A bat at rest sends out ultrasonic sound waves at 46.2 kHz and receives them returned from an object moving directly away from it at 21.8 m/s, what is the received sound frequency?
f= ? Hz

Answer:

As the mass of an object increases, the force of gravity increases as well.

Explanation:

Objects with more mass have more gravity. They work together.

Answer:

Explanation:

The change in momentum is in the negative direction.

Answer: [tex]5.944\times 10^{23}\ kg[/tex]

Explanation:

Given

Time period [tex]T=7.08\times 10^3\ s[/tex]

Orbital speed [tex]v=3.40\times 10^3\ m/s[/tex]

mass of GS [tex]m_{GS}=930\ kg[/tex]

Radius of Mars [tex]r=3.43\times 10^6\ m[/tex]

Consider the mass of mars is M

Here, Gravitational pull will provide the centripetal force

[tex]F_G=F_c[/tex]

[tex]\dfrac{GMm_{GS}}{r^2}=\dfrac{m_{GS}v^2}{r}\\M=\dfrac{v^2\cdot r}{G}\\M=\dfrac{(3.43\times 10^3)^2\cdot 3.43\times 10^6}{6.67\times 10^{-11}}[/tex]

[tex]M=5.944\times 10^{23}\ kg[/tex]

In March 1999 the Mars Global Surveyor (GS) entered its final orbit on Mars, sending data back to Earth. The mass of Mars is approximately 6.419 × 10²³ kg.

Kepler's Third Law states that the square of the orbital period (T) is proportional to the cube of the semi-major axis (a) of the orbit:

T² = (4π² / GM) × a³

In a circular orbit, the semi-major axis is equal to the radius of the orbit (r).

Given:

Orbital period (T) = 7.08 × 10³ s

Orbital speed (v) = 3.40 × 10³ m/s

Mass of GS (m) = 930 kg

Radius of Mars (r) = 3.43 × 10⁶ m

The orbital speed (v) is related to the radius (r) and the gravitational constant (G) by:

v = √(GM / r)

v² = GM / r

G = (v² × r) / M

T² = (4π² / [(v² × r) / M]) × r³

T² = (4π² × M × r²) / v²

M = (T² × v²) / (4π² × r²)

M = ( (7.08 × 10³)² × (3.40 × 10³)² ) / (4π² × (3.43 × 10⁶)²)

M = 6.419 × 10²³ kg

Therefore, the mass of Mars is approximately 6.419 × 10²³ kg.

To know more about the mass of Mars:

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Answer:

7000J

Explanation:

Given parameters:

Mass of car  = 1400kg

Initial speed  = 10m/s

Final speed  = 20m/s

Unknown:

Amount of work done  = ?

Solution:

In this problem, the amount of work done is the same as the change in kinetic energy of the body.

So;

   Work done  = Final kinetic energy  - initial kinetic energy

           Kinetic energy  = [tex]\frac{1}{2}[/tex]  m v²

   Work done  = [tex]\frac{1}{2}[/tex]  m(V²f - V²i )

m is the mass

vf is the final velocity

vi is the initial velocity

   Work done  =  [tex]\frac{1}{2}[/tex] x 1400 x (20 - 10)  = 7000J

Answer:

Amplitude increases with decreasing velocity.

Explanation:

At the same time, an increase in attention takes place

Answer:

Resistance is the opposing of the flow of current through a conductor.

Answer:

reducing temperature of the surrounding

Explanation:

combustion reactions are exothermic so they give off heat. reducing the temperature of the surrounding will enable more efficient energy transfer

Answer:

A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products.

Answer:

the answer is reactants i guess

Answer:

6.94 m/s²

Explanation:

Given that:

Initial Velocity (u) = 18.6 m/s

Time, t = 0.582

S, distance = 12 m

S = ut + 0.5at²

12 = (18.6 * 0.582) + 0.5(a)(0.582²)

12 = 10.8252 + 0.169362a

12 - 10.8252 = 0.169362a

1.1748 = 0.169362a

a = 1.1748 / 0.169362

a = 6.9366209

a = 6.94 m/s²

Hence, acceliofbthe car should be 6.94 m/s²

Answer:

a) They are the same.

Explanation:

Assuming no friction, there should be no energy transfer and thus the Law of Conservation of Energy says:

[tex]PE=KE,\\mgh=\frac{1}{2}mv^2[/tex]

These types of problems also disregard any air resistance the surface of the object may cause. Therefore, no energy is transferred and from the Law of Conservation of Energy, [tex]100\%[/tex] of energy is preserved.

Answer: thermal conductivity

The difference in the rate at which these two materials transfer thermal energy throughout the cups is known as thermal conductivity.

It is the rate where the heat is to be transferred from conduction via the cross section area of the unit with respect to the material at the time when the temperature should be gradient and existed with the perpendicular to the area.

Also, in this, two material is to be transferred via the thermal energy with the help of cups.

Learn more about energy here: https://brainly.com/question/17447827

Answer:

Earth.

Explanation:

Center of gravity can be defined as the specific point where all of the weight of an object is concentrated.

Generally, all the objects found around the world all have a center of gravity.

When an object is balanced so that a displacement lowers its center of gravity, the object is said to be in stable equilibrium.

Hence, the force of gravity acting on an object is directed through this center of gravity and toward the center of the earth.

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, weight is given by the formula;

[tex] Weight, W = mg [/tex]

Where;

m is the mass of an object.

g is acceleration due to gravity.

Answer:

D. The motion cannot be determined without knowing the speeds of the objects before the collision.

Explanation:

This question is tricky! We know the object moving to the left has a greater mass than the one moving to the right. We'd assume they would move to the left because the leftwards object has a greater mass, right?

Not. So. Fast.

We can solve for the objects' final velocity using the formula for momentum, m₁v₁ + m₂v₂ = (m₁ + m₂)v .

Now here's where the trap is sprung: we don't think about the equation. This shows that the final velocity of the objects and the direction depends on both the mass of the objects and their initial velocity.

Basically, what if the 3 kg object is moving at 1 m/s and the 4 kg object is moving at –0.5 m/s? The objects would move to the right after the collision!

Do we know the velocity of these objects? No, right?

That means we can't determine the direction of their motion unless we know their initial, pre-collision velocity. This question is tricky because we look at the 4 kg vs. 3 kg and automatically assume the 4 kg object would dictate the direction of motion. That's not true. It depends on velocity as well.

I hope this helps you! Have a great day!

Answer:

[tex]v_f=2\:\mathrm{m/s}[/tex]

Explanation:

From the Law of Conservation of Momentum, momentum is conserved. Therefore, we can set up the following equation:

[tex]m_1v_1+m_2v_1=m_fv_f[/tex]

Since the 5kg toy car was initially and rest, [tex]m_2v_2=0[/tex].

Therefore, plugging in our values, we have:

[tex]10\cdot 3=(10+5)v_f,\\v_f=\frac{30}{15},\\v_f=\fbox{$2\:\mathrm{m/s}$}[/tex].

Answer:

Let m1 = mass of big toy car=10kg

m2= mass of small toy car= 5kg

U1= initial velocity of big toy car= 3m/s

U2= initial velocity of small toy car=0

Since the big toy car moved the small one after the collision, their final velocity will be the same.

m1u1 + m2u2= (m1+m2)v

10(3)+(5)(0)=(10+5)v

30=15v

Divide both sides by 15

V=2

The final velocity is 2m/s

Explanation:

Answer:

v= -107.8 m/s

Explanation:

       [tex]v_{f} = v_{o} + a*t = a*t = -g*t = 9.8m/s2*11s = -107.8 m/s (1)[/tex]

Explanation:

(10) Mass of a soccer player, m = 0.42 kg

Initial speed, u = 0

Final speed, v = 32.5 m/s

Time, t = 0.21 s

We need to find the force that sends soccer ball towards the goal.

Force, F = ma

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.42 \times (32.5-0)}{0.21}\\\\F=65\ N[/tex]

So, 65 N of force soccer ball sends towards the goal.

(11) Mass of the satellite, m = 72,000 kg

Initial speed, u = 0 m/s

Final speed, v = 0.63 m/s

Time, t = 1296 s

We need to find the force is exerted by the rocket on the satellite.

Force, F = ma

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{72,000\times (0.63-0)}{1296}\\\\F=35\ N[/tex]

So, 35 N of the force is exerted by the rocket on the satellite.

Hence, this is the required solution.

Answer:

b) Springs oscillate with the same frequency,

Explanation:

expression for frequency of vibration of mass hanging from a spring is given as follows

f = [tex]\frac{1}{2\pi} \times \sqrt{\frac{k}{m} }[/tex]

k is force constant of spring and m is mass vibrating .

In the present case, if mass stretches the spring by x and remains balanced

mg = k x

[tex]\frac{k}{m} =\frac{g}{x}[/tex]

g and x are same  for both cases

[tex]\frac{k}{m}[/tex] will also be same for both cases .

Hence frequency of vibration will also be same for both the balls .

Answer:

B. 25 seconds

Explanation:

500÷20=25

Answer:

A)5524J,

B) 29.2Nm

Explanation:

This question can be treated using work- energy theorem

Work= change in Kinectic energy

W= Δ KE

Work= difference between the final Kinectic energy and intial Kinectic energy.

We know that

Kinectic energy= 1/2 mv^2 .............eqn(1)

This can be written in term of angular velocity, as

KE= 1/2 I

Answer:

[tex]|v|(t)=\sqrt{v_{x}^{2}(t)+v_{y}^{2}(t)+v_{z}^{2}(t)}=C[/tex]

[tex]2v(t)\cdot \frac{dv(t)}{dt}=0[/tex]

[tex]v(t)\cdot a(t)=0[/tex]

Explanation:

Let's start with the definition of a constant velocity.

If the velocity magnitude, in three dimensions,  is a constant value (C) we have a constant velocity, which means.

[tex]|v|(t)=\sqrt{v_{x}^{2}(t)+v_{y}^{2}(t)+v_{z}^{2}(t)}=C[/tex]

Now, we know that the dot product between v(t) and v(t) is the |v|².

[tex]v(t)\cdot v(t)=|v|^{2}(t)[/tex]

If we take the derivative whit respect to time in both sides of this equation we will have:

[tex]\frac{d}{dt}(v(t)\cdot v(t))=\frac{d}{dt}|v|^{2}(t)[/tex]

We apply the product rule on the left side and the right side will zero because the derivative of a constant is 0.

[tex]\frac{dv(t)}{dt}\cdot v(t)+v(t)\cdot \frac{dv(t)}{dt}=0[/tex]

[tex]2v(t)\cdot \frac{dv(t)}{dt}=0[/tex]

We know that dv(t)/dt = a(t) (using the acceleration definiton)

Therefore, we conclude:

[tex]v(t)\cdot \frac{dv(t)}{dt}=0[/tex]

[tex]v(t)\cdot a(t)=0[/tex]

If the dot product is 0, it means that v(t) and a(t) are orthogonal.

I hope it helps you!

Answer:

D.

Explanation:

im guessing.

Answer:

Q1: (a)

[tex]1cm \: = 10 {}^{ - 2}m[/tex]

so

[tex]45 \times {10}^{ - 2} m[/tex]

Q2:

[tex]1km = 10 {}^{3} m \\ 6378km \times {10}^{ 3} [/tex]

this is the radius in meter

diameter = 2r

in this i don't know which choice is the right answer

Q3:

[tex]1gram = \: {10}^{ - 3} kg[/tex]

so

[tex]250 \times {10}^{ - 3} = 2.5 \times {10}^{ - 1} kg[/tex]

again there is no correct answer

Answer:

[tex]375\:\mathrm{N}[/tex]

Explanation:

Work is given by the equation [tex]W=F\Delta x[/tex]. Plugging in given values, we get:

[tex]W=75\cdot 5=\fbox{$ 375\:\mathrm{N}$}[/tex].

Answer:

They can cause sunburn. Exposure to UV rays can cause premature aging of the skin and signs of sun damage such as wrinkles, leathery skin, liver spots, actinic keratosis, and solar elastosis. UV rays can also cause eye problems.

Explanation:

Answer:

Hello your question is incomplete attached below is the missing part of the question

In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these situations, two objects of masses m1 and m2 are attached to a seesaw. The seesaw is made of a bar that has length l and is pivoted so that it is free to rotate in the vertical plane without friction. Assume that the pivot is attached tot he center of the bar.

You are to find the angular acceleration of the seesaw when it is set in motion from the horizontal position. In all cases, assume that m1>m2.I

answer : part A = 2*[(M1 - M2)/(M1 + M2)]*g/L

              part A = attached below

Explanation:

Part A :

Assuming that mass of swing is negligible

α = T/I

where ; T = torque, I = inertia,

hence T =  L/2*9*(M1 - M2)

also;  I = [tex]M1*(L/2)^2 + M2*(L/2)^2[/tex]=  ( M1 + M2) * (L/2)^2

Finally the magnitude of the angular acceleration α

α = 2*[(M1 - M2)/(M1 + M2)]*g/L

Part B attached below

Answer:

the Indian Ocean on 26 December 2004. This event claimed 227,898 dead and missing from 14 countries. The difference in mortality rates between these tsunamis reflects, in part, the benefits of understanding how tsunami waves are generated and move, and educating citizens to make scientifically

sound and potentially life-saving decisions.

A tsunami is a series of rapidly propagating, shallow-water ocean waves that develops when a submarine earthquake, landslide, or volcanic eruption displaces a large volume of water. Powerful earthquakes, with magnitudes of 9 or greater, caused both the 2004 and 2011 tsunamis. The earthquakes resulted from the movement of large tectonic plates. The 11 March 2011 earthquake occurred at 32 km (20

mi.) deep in Earth’s crust about 130 km (81 mi.) east of the city of Sendai. This location is on the boundary between two tectonic plates—the Pacific plate to the east and North American plate to the west. This

boundary fractured, releasing energy that was transmitted through the rocks and elevated portions of the

ocean floor. This drastic movement transmitted energy to the overlying ocean water, which generated

tsunami waves that radiated outward. The waves washed over the nearby coastlines and were felt around

the globe within hours (Figure 1.1).  

Explanation:

Answer:

I believe Geosphere (lithosphere) and Hydrosphere

Explanation:

I hope it's right if not please notify me.

Answer:

because they are the rocks that line the surface of our planet ​

Explanation:

We see sedimentary rocks more than other rock types because they are the rocks that line the surface of our planet.

Sedimentary rocks typically form the earth cover due to the way they are formed.

Answer:

D. Iron is more easily magnetized than steel but steel is more easily demagnetized than iron.