A boy throws a tennis ball of mass 3kg at a wall with velocity of 40m/s.If it bounces back with 35m/s in an impact that lasted for 0.01s the change in its linear momentum and the force exerted on the tennis by the wall are

Answers

Answer 1

Answer:

The change in the linear momentum is 225 kg.m/s and the force exerted on the tennis ball is 22,500 N.

Explanation:

What is linear momentum?

Linear momentum is the measure of a body's motion. Every object that has mass and moves at any velocity has linear momentum. Here are some examples of everyday life: falling balls, launching rockets, driving a car etc.

Now let's attack the problem.

First, we got to write the data down:

[tex]\bullet \quad m=3\,kg\\\\\bullet \quad v_o=40\,m/s\\\\\bullet \quad v=35\,m/s\\\\\bullet \quad \Delta t =0.01\,s[/tex]

We can write the change in linear momentum of the tennis ball as follows:

[tex]\Delta p = p-p_o[/tex]

The ball's momentum is equal to its mass times its velocity. Hence:

[tex]\Delta p= m\cdot v-m\cdot v_o[/tex]

Let's set the reference system as positive to left (see picture attached). For that purpose, when the ball bounces back its velocity changes sign.

Now, we are able to plug in the data:

[tex]\Delta p = 3\cdot 35 - 3\cdot(-40)\\\\\\\Delta p = 105+120\\\\\\\therefore \boxed{\Delta p =225\,kg\cdot m/s}[/tex]

To calculate the exerted force, we must apply the impulse theorem, which states that impulse equals the change in linear momentum of an object. We get:

[tex]\mathbb{I}=\Delta p[/tex]

Hence,

[tex]F \cdot \Delta t=\Delta p\\\\\\F\cdot 0.01=225\\\\\\F=\dfrac{225}{0.01}\\\\\\\therefore \boxed{F=22,\!500\,N}[/tex]

Conclusion: the change in linear momentum is 225 kg . m/s and the exerted force is 22,500 N.

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A Boy Throws A Tennis Ball Of Mass 3kg At A Wall With Velocity Of 40m/s.If It Bounces Back With 35m/s

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Explain how solar and lunar eclipse occur with the help of a labelled diagram.​

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Answer:

Reflection. If a sound is not absorbed or transmitted when it strikes a surface, it will be reflected. ... Reflection of a sound wave at a barrier, as if from an imaginary source at an equal distance behind the barrier. Sound reflection gives rise to DIFFUSION, REVERBERATION and ECHO.

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Explanation:

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Why does the force between the locomotive and the first car always have to be larger
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Answer:

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A steel projectile is shot horizontally at 54 m/s from the top of a 357 m tower. How far
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Answers

Hi there!

We can begin by solving for the time it takes the projectile to reach the ground.

Use the equation:

[tex]t = \sqrt{\frac{2h}{g}}[/tex]

Plug in the given height:

[tex]t = \sqrt{\frac{2(357)}{9.8}} = 8.536 s[/tex]

Use the equation:

d = vt, to solve for the horizontal distance:

d = (54)(8.536) = 460.944 m

part 3 of 3
---
What is the velocity when t = 8 s?
Answer in units of m/s.
Answer in units of m/s

Answers

Answer:

1 m/s

(i think, *nervous sweat*)

Explanation:

We can tell this by looking at the graph. When t = 8, we will look at the time. We see that when the x (time) is 8, the velocity is 1 m/s.

l am so confused is it right?

Answers

Answer:

D

Explanation:

First,mg>fv: It does a download acceleration,and the speed of the object increase.

Second,mg=fv: it hasn't a acceleration.

you can think the f is a constant.

what is the acceleration of an object if the force equals 300 N and the mass is 25kg?

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Answer:

Explanation: If a net force of 50 N pulls on a 10 kg object, how much acceleration will it cause? Then an answer is possible. Equation: Net force = mass * acceleration.

pls answer the question I will make you as brainiest​

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Answer:

Answer in the drawing. Please mark me brainliest

a spring vibrates 120 times in 2 mins find its frequency and time period​

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2 minutes is 120 seconds, so if you were finding vibrations per minute, it would be 60 times a minute.

the chemical compositions of jupiter and saturn are most similar to those of:

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Most similar to Uranus and Neptune

Given a table of values for the exponential function f(x) and a description of the
transformation for the function g(x)
, fill out the table of values based on the original
points for glx), the transformed function.
- 1
0
2
16
3
Reflect over
0
2
4
0-4, -1, -12
1
16
.
64
01, 1, 4, 16, 64
,
4, 1, , 162
0-1, -1, –4, – 16, – 64

Answers

Answer:its D

Explanation:

i did the test and got it right

The transformation function of the given exponential function is -1/4, -1, -4, -16, -64. Hence option D is correct.

What is an exponential function?

An exponential function is a mathematical relation to find exponential growth or decay for the given data. It represents the constant change in independent variables and gives the same proportional change.

The exponential function is expressed as f(x) = exp (x) or eˣ where x is variable and e is constant which is called the base of the equation.  

From the given,

the exponential function f(x) = 1/4, 1,4,16,64

The transformation function G(x) is the inverse of the exponential function and is equal to -1/4,-1, -4,-16,-64.

Hence, the ideal solution is option D.

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A horizontal force acts on an object on a fric- tionless horizontal surface. If the force is halved and the mass of the object is doubled, the acceleration will be (1) four times, (2) two times, (3) one-half, (4) one-fourth as great. (b) If the acceleration of the object is , and the force on it is doubled and its mass is halved, what is the new acceleration

Answers

(a)  If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)  if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

The force on an object is determined by applying Newton's second law of motion;

F = ma

[tex]\frac{F_1}{m_1a_1} = \frac{F_2}{m_2a_2}[/tex]

(a)

when the force is halved, F₂ = 0.5F₁,

mass is doubled, m₂ = 2m₁

[tex]\frac{F_1}{m_1a_1} = \frac{0.5F_1}{2m_1a_2} \\\\2m_1a_2F_1 = 0.5F_1 m_1a_1\\\\2a_2 = 0.5a_1\\\\a_2 = \frac{0.5a_1}{2} = \frac{a_1}{2 \times 2} = \frac{a_1}{4} \\\\a_2 = \frac{1}{4} (a_1)[/tex]

Thus, If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)

when the force is doubled, F₂ = 2F₁,

mass is halved, m₂ = 0.5m₁

[tex]\frac{F_1}{m_1 a_1} = \frac{2F_1}{0.5m_1 a_2} \\\\0.5m_1a_2 F_1 = 2F_1m_1a_1\\\\0.5a_2 = 2a_1\\\\a_2 = \frac{2a_1}{0.5} \\\\a_2 = 4(a_1)[/tex]

Thus, if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

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a physics student throws a stone horizontally off a cliff. one second later, he throws a second identical stone in exactly the same way. which of the following statements is true?

Answers

The second stone hits the ground exactly one second after the first.

The distance traveled by each stone down the cliff is calculated using second kinematic equation;

[tex]h = v_0_yt + \frac{1}{2} gt^2[/tex]

where;

t is the time of motion [tex]v_0_y[/tex] is the initial vertical velocity of the stone = 0

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The time taken by the first stone to hit the ground is calculated as;

[tex]t_1 = \sqrt{\frac{2h}{g} }[/tex]

When compared to the first stone, the time taken by the second stone to hit the ground after 1 second it was released is calculated as

[tex]t_2 = \sqrt{\frac{2h}{g} } + 1[/tex]

[tex]t_2 = t_1 + 1[/tex]

Thus, we can conclude that the second stone hits the ground exactly one second after the first.

"Your question is not complete, it seems be missing the following information;"

A. The second stone hits the ground exactly one second after the first.

B. The second stone hits the ground less than one second after the first

C. The second stone hits the ground more than one second after the first.

D. The second stone hits the ground at the same time as the first.

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NEED HELP!!!! 15 POINTS!!!!

Imagine that you are going to make an exercise routine. If your goal was to develop your health rather than one specific improvement, what should be in your plan?
A.
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B.
a variety of aerobic and anaerobic exercises
C.
a single exercise with increasing intensity
D.
an exercise that you have never tried before

PLEASE NO LINKS

Answers

Answer:

c

Explanation:

If the goal of the exercise routine is to develop overall health rather than focusing on one specific improvement, a well-rounded approach that addresses various aspects of fitness would be ideal.

This would involve a combination of different types of exercises to promote cardiovascular health, muscular strength, flexibility, and overall well-being. From the given options, the best choices would be:

B. A variety of aerobic and anaerobic exercises: This option is important because it incorporates both cardiovascular exercises (aerobic) and strength-building exercises (anaerobic), ensuring a balanced approach to fitness.

A. A focus on the benefits of stretching: Stretching is important for maintaining flexibility and preventing injuries. Incorporating stretching exercises, such as static and dynamic stretches, can contribute to overall health and mobility.

D. An exercise that you have never tried before: While not as essential as the first two options, trying new exercises can add variety and excitement to your routine. It can also engage different muscle groups and challenge your body in new ways.

C. A single exercise with increasing intensity: While progressively increasing the intensity of a single exercise can be part of a fitness plan, focusing solely on a single exercise may not provide the diverse benefits that a combination of exercises can offer. Variety is key to a well-rounded fitness routine.

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9- Where did Rutherford propose that most of the mass of an atom
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Answer:

A) in the middle of the atom

Explanation:

He concluded that all of the positive charge and the majority of the mass of the atom must be concentrated in a very small space in the atom's interior, which he called the nucleus.

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Answer:

Boiling water

Explanation:

a ball is thrown vertically down from the edge of a cliff with a speed of 5.2m/s how high is the cliff if it took 11s for the ball to reach the ground​

Answers

initial velocity=u=5.2m/sFinal velocity=v=0m/sTime=t=11sHeight=hAcceleration=g=9.8m/s^2

[tex]\\ \sf\longmapsto h=ut+\dfrac{1}{2}gt^2[/tex]

[tex]\\ \sf\longmapsto h=5.2(11)+\dfrac{1}{2}(9.8)(11)^2[/tex]

[tex]\\ \sf\longmapsto h=57.2+4.9(121)[/tex]

[tex]\\ \sf\longmapsto h=57.2+592.9[/tex]

[tex]\\ \sf\longmapsto h=650.1m[/tex]

5. What must occur for an object to exert a contact force on another object?

Answers

Answer:

An object must be touching another.

To hit a fish that he sees beneath the water, where should he aim?

Answers

Ok I guess you are gonna use arrow/spear. Ok so what I learned is that the best place to hit and fish is the gills or the eye(s) because without the gills fish won't be able to breath.If you hit it on the eye it will take a while to kill the fish.The fish will feel lots of pain and start swim like crazy and probably go away.So i will say the BEST way to kill a fish to to hit it's gills.

In case you don't have any materials to kill fish:

IF you are in the wild with fish and you don't have a hook,spear,arrow, etc. I will recommend you to use a rock that his big but easy to grip.Hit the fish on top of its head just behind the eyes.Or get a stick no too thick or too skinny just like between those and start whittle it to a arrow then aim and shoot.

Hope this helps! =D

Li Wei loves cardio and finds it very easy to fit into his schedule. Because he knows it is important to diversify his exercise routine, sometimes he runs and other days he rides his bike. What else should Li Wei consider regarding his routine?


OPTIONS:

A.
He should add some strength training.
B.
He needs to add one more form of cardio.
C.
He has too much cardio and should cut half of it.
D.
His program works for him, so he should not change it.

PLEASE NO LINKS

Answers

Answer:

D.

Explanation:

Li Wei loves cardio and finds it very easy to fit into his schedule. Li Wei should consider his routine is his program works for him, so he should not change it. The correct option is D.

What is cardio?

Any form of exercise that raises your heart rate and keeps it there for a long time is considered cardio. As you start to breathe more quickly and deeply, your respiratory system will start to work harder.

The four components of a fitness program are flexibility, cardio, strength, and power.

The physical exercise that increases muscular strength and fitness is referred to as strength.The capacity to produce the most muscle contractions possible during a movement is referred to as power.Cardio refers to the capacity to handle various circumstances of various lengths.Flexibility is the characteristic that is linked to the range of motion offered by a particular joint.

Therefore, the correct option is D. His program works for him, so he should not change it.

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In induction, what charge does a neutral substance gain compared to the object brought near it?

Answers

Explanation:

In induction, what charge does a neutral substance gain compared to the object brought near it?

The neutral object gains the same type of charge as the object that touched it because the electrons move from one object to the other (Figure 10.16). Induction is the movement of electrons within a substance caused by a nearby charged object, without direct contact between the substance and the object.

The charge gained by the neutral substance, gained compared to the object brought near it, had the same kind of charge that was present when it touched it.

What is induction?

The alteration of the distribution of electric charge on a substance is caused by the effect of induction. A negatively charged object brought close to an electrically neutral object causes a positive charge on the near side and a negative charge on the far side of the neutral object as a result of the electric force between charged particles that make up materials.

This very little polarization, or separation of charge, lessens the electric field inside the dielectric.

Because the electrons go from one thing into the next, the neutral object acquires the same kind of charge that was present when it touched it. Lacking physical touch, induction is the movement of electrons within a substance as a result of a nearby charged item.

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What is final velocity

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Answer:

Final velocity is the velocity which the body has at the end of the given time period.

A 1.35 kg block is pulled across a
flat, frictionless floor with a 3.07 N
force at 32.0° above horizontal.
What is the acceleration of the block?

Answers

Answer:

F=ma

3.07=1.35(a)

3.07/1.35 = a

a=2.27m/s^2

Explanation:

Since the question gives us both the force and mass of the object we can use the f= ma equation and just plug in both the force and mass and just solve for acceleration. I believe the degree listed in the question is just there to throw you off.

to analyze the characteristics and performance of the brakes on a 1500 kg car, researchers collected the data shown in the table above. it shows the car’s speed when the brakes are first applied and the corresponding braking distance required to stop the car. the magnitude of the average braking force on the car is most nearly:

Answers

He magnitude of the average braking force is 12,000 N.

The braking force can be calculated using the following formula:

Braking Force = (0.5 x mass of the car x squared velocity) / distance

Now, let's use this formula to find the Braking force in each case based on the information of the chart:

F = (0.5 x 1,500 x 100) / 6.1  =  12,295F = (0.5 x 1,500 x 400) / 23.9 = 12,550F = (0.5 x 1,500 x 900) / 53.5 = 12,616

Now, let's add the results and divide the result into three to find the average:

12,295 + 12,550 + 12,616 = 37,461/ 3 = 12,487

From these, the option that is the most similar is C 12,000 N

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A force of 20 N acts upon a 5 kg biock. Calculate the acceleration of the object.

Answers

Answer:

F=ma

Explanation:

Given required solution

F=20N a=? a=F/m

m=5kg a=20/5

a=4m/s^2

what is the acceleration caused by gravity on earth

Answers

Answer:

Explanation:

It's 9.8 m/s^2

Need an answer in Meters

Answers

Answer:

• let's first get time

[tex]{ \rm{s = ut + \frac{1}{2}g {t}^{2} }} \\ \\ { \rm{78.4 = 30t + 5 {t}^{2} }} \\ \\ { \rm{ {t}^{2} + 6t - 15.68 = 0}} \\ \\ { \rm{time \approx \: 2 \: seconds}}[/tex]

• let's find horizontal displacement

[tex]{ \rm{s = ut + \frac{1}{2}g {t}^{2} }} \\ \\ { \rm{s = (30 \times 2) \times ( \frac{1}{2} \times 0 \times {2}^{2}) }} \\ \\ { \rm{displacement = 60 \: meters}}[/tex]

g is acceleration due to gravity [ vertically: g is 10 m/s². horizontally: g is 0 ]

I WILL MARK U HELP PLZ
The free body diagram for an object is projected. Calculate the net force acting on the object. If this object is 10 kg, how/where will it accelerate?

Answers

Explanation:

By the end of the section, you will be able to:

Apply problem-solving techniques to solve for quantities in more complex systems of forces

Use concepts from kinematics to solve problems using Newton’s laws of motion

Solve more complex equilibrium problems

Solve more complex acceleration problems

Apply calculus to more advanced dynamics problems

through this steps you will get the answer.thank you
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