Answer:
628 J
Explanation:
ME = PE + KE
PE = mgh = 0, because h = 0
KEi (initial KE) = 1/2mv² = 1/2(62.3 kg)(4.49 m/s)² = 628 J
KEf (final KE) = 0, because v-final = 0
All the initial ME, which is all KE, converts to thermal E due to friction
Three point charges are arranged at the corners of a square of side L as shown in Fig. What is the potential at the fourth corner (point A), taking V=0 at a great distance?
Thus the electric field at the fourth corner of the square of side L is E4 = kQ.[2/a² + 1/a√2].
What is Electric field strength?Electric field strength is a quantitative expression of the intensity of an electric field in an electric circuit at a particular location and time. The standard unit of the electric field strength is the volt per meter (V/m or V·m⁻¹). An electric field strength of 1 V/m represents a potential difference of about 1V between the two points which are separated by 1 meter distance.
We are given that:
Number of point charges = 3
Here, we shall use the superposition principle to calculate the net electric field at the fourth point, so
E4 = E1 + E2 + E3
E4 = kQ/a² + kQ/√(2a²) + kQ/a²
E4 = kQ [1/a² + 1/√(2a²) + 1/a²]
E4 = kQ [2/a² + 1/a√2]Thus the electric field at the fourth corner is E4 = kQ [2/a² + 1/a√2].
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The sum of the x components of vectors A and B in (Figure 1 ) is
-5
4
14
6
Vectors A and B are shown in a tip to tail arrangement. Vector A begins at the origin (0,0) and ends at the x y coordinate (9,3). Vector B begins at the tip of vector A and ends at the x y coordinate (4,6).
The resultant (x,y) coordinate of vector B is (- 5, 3) and that of A is (9,3). Then, the sum of x components of vector A and B is 4.
What are vectors ?Vectors are physical quantities having both magnitude and direction. For example force, velocity, displacement etc .are vector quantities. Coordinates are used to describe the position of these vectors.
The coordinates of tail of the vector A is (0, 0) and the head is (9,3)
Then the coordinate of A is (9 -0, 3-0) = (9,3)
Similarly, the tail coordinate of B is (9,3) and head is (4,6). The coordinates of B vector is (4-9, 6-3) = (-5, 3)
Now the sum of x components of A and B is = - 5 + 9 = 4.
Therefore, option b is correct.
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Find the full load primary and secondary current of a 230/115V, 2kVA transformer.
The full load primary current of a 230/115V, 2kVA transformer can be calculated using the formula:
I_primary = (2kVA * 1000 VA/kVA) / (230V)
I_primary = 8.7V
The full load secondary current of the transformer can be calculated using the formula:
I_secondary = (2kVA * 1000 VA/kVA) / (115V)
I_secondary = 17.4V
Therefore, the full-load primary current of the transformer is approximately 8.7V, and the full-load secondary current is approximately 17.4V. It is important to note that these values are based on the assumption that the transformer is operating at its full load capacity. If the transformer is operating at a lower load, the primary and secondary currents will be correspondingly lower.
What are the magnitude and direction of the current in the 20 Ω resistor in (Figure 1)?
Express your answer with the appropriate units. Enter positive value if the current is clockwise and negative value if the current is counterclockwise.
To solve this we must be knowing each and every concept related to net current. Therefore, the circuit's overall net current is 0.1 A, flowing clockwise.
What is the net current?The term "net current" refers to the total currents after taking current direction into account. If a node sends 1 mA inside and 5 mA out, the total current equals 4 mA out.
The sum of all entering currents must match the sum of all exiting currents, according to KCL. According to Ohm's Law, the current flowing is equivalent to the combined voltage dividing by the entire resistance. In contrast to a series circuit, where the total current is the same across all of the components, the total current inside a parallel connection is really only equal to the particular current in that part of the circuit.
Net current
i = V / Ri
= (9 - 6) / (10 + 20)i
= 0.1 A
in clockwise way
Therefore, the circuit's overall net current is 0.1 A, flowing clockwise.
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Find the location of the CM of a system of three particles arranged such that two of the particles with mass m are separated by distance I along the y-axis. The third mass 2m lies on the x-axis and is separated by a distance I from one of the masses.
Answer:
CM of a system ( 0.5l , 0.25l )
Explanation:
x = (m1.x1 +m2.x2 +m3.x3) / ( m1 + m2 +m3)
x = ( m x 0 + m x 0 + 2m x l ) / ( m+m+2m)
x = 2m x l / 4m
x = 0.5 l
y = (m1 x y1 +m2 x y2 +m3 x y3) / ( m1 + m2 +m3)
y = (m x 0) + m x l + 2m x 0 ) / ( m + m + 2m )
y = m x l / 4m
y = 0.25 l
It is a “new moon” (the Moon is totally dark in the sky). Using the masses of the Earth, Sun, and Moon and the average distances between the Earth-Moon and Earth-Sun, find the net gravitational force on the Earth from the Sun and the Moon combined.
Find also distance when it is full moon
It is a “new moon” (the Moon is totally dark in the sky). The gravitational force between the Earth and the Moon is:
2.9 x 10^20 N3.5 x 10^22 N3.5 x 10^22 NWhat is gravitational force?Generally, The gravitational force between two objects is given by the equation:
force = G * (mass1 * mass2) / distance^2
Where G is the gravitational constant (6.67 x 10^-11 N*(m/kg)^2), mass1 and mass2 are the masses of the two objects, and distance is the distance between the two objects.
The mass of the Earth is 5.972 x 10^24 kg, the mass of the Moon is 7.347 x 10^22 kg, and the mass of the Sun is 1.989 x 10^30 kg. The average distance between the Earth and the Moon is 384,400 km, and the average distance between the Earth and the Sun is 149.6 million km.
The gravitational force between the Earth and the Moon is:
force = (G * (mass of Earth) * (mass of Moon)) / (distance between Earth and Moon)^2 force
= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (7.347 x 10^22 kg) / (384400 x 10^3 m)^2 force
= 2.9 x 10^20 N
The gravitational force between the Earth and the Sun is:
force = (G * (mass of Earth) * (mass of Sun)) / (distance between Earth and Sun)^2 force
= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (1.989 x 10^30 kg) / (149.6 x 10^9 m)^2 force
= 3.5 x 10^22 N
To find the net gravitational force on the Earth from the Sun and Moon combined, we add the two forces we found above.
Net force = 2.9 x 10^20 N + 3.5 x 10^22 N
= 3.5 x 10^22 N
When it is a Full Moon the distance is the same 384,400 km
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Part A
What is the radius of the hydrogen-atom Bohr orbit shown in the figure? (Figure 1)
r = ____ nm
The radius of the hydrogen-atom Bohr orbit shown in the figure is 5.3 nm.
What is Bohr orbit?The path that hypothetical electrons take around the nucleus is known as Bohr's orbit.
These orbits are described by Bohr in his hypothesis of the structure of an atom as energy levels or shells where electrons move in a fixed circle around the nucleus.
These orbits resemble solar system orbits, with the exception that they are attracted by electrical forces rather than gravity. The term "ground state" refers to the amount of energy that an electron typically occupies.
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Which of the following best illustrates an application of the principles of behaviorism?
A therapist is helping a client explore feelings about past events.
O A parent is using "time out" as a consequence for bad behavior.
O A friend is listening intently and showing concern for another.
O A mechanic is developing a mental map of the engines she routinely fixes.
The statement that best illustrates the application of the principles of behaviorism is -
"A parent is using "time out" as a consequence for bad behavior".
What is behaviorism?The theory that human and animal behaviour can be explained in terms of conditioning, without appeal to thoughts or feelings, and that some mental conditions are best treated by altering behaviour patterns.
Given are the applications of the principles of behaviorism.
The statement that best illustrates the application of the principles of behaviorism is -
"A parent is using "time out" as a consequence for bad behavior".
Therefore, the statement that best illustrates the application of the principles of behaviorism is -
"A parent is using "time out" as a consequence for bad behavior".
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Across a resistor, voltage
a. drops
b. builds
c. speeds up
Answer:
drops
Explanation:
Ohm's Law states that V=I*R, where V is voltage, I is current and R is resistance. In a series circuit, the voltage drop across each resistor will be directly proportional to the size of the resistor. In a parallel circuit, the voltage drop across each resistor will be the same as the power source
1- A ball, M = 4 kg is released from rest (vi =0) at a height, h = 2 m above the ground. (a)
What is the kinetic energy of the ball just before it hits the ground? What is the change in the
potential energy, ΔU during this motion? (b) Find the kinetic energy of the ball at a height, y
= 1.2 m above the ground. (Take g = 10 m/s2
).
(a) The kinetic energy of the ball just before it hits the ground is 78.4 J.
(b) The kinetic energy of the ball at a height of 1.2 m is 31.36 J.
What is the kinetic energy of the ball?The kinetic energy of the ball just before it hits the ground is calculated as follows;
K.E ( bottom) = P.E (top)
P.E (top) = mgh
where;
m is the mass of the objecth is the height of the objectg is acceleration due to gravityP.E (top) = 4 x 9.8 x 2
P.E (top) = 78.4 J
The change in the potential energy of the ball during its motion is calculated as follows;
ΔU = P.Ef - P.E i
where;
P.Ef is the final potential energy at ground levelP.Ei is the initial potential energy at maximum heightΔU = 0 J - 78.4 J
ΔU = -78.4 J
The kinetic energy of the ball at a height of 1.2 m is the change in the potential energy of the ball and it is calculated as follows;
K.E = -ΔU
K.E = -mg (hf - hi)
K.E = (4 x 9.8)(2m - 1.2 m)
K.E = 31.36 J
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Mention four factors on which the amount of precipitation intercepted by vegetal cover depend on
Precipitation amount, storm frequency, and severity, storm duration, kind of precipitation, wind during storm, and wind during evaporation are the main precipitation and storm elements that influence interruption loss (Kenneth, 1996).
What does it signify when vegetation blocks precipitation?All procedures that stop rainfall from instantly reaching the soil are referred to as interceptions. The two main ways that vegetation intercepts water are by catching it on leaf surfaces throughout the canopy and by depositing litter on the ground.
Intercepted precipitation: What is it?Precipitation that is intercepted by leaves, plant branches, and the forest floor prevents it from reaching the soil and instead stays on the surface.
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A 68.2 kg high jumper leaves the ground with a vertical velocity of 8 m/s. How high can he jump? The acceleration of gravity is 9.8 m/s². Answer in units of m.
3. Which of the forms of electromagnetic radiation listed below has the greatest energy?
Ogamma rays
O infrared
O ultraviolet
radio waves
Answer:
Choice A. gamma rays
Explanation:
A snowboarder on a slope starts from rest and reaches a speed of 3.4 m/s after 7.3 s.
The acceleration of the snowboarder is 0.466 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the acceleration of the snowboarder, we use the formula below.
Formula:
a = (v-u)/t........................ Equation 1Where:
a = Accelerationv = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 3.4 m/su = 0 m/st = 7.3 sSusbtitute these values into equation 1
a = (3.4-0)/7.3a = 0.466 m/s²Hence, the acceleration is 0.466 m/s².
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I would like to ask for help in understanding on what basis the universe is considered to be expanding? As far as I understand, it is only an idea (hypothesis, theory) and not a scientific fact as the media presents it. Given that we on Earth receive evidence of various radiations from the past, we cannot say with certainty that the Universe is still expanding. Let's say the Universe stopped expanding 4 billion years ago and started contracting, would the results of all our observations be the same as they are or not?
Expansion of universe is not a hypothetical one but the universe is expanding in the sense increase distance over the space and dark matter.
What is universal expansion?The increase in distance over time between any two particular gravitationally unbound regions of the observable universe is known as the universe's expansion.
As a result, the size of space itself expands intrinsically. It is not necessary for space to exist outside of the cosmos or for it to extend into anything.
The metric changes in scale rather than space or the things in space moving in the conventional sense. Objects move farther apart from one another at ever-increasing speeds as the spatial component of the universe's spacetime metric scales up.
Any viewer in the cosmos would see that all of space appears to be expanding, except for the galaxies receding with a speed proportional to the distance from the observer.
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A solenoid is connected to a battery as shown in the figure, and a bar magnet is placed nearby. What is the direction of the magnetic force that this solenoid exerts on the bar magnet? (Hint: Think of the solenoid as a bar magnet, and identify what would be its north and south poles.)
According to the right-hand rule, the magnetic field of the solenoid will be directed towards the left direction.
What is Right-hand rule?Right Hand Thumb Rule is the rule which is used If a current carrying conductor is imagined to be held in the right hand direction such that the thumb always points along the direction of the current flow, then the direction of the wrapped fingers in the hand will give the direction of the magnetic field lines of the bar magnet.
By the application of the right-hand rule, the magnetic field of the solenoid will be directed towards the left hand direction.
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If a vehicle goes from 15.0 km/h to 28.0 km/h in 4.60 seconds, how far will it have traveled?
Answer:
To find the distance the vehicle traveled, you will need to find the average speed of the vehicle over the 4.60 seconds and multiply that by the time traveled.
The average speed of the vehicle can be found by adding the initial speed and the final speed, and then dividing by 2: (15.0 + 28.0) / 2 = 21.5 km/h.
The distance traveled can be found by multiplying the average speed by the time traveled: 21.5 km/h * 4.60 s = 98.7 km.
So, the vehicle will have traveled 98.7 km.
Explanation:
As a warehouse worker pushes a crate across a concrete floor, the force he
applies is not perfectly horizontal, as shown in the image below. If the
coefficient of kinetic friction between the crate and concrete floor is 0.5, what
is the net force on the crate?
Pushing Force
350 N
Weight
460 N
OA. 95 N
OB. 115 N
O C. 130 N
OD. 145 N
10⁰
-Friction Force
2
The crate will be under a net force of 95 N. Resolving the force in the x-direction yields the net force on the crate: F = 300 cos 10° - N F= 295.44-196.45, F= 95.
How do you calculate the frictional force?The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it.
What are the friction laws?The friction of a moving item is inversely proportional to the normal force and runs perpendicular to it. The type of surface the thing comes into touch with determines the amount of friction it experiences. As long as there is a point of contact, friction does not depend on the area of contact.
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Calculate the potential energy of a rock of mass 500 g, held at a height of 2 m above ground.
The potential energy of a rock of mass 500 g, held at a height of 2 m above ground is 9.8J.
The formula for the gravitational potential energy of an object is:
PE = mgh
where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2 on the Earth's surface), and h is the height of the object above the reference point.
So, in this case, we can plug in the given values to find the potential energy of the rock:
PE = (500 g) x (9.8 m/s^2) x (2 m)
The weight of the rock is m*g = 500 g * 9.8 m/s^2 = 4.9 N
Therefore,
PE = 4.9 N x 2 m = 9.8 J
Therefore, the potential energy of a rock of mass 500 g, held at a height of 2 m above ground is 9.8J.
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what change do you need to make when comparing objects going upward against gravity versus downward with gravity?
A. Different amount of time in motion
B. Different length of displacement
C. Different sign + or - on the acceleration
D. Different changes to velocity
If an object is working against gravity, that means gravity must have the opposite sign of the object (this is why we see objects slow down at their peak height and return to us if we throw them in the air!). If the object is working with gravity, though, they must both be moving in the same direction, therefore gravitational acceleration would be the same sign as the velocity (positive or negative depending on how you define your axes).
Therefore, your answer should be C. Different sign + or - on the acceleration.
I hope this helps!
Heat Transfer 12 Directions: Drag the arrows to the correct locations on the image. directions in which heat flows. The diagram below shows three solid objects. Two of the objects are hot and one is cold. If heat is transferred between these objects via conduction, use the arrows to indicate the direction.
That's the question and please someone help me I can't figure this out because of how much I've been absent throughout this lesson
If heat is transferred between these objects via conduction, both arrows will point towards the cold.
Heat energy is transferred through the mechanism of conduction when nearby atoms or molecules collide. In solids and liquids, where particles are more closely spaced, conduction happens more easily than in gases, where particles are more widely spaced. Heat transfers through solid materials via conduction. The roof, walls, and windows of your house all carry heat on hot days.
The act of heating a skillet on a stovetop is a typical illustration of conduction. The surface of the pan receives heat directly from the burner. The amount of kinetic energy that the particles in a sample of matter have converted to heat is measured by temperature. Conduction mostly comes in two flavors. Steady-state conduction is what they are. temporary conduction.
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Most space lawyers agree that the barrier between airspace and outer space lies somewhere between where
the highest planes fly and the lowest satellites orbit.
True
False
True. The majority of space lawyers concur that the line dividing airspace from outer space is located halfway between the altitude at which airplanes fly and the orbital altitude of satellites.
What purposes do satellites serve?They serve a variety of functions, including that of the Satellite Navigation System, amateur radio, television transmission, and weather forecasting. In order to conduct study and acquire data, they also employ telescopes to view outward somewhere at solar system.
Do satellites provide internet access?Over 99% of Americans have access to satellite internet, along with most other (but certainly not all) rural residents. You do not need to have a home internet connection because the broadband signal is transmitted from satellites.
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You are in the year where the earth has no more land available for houses you decide to build an apartment up and need things to survive in each earths 5 layers (troposphere,stratosphere, mesosphere, thermosphere, exosphere) Question: what things would you need to survive the mesosphere
PLS I RLLY NEED SOME HELP
The things that I will need to survive the layer of the earth called the mesosphere would be thick clothings.
What are the 5 layers of the earth?The five(5) layers of the earth include the following such as:
troposphere,stratosphere, mesosphere, thermosphere, and exosphere.The Mesosphere is one of the layers of the earth that is found directly above the stratosphere and then below the thermosphere.
The characteristics of the mesosphere is that the temperature rises due to reduced absorption of solar radiation and increased cooling by CO2 radiative emissions.
Therefore, for an individual to survive and live effectively at the Mesosphere layer of the earth, such needs thick clothings.
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if a player kicks a football from ground level with a velocity of 27/ms at an angle of 30 degrees above the horizontal then what is the initial horizantal velocity of the football?
The initial horizontal velocity of the football if a player kicks a football from ground level with a velocity of 27/ms at an angle of 30 degrees above the horizontal is 23.662 m/s.
To find the initial horizontal velocity (Vx) of the football, you can use the horizontal component of the velocity vector. The horizontal component of velocity is found by multiplying the velocity by the cosine of the angle of launch.
[tex]V_{x}[/tex] = V × cos(angle)
where V is the initial velocity, the angle is the angle of launch (in this case, 30 degrees), and cos is the cosine function.
So, in this case, the initial horizontal velocity of the football would be:
[tex]V_{x}[/tex] = 27 m/s × cos(30)
[tex]V_{x}[/tex] = 27 m/s × 0.866
[tex]V_{x}[/tex] = 23.662 m/s
So the initial horizontal velocity of the football, which moves in the x-direction, is approximately 23.662 m/s.
This means the football will move 23.662 m/s in x direction initially and if no air resistance acts upon the football, it will move at the same velocity in x direction throughout the motion.
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19. A pitcher throws a baseball toward a batter at 30m/s. The batter swings his
bat and hits the baseball. The baseball flies away in the opposite direction at a
speed of 35m/s. Is there a transfer of energy in this situation? (SC.7.P.11.4)
a) Yes, because both the bat and the ball are moving after the collision.
b) No, because the ball and the bat only touched for a short time.
c) Yes, because the force from the bat changes the motion of the ball
A pitcher throws a baseball towards a batter at 30m/s. The batter swings his bat and hits the baseball, then there is a transfer of energy in this situation : c) Yes, because the force from the bat changes the motion of the ball.
How is energy transferred from baseball bat to a baseball?Although baseball may appear hard and solid, it actually behaves much like a rubber ball. In the fraction of a second that ball collides with the swinging bat, ball compresses as the energy of motion goes into deforming the ball and transforms it into an elastic potential energy.
The collision of baseball with bat is elastic and the collision between baseball and glove is nearly inelastic.
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A 3.00kg mass is attached to an ideal spring with k=200N\m if the velocity of body at 0.25m Is 2.3m\s find the amplitude and maximum velocity
To solve this we must be knowing each and every concept related to velocity. Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.
What is velocity?V is the velocity measurement of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.
For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below.
v = √(k / m) ×A
v = velocity of the mass
k= spring constant
m =mass of the object
A= amplitude of the oscillation.
substituting all the given values in the above equation, we get
2.3 m/s = √(200 N/m / 3.00 kg)×A
A = 2.3 m/s / √(200 N/m / 3.00 kg)
= 0.23 m
v =√(200 N/m / 3.00 kg) ×0.23 m
= 2.75 m/s
Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.
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A 6 kg bowling ball is lifted 1.2 m into a storage rack. The acceleration of gravity is 9.8 m/s². Calculate the increase in the ball's potential energy. Answer in units of J.
Answer:
70.56 J
Explanation:
The increase in potential energy of the ball can be calculated using the formula:
PE = mgh
where:
PE is the increase in potential energy
m is the mass of the ball (6 kg)
g is the acceleration of gravity (9.8 m/s²)
h is the height the ball is lifted (1.2 m)
Substituting in the values, we get:
PE = (6 kg)(9.8 m/s²)(1.2 m)
This simplifies to:
PE = 70.56 J
So the increase in the ball's potential energy is 70.56 J.
A 6 kg bowling ball is lifted 1.2 m into a storage rack. The acceleration of gravity is 9.8 m/s² Calculate the increase in the ball's potential energy. Answer in units of J.
Answer:
70.56 J
Explanation:
Gravitational Potential Energy= mass×gravitational pull× height
= 6×9.8×1.2= 70.56 J
If a ball is travelling in a circle of diameter 10m with velocity 20m/s, find the angular velocity of the ball.
Answer:
4 rad/s
Explanation:
The angular velocity is velocity over time:
[tex]\displaystyle{\omega = \dfrac{v}{r}}[/tex]
We know that the velocity is 20 m/s and the radius is half of diameter which is 10m/2 = 5 m. Hence, substitute in the formula:
[tex]\displaystyle{\omega = \dfrac{20 \: \text{m/s}}{5 \: \text{m}}}\\\\\displaystyle{\omega = 4 \: \text{rad/s}}[/tex]
Therefore, the angular velocity is 4 rad/s
Hi can anyone please help me with this question? i just cant seem to do it.. Thanksss
Newtons Universal Gravitational Law.
Bill gates a billionaire and space-X CEO, send Robin, 65kg, to planet Gidz. Gidz has a very weak gravitational attraction, of 1.56 N/Kg. Planet GIdz has a radius of 6.35 x 10^11 m.
i. determine the mass of planet Gidz.
Answer:
F = G M m / R^2 = m a
G M / R^2 = a
M = a R^2 / G
M = 1.56 N/kg * 6.35 m^2 / 6.67E10-11 N-m^2 / kg^2
M = 1.56 * 6.35 / 6.67E-11 kg
M = 1.49 * 10^11 kg