The Mass of the board is also 60kg when a 60 kg load is located at the very end of a uniform board of length l, which is supported one-quarter of the way from the end and is balanced.
What is the Mass of the board ?The Mass of the board is also 60kg because of a 60 kg load is located at the very end of a uniform board of length l which is also balanced and supported by one end.
Given:
Load is located at the very end of a uniform board= 60Kg
length of uniform board = L
Solution:Now to find the mass of the board do as follows;
⇒FN(l/4)-Mg(l/4)-60g(l/4)=0
⇒Mg(1/4)=60g(1/4)
⇒M(mass)=60kg
Hence , the Mass of the board is also 60kg .
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Which statements are explained by Newton’s law of universal gravitation?{|
{|}Heavier objects fall faster than lighter objects.
{|}The strength of Earth’s gravity decreases as an object gets farther from Earth.
{|}The strength of gravity depends on an object’s mass.
{|}Mass and weight are the same quantities.
In the given explanations, Newton’s law of universal gravitation can be explained by the statement, "Heavier objects fall faster than lighter objects". Thus, Option A is the correct answer.
What is Universal Law?Gravity is a natural phenomenon that causes all massive objects to attract each other. The magnitude or force of this interaction depends on the masses and distance of the bodies. This causes objects to fall toward Earth, for example, and keep satellites and celestial bodies in their orbits, such as the Earth's orbit around the Sun. Gravity also causes the tidal phenomenon.
In physics, gravity can be approximated by Isaac Newton's laws of gravity. Although the accuracy of the law is sufficient, for example, when calculating the orbits of spacecraft, gravity is best described by Albert Einstein’s general theory of gravity, in which it is considered the curvature of space-time.
Newton's law of universal gravitation states that a particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Hence, Option A is the correct answer.
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A 2500-kg SUV travels around a circular track that has a radius of 85 m. The centripetal
force is 14236 N. What is the SUV's velocity? ()
Answer:
SUV's velocity is 22 m/s
Explanation:
[tex]F=\frac{mv^{2} }{r} \\\\v=\sqrt{\frac{Fr}{m} } \\\\v=\sqrt{\frac{14236 N * 85 m}{2500 kg} } \\\\v=22 \frac{m}{s}[/tex]
next we move the q and 4q charges to be 3 times as far apart as they were: two charges, q and 4q, farther apart now what is the magnitude of the force on the 4q charge?
F"=4F/9 or F"=4F ÷9 is the magnitude for the force acting on the 4q charge.
Coulomb's law states that the magnitude of the forces between Q and 4Q is,
F'=КQ×4Q÷d²
= 4F ---------------------------(1)
Now, if the distance is made 3 times greater than before, or in three dimensions,
F''=КQ×4Q÷ (3d)²
Or F''= 4КQ² ÷ 9d²
or, F''= 4÷9 × ₍КQ²÷ d²₎
or, F''= 4F/9
Coulomb's law: a rule indicating that opposing charges attract and similar charges repel, with a force proportional to the product of the charges and inversely proportional to the square of the space between them.
Dimensions: an area that may be measured for its length, width, depth, or height.
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how do the allowed orbits for electrons in atoms differ from the allowed orbits for planets around the sun? explain how the correspondence principle applies here.
The movement occurs as . Each orbit has a different energy, and electrons can move to other orbits by emitting or absorbing energy, which is also quantized.
The correspondence principle in physics states that the behavior of systems described by quantum mechanics theory reproduces classical physics in the limit of large quantum numbers.Bohr's correspondence principle is best understood as the statement that each allowed quantum transition between stationary states corresponds to one harmonic component of classical motion, according to the selection rule interpretation.To know more about Correspondence principle here
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as a result of the expansion, how do the average distances between galaxies in the distant past compare to the average distance between them today?
As a result of the expansion, parallax method is the way to compare the average distances between galaxies in the distant past and average distance between them today
Radio telescopes are used by astronomers all over the world to study the naturally occurring radio waves that are emitted by stars, planets, galaxies, clouds of dust, and gas molecules. For the most part, we are all familiar with visible-light astronomy and the information it provides about these objects. What we see with our eyes is referred to as visible light or optical light.The parallax method can be used to determine how far away nearby stars are. Over a period of six months, the position of the star in the sky is measured twice (e.g. g. both in the spring and in the fall). In contrast to stars further away, this one will seem to have moved. The same effect can be produced by holding your arm out in front of you and looking at your thumb with your left eye first, then your right eye later. The thumb will appear to leap in front of the background. The distance to the star can be calculated with ease by measuring the angle the star has shifted and knowing the radius of Earth's orbit.[tex]\alpha =L/x\\\\x=\sqrt{1-\frac{a}{y} } \\\\\alpha =\frac{L}{\sqrt{1-\frac{a}{y} }}[/tex]To study more about visible-light astronomy -
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explain the advantages of simplifying combinational logic circuits and how they make designs more efficient and beneficial to society.
Advantages of simplifying combinational logic circuits:
1. Simplified uses fewer gates to provide the same logic properties as necessary.
2. A circuit with fewer gates is smaller and less expensive than an original.
3. Because there are fewer interconnections, the reliability of the circuit will increase.
4. The circuit's operating speed goes up.
5.There are no redundant gates because of the simplification.
How simplifying combinational logic circuits make designs more efficient and beneficial to society?
It is challenging to design a circuit if it is complex, so the circuit should be as basic as feasible before design. We may need to provide a less amount of power if there are more gates. Therefore, combinational logic circuit simplification is good for society.
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Suppose you have two pairs of the same shoes in different sizes. Would their coefficients of friction be the same? Explain.
Coefficients of friction would be the same for two pairs of the same shoes in different sizes as coefficient of friction does not depend on the size of shoes and weight.
Why coefficient of friction would be same for two pairs of shoes of different sizes?The force of friction does not depend on the area of the contact and friction slows a moving object down. Frictional force depends on the nature of the surfaces in contact and the materials.
The coefficient of friction depends on the objects that are causing friction and the value is usually between 0 and 1 . A value of 0 means there is no friction between the objects.
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Write the derived unit of following physical quantities. (a) (Area) (b) (Pressure)
Answer:
The SI unit of Area is meter square (represent as m2)
The SI unit of pressure is one newton per square metre ( represent as N/m2).
what is the near point in cm of a person whose eyes have an accommodated power of 54.8 d? (assume a lens-to-retina distance of 2.00 cm.)
The near point of a person whose eyes have an accommodated power of 54.8d (assuming a lens-to-retina distance of 2cm is 20.83cm.
What is accommodated (eyes)?It is the process by which certain muscles (called ciliary muscles) function to change the focal length of the eyes so that the image is clearly formed on the retina which is called accommodation of the eye.
How to calculate the near point based on the information given from the question?
Power = P = 54.8D
Distance between the lens and the retina, Di = 2cm = 0.02m
Distance between the object and eyes, Do (we are trying to answer this)
The formula that we will use :
1 / Do = P - 1 / Di
1 / Do = 54.8 - 1 / 0.02
1 / Do = 4.8
Do = 1 / 4.8
Do = 0.2083m = 20.83cm
Therefore, the near point of a person whose eyes have an accomodated power of 54.8D is 20.83cm.
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find the energy in joules of photons of radio waves that leave an fm station that has a 90.0-mhz broadcast frequency.
5.94 ×10-26 J of energy of photons of radio waves is required to leave an FM station having 90MHz broadcast frequency
A photon's energy E and frequency f are exactly related. This is expressed mathematically as
Equation
E=hf (1)
where h is the Planck constant.
Given that the frequency of the radio wave is f=90 MHz
=9.0×107 Hz
and knowing the fact that the numerical value of Planck's constant is h=6.6×10−34 m-m-kg/s
then the energy of the photon in J using Eq. (1) is:
E=6.6×10−34× 9×107
E=5.94 ×10-26 J
what is Frequancy?
The frequency of a repeated event is its number of instances per time unit. It differs from angular frequency and is sometimes referred to as frequency for clarification. The unit of frequency is hertz (Hz), or one occurrence per second. The duration is the inverse of frequency since it is the amount of time that passes between events.
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2. A school bus moves at a speed of 35 miles per hour (mph) for 20
miles. How long will it take for the bus to arrive at school?
Answer:
Time, t = 0.57 hours or 34 minutes and 12 seconds.
Explanation:
Given:
Speed of the school bus, s = 35 mi/hr
Distance covered by the bus, d = 20 miles
Speed(s) is equal to Distance over Time (s=d/t)
Meaning time is equal to distance over speed (t=d/s)
plugging our given information into the formula, we know Time is equal to 20 over 35 (t=20/35)
20/35=0.57, so
t = 0.57 hours
the time taken by the bus to reach school is 0.57 hours or 34 minutes and 12 seconds.
Answer:
Explanation:
Mathematically, speed is given by this formula;
Speed=distance/time
Making time the subject of formula, we have:
Time = distance/speed
Substituting the given parameters into the formula, we have;
Time = 20/35
Time = 0.571 hours.
When you have two like charges in a line – where is the electric field the greatest? Is there ever a point where the field will be zero?
The magnitude of the electric field will be greater where the lines of the charges are closest to each other.
An electric field is defined as an area that holds the electrically charged particles in its physical field and the electric field also exerts a force on all charged particles either attracting them or repelling them. If the force that is exerted on the charged particle varies from one point in the field to other then the electric field is said to be non-uniform.
In opposite charges, zero is not a possibility between two charges because the field vectors from both opposite charges will head toward the negative charge.
So we can conclude that the point where the field is zero does not exist.
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a car travels 80 km east in two hours. what is its average velocity? question 27 options: 160 km/hr east. 160 km/hr west. 40 km/hr east. 40 km/hr west.
80 kilometers east in two hours in a car. The car has a westward speed is 40 km/h.
What is a simple definition of velocity?The vector illustration expression of velocity is the movement in space-time of an object or particle. The recognized unit of velocity magnitude is the centimeter per second (m/s) (also known as speed).
What is velocity vs speed?Speed is the rate at which an object is moving across a path over time, whereas velocity is the speed or direction that an organism is moving. In other words, velocity is a scalar value, but velocity is a vectors.
Briefing:An object's velocity is a vector quantity. Both magnitudes and direction are present.
Arrows serve as directional indicators.
Car A is traveling west. Moving in an east-south direction is Car B. Vehicle C is traveling in a southerly direction. Vehicle E is traveling in a northerly direction.
Therefore, the Car is moving west at a speed of 40 km/h.
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Give an example of a sport wherre shoes with a low coefficient of friction would be advantageous.
The example of a sport where shoes with a low coefficient of friction would be advantageous are hockey, football and cricket.
What do sportsmen perform in sports that have little friction?The athlete can move more quickly down the slope when there is no friction. Because there is little surface area in contact with the ice, friction is decreased. A force that is often up to eight times greater than gravity is applied to the ice as the competitors speed around a curved path.
What role does the coefficient of friction play in athletics?In a sled-towing activity, an athlete's sprint time should presumably get longer as the coefficient of friction of the running surface rises because more of the athlete's muscular force is lost to sled friction.
In football, what kind of friction is used?Football Collision
When the football is rolling or sliding during a play, frictional forces are working against it. The reason behind this is that as these balls roll across the ground, surface friction creates an opposing force that significantly slows the ball down.
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A conducting sphere of radius r carries positive charge q. Calculate the amount of work that would be required to move a small positive test charge q0 slowly from r=5r to r=3r. Assume that the presence of q0 has no effect on how the charge q is distributed over the sphere.
The amount of work requires is W=[tex]\frac{4qq_{o}}{225\pi e_{o}R^{2} }[/tex]
What is a sphere?
A sphere is a spherical, three-dimensional object. Three axes—the x, y, and z axes—are used to define the sphere. Between a circle and a sphere, this is the primary distinction. Like other 3D objects, a sphere has no edges nor vertices.
Given
Radius of Conducting Sphere is R with Positive charge q
Small sphere is at a distance of r=5 R which is required to move slowly to r=3 R
So, Electric Potential Energy Between two Charged Particle will be
U=k.[tex]\frac{q_{1}q_{2}}{r^{2} }[/tex]
Now, the initial potential energy
[tex]U_{1}[/tex]=k.[tex]\frac{qq_{o}}{5R^{2} }[/tex]
[tex]U_{1}[/tex]= k.[tex]\frac{qq_{o}}{25R^{2} }[/tex]
at r=3R
[tex]U_{2}[/tex]= k. [tex]\frac{qq_{o} }{(3R)^{2} }[/tex]
[tex]U_{2}[/tex] = k. [tex]\frac{qq_{o} }{9R^{2} }[/tex]
Work done=[tex]U_{2}[/tex]-[tex]U_{1}[/tex]
W = k. [tex]\frac{qq_{o}}{9R^{2} }[/tex] - k. [tex]\frac{qq_{o}}{25R^{2} }[/tex]
W = k. [tex]\frac{qq_{o}}{R^{2} }[/tex] [tex]\left[\frac{1}{9}-\frac{1}{25}][/tex]
W = k. [tex]\frac{qq_{o}}{R^{2} }[/tex].[tex]\left[\frac{16}{225} ][/tex]
W = [tex]\frac{1}{4\pi e_{o} }[/tex].[tex]\frac{qq_{o}}{R^{2} }[/tex].[tex]\left[\frac{16}{225} ][/tex]
W= [tex]\frac{4qq_{o} }{225\pi e_{o}R^{2} } }[/tex]
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On a recent adventure trip, Anita Break went rock-climbing. Anita was able to steadily lift her 80.0-
kg body 20.0 meters in 100 seconds. Determine Anita's power rating during this portion of the
climb.
Anita's power rating during this portion of the climb is 15680 J.
What is the rock-climbing?Rock climbing is an activity in which people climb up, down, or over natural or man-made rock cliffs. The objective is to reach the top of the terminus of a path without falling. It is under the physical Education.
Given that,
mass (m) = 80.0 kg
time = 100 sec
height = 20.0 m
Now, Anita needs to apply a force that is equal to her weight in order to elevate her body a distance of 20.0 m.
Thus, force is equal to:
F = (80 kg) × (9.8 N/kg)
F = 784 N.
So the work she does to lift her body in 20.0 m is:
W = (784 N) ×(20.0 m) × cosine(0°)
W = 15680 J.
So, Anita's power rating during this portion of the climb is 15680 J.
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A full grocery cart requires more force to push than an empty cart what law is it?
Answer:
The law of conservation of matter.
A full grocery cart requires more force to push than an empty one because the weight of the groceries is pushing down on the cart, and the cart itself is resisting this downward force.
consider the following circuit. after leaving the switch at the position a for a long time, move the switch from a to b. there will be current oscillations.
- What is the maximum current?
- Consider the following statements
A1. The current flow is counterclockwise
A2. The current is zero
A3. The current flow is clockwise
B1. The charge on the left plate of C is positive
B2. The charge on the left plate of C is zero
B3. The charge on the left plate of C is negative
Which pair of choices below best describesthe situation at t =5/8T, where T is the periodof oscillations in LC circuit? Let the timewhen the switch is moved from a to b be att = 0.
After leaving the provided switch at the given position for a longer time, then its moves given switch from a to b. At t = 0, the left part of the plate C has charge q = max and therefore, the current flowing through it is zero.
Oscillation is the repetitive or periodic variation, usually in time, of a few degree approximately a crucial value or extra one-of-a-kind states. Familiar examples for all oscillation encompass a swinging type of pendulum with alternating current. A wave is stated to oscillate, which means to transport to and fro in a regular, repeating way.
This fluctuation may be among extremes for all position, like force or quantity. Different sorts of waves have one-of-a-kind sorts of oscillations.
Longitudinal types of waves: here oscillation is parallel route of the wave.
The maximum charge stored in the capacitor is,
Q = CE ------(1)
i = 0
At t = t/4, the left part of the plate C has charge q = 0 and therefore, the current flowing through it is clockwise.
i = clockwise
At t = t/2, the left part of the plate C has charge q = -9max and therefore, the current flowing through it is zero.
i = 0
At t = 3t/4, the left part of the plate C has charge q = 0 and therefore, the current flowing through it is counter clockwise
i = counter clockwise
At t = 0, the left part of the plate C has charge q = max and therefore, the current flowing through it is zero.
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The equation to find gravitational force is below. The value of
G is given as well. The mass of the Earth is 5.98 x 1024 kg and
the mass of a person sitting on the Earth is 70 kg. The
distance between the center of the Earth and the person is
6.38 x 106 m. Use the equation given to find force. Show ALL
of your WORK in the file you upload.
The gravitational force of the Earth is 686N.
How to calculate gravitational force?Gravitational force is a very long-range, but relatively weak fundamental force of attraction that acts between all particles that have mass; believed to be mediated by gravitons.
The equation to calculate gravitational force is as follows:
F = Gm₁m₂/r²
Where;
F is the Gravitational force between two objects measured in Newton (N)G is the Universal Gravitational Constant with a value of 6.674 × 10-¹¹ Nm²kg-²m₁ is the mass of one massive body measured in kg.m₂ is the mass of another massive body measured in kgr is the separation between them measured in kilometre (km)F = 6.674 × 10-¹¹ {5.98 × 10²⁴ × 70}/(6.38 × 10⁶)²
F = 6.674 × 10-¹¹ {4.186 × 10²⁶ ÷ 4.07 × 10¹³}
F = 6.674 × 10-¹¹ {1.03 × 10¹³}
F = 6.86 × 10²
F = 686N
Therefore, 686N is the gravitational force.
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A spring launches a 7kg box on the floor with
force of 50 N. what is the
box's
a net
acceleration?
The magnitude of acceleration of the box be 7.14 m/s².
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Mass of the box be: m = 7 kg.
Force applied on it: F = 50 N.
From Newton's second law of motion, we can write:
force = mass × acceleration
⇒ acceleration = force/mass = 50/7 m/s² = 7.14 m/s².
Hence, acceleration of the box be 7.14 m/s².
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an aluminum flagpole is 39.4 m high. by how much does its length increase as the temperature increases by 15
The length of the aluminum flagpole will increase by 0.00881 m as the temperature increases by 15.
The length of an aluminum flagpole may not change with temperature. While thermal expansion can cause materials to change in size when heated or cooled, aluminium, as a metal, is not significantly affected by temperature changes. As such, the length of an aluminium flagpole is unlikely to be significantly affected by changes in temperature.
Calculate the Coefficient of Linear Expansion for Aluminum
The coefficient of Linear Expansion for aluminum is about 0.000023 per degree Celsius
Calculate the change in length
Change in length = (Coefficient of Linear Expansion x Original Length x Change in Temperature)
Change in length = (0.000023 x 39.4 m x 15) = 0.00881 m
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a ? is a two-terminal device that passes current of one polarity and blocks current of the opposite polarity.
A diode is a two terminal device that passes and blocks the current.
What is a diode?A diode is a semiconductor gadget that essentially switches current in a single direction.
However, it substantially inhibits current flow in the opposite direction. It permits an easy flow of current in one direction.
Due to the fact that they convert alternating electricity into pulsing direct current, diodes are sometimes referred to as rectifiers. Type, voltage, and current capability are used to rate diodes.
The anode and cathode determine the polarity of diodes. The majority of diodes only permit current to flow when the anode is subjected to positive voltage.
A diode is forward-biased when it permits current flow. Reverse-biased diodes function as insulators.
The arrow of the diode symbol points away from the direction of electron flow. The symbol was created by engineers, whose current flowed in a positive direction.
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Specialized organelles (Chloroplasts & Mitochondria - Energy in Plant), Cell membrane, Nucleus
Cell membrane - It acts as a barrier for the inner and out environments of the cell and it controls what goes in and what comes out of the cell.
Nucleus - It stores genetic code or the instructions on how the cell should work. It also controls the metabolic reactions inside the cell.
A 9.5 kilogram object is moving at 6.4 m/s on a horizontal, frictionless surface. What is the total work (in Joules) that must be done on the object to increase its speed to 10.7 m/s?
(Express your answer rounded to the nearest 10th)
The total work (in Joules) that must be done on the object to increase its speed to 10.7 m/s is 349J.
What is the total work (in Joules) that must be done on the object to increase its speed to 10.7 m/s?ΔK.E = W
ΔK.E = K.Ef - K.Ei
⇒ ΔK.E = 1/2m(Vf² - Vi²)
⇒ ΔK.E = 1/2×9.5(10.7² - 6.4²)
⇒ ΔK.E = 349J
Hence, the total work is 349J
How can you determine how much work has been done on an object?Work = Force Distance is the formula for calculating work. The joule (J), sometimes known as the Newton meter (N m), is the SI unit for work. When an object is moved across a distance of 1 m by 1 N of force, the work done is equal to 1 joule.
How do you figure out how much labor is done when kinetic energy changes?Between KE and W relationship: An object's change in kinetic energy equals the work performed on it by a net force: W = KEi - KEf. The work-energy theorem is the name given to this relationship.
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Use the data provided to calculate the amount of heat generated for each cylinder height. round your answers to the nearest tenth. 100 m: kj 200 m: kj 1000 m: kj
The amount of heat generated for each cylinder height is found out to be
100 m : 4.9 kJ
200 m : 9.8 kJ
1000 m : 49.1 kJ
In order to calculate this, you just have to calculate the PE of every cylinder and formula for PE is:
PE = g* h* m
where, m is mass
h is height
g is gravity
So, we just have to insert the values into the formula, to obtain results.
For 100m cylinder, PE = g* h* m
PE = 9.8* 100* 5 = 4900 J = 4.9 kJ
For 200m cylinder,
PE = 9.8* 200* 1 = 9800 J = 9.8 kJ
For 1000m cylinder,
PE = 9.8* 1000* 1 = 49100 J = 49.1 kJ
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what is the minimum kinetic energy in electrovolts that an electron must have while traveling inside a slab of
The minimum kinetic energy in electron volts that an electron must have while travelling inside a slab of crown glass is 0.16715 Mev.
Given that, refractive index of glass is 1.52
n = 1.52
We know the formula for refractive index as, n = c / v
where, c is the speed of light
The speed of light in glass is v
v = c / n = (3* 10⁸)/(1.52) = 1.9723 * 10⁸ m/s
We know the formula for kinetic energy as,
KE = mc²/√[1 - (v²/c²)] - mc²
where, m is the mass of electron
KE = 9.1094* 10⁻³¹*(3* 10⁸)²/√[1 - (1.9723 * 10⁸)²/(3* 10⁸)²)] - 9.1094* 10⁻³¹* (3* 10⁸)² = 2.678 * 10⁻¹⁴ = 0.16715 Mev
The question is incomplete. The complete question is, "The Russian physicist P. A. Crenkov discovered that a charged particle traveling in a solid with a speed exceeding the speed of light in that material radiates electromagnetic radiation. (This phenomenon is analogous to the sonic boom produced by an aircraft moving faster than the speed of sound in air. Cerenkov shared the 1958 Nobel Prize for this discovery. What is the minimum kinetic energy (in electronvolts) that an electron must have while traveling inside a slab of crown glass n = 1.52 in order to create Cerenkov radiation?"
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A plane is flying to Minnesota with a velocity of 265.62 km/h, N. The plane encounters a crosswind with a velocity of 56.07 km/h, W. What is the magnitude of the resultant velocity of the plane? (Answer in km/h)
Answer:
First, write the velocities in component f…
Explanation:
As per as calculations
objects such as the great nebula in andromeda were once called extragalactic nebulae. it is now realized that they are actually
Objects such as the Great Nebula in Andromeda were once called extragalactic nebulae. It is now realized that they are actually.
What is extragalactic system?Extragalactic systems are systems containing objects that lie outside the Milky Way. The branch of astronomy that deals with this massive region of space is called Extragalactic Astronomy. In other words, it is the polar opposite of Galactic Astronomy.
Are there extragalactic planets?Astronomers believe they've spotted the first extragalactic exoplanet beyond our own galaxy. Residing some 28 million light-years away near the heart of the Whirlpool Galaxy (M51), the binary system M51-ULS-1 consists of either a neutron star or a black hole that's tangoing with a more standard companion star.
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An Amazon delivery driver, Shaggy, pushes a loaded dolly with a total mass of 30 kilograms onto a truck. Initially, the dolly accelerates at 0.2 meter/second^2. What force did Fred apply to the dolly?
The force applied to the dolly was 6N.
What is acceleration?Acceleration is the rate of change in velocity. It involves a change in speed and direction. When acceleration involves a change in speed only: Positive acceleration it occurs when an object speeds up. Negative acceleration it occurs when an object slows down.
Acceleration is a change of velocity over a period of time, expressed by the equation below.
F = ma
where f = force applied
m = mass of the body
a = acceleration of the body
F = ma
F = 30 x 0.2
F = 6N
In conclusion, the dolly received a force of 6N from Fred.
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A cyclist who starts from rest will cycle with uniform acceleration. He moves 8m in 4th second. How far does he move in 5 seconds?
Answer: 200m in 5seconds.
Explanation: To find the distance traveled by the cyclist in 5 seconds, we need to use the equation for distance traveled with uniform acceleration:
d = d0 + v0t + 1/2a*t^2
where d is the distance traveled, d0 is the initial displacement (in this case, 0 since the cyclist starts from rest), v0 is the initial velocity (also 0 in this case), t is the time elapsed, and a is the acceleration.
We are given that the cyclist moves 8m in 4 seconds, so we can plug these values into the equation:
8m = 0 + 04s + 1/2a*4s^2
8m = 1/2a16s^2
a = 8m / (1/2 * 16s^2)
a = 16m/s^2
Now that we have the acceleration, we can use the equation to find the distance traveled in 5 seconds:
d = 0 + 05s + 1/216m/s^2*5s^2
d = 1/216m/s^225s^2
d = 200m
Therefore, the cyclist will move a distance of 200m in 5 seconds.