Total momentum of masses after collision is : 100kgm/s
velocity of the masses after collision is : 5m/s
Explanation :
The conservation of momentum principle states that the amount of momentum within a problem domain remains constant; momentum is neither created nor destroyed, but only changed by the action of forces as described by Newton's laws of motion.
To find total momentum ,
we have to find momentum of each object .
Momentum of object with 16kg masses,
p = mv
here m = 16 kg and v = 5m/s
p1 =16×5
=80kgm/s
momentum of object with 4kg masses, and v =5m/s
p2 = 4 x 5
= 20kgm/s
total momentum is,
P = p1 + p2
80 + 20 = 100kgm/s
total momentum after collision,
100kgm/s (law of conservation of momentum)
velocity of masses is ,
total p= (m1+m2)×v
100 = (16+4)v
v = 100÷20
v = 5m/s
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What is the magnitude of the magnetic force experience by a cable that is 3 cm long, going trough a magnetic field 44 x10-3 T strong, with a current of 2 A that is perpendicular to the field
The equation describes the force acting on a wire carrying current I and having length L in a magnetic field. Where is the angle formed by the wire and the magnetic field, and F=ILB sin x.
magnitude of the magnetic force experience
by a cable is 2.64 x 10 ^ -3 N
What is the formula of magnitude of magnetic force?The equation describes the force acting on a wire carrying current I and having length L in a magnetic field. Where is the angle formed by the wire and the magnetic field, and F=ILB sin x. The field and current are parallel to the force.The current's size has a direct correlation with the field's strength. The strength of the field is inversely proportional to the point's separation from the wire at any given time.When a current-carrying conductor is placed in a magnetic field, the force it experiences is at its strongest when the conductor is kept perpendicular to the magnetic field's direction.F = ILB sin x
= 2 x .03 x 44 x 10^ -3 x sin 90 = 2.64 x 10 ^ -3 N
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module 1 question 11
A cheetah can accelerate from rest to a speed of 26.5 m/s in 6.50 s. What is its acceleration?
m/s2
The acceleration of the cheetah is 4.07 m/s^2.
Acceleration is the rate of change of the velocity of an object with respect to time. The unit of acceleration is meter per seconds squared (m/s^2). The equation of acceleration is given below.
a = (v_f - v_i)/t
Where a = acceleration, v_f = final velocity, v_i = initial velocity and t = time.
Here, the final velocity = 26.5 m/s, initial velocity = 0 m/s (cheetah is at rest) and time = 6.5 s. The acceleration of the cheetah will be,
a = (26.5 - 0)/6.5
a = 4.07 m/s^2
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Give 5 example of a factual statement and five example of an opinion
What is it called when you place the ball in your palm (facing up or sideways) during a dribble?
When you place the ball in your palm (facing up or sideways) during a dribble it is called carrying.
What is carrying in basketball?Carrying occurs when the dribbling player continues to dribble after allowing the ball to come to rest in one or both hands and/or places their hand underneath the basketball. Carrying is a violation of the basketball rules.
There is a type of carrying, known as palming which involves holding the ball in one hand in a grip without allowing it to fall naturally.
Dribbling in basketball is referred to as a repetitive action in which a player uses one hand to bounce the basketball continuously on the court.
There are types of dribbling in basketball which includes:
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Without adding more sources of light,how can he enhance the light in his salon
Placing lights at either side of the mirror to directly brighten the complexion is the simplest way to help reduce shadows on the face. The temperature of this bulb should be comfortable as well (2,700 to 3,500 Kelvin).
How can I update the lighting in my salon?Lighting in salons should be positioned to eliminate shadows. Placing lights at either side of the mirror to directly brighten the complexion is the simplest way to help reduce shadows on the face. The temperature of this bulb should be comfortable as well (2,700 to 3,500 Kelvin).
Why does lighting in a spa matter?Compared to other spaces or buildings, a beauty salon has a lot more practical uses for lighting. It facilitates work, helps staff members see consumers clearly, and ensures that everything is carried out correctly.
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Match each phase change description with the correct term.A change from solid to gasA change from liquid to gasA change from gas to liquidA change from solid to liquid?Melting?Sublimation?Condensation
By definition we have that:
Melting: A change from solid to liquid
Sublimation: A change from solid to gas
Condensation: A change from gas to liquid.
Vaporization: A change from liquid to gas
The Hubble Space Telescope has a resolution of about 0.05″. What is the size of the smallest feature it can distinguish on the surface of Mercury, at closest approach to Earth?
If the Hubble Space Telescope has a resolution of about 0.05, then the size of the smallest feature it can distinguish on the surface of Mercury, at closest approach to Earth is 92 m.
What is the earth?
The Earth is described as an ellipsoid with a circumference of about 40,000 km. The earth found is the densest planet in the Solar System and it is also the largest of the four rocky planets.
The Hubble Space Telescope is a space telescope that was launched into low Earth orbit in 1990 and remains in operation. It was not the first space telescope, but it is one of the largest and most versatile, renowned both as a vital research tool and as a public relations boon for astronomy.
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If a batter can apply the same out of maximum force from their hands to each bat to swing it why would the speed of the bat swing decrease as the mass of the bat increases
The speed of the bat swing decrease as the mass of the bat increases because mass is inversely proportional to velocity squared if the centripetal force is constant.
[tex]F_{c}[/tex] = m v² / r
[tex]F_{c}[/tex] = Centripetal force
m = Mass
v = Velocity
r = Radius
Rearranging for v,
v² = [tex]F_{c}[/tex] * r / m
Since [tex]F_{c}[/tex] and r is constant,
v² ∝ 1 / m
Since v² is inversely proportional to m and vice-versa, as the mass of the bat increases, speed of the bat swing decreases.
A centripetal force is responsible for making a body follow a curved path. The direction of centripetal force is perpendicular to the motion and towards the center of curvature.
Therefore, the speed of the bat swing decrease as the mass of the bat increases because mass is inversely proportional to velocity squared if the centripetal force is constant.
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A student is investigating the specific heat capacity of a block of iron. Their method is to heat up the insulated block of iron using an electric heater and measure its temperature using a digital thermometer at regular intervals. The block will be heated up from room temperature to 80
°C. What is the independent variable in this experiment?
• The increase in temperature of the block of iron
• The mass of the block of iron
The time the block of iron takes to reach 80 °C
The energy supplied to the block of iron by the electric heater
As we carry out the experiment, the independent variable here is the he increase in temperature of the block of iron.
What is an experiment?In many instances, it is very important for us to be able to understand the cause and effect relationship that is likely to exists between two variables. The only way that we could be able to in fact deduce the cause and effect relationship that does exist when we have two variables is by the use of an experiment.
Hence, when ever we are doing an experiment there must be an independent variable as well as well as a dependent variable. The variable that we are manipulating in the experiment is the independent variable. The dependent variable changes as we manipulate the independent variable.
As such, in the case of this experiment, the independent variable here is the increase in temperature of the block of iron.
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three glasses of thickness 2cm , 4cm and 7cm are arranged adjacent .if their refractive indices arec 1.5 , 1.6 and 1.8 respectively. find the bottom of the prism to be raised above.
*Solution*
d = (2/1.5)+(4/1.6)+(7/1.8)
d =
A prism is a translucent, triangular object composed of glass or plastic (or any transparent material). Refraction is a phenomenon that causes white light to curve when it passes through a prism. Light is bent when it travels from one medium (like air) to another medium through the process of refraction (like water or glass).
The refractive index of an optical medium is a dimensionless quantity that describes how efficiently the medium bends light. The amount of light that enters a substance is refracted or bent depends on the substance's refractive index.
Apparent depth is the distance between the real depth of an item and its image when it is submerged in a transparent medium, which is lowered by a factor equal to the relative index of refraction of the medium with regard to air.
apparent depth is equal to actual depth / refractive index.
d = (2/1.5) + (4/1.6) + (7/1.8)
= 5.741 cm
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A pipe of length 10.0 m increases in length by 1.5 cm when its temperature is increased by 90°F. What is its coefficient of linear expansion?
The coefficient of linear expansion, given that the length of the pipe increased by 1.5 cm is 1.67×10¯⁵ /°F
How to determine the coefficient of linear expansionFrom the question given above, the following data were obtained
Original diameter (L₁) = 10 mChange in length (∆L) = 1.5 cm = 1.5 / 100 = 0.015 mChange in temperature (∆T) = 90 °FCoefficient of linear expansion (α) =?The coefficient of linear expansion can be obtained as illustrated below:
α = ∆L / L₁∆T
α = 0.015 / (10 × 90)
α = 0.015 / 900
α = 1.67×10¯⁵ /°F
Thus, we can conclude that the coefficient of linear expansion is 1.67×10¯⁵ /°F
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Sweet Cravings Bakery was interested in seeing if there was an association between cake flavor and frosting flavor. Given are the results of the survey in a relative frequency table.
Vanilla Chocolate Total
Vanilla Buttercream 0.15
Cream Cheese Icing 0.14 0.33
Cookie Butter Buttercream 0.20
Total 0.60 1.00
Which category has the lowest joint relative frequency?
Cupcakes with vanilla buttercream
Cupcakes that are chocolate
Chocolate cupcakes with vanilla buttercream
Vanilla cupcakes with vanilla buttercream
The category with the lowest joint relative frequency is Chocolate cupcakes with vanilla buttercream.
Relative frequency = Subgroup frequency / Total frequency
Some of the relative frequencies are given. From that we can find the remaining frequencies using basic addition and subtraction.
Vanilla Chocolate Total
Vanilla Buttercream 0.15 0.06 0.21
Cream Cheese Icing 0.19 0.14 0.33
Cookie Butter Buttercream 0.26 0.20 0.46
Total 0.60 0.40 1.00
Joint relative frequency = Joint frequency / Total frequency
The joint relative frequency of
Cupcakes with vanilla buttercream = 0.21Cupcakes that are chocolate = 0.40 Chocolate cupcakes with vanilla buttercream = 0.06Vanilla cupcakes with vanilla buttercream = 0.15Therefore, the category with the lowest joint relative frequency is Chocolate cupcakes with vanilla buttercream.
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Describe how you can tell if an object is accelerating by observing its motion. Be sure to cover all cases.
If an object is changing its direction or the speed of the object is changing then the object is said to be accelerating.
What is meant by acceleration?Acceleration is the rate at which speed and direction of velocity change over time. A point or object moving straight ahead is accelerated when it accelerates or decelerates. Even though the speed is constant, motion on a circle accelerates because the direction is constantly shifting.
An object is said to be accelerating if its velocity is changing, whether the change in velocity is constant or varies by a fixed amount.
Since acceleration is a vector quantity—which means it has both a magnitude and a direction—it follows that an object is said to be accelerating if its direction is changing.
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The question is in the photo
Given:
car is parked ouphill on a sloped street.
To draw the free body diagram.
Explanation:
he ffree-bodydiagram of the car is shown below.
Here, W is the force due to gravity which is its weight.
There is a frictional force, f acting towards the slope.
N is the normal force.
The car will remain at rest if no force is acting on the body.
The weight can be resolved into sine and cosine components.
The horizontal component of weight cancels out the normal force and the vertical component of weight cancels the frictional force.
Thus, the car is at rest as no net force is acting on it.
a 5.5 kg box is pushed across the lunch table. The net force applied to the box is 9.7N. what is the acceleration of the box.
Answer:
1.8 m / s^2
Explanation:
F = ma ( ignoring friction)
F/ m = a
9.7 / 5.5 = 1.8 m/s^2
please, I need help with this question.
A ball is kicked from the origin at an angle θ = 30 with an initial speed of V = 20 m/s m /s. Calculate the x and y components of the velocity vector v⃗.
Thanks
The x and y components of the velocity vector is 17.32 m/s and 10 m/s respectively.
What is the x - component of the velocity?
The x-component of the ball's velocity is the velocity of the ball in the horizontal direction or x-axis.
The velocity of the ball in x-direction is calculated as follows;
Vx = V cosθ
where;
Vx is the horizontal velocity of the ballV is the speed of the ballθ is the angle of inclination of the speedVx = (20 m/s) x (cos 30)
Vx = 17.32 m/s
The velocity of the ball in y-direction is calculated as follows;
Vy = V sinθ
where;
Vy is the vertical velocity of the ballV is the speed of the ballθ is the angle of inclination of the speedVy = 20 m/s x sin(30)
Vy = 10 m/s
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Rank these automobiles based on the magnitude of their momentum before the brakes are applied, from largest to smallest.Rank from largest to smallest. To rank items as equivalent, overlap them. If the ranking cannot be determined, check the box below.
Explanation
The magnitude of the momentum of an object is given by:
[tex]p=mv[/tex]where p is the momentum
m is the mass of the object
v is the mass of the object
so
Step 1
ind the momentum of aeach vehicle
a)
let
mass=1000 Kg
v=20 m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=1000\text{ Kg}\cdot20\text{ }\frac{m}{s} \\ P_1=20000Kg\frac{m}{s} \end{gathered}[/tex]b
let
mass=2000 Kg
v=5 m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=2000\text{ Kg}\cdot5\text{ }\frac{m}{s} \\ P_2=10000Kg\frac{m}{s} \end{gathered}[/tex]c
let
mass=1000 Kg
v=10 m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=1000\text{ Kg}\cdot10\text{ }\frac{m}{s} \\ P_3=10000Kg\frac{m}{s} \end{gathered}[/tex]d)let
mass=500 Kg
v=20 m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=500\text{ Kg}\cdot20\frac{m}{s} \\ P_4=10000Kg\frac{m}{s} \end{gathered}[/tex]e)xlet
mass=4000 Kg
v=5 m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=4000\text{ Kg}\cdot5\frac{m}{s} \\ P_5=20000Kg\frac{m}{s} \end{gathered}[/tex]f)let
mass=500 Kg
v=10m/s
replace and calculate
[tex]\begin{gathered} p=mv \\ P=500\text{Kg}\cdot10\frac{m}{s} \\ P_6=5000Kg\frac{m}{s} \end{gathered}[/tex]Step 2
ow, raknk the automobiles based on the magnitude of the momentum( from the largest to smallest)
so
(automoblile 1 is the one on the left)
I hope this helps you
A car slams into a brick wall, with an impulse of 10Ns, the duration of the impulse was 0.2 sec. What was the average force the car hit the wall?
Answer:
50 N
Explanation:
The change in momentum in this case can be calculated in this way
Impulse (Ns) = force (N) X time (s)
We have Impulse and time here:
10Ns= force X 0.2s
We rearrange the formula to get force
10 ÷ 0.2 = 50
Therefore average force is 50N
A new airbus 5200 weighs 150,000 lbs and has a maximum take off acceleration of 2.7 m/s. How long of a runway is required to reach a velocity of 82 m/s for a safe take off.
Cindy runs 2 km every morning. She takes 2 minutes for the first 250 m, 4 minutes for the next 1,000 m, 1 min for the next 350 m, and 3 min for the rest.
Cindy's average speed for the entire run is ______ m per min. One km is the same as 1,000 m.
Hint: average speed = total distance/total time
Cindy's average speed for the entire run is 200 m per min.
What is Cindy's average speed for the entire run?
First, to measure Cindy's average speed, we need to know that the average speed of Cindy would be the total distance she had covered while running by the total amount of time it took her to cover the distance. So, we need to measure her average rate of speed over the extent of her runs.
In order to calculate average speed we will calculate the total distance in meters traveled by Cindy.
Given:
Total distance = 2 Km
Convert km to meter, since she is running at a different speed measured in meter.
1 km = 1,000 m
Total distance = 2 Km = 2000 m
Then, the total amount of time in minutes it took her to cover this distance is: 2 (for the first 250 m) + 4 (for the next 1,000 m) + 1 (next 350 m) + 3 (time used for rest) = 10 minutes
Average speed = total distance / total time
Average speed = 2000 m / 10 minutes
Therefore, her average speed = 200 m per min
In summary, Cindy, though rested for 3 minutes, maintained an average speed of about 200 m per min for the entire run.
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A: Small rockets are used to make tiny corrections to the velocity of a satellite. If a rocket has a thrust of 35 N and is used to change the velocity of a 72000 kg satellite by 0.63 m/s, for how long (time) should it be fired?
B: A 2-kg pumpkin flies through the air at 42 m/s (93mph)! It strikes a 500kg Volkswagen Bug that has been abandoned in a corn field for quite some time. The pumpkin bounces off the car and has a final velocity of -2.68 m/s (-6.0 mph). What is the final velocity of the car?
The small rocket will be take time 1296 sec.
We are given that,
The thrust of the rocket = F = 35N
The velocity of the rocket = v = 0.63m/s
The mass of the satellite = m = 72000kg
Therefore , to get time t of the rocket when it would be fired and we use the equation such as , the product of the mass and velocity of an object i.e. known as momentum (p).
p = mv
Where p is the momentum of the rocket, m is the mass and v is the velocity of the rocket.
Since , here we can write Newtonian relations such as, Momentum is equivalence as a function of Force (F) and time (t) which is given as,
p = F t
So that from above two equation we can write as,
mv = Ft
t = mv/F
t = {(72000kg) ×(0.63m/s)}/35N
t = 1296 sec
Therefore, the rocket will be fired in 1296 seconds.
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An electrical vacuum tube was sealed off during manufacturing at a pressure of 1.2 *10^7 mmhg at 27degree Celsius and volume of 100cm what is the pressure of the tube and how mana gas of molecule remain in the tube
3.86×10^11 molecules of gas remain in the tube
P = nkT
n = P/kT
= hdg/kT
Number of molecules in the electron tube is = n×V = hdgV/kT
⟹n = hdg/kT
=
1.2×10^−10 ×13600 × 9.8 × 100 × 10^−6/1.38×10^−23 × 300
= 3.86×10^11
State four factors that affect capacitance of capacitor
Dependence:
-Area
-Separation
-Medium
Independent from:
-Charge
-Electric potential
-Metal
2nd question please, no explanation. Trying to see if I was right
The gravitational potential energy depends on the altitude, more altitude means more potential energy. But, equal altitude means equal potential energy.
Therefore, A and D have the same potential energy.Mass can be defined as the amount of matter in an object. If you were to go to another planet or the moon, would the mass of the object increase, decrease, or stay the same? Explain.
Mass does not change thus the object would have the same mass in ay planet or the moon.
What is the mass?
We need to look at the mass of the body as the quantity of matter that we can find in the body. This implies that the more of matter that we can find in a particular object, the more the mass of the object. It is also possible to define the mass as the quantity of the inertia in an object. These are the basic ways that the mass of the object could be considered or understood in this case.
We know that the mass of the object does not change. This is because the quantity of the matter that an object has is not going to change no matter where the object is found whether on the earth or in the moon.
Having said this, we can now agree that the mass of the object would stay the same both on earth and in the moon.
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A lump of lead with mass 0.50 kg is dropped from a height of 20 m onto a hard surface. It does not rebound but remains there at rest for a long period of time.
what are:
a)∆Q,(b)∆W and (c)∆U for the lead during this process?
d) What is the temperature change in the lead immediately aer the impact? [specific heat capacity of lead = 128 kJ/kg K]
The temperature change in the lead immediately ∆T=1.56 K.
Temperature is a physical amount that expresses the hotness of a count number or radiation. There are 3 sorts of the temperature scale.
Temperature is a measure of the common kinetic power of the particles in an item. when the temperature will increase, the motion of the debris also increases. Temperature is measured with a thermometer or a calorimeter.
Temperature is a degree of the common kinetic strength of the particles of a substance. The higher the temperature of an item, the better its kinetic strength. Kinetic electricity is a form of electricity related to movement.
a. ΔQ=mgh
ΔQ=0.5×9.80×20
ΔQ=98 J.
⇒∆U= ∆Q
⇒∆W=0
d. The temperature change is ∆T=1.56 K
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A student drops a water balloon out of a dorm window 17 m above the ground. What is its speed when it hits the ground?
PLEASE HELP!!!
The speed of the water balloon dropped out of a dorm window 17 m above the ground when it hits the ground is 18.25 m / s
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration due to gravity
s = Displacement
d = 17 m
a = 9.8 m / s²
u = 0
v² = 0 + ( 2 * 9.8 * 17 )
v² = 333.2
v = 18.25 m / s
The equation used to solve the problem is an equation of motion. An equation of motion is used to describe the position of an object in motion with constant acceleration.
Therefore, the speed of the water balloon when it hits the ground is 18.25 m / s
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When someone throws a ball, the action force is the person pushing on the ball. What is the reaction force?
the ball pushing on the person
the ball pushing against air
the ball being pulled toward the ground
the ball being pulled away from the person
Answer:
the ball being pulled toward the ground
Explanation:
(PLEASE ANSWER) Which of the following conditions would result in the greatest amount of gravitational force between a planet and it's moon? Select THREE answers.
A. The mass of the planet is small.
B. The mass of the moon is small.
C. The distance separating the planet and moon is small.
D. The mass of the planet is large.
E. The mass of the moon is large.
F. The distance separating the planet and moon is large.
Answer:
[tex] \small \fbox{\sf Option C, D and E are the correct answer.}[/tex]
Explanation:
The gravitational force of attraction between any two masses is given by the formula,
[tex]F = G \frac{m_1 \cdot m_2}{r^2}[/tex]
Where,
F is force of attraction between masses,m1 is mass of object 1 say planet, m2 is mass of object 2 say moon,r is the distance separating the planet and moon.From above relation we can conclude that,
Gravitational force of attraction is directly proportional to the product of masses of each object.Gravitational force of attraction is inversely proportional to the distance separating the planet and moon.Hence, the greatest amount of gravitational force between a planet and it's moon would be largest when,
The mass of the planet is large.The mass of the moon is large.The distance separating the planet and moon is small.Option C, D and E are the correct answer.
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In 6–8 sentences, write a summary of what you learned from this activity. Include an explanation of what causes the spectral shifts you observed. Also, explain how scientists might use spectra analysis to support the big bang theory.
Answer :First part is what you learned so write what you learned then the other parts is The evidence that the universe is expanding comes with something called the red shift of light. Light travels to Earth from other galaxies. As the light from that galaxy gets closer to Earth, the distance between Earth and the galaxy increases, which causes the wavelength of that light to get longer.
Explanation: