A 2.30kg hoop 2.20m in diameter is rolling to the right without slipping on a horizontal floor at a steady 3.00rad/s .
Part A
How fast is its center moving?
Part B
What is the total kinetic energy of the hoop?
Part C
Find the magnitude of the velocity vector of each of the following points, as viewed by a person at rest on the ground: (i) the highest point on the hoop; (ii) the lowest point on the hoop, (iii) a point on the right side of the hoop, midway between the top and the bottom.
Separate your answers by commas.
Part E
Find the magnitude of the velocity vector for each of the points in part (C), except as viewed by someone moving along with same velocity as the hoop.
Separate your answers by commas.

Answer:

this video shows how to solve the problem :)

Explanation:

The amount of force that hit the wall is 200N.

Force is a physical quantity that denotes ability to push, pull, twist or accelerate a body and which has a direction.

The force can be calculated by multiplying the mass by the acceleration as follows:

Force = mass × acceleration

According to this question, an object of 20kg accelerates at 10 m/s² into a wall. The force applied is as follows:

Force = 20kg × 10m/s² = 200N

Therefore, 200N is the force applied by the object on the wall.

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Only when heat is transferred from the system to its surroundings does a closed system suffer a decrease in entropy.

define entropy ?

Entropy is a key term in physics and chemistry, and it also has applications in cosmology and economics. It is a branch of physics known as thermodynamics. It is a key idea in physical chemistry.

Entropy is the measure of the disorder of a system. It is a comprehensive feature of a thermodynamic system, which implies that its value varies with the amount of matter present. Entropy is usually denoted by the letter S in equations and has units of joules per kelvin (JK1) or kgm2s2K1. Entropy is low in a highly ordered system.

Only when heat is transferred from the system to its surroundings does a closed system suffer a decrease in entropy.

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Average force acting on Purley is -1749m/[tex]s^{2}[/tex].

What is Newton's second law of motion?

According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is determined by multiplying its mass by its speed.

Given,

According to newton's second law of motion:

F =ma

Purley's initial speed = 173km/h

Final speed = 0

Distance traveled = 0.66 m

So, [tex]v_{i}[/tex] = 172 km/h × 1 hr/3600 s × 1000m/1km

[tex]v_{i}[/tex] = 48.1 m/s

By using kinematics

[tex]v^{2} f[/tex] = [tex]v^{2} i[/tex] + 2ad

[tex]0^{2}[/tex] = 48.[tex]1^{2}[/tex] + 2a(0.66)

-1.32a = 2309

a= -1749 m/[tex]s^{2}[/tex]

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The acceleration will be 0.2m/s^2 while the velocity will be 1m/s

Force = 300N

Mass = 1500kg

Time = 5 seconds

We know that

Force = ma

a = F/m

a = 300/1500

a = 0.2 m/s^2

Also, the expression for Velocity is given as

Ft = mv

300*5 = 1500*v

Making velocity the subject of the formula we have

1500 = 1500*v

v = 1 m/s

The rate of change of an object's velocity with respect to time is defined as acceleration.

Acceleration implies that the speed is changing, but this is not always the case. When an object moves in a circular path at a constant speed, it is still accelerating because its velocity direction changes.

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The terminal velocity of gold sphere is 39.2 cm/s

Terminal velocity is the maximum velocity attainable for an object as it falls through a fluid.

The terminal velocity of the gold sphere is given by v = 2gr²(ρ - σ)/9η where

So, susbtituting the values of the variables into the equation, we have that

v = 2gr²(ρ - σ)/9η

v = 2 × 9.8m/s²× (10⁻² cm)²(19 g/cm³ - 1.0 g/cm³)/(9 × 10⁻³ Pa-s)

v = 2 × 9.8 m/s² × 10⁻⁴ cm² × (18 g/cm³)/(9 × 10⁻³ Pa-s)

v = 2 × 980 cm/s² × 10⁻⁴ cm² × 2 g/cm³/(1 × 10⁻³ Pa-s)

v = 3920 g/s² × 10⁻⁴/(1 × 10⁻³ Pa-s)

v = 392 cm/s × 10³ × 10⁻⁴

v = 392 × 10⁻¹ cm/s

v = 39.2 cm/s

So, the terminal velocity is 39.2 cm/s

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The acceleration of the crate is 0 m/s2.

This is because the force applied is equal to the force of friction between the crate and the floor, so the crate is not accelerating. The force of friction is equal to the force applied, and since no acceleration is occurring, the force must be equal to the mass of the crate multiplied by the acceleration of gravity (9.81 m/s2).

This means that the force applied (1 N) is equal to the mass of the crate (27 kg) multiplied by the acceleration of gravity (9.81 m/s2). Therefore, the acceleration of the crate is 0 m/s2.

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A planet has a different meaning than the astronomical understanding of what a planet is. Before the advent of telescopes, the night sky was thought to consist of two very similar components. Fixed stars, which are stationary relative to each other, and moving objects ("wandering stars").

What are planets?

Planets are large, round objects that are neither stars nor remnants. The best theory of planet formation available is the nebular hypothesis, which postulates that interstellar clouds collapse from the nebula, creating young protostars orbiting the protoplanetary disk. Planets grow within this disk by the gradual accumulation of matter by gravity, a process called accretion. The solar system has at least eight planets: the terrestrial planets Mercury, Venus, Earth, and Mars, and the giant planets Jupiter, Saturn, Uranus, and Neptune. Each of these planets rotates around an axis that is tilted with respect to the poles of its orbit. All of them have atmospheres, but Mercury's is faint, and some share features such as ice caps, seasons, volcanism, hurricanes, tectonics, and even hydrology. Except, the planets in our solar system generate magnetic fields, and all planets except Venus and Mercury have natural satellites. Giant planets have planetary rings, most notably Saturn's rings.

Some cultures equate celestial bodies with gods, and these connections to mythology and folklore exist in naming schemes for newly discovered celestial bodies in the solar system. When the heliocentric theory superseded the heliocentric theory in the 16th century and his 17th century, the earth itself was recognized as a planet.

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The SI unit for the penetration coefficient of ultrasonic waves is m⁻¹.

option A is the correct answer.

Penetration coefficient describes the amount of particles reduced from the infiltration of outdoor particles due to the filtering effect of the building envelope.

Ultrasonic waves describes sound waves with frequencies higher than the upper audible limit of human hearing.

The SI unit of penetration coefficient of ultrasonic waves is expressed in either decibels per meter ( dB/mv ), or nepers per meter ( Np/m ) or equivalent to per meter ( m⁻¹ ).

Thus, the SI unit for the penetration coefficient of ultrasonic waves is per meter ( m⁻¹ ).

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The Thevenin Voltage (Vr) of the circuit with respect to Z is 6V.

Thevenin Voltage (Vr) is the equivalent voltage source in a Thevenin equivalent circuit. It is the open circuit voltage that exists between the two terminals of a circuit when all other elements are removed.

The Thevenin equivalent of the above circuit with respect to Z is Vr

= 6V, ise = 0.5A, and ZT = 4Ω.

Calculate the Thevenin Voltage (Vr)

Step 1a: Calculate the total resistance in the circuit

Rtotal = (2Ω + 3Ω) || (4Ω + 5Ω)

      = (2Ω*5Ω)/(2Ω + 5Ω) + 4Ω

      = 7 Ω

Step 1b: Calculate Thevenin Voltage (Vr):

Vr = (Rtotal/(Rtotal + 4Ω))*6V

  = (7Ω/(7Ω + 4Ω))*6V = 6V

Calculate the Thevenin Impedance (ZT)

ZT = Total = 7Ω

Calculate the short-circuit current (ise)

ise = Vr/ZT  = 6V

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The acceleration will be constant and in a downward direction. And as the ball moves in direction of the acceleration so the velocity will keep increasing because velocity is inversely proportional to height, when the ball is in free fall.

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is accelerating.

Free fall is characterized as a condition where an object is only affected by gravity. The ball experiences an external force, which quickens its motion. Gravitational acceleration is another name for this rate of free-fall acceleration. A downward motion without any beginning force or speed is called a free fall.

Hence, the acceleration will be constant and in a downward direction. And as the ball moves in direction of the acceleration so the velocity will keep increasing because velocity is inversely proportional to height, when the ball is in free fall.

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The accelaration of the edge of the rotor is linear acceleration.

Accelaration is the rate of the change of the velocity of an object with respect by time.

The electric motor is  spinning at a rate of 2695 Devolution Permanent. By two by over 60 is how this can be converted into reading persecond. The value is coming out at 282.08 ingredient per second. The areas of the model is 7.605 cm. The linear acceleration of the by  motor is what we have to l find. We have to find out of  the tangential acceleration that is given by the formula and omega squared R, if I substitute the values. This will be to 82.08 The  motor has a linear Acceleration.

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If initial horizontal velocity  (Vxi) = 10 m/s, then final horizontal velocity (Vxf) = positive 10m/s.

option B is the correct answer.

The horizontal velocity of a projectile is the velocity of the projectile along the x - axis or x - direction.

During the horizontal motion of a projectile, the horizontal velocity of the projectile will be constant since gravity does not act in the horizontal direction.

That is to say, that the initial velocity of the projectile along horizontal direction will be equal to the final velocity of the projectile along the same horizontal direction.

Vxi = Vxf

where;

Thus, If the initial horizontal velocity is 10 m/s. then the final horizontal velocity will be 10 m/s.

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VL (peak) = VL × √2= 2.335 angle (90) volts is the rms current in the circuit.

Rms current is Root-Mean-Square of instantaneous current values. The RMS value of alternating current is given by direct current which flows through a resistance

At resonance the capacitive and inductive reactance are such that they cancel each other and the circuit is entirely resistive at that point

so,

At resonance the current is given as

I(rms) = Erms/R = 125 /740 = 0.169 A= 1.6 × 10^-1 A

Now for series RLC circuit the resonant frequency is given as

w= 2πf=1/• LC = 1/√41× 10^-3* 0.44××10^-3

f= 37.94 Hz

The inductive reactance at resonant frequency is given as

xL= jwL = j 2πf×L = j×2×π×37.94×41×10^-3 = j9. 77 ohm= 9.77 angle (90)

as 9.77 angle (90) = 9.77 cos 90+ j9. 77 sin (90) = 0+ j9.77

So the voltage across the inductor is given as

VL= I×XL

=0.16 × 9.77 angle (90) = 1.65 angle (90)

Note this is the rns value for the peak value the voltage is to be multiplied by √2

VL (peak) = VL ×√2= 2.335 angle (90) volts

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Part A. The midway magnitude of the electric field is 17.2 * 10³ N/C.

Part B. The electric field intensity is 47.17 * 10³ N/C N/C when the wire shape is a circle.

The intensity of an Electric Field

Given this, the wire length is 9.50 cm and the charge density is 125 nC/m.

Part A

The electric field at the wires halfway is

E = q/4πε * 1/ (z(z²/a²+1)¹/²)

Where E is the intensity of the electric field, 8.85*10⁻¹² is the permittivity, z is 5.5 cm, a is the midpoint, 9.5/2 cm, and q is the charge density.

Substituting the value in the above equation

E = 17.2 * 10³N/C

The midway magnitude of the electric field is 17.2 * 10³ N/C

Part B

When the wire is a circle then, the charge density at the wire is

Q = q*l

Q= 1.235 * 10⁻⁸ * 0.095

Q = 1.235*10⁻⁸ C

And to calculate the radius

r = l/2π

r = 9.50/ 2*3.14

r = 1.512cm

r = 0.015m

The electric field density at the midpoint of the circle is,

E = Q/4π * z(z²+r²)¹/² * E

Substituting the values in the above equation, we get

E = 47.17 * 10³ N/C

The electric field intensity is 47.17 * 10³ N/C N/C when the wire shape is a circle.

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If all pipelines are round and of the same elevation as the question suggests, then point B's gauge pressure is 11.5 KPa.

Distance above water level is known as elevation. Elevations are often expressed in feet or meters. On charts, they can be represented by contour lines that link points of the same elevation, by colours, or by numbers that indicate the precise elevations of specific places on the Planet's surface.

From continuity equation:

Velocity of water at B = (2*pi*3²)/[2*pi*1²] =9 m/s

then from Bernoulli equation;

v² /2 + φ + p/ρ =constant

ρ=1000 kg/m³

3²/2 +φ +50000/1000 = 9²/2 +φ +P/1000

Therefore,

Pressure at B = 11.5 KPa

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The complete question is-

The 3.0 cm-diameter water line in the figure splits into two 1.0 cm-diameter pipes. All pipes are circular and at the same elevation. At point A, the water speed is 2.0 m/s and the gauge pressure is 50 kPa.

What is the gauge pressure at point B?

That which occurs during weak electrical stimulation of the presynaptic neuron is;

Weak activity of the presynaptic neuron leads to modest depolarization and calcium influx through NMDA receptors.

what are NMDA receptors?

The N-methyl-D-aspartate receptor, is described as a glutamate receptor and ion channel found in neurons.

The NMDA receptor is one of three types of ionotropic glutamate receptors, the other two being AMPA receptors and kainate receptors.

In the context of the roles of nmda receptors and ampa receptors in long-term potentiation (ltp), weak activity of the presynaptic neuron leads to modest depolarization and calcium influx through NMDA receptors.

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The potential energy (PE) and kinetic energy (KE) of the skateboarder at the end of the simulation is PE = 0 J; KE = 1,560 J. Hence option 2 is correct.

Potential energy is defined as the energy stored that an object can hold due to its position in relation to other objects, internal tensions, electric charge, or other circumstances. One of the two types of energy is potential energy, which is the latent energy in an object at rest.

The skateboarder's potential energy is transformed into kinetic energy, also known as the energy of motion, as her position along the track and speed vary. The system's total potential energy determines the maximum amount of kinetic energy the skateboarder can possess.

Thus, the potential energy (PE) and kinetic energy (KE) of the skateboarder at the end of the simulation is PE = 0 J; KE = 1,560 J. Hence option 2 is correct.

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When helium-3 and deuterium combine in this nuclear process, regular helium and a proton are produced, wasting less energy and making the reaction easier to contain.

The fusion of deuterium and tritium is the most promising of the hydrogen fusion processes that make up the deuterium cycle.

The reaction produces 17.6 MeV of energy, but in order to induce fusion, one must tunnel through the coulomb barrier, which requires extremely high temperatures.

Therefore, 8.4 1020 joules of energy would be released if one ton of deuterium were to undergo the fusion reaction with tritium. This is comparable to the 2.9 1010 joules of energy found in a ton of coal.

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The wavelength of light emitted from the tube as atom returns to the ground state is 1.02×[tex]10^{-7[/tex]m.

The spectrum of the electromagnetic radiation emitted or absorbed by an electron during transitions between different energy levels within an atom. When an electron gets excited from one energy level to another, it either emits or absorbs light of a specific wavelength.

The wavelength can be determined by either energy or by frequency.

in the question energy of an atom is given, so we will use wavelength energy formula.

λ=hc/E =6.626×10⁻³⁴J⋅s×2.998×10⁸m⋅s⁻¹/12.08 ×1.6×[tex]10^{-19[/tex]

= 19.864×[tex]10^{-7[/tex]/19.328

= 1.02 ×[tex]10^{-7[/tex] m

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According to the given statement, the speed of a point on the rim  is 2.68 m/s.

Energy is a major factor in our everyday routines even though it is an essential need for humans. Our human-made structures are not only heated by energy, but also cooled by it. To lift you finger, climb out of bed, or even stroll down main sidewalk, you need energy.

kinetic energy = E = 0.18 J  

mass = m = 100g = 0.1 kg

diameter = d = 8.0 cm = 0.08 m

Speed = v = ?

v = 2.44 m/s

Briefing:

First convert diameter into radius

r = d/2 = 0.08/2 = 0.04 m

The moment of inertia of disc is given by

I = 0.5mr²

In which m is the disk's mass & r is its radius

I = 0.5(0.1)(0.04)²

I = 0.00008 kg.m²

Additionally, since we are discussing rotating motion, rotational kinetic energy is provided by

E  =  0.5 I ω²

we have to separate ω

ω² = E/0.5 I

ω = √E/0.5 I

ω = √0.18/0.5(0.00008)

ω = 67.08 rad/sec

Finally we know that speed is given as

v = ω r

v = 67.08 (0.04)

v = 2.68 m/s

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The Final tension in the rope is 473.4N.

a=0.0337m/s²

T=mg-ma=m[g-a]

=473.4N

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According to the given statement M = 18.67 x 10⁶ Solar masses of the object that the star is orbiting.

The rate at which the position of an object shifts in any direction. Speed is defined as the ratio of the distance traveled to the time required to cover that distance. Speed is a numerical number since it just has a path and no magnitude.

Briefing:

M = Mass of Object = ?

v = orbital speed of star = 1100 km/s = 1100000 m/s

G= 6.67 x 1011 N.m2/kg is the universal gravitational constant,

r = distance between star and object = (22 light-days)(2.59 x 10¹³ m/1 light-day) = 5.698 x 10¹⁴ m

Therefore,

[tex]M=\frac{(1100000 \mathrm{~m} / \mathrm{s})^2\left(5.698 \times 10^{14} \mathrm{~m}\right)}{6.67 \times 10^{-11} N . \mathrm{m}^2 / \mathrm{kg}^2}[/tex]

M = (9.39 x 10³⁷  kg)(1 solar mass/ 1.989 x 10³⁰ kg)

M = 18.67 x 10⁶ Solar masses

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The expression representing width is w = 3l +5, where l = length. When area is 26, the equation for length is 4[tex]l^{2}[/tex]+5l -26=0.

Rectangle is a parallelogram with its opposite sides equal. We can find area of rectangle using the formula,

Area is defined as the extent occupied by an object in 2D plane. The plane may be flat or curved region. The S.I. unit of area is square meter.

Area = length × width

So,  we have length = l,

as per the given information in the question,

width = w = 4l+5

So, area, a = (4l+5) ×l= 26

     4[tex]l^{2}[/tex] +5l = 26

4[tex]l^{2}[/tex] +5l-26 = 0

Solving this equation, we can find the value of l and then width.

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To calculate the distance to a star cluster using the main-sequence fitting method, we must first be able to build the cluster's main sequence in order to "fit" it to the standard main sequence.

The vast collections of stars known as stellar clusters. There are two primary categories of star clusters: globular clusters, which are gravitationally coupled tight groups of stars between 10,000 and 500,000 years old, and open clusters, which are more loosely bound groups of stars, typically with fewer than a few hundred members and frequently extremely young. While open clusters are being disrupted over time by the gravitational pull of massive molecular clouds as they move through the galaxy, cluster members will still move through space largely in the same direction even though they are no longer gravitationally bound; at this point, they are known as a stellar association, also known as a moving group.

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Dark matter was first detected because the excess for the amount of gravity that could be present due to the luminous mass.

Since, by measuring the rotation of the galaxies and their gravitational attraction, the scientists determined that there appeared to be an excess of gravity, which could not be explained by the amount of luminous mass present. This led to the conclusion that dark matter must exist to explain this excess gravity.

Dark matter plays a fundamental role in the formation and evolution of galaxies. This invisible matter is composed of subatomic particles that interact with gravity, but does not emit light, so it cannot be detected directly. Despite this invisibility, advances in technology have allowed scientists to determine the amount of dark matter present in the Universe and its contribution to the evolution of galaxies.

Studies of galaxies suggest that dark matter plays an important role in their formation, this means that dark matter is responsible for the formation of galactic structures, such as disks and the central bar.

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The answer to the question is 5.66 feet for the channel's diameter after 2 if it is 12 feet wide at 1.

Simply expressed, upstream activities comprise the discovery and production of petroleum and natural gas, whereas downstream activities relate to the procedures used from the extraction phase until the product is given to the client in the desired shape.

[tex]$$\begin{aligned}& F r_1=\frac{V_1}{\sqrt{g V_1}}=0.5 \text {, or } \sqrt{g Y_1}=2.0 V_1 \\& \text { and } \\& F_{r_2}=\frac{V_2}{\sqrt{g y_2}}=3.0 \text { where } y_2=0.5 y_1 \\& \text { Thus, } \frac{V_2}{\sqrt{0.5 g Y_1}}=3.0 \text {, or } \sqrt{g y_1}=V_2 /(3 \sqrt{0.5}) \\& \text { By equating Eq. (1) and }(2) ; 2.0 V_1=V_2 /(3 \sqrt{0.5}) \\& \text { or } \\& V_2=4.24 V_1\end{aligned}$$[/tex]

However,

[tex]$Q_1=Q_2$[/tex] or [tex]$b_1 y_1 V_1=b_2 y_2 V_2$[/tex]

where [tex]$b=$[/tex] channel width. Thus, with [tex]$b_1=12 \mathrm{ft}$[/tex]

(12ft)y₁(V₁) = b₂(0.5y₁)(4.24V₁) or b₂ = 12ft/0.5(4.24) = 5.66ft

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The complete question is-

In flowing from section 1 to section 2 along an open channel, the water depth decreases by a factor of 2 and the Froude number changes from a subcritical value of 0.5 to a supercritical value of 3.0. Determine the channel width at 2 if it is 12 ft. wide at 1.

Answer:

heat and pressure is the correct answer

The Hypnotic Induction Profile (HIP) or the eye roll test, first proposed by Herbert Spiegel, is a simple test to loosely determine if a person is susceptible to hypnosis. A person is asked to roll their eyes upward. The degree to which the iris and cornea are seen is measured.

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According to statement no, only system in general is constrained by conservation of momentum.

A surface is said to be frictionless if it has a loads applied on any thing that is virtually zero or insignificant, i.e., there is no resistance between the surface and the substance, allowing that object simply slide & freely move without any friction.

Although gas, sand, radiation, fields, and minuscule particles are present in outer space, their concentration is too low for them to have a significant impact on spacecraft. As a consequence, traveling objects cannot be slowed down in space by any kind of friction.

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