The momentum of the car is 15030kgm/s
What is momentum?The momentum of a body is the product of the mass of the body and it's velocity. It is a vector quantity and measured in kgm/s.
Momentum is expressed as :
momentum = mass× velocity
using the relation v² = u²+2as to get the velocity of the car.
v² = 0²+2×3.5× 40
v² = 280
v = √280
v = 16.7m/s
from momentum = mass× velocity
= 900× 16.7
= 15030kgm/s
therefore the momentum of the car is 15030kgm/s
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a van of mass 2000 kg is travelling at 10 m/s calculate its kinetic energy. If its speed increases to 20m/s by how much does its kinetic energy increases
The increase in the kinetic energy was found to be 300000 J
define kinetic energy ?
The energy an item has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort while slowing down from its current pace to a condition of rest. Formally, a kinetic energy is any term that contains a derivative with respect to time in the Lagrangian of a system.
kinetic energy was mentioned as ⇒1/2(m)v^2
kinetic energy =1/2(m)v^2
=1/2x2000x(10)^2
=100000 J
=1/2(m)v^2
=1/2x2000x(20)^2
=400000 J
therefore the increase in the kinetic energy was 400000-100000=300000 J
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An exposed wiring system for indoor wet locations where walls are frequently washed must be mounted so that there is at least ----- between the mounting surface and electrical equipment.
An exposed wiring system for indoor wet locations where walls are frequently washed must be mounted so that there is at least 6 mm (1/4 in.) air gap between the mounting surface and electrical equipment.
This is to prevent water from entering the electrical equipment and causing an electrical shock. Since, the air gap provides a barrier between the wet walls and the electrical equipment and helps prevent shocks from occurring.
What is a cabling system?Is a collection of cables and associated hardware used to provide physical connectivity between two or more systems. It is also used to carry signals between computers and other network devices such as printers and modems. The cabling systems include:
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please answer this i have 20 min
Answer:
bro what is this
Question 1 options:
Speed is the rate of motion, and velocity contains a ____ of the rate of motion.
Speed is the rate of motion, and velocity contains a direction of the rate of motion, so the blank space is filled by "direction".
What is velocity?When anything is moving, its velocity tells us how quickly that something's location is changing from a certain vantage point and as measured by a particular unit of time.
If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.
Speed is only given the magnitude of the rate of motion, while velocity is given the direction of the rate of motion,
Therefore, Speed is the rate of motion, and velocity contains a direction of the rate of motion.
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If you keep a gas's temperature constant, how would you increase the volume of the gas?
a
You would change the temperature
b
You would increase the pressure
c
You would decrease the temperature
d
You would decrease the pressure
when the temperature is kept constant, to increase the volume of the gas, you will decrease the pressure (Option D)
How do I increase the volume at constant temperature?The volume of a gas at constant temperature is explained by the Boyle's law equation which is states as follow:
The volume of a fixed mass of gas is inversely proportional to the pressure at conctant temperature. Mathematically, it is expressed as follow:
P ∝ = 1/V
P = K / V
P₁V₁ = P₂V₂
Where
P₁ and P₂ are initial and new pressure V₁ and V₂ are initial and new volume
From the above formula, we can see that volume and pressure exist in inverse proportionality. This means that when the volume increases, the pressure will decrease and also, when the volume decreases, the presure will increase.
With the above information, we can conclude that the correct answer to the question is: You would decrease the pressure (Option D)
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Imagine you work as a consultant, and your daily job involves listening to the constructive criticism of others. As part of your job, you must listen to opposing viewpoints to make important decisions. In this activity, you are a consulting dam engineer. You must make a decision about four different dams; should they be repaired, taken down, or left alone? You will listen to contrasting opinions about what should be done with the dams before you make the final decision. As the consulting dam engineer, what do you decide to do with this dam? Explain your reasoning. By making your decision, did you support the opinions of the mayor and/or the dam safety official? Why or why not? (Site 1)
The primary cause of the decision-making and construction process delays is a lack of knowledge. Never criticize a teammate in front of other teammates or the manager when giving them constructive criticism.
What to do as a consulting dam engineer and how to decide?A great deal is that more information is required to portray the current structure, its background, and its make-up. They can go get another dam consulting engineer if it is too much trouble for them or if they don't like it.
However, there are a few things that are quite challenging to adhere to:
Observing how other people differ in their perspectives.observing how other people differ in their perspectives. Any of this dam's structural, meteorological, or environmental features should be taken into consideration.Taking the dam safety officer's advice into accountThe absence of information in the query is what makes all of these challenges difficult. Thus, it is clear that the main cause of the decision-making and construction process delays is a lack of knowledge.
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In 1979, Dr. Hans Liebold of Germany drove a race car 12.6 km with an average speed of 404 km/h. Suppose Liebold applied the brakes to reduce his speed. What was the car’s final speed if −3.00 MJ of work was done by the brakes? Assume the combined mass of the car and driver to be 1.00 × 103 kg
The vehicle's last speed if −3.00 MJ of work was finished by the brakes will be 398.45 km each hour.
What is the conservation of energy?
According to the principle of conservation of mass, energy cannot be gained or lost; it can only be converted from one form of energy to another. This indicates that only if energy is introduced from outside, a unit always uses the same quantity of energy.
In 1979, Dr. Hans Liebold of Germany drove a race vehicle 12.6 km with a typical speed of 404 km/h. Assume Liebold applied the brakes to decrease his speed. Expect the consolidated mass of the vehicle and driver to be 1.00 and 103 kg.
The final speed is given as,
1/2 x m [(v₂)² - (v₁)²] = 3 x 10⁶
1/2 x (1 + 103) x [(v₂)² - (404 x 18/5)²] = 3 x 10⁶
(v₂)² = 2057687.06
v₂ = 1,434.43 m/s
v₂ = 398.45 km per hour
The vehicle's last speed if −3.00 MJ of work was finished by the brakes will be 398.45 km each hour.
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As an object moves from point A to point B only two forces act on it: one force is conservative and does -70 J of work, the other force is nonconservative and does +50) of work. Between A and B, A) the kinetic energy of object decreases, mechanical energy decreases.B) the kinetic energy of object increases, mechanical energy increases. C) the kinetic energy of object increases, mechanical energy decreases D) the kinetic energy of object decreases E) mechanical energy increases
As the object moves from point A to B, the kinetic energy of the object decreases and the mechanical energy of the object increases.
In this problem, the law of energy conservation is applied. It is given that the work done by conservative force is -70J and the work done by non-conservative force is 50J.
The resulting forces between these two forces is -70J + 50J = -20 J.
The conservative force is linked with the movement caused by the sum of two energies, therefore there is a decrease in kinetic energy. The increase in mechanical energy is due to the positive non-conservative force.
Thus, the correct answer is kinetic energy of the object decreases and the mechanical energy increases.
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Please help me with this
You want to use a pendulum clock on the moon gm = 1.625 m
s2 .
a) What length should the pendulum have in order for it to have a period of T = 1.00s? [6pt.]
b) Now you need a clock for your trip into interstellar space. A pendulum clock won’t work, even while
moving with a constant velocity. Why? [3pt.]
c) You then decide to create a clock from a spring and an object with a mass m = 655g. What is the amplitude of the spring if it has a maximum velocity of vmax = 0.5ms , and a period of T = 1.00s?
[8pt.]
(a) T = 4.12 cm.
(b) T ∝ [tex]\sqrt{m}[/tex], time period doesn't depends on velocity. Thus, a pendulum clock wouldn't work.
(c) A = 0.0795 m
What is pendulum clock?Pendulum clocks were the main timekeeping devices used in 18th and 19th-century houses, industries, offices, and train stations for scheduling daily activities, shifts at work, and public transit. Their increased precision enabled the quicker pace of living required for the Industrial Revolution.
(a)
[tex]g_m[/tex] = 1.625 m/sec²
T = 1 sec
T = 2Π × [tex]\sqrt{l/g}[/tex]
or, T = 2Π × [tex]\sqrt{l/1.625}[/tex]
or, T = 1.625 × [4 × (3.19)²]
or, T = 0.0412 m
or, T = 4.12 cm.
(b)
T ∝ [tex]\sqrt{l}[/tex] and T = 2Π × [tex]\sqrt{m/k}[/tex]
or, T ∝ [tex]\sqrt{1/g}[/tex] then, T ∝ [tex]\sqrt{m}[/tex]
So, time period doesn't depends on velocity. Thus, a pendulum clock wouldn't work.
(c)
m = 655 gm = 0.655 kg
V(max) = 0.5 m/sec
T = 1 sec
A = ?
V(max) = A × ω
or, V(max) = A × (2Π/T)
or, 0.5 = A × (2Π/ 1)
or, A = 0.0795 m
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A 10.5 kg board 6.00 m long is
supported by two sawhorses, one at each end. A 4.45 kg saw sits on the board 1.80 m from the left end. Find the upward force that the LEFT sawhorse exerts on the board.
Answer: Omitting g for weigh because problem omits g
Taking torque about left sawhorse
Mr * 6 = 3 * 10.5 + 4.45 * 1.8 = 31.5 + 8.0 = 39.5
Mr = 39.5 / 6 = 6.60 mass exerted upward by right sawhorse
6.6 + Ml = 10.5 + 4.45 balancing upward and downward mass
Ml = 8.4 kg upward force (kg) exerted by left sawhorse
Check: take torque about right end
8.4 * 6 = 3 * 10.5 + 4.45 * 4.2
50.4 = 31.5 + 18.7 = 50.2 balances within rounding error
The upward force that the left sawhorse exerts on the board is 164 N.
What is meant by torque ?Torque is defined as the rotational analogue of force. It is the cross product of force and the perpendicular distance.
Here,
Mass of the board, m₁ = 10.5 kg
Length of the board, L = 6 m
Torque of the board, τ₁ = m₁g x r₁
τ₁ = 10.5 x 9.8 x (6/2)
τ₁ = 308.7 Nm
Mass of the saw, m₂ = 4.45 kg
Length of the saw, r₂ = 6 - 1.8 = 4.2 m
Torque of the saw, τ₂ = m₂g x r₂
τ₂ = 4.45 x 9.8 x 4.2
τ₂ = 183.2 Nm
So,
Torque on the left saw = Torque on the board + torque on the saw
τ' = 308.7 + 183.2
τ' = 491.9
Therefore force exerted by the left saw, F = τ'/(L/2) = 491.9/3
F = 164 N
Hence,
The upward force that the left sawhorse exerts on the board is 164 N.
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An 15-cm-long bicycle crank arm, with a pedal at one end, is attached to a 25-cm-diameter sprocket, the toothed disk around which the chain moves. A cyclist riding this bike increases her pedaling rate from 65 rpm to 91 rpm in 11 s .
A) What is the tangential acceleration of the pedal?
B)What length of chain passes over the top of the sprocket during this interval? Need units as well
The tangential acceleration and length of chain of rocket is 0.5708 and 9.4m respectively.
Any object's rotational motion experiences tangential acceleration, which is the rate at which the tangential velocity varies. When an object is moving, it behaves in a tangential direction. When an object is moving in a circle, the tangential velocity also operates in the same direction. Only when an object follows a circular path does tangential acceleration take place. In cases where the body is rotating more quickly, it is positive; in cases where it is slowing down, it is negative; and in cases where the body is rotating uniformly throughout the orbit, it is zero.Initial angular velocity, w = 65rpm = 65(rad/s = 6.594rad/s
Final angular velocity, w = 91rpm = 91(rad/s = 9.734rad/s
time taken, t= 11s
Then let total radians covered in this much time be 0 and angular acceleration be a, using equations of motion.
a). 9.734 6.59 and 0.2854rad/s
= (9.734)(6.594) +2(0.2854)/3
A=0.5708
b).Then radius of sprocket R= diameter/2= (25/2)cm E =12.5cm
Then length of chain passes over the top of sprocket in this intervalis
r= (0-12.5m)(89/ 821)
r=9.4m
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A crane lifts a crate upwards through a height of 20m. The lifted force provided by the crane is 5kN, how much work is done by the force? how much energy is transferred to the crate
The work done by the crane in lifting the crate is calculated to be 100 KJ.
How to calculate the work done when an object is on a height?Energy is transferred as a gain in the object's gravitational potential energy when work is done to increase the height of the item. Potential energy refers to the work that an object does as a result of its height. An object with mass m at a height h has a gravitational potential energy PE, which is given by the relationship:
PE = m × g × h
where,
m = mass of the object
g = gravitational force acting upon the object
h = height of the object at which it is lifted
Now, it is given that,
Force provided by the crane = mg = 5 KN = 5000 N (∵ 1kN = 1000N)
Height = 20 m
On substituting the given values in the above relation, we get:
PE = 5000N × 20m
PE = 100000 Joules or 100 kilo Joules
Hence, the work done by the crane in lifting a crate upwards is found to be 100 KJ in the form of potential energy.
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Height h = 20 m and force F = 5 kN are provided.
To Discover: Work Done, W
Work Done, as we are all aware, is the result of force and displacement. Here, we must compute the work performed by the crane in opposition to gravity.
Where,
W = mgh
The mass is m.
Gravitational acceleration, or g,
h is the height the item has gained.
mg = 5 kN for force.
1 kN = 1000 N
As a result, 5 kN equals 5*1000 N.
Replace with the value we obtain
→ W = 5000 × 20
→ W = 100000 J
→ W = 100000/1000 Kj
→ W = 100Kj
As a result, the crane's labour to raise the cargo was 100 KiloJoules.
According to work energy theorem Word Done = Energy Used
Thus, 100KJ is the required amount of Kinetic Energy required by the Crane.
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Geoff counts the number of oscillations of a simple pendulum at a location where the acceleration due to gravity is 9.80 m/s2, and finds that it takes 24.0 s for 14 complete cycles.
1) Calculate the length of the pendulum. (Express your answer to three significant figures.)
The length of the pendulum is 0.910m if acceleration due to gravity is 9.8 m/[tex]s^{2}[/tex] and it takes 24 s to go 14 cycles.
First we will calculate Time period of pendulum
T = no of oscillations/ time
= 14/24
= 0.5833
We can find length of pendulum using formula
L=g(T/2π)^2
= 9.8(0.583/2×3.14
=9.8(0.583/6.28)
= 0.910 m
A simple pendulum is an arrangement of oscillating bob that has periodic motion. The simple pendulum has a small bob of mass ‘m’ suspended by a thin string fixed to a platform and length of string is L.
The time taken to complete one oscillation is defined as the time period of the pendulum. For simple pendulum of length L , time period is T = 2π √R/2g.
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Four point charges have the same magnitude of 2.4×10^−12C and are fixed to the corners of a square that is 4.0 cm on a side. Three of the charges are positive and one is negative. Determine the magnitude of the net electric field that exists at the center of the square.
The magnitude of the net electric field at the center of the square is
5.38799 x 10^4 N/C.
What is an electric field?An electric field is described as the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.
Qa = Charge at point
A = −2.4× 10 −12C
Qb = Charge at point
B = 2.4 × 10 −12C
Qc = Charge at point
C = 2.4×10−12C
Q = Charge at point
D = 2.4 ×10−12C
a= side of the square = 4cm = 0.04 m
Ea = magnitude of the electric field at center of the square due to charge
QAEb
= magnitude of the electric field at center of the square due to charge
QBEc
= magnitude of the electric field at center of the square due to charge
QCEd
= magnitude of the electric field at center of the square due to charge
QDE x = Net electric field in X-axis.
Ey
= Net electric field in Y-axis
Magnitude of electric field at distance R due to a charge q = kx q/R^2
Where k = 8.98 X 10^9
Magnitude of net electric field in X-axis is
Ex = Ea×cos45 + Ec × cos45 +Eb × cos45 − Ed × cos45
Ex =
3.80989 × 10^4 N/C (If you substitute values)
Magnitude of net electric field in Y-axis is
Ex = Ea× Sin45 + Ec × Sin45 +Eb × Sin45 − Ed × Sin45
Ex = 5.38799 × 10^4 N/C
Therefore, the magnitude of the net electric field at the center of the square is
5.38799 x 10^4 N/C.
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Where in the image above is the mass on the spring at its equilibrium position?
At C only
At A and E
Never
At B and D
The equilibrium position from the above was the position only at the C.
define equilibrium ?
1. A situation when all acting effects are neutralised by other factors, leaving a system that is stable, balanced, or unchanging.
2. Emotional or mental equilibrium.
3. Physics The state of a body or physical system when it is at rest or moving slowly, during which all forces acting on it result in zero and all torques about all axes add up to zero.
4. Chemistry a. A chemical reaction in which both the forward and reverse reactions proceed at the same rate, preventing a change in the concentration of the reactants and products over time.
b. The condition of a system in which there are several phases and interchange between them happens at equal rates, resulting in a net loss of energy.
The sole position at the C was the equilibrium position from the above.
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someone PLEASE help me with this i need it so bad
The length of X components is 3,708 and Y component is 11,412
How to calculate X and Y components of the vector?Another method for locating vector components is to use the angle measured in the opposite direction from the +x axis. Then, the x-component will always be cos and the y-component will always be sin.
A vector's rectangular component Ax, Ay, and Az, respectively, are the projections of vector A along the x, y, and z directions. Space coordinates of a point: The triplet (x, y, z) denotes a point's coordinates.
Given ,
x-component
= 12 * cos 72
= 12 * 0,3090
= 3,708
y component
= 12 . sin 75
= 12 . 0,9510
= 11,412
Therefore The length of X components is 3,708 and Y component is 11,412
The complete question is : What are the lengths of the x and y components of this vector?
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A box moves down one ramp and up another ramp along the path shown in the image. Between which two points does the box gain potential energy as it travels?
Points 3 and 4.
Points 1 and 2.
Points 1 and 3.
Points 2 and 3.
The box gains potential energy as it travels between points 3 and 4 according to the figure.
What is potential energy?The energy held within an object is known as potential energy. There are several different types of potential energy, including gravitational potential energy, elastic potential energy, and electric potential energy.
Here, the energy that an object possesses as a result of its position in relation to other objects is referred to as its gravitational potential energy.
When the box travels from point 3 to point 4, its height increases, that's why, the box gains potential energy as it travels between points 3 and 4.
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The black hole in the galaxy M87 has a mass of about 3 billion solar masses. Let us assume that most of that mass flowed into the black hole through an acretion disk that radiated 10% of the mass-energy passing through it. (a) In that case, what would be the total amount of energy radiated by the accretion disk during the history of the black hole? (b) What would be the average luminosity (in solar luminosities) of the accretion disk, if it that energy over a period of 10 billion years? (c) How does that average huminosity compare with the luminosity of the Milky Way?
Despite being only 38 billion kilometers (24 billion miles) big, that black hole contains a mass equivalent to six and a half billion Suns. It was the first black hole that had been directly pictured.
Which black hole is in M87?We need to know the black hole's mass, brightness, and energy-radiation timescale in order to calculate the total energy emitted by the accretion disk during the course of its existence. Using Einstein's equation for general relativity, we can determine the black hole's mass.
Then, using the Stefan-Boltzmann formula, we may utilize that knowledge to determine the luminosity of the accretion disk. Finally, we may utilize that knowledge to determine how long it will emit energy given its luminosity. The entire energy emitted by the accretion disk throughout the black hole's existence comes from the mass-energy that passes through it. The accretion disk's brightness is W/m2, on average.
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a capacitor is charged at a constant charging current of 2.0 x 10^-5A. The time taken to charge the capacitor is 30s and during this time the voltage across the capacitor rises from OV to 12V. What is the capacitance of the capacitor?
Answer:
5×10-5 farads
Explanation:
Indications:
Q = charge
I = Current
t = Time
C = Capacitance
V = Voltage
Now, we know, Q = IT = 2×10^-5 ×30 = 6×10^-4 C
again, we know, Q = VC
⇒ C = Q/V = 6×10^-4/12 = 5×10^-5 Farads
Q13: Which distance P, Q, R, or S, represents the amplitude of the wave below?
Answer:
The answer is S
Explanation:
Amplitude is defined as the height of a wave from its undisturbed level.
hydrogen molecules, with a molar mass of 2.016 g/mol, in a certain gas have an rms speed of 390 m/s. a)What is the temperature of this gas, in kelvins?
The temperature of hydrogen molecules with a molar mass of 2.016 g/mol in a certain gas have an rms speed of 390 m/s in kelvins is 3.01K.
The RMS speed of gas molecules is the measure of the speed of the particles in a gas. It is the average squared velocity of molecules in a gas.
The formula for rms speed as follows
Vrms = √3*K*T / m
where
K = Boltzmann constant
T = temperature
m = mass of the gas molecules
to find T, the formula can be rearranged like this
T = m*v²rms / 3k
Now, let's find the mass of hydrogen molecules
m = molecular weight / avogadro's number
molecular weight = 2.016 g/mol
avogadro's number = 6.022 * 10^23
m = (2.016 g/mol / 6.022 * 10^23) * 10^-3 kg / mol
= 3.347 * 10^-27 kg
Next, we want to find the temperature of this gas.
T = m* v²rms / 3k
m = 3.347 * 10^-27 kg
k = 1.38 * 10^-23 J/K
Vrms = 390 m/s
T = (3.347 * 10^-27 kg) * (390 m/s)² / 3 * (1.38 * 10^-23 J/K)
= 12.3K (rounded)
Therefore, the temperature of this gas is 12.3Kelvins.
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When you paddle a boat in the water, the force of your paddle
will push the water which will apply an equal force back on
you. True or false
The paddle will experience a force from the water equal to the product of the water pressure and the paddle's surface area.
what is pressure ?
Pressure (symbol: p or P) is the force applied perpendicular to the surface of an object per unit area across which that force is distribute Gauge pressure (sometimes called gauge pressure)[a] is the pressure relative to the ambient pressure.
Various units are used to express pressure. Some of these are derived from dividing a unit of force by a unit of area; for example, the SI unit of pressure, the pascal (Pa), is one newton per square metre (N/m2); similarly, the pound-force per square inch (psi) is the conventional unit of pressure in the imperial and US customary systems. Pressure can also be stated in terms of normal atmospheric pressure; this pressure equals the atmosphere (atm).
The paddle will experience a force from the water equal to the product of the water pressure and the paddle's surface area. Any more power will only go to raise the speed of the paddle. Because of this, more water may be forced into a smaller space.
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Answer: The answer is ture
Explanation: Newtons third law which says
A circular rod of cross-sectional area 100 mm2 has a tensile force of 100 kN applied to it. The stress in the rod is:
According to the question the tensile stress of circular rod is 3142.85M Pa
What is an instance of tensile strength?The minimum tensile stress (force per unit area) required to break the material is how it is represented. The material has a tensile strength of 1,000 pounds of force, for instance, if a metal rod with a cross - sections of one square inch can bear a pulling force of 1,000 pounds but snaps with further pressure.
Briefing:
Tensile stress = Tensile load /Cross section area
Given load = 100kn = 100*10^3 = 10^5N
Area = 100πmm^2
Tensile Stress = 3142.85M Pa
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A proton moves at 4.20 x 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 7.60 * 103 N/C. Ignore any gravitational effects_ Find the time interval required for the proton to travel 4.50 cm horizontally. ns (b) Find its vertical displacement during the time interval in which it travels 4.50 cm horizontally. (Indicate direction with the sign of your answer.) mm (c) Find the horizontal and vertical components of its velocity after it has traveled 4.50 cm horizontally_ j km/s
The time interval required for the proton to travel 4.50 cm horizontally is 1.07 x 10⁻⁷ s , vertical displacement during the time interval in which it travels 4.50 cm horizontallyis 0.0043 m, and the horizontal and vertical components of its velocity after it has traveled 4.50 cm horizontally_ j km/s.
a. Let t be the amount of time needed for a proton to move 4.50 cm 0.045 m horizontally. It is calculable as follows:
t = d/v
where t is time, d is distance and v is velocity
t= d/v
t = 0.045m / 4.20 x 10⁵ m/s = 1.07 x 10⁻⁷ s
b. because the initial speed in the vertical direction is 0. So,
Thus, q E = ma.
ay= (Ey q)/m
Displacement is given by :
y=ut + 1/2ayt²
y =1/2 ((Ey q)/m) t²
y =(1/2)(7.60 x 10³ N/C x 1.67 x 10⁻¹⁹)(1.07 x 10⁻⁷)²
y= 0.0043 m
c.Use the following kinematics equation for the vertical component of velocity:
V(y)²-u²= 2ayd
[tex]v_y=\sqrt{\frac{E_{y}q}{m}d_{y} } \\v_y=\sqrt{\frac{7.60 X 10^3 N/C _{} X 1.67 x 10^{-19}}{ 1.67 x 10^{-27}} 0.045[/tex]
v=1.8493 X10⁵ m/s
velocity horizontal component,
vₓ =d/t
vₓ= 0.045/( 1.07 x 10⁻⁷ s) = 4.20 x10⁵
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you will write an application that will allow the user to calculate their body mass index (bmi) as well as calculate the user's heart rate range for varying levels of exercise intensity--also known as the karvonen formula.
The body mass index (BMI) is a measurement based on a person's mass (weight) and height.
The BMI is calculated by dividing the body weight by the square of the height, and it is expressed in kilogrammes per square meter (kg/m2) since weight is measured in kilogrammes and height is measured in meters.A table or chart that presents BMI as a function of mass and height using contour lines or colors for different BMI categories and may utilize other units of measurement can be used to calculate BMI (converted to metric units for the calculation).Based on tissue mass (muscle, fat, and bone) and height, the BMI is a practical guideline used to roughly classify a person as underweight, normal weight, overweight, or obese.To know more about body mass index
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An astronaut has landed on an unknown planet. She drops a wrench from a height of 4.07 meters above the surface. The wrench takes 4.97 seconds to fall to the surface. What is the
acceleration of gravity (in meters per second squared) on this planet? Round your answer to two decimal places.
The acceleration of gravity in the new planet is 0.41 m/s^2.
What is gravitational acceleration?
Gravitational acceleration is the acceleration that an object experiences due to the force of gravity. It is the rate at which an object's velocity changes as it falls toward the center of a gravitational field, such as the Earth or another planet.
The magnitude of gravitational acceleration is often denoted by the symbol "g," and it is equal to the acceleration an object would experience if it were dropped from rest at the surface of the Earth. On the surface of the Earth, g is approximately 9.8 meters per second squared or 1 g. However, the value of g can vary slightly depending on the location and the strength of the gravitational field. For example, g is slightly weaker at the Earth's poles than it is at the equator due to the Earth's slightly oblate shape.
According to the problem:
The acceleration due to gravity on the planet can be determined by the equation:
acceleration = (distance fallen) / (time taken)^2
Substitute 4.07 meters for the distance and 4.97 seconds for the time to determine the acceleration as the following:
acceleration = (4.07 meters) / (4.97 seconds)^2 = 0.41 m/s^2
So the acceleration of gravity on this planet is approximately 0.41 meters per second squared.
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A gas at a pressure of 2.00 atm undergoes a quasistatic isobaric expansion from 3.00 to 5.00 L. How much work is done by the gas?
The work done by the gas is 405.2 J.
What is the work done by the gas?The work done by the gas at the constant pressure is calculated by applying the following equation.
W = PΔV
W = P ( V₂ - V₁)
Where;
V₂ is the final volume of the gasV₁ is the initial volume of the gasP is the pressure of the gasThe given parameters include the following;
final volume of the gas = 5 L
initial volume of the gas = 3 L
constant pressure of the gas = 2 atm
The work done by the gas is calculated as follows;
W = 2 atm ( 5 L - 3 L )
W = 4 atm.L
1 atm.L = 101.3 J
4 atm.L = ?
= 405.2 J
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Electrical stimulation of the brain (ESB) is used on humans during brain surgery to map out ___________.
d. the brain and critical structures
Electrical stimulation of the brain (ESB) is used on humans during the brain surgery used to map out the brain and critical structures.
Surgical operation is a medical distinctiveness that makes use of operative manual and instrumental techniques on a person to research or deal with a pathological circumstance together with a disorder or damage, to help improve physical characteristics, and appearance, or to repair undesirable ruptured areas.
A patient may additionally have surgical treatment to in addition discover the situation for the motive of prognosis. cast off or repair diseased tissues or organs.
Sushruta is the father of surgical operations. If the history of science is traced back to its origin, it likely starts from an unmarked technology of ancient instances.
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Compare the wavelength of an electron traveling at a speed of 1.0* 10^7m/s with that for a ball of mass 0.10kg traveling at 35m/s
The wavelength of the electron, given that it is travelling at 1.0×10⁷ m/s is higher than that of the ball travelleing at 35 m/s
How do I compare the wavelength of the electron and ball?To compare the wavelength of both the electron and ball, we shall determin the the wavelength of both the electron and ball. Details below:
For electron:
Mass of electron (m) = 9.1×10⁻³¹ KgVelocity of electron (v) = 1.0×10⁷ m/sPlanck's constant (h) = 6.626×10⁻³⁴ JsWavelength of electron (λ) = ?λ = 2h / mv
λ = (2 × 6.626×10⁻³⁴) / (9.1×10⁻³¹ × 1.0×10⁷)
λ = 1.46×10⁻¹⁰ m
For ball:
Mass of ball (m) = 0.10 KgVelocity of ball (v) = 35 m/sPlanck's constant (h) = 6.626×10⁻³⁴ JsWavelength of ball (λ) = ?λ = 2h / mv
λ = (2 × 6.626×10⁻³⁴) / (0.10 × 35)
λ = 3.79×10⁻³⁴ m
From the above calculation we obtained:
Wavelength of electron = 1.46×10⁻¹⁰ mWavelength of ball = 3.79×10⁻³⁴ mThus, we can conclude that the the wavelength of the electron is higher than that of the ball.
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if a 0.08kg cell phone falls of a table at 15 m/s then what is its kinetic energy right before it hits the ground?
The Kinetic energy of the cell phone of mass 0.08 kg is 9 J.
What is kinetic energy?Kinetic energy is the energy of a body in motion.
To calculate the kinetic energy of the cell phone, we use the formula below.
Formula:
K.E = mv²/2............. Equation 1Where:
K.E = Kinetic energy of the cell phonem = Mass of the cell phonev = Velocity of the cell phoneFrom the question,
Given:
m = 0.08 kgv = 15 m/sSubstitute these values into equation 1
K.E = 0.08×15²/2K.E = 9 JHence, the Kinetic energy of the cell phone is 9 J.
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