A 200 milliliter sample of gas has a pressure of 1 atmosphere. If the volume of the gas is decreased to 50 milliliters at constant temperature, the new pressure of the gas will be

1) 4 atm
2) 1 atm
3) 3 atm
4) 2 atm

Answer:

KCIO

Explanation:

the only reason is because I looked online and the meaning for that is potassium hypochlorite my guy so if this is not right then I'm sorry but good luck.

The volume of 0.30 M potassium chromate needed to react with 15 ml of 0.10 M ferric nitrate is 5 ml.

Molarity of a solution is the ratio of its number of moles of solute to the volume of solution in liter. It is the common term used to express the concentration of a solution.

Let V1 and M1 be the volume and molarity of solution 1 and V2 and M2 that of solution 2 which are reacting together.

Thus, V1 M1 = V2 M2.

The volume of 0.30 M potassium chromate is calculated as  follows:

volume = (15 ml × 0.10 M) / 0.30 M = 5 ml.

Therefore, the volume of the potassium chromate solution is 5 mL.

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Answer:

According to Newton's law of gravitation two objects attract each other

Answer: C. Attract each other!

Explanation:

Answer:

Ksp of PbSO4 is 2.5 *10^-8

Explanation:

Given -

Solubility of PbSO4 = 0.048g/Liter

[Pb+2] * [SO42-] = mass/molecular weight of PbSO4

[Pb+2] * [SO42-] =  0.048g/Liter/303.3g/mol = 0.000158 M

Concentration of PbSO4 = moles/volume = 0.000158 M/1L = 0.000158 M

Ksp = [Pb+2] * [SO42-]

ksp = 0.000158 * 0.000158 = 2.5 *10^-8

Answer: A

Explanation:

Answer:

1)2Na + Cl2 ----> 2NaCl

2)Ca + Br2 ---->CaBr2

3)K + H2O -----> KOH + H2

Answer:

i voted her!!!!

Explanation:

Answer:

(we use hess's law) it is so simple but the second reaction is not correct please right it

Answer:

1.2x10⁻⁵M = Concentration of the product released

Explanation:

Lambert-Beer's law states the absorbance of a solution is directly proportional to its concentration. The equation is:

A = E*b*C

Where A is the absotbance of the solution: 0.216

E is the extinction coefficient = 18000M⁻¹cm⁻¹

b is patelength = 1cm

C is concentration of the solution

Replacing:

0.216 = 18000M⁻¹cm⁻¹*1cm*C

Complete question :

Use the equation qliquid = m × c × ΔT to calculate the heat gained by the cold liquid. Use the specific heat for the liquid you selected.

m = 248.9 g ; T = 72.6°C ; C = 3.73 j/g°C

Use the equation qwater = m × c × ΔT to calculate the heat lost by the hot water. Show your work using the problem-solving method shown in previous rubrics.

M = 237 g ; T = 41.2°C ; C = 4.184 j/g°C

Answer:

Quantity of heat gained = 67401.6 Joules

Quantity of heat lost by hot water = 40854.25 Joules

Explanation:

The heat gained by cold liquid :

Q = m × c × ΔT

m = 248.9 g ; T = 72.6°C ; C = 3.73 j/g°C

Q = 248.9 * 3.73 * 72.6

Q = 67401.6 Joules

Quantity of heat gained = 67401.6 Joules

Heat lost by hot water :

m × c × ΔT

M = 237 g ; T = 41.2°C ; C = 4.184 j/g°C

Q = 237 * 41.2 * 4.184

Q = 40854.25 Joules

Quantity of heat lost by hot water = 40854.25 Joules

Answer:

B

Explanation:The poisonous substances, present in the environment can easily get into the trophic level as living organism depends on each other and environment for food and nutrition. These poisonous substances may not be broken down in the body or excreted easily, efficiently and quickly. Instead, they accumulate in the tissues, and as the living organism eats more, the concentration of these substances increases and they pass from one trophic level to the next. The tertiary consumer being at the top of trophic levels receives the maximum pollutant. This phenomenon is known as biological magnification.

So, the correct answer is option B.

Answer:

C. or B.

Explanation:

The reason I chose c best, is when your cooking something with a pot with food in it max heat in about 5 minutes, the handle starts to get warmer every minute. This is conduction, where the heat transfers from the very bottom all the way to the very edge of something that is heated at a certain temperature.

Answer:

To ensure stable reading, insert the conductivity meter in the solution for at least 60 seconds.

Explanation:

The False statement is ; To ensure stable reading, insert the conductivity meter in the solution for at least 60 seconds.

All other statement will affect the experiment's redox potential but  inserting the conductivity meter in the solution for at least 60 seconds will not affect the Redox potential  .

Redox potential is used to describe/measure a system's oxidizing capacity

Answer:

The answer is "12.06"

Explanation:

Given:

[tex]M(HBrO) = 0.3\ M\\\\V(HBrO) = 20 \ mL\\\\M(KOH) = 0.15 \ M\\\\V(KOH) = 64 \ mL[/tex]

[tex]\to mol(HBrO) = M(HBrO) \times V(HBrO) = 0.3 M \times 20 mL = 6 \ mmol\\\\\to mol(KOH) = M(KOH) \times V(KOH)= 0.15 M \times 64 mL = 9.6 mmol[/tex]

  6 mmol of both will react

excess KOH remaining[tex]= 3.15 \ mmol[/tex]

Volume[tex]= 20 + 64 = 84 \ mL[/tex]

[tex][OH^{-}] = \frac{ 9.6 \ mmol}{84\ mL} = 0.01142\ M[/tex]

use:

[tex]pOH = -\log [OH^-][/tex]

        [tex]= -\log (1.142\times 10^{-2})\\\\= 1.94[/tex]

use:

[tex]PH = 14 - pOH[/tex]

       [tex]= 14 - 1.94\\\\= 12.06[/tex]

The pH of the resulting  solution is  12.63.

The equation of the reaction is;

HBrO(aq) + KOH(aq) ------> KOBr(aq) + H2O(l)

Number of moles of KOH= 64/1000 × 0.150 M = 0.0096 moles

Number of moles of HBrO = 20/1000 × 0.300 M = 0.0060 moles

Number of moles of excess base = 0.0096 moles -  0.0060 moles = 0.0036 moles

Total volume of solution = 64.0 mL +  20.0 mL = 84 mL = 0.084 L

Molarity of excess base =  0.0036 moles/0.084 L = 0.043 M

pOH = -log[OH-]

pOH = -log[ 0.043 M]

pOH = 1.37

pH + pOH = 14

pH = 14 -pOH

pH = 14 - 1.37

pH = 12.63

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Answer: The molar mass of X is 61.3g/mol

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=K_f\times m[/tex]

[tex]\Delta T_f=T_f^0-T_f=(6.55^0C-5.9^0C)=0.65^0C[/tex] = Depression in freezing point

[tex]K_f[/tex] = freezing point constant = [tex]20.2^0C/mol[/tex]

m= molality  = [tex]\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in Kg}}[/tex]

where,  

Now put all the given values in this formula, we get

[tex]0.65^0C=20.2°C/m\times frac{0.148g}}{M\times 0.075kg}[/tex]

[tex]M=61.3g/mol[/tex]

Thus molar mass of X is 61.3g/mol

Answer:

True

Explanation:

Markovnikov rule states that the negative part of the addendum is added to the carbon atom having the least number of hydrogen atoms.

This means that during acid-catalyzed addition of water to an alkene, the -OH is added to the more substituted carbon atom while the -H is added to the least substituted carbon atom in obedience to Markovnikov regiochemistry.

Answer:

a. True

Explanation:

Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H+ adds to the sp2 carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol.

Answer:

A) w/w % of Fe - 2.44%

B) w/w % of Mg - 4.590%

C) w/w % of Ca - 96%

Explanation:

A) w/w % of Fe in limestone as Fe2O3 = (Mass of Fe2O3 /Mass of limestone) x 100

 0.0357/1.4639 X 100

= 2.438 =2.44

B) w/w % of Mg in limestone as Mg2P2O7 = (Mass of Mg2P2O7 /Mass of limestone) x 100

= 0.0672/1.4639 X 100

= 4.590

C) w/w % of Ca in limestone as CaSO4 = (Mass of CaSO4/Mass of limestone) x 100

= 1.4058/1.4639 X 100

= 96

Answer:Fe =1.71%    Ma=0.99%    Ca=28.24%

Explanation:

Answer:

H2SO4 + 2NAOH➡NA2SO4+2H2O

H2SO4 = 1*2 +32+16*3= 98g

NAOH = (11+16+1)=28

Explanation:

To calculate the number of Mole = Mole *Molar Mass

To calculate for gram = Mole/ Molar Mass

20.5g NaoH/1 * 1 mole NaOH/28g NaoH = 0.73M NaoH

0.73M NaoH /1 * 1 M H2SO4 /2M NaoH = 0.37M H2SO4

0.37 M H2SO4 /1 * 98g H2SO4 /1M H2SO4 = 0.00367g H2SO4

:- 0.00367g of Sulphuric Acid will be needed to complete the reaction.

Answer: change the nitrogen with oxygen for the first part then have the nitrogens collided instead of oxygens in the last part - not sure if my terminology is correct but here is the pic to show!

Explanation:

Answer:

Use the drop-down menus to make your selections.

What is the difference between wave A and wave B?

✔ Wave A has higher amplitude than wave B.

What is the difference between wave C and wave D?

✔ Wave C has a lower frequency than wave D.

Explanation:

Answer:

it can be removed

1. by boiling

Ca(HCO3)2 > CaCO3 + H2O +CO2

2. by treating with calcium hydroxide

Answer:

38.4%

Explanation:

We'll begin by calculating the molar mass of Al(ClO₃)₃. This can be obtained as follow:

Molar mass of Al(ClO₃)₃

= 27 + 3[35.5 + (16×3)]

= 27 + 3[35.5 + 48]

= 27 + 3[83.5]

= 27 + 250.5

= 277.5 g/mol

Next, we shall determine the mass of Cl in Al(ClO₃)₃. This can be obtained as follow:

Mass of Cl in Al(ClO₃)₃ = 3 × Cl

= 3 × 35.5

= 106.5 g

Finally, we shall determine the percentage of Cl in Al(ClO₃)₃. This can be obtained as follow:

Mass of Cl in Al(ClO₃)₃ = 106.5 g

Mass of Al(ClO₃)₃ = 277.5 g

Percentage of Cl =?

Percentage of Cl = mass of Cl / mass of Al(ClO₃)₃ × 100

Percentage of Cl = 106.5 / 277.5 × 100

Percentage of Cl = 38.4%

Answer:

Explanation:

You can make a couple of statements.

Answer:

The wolves role in the ecosystem is to hunt/eat deer. In the question it states, "...ranchers aggressively killed wolves because they posed a threat to their cattle. As the wolf population declined, the deer population began increasing." It's clearly cause and affect, the wolves use to eat a lot of deer, then a large percentage of wolves died by the ranchers. The wolves role in the ecosystem is to hunt deer and help balance out animal to vegetation ratio.

Explanation:

Because i'm awesome lol

(Give me good ratings pleaseeeee.

Answer:

Explanation:

Dear student, this question appears to be incomplete but in the diagram attached below, I have carefully drawn out the required organic structure.

The aim of this question is to show the mechanism of the given structure and to point out the resonance structure.

The first diagram shows the complete part (i.e. the structure of the organic compound) and its major product(answer).

The second diagram shows the mechanism by which we arrived at the major product.

From the second diagram attached below, the -oxo substituent of the methanol attacks the hydrogen atom as shown below, leading to the formation of the enolate ion (a resonance stabilized anion).

However, this is because the alpha carbon attaches to the hydrogens readily leaves as H⁺ to yield an enolate ion as a result of -C- that is doubly bonded to oxygen (an Electron withdrawing group).

Kindly check out the images attached below to see the mechanism.

Answer:

a. Volatile.

b. Air foil.

c. Sash.

d. Work surface.

Explanation:

In science, matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.

Generally, matter exists in three (3) distinct or classical phases and these are;

I. Solid.

II. Liquid.

III. Gas.

Matching the terms with their respective definition, we have;

a. Volatile: A characteristic that describes substances that evaporate readily, producing large amounts of vapors.

b. Air foil: the front vent of a fume hood, which helps maintain proper air circulation.

c. Sash: the glass panel in front of the fume hood that shields the user from fumes and other hazards.

d. Work surface: the horizontal, flat area of a fume hood upon which experiments are carried out.

Answer:

The answer is "52.8".

Explanation:

Please find the graph file in the attachment.

They have the atoms in 8 corners with one unit cell in an one so mesh (SCC).

Atoms throughout the corner contribute [tex]\frac{1}{8}[/tex]to both the cell unit

Atom number per SCC unit cell, [tex]Z = (8 \times \frac{1}{8}) = 1[/tex]

Let 'r' become the atom's radius.  [tex]r = 3.43\times 10^{-8}\ \ cm[/tex]

We can see from the diagram that edge length [tex]AB = a = 2r[/tex]

[tex]Packing\ efficiency = \frac{(1 \ atom \ Volume \times Z)}{Volume \ of \ unit\ cell \times 100}\\\\[/tex]

                                 [tex]= \frac{\frac{4}{3}\times \pi \times r^3 \times 1}{a^3 \times 100}\\\\=\frac{\frac{4}{3}\times \pi \times r^3 \times 1}{(2r)^3 \times 100} \\\\=\frac{\frac{4}{3}\times \pi \times( 3.43\times 10^{-8}cm)^3 \times 1}{(2\times 3.43\times 10^{-8}cm)^3 \times 100}\\\\= 52.8 \%[/tex]