berlin's songs expressions of continuity in american culture? in what ways did they signify change in american culture? Find a basis for the eigenspace corresponding to the eigenvalue. 2-6 Al La 2 = 11 9 A basis for the eigenspace corresponding to a = 11 is a (Type a vector or list of vectors. Type an integer or simplified fraction for each matrix element. Use a comma to separate answers as needed) Find a basis for the eigenspace corresponding to the eigenvalue of A given below. A= 3 02 0 4,2 = 2 2 -3 3 A basis for the eigenspace corresponding to a = 2 is O. (Use a comma to separate answers as needed.) Using complete sentences, explain the three criteria that make a resource scarce. What actions do you take immediately after a burn occurs? Find the number of moles of oxygen atoms in 3.00 mol of copper(II) sulphate pentahydrate.