A baby fish was 1.5 centimeters in length when it first hatched . The fish grew at a rate of 0.25 centimeter per week.
Which graph best shows this relationship between the length of the fish in centimeters , y, and the time in weeks, x?
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Answer:

[tex]9 (\frac{2}{3})^{n-1}[/tex]

Hope this helps!

Answer:

11

Step-by-step explanation:

when y = 4

x = 3(4) -1

x= 12-1 = 11

Step-by-step explanation:

If the question is how much sugar contains pie, then do it like this:

6:3=2

So in one container you have 2 pounds of sugar. And if you use 1 container for a pie you will use : 2 pounds of sugar for pie.

If question is how much sugar does he have after that, it would be:

6-2=4 pounds of sugar or

3-1= 2 containers of sugar

9514 1404 393

Answer:

  A)  B = 37.2°, b = 309.1, c = 382.3

Step-by-step explanation:

You know the third angle must be ...

  B = 180° -131.6° -11.2°

  B = 37.2° . . . . . . eliminates choice D

You know the two missing sides are both longer than 99.3, eliminating choice C.

Since angle C is the largest angle, side c is the longest side, eliminating choice B.

By the process of elimination, we know the correct choice is A.

__

The Law of Sines will tell you the length of side C is related to the other triangle values by ...

  c/sin(C) = a/sin(A)

  c = (99.3 ft)×sin(131.6°)/sin(11.2°)

  c ≈ 382.3 ft . . . . matches choice A

Answer:

Step-by-step explanation:

Let A ≤ B ≤ C

largest angle is 16 less than 4 times the smallest angle

C = 4A-16

middle angle is 7 more than half the measure of the largest angle

B = C/2 + 7

A+B+C = 180°

A = 28 ⅐°

B = 55 2/7°

C = 96 4/7°

Step-by-step explanation:

most likley

Answer:

t(s) is in the acceptance region. We accept H₀ we don´t have enough evidence to justify differences in the procedures

Step-by-step explanation:

Traditional procedure bring as μ  =  8,6 h

Sample Information:

Sample size   n  = 26

Sample mean  x  =  8,4

Sample standard deviation   s  = 1

With  n  = 26  unknown population standard deviation, and population with normal distribution we should use t-student test

then  n = 26      degree of freedom  df  =  n - 1    df  =  25

significance level 0,1  with that information we look in t-student table t (c) ( two tails test)

t(c) = - 1,708

Test Hypothesis

Null hypothesis                  H₀                 x =  μ

Alternative Hypothesis     Hₐ                 x ≠  μ

Alternative hypothesis indicates that the test should considered two tails

To calculate  t(s)

t(s)  =  (  x  -   μ ) / s/√n

t(s)  = ( 8,4  -  8,6 )/ 1/√26

t(s)  = - 0,2 *  5,09 / 1

t(s) =  - 1,019

Comparing |t(s)| and |t(c)|

1,019 < 1,708     |t(s)| <  |t(c)|

t(s) is in the acceptance region. We accept H₀ we don´t have enough evidence to justify differences in the procedures

Answer:

A(-5, -2), B(-3, 3), C(3, 5), D(1, 0) is the answer.

Step-by-step explanation:

Answer:

common endpoint

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Answer:

0.0571 = 5.71% probability that this fund-raising event is a success

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The organizers would call this event a success if the total contributions exceed $4,600

Forty families, so sample mean above 4600/40 = 115.

Mean and a standard deviation of $105 and $40

This means that [tex]\mu = 105, \sigma = 40[/tex]

Sample of 40

This means that [tex]n = 40, s = \frac{40}{\sqrt{40}} = 6.3246[/tex]

What is the probability that this fund-raising event is a success?

Sample mean above 115, which is 1 subtracted by the pvalue of Z when X = 115. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{115 - 105}{6.3246}[/tex]

[tex]Z = 1.58[/tex]

[tex]Z = 1.58[/tex] has a pvalue of 0.9429

1 - 0.9429 = 0.0571

0.0571 = 5.71% probability that this fund-raising event is a success

Answer:

r=7

Step-by-step explanation:

74000=28000(1+r/12)^12(14)

divide 74000 by 28000, and cancel out 28000.

1.00580=1+r/12

(100) .06962=r

r = 6.96198

the 6 after the 9 rounds 9 to 0, which rounds the 6 to 7

r=7

Answer:

abajwuvdtrbxt really disjdshkrgegvzgfj

9514 1404 393

Answer:

  g(n) = 2n +49

Step-by-step explanation:

The recursive formula tells you this is an arithmetic sequence with first term 51 and common difference 2. The explicit formula for such a sequence is ...

  an = a1 +d(n -1) . . . . first term a1, common difference d

Using the sequence values, we have ...

  g(n) = 51 +2(n -1)

  g(n) = 2n +49 . . . . . simplified

Answer:

Cannot see the other picture as you just sent one

And the tables will help you and so will this.

Step-by-step explanation:

Look at the value for question of getting an answer right and you have to do a table that looks like this attached  

4 games at 2/3 chance for each = 16/27

We look at 1/3 x 1/3 = 11/ 20

we look at 2/3 x 2/3 = 0.444 = 22/50 = 11/25

The other two games are

1/3 x 2/3 = 0.22 + 0.22 = 0.44

0.44  =  11/25

+ 3/20

= 16/27

It wont be as complicated as that. But im sure this will help.

Answer:

The necessary sample size is of 5683.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].

Past surveys reveal the 30% of tourists going to Las Vegas to gamble spend more than $1,000.

This means that [tex]\pi = 0.3[/tex]

The estimate is to be within 1% of the population proportion. What is the necessary sample size?

A sample size of n is necessary. n is found when [tex]M = 0.01[/tex]. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.01 = 1.645\sqrt{\frac{0.3*0.7}{n}}[/tex]

[tex]0.01\sqrt{n} = 1.645\sqrt{0.3*0.7}[/tex]

[tex]\sqrt{n} = \frac{1.645\sqrt{0.3*0.7}}{0.01}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.645\sqrt{0.3*0.7}}{0.01})^2[/tex]

[tex]n = 5682.6[/tex]

Rounding up:

The necessary sample size is of 5683.

Answer:

3/8

Step-by-step explanation:

........ur welcome.........

6/8 - 3/8

Answer:

3/8

Step-by-step explanation:

6/8-3/8 =38 your welcome guys;)

Answer:

4

Step-by-step explanation:

That sucks hope you find them.

Answer: 14.22 ounces each

Step-by-step explanation:

128 ounces in a gallon divided by 3 divided by 3 again

Answer:

Step-by-step explanation:

8

Answer:

$126

Step-by-step explanation:

10-8=2(hours overtime)

1 1/4 × 12 = $15 per hour

2×15=$30

8×12=$96

$96+$30= $126