A, B, C and D are four towns. B is 30 kilometres due east of A. C is due 30 kilometres north of A. D is due 45 kilometres due south of B. Calculate the bearing of D from B

ONLY ANSWER QUESTION B PLEASE
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A, B, C And D Are Four Towns. B Is 30 Kilometres Due East Of A. C Is Due 30 Kilometres North Of A. D

Answers

Answer 1

Answer:

213.7°

Step-by-step explanation:

The bearing of B from D is angle ADB,  Thus, ∠ADB = arctan(30/45) ≈ 33.7°

The bearing of D from B is that angle plus 180°, Thus, 180° +33.7° = 213.7°

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Part A: 135

Part B: 213.7  

------------------------------------------------------------------------------------------------------------

[RevyBreeze]

Answer 2

MATE!

213.7°

The bearing of B from D is angle ADB,  Thus, ∠ADB = arctan(30/45) ≈ 33.7°

The bearing of D from B is that angle plus 180°, Thus, 180° +33.7° = 213.7°

Part A: 135

Part B: 213.7  


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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

[tex]\\ \sf\longmapsto \sqrt{X^{a-b}}\times \sqrt{X^{b-c}}\times \sqrt{X^{c-a}}[/tex]

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[tex]\\ \sf\longmapsto X^{\frac{a-b+b-c+c-a}{2}}[/tex]

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Step-by-step explanation:

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See attachment for the scatter plot

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https://brainly.com/question/7656407

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Step-by-step explanation:

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