Answer:
(a) The gauge pressure is 4,885.3 Pa
(b) The anchoring force needed to hold the elbow in place is approximately 296.5 N
The direction of the anchoring force is approximately ≈ 134.8
Explanation:
The given parameters in the fluid dynamics question are;
Pipe elbow angle, θ = 90°
The mass flowrate of the water, [tex]\dot m[/tex] = 40 kg/s
The diameter of the elbow, D = 10 cm
The pressure at the point of discharge of the fluid = Atmospheric pressure
The elevation between the inlet and exit of the elbow, z = 50 cm
The weight of the elbow and the water = Negligible
(a) The velocity of the fluid, v₁ = v₂ = v is given as follows;
ρ·v·A = [tex]\dot m[/tex]
v = [tex]\dot m[/tex]/(ρ·A)
Where;
ρ = The density of the fluid (water) = 997 kg/m³
A = The cross-sectional area of the of the elbow = π·D²/4 = π×0.1²/4 ≈ 0.00785398163
A = 0.00785398163 m²
v = 40 kg/s/(0.00785398163 m² × 997 kg/m³) ≈ 5.1083 m/s
Bernoulli's equation for the flow of fluid is presented as follows;
[tex]\dfrac{P_1}{\rho \cdot g} +\dfrac{v_1}{2 \cdot g} + z_1 = \dfrac{P_2}{\rho \cdot g} +\dfrac{v_2}{2 \cdot g} + z_2[/tex]
v₁ = v₂ for the elbow of uniform cross section
P₁ - P₂ = ρ·g·(z₂ - z₁)
P₁ - P₂ = The gauge pressure = [tex]P_{gauge}[/tex]
z₂ - z₁ = z = 50 cm = 0.5 m
∴ [tex]P_{gauge}[/tex] = 997 kg/m³ × 9.8 m/s² × 0.5 m = 4,885.3 Pa
The gauge pressure, [tex]P_{gauge}[/tex] = 4,885.3 Pa
(b) The forces acting on the elbow are;
[tex]F_{Rx}[/tex] + [tex]P_{gauge}[/tex]·A = -β·[tex]\dot m[/tex]·v
[tex]F_{Ry}[/tex] = β·[tex]\dot m[/tex]·v
∴ [tex]F_{Rx}[/tex] = -β·[tex]\dot m[/tex]·v - [tex]P_{gauge}[/tex]·A
[tex]F_{Rx}[/tex] = -1.03 × 40 kg/s × 5.1083 m/s - 4,885.3 Pa × 0.00785398163 m² ≈ -208.83 N
[tex]F_{Ry}[/tex] = 1.03 × 40 kg/s × 5.1083 m/s = 210.46196 N
The resultant force, [tex]F_R[/tex], is given as follows;
[tex]F_R[/tex] = √([tex]F_{Rx}[/tex]² + [tex]F_{Rz}[/tex]²)
∴ [tex]F_R[/tex] = √((-208.83)² + (210.46196)²) ≈ 296.486433934
Therefore;
The anchoring force needed to hold the elbow in place, [tex]F_R[/tex] ≈ 296.5 N
The direction of the anchoring force, θ
[tex]\theta = tan^{-1}\left( \dfrac{F_{Ry}}{F_{Rx}} \right)[/tex]
∴ θ = arctan(210.46196/(-208.83)) = -45..2230044°
θ = 180° + -45.2230044° = 134.7769956°
∴ The direction of the anchoring force is approximately, θ ≈ 134.8°
Metals allow electrons to flow through and complete the circuit. Therefore they are called?
Answer:
the answer would be conductors
What are sport skills sometimes referred to as?
a skill-related fitness
b. performance skills
c. health-related fitness
d. physical fitness
When melting of a metamorphic rock occurs, it changes into what?
Answer:
The upper limit of metamorphism occurs at the pressure and temperature of wet partial melting of the rock in question. Once melting begins, the process changes to an igneous process rather than a metamorphic process. During metamorphism the protolith undergoes changes in texture of the rock and the mineral make up of the rock.
Explanation:
i hope this helps
When melting of a metamorphic rock occurs, it changes into Magma and igneous rock will emerge as a result of this..
What is metamorphism?Sedimentary, igneous, and metamorphic rocks are the three distinct types of rocks that make up the rock cycle. Rocks such as sedimentary and igneous rocks were not always rocks.
A very particular set of circumstances must exist for a rock to undergo metamorphism. It is necessary to subject the preexisting rock to extreme temperatures, high pressures, or hot, mineral-rich fluids. All three of these conditions are typically true. The Earth's crust is where these conditions are most frequently encountered, either there or at plate borders when tectonic plates meet.
It is essential that the current rock not melt in order to produce metamorphic rock. The rock will melt under excessive heat or pressure and turn into magma. Instead of a metamorphic rock, an igneous rock will emerge as a result of this.
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#SPJ5
what is SI unit of speed
Answer:
m/s
Explanation:
The SI unit of speed is the metre per second, but the most common unit of speed in everyday usage is the kilometre per hour or, in the US and the UK, miles per hour.
m/s
which is also written as
ms-¹
The above mentioned symbols are said as 'meter per second'
hope it helps!
How many lobes are in the lungs
Answer:
There are 5 lobes in the lungs.
Explanation:
The right lung consists of three lobes: the RUL, the RML, and the RLL. While the left lung consists of two lobes: the LUL, and the LLL.
This girl named Emma she my crush what do I say to her.
Answer:
you gotta shoot your shot.
Explanation:
look for the signs. ask her out before someone else does. you got this dawg
Which three parts of the graph’s curve represent the solid, liquid, and gaseous state of water? Explain your reasoning.
B,C,D maybe
Explanation:
plz dont get mad
How much energy (in kWh) can you get from a 72 cell solar panel in one year?
Carbon dioxide can be represented by the chemical formula
es
A)
C₂0
B)
CO2
C)
Ca,
D)
CaOz
pls help fast !!!
Answer:
Your answer is B co2
Explanation:
Answer: CO2
Explanation:
Carbon dioxide is consisted of one carbon molecule and 2 oxygen molecules, therefore CO2
AP Physics Question
An amusement park ride consists of a large vertical wheel of radius that rotates counterclockwise on a horizontal
axis through its center, as shown above. The cars on the wheel move at a constant speed . Points and
represent the position of a car at the highest and lowest point of the ride, respectively. A person of weight sits
upright on a seat in one of the cars. As the seat passes point , the seat exerts a normal force with magnitude
on the person. While passing point , the person releases a small rock of mass , which falls to the ground
without hitting anything.
2. Which of the following best describes the passenger’s linear and angular velocity while passing point ?
A
Linear Velocity Angular Velocity
Constant Changing
B
Linear Velocity Angular Velocity
Constant Constant
C
Linear Velocity Angular Velocity
Changing Changing
D
Linear Velocity Angular Velocity
Changing Constant
The linear velocity is changing and the angular velocity is Constant best describes the passenger’s linear and angular velocity while passing a point.
What is the definition of Angular velocity?The rate of change of angular displacement is defined as angular speed, and it is stated as follows:
ω = θ t
Where,
θ is the angle of rotation,
t is the time
ω is the angular velocity
The linear velocity is given as the product of angular velocity and radius.
v=ωr
In the circular motion, the linear velocity is changing. Because the radius is changing.While the angular velocity is constant.Because it is an independent quantity.
Hence the Linear velocity is changing and the angular velocity is Constant best describing the passenger’s linear and angular velocity while passing a point.
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what is 1 AU equal to in kilometres
Answer:
1 au is 1.496e+8 kilometres
Explanation:
Easy AU to km conversion. A kilometer, or kilometre, is a unit of length equal to 1,000 meters, or about 0.621 miles.
Hope this helps :)
In red shift, the wavelengths of light become?
Answer:
Explanation:god is good because the god is what it stays
god is good because the god is what it staysgod is good because the god is what it staysgod is good because the god is what it stays
How are amplitude, intensity, and
loudness related?
Answer:
Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder. The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less.
Explanation:
What is the wavelength of visible light emitted at 4.2 x 10^8 Answer in units of M
Answer:
0.714 m
Explanation:
From the question,
v = λf......................... Equation 1
Where v = velocity of visible light, f = frequency of visible light, λ = wave length of visible light.
make λ the subject of the equation
λ = v/f.................. Equation 2
Given: f = 4.2×10⁸ Hz
Note: Light is an electromagnetic wave, and all electromagnetic waves travels with the same speed (3×10⁸ m/s)
Constant: v = 3×10⁸ m/s
Substitute these values into equation 2
λ = 3×10⁸/4.2×10⁸
λ = 0.714 m
Question 13 of 20
A copper atom has an atomic number of 29 and an atomic mass of 64. What
is the structure of this atom?
A. It has a central nucleus composed of 29 protons and 29 neutrons,
surrounded by an electron cloud containing 35 electrons.
B. It has a central nucleus composed of 29 protons and 35 neutrons,
surrounded by an electron cloud containing 29 electrons.
O C. It has a central nucleus composed of 35 protons and 29 neutrons,
surrounded by an electron cloud containing 29 electrons.
D. It has a central nucleus composed of 29 protons and 64 neutrons,
surrounded by an electron cloud containing 29 electrons.
SUBMIT
Answer:
B. It has a central nucleus composed of 29 protons and 35 neutrons,
surrounded by an electron cloud containing 29 electrons.
Explanation:
Protons and neutrons are the only subatomic particles with mass, and they are located in the nucleus. If this atom has an atomic number of 29 and is copper, it must have 29 protons (protons define which element is being observed). This means all remaining mass is from neutrons. 64-29 = 35.
Electrons have no mass and orbit the nucleus in the electron cloud. Since this copper atom is neutral (we are not told it has a charge), there must be an equal number of protons and electrons.
Answer:
B. It has a central nucleus composed of 29 protons and 35 neutrons,
surrounded by an electron cloud containing 29 electrons.
Explanation:
Hope this helps
Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them. How far apart are these charges?
Answer:
r = 0.2499 m
Explanation:
Use Coulomb's Law: [tex]F_{e} = kq_{1}q_{2} / r^{2}[/tex] where Fe is the electric force, q1 and q2 are the 2 charges respectively, k is a constant (8.99*10^9 N • m^2 / C^2) and r is the distance.
[tex]3.6 N = (8.99*10^{9})(5*10^{-6})(5*10^{-6}) / r^{2}[/tex]
r = 0.2499 m
The distance that should be apart from these charges should be considered when the r = 0.2499 m.
Calculation of the distance apart:Since
Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them
So
here we use Columb law
Electric force = k * two charges * two charges)r^2
3.6 N = (8.99*10^9) * ( 5 * 10^-6) * (5*10^-6)r^2
r = 0.2499 m.
Hence, The distance that should be apart from these charges should be considered when the r = 0.2499 m.
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A force of 40 N stretches a spring 0.20 m what is the spring
constant?
a. 2000 N/m
b. 200 N/m
c. 20 N/m
d. 2 N/m
AP Physics Question 3
A planet has two moons, Moon and Moon , that orbit at different distances from the planet’s center, as shown.
Astronomers collect data regarding the planet, the two moons, and their obits. The astronomers are able to estimate
the planet’s radius and mass.
3. The masses of the two moons are determined to be for Moon and for Moon . It is observed that
the distance between Moon and the planet is two times that of the distance between Moon and the
planet. How does force exerted from the planet on Moon compare to the force exerted from the planet on
Moon ?
The gravitational force exerted from the planet on Moon is two times larger than the gravitational force
exerted from the planet on Moon .
B
The gravitational force exerted from the planet on Moon is eight times larger than the gravitational force
exerted from the planet on Moon .
C
The gravitational force exerted from the planet on Moon is two times smaller than the gravitational force
exerted from the planet on Moon .
D
The gravitational force exerted from the planet on Moon is eight times smaller than the gravitational force
exerted from the planet on Moon .
Gravitational force increases as the mass increases and decreases as the distance between the bodies is increased.
The correct option is; The gravitational force exerted from the planet on Moon A is eight times larger than the gravitational force exerted from the planet on Moon B.Reasons:
The given parameters are;
The moons of the planet = Moon A and Moon B
Mass of Moon A = 2·M
Mass of moon B = M
The distance between Moon B and the planet = 2 × The distance between Moon A and the planet
Required:
Comparison (compare) of the force exerted from the planet on Moon A and Moon B.
Solution:
The force, F, exerted from the planet is the gravitational force which is given by Newton's Law of Gravitation as follows;
[tex]\displaystyle F = \mathbf{G \cdot \frac{M_{planet} \times M}{R^2}}[/tex]Where;
G = Universal gravitational constant
[tex]M_{planet}[/tex] = Mass of the planet
M = Mass of the Moon
R = The distance from the planet to the Moon
For Moon A, we have;
Mass = 2·M
Distance = R
Which gives;
[tex]\displaystyle F_A = G \cdot \frac{M_{planet} \times 2\cdot M}{R^2} = 2\cdotG \cdot \frac{M_{planet} \times M}{R^2} = \mathbf{2 \cdot F}[/tex]
With Moon B, we have;
Mass = M
Distance = 2·R
Therefore;
[tex]\displaystyle F_B = G \cdot \frac{M_{planet} \times M}{(2 \cdot R)^2} = G \cdot \frac{M_{planet} \times M}{4 \cdot R^2} = \frac{1}{4} \cdot G \cdot \frac{M_{planet} \times M}{R^2} = \mathbf{\frac{1}{4} \cdot F}[/tex]
Which gives;
[tex]\displaystyle \frac{F_A}{F_B} = \frac{2 \cdot F}{\frac{1}{4} \cdot F } =2 \times \frac{4}{1} = \mathbf{8}[/tex]
[tex]\displaystyle \frac{F_A}{F_B} = 8[/tex]
[tex]F_A = \mathbf{8 \times F_B}[/tex]
The force from the planet on Moon A, [tex]F_A[/tex], is 8 times the force from the planet on Moon B.
Therefore, whereby option B is;
The gravitational force exerted from the planet on Moon A is eight times larger than the gravitational force exerted from the planet on Moon B.The correct option is option B
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A 230 kg motorcycle zooms away from a red light with a force of
13,800 Newtons. What is the acceleration of the motorcycle in m/s??
Answer:343
Explanation:
An oscillator is made with a rubber band and a block of wood
as shown in the diagram. What happens to the oscillator if we
make the block of wood heavier?
Answer:
Explanation:
a. The frequency increases.
b. The period increases.
c. The frequency stays the same.
d. The period stays the same
Please hurry
Starting from rest, this airliner accelerates at 2.4m/s2 for 32 seconds before leaving the ground. Calculate its velocity at liftoff.
Answer:
The velocity will be "76.8 m/s".
Explanation:
The given values are:
Acceleration,
a = 2.4 m/s²
Time,
t = 32 seconds
By equation of motion,
⇒ [tex]v=u+at[/tex]
On substituting the values, we get
⇒ [tex]=0+2.4\times 32[/tex]
⇒ [tex]=0+76.8[/tex]
⇒ [tex]=76.8 \ m/s[/tex]
Suppose a small black hole with mass equal to 7.35 × 10^30 kg drifted past Earth at the same distance as the Moon. The mass of the Moon is about 7.35 × 10^22 kg. What might be expected? (Please do not answer if you do not know, this is for a project worth 30% of my grade)
Answer:
wt f i dont care
Explanation:
Rank the ten objects from loudest to softest.
please help me
A football player kicks a football and exerts a force on the football of 0.4 kg (m/s²). The football’s acceleration is 0.92 m/s². What is the mass of the football?
Answer:
0.368 Newtons
Explanation:
Answer:
i think it's 0.88
Explanation:
A car slams into a wall with a force of 5000 N. What is the force of the wall on the car? 5000 N -5000 N 49000 N 510 N It cannot be determined with the information provided.
Answer:
-5000 N
Explanation:
Newtons third law of motion states that action and reaction are equal and opposite. This means that to every action, there is an equal opposite reaction.
Hence when a body A exerts a force FA on another body B, the body B also exerts a force FB on A which is equal in magnitude to FA but opposite in direction. FB is the reaction force due to FA.
Hence, when a car hits a wall with a force of 5000N, the reaction of the wall on the car is -5000N
What is the nergy of a wave that has a
frequency of 6.32 x 10^20 Hz?
here you go thank bob not me he will be very thankful
If a 7 kg bowling ball is lifted 2 m into the air and dropped, what speed will it strike the ground? (
Answer:
6.32m/s
Explanation:
note:Now these calculations are based in the fact that acc. due to gravity is 10m/s²
okay so I'm thinking you think the speed of a body depends on the mass of the body also,umh... well it doesn't at all!
when two bodies of different masses fall from the same height,they fall at the same time( this is just to say)
now enough of the talking let solve....
so the ball was dropped .ie from rest to the ground through a distance of 2m,
the formula for calculating the distance if a body moving in a straight line is given by:
S=ut + ½at² where u is initial velocity, a is acceleration ( of the body or due to gravity, but since its falling freely under the influence of gravity its " we use the acceleration due to gravity ,which is 10m/s²) and t is the time taken to cover the distance.
from our question the ball was dropped from rest thus its u is 0 therefore we use this equation to find the time it took to touch ground (S=½at²)
solving ....
we get t to be 0.632s
to find the speed we substitute t in the equation below:
V=u+at ,but since u=0
V=at =10•0.632=6.32m/s
therefore the speed the body uses to strike the ground is 6.32m/s
number of atoms of each element Sulfur dioxide?
Answer:
Element Symbol # of Atoms
Oxygen O 2
Sulfur S 1
Explanation:
If a net force acting on a moving object causes its speed to increase, what
happens to the object's momentum?
A. It stays the same.
B. It increases.
C. It changed directions.
D. It decreases.
Answer:
It increases.
Explanation:
If a force acts in the same direction as the object's motion, then the force speeds the object up. Either way, a force will change the velocity of an object. And if the velocity of the object is changed, then the momentum of the object is changed.
please help me
A football, that has a mass of 0.43 kg, is kicked across a field at an acceleration of 0.92 m/s². What is the force used on the football?
Answer:
0.3956
Explanation:
Newton's 2nd law of motion says that Force = Mass*Acceleration (f=ma) so to find the force used on the football you multiply it's mass by its acceleration.
0.43*0.92 = 0.3956.
0.4 if you round