A certain lever has a mechanical advantage of 5.5 how heavy of a load could the lever lift with an input force of 20.0 N

Answers

Answer 1

Answer:110N

Explanation:

ma=f in/ f out (formula)

Input: 20.0N

Ma:5.5

Output:?

^ given information

Plug the numbers into the equation ~
5.5= 20N/?
5.5x20=110N

Answer 2

If a certain lever has a mechanical advantage of 5.5, then the leaver would be able to lift a load of 110 Newtons  with an input force of 20.0 N

What is the mechanical advantage?

Mechanical advantage is defined as a measure of the ratio of output force to input force in a system, It is used to analyze the forces in simple machines like levers and pulleys.

Mechanical advantage = output force(load) /input force (effort)

As given in the problem a certain lever has a mechanical advantage of 5.5, then we have to find out how heavy of a load could the lever lift with an input force of 20.0 N,

Mechanical advantage = output force(load) /input force (effort)

5.5 = load / 20.0 Newtons

load = 5.5 × 20

       = 110 Newtons

Thus, the leaver would be able to lift a load of 110 Newtons  with an input force of 20.0 N

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This question involves the concept of the scalar product.

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Answers

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A 2.60 kg block is in equilibrium on an incline
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Answers

Answer:

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Answers

answer

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Answers

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Answer:

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Answers

Answer:

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Answers

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~Cornasha_Weeb

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Answers

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