a 30-kg child sitting in a chair applies a force of approximately 300 N downward. on the chair approximately how much force does the chair apply upward to the child

A. 10N
B. 30N
C. 300N
D .600N​

Answer:

The force of Gravity on the ball

Explanation:

Gravity of earth pulls the ball back down to the ground.

Answer: It is a transverse wave ^^

Explanation:

Answer:

I’m. Nog sure

Explanation:

Answer:

A. The expected electricity bill for this month is Rs 18,896.2

B. The item which consumed the most energy during the month is the electric cooker with a total consumption of 1,110Kw/Month

Explanation:

Step 1 - Identify electrical appliances

I only have 8 electrical appliances in my home.

Step 2 - Assign usage per hour and calculate wattage used /month

Step 3 - Add up all the Kw used per month and multiply by the cost of 1 Kw

Total Kilowatt Consumed/Month = 1110 +108+120+10+84.6+421.2+29.7+6.12

= 1,889.62Kw/Month

Total cost of energy consumed per month = 1889.62 * Rs 10

= Rs 18,896.2

Cheers!

Answer:

Because both monomers and polymers and cross linked polymers are mers with physically properties which is good for applycations

Explanation:

because they are good for using and not using

also, this is a 5 point question, you are not  fooling anyone. thx for 5 points tho

Answer:

20 Hz, 20000 Hz

0.0166 m, 16.6 m

Explanation:

The minimum frequency that a human ear can hear is 20 Hz

The maximum frequency that a human ear can hear is 20000 Hz.

v = Velocity of sound = 332 m/s

Wavelength is given by

[tex]\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{332}{20}\\\Rightarrow \lambda=16.6\ \text{m}[/tex]

The longest wavelength that can be heard by the human ear is 16.6 m

[tex]\lambda=\dfrac{332}{20000}\\\Rightarrow \lambda=0.0166\ \text{m}[/tex]

The shortest wavelength that can be heard by the human ear is 0.0166 m.

Answer:

Approximately [tex]5.5\; \rm N[/tex], assuming that the volume of these two charged objects is negligible.

Explanation:

Assume that the dimensions of these two charged objects is much smaller than the distance between them. Hence, Coulomb's Law would give a good estimate of the electrostatic force between these two objects regardless of their exact shapes.

Let [tex]q_1[/tex] and [tex]q_2[/tex] denote the magnitude of two point charges (where the volume of both charged object is negligible.) In this question, [tex]q_1 = 20 \times 10^{-6}\; \rm C[/tex]  and [tex]q_2 = 15 \times 10^{-6}\; \rm C[/tex].

Let [tex]r[/tex] denote the distance between these two point charges. In this question, [tex]r = 0.7\; \rm m[/tex].

Let [tex]k[/tex] denote the Coulomb constant. In standard units, [tex]k \approx 8.98755\times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2}[/tex].

By Coulomb's Law, the magnitude of electrostatic force (electric force) between these two point charges would be:

[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\end{aligned}[/tex].

Substitute in the values and evaluate:

[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\\ &\approx 8.98755 \times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2} \\ &\quad \times 20\times 10^{-6}\; \rm C\\ &\quad \times 15\times 10^{-6}\; \rm C \\ &\quad \times \frac{1}{{(0.7\; \rm m)}^{2}}\\ &\approx 5.5\; \rm N \end{aligned}[/tex].

Answer:

B

Explanation:

I can't explain right now, mabe later.

Answer:

299,792,458 m/s = speed of light

Explanation:

Answer:

What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.

Explanation:

What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.

Answer:

2.5m/s²

Explanation:

Given parameters:

Mass of car  = 1400kg

Resultant force  = 3500N

Speed  = 30m/s

Unknown:

Average acceleration = ?

Solution:

According to the Newton's second law of motion:

     Force  = mass x acceleration

Now;

       3500 = 1400 x acceleration

      Acceleration  = [tex]\frac{3500}{1400}[/tex]   = 2.5m/s²

Answer:

See the answer below

Explanation:

The time Laura took to reach the post office would depend on the speed of cycling.

We know that;

 speed = [tex]\frac{distance}{time}[/tex]

hence,

time = [tex]\frac{distance}{speed}[/tex]

Since the distance from Laura's house to the post office is 4 km, the equation becomes;

time = [tex]\frac{4}{speed}[/tex]

Just ensure that the speed is in km per hour, minute, or seconds in order to obtain the time in hours, minutes, or seconds respectively.

Answer:

The new force is 2.8125 N

Explanation:

Newton’s Law of Universal Gravitation

Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.  

[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]

Where:

m1 = mass of object 1

m2 = mass of object 2

r     = distance between the objects' center of masses

G   = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2

Suppose two spheres have a gravitational force between them of F = 45 N. Now increase the distance to r'=4r. The new force F' is:

[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{(4r)^{2}}}[/tex]

[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{16r^{2}}}[/tex]

[tex]\displaystyle F'=\frac{1}{16}\ G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]

Substituting the original value of the force:

[tex]\displaystyle F'=\frac{1}{16}\ 45 N[/tex]

F' = 2.8125 N

The new force is 2.8125 N

Answer:

[tex]\boxed {\boxed {\sf 12 \ Newtons }}[/tex]

Explanation:

Force is equal to the product of mass and acceleration.

[tex]F=m*a[/tex]

We know the mass, but not the acceleration. Therefore, we must calculate it before we can calculate force.

1. Calculate Acceleration

Acceleration is the change in velocity over the change in time.

[tex]a=\frac{V_f-V_i}{t}[/tex]

The final velocity is 10 meters per second and the initial velocity is 4 meters per second. The time is 1 second.

[tex]V_f=10 \ m/s \\V_i= 4 \ m/s \\t= 1 \ s[/tex]

Substitute the values into the formula.

[tex]a=\frac{10 \ m/s-4 \ m/s }{1 \ s}[/tex]

Solve the numerator.

[tex]a=\frac{6 \ m/s}{1 \ s }[/tex]

Divide.

[tex]a= 6 \ m/s/s=6 \ m/s^2[/tex]

2. Calculate Force

Now we know the acceleration and the mass.

[tex]m= 2 \ kg \\a= 6 \ m/s^2[/tex]

Substitute the values into the fore formula.

[tex]F= 2 \ kg * 6 \ m/s^2[/tex]

Multiply.

[tex]F= 12 \ kg*m/s^2[/tex]

[tex]F= 12 \ N[/tex]

The force applies to the ball was 12 Newtons.

Answer:

The planets spun in epicycles.

Explanation:

The planets were not simply attached to a mystical sphere (“deferent”) but they were actually attached to a mini-sphere (“epicycle”) which rotated on the larger one.

Answer:A

Explanation:

Figure 1= binary fission in amoeba

figure 2= budding in yeast

difference

1.Parent divides to form two daughter cells and itself gets disappeared in binary fission but in budding , a bud gets matured and detaches from the parent

Answer:

The index of refraction varies with frequency or color. Frequency does not change as light travels from one medium to another.

Explanation:

Green light has a higher refractive index than orange light for the same material because orange color has a higher wavelength than green light and if the wavelength of light increases the refractive index decreases.

The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is more frequently described in nanometers (nm), which are units of 10-9 m, or angstroms, which are units of 10-10 m, for infrared (IR), visible light (UV), and gamma radiation.

Frequency, which is defined as the number of wave cycles per second, and wavelength have an inverse relationship. The wavelength of a signal decreases with increasing frequency, or we can say that wavelength and refractive index are inversely proportional to each other.

To get more information about Wavelength :

https://brainly.com/question/13533093

#SPJ5

Explanation:

W=f×d

=20×6

w=120 joule

Answer:

W= F × d

W= 2kn × 3.6

W= 7.2 J

Work is measured in Joules!

Answer:

b

Explanation:

Answer:

Inside a femur bone found in the woods,

saliva of gum

Answer:

1.  -0.863 kgm/s 2. -1.438 kgm/s

Explanation:

1. What is the change in momentum of the bullet if it embeds in the block?

Since the block does not move, the velocity of the bullet after hitting the block , v is zero. That is v = 0 m/s

Now, the momentum change of the bullet ΔP = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = 0 m/s (since it embeds in the block and the block does not move).

So, ΔP = m(v - u)

= 5.75 × 10⁻³ kg(0 m/s - 1.50 × 10² m/s)

= 5.75 × 10⁻³ kg(- 1.50 × 10² m/s)

= -8.625 × 10⁻¹ kgm/s

= -0.8625 kgm/s

≅ -0.863 kgm/s

2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?

If it bounces off the block in the opposite direction with a speed of 100 m/s, then its final velocity is v = -100 m/s.

So, our momentum change ΔP' = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = -100 m/s = -1 × 10² m/s

So, ΔP = m(v - u)

= 5.75 × 10⁻³ kg(-1 × 10² m/s - 1.50 × 10² m/s)

= 5.75 × 10⁻³ kg(-2.50 × 10² m/s)

= -14.375 × 10⁻¹ kgm/s

= -1.4375 kgm/s

≅ -1.438 kgm/s

Answer

given :

m=1.4 kg

r/q = N

N = m(9.8)

= 1.4 kg(9.8)

= 13.72 Newton

Answer:

9.8066500286389 N

Explanation:

Answer:

5.28 x 10⁻⁹N

Explanation:

Given parameters:

Mass of alien  = 71kg

Distance  = 670m

Mass of ship  = 500000kg

Unknown:

Gravitational attraction  = ?

Solution:

The gravitational attraction can be found using the Universal gravitation law proposed by Newton;

      Fg  = [tex]\frac{G x mass 1 x mass 2}{d^{2} }[/tex]  

G is the universal gravitation constant  = 6.67 x 10⁻¹¹

 d is the distance

 Fg is the gravitational attraction

  Fg  = [tex]\frac{6.67 x 10^{-11} x 71 x 500000 }{670^{2} }[/tex]   = 5.28 x 10⁻⁹N