a 35 kg chair is lifted 5M off the ground. what is the potential energy?

Based on the length of a football field and the timeline of earth's history, the first 10 yards represents 460 million years.

Beginning from 460 million years ago, there was massive explosion and expansion of life on earth.

A timeline of earth's history shows the events that occurred from the beginning when earth was formed 4.6 billion years ago until today.

In this activity, a football field is used to represent the timeline of earth's history.

Each end of the football field represents the two end zones, Earth's beginning and TODAY end zone.

Thus, the first 10 yards equals = 46,000,000 × 10 The The first 10 yards = 460,000,000 years.

From the TODAY end zone, the the first 10 yards = 460,000,000 years.

460,000,000 years ago marked the time from the appearance of the first plants until humans and all life on earth as it is today.

This, meant that within this period, there was massive explosion and expansion of life on earth.

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Answer:

b. migration

A migration can be defined as the changes that occur in the behavior, structure, physiology of the organism so as to allow it to survive in unfavorable environmental conditions. Behavioral adaptation can be defined as the changes that occur in an organism's behavior which affects it's actions and helps it to survive like choice of mating partner, calling the mates for copulation and migration to different location all are the examples of the behavioral adaptations

Explanation: Behavioral adaptations are the things organisms do to survive. For example, bird calls and migration are behavioral adaptations. Adaptations are the result of evolution. Evolution is a change in a species over long periods of time.

We need to verify the thrid equation of kinematics here

[tex]\\ \tt\longmapsto v^2-u^2=2as[/tex]

[tex]\\ \tt\longmapsto 20^2=2(-8)s[/tex]

[tex]\\ \tt\longmapsto 400=-16s[/tex]

[tex]\\ \tt\longmapsto s=|400/-16|[/tex]

[tex]\\ \tt\longmapsto s=25m[/tex]

The squirrel has a good luck ,Car gets stopped just 1m away from the squirrel .

Explanation:

According to the Question

A squirrel runs out in front of a car moving at +20m/s ( initial speed u) . The driver slams on the brakes and begins decreasing at -8m/s² ( here the acceleration is acting in opposite directions of motion a )

When Squirrel was 26 metres ( Distance from the car initially )

Using Kinematic Equation

On substituting the value we obtain

➥ 0² = 20² + 2 × -8 × s

➥ 0 = 400 - 16 × s

➥ -400 = -16 × s

➥ 400/16 = s

➥ 25 = s

So, the squirrel is 25 metres from the car .

Answer:

4.26 m/s

Explanation:

h = 0.925

v = 0

u = ?

v = u^2 - 2gh

0 = u^2 - 2gh

u = sqrt 2gh

= sqrt 2*9.8*0.925

= 4.258

= 4.26

Communication is the act of conveying information from one person to another. .'Good communication makes it difficult to express wants and needs.'These statement is not true about good communication.

Communication is the act of conveying information from one location, person, or organization to another. There is a sender, a message, and a recipient for every message.

Communication, while it may appear to be a simple notion, is actually a very complex topic. The message's path from sender to the destination might be influenced by a multitude of circumstances.

Hence the option 'A' is right. 'Good communication makes it difficult to express wants and needs this statement is not true about good communication.

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the answer is A

Explanation : took the quiz on edge 2020

Difference in height = 10 - 5 = 5 meters

Kinetic energy = Energy ( 500 N) x height (5 m) = 2,500 N/m  = 2,500 joules

Answer: 2,500 joules

Answer:

14m/s2

Explanation:

initial velocity=2m/s

final velocity =?

time=4s

acceleration=3.0m/s

v=u+at

v=(2)+(3*4)

v=14m/s

by substituting the values in the equation we get the value 14m/s.

Answer:

➢when you crank you make kinetic energy and then the kinetic energy makes potential energy.

Explanation:

hope it will help you have a great day bye and Mark brainlist if the answer is correct

[tex]kai6417[/tex]

#carry on learning

The protostar's surface area was 1.1  times greater.

The surface of the star can be assumed be circular and the surface area can determined as follows;

Area = πr²

[tex]Area = \frac{\pi d^2}{4} \\\\Area = \frac{(100d)^2}{(95d)^2} \\\\[/tex]

Surface area = 1.1 times greater

Thus, the protostar's surface area was 1.1  times greater.

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Answer:

The Bowling Ball is Denser.

Explanation:

If we consider both balls in terms of mass they are very different.  Size and volume can be the same though.

What makes the mass?  Think of what fills each of the balls.

A Basketball is filled with air, which weighs very little.

Meanwhile, a bowling ball is filled with coverstock, made up of plastic, urethane and resin.  These materials weigh considerably more than air!

Answer:

Depends

Explanation:

If you understand the content rush through questions. If you dont understand learn the key concepts of all the chapters then on the commute tomorrow test your self on the concepts. Good luck!

[tex]\bold{\huge{\pink{\underline{ Solution }}}}[/tex]

Concept Used :-

Here, we will use the concept of speed, distance and time

We have given two conditions here

We know that,

[tex]\bold{\pink{ Speed = }}{\bold{\pink{\dfrac{ Distance }{Time}}}}[/tex]

Subsitute the required values in the above formula :-

[tex]\sf{1.4 = }{\sf{\dfrac{ 500 }{t}}}[/tex]

[tex]\sf{ t = }{\sf{\dfrac{ 500 }{1 .4}}}[/tex]

[tex]\sf{ t = }{\sf{\dfrac{ 500 }{1.4}}}[/tex]

[tex]\bold{\boxed{\red{ t = 357.14 \:sec }}}[/tex]

Hence, Time taken by Elena to cover distance of 500 m is 357.14 sec

We know that,

[tex]\bold{\pink{ Speed = }}{\bold{\pink{\dfrac{ Distance }{Time}}}}[/tex]

[ Speed = 1.4 * 60 × 60/1000

Speed = 1.4 × 18/5 = 5.04 km/h }

Subsitute the required values in the above formula :-

[tex]\sf{ 5.04 = }{\sf{\dfrac{ S(Distance)}{2}}}[/tex]

[tex]\sf{ S = 5.04 }{\sf{\times{ 2}}}[/tex]

[tex]\bold{\tt{\boxed{\red{ S = 10.08 km }}}}[/tex]

Hence, The distance covered by Elena in 2 hours is 10.08 km.

Given :-

To Find :-

Solution :-

See attachment .

Firstly break the velocity of A , into it's vertical components . That will be ,

[tex] v_A = v_A cos60^o + v_A sin60^o [/tex]

Now the component , [tex]v_A cos60^o [/tex] coincides on side AC and is directed from A to C . Along CA, the velocity of particle C is directed . So both are in opposite directions.

So , the relative velocity of C with respect to A will be ,

[tex] v_{CA}= v_C - v_A [/tex]

Substitute ,

[tex] v_{CA}= v - ( - v cos 60^o) [/tex]

Value of cos 60° is 1/2 ,

[tex] v_{CA}= v + v\bigg(\dfrac{1}{2}\bigg)=v +\dfrac{v}{2}[/tex]

Add the terms,

[tex] v_{CA}= \dfrac{2v + v}{2}=\dfrac{3v}{2}[/tex]

Hence , now we can find the time taken by A and C ,to meet each other will be ,

[tex]s = v t [/tex]

Substitute ,

[tex]d = \dfrac{3v}{2} t [/tex]

Multiplying both sides by 2 ,

[tex] 2d = 3vt [/tex]

Dividing both sides by 3v ,

[tex] t = \dfrac{2d}{3v} [/tex]

Similarly , taking any two particles you will get the same time .

Hence the particles meet after 2d/3v time .

I hope this helps .

Answer:

  never

Explanation:

Particles moving on paths that don't meet at a point will be particles that never meet. Even if the paths meet at a point, which these don't, the particles may not meet if they arrive at different times.

__

Consider the diagrams in the attachments. In order, they show the positions of the particles shortly after takeoff, midway along the line, and after they have gone farther than the length of the line. The point of closest approach is shown in the second attachment, when the particles are halfway along the line.

Consider particles A and C. Their north/south direction is 'north' for each of them. They both have the same velocity in the 'north' direction, but have started at different points, so can never meet. Those two particles have opposite velocities in the east/west direction, so can pass each other (which they do in the second attachment), but cannot meet.

Answer:

Hamid

Explanation:

I got it right on my test

Explanation:

i will use chainsaw to cut a tree and even if that doesn't work I will use axe to make my work easy.

hope this helps you

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Answer:

B) 4 m/s²

Explanation:

[tex] \boxed{ \sf{ F= m \times a}}[/tex]

Here,

Substituting the respective values for F and m:

==> 220 = 55 × a

==> 220 = 55 × a

dividing the equation by 55:

==> 4 = a

Therefore, an object of 55 kg when pulled across a frictionless surface by a force of 220 N accelerates at 4 (m/s)/s

Answer:

A

Explanation:

Answer:

According to Pascals law, THE PRESSURE EXERTED TO A CONFINED LIQUID IS TRANSMITTED EQUALLY AND UNDIMINISHED IN ALL DIRECTIONS THROUGHOUT THE MASS OF THE LIQUID--Blaise Pascal

so the pressure at A2 must be equal to A1

buy however the F1 will be less than F2 since:

P1=F1/A1 and P2=F2/F1

P1=P2 according to Pascal

so, F1/A1=F2/A2

with less amount of force at P1 THE force gets multiplied.

Therefore it's obvious that option A and B is wrong. I can't see option C properly.

but, you are going to have this option.

C.F1>F2

so the option with F1>F2 is correct

PLEASE MARK BRAINLIEST

I think its D answer

sorry I dont have explanation but I think its D

Answer:

In order to minimize the potential energy, they repel each other (in the case of a positive and negative charge, potential energy is minimized by bringing them together, so they attract).

Explanation:

Hope it helps

Two electrons repel when they interact, because they both have similar negative electric charge.

When the two charges or the charged bodies interact each other, the force of attraction or repulsion acts between them. This force of attraction or repulsion can be find out using the coulombs law.

According to the Coulombs law, the force of attraction of repulsion between charged two bodies is directly proportional to the product of charges of them and inversely proportional to the square of distance between them. It can be given as,

[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]

Here, (k) is the coulombs constant,  (q1 and q2) is the charges of two bodies and (r) is the distance between the two charges.

This force of attraction or repulsion is identified by the sign of the particular charge. According to the property of interacting charges-

As the electrons are negatively charges. Therefore, two electrons repel when they interact, because they both have similar negative electric charge.

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Answer:

Electric current produces a magnetic field. This magnetic field can be visualized as a pattern of circular field lines surrounding a wire. ... Magnetic Field Generated by Current: (a) Compasses placed near a long straight current-carrying wire indicate that field lines form circular loops centered on the wire.

Explanation:

[tex]\large \bf\gray\dagger\pink{\frak{Solution}\curvearrowright}[/tex]

The feild never generates magnetic field on it's on. It simulataniously because when the flow of current stops , it loses it's magnetism and then there will no magnetism thus no magnetic feild.

Answer:

v= 4.8 m/s

Explanation:

m= 2.0

KE= 1/2 mv^2

v= ?

v= 1/2 (2.0)^2

v= 4.8 m/s

Answer:

C is the correct answer of this question.

Answer:

Speed = 24 m/s.

No! It doesn't break the speed limit.

Explanation:

The formula we'll be using to find the car's speed:

[tex] \boxed{ \mathsf{speed = \frac{distance}{time} }}[/tex]

The detectors are placed 1.2 m apart.

==> Distance the car travels = 1.2 m

The car, it says, takes 0.050 s to travel that distance.

==> Time taken by the car to travel 1.2 m = 0.050 s

Using the formula mentioned above, let's calculate the speed of the car:

[tex] \sf{speed = \frac{distance}{time} }[/tex]

[tex] \implies \sf{speed = \frac{1.2}{0.050} }[/tex]

On dividing 12 by 0.050 we obtain 24.

[tex] \implies \sf{speed = 24 \: m/s }[/tex]

Any car traveling with a speed that is greater than or equal to 25 m/s is breaking the speed limit.

And since the car in our focus is traveling at 24 m/s that is less than 25 m/s, it doesn't break the speed limit.

Apply thrid equation of kinematics

[tex]\\ \tt\longmapsto v^2=u^2+2as[/tex]

[tex]\\ \tt\longmapsto v^2=2(5)(1000)[/tex]

[tex]\\ \tt\longmapsto v^2=10000[/tex]

[tex]\\ \tt\longmapsto v=100m/s[/tex]

The variable that changes is the period of the motion.

The term simple harmonic motion refers to a regular repeating motion. The acceleration of the SHM is always directed towards the center. The spring is an example of a system undergoing simple harmonic motion.

From the description in the question, the variable that changes is the period of the motion.

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