A 1.8 kg book has been dropped from the top of the football stadium. Its speed is 4.8 m/s when it is 2.9 m above the ground. How high is the stadium?

When a 9.0-kg box of oranges slides from rest down a frictionless incline from a height of 5.0 m with a  frictional force then the coefficient of kinetic friction between A and B is 9.9m/s.

The frictional force acting between two moving objects is termed as Kinetic friction.

Given:

Let v represent the speed of the box at point A, x represent the distance the box slides down the slope (without friction), and represent the angle of the incline.

Remember that v = ultimate speed, therefore v 2 - v02 = 2 an x

beginning speed being

A=acceleration and X=displacement

While moving up the slope, the box begins at rest (v0 = 0) and moves a distance x with an acceleration of a to reach a speed v.

F = m g sin() = m a, where m = 9.0 kg and g = 9.8 m/s2, and a = g sin().

Using a little trigonometry, write the distance x in terms of :

x = (5.0 m) / sin(x), where sin(x) = (5.0 m)

v, enter the following into the formula above:

= 2 g sin(5.0 m) / sin(5.0 m)

10.0 m) g v

= 9.9 m/s

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(a) The displacement of the person as illustrated is 0 m.

(b) The distance travelled by the person is determined as 12 m.

The displacement of the person as illustrated is the change in the position of the person.

Mathematically, the formula for displacement of an person is given as;

Δx = xf - xi

where;

Δx = (2 m + 4m ) - ( 4m  + 2m ) = 0

The total distance travelled by the person is calculated as;

d = 2 m + 4 m + 4 m + 2 m

d = 12 m

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the acceleration of the more massive box is = F/3M.

This equation a = v/t denotes acceleration (a), which is the velocity that changes (v) over the time period (t).

The three main types of accelerated motions are uniform acceleration, quasi acceleration, and average acceleration.The motion in which an item moves inside a straight line while increasing in velocity at regular intervals is referred to as uniform acceleration.

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The biological approach examines psychological difficulties by investigating the physical basis for animal and human behavior.

It is a key perspective in psychology that entails researching the brain, immunological system, neurological system, and genetics. Data refers to the observations and measurements made during an experiment. Data collection is an essential aspect of the scientific process because it allows the experimenter to keep track of what is going on during the experiment. This branch of psychology is sometimes known as biopsychology or physiological psychology. Studying the physical basis for animal and human behavior provides a new perspective on psychological concerns. by investigating the physical basis for animal and human behavior.

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(a) The fraction of neutron's kinetic energy transferred to the atomic nucleus is 0.08.

(b) The final kinetic energy of the neutron is 5.08 x 10⁻¹³ J.

The final velocity of the atom is calculated by applying the principle of conservation of linear momentum as follows;

initial momentum of the neutron = final momentum of the atomic nucleus

m₁u₁  = m₂u₂

where;

The mass of the atomic nucleus = 12.4 m₁

u₂  = m₁u₁ / m₂

u₂  = m₁u₁ / (12.4 m₁)

u₂  = 0.08u₁

The initial kinetic energy of the neutron is calculated as;

K.Ei = ¹/₂m₁u₁²

The final kinetic energy of the atomic nucleus is calculated as;

K.Ef =  ¹/₂m₂u₂²

K.Ef =  ¹/₂(12.4 m₁)(0.08u₁)²

K.Ef = 0.08 (¹/₂m₁u₁²)

K.Ef = 0.08 (K.Ei)

The fraction of neutron's kinetic energy transferred to the atomic nucleus is calculated as;

= 0.08 (K.Ei) / K.Ei

= 0.08

= 8 %

The final kinetic energy of the neutron is calculated as follows;

K.E.f (neutron) = (1 - 0.08) x (5.53  x 10⁻¹³ J)

K.E.f (neutron) = 5.08 x 10⁻¹³ J

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The emf induced in a rotating loop in the greatest uniform magnetic field when the normal to the plane of the loop makes an angle with the field of 0 (zero).

Induction electromotive force (abbreviated as induction emf) is an electromotive force that arises in the coil caused by a changing magnetic field with a fast tempo. This force includes a certain amount of magnetic flux.

Factors that affect the magnitude of the induced emf are:

The figure shows that the angle of rotation in the normal plane is 0 degrees. The induced emf strength is maximum only when the plane normal to the coil makes 90 or 270 degrees with the magnetic field as shown in the figure below.

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Answer:

A coffee mug is opaque while a wine glass is transparent.

The work done in pushing a 40 kg chair from the kitchen table to 10 meters down the hall would be 3920 Nm.

Gravity, also called gravitational force in mechanics, is the universal force of attraction that acts between all matter. It is the weakest of the known forces in nature, and therefore plays no role in determining the internal properties of everyday matter. It controls the orbits of objects, stars, galaxies, and the universe as a whole, as well as the structure and evolution of objects elsewhere in the universe.

On Earth, every object has a weight, or downward gravitational force, proportional to its mass. , the mass of the Earth acts on them. Gravity is measured by the acceleration it imparts to a free-falling object. At the Earth's surface, the acceleration of gravity is approximately 9.8 meters (32 feet) per second. For each second her body is in free fall, its velocity increases by about 9.8 meters per second. On the moon, the acceleration of a free-falling object is approximately 1.6 meters per second.

Gravitational force on chair:

F = mg

When, F = force

m = mass of chair (40 kg)

g = gravitational acceleration (9.8 m/s²)

F = 40 × 9.8

F = 392 N

For work done:

W = F × s

Where, w = work done

F = force (392 N)

s = distance (10 m)

W = 392 × 10

W = 3920 Nm

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The force on the wall by a ball having a mass of 350 g is 140N.

Force is the product of mass and acceleration.

To calculate the force on the wall, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the force on the wall is 140N.

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Just before the collision, the ball has a velocity of 9.3 m/s, downward. After the collision, the ball has a velocity of 6.2 m/s, upward.

To solve this problem, we can analyze the motion of the ball and block before and after the collision using the principles of conservation of energy and momentum. Since the collision is elastic, the total kinetic energy of the system is conserved. The ball has gravitational potential energy before the collision, which is converted to kinetic energy as it falls.

The block has no kinetic energy before the collision, but gains some after the collision due to the transfer of momentum from the ball. By equating the total kinetic energy before and after the collision and using the principle of conservation of momentum, we can solve for the velocities of the ball and block.

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Answer:

Hussein's intelligence is above average.

Explanation:

An IQ score of 150 is considered to be very high, and indicates that Hussein's intelligence is well above average. The average IQ score is 100, and scores above 130 are considered to be in the range of highly gifted individuals. Therefore, it is likely that Hussein has a high level of intelligence. However, it is important to note that IQ tests are not perfect measures of intelligence, and there are many other factors that contribute to a person's overall level of intelligence.

Answer:

The initial speed of the van is 9.044 m/s

Explanation:

After an inelastic collision, bodies stick together and move at a common speed. Momentum is conserved, but some kinetic energy is lost.

Here is the formula for an inelastic collision:

[tex]m_1*v_{1i} +m_2*v_{2i}=v_f(m_1+m_2)[/tex]

Let the van be object 1; let the compact car be object 2.

Lets solve for [tex]v_{1i}[/tex]

Isolate terms with [tex]v_{1i}[/tex] to the left hand side.

Subtract [tex]m_2*v_{2i}[/tex] from both sides:

[tex]m_1*v_{1i}=v_f(m_1+m_2)-m_2*v_{2i}[/tex]

Divide both sides by [tex]m_1[/tex].

[tex]v_{1i}=\frac{v_f(m_1+m_2)-m_2*v_{2i}}{m_1}[/tex]

Simplify

[tex]v_{1i}=\frac{m_2(v_f-v_{2i})}{m_1}+v_f[/tex]

Enter our numbers into the equation.

[tex]m_1=2713[/tex]

[tex]m_2=843[/tex]

[tex]v_{2i} =0[/tex]

[tex]v_f=6.9[/tex]

[tex]v_{1i} =\frac{843(6.9-0)}{2713} +6.9[/tex]

[tex]v_{1i} =\frac{843(6.9)}{2713} +6.9[/tex]

[tex]v_{1i} =\frac{5816.7}{2713} +6.9[/tex]

[tex]v_{1i} =2.144 +6.9[/tex]

[tex]v_{1i} =9.044[/tex]

Their resultant at point P is 17.07μV/m.

Electromagnetic waves are a type of energy wave that has both electric and magnetic field components. They are created by the movement of electrically charged particles and travel through space at the speed of light. Electromagnetic waves can be used for communication, radiation, and other purposes. They are also responsible for the electromagnetic spectrum, which ranges from high-energy gamma rays to low-energy radio waves. Electromagnetic waves are used in a variety of applications, such as radio and television broadcasts, cellular phone communications, and radar. They can also be used to diagnose medical conditions and to detect objects in space. Electromagnetic waves are used in scientific research and are important in the understanding of the universe.

The amplitude of first wave,a1 = 10.0μV/m
The amplitude of second wave, a2 = 5.00μV/m
The amplitude of third wave, a3 = 5.00μV/m
Phase angle of first wave, θ1  = 0°
Phase angle of second wave, θ2 = 45°  
Phase angle of third wave , θ3 = -45°
Their resultant at point P is given by ,
R =  a1 Cosθ1 + a2 Cos θ2 + a3 Cosθ3

  = 10 * Cos0 + 5 * Cos(45) + 5 * Cos(-45)

   =17.07μV/m

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1.3 m/s is the speed . when Alison rode her skateboard 39 meters in 22 seconds.

Option C is correct

Divide the distance traveled by the time required to cover that distance to determine an object's speed. This formula is speed=distance/time (s=d/t). A unit of distance is divided by a unit of time in the speed equation.

Calculating Speed and Velocity The ratio of the object's total distance over a period of time to that period is used to determine speed. The ratio of a displacement interval to the time taken, on the other hand, allows one to calculate velocity.

speed=distance/time (s=d/t )

S = 32 / 22 = 1.3 m/s

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The object changes its position as a result of the force applied to it. This change in position is known as acceleration.

The magnitude of the acceleration of the object depends on the magnitude of the force applied and the mass of the object. Based on the Second Law of Motion, the acceleration of an object is directly proportional to the force applied and inversely proportional to the mass of the object. This relationship can be expressed mathematically as:

a = F/m

where a is the acceleration of the object, F is the force applied, and m is the mass of the object.

So in this case, if a force of F is applied to the 5kg object, it will experience an acceleration of a = F/5. For example, if a force of 10N is applied to the object, it will accelerate at a rate of 2 m/s^2 (a = 10N/5kg = 2 m/s^2).

Therefore, the correct answer is as given above

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Beams that bounce off a surface and continue to travel through that same medium are said to be reflected. However, because of this The refracted beams are 3, 5, and the reflected beams are 2, 4, and 2.

Cogitate, deliberate, reason, conjecture, and think are some typical synonyms of reflect. While each of these phrases means "to utilize one's skills of imagination, judgment, or inference," "reflect" denotes thoughtful deliberation about a memory.

To contemplate something thoroughly and deeply I must think for a while before making a choice. Think about or consider something She was given some alone time to consider the effects of her choice. show that... The interview had gone well, he thought as he was driving home.

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The magnitudes of gross magnetic fields at sites A and B are 2.66 x T, and the magnetic field there is identical because the distance between the two wires is equal. Using the right-hand rule as a guide

The simplest definition of magnitude in physics is "distance or quantity." In either a relative or absolute meaning, it displays the size or motion of an object. It serves as a technique to convey the size or breadth of something.

Size is referred to as magnitude. A automobile is traveling more quickly than a bike, for instance, when it comes to speed. In this case, the car is moving faster than the bike by a larger margin. In terms of motion, it describes the absolute or relative size or direction that an item goes.

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It struck him with 60 W of power. when a 10 kg rock hits a guy after falling from a height of 18 m and landing on him after around 3 s.

Power is the rate of production of work. P=Wt. The watt (W), which is equal to 1 joule per second (1J/s), is the SI unit for power. Power is a measure of how quickly energy is used up since power is the transfer of energy. An example would be a 60-W light bulb, which uses 60 J of energy every second.

Power= mass. velocity + power=10*18/3*10 = 60 W,

resulting in the power of a falling rock being 60W.

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The magnetic field at the point of the proton moving in the negative direction is equal to  1.84 ×10⁻¹⁴ T.

The magnetic force experienced by the proton moving in the negative direction is equal to  4.71 x 10⁻²⁸ N.

The magnitude of the magnetic field due to the proton at distance 'r' moving in the negative direction is determined as follows;

F = q.v.B = (kq²)/r²

q.v.B = kq²/r²

B = kq/vr²

Where, k is the coulomb's constant, r is the distance between two protons, q is the charge of the protons, and v is the proton's speed.

Given the charge on the proton, q = 1.602 × 10⁻¹⁹C

The speed of the proton, v = 1.6 × 10⁵ m/s

B = (9 × 10⁹ × 1.602 × 10⁻¹⁹) / (1.6 x 10⁵ m/s × 0.7 × 0.7)

B = 18.39 × 10⁻¹⁵ T

B = 1.84 ×10⁻¹⁴ T

The magnetic force in the negative direction experienced by the proton is calculated as follows;

F = qvB

F = 1.602 ×  10⁻¹⁹×  1.6 x  10⁵ ×  18.39 × 10⁻¹⁵ T

F = 47.1 ×  10⁻²⁹ N

F = 4.71 ×  10⁻²⁸ N

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Answer:
0.3949 m/s

Explanation :)

In this scenario, we can use the conservation of momentum to determine the new velocity of the 0.16 kg ball after the collision. The conservation of momentum states that the total momentum of a system of objects remains constant if there are no external forces acting on the objects. In this case, the two balls are the only objects involved in the collision, so we can use the conservation of momentum to determine the new velocity of the 0.16 kg ball.

We can start by calculating the total initial momentum of the two balls before the collision. The momentum of an object is equal to its mass multiplied by its velocity, so the initial momentum of the 0.16 kg ball would be 0.16 kg * 0.42 m/s = 0.0672 kgm/s. The initial momentum of the 0.017 kg ball would be 0.017 kg * 0.18 m/s = 0.00306 kgm/s. The total initial momentum of the system would be the sum of the two balls' initial momenta, or 0.0672 kgm/s + 0.00306 kgm/s = 0.07026 kg*m/s.

After the collision, the two balls continue moving in the same direction, so their final momenta must also be in the same direction. Since the momentum of the system must remain constant, the final momentum of the 0.16 kg ball must be equal to the initial momentum of the system minus the final momentum of the 0.017 kg ball. We know that the final momentum of the 0.017 kg ball is 0.017 kg * 0.41 m/s = 0.00707 kgm/s, so the final momentum of the 0.16 kg ball must be 0.07026 kgm/s - 0.00707 kgm/s = 0.06319 kgm/s.

To find the new velocity of the 0.16 kg ball, we can divide its final momentum by its mass. This gives us 0.06319 kg*m/s / 0.16 kg = 0.3949 m/s. Therefore, the new velocity of the 0.16 kg ball after the collision is 0.3949 m/s.

(a) The direction of the magnetic field is positive z direction.

(b) The magnitude of the magnetic force is 2.063 x 10⁻¹³ N.

The direction of the magnetic field is determined by applying Fleming's right hand rule.

The right hand rule states that if you point your right thumb in the direction of the velocity, your index finger in the direction of the magnetic field and then your middle finger will point in the direction of the the resulting magnetic force.

The magnitude of the magnetic force is calculated as follows;

F = qvB

where;

F = ( 1.602 x 10⁻¹⁹ x 4.6 x 10⁵ x 2.8 )

F = 2.063 x 10⁻¹³ N

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The force that is acting on the spheres is obtained as  0.006 N from the calculation that is done here.

We know that the force can be obtained by the use of the Coulomb's law. From the Coulomb's law, we know that the force that acts for the charges on the charges must be an attractive force as we can see and then we can be able able to use the formula;

F = K[tex]q_{1}[/tex][tex]q_{2}[/tex]/r^2

F = force on the object

K = electric constant

[tex]q_{1}[/tex] and [tex]q_{2}[/tex] = magnitude of the charges on the object.

Then we have;

F = 9 * 10^9 * 2 × 10^–7 *  3 × 10^–7 /(30 * 10^-2)^2

F = 54 * 10^ -5/0.09

F = 0.006 N

Thus, it is clear that we have an attractive force that would act on the species and the magnitude of the charged spheres  0.006 N as we can see from the calculation here.

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The Total work done = work done on the object + work done on the cable

From the given information,

weight of the object is = 1500 N

weight of rope is = 3N per m

height interval is = 0 to 40 m

Work = force x distance

If distance = x, then, we have the integral below as shown in the image:

By substituting x = 40 and x = 0, it becomes

1620(40) - 3/2 * (40)^2 - 1620(0) - 3/2 * (0)^2

= 64800 - 2400

= 62400 Nm

the work done from the ground to the top of the building is 62400 Nm

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For total internal reflection to occur, all of the following must happen but light must travel slower in the first medium.

Total internal reflection,  can be described as the complete reflection of a ray of light within a medium  however this medium could be water or glass from the surrounding surfaces back into the medium.

It should be noted that the total internal reflection will not take place unless the incident light is traveling within the more optically dense medium , hence phenomenon occurs if the angle of incidence is greater compare to certain limiting angle.

Therefore, option A is correct.

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From the given velocity vs time graph, the acceleration of object A is equal to 3 m/s². Therefore, option C) is correct.

Acceleration can be demonstrated as the rate of change of an object's velocity of an object with respect to time.

Acceleration can also be calculated from the second derivative of position w.r.t. time or the first derivative of velocity w.r.t. time.

[tex]\displaystyle a =\frac{dv}{dt}[/tex]

Given, on the velocity versus time graph for object A:

at time t₁ = 1 sec, the velocity v₁ = 3 m/s

At time t₂ = 2 sec, the velocity v₂ = 6 m/s

Acceleration of the object A can be calculated as:

[tex]\displaystyle a= \frac{v_2-v_1}{t_2-t_1}[/tex]

[tex]\displaystyle a= \frac{6-3}{2-1}[/tex]

a = 3 m/s²

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Answer:

4NO+2O2------>4NO2

that's the answer

Answer:

The force applied on the string is 0.25 N and the Young's modulus of the string is 10 N/m

Explanation:

The force applied on the string can be calculated using the equation:

Force = (change in length * Young's modulus) / original length

The Young's modulus of the string can be calculated using the equation:

Young's modulus = (Force * original length) / change in length

Plugging in the given values:

Force = (2.5 cm * Young's modulus) / 2 m

= (0.025 m * Young's modulus) / 2 m

= 0.025 * Young's modulus

= 0.25 (given)

= 0.25 N

Young's modulus = (0.25 N * 2 m) / 0.025 m

= 10 N/m

Answer: approximately 9.02 m/s.

Explanation: In this scenario, we can use the conservation of momentum to determine the initial speed of the van. Momentum is defined as the product of an object's mass and velocity, and it is conserved in collisions where there is no net external force. This means that the total momentum of the van and car before the collision must be equal to the total momentum of the van and car after the collision.

We can write this as an equation:

2,713 kg * v1 + 0 kg * 0 m/s = 2,713 kg * 6.9 m/s + 843 kg * 6.9 m/s

where v1 is the initial speed of the van. Solving for v1, we get:

v1 = (2,713 kg * 6.9 m/s + 843 kg * 6.9 m/s) / 2,713 kg

= 6.9 m/s + (843 kg * 6.9 m/s) / 2,713 kg

= 6.9 m/s + 3.12 m/s

Therefore, the initial speed of the van was approximately 9.02 m/s.

Answer:

True.

Explanation:

The Stanford-Binet test was developed by Alfred Binet and Theodore Simon in 1905 to measure intelligence. It was first used during World War I to identify individuals for officer status in the United States Army. The test was later revised and is still used today as an intelligence test for children and adults.