A car accelerating from 10m/s to 25m/s
in 6sec find average acceleration

The angle at which a ray of light strikes a pane of window glass is smaller than the angle at which it passes out the other side.

When light go through window glass it will experience refraction due to change of light speed. The relation between angle of incidence and angle of refraction is given by the Snell's law:

n₁ sin∅₁ =  n₂ sin∅₂

Where:

n₁ = incident index (refractive index of medium 1)

n₂ = refraction index ((refractive index of medium 2)

∅₁ = incident angle

∅₂ = refraction angle

Typical refractive index for glass is around 1.5 while refractive index for air is 1.000273.

In the given case, the ray of light is from the window glass and pass out the other side. Hence,

n₂ = air

n₁ = glass

Since  n₁ > n₂ , the velocity in the air is greater than the velocity in the window glass. Hence, ∅₁ < ∅₂  or the incident angle is smaller than the refracted angle.

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The force P on the cable if the spring is compressed 0.5 in with a stiffness of k = 800 lb/ft is 46.91 lb

k = Fe / δ

k = Stiffness of spring

Fe = Force on spring

k = 800 lb / ft = 6.67 lb / in

δ = 0.5 in

Fe = k δ

Fe = 6.67 * 0.5

Fe = 33.33 lb

At joint A,

∑ MA = 0

( - Bx * 6 ) + ( - By * 6 ) + ( 33.33 * 30 ) = 0

Bx + By = 166.67  → ( 1 )

At joint D,

∑ MD = 0

( - By * 6 ) + ( P * 4 ) = 0

By = 0.067 P  → ( 2 )

∑ Fx = 0

- Bx + FCD cos 30° = 0  → ( 3 )

At joint B,

∑ MB = 0

( - FCD sin 30° * 6 ) + ( P * 10 ) = 0

FCD = 3.33 P

Sub FCD in ( 3 ),

- Bx + 3.33 P cos 30° = 0

Bx = 2.8867 P

Sub Bx and By in ( 1 ),

2.8867 P + 0.667 P = 166.67

P = 46.91 lb

Therefore, the force P on the cable if the spring is 46.91 lb

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The magnitude of the net force on particle Q₂ is  6.487 x 10⁶ N.

The net force on particle Q₂ is obtained by applying Coulomb's law of electrostatic force.

Force between Q₁ and Q₂;

F₁₂ = kq₁q₂/r²

where;

F₁₂ = (9 x 10⁹ x 20.5 x 10⁻³ x 9.3 x 10⁻³)/(0.98)²

F₁₂ = 1.787 x 10⁶ N

Force between Q₂ and Q₃;

F₂₃ = kq₂q₃/r²

F₂₃ = (9 x 10⁹ x 9.3 x 10⁻³ x 31.6 x 10⁻³)/(0.75)²

F₂₃ = 4.7 x 10⁶ N

The net force on particle Q₂;

F(net) = F₁₂ + F₂₃

F(net) = 1.787 x 10⁶ N +  4.7 x 10⁶ N

F(net) =  6.487 x 10⁶ N

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The total momentum after the collision  is 1.80 kgm/s

Since we are provided with the mass of both the objects which is  1. 00 kg and there were moving towards each other before Collison under a closed system with the velocity of 1. 80 m/s.

Since the momentum of an object  is the magnitude of there mass imotion, the formula for calculating momentum is  = mass * velocity

So, the momentum of the objects before collisions are = 1 kg *1. 80 m/s

= 1.80 kgm/s ,. when two objects collide in a closed system, the total energy of the two objects before the collision is the same as the entire momentum of the two objects after the collision. The momentum of each object may change, but the entire momentum must stay the same.So the momentum after the collision is 1.80 kgm/s

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Answer: The correct answer is 0.00 kg · m/s.

Explanation:

The independent variables of measuring physical properties are given below -

What is physical properties?

A physical properties in any property that is measurable, whose value describe a state of physical system.

The changes in the physical properties of a system can be used to describe its changes between the  momentary that state of

Physical properties are often referred to as observables.

They are not modal properties.

Any variable that can be attributed a value without attributes a value to any to any other variables is called independent variables.

It is a variable that stands alone and isn't changed by other variables you are trying to measure.

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Answer:

100 m/s^{2}

Explanation:

the given information we have is:
vi = 30m/s

vf = 20m/s

t = 0.10s

we need to find a so we will use the following kinematics equation

[tex]vf=vi+at[/tex]

we can rearrange the equation so it will give us our desired answer like so:

[tex]a = \frac{vf-vi}{t}[/tex]

now we can plug in our given numbers

[tex]a = \frac{20 m/s - 30 m/s}{0.10s}[/tex]

which will equal

[tex]100 m/s^{2}[/tex]

Using the Time period formula for a Satellite,

the radius of orbit from earth center is 6.7590.

Time period : The satellite period is the time it takes for a satellite to make one orbit around the Earth, denoted by T. Therefore, T = distance traveled in 1 revolution/orbital velocity = 2πr/V.

We have the following information,

the Satellite revolves the earth twice in a day .

As we know,

mass of the earth(M) is 5.97 × 1024 kg

Gravitational constant (G)= 6.67 × 10-11 Nm²/kg²

The time taken to complete two rounds is a day. Time taken by the satellite in one alone will be cost to one by the day i.e., T = 24 hours

The time period of the satellite must be equal to

2T = 2×24×60×60 sec = 172800 sec.

According to Kepler's 3Rd law ,

T² = ( 4π²/GM )r³---(1)

where, T ---> time period

M --> mass of earth

G--> gravtional constant

r --> radius of orbit

putting all the values in above formula

(172800)² = ( 4×(3.14)²/(6.67 × 10-11 Nm²/kg²× 5.97 × 1024 kg))r³

=> r³ = (172800)²/96,720,640.93= 308.722

=> r = 6.75890 ~ 7

Hence, the radius of orbit is 6.75890

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The correct Option is Always true.

According to Archimedes' principle when an object is immersed in a liquid, and it is either partially or wholly submerged, the upward force that acts on the object, is known as buoyancy force and it is equal to the weight of the liquid displaced by the object.

So, the buoyancy force is always present whenever an object is placed in a liquid. Archimedes' principle proves that The magnitude of buoyancy force is always equal to the weight of the fluid  displaced by the object

Hence the correct option is Always.

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The complete Question is :

An object is placed in a fluid and then released. Assume that the object either floats to the surface (settling so that the object is partly above and partly below the fluid surface) or sinks to the bottom. (Note that, for Parts A through D, you should assume that the object has settled in equilibrium.)

A.Consider the following statement: The magnitude of the buoyancy force is equal to the weight of fluid displaced by the object.

Under what circumstances is this statement true?

A. always

B. only for an object that floats

C. only for an object that sinks

D. never

50.0 g of water will require 3135  Joules energy is needed to change temperature by 15.0 C .

mass is 50 g

temperature is 15

Q=mC8ΔT

where,

m is mass of substance

C8=4.18 jouls /g

Q=50*4.18*15

Q=3135 J

The temperature is a numerical indicator of how cold or hot something is. One can measure temperature by using a thermometer. The calibration of thermometers involves using various temperature scales, which historically defined them using various reference points and thermometric materials. Several scales, including Fahrenheit and Celsius, can be used to express temperature, which is a unit of measurement. A hotter body (one with a higher temperature) will spontaneously move heat energy in the opposite direction to a cold body, as shown by temperature. the level of heat or cold in a body or environment the sensation of coldness or heat.

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The centripetal acceleration for radius 2.0 m = 50 m/s²

The centripetal acceleration for radius 4.0 m = 25 m/s²

The centripetal acceleration for radius 6.0 m = 16.67 m/s²

The centripetal acceleration for radius 8.0 m = 12.5 m/s²

The centripetal acceleration for radius 10.0 m = 10 m/s²

An object that moving in a circle and has an acceleration vector pointing towards the center of the circle is called centripetal acceleration.

a₀ = v²/r

Where, a₀ = Centripetal acceleration

v = velocity of the object

r = radius of circular path

Given,

m = 1 kg

v = 10 m/s

r = 2.0 m, 4.0 m, 6.0 m, 8.0 m, 10.0 m

Now,

a₀₁ = 10²/2

a₀₁ = 50 m/s²

a₀₂ = 10²/4

a₀₂ = 25 m/s²

a₀₃ = 10²/6

a₀₃ = 16.67 m/s²

a₀₄ = 10²/8

a₀₄ = 12.5 m/s²

a₀₅ = 10²/10

a₀₅ = 10 m/s²

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The complete question is as follows:

"Keeping the mass at 1.0 kg and the velocity at 10.0 m/s, record the magnitude of centripetal acceleration for each given radius value. Include units. Radius: 2.0 m 4.0 m 6.0 m 8.0 m 10.0 m Acceleration: Radius factor: Acceleration factor:"

Answer:

F = q V X B = I L X B     are descriptions of the force on a moving charge

Suppose that a battery terminal is + on the left connected by a wire to    a - charge on the right, the X indicates a cross product so the force on the moving charge is perpendicular to both the magnetic field and the moving charge.

If one wraps the hand around the wire with the thumb pointing in the direction of the "conventional" current, the induced field will be in the direction of the fingers - V X B is the cross product of the moving charge and the magnetic field;
Note q V = q L / t = (q / t) * L = I L

A force of 80 newtons is applied to the combined masses.acceleration of the system is =40/3 or 13.33 metre/sec².

acceleration, rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down. Motion on a circle is accelerated even if the speed is constant, because the direction is continually changing.

acceleration of object A= FORCE APPLIED ÷ MASS OF A

                                                               =80÷ mass of A

                       mass of A = 80÷ acc of object A

                        mass of A= 80÷20=4kg

                         mass of A = 4kg

acc of object B = force applied ÷ mass of B

 mass of object B =force applied ÷ acc of object B

 mass of object B=80÷40=2kg

mass of object B =2Kg

when same force is applied to the combined system of 4kg and 2kg then acceleration of the combined mass is = force applied ÷ total mass

=80÷[4+2]

=80÷6

=40÷3

=13.333 metre/sec²  

acc of the combined system is 13.333 metre/sec²

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In order to lift a bucket of concrete, you must pull up harder on the bucket than it pulls down on you is referred to as a false statement.

This is referred to as an external agent which is capable of influencing the motion of an object or body. It is also capable of changing the state of rest of a body and the unit in Newton.

When lifting the bucket, the total opposite forces and not only the weight which is what pulls it down must be overcome in other to lift the object or body successfully which is why false was chosen.

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Answer:

windmill, device for tapping the energy of the wind by means of sails mounted on a rotating shaft. The sails are mounted at an angle or are given a slight twist so that the force of wind against them is divided into two components, one of which, in the plane of the sails, imparts rotation.

Explanation:

The use of windmills was increasingly widespread in Europe from the 12th century until the early 19th century. Their slow decline, because of the development of steam power, lasted for a further 100 years. Their rapid demise began following World War I with the development of the internal-combustion engine and the spread of electric power; from that time on, however, electrical generation by wind power has served as the subject of more and more experiments

To work efficiently, the sails of a windmill must face squarely into the wind, and in the early mills the turning of the post-mill body, or the tower-mill cap, was done by hand by means of a long tailpole stretching down to the ground. In 1745 Edmund Lee in England invented the automatic fantail. This consists of a set of five to eight smaller vanes mounted on the tailpole or the ladder of a post mill at right angles to the sails and connected by gearing to wheels running on a track around the mill

The most important use of the windmill was for grinding grain. In certain areas its uses in land drainage and water pumping were equally important. The windmill has been used as a source of electrical power since P. La Cour’s mill, built in Denmark in 1890 with patent sails and twin fantails on a steel tower. Interest in the use of windmills for the generation of electric power, on both single-user and commercial scales, revived in the 1970s.

Cu = 0.385 J/gC, show smallest temperature change upon gaining 200 J.

Calculation:-

50.0 g Cu , Cu = 0.385 J/gC, will show the smallest change in temperature.

Temperature is the measure of hotness or coldness expressed in terms of any of several scales, including Fahrenheit and Celsius.

In A  temperature change = (50 × 0.903)/ 200 = 0.22575 °C

In B temperature change = (50 × 0.385)/200 = 0.09625 °C,

Therefore, 50.0 g Cu , Cu = 0.385 J/gC, will show the smallest change in temperature.

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Disclaimer:- Your question is incomplrte, please see below for complete question.

which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 j of heat? which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 j of heat?

a. 50.0 g fe,

b. 0.385 J/gC

c. both

d. none

The cube will float.

The upward buoyant force that is applied to a body submerged in a fluid, whether wholly or partially, is equal to the weight of the fluid that the body displaces and acts in the upward direction at the center of mass of the displaced fluid, according to Archimedes' principle.

Given parameters:

The average density of an object is 0.46 kg/m³.

The density of olive is oil 0.92 kg/m³.

As The average density of an object  < density of olive oil; the liquid displaced by the object has more weight than the weight of the object.

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The magnitude of the sum of these two vectors is 23.95 m.

The sum of the vectors is the resultant vector obtained by resolving the vectors into x and y component.

the horizontal component of the vector (x)  = v cosθ

the vertical component of the vector  (y) = v sinθ

where;

For the first vector;

x = 16.3 m x cos(27.8) = 14.42 m

y = 16.3 m x sin(27.8) = 7.6 m

For the second vector;

x = 7.7 m  x   cos(20) = 7.24 m

y = 7.7 m  x  sin(20) = 2.63  m

Net horizontal and vertical vector;

∑x = 14.42 m  +   7.24 m   = 21.66 m

∑y = 7.6 m + 2.63 m = 10.23 m

The magnitude of the sum of these two vectors is calculated as;

v = √(∑x² + ∑y²)

v = √(21.66²   +    10.23²)

v  = 23.95 m

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The glass & lead ball will both fall to the ground simultaneously. Galileo lowered two walls from the roof of Pisa. Whichever one lands on the ground first must be determined.

To shape metal, fill forming bags or use them as counterbalance. A minimum of 97% of the material is pure lead. All of these balls have precisely made for a flawless finish. They are additionally called lead shot.

Lead balls are frequently used in radiation protection for fill and melt into cracks and holes in lead shields in which other lead products, such as lead sheet or lead bricks, are inaccessible. The substance has a low point of melting and thus is simple to work with and quick to form a uniform barrier layer.

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In such a motion, the rigid body rotates along a fixed axis that is parallel to a fixed plane.

In other words, with respect to an inertial frame of reference, the axis is stationary and does not move or change direction. I=jmjr2j, where mj is the mass of the point particle and rj is its distance from the rotation axis, is the moment of inertia for a system of point particles revolving about a fixed axis. The angle of rotation is the angle at which an object revolves (turns) around a given point. Constant angular speed rotation is the most basic type of rotation around a fixed axis. The total torque then becomes zero.

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The highest height attained is 2gu.

The vertical velocity is 0 at its highest point. Once more increasing in magnitude as the item descends back toward Earth, the vertical velocity now faces away from the initial vertical velocity.

0 m/s. Any projectile at its highest point has an instantaneous speed of zero. The time to reach maximum height is equal to the time to arrive at the destination since gravity accelerates the ball by the same amount whether it is moving up or down.

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The final velocity at the end of this time will be 200 [tex]m/s^{2}[/tex]

When any object is in free fall, then

The value of acceleration = g  [tex]m/s^{2}[/tex] = 10 [tex]m/s^{2}[/tex]

The initial velocity (u) = 0 m/s

Let the final velocity (v) = v m/s

The mass of the object (m) = 10 kg

Time taken to reach the ground = 20 s

We will calculate the height (s) from which the object falls,

We employ the 2nd equation of motion since the object is under constant acceleration,

We have,

[tex]s = ut +\frac{1}{2} at^{2}[/tex]

Putting the values in the equation, we get

[tex]s = 0 +\frac{1}{2} *10 *20^{2} \\\\s = 2000[/tex]

Thus, the height is 2000 m

Now, we apply the third equation of motion,

[tex]v^{2} -u^{2} = 2as[/tex]

Putting all the values, we get,

[tex]v^{2} -0^{2} = 2*10*2000\\\\v^{2} = 40000\\\\v = 200[/tex]

Hence, the final velocity at the end of this time will be 200 [tex]m/s^{2}[/tex]

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A) The initial kinetic energy of the bullet is 722J

B) Kinetic energy of the bullet and pendulum immediately after the bullet becomes embedded in the pendulum  0.68J

C)  The vertical height through which the pendulum rises  0.69cm

The following data-

Mass of the bullet - 10.0g

speed - 380m/s

mass of the pendulum - 10.0kg

length of cord - 70.0cm

To find the initial kinetic energy of the bullet -

KE=1/2mv^2

KE = 1/2 x 0.010 x 380^2

KE= 722J

initial kinetic energy = 722 J

To find the Kinetic energy of the bullet and pendulum immediately after the bullet becomes embedded in the pendulum, we need to first find the final velocity and vertical height through which pendulum rises-

we will find final velocity by applying the law of conservation of momentum

We know, Momentum of bullet is equal to the sum of the momentum of bullet and pendulum.

MbVb= (Mb+Mp)V

where,

Mb= mass of bullet

Mp = mass of pendulum

Vb = velocity of bullet

V = Final velocity

0.010 x 380 = ( 0.010 + 10)V

3.8 = 10.01V

V = 3.8/10.01

v = 0.37m/s

The final velocity = 0.37m/s

now, to find the vertical height

height = V^2/2g

= 0.37^2/2 x 9.8

= 0.136/19.6

= 0.00693m

converting to cm

0.00693 x 100 = 0.69 cm

To find the kinetic energy of the bullet and pendulum immediately after the bullet becomes embedded in the pendulum -

KE = 1/2 (Mb + Mp)V^2

KE = 1/2 ( 0.010 + 10) x 0.37 ^2

KE = 1/2 ( 10.01) x 0.1369

KE = 0.68J

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The box's acceleration is 2.75m/s².

It is said that an equilibrium is stable when small, externally induced displacements from it result in forces that have a tendency to oppose the displacement and bring the body or particle back to the equilibrium state. A brick placed flat on the ground or a weight suspended by a spring are two examples.

Given,

F = 185 N is the amount of force that the student applied

Horizontal is at an angle of θ = 25°

Mass of box = 35kg

Between the box and the floor, there is a kinetic friction coefficient of

µ = 0.27

The equilibrium of forces is the foundation for the presented issue. We also need to find the equation of motion for the force's horizontal and vertical components in order to solve the problem. So,

Across the horizontal axis,

Tcosθ - µN = ma  (1)

The forces acting in the vertical direction are,

N + Tsinθ = mg

N = mg - Tsinθ  (2)

Replace (1) with the value of equation (2) as,

Tcosθ - µ( mg - Tsinθ) = ma

a = Tcosθ - µ( mg - Tsinθ)/m

The applied force, T = F = 185 N, causes the tension force on the rope.

fixing as,

a = 185×cos25× -(0.25)×35×9.8+((185)sin25)/35

a = 2.75m/s².

Consequently, we can say that the box's acceleration is a = 2.75m/s².

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The amount of potential electricity saved inside the marble decreases while its kinetic strength will increase.

In physics, the kinetic energy of an item is the electricity that it possesses because of its movement. it's far defined because the paintings needed to boost up a body of a given mass from relaxation to its said pace. Having received this electricity throughout its acceleration, the frame keeps this kinetic power except its speed changes.

Kinetic energy is a shape of energy that an object or a particle has by means of purpose of its motion. If work, which transfers strength, is carried out on an item by applying a net pressure, the object accelerates and thereby gains kinetic electricity.

Electric kinetic power truly explains the transit of the electrical electricity itself, power. as an instance, the electrical contemporary that includes the charge from a battery to the mild bulb is kinetic electricity.

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Jupiter can never be farther from the sun than Saturn if the mass of the sun is 1991030 kg, the orbital radius of Jupiter is 7781011 m, and the orbital radius of Saturn is 1431012 m.

Fc = m v² / r

Fg = G M m / r²

Fc = Centripetal force

Fg = Gravitational force

m = Mass of planet

v = Linear Velocity of planet

r = Orbit radius

G = Gravitational constant

M = Mass of sun

Fc = Fg

G M m / r² = m v² / r

v² = G M / r

M = 1991030 kg

G = 6.67 * [tex]10^{-11}[/tex] N m² / kg²

v² = G M / r

For Jupiter,

r = 7781011 m

vj² = 6.67 * [tex]10^{-11}[/tex] * 1991030 / 7781011

vj² = 1.17 * [tex]10^{-11}[/tex]

vj = 3.42 * [tex]10^{-6}[/tex] m / s

For Saturn,

r = 1431012 m

vs² = 6.67 * [tex]10^{-11}[/tex] * 1991030 / 1431012

vs² = 9.28 * [tex]10^{-11}[/tex]

vs = 9.63 * [tex]10^{-6}[/tex] m / s

vs > vj

Therefore, Jupiter can never be farther from the sun than Saturn

The given question is incomplete. The complete question is :

Suppose the sun's gravity were switched off. the planets would leave their orbits and fly away in straight lines as described by newton's first law. (assume the mass of the sun is 1991030 kg, the orbital radius of Jupiter is 7781011 m, and the orbital radius of Saturn is 1431012 m. Would Jupiter ever be farther from the Sun than Saturn?

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Answer:

Below

Explanation:

Here is one possibility:

Vertical components added together = 80 sin 120 + 0 = 69.28

Horizontal components  = 80 cos 12 0  + 100 = 60 N

Resultant magnitude =   sqrt ( 69.28^2 + 60^2) = 91.65 N

    Angle = arctan (69.28/60)=49.1°

L=1 is the only combination possible because l1=0 and l2=1. S=1,0 is one of the possible combinations of S. This indicates that M = 3 or M = 1. Term symbols will take the 1P and 3P forms.

A specific electronic state of an atom (often one with many electrons) is designated by an atomic term symbol in electronic spectroscopy by providing the quantum numbers for the angular momenta of that atom. An atomic term symbol's shape suggests Russell-Saunders coupling. When rotated about the internuclear axis, a sigma antibonding orbital in the * orbital family likewise keeps the same phase. S is the total sum of the spin vectors of all the electrons. Although subtle, the distinction between S and Ms is crucial for comprehending multiplicity.

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Answer:

See below

Explanation:

The energy is her Potential Energy acquired by her doing work against gravity to climb up the rope ladder to the height of the zip line start.