A 2 kg ball is dropped from a height of 60 m. Find its speed just before it hits the ground. Assume no friction. Answer​

Answer:

80 [Ω].

Explanation:

according the formula I=U/R, where U=120[V], I=1.5[A], the required resistance can be calculated

[tex]R=\frac{U}{I}; \ => \ R=\frac{120}{1.5}=80[Ohm].[/tex]

Answer:

45

Explanation:

Answer:

By encouraging them.

Explanation:

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Answer:

His ability to soar to the basket and do things we'd never before seen captured the world's attention and helped make basketball more of a global sport than it had ever been.  His reverse layups, slam dunks, and fadeaway shots were exciting to say the least.

Explanation:

The work the truck engine did during the 2 hour period is 8.1 × 10⁹ J

From the question, we are to determine how much work the truck engine did

Work is given by the formula

Work = Force × Distance

First, we will determine the distance traveled by truck

From the formula,

Distance = Speed × Time

From the given information

Speed = 45 m/s

Time = 2 hours = 2×60×60 = 7200 secs

Then,

Distance = 45 × 7200

Distance = 324000 m

Now, for the work done

Work = Force × Distance

From the given information,

Force = 25 kN = 25000 N

Therefore,

Work = 25000 × 324000

Work = 8.1 × 10⁹ J

Hence, the work the truck engine did during the 2 hour period is 8.1 × 10⁹ J

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Momentum

eastward = +

westward = -

[tex]\tt P_A=5\times 2=10~kg.m/s\\\\P_B=2\times 5=-10~kg.m/s[/tex]

total momentum:

[tex]\tt P_A+P_B=10-10=0~kg.m/s[/tex]

V(final) = V(initial) + a•t

Take the numbers you know, pluggum in, and you should get 3.836 m/s .

Note: This is just the final speed. Without any direction information, there's no way to find the velocity.

Answer: The hydration reaction of sulfuric acid is highly exothermic. If water is added to concentrated sulfuric acid, it can boil and spit dangerously. You should always add the acid to the water rather than the water to the acid for safety.

hope this helps!

Answer:

1 g/cm³

Explanation:

1 kg = 1000 g

1 cm = 0.01 of a meter

1 m³ = 100 cm * 100 cm * 100 cm = 1,000,000 cm

1,000 kg / 1 * 1000 g / 1 kg

^ divided by 1,000,000 cm

1,000,000 divided by 1,000,000 = 1 g/cm³

The gravitational force is s type of force that has the ability to attract any two objects having mass. The gravitational force will be [tex]4.16\times10^{23}[/tex].

The gravitational force is s type of force that has the ability to attract any two objects with mass. Gravitational force tries to pull two masses towards each other.

                      [tex]F= G\frac{m_1m_2}{r^{2} }[/tex]

Given,

mass of the sun ([tex]m_1[/tex])= [tex]1.99\times10^{23}[/tex] kg

mass of Jupiter([tex]m_2[/tex])= [tex]7.79\times10^{8}[/tex] kg

distance between the sun and Jupiter (r)= [tex]1.90\times10^{27}[/tex] m

[tex]F= G\frac{m_1m_2}{r^{2} }\\\\\\F=4.16\times10^{23}\times\frac{1.99\times10^{23}\times7.79\times10^{8}}{({1.90\times10^{27})^2} }[/tex]

[tex]F= 4.16\times(10)^{23}[/tex]   Newton

Hence the gravitational force between the sun and Jupiter will be [tex]4.16\times10^{23}[/tex]

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Answer:

equator

Explanation:

The diameter of earth is largest when measured around the equator, due to the equatorial bulge.

The equatorial bulge is a phenomenon caused by the Earth's diameter being wider in the Equator.

A straight line with its endpoints located on the edge of the circle and its center is used to calculate the diameter of a circle. Latitudes like the equator and the Arctic Circle have diameters that can be calculated by scientists.

The Equator is the place on Earth where it is the broadest. At the equator, the circumference of the Earth is 40,075 km.

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The wavelength of the  radio wave in water is 222nm

The relationship between the refractive index  wavelengths in a vacuum and in water is given by:

n = λ1/λ2

So,

let λ1 be the wavelength of light in a vacuum

λ2 be the wavelength of light in water.

nwater = 1.33

Plugging in values, we have

n = λ1/λ2

1.33 =295 m /λ2

λ2 = 295 m/1.33

 = 221.80nm

 ≈222nm

Therefore the wavelength of radio wave in water is 222mn.

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Answer:

We know that 1 meter = 100 centimeters, and 1 foot = 12 inches.

So  (1,609 meters) x (100 centimeters/meter)  =  (5,280 feet) x (12 inches/foot)

The second fraction on each side of the equation is equal to ' 1 ', because

the numerator is equal to the denominator, so sticking it in there doesn't

change the value of that side of the equation.  But now we can cancel some

units,and wind up with the units we need.

  (1,609 meters) x (100 centimeters/meter)  =  (5,280 feet) x (12 inches/foot)

        (1,609 x100) centimeters  =  (5,280 x 12) inches

            160,900 centimeters  =  63,360 inches

Divide each side by  63,360 :        2.54 centimeters =  1 inch

Explanation:

Answer:

A complete vibration is called a "period".

Starting at 0, the particle would move to +A, back to zero, to -A and back to zero to complete one cycle of a vibration

Answer:

B. the maximum velocity of the mass

Explanation:

The maximum velocity occurs at the equilibrium position (x=0) when the mass is moving toward x=+A .

Answer:

here Humans impact the physical environment in many ways: overpopulation, pollution, burning fossil fuels, and deforestation. Changes like these have triggered climate change, soil erosion, poor air quality, and undrinkable water. These negative impacts can affect human behavior and can prompt mass migrations or battles over clean water.

Explanation:

Hi there!

Assuming the rod is pulled back 90° (π/2 radians), we can use angular kinematics to solve.

Using the equation:

[tex]\omega_f^2= \omega_i^2 + 2\alpha \theta[/tex]

[tex]\omega_f[/tex] = final angular velocity (? rad/sec)

[tex]\omega_i[/tex] = initial angular velocity (0 rad/sec)

[tex]\alpha[/tex] = angular acceleration (rad/sec², must solve for)

[tex]\theta[/tex] = angular displacement (π/2 rad)

Recall Newton Second Law's rotational equivalent:
[tex]\Sigma \tau = I\alpha[/tex]

τ = Torque (Nm)

I = Moment of inertia (kgm²)
α = angular acceleration (rad/sec²)

Setting the pivot point at the end, and knowing that the force of gravity works at an object's center of mass (1.5m from the rod's end), we can solve for the angular acceleration.

[tex]\tau= F \times r\\\\\tau = W \times r = 10(9.8) * 1.5 = 147 Nm[/tex]

Now, solve for the moment of inertia given I = 1/3ML² at one of its ends:
[tex]I = \frac{1}{3}(10)(3^2) = 30 kgm^2[/tex]

Solve for the angular acceleration:
[tex]147 = 30\alpha\\\\\alpha = 4.9 \frac{rad}{sec^2}[/tex]

Now, we can use the kinematic equation to solve.

[tex]\omega_f^2 = 0 + 2(4.9)(\frac{\pi}{2}})\\\\\omega_f = \sqrt{2(4.9)(\frac{\pi}{2})} = \boxed{3.923 \frac{rad}{sec}}[/tex]

Answer:

waste water can be purified naturally by sunlight, temperature, filtration, adsorption, sedimentation, biodegradation,

Answer:

Filtration, sedimentation, or distillation

Answer:

Doubling the speed.

E - M v^2

M = W / g     energy is proportional to weight

But energy is proportional to v^2

We have that the magnitude of the magnetic field is determined by the amount of current produced.

Generally,  the magnetic field strength is called the tesla This  is measured as one Newton per ampere-meter.

Electromagnet is a  magnet where the magnetic field is created by an electric current,

Therefore the magnitude of the magnetic field is determined by the amount of current produced

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Answer:

A

Explanation:

Answer:

5,0000

Explanation:

because if u divide the 10 by 2 possible it will be 5 so u add your zero

The potential energy of the fighter jet of mass 'm' at a height of 10000 meters will be 98000m.

The energy of the body due to its position is called potential energy. If a body of mass 'm' is at height 'h' above the ground, then its potential energy with respect to earth will be -

E[P] = mgh

Given is a fighter jet traveling at a height of 10,000 meters.

The potential energy of a body at height 'h' above the ground is given by-

E[P] = mgh

where -

m is the mass of body

g is the acceleration due to gravity

Assume that the mass of jet fighter is 'm'. Then its potential energy will be -

E = mgh

E = m x 9.8 x 10000

E = 98000m

Therefore, the potential energy of the fighter jet of mass 'm' at a height of 10000 meters will be 98000m.

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Answer:

800 kg is your answer.

Explanation:

[tex]Solution,\\\\Force(F)=1200N\\\\Acceleration(a)=1.5m/s^{2} \\\\As,\\\\F=ma\\\\1200=m*1.5\\\\m=\frac{1200}{1.5} \\\\m=800kg[/tex]

Answer:

cargo planes hold cargo so there hevier

Explanation:

Explanation:

What is the key difference between photoheterotrophs and photoautotrophs? Photoheterotrophs use organic compounds as their carbon source; photoautotrophs use carbon dioxide as their carbon source.

So, the temperature of a wave that has a wavelength of 5 m is [tex] \boxed{\sf{5.796 \times 10^{-4} \: K}} [/tex]

Hi ! Here, I will help you to explain about The relationship between temperature and electromagnetic wavelength uses the principle of Wien's Constant. According to Wien, if we multiply temperature with the electromagnetic wavelengths will always got the same number (constant). Therefore, The relationship is expressed in this equation :

[tex] \boxed{\sf{\bold{C = \lambda_{max} \times T}}} [/tex]

With the following condition :

We know that :

What was asked :

Step by step :

[tex] \sf{C = \lambda_{max} \times T} [/tex]

[tex] \sf{2.898 \times 10^{-3} = 5 \times T} [/tex]

[tex] \sf{T = \frac{2.898 \times 10^{-3}}{5}} [/tex]

[tex] \sf{T = \frac{2.898 \times 10^{-3}}{5}} [/tex]

[tex] \sf{T = 0.5796 \times 10^{-3}} [/tex]

[tex] \boxed{\sf{T = 5.796 \times 10^{-4} \: K}} [/tex]

So, the temperature of a wave that has a wavelength of 5 m is [tex] \boxed{\sf{5.796 \times 10^{-4} \: K}} [/tex]

Answer:

Answer:

a. gravity & hand on book

b. yes - 3rd law

c. no, the are acting on the same object

Hope this helped!

Answer:

The first force is your hand holding the book up, and the other one is gravity pulling the book down. Hope i helped :D

Explanation:

Example: Increasing the tension in A string causes the speed of waves on the string to increase. Since the wavelengths of the standing waves remains constant, this results in a larger frequency of oscillations in the string, which we percieve as a higher pitch when the string vibrates the air.