A car traveling in a northeasterly direction at a rate of 50 km/h represents which of the following?
A.
deceleration
B.
velocity
C.
speed
D.
acceleration

Answers

Answer 1

Answer:

c.

Explanation:

Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector.

Formula

s = \frac{d}{t}

s = speed

d = distance traveled

t = time elapsed


Related Questions

Describe the water cycle. Be sure to include the following terms in your response: evaporation, condensation, and precipitation.your respone:

Answers

Evaporation, or turning liquid to a gas, is first. Then it goes into the atmosphere and codensates, or turns back to a liquid, these water droplets form into clouds and come down as precipitation, rain, sleet, snow etc. Then the water cycle starts again

Please I need help with this ❤️ ?

Answers

Answer:

Compound 'A' C5H12 does not react with phenyl hydrazine. Oxidation of 'A' with K2Cr2o7,/H" gives B' (c5H10o). Compound 'B' reacts with phenyl hydrazine but does not give Tollen's test. The

please someone help me understand this question ​

Answers

[tex]\\ \sf\longmapsto F=\dfrac{Gm_1m_2}{r^2}[/tex]

m1 and m2 has same units let both be m

[tex]\\ \sf\longmapsto F=\dfrac{Gm^2}{r^2}[/tex]

[tex]\\ \sf\longmapsto G=\dfrac{Fr^2}{m^2}[/tex]

SI units:-

F=Newton (N)r=metre(m)mass=m=kg

[tex]\\ \sf\longmapsto G=\dfrac{Nm^2}{kg^2}[/tex]

Option C is correct

How did Thomson's model get its name?

Answers

Answer:

thats actually a really good question. sadly i don't know the answer to it. but im sure that there are others who can!

A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) 28 kg⋅m/s 28 kilograms times meters per second 280 kg⋅m/s 280 kilograms times meters per second 70,000 kg⋅m/s 70,000 kilograms times meters per second 7,000 kg⋅m/s

Answers

The impulse of the boxers punch is 28 kgm/s.

The given parameters;

applied force by the boxer, F = 1400 Ntime of force action, t = 0.02 s

The impulse of the boxers punch is calculated as follows;

[tex]J = Ft[/tex]

where;

F is the applied force (N)t is the time of force action (s)

The magnitude of the impulse is calculated as follows;

[tex]J = 1400 \times 0.02 \\\\J = 28 \ kg m/s[/tex]

Thus, the impulse of the boxers punch is 28 kgm/s.

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If astronomers discovered a new planet and found its period of rotation around the Sun to be 105 years, how long would its semi-major axis length be as it orbited the Sun in AU?

Answers

From Kepler's third law, its semi-major axis length will be 22.2 AU approximately as it orbited the Sun in AU. The closest option is option C

Given that an astronomers discovered a new planet and found its period of rotation around the Sun to be 105 years.

According to Kepler's third law,

[tex]T^{2} \alpha r^{3}[/tex]

Where

T = Period ( in earth years) = time to complete one orbit

r = Length of the semi major axis in Astronomical unit.

[tex]T^{2}[/tex] = [tex]\frac{4\pi ^{2} }{GM} * r^{3}[/tex]

convert years to seconds

105 x 365 day x 24 hours x 3600 s

T = 3311280000 seconds

Mass of the sun M = 1.989 × 10^30 kg

G = 6.67 x [tex]10^{-11}[/tex]N m^2/kg^2

Substitute all the parameters into the formula

[tex]T^{2}[/tex] = 1.096 x [tex]10^{19}[/tex] = [tex]\frac{4\pi ^{2} }{6.67 * 10^{-11} * 1.989 * 10^{30} } * r^{3}[/tex]

1.096 x [tex]10^{19}[/tex] = 2.976 x [tex]10^{-19}[/tex] [tex]r^{3}[/tex]

[tex]r^{3}[/tex] = 1.096 x [tex]10^{19}[/tex] / 2.976 x [tex]10^{-19}[/tex]

[tex]r^{3}[/tex] = 3.68 x [tex]10^{37}[/tex]

r = [tex]\sqrt[3]{3.68 * 10^{37} }[/tex]

r = 3.33 x [tex]10^{12}[/tex] m

1 AU = 1.5 x [tex]10^{11}[/tex] m

r = 3.33 x [tex]10^{12}[/tex] / 1.5 x [tex]10^{11}[/tex]

r = 22.18 AU

Therefore, its semi-major axis length will be 22.2 AU approximately as it orbited the Sun in AU. The closest option is option C

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Answer:

C. 22.3 AU

Explanation:

Not only is the above an unnecessarily complicated answer, it's not even fully correct, and definitely not what they want you to do.

T^2 = s^3, where T = orbital period and s = semi-major axis length.

Substitute T and you get 105^2 = s^3. Solve for s.

11025 = s^3

3√11025 = s

22.25663649 = s

Therefore, the answer is C. 22.3 AU

The internal energy of a material is determined by _____.

its temperature

the kinetic energy of its molecules

the potential energy of its molecules

the combined amount of kinetic and potential energy of its molecules

Answers

The internal energy of a system is identified with the random, disordered motion of molecules; the total (internal) energy in a system includes potential and kinetic energy.

Put the waves in order from shortest to longest wavelength

Answers

Answer:

b, a, c

Explanation:

The middle one has the shortest wavelength, then it's the top one and the last one has the longest wavelength.

Initial Velocity is 27.5 m/s. Time is 42 seconds. Final Velocity is 4.5 m/s. Solve for acceleration.

Answers

Answer:

-0.5476

Explanation:

a=(Vf-Vi)/t

a=(4.5-27.5)/42

a=-0.547619047

acceleration≈-0.5476

A Person is carrying 6kg in one hand and 5kg in another.Calculate the resultant force applied by him​

Answers

I think first of all you should convert both masses to weight by
W= mg ( gravity is 9.8m/s^2)

W= (6)(9.8)= 58.8N
W= (5)(9.8)= 49N

Resultant force = 58.8-49= 9.8N

Final answer:
9.8N

I’m really sorry if the answer turned out to be wrong but I tried my best so good luck!!

Which two changes would decrease the electric force between two charged
particles?
- A. Decrease the charge of one of the particles.
B. Increase the charge of both particles.
C. Increase the charge of one of the particles.
D. Decrease the distance between the particles.
E. Increase the distance between the particles.


PLEASE HELP I KEEP FAILING!!!!

Answers

Answer:

it is b and e

Explanation:

if u look at the words twice you will notice that b and e are both saying the same meanings just in diff rent words way u need to look close on things like that and u will get passing grades

Lower chamber of Congress has how many members?

Answers

Answer:435 Representatives

Explanation:The lower chamber of Congress, in which the number of representatives per state is determined by the state's population, with 435 Representatives total. Members of the House of Representatives serve two-year terms, so they are up for reelection every two years.

A dart is thrown at a target that is supported by a wooden backstop. It strikes the backstop with an initial velocity of 350 m/s [E] The dart comes to rest in 0.0050 s.

a. What is the acceleration of the dart?
b. How far does the dart penetrate into the backstop?​

Answers

Answer:u=350m/sec

v=0m/sec

t=0.005sec

a=v-u/t

=0-350/0.005

= -350/0.005

= -350×1000/5

= -70×1000

= -70000 m/sec^2

Explanation: i think this will help you thankyou

Assertion: In domestic electric circuits, the metallic body is connected to the earth wire, which
provides a low-resistance conducting path for the current.

Reason: It ensures that any leakage of current to the metallic body of the appliance keeps its

potential to that of the earth, and the user may not get a severe electric shock. pls fast

Answers

Answer:

The answare is it ensures that any leakage of current to the metallic body of the appliance keeps its potential to that of the earth, and the user may not get a severe electric shock.

A strong weightless rope has a mass, m, hanging from the middle of it. The tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees. How much mass is hanging from the rope?​

Answers

By using Lami's theorem, Mass m = 1.75 kg approximately

Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.

By using Lami's theorem, we can get how much mass is hanging from the rope.

Let the angle between the rope = α = 180 - 40

α = 140 degrees

The angle between one of the rope and mass = β = 20 + 90

β = 110 degrees

The angle between the mass and the other rope = γ = 360 - (140 + 110)

γ = 360 - 250

γ = 110 degrees

W/ sinα = T/ sinβ = T/sinγ

W/ sinα = T/ sinβ

Substitute all the necessary parameters

W/sin140 = 25/sin 110

W / 0.643 = 25 / 0.939

W = 17.1 N

Weight W = mg

17.1 = 9.8m

mass m = 17.1/9.8

Mass m = 1.7455 kg

Mass m = 1.75 kg approximately

Therefore, 1.75 kg mass is hanging from the rope.

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An eagle flying at a constant 120 km/h and has kinetic energy of 2,800 J. What is the mass of the eagle?

Answers

Answer:

The mass of the eagle is about 5 Kg

Explanation:

1/2 M= Ke/V^2

120 km/h = 33.3333m/s

1/2 M = 2,800/33.3333^2

1/2 M = 2,800/ 1111.10888889

1/2 M = 2.52000504001

(2) 1/2 M = (2) 2.52000504h001

= M = 5.04001008002

About 5 Kilograms

The planets never travel in a straight line as they orbit the Sun. According to Newton's second law of motion, this must mean that _________. the planets are always accelerating a force is acting on the planets the planets have angular momentum the planets will eventually fall into the Sun

Answers

Explanation:

The planets never travel in a straight line as they orbit the Sun. According to Newton's second law of motion, this must mean that: Your Answer: The planets have angular momentum.'

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According to Newton's second law of motion, this must mean that force is acting on the planets. The correct option is (b).

As per Newton's second law of motion, an object's acceleration is inversely related to its mass and directly proportional to the net force exerted on it.

The curving courses of the planets in their solar system show that they are constantly changing their direction, as it causes them to accelerate.

The planets are being accelerated in the direction of the Sun as a result of the Sun's gravitational pull on them. The planets continually speed up toward the Sun due to the centripetal force required to maintain them in their orbits, which is caused by the gravitational attraction between the Sun and the planets. As a result, the planets orbit the Sun in elliptical patterns rather than in a straight line.

Hence, According to Newton's second law of motion, this must mean that force is acting on the planets. The correct option is (b).

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The complete question is:
The planets never travel in a straight line as they orbit the Sun. According to Newton's second law of motion, this must mean that _________.

(a) the planets are always accelerating

(b) a force is acting on the planets

(c)  the planets have angular momentum

(d) the planets will eventually fall into the Sun

If an input force of 202N is applied to the handles of the wheelbarrow in the sample problem how large is the output force that just lifts the load?

Answers

For this case, the relationship between the two forces is given by:

F1 = nF2

Where,

F1: output strengthF2: input forcen: mechanical advantage

Then, replacing the values we have:

F1 = (2.2)(202)

Having the calculations we have:

F1 = 444.4N

Answer: The output force that only lifts the load is F1 = 444.4N.

NEED HELP ASAP 40 POINTS L!!!! Jaden is interested in learning more about the basics of astrono ny and looking more closely at the sky all by himself. He wantS to get a basic starter telescope to help him with this endeavor, and his teacher SuggestS an organization that might be able to help him with this. What organization is Jaden's teacher likely referring to? The Little Astronomers Celestial Sightseeing Group The Beginning Astronomy Organization Astronomers Without BordersS​

Answers

The little Astronomers

True or false organisms only compete with their own species?

Answers

Answer: yes

Explanation:

Animals of different species typically compete with each other only for food, water and shelter. But they often compete with members of their own species for mates and territory as well.

The weight of a person in an elevator at rest = 500 N. Acceleration due to gravity is 9.8 m/s2. When lift accelerated, the tension force is 750 N. What is the acceleration of lift.

Answers

Answer:If the elevator accelerated downward then the tension force smallest then 500 N. Otherwise, if the elevator accelerated upward then the tension force larger then 500 N.

The tension force = 750 N because the elevator accelerated upward. Force acts upward has plus sign and force acts downward has minus sign.

T – w = m a

750 – 500 = 50 a

250 = 50 a

a = 250 / 50

a = 5.0 m s–2

Explanation:

A coin of mass 0.0050 kg is placed on a horizontal disk at a distance of 0.14 m from the center, as shown above. The coin doesn’t slip and the time it takes for the coin to make a complete revolution is 1.5 s.
A)The figure below shows the disk and coin as viewed from above. Draw and label vectors on the figure below to show instantaneous acceleration and linear velocity vectors for the pin when it is at the position shown below.
B)Determine the linear speed of the coin
C)The rate of rotation of the disk is gradually increased. The coefficient of stats if friction between the coin and the disk is 0.50. Determine the linear speed of the coin when it just begins to slip.
D)If the experiment in part c were repeated with a second, identical coin glued to the top of the first coin, how would this affect the answer to part c? Explain.

Answers

A) Figure attached below

B) The linear speed of the coin = 0.59 m/s

C) Linear speed as coin begins to slip = 0.83 m/s

D) The tangential speed will remain the same as seen in part C

Given data :

mass of coin = 0.0050 kg

Distance of coin from the center of disk = 0.14 m

Time to make a complete revolution = 1.5 s

A) Diagram showing the vectors on the figure is attached below

B) Determine the Linear speed of the coin

Linear speed of coin = 2 * π * ( 0.14 ) / 1.5

                                   = 0.59 m/s

C) Determine the linear speed of the coin when it just begins to slip

given that: friction between coin and disk = 0.50

Friction becomes maximum when coin begins to slip

Maximum frictional force (Fmax) =  uV

where V = mg

∴ Fmax = u*mg ---- ( 1 )centripetal force = [tex]\frac{mv^{2} }{r}[/tex] ---- ( 2 )

Equating equations ( 1 ) and ( 2 ) to determine the linear speed ( v )

v² = u*r*g

∴ v = √(u*r*g ) = √( 0.5 * 0.14 * 9.8 )

                        = 0.83 m/s

 

D) If the experiment is repeated with a second coin glued to the top of the first coin the tangential speed will remain the same

Hence we can conclude that The linear speed of the coin = 0.59 m/s Linear speed as coin begins to slip = 0.83 m/s , The tangential speed will remain the same as seen in part C

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An astronomical unit (A.U.) is 1 point A) a term for defining the luminosity of a star B) the average distance from the Earth to the sun C) the average distance of any given planet to the sun D) equal to a light year

Answers

Answer:

B) the average distance from the Earth to the Sun

Explanation:

An Olympic runner completes the 200-meter sprint in 23 seconds. What is the runnera''s average speed? (Round your answer to the nearest tenth of a meter per second. ) 0. 9 m/s 1. 2 m/s 8. 7 m/s 10. 1 m/s.

Answers

The average speed of the runner is 8.7m/s

Hence, Option C) 8.7m/s is the correct answer.

Given the data in the question;

Distance covered by runner; [tex]d = 200m[/tex]Time taken; [tex]t = 23s[/tex]

Average speed; [tex]s =\ ?[/tex]

Speed is simply the rate at which a particle covers a given distance. It is expressed as:

Speed = Distance / Time

[tex]s = \frac{d}{t}[/tex]

We substitute our given distance into the equation;

[tex]s = \frac{200m}{23s} \\\\s = 8.7m/s[/tex]

The average speed of the runner is 8.7m/s

Hence, Option C) 8.7m/s is the correct answer.

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A student lifts a backpack straight up with a force of 53.5 N for a distance of 0.65 m. How much work is done on the backpack?

Happy Christmas Eve!!

Answers

The answer is 34.775j because w=Fd (53.5N)(0.65m)=34.775j

Answer:

W = 34.775J

Explanation:

W = F × d

W = 53.5N × 0.65m

W = 34.775J

W = work = unknown

f = force = 53.5N

d = distance = 0.65m

How charged objects can affect other objects without touching them. ?

Answers

By gravity as well as electrostatic and magnetic attraction and repulsion
Example forces being exerted by one object on another without them being in contact with each other

Can any1 tell if my answer is right

Answers

Answer:

The correct answer would be C. 5.0kg

Explanation:

The mass of an object never changes unless parts of the object are taken away. In other words, although the gravitational force is different on the moon then on the earth the mass of the object would remain the same.

The relationship between Acceleration and Mass is described as:
O a. Equal
O b. Directly Proportional
O c. Inversely Proportional
O d. Opposite
O e. None of these

Answers

Explanation:

According to Newton's second law

[tex]\\ \sf{:}\dashrightarrow Force=Mass\times Acceleration [/tex]

[tex]\\ \sf{:}\dashrightarrow Mass=\dfrac{Force}{Acceleration}[/tex]

[tex]\\ \sf{:}\dashrightarrow Mass\propto \dfrac{1}{Acceleration}[/tex]

Option C

ONLY ANSWER IF YOU KNOW FOR SURE PLEASE :)


answer all three please, it should not take long

Answers

Answer:

Question one is b, Question two is b, and question three is b, im pretty positive that what it is

what do i do on this rubixs cube

Answers

Answer:

You solve it

Explanation:

Answer:

you just spin it and spin it and spin it                                                                                                                   and spin it                      

and spin it

and spin it

and spin it

and spin it

until you get mad then throw it at the wall

Explanation:

ya then you look up a vid that is called rubix cube meme and there should be a pink animal its funny you should watch it!!!!!!!!!

Other Questions
3(4 x 6)= (3 x 4) 6 is an example of the __________ property. A.commutative B.associative C. distributive D.inverse Dan and Lori Cole operated a Curves franchise exercise facility in Angola, Indiana, as a partnership. The firm leased commercial space from Flying Cat, LLC, for a renewable three-year term. The Coles renewed the lease for a second three-year term. Two years later, however, the Coles divorced and the partnership was dissolved. By the end of the second term, the Coles owed Flying Cat more than $21,000 on the lease. Without telling the landlord about the divorce, Lori signed another extension. More rent went unpaid. Flying Cat obtained a judgment in an Indiana state court against the partnership for almost $50,000. Can Dan be held liable? Why or why not?1. In order to form a partnership, Dan and Lori were required to:____.A. form an agreement between themselves to become a partnership B. rewrite bylaws C. conform to federal regulations D. file minutes with the appropriate office in their state (e.g., secretary of state)2. What is an important reason for Dan and Lori to form a partnership? A. to be taxed at the entity level B. to be considered a corporation under state law C. to establish joint ownership and share profits and losses D. to file articles of organization with the secretary of state.)3. Dan and Lori are _____.A. members B. partners C. shareholders of the partnership.4. Limited liability companies are creatures of ___.A. state constitutions B. statute C. case law D. secondary sources5. In order to form a limited liability company, Flying Cat would be required to file ____.A. articles of organizationB. bylaws C. regulations D. minutes with the appropriate office in their state (e.g., secretary of state))6. Generally, are limited liability companies required to include words or initials such as "limited liability company" or "LLC" as part of the company name? 7. What is an important reason for Flying Cat to form as a limited liability company? A. to be taxed at the entity level B. to be considered a corporation under state law C. to protect the members from personal liability D. to file articles of organization with the secretary of state)8. Generally, the liability of members of Flying Cat, LLC, would be limited to their respective?A. ownership interests in the company B. investments in the company C. personal assets9. Did both Dan and Lori operate the Curves franchise as a partnership?10. When Dan and Lori renewed their commercial lease for a second three-year term, were they still a partnership?11. Dan and Lori divorced ____.A. before B. after the end of the second three-year term.12. When Lori signed for another extension, did Lori or Dan tell Flying Cat about the divorce? 13. At the time of signing of the extension, it was ___.A. reasonable B. unreasonable for Flying Cat to believe that Dan and Lori remained partners in the Curves franchise.14. A court would likely find Dan ____.A. liable B. not liable for $21,000 of debt that accrued before the end of the second term.15. Would a court likely hold Dan responsible for the remaining debt that accrued after the extension signed by Lori?16. Why? Flying Cat would have _____.A. reasonably B. reasonably believed that both Dan and Lori were partners at the time the extension was signed.17. Therefore, would Dan likely be held liable by the court for the nearly $50,000 debt the partnership accrued? 18. What if the facts were different? Assume that Dan notified Flying Cat that he was no longer a partner in the partnership at the time Lori signed the extension. Would Dan likely be held liable for any debts after Lori signed the extension agreement? 19. Why? 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