A cone and a cylinder have the same base and height, as shown below.
The volume of the cylinder is 84 rin.3 What can be concluded about the volume of the cone? Check all that apply.
1
The volume of the cone is the volume of the cylinder.
The volume of the cylinder is 2 times the volume of the cone.
The volume of the cone is less than the volume of the cylinder.

Answer:

  0, for q ≠ 0 and q ≠ 1

Step-by-step explanation:

Assuming q ≠ 0, you want to find the value of x such that ...

  q^x = 1

This is solved using logarithms.

__

  x·log(q) = log(1) = 0

The zero product rule tells us this will have two solutions:

  x = 0

  log(q) = 0   ⇒   q = 1

If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to any power.

_____

Additional comment

The applicable rule of logarithms is ...

  log(a^b) = b·log(a)

choice (A) is correct

hope it helps

The quotient of 21.49 ÷ 3.76 using compatible numbers is approximately 5.69

Quotients are result derived from the ratio of two rational or integers. Given the expression

21.49 ÷ 3.76

Convert to fraction

21.49 ÷ 3.76 = 2140/100  ÷  376/100
21.49 ÷ 3.76 = 2140/376

21.49 ÷ 3.76 =  5.69

Hence the quotient of 21.49 ÷ 3.76 using compatible numbers is approximately 5.69

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Answer:

Step-by-step explanation:

Limits exist for:

[tex]\lim_{x \to4 \4} \frac{x^2 -x-12}{4-x}[/tex] = [tex]\frac{(x-4)(x+3)}{4-x}[/tex] = ( - 1 )( x + 3 ) = - 7

[tex]\lim_{x \to \ 2} \frac{x^2 +2x-8}{2-x}[/tex] = [tex]\frac{(x+4)(x-2)}{2-x}[/tex] = ( - 1 )( x + 4 ) = - 6

[tex]\lim_{x \to2 } \frac{x^2 +3x - 10}{x^2 -4}[/tex] = [tex]\frac{(x+5)(x-2)}{(x+2)(x-2)}[/tex] = [tex]\frac{x+5}{x+2}[/tex] = [tex]\frac{7}{4}[/tex]

For this problem, we need to use our integral knowledge to set up the problem:

The bounds will be from 2 to 6, cutting tiny horizontal bars into the graph, to approximate the area

Now for the function inside the integral:

 ⇒ it is the top function minus the bottom function

       ⇒ function within integral = x² - 0

Let's put it all together and solve:

   [tex]Area=\int\limits^6_2 {x^2-0} \, dx =\int\limits^6_2 {x^2} \, dx=\frac{6^3}{3} -\frac{2^3}{3} \\Area=\frac{6^3-2^3}{3} =\frac{216-8}{3} =\frac{208}{3}[/tex]

Answer: 208/3 ≈ 69.333

Hope that helps!

Answers:

======================================================

Explanation:

Skip to the "Work Shown" section below to see the steps for each part.

Each variable is a place holder for some unknown number. We can think of it like a box that holds a number. Luckily the letter x is found in the word "box" to help cement this line of thinking.

1x = 1 box

2x = 2 boxes

3x = 3 boxes

and so on

This shorthand notation allows us to quickly add boxes

2 boxes + 3 boxes = 5 boxes

So 2x+3x = 5x

And we can subtract boxes as well

7 boxes - 3 boxes = 7x - 3x = 4x = 4 boxes

The same number must go in box x for this to work out.

When it comes to dealing with negative numbers, it might help to use a vertical number line. I like to think of it like going up and down an elevator on a skyscraper. Negative integers represent basement levels.

It's possible to have boxes within boxes. The box A has the three boxes x-y+z inside it. So wherever we see an "A", replace it with x-y+z. Unfortunately we don't know what numbers go in the boxes for x, -y and z. Use the same type of thinking for B and C.

Don't forget to use the distributive property to distribute the negative through to each term.

Example: (x+y)-(w+z) = x+y-w-z

Many students make the mistake in saying that (x+y)-(w+z) = x+y-w+z which is not true. The +z should be -z at the very end.

Let me know if you have any other questions.

The next section below shows the steps needed to get the three answers.

----------------

Work Shown:

Part (I)

A+B+C = (x-y+z)+(2x-3y+4z)+(4x-5y-6z)

A+B+C = (x+2x+4x)+(-y-3y-5y)+(z+4z-6z)

A+B+C = 7x - 9y - z

Part (II)

A-B+C = (x-y+z)-(2x-3y+4z)+(4x-5y-6z)

A-B+C = x-y+z-2x+3y-4z+4x-5y-6z

A-B+C = (x-2x+4x)+(-y+3y-5y)+(z-4z-6z)

A-B+C = 3x - 3y - 9z

Part (III)

A+B-C =  (x-y+z)+(2x-3y+4z)-(4x-5y-6z)

A+B-C =  x-y+z+2x-3y+4z-4x+5y+6z

A+B-C = (x+2x-4x)+(-y-3y+5y)+(z+4z+6z)

A+B-C = -x + y + 11z

Answer: 3

Step-by-step explanation:

      First, we will write a mathematical equation for the phrase given.

-> Let n be "a number"

             four subtracted from twice a number is two

             four subtracted from twice a number = 2

             (twice a number) - 4 = 2

             2n - 4 = 2

      Now, we will solve this equation by isolating the variable.

             2n - 4 = 2

             2n = 6

             n = 3

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The length of the rope Kurt started with is 13 1/3 inches

From the question, we are to determine the total length of the rope

From the given information,

The first piece was 4 4/5 inches long

and

The second piece was 8 1/2 inches long

Then,

The length of the rope Kurt started with will be

4 4/5 + 8 1/2

[tex]4\frac{4}{5} + 8\frac{1}{2}[/tex]

First, convert the fractions into improper fractions

[tex]\frac{24}{5} + \frac{17}{2}[/tex]

The Lowest common multiple (LCM) of the denominators is 10.

Then, we get

[tex]\frac{(2\times 24) + (5 \times 17)}{10}[/tex]

= [tex]\frac{48 + 85}{10}[/tex]

= [tex]\frac{133}{10}[/tex]

= [tex]13 \frac{1}{3}[/tex]

Hence, the length of the rope Kurt started with is 13 1/3 inches.

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Answer:

Zero

Step-by-step explanation:

the line is not going up or down therefore there is no slope

Answer:

$18

Step-by-step explanation:

One book=$6

Two books=$12

6(price of one book)x4(four books)=24

So then it says find it for three books

So then you do $6x3 books which is $18 :)

Answer:

14 Minutes

Step-by-step explanation:

1.68 divided by 0.12 is 14 or Multiply 0.12 by 14 and you get 1.68.

The type of statistical technique that is employed in future predictions of outcomes based on presented data is: C. linear regression.

Linear regression can be described as a statistical technique that is used to make future predictions using the regression equation of a line of best fit that models the relationship between variables Y and X.

Through the regression equation, outcomes of the future can be predicted. This statistical technique is known as: C. linear regression

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Answer: you can use .5 yards of ribbon

Step-by-step explanation: this equals 18inches or 1.5 feet hope this helps

Answer:

she should get ready by 11:10

Step-by-step explanation:

Add All the time up 75(1 hour 15min=60+75)+40+25+30=170minutes

170minutes/60= 2 hour 50minutes

subtract 2 hour 50minutes from 2:00

= 11:10

Answer:

1/7

Step-by-step explanation:

Answer:

P(AUB)=P(A)+P(B)

Step-by-step explanation:

I found it somewhereI don't know?Trust me:)

Step-by-step explanation:

area of a rectangle is

length × width

so, in our case

2 2/5 km² = 1 2/5 × width (or length, it does not matter)

12/5 km² = 7/5 × width

width = 12/5 / 7/5 = 12×5 / 7×5 = 12/7 = 1 5/7 km

Answer:

I need it in English please so I can helps

Answer:

Step-by-step explanation:

The total number of bags in the bottle = 20 + 15 = 35

Then

the probability that the first bag is blue = 20/35

If we replace the first bag :

the probability that the second (picked) bag is blue = 15/35

Conclusion:

If two bags are picked at random one after the other with replacement

Then

the probability that the first bag is blue and then red is :

(20÷35)×(15÷35)

= (4÷7)×(3÷7)

= 12÷49

= 0.244897959184

Answer:

look at the photo

...................................

Answer:

252 in^3

Step-by-step explanation:

give brainliest, please!

hope this helps :)

to figure out the volume we have to multiply the base, and height together.

the base is 18 and the height is 14.

18 times 14 = 252

252 in^3

Answer:

3,024 in. 3

Step-by-step explanation:

1 foot = 12 inches

18x12x14= 3024

I just did this assignment

there you go hope it helps :)

The value of the annual premium will be $1134.40

From the information given, the annual base premium will be:

= Liability premium + Collision premium + Comprehensive premium

= $383 + $240 + $86

= $709

The annual premium will be:

= Annual base premium × Driver eating factors

= $709 × 1.60

= $1134.40

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Answer:

21 316/729

Key rules to solve:

Step-by-step explanation:

[tex]\left(\frac{2-1}{2\cdot \:7\frac{1}{3}}\right)^6[/tex]

[tex]=\left(\frac{2-1}{2\cdot \frac{22}{3}}\right)^6[/tex]

[tex]=\frac{\left(2-1\right)^6}{\left(2\cdot \frac{22}{3}\right)^6}[/tex]

[tex]=\frac{1}{\left(2\cdot \frac{22}{3}\right)^6}[/tex]

[tex]=\frac{1}{\frac{7256313856}{729}}[/tex]

[tex]\rightarrow 21 \frac{316}{729}[/tex]

Answer:

Point A

Step-by-step explanation:

Please Mark me as brainliest

Answer: point A

Step-by-step explanation:

You move two to the right and up one because the two is the x-coordinate so on the x-axis you start from (0,0) and move to the right since it’s positive. If it was negative it would be to the left. Same as when dealing with y. The y coordinate is one so you move up on the y-axis(always start from the origin which is (0,0)). If it was negative you move down. Rise/run in this case 1/2.

Answer:

x= -2, x= +11

Step-by-step explanation:

I hope this is right!

To factorise, we need two numbers that add to make -9 and multiply together to make -22.

2 - 11 works, so we put it in the brackets in this order.

(x + 2) (x - 11)

so x + 2 = 0 and x - 11 =0

but we could also simplify this to say that x could be either -2 or + 11.

I hope this helps.

Have a lovely day.

The crane is 139.8cm tall.

The angle formed by the line of sight and the horizontal plane for an object above the horizontal.

Using Trigonometry

tan 30 = h/y

1/√3 = h/y

y= h√3

and, tan 25= h/y+62

         0.96= h/(h√3 +62)

             h= 0..96 (h√3 +62)

             h= 0.96*h*1.732+0.96*62

             h=0.796h +28.52

             0.2404h= 28.52

                  h= 139.8 cm

Hence, whooping crane is 139.8 cm.

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The appropriate domain of the population function is 0 ≤ t ≤ 14

The function is given as:

P(t) = 3(2)^t

From the question, we understand that the maximum time is 2 weeks.

2 weeks in days is 14 days

This means that the function is valid for 14 days i.e. t = 0 to 14

Hence, the appropriate domain of the population function is 0 ≤ t ≤ 14

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