Answer:
This question appears incomplete
Explanation:
This question appears incomplete because of the absence of options. However, when a solid substance conducts electricity when dissolved in water (or in it's aqueous form) and has a high melting and boiling point, that substance is likely to be an electrovalent or ionic compound. This is because, ionic compounds are crystalline solids at room temperature with the properties above. Examples of ionic compounds are sodium chloride (NaCl) and potassium iodide (KI). The type of bond present in these compounds is what is referred to as the electrovalent/ionic bond.
which materials conduct heat most easily
Answer:
Metal, Copper, and Alluminum
Explanation: It is what it is
The following questions apply to the Electrophilic Aromatic Substitution (EAS) Nitration of Methyl Benzoate which yields Methyl m-Nitrobenzoate as the product:1) Draw and name the other possible EAS mono-nitration products that may be formed in addition to the desired methyl m-nitrobenzoate.2) If you perform an EAS nitration reaction with methyl m-nitrobenzoate as the reactant, which isomer is the major product? (At which ring position do you expect substitution to occur?) Draw and name the expected product.3) Suggest two ways to determine if the impure methyl m-nitrobenzoate (before recrystallization) contains other substitution products as impurities.4) Discuss differences you'd expect to see in IR, 1H and 13C NMR spectra of methyl benzoate vs. methyl m-nitrobenzoate that are consistent with the formation of the product in this procedure.
Answer:
Explanation:^^
EAS reaction has been the reaction in which the Hydrogen atom of the aromatic ring has been replaced or substituted by the electrophilic group at the ortho, para, or meta position.
1. The reaction of Nitration of methyl benzoate will yield, methyl m- nitrobenzoate as the major product.
The minor products in the reaction will be the dinitro products. The mono nitration product will be
methyl o-nitrobenzoatemethyl p-nitrobenzoate.2. The major product formed with the nitration of methyl meta nitrobenzoate has been the dinitro product.
3. The impurity in the methyl m nitrobenzoate can be determined with the determination of the melting point of the compound. The presence of the impurity will change the melting point of the product.
The purity can be determined with the proton NMR analysis, to confirm the product.
4. The difference expected in the NMR spectra of methyl benzoate and methyl m-nitrobenzoate has been the peaks with the methyl benzoate are predominated in the spectra will in the nitro compound, the peaks have been varied with the pi transitions in the structure.
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What are products of photosynthesis (2)
Answer:
Oxygen and simple sugars.
Explanation:
Water, sunlight and carbon dioxide is taken in to photosynthesise and the product would be oxygen that is breathed out through the stomata and simple sugars that are used as fuel for the plant.
James adds some magnetic marbles to a glass jar full of ordinary marbles, and then shakes up the jar.
Answer: Magnetic marbles will tend to attract each other
A 3.8-mol sample of KClO3 was decomposed according to the equation. How many moles of O2 are formed assuming 100% yield?
Answer:
5.7 moles of O2
Explanation:
We'll begin by writing the balanced decomposition equation for the reaction. This is illustrated below:
2KClO3 —> 2KCl + 3O2
From the balanced equation above,
2 moles of KClO3 decomposed to produce 3 moles of O2.
Next, we shall determine the number of mole of O2 produced by the reaction of 3.8 moles of KClO3.
Since 100% yield of O2 is obtained, it means that both the actual yield and theoretical yield of O2 are the same. Thus, we can obtain the number of mole of O2 produced as follow:
From the balanced equation above,
2 moles of KClO3 decomposed to produce 3 moles of O2.
Therefore, 3.8 moles of KClO3 will decompose to produce = (3.8 × 3)/2 = 5.7 moles of O2.
Thus, 5.7 moles of O2 were obtained from the reaction.
digital divide,cyberbullying and computer addiction are the common problems that some people encountered.what did you know about it?
Answer:
this is not chemistry
Explanation:
not chemistry
Like Earth, the moon
A rotates and waxes
B goes through a cycle of phases
Crevolves and rotates
O
Dwaxes and wanes.
Which list includes all the steps of a descriptive investigation?
O
A. Asking questions, making observations, and overcoming
limitations
a
B. Asking questions, making observations, collecting data, and
forming a conclusion
o
C. Asking questions, making observations, collecting data,
comparing, and forming a conclusion
D. Asking questions, making observations, experimenting, analyzing
data, and forming a conclusion
Answer:
i think it's C or D.
Explanation:
but if I had to choose i would pick D. sorry if it's wrong. but i hope it's right.
Answer:
D was not correct
Explanation:
The Lewis structure for ethyne (C₂H₂) shown below is incorrect. Starting from this structure, complete the correct structure.
Answer:
In drawing the Lewis structure for C2H2 (also called ethyne) you'll find that you don't have enough valence electrons available to satisfy the octet for each element (if you use only single bonds). The solution is to share three pairs of valence electrons and form a triple bond between the Carbon atoms in C2H2 .
A cook had a jar containing a sweet food and a jar containing a sour food. The image above shows the sweet and sour foods. At room temperature, both foods are liquids. The same amount of energy was transferred into both substances. Later, one of the foods had changed phase while the other had not. Which food changed phase, and how did it change? PLEASE ANSWER ASAP
Answer: One of the foods was sour and one was sweet
Explanation:
The sweet one has changed because it has more sugar then the sour one, It either got moldy or melted.
True or False some synthetics are safer than their natural counterparts
Answer:
The answer is False
hope this helpes
During a titration, 50.0 ml of 0.2M NaOH were required to neutralize 50.0ml of H3PO4. What's the concentration of the H3PO4 solution? Question 9 options: A) 0.07M B) 1.8M C) 0.6M D) 0.2M
Answer:
0.07 M
Explanation:
Given data:
Volume of NaOH = 50.0 mL
Molarity of NaOH = 0.2 M
Volume of H₃PO₄ = 50.0 mL
Concentration of H₃PO₄ = ?
Solution:
3NaOH + H₃PO₄ → Na₃PO₄ + 3H₂O
Number of moles of NaOH react:
Molarity = number of moles / volume in L
0.2 M = number of moles = 0.05 L
Number of moles = 0.01 mol
Now we will compare the moles of NaOH with H₃PO₄ .
NaOH : H₃PO₄
3 : 1
0.01 : 1/3×0.01 = 0.0033
Concentration of H₃PO₄:
Molarity = number of moles / volume in L
Molarity = 0.0033 mol / 0.05 L
Molarity = 0.07 M
Answer:
A.) 0.07M
Explanation:
I got it right in class!
Hope this Helps!! :))
how many atoms of oxygen are contained in 160 grams if N2O3?
Answer:
3.80x1024 grams containing if not that then above 80 grams 6 grams
Explanation:
Answer:
C
Explanation:
plato
3.80 x10^24
Calculate the following equation (2.55 -0.7)*4.3
Answer:
-7.6755
Explanation:
Calculate
I calculate it
The crust and upper mantle make up Earth's ____.
a. lithosphere
b. asthenosphere
c. core
d. continents
Answer:
a. the lithosphere
Explanation:
Can gravity be considered a force? Explain your reasoning
Answer:
I think that gravity can be considered a force.
Explanation:
As the object falls, it moves faster and faster. Gravity is considered a universal force because it acts between any two masses anywhere in the universe. For example, there is a gravitational pull between the Sun and the Moon. Even small masses attract one another.
Hope this helped! :)
The SI unit for pressure, the pascal (Pa), is shorthand for
A. m2
B. N/m2
c. N
The pascal is sorthand for N/m^2
What is the mass ratio and atomic ratio for cl2o7
Answer:
Mass ratio: 71:112
Atomic ratio: 2:7
Explanation:
1. To get the mass ratio of of the compound Cl2O7, the following steps are followed:
- The atomic mass of Cl = 35.5g/mol, O = 16g/mol
- The mass of each element in the compound is as follows:
Cl2 = 35.5(2) = 71g
O7 = 16(7) = 112g
The mass ratio is the ratio of one mass of an element to another in the compound, hence, the mass ratio is 71:112
- The molar mass of the compound, Cl2O7, is determined:
71 + 112 = 183g/mol
- The mass percent of each element is determined by dividing the mass of each element present by the Molar Mass:
Cl = 71/183 = 0.3879 × 100 = 38.8%
O = 112/183 = 0.612 × 100 = 61.2%
2. Atomic ratio is the ratio of one atom in a molecule to another. It can be calculated this:
In Cl2O7, there are 9 total atoms (2 atoms of Cl + 7 atoms of oxygen).
Hence, that atomic ratio of Cl to oxygen in Cl2O7 is 2:7
The mass ratio of Cl₂O₇ is 71:112 and atomic ratio of Cl₂O₇ is 2:7.
What is mass ratio and atomic ratio?Mass ratio define as the ratio of the masses of constitute particles of the compound and atomic ratio is define as the ratio of the numbers of atoms present in that compound.
Given compound = Cl₂O₇
Mass of chlorine = 2×35.5 = 71g
Mass of oxygen = 7×16 = 112g
Mass ration of Cl₂O₇ is 71:112
And atomic ratio of Cl₂O₇ is 2:7
Hence, 71:112 is the mass ratio and atomic ratio is 2:7.
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What happens when an atom becomes to gain a -1 charge it will
when an atom gains or loses an electron, it becomes an ion. Ions formed by the loss of an electron have a positive charge, and those formed by gaining an electron have a negative charge. Positive ions are called cations, and negative ions are called anions.
50.0 mL of 0.200 M HNO2 is titrated to its equivalence point with 1.00 M NaOH. What is the pH at the equivalence point?
Answer:
8.279
Explanation:
The pH can be determined by hydrolysis of a conjugate base of weak acid at the equivalence point.
At the equivalence point, we have
[tex]$n_{NaOH}=n_{HNO_2}$[/tex]
= 25.00 x 0.200
= 5.00 m-mol
= 0.005 mol
Volume of the base that is added to reach the equivalence point is
[tex]$\frac{0.005}{1.00} \times 1000= 5.00 \ mL$[/tex]
Number of moles of [tex]$NO^-_{2}=n_{HNO_2}$[/tex]
= 0.005 mol
Volume at the equivalence point is 25 + 5 = 30.00 mL
Therefore, concentration of [tex]$NO^-_{2}= \frac{5}{30}$[/tex]
= 0.167 M
Now the ICE table :
[tex]$NO^-_2 + H_2O \rightarrow HNO_3 + OH^-$[/tex]
I (M) 0.167 0 0
C (M) -x +x +x
E (M) 0.167-x x x
Now, the value of the base dissociation constant is ,
[tex]$K_w=K_a \times K_b$[/tex] [tex]$(K_w \text{ is the ionic product of water })$[/tex]
[tex]$K_b =\frac{K_w}{K_a}$[/tex]
[tex]$K_b =\frac{1 \times 10^{-14}}{4.6 \times 10^{-4}}$[/tex]
= [tex]$2.174 \times 10^{-11}$[/tex]
Base ionization constant, [tex]$K_b = \frac{\left[HNO_2\right] \left[OH^- \right]}{\left[NO^-_2 \right]}$[/tex]
[tex]$2.174 \times 10^{-11}=\frac{x^2}{0.167 -x}$[/tex]
[tex]$x= 1.9054 \times 10^{-6}$[/tex]
So, [tex]$[OH^-]=1.9054 \times 10^{-6 } \ M$[/tex]
pOH =- [tex]$\log[OH^-]$[/tex]
= [tex]$- \log(1.9054 \times 10^{-6} \ M)$[/tex]
=5.72
Now, since pH + pOH = 14
pH = 14.00 - 5.72
= 8.279
Therefore the ph is 8.279 at the end of the titration.
Titration is a chemical process used to determine the concentration of an unknown sample from the known sample. At the equivalence point, the pH is 8.279.
What is the equivalence point?In titration, the point at which the titrant neutralizes the unknown analyte solution is called the equivalence point.
The moles of equivalence point of sodium hydroxide and nitrous acid are:
[tex]\begin{aligned}\rm n_{NaOH} &= \rm n _{HNO_{2}}\\\\&= 25.00 \times 0.200\\\\&= 0.005 \;\rm mol\end{aligned}[/tex]
The volume of the added base is 5.00 mL.
The moles of nitrogen dioxide are 0.005 moles and the volume at the equivalence point is 30 mL.
The molar concentration of nitrogen dioxide will be, 0.167 M.
From the ICE table, the base dissociation constant is calculated as:
[tex]\begin{aligned}\rm K_{w} &= \rm K_{a} \times K_{b}\\\\\rm K_{b} &= \dfrac{1 \times 10^{-14}}{4.6 \times 10^{-14}}\\\\&= 2.174 \times 10^{-11}\end{aligned}[/tex]
The ionization constant of the base is given as,
[tex]\begin{aligned}\rm K_{b} &= \rm \dfrac{[HNO_{2}][OH^{-}]}{[NO_{2}^{-}]}\\\\2.174 \times 10^{-11} &= \rm \dfrac{x^{2}}{0.167- x}\\\\&= 1.905 \times 10^{-6} \end{aligned}[/tex]
Now, pOH is calculated as:
[tex]\begin{aligned} \rm pOH &=\rm - log [OH^{-}]\\\\&= \rm -log (1.905 \times 10^{-6})\\\\&= 5.72\end{aligned}[/tex]
The pH of the titration is calculated as:
[tex]\begin{aligned} \rm pH + pOH &= 14\\\\\rm pH &= 14.00 - 5.72\\\\&= 8.279\end{aligned}[/tex]
Therefore the pH is 8.27.
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7)
According to your lab procedure, identify the chemicals necessary to produce NH3(g).
Write a net ionic equation for the generation of NH3(g).
Answer:
Explanation:
Chemicals to produce NH₃ ( ammonia )
1 ) Ammonium chloride ( NH₄Cl )
2 ) Calcium hydroxide Ca(OH)₂
2NH₄Cl + Ca(OH)₂ = CaCl₂ + 2NH₃ + 2H₂O.
Net Ionic equation
2NH₄⁺ ( aq ) + 2OH⁻ (aq ) = 2NH₃(g) + 2H₂O .
Two containers, A and B, contain the same number of gas particles. Container A's particles are at a temperature of 40 C and a speed of 3 m/s. Container B's particles are at a temperature of 20 C and a speed of 1 m/s. In which container will there be greater pressure: Container A or Container B? Explain how this can be determined.
Answer:
A
Explanation:
as the temperature and speed is higher pressure will be higher
as the temperature is higher particles will be more active
and as speed is they will collide with more force
so the pressure will be higher in container B
What is the maximum amount in moles of P2O5 that can theoretically be made from 161 g of P4 and excess oxygen
Constants: A: MW = 150 g/mol; B: = MW 100 g/mol; C: MW = 200 g/mol. 2.0 g C was made from 4.5 g A and 4.0 g
a. Calculate the yield for the following reaction: 3A + B -> C
b. Calculate the yield for the following reaction: 2A + 3B -> C
c. Calculate the yield for the following reaction: A + B->3C
Answer:
a. 100%
b. 133%
c. 300%
Explanation:
To find yield first we need to determine theoretical yield converting each reactant to moles and find limitng reactant for each reaction:
Moles A:
4.5g * (1mol / 150g) = 0.03 moles
Moles B:
4.0g * (1mol / 100g) = 0.04 moles
a. For a complete reaction of 0.03 moles of A are needed:
0.03 moles A * (1 mole B / 3 moles A) = 0.01 moles of B
As there are 0.04 moles of B, A is limiting reactant.
Theoretical moles and mass of C are:
0.03 moles A * (1 mole C / 3 moles A) = 0.01 moles of C.
0.01 moles of C * (200g / mol) = 2g are produced.
Yield is:
2g / 2g * 100 = 100%
b. For a complete reaction of 0.03 moles of A are needed:
0.03 moles A * (3 mole B / 2 moles A) = 0.045 moles of B
As there are 0.04 moles of B, B is limiting reactant.
Theoretical moles and mass of C are:
0.04 moles B * (1 mole C / 3 moles B) = 0.0133 moles of C.
0.0133 moles of C * (200g / mol) = 2.67g are produced.
Yield is:
2.67g / 2g * 100 = 133%
c. For a complete reaction of 0.03 moles of A are needed:
0.03 moles A * (1 mole B / 1 moles A) = 0.03 moles of B
As there are 0.04 moles of B, A is limiting reactant.
Theoretical moles and mass of C are:
0.03 moles A * (1 mole C / 1 moles A) = 0.03 moles of C.
0.03 moles of C * (200g / mol) = 6g are produced.
Yield is:
6g / 2g * 100 = 300%
A water carbonating system is used at home and operates by providing CO2 at 5.0 atm.
Required:
a. Estimate the molar concentration of the CO2.H2O solution it produces.
b. After some weeks of use, the pressure in the water carbonating plant mentioned in the previous exercise has fallen to 2.0 atm. Estimate the molar concentration of CO2 in the carbonated water it produces at this stage.
Answer:
a. 0.17 M
b. 0.066 M
Explanation:
a.
Step 1: Given and required data
Pressure of CO₂ (P): 5.0 atm
Henry's law constant for CO₂ (k): 3.3 × 10⁻² M atm⁻¹
Step 2: Calculate the molar concentration (C) of CO₂
We will use Henry's law.
C = k × P
C = 3.3 × 10⁻² M atm⁻¹ × 5.0 atm
C = 0.17 M
b.
Step 1: Given and required data
Pressure of CO₂ (P): 2.0 atm
Henry's law constant for CO₂ (k): 3.3 × 10⁻² M atm⁻¹
Step 2: Calculate the molar concentration (C) of CO₂
We will use Henry's law.
C = k × P
C = 3.3 × 10⁻² M atm⁻¹ × 2.0 atm
C = 0.066 M
Which one of the following is not an alcohol?
A) acetone
B) glycerol
C) ethanol
D) cholesterol
E) ethylene glycol
Answer:
I think it's b because I heard the others
The correct answer is option A: acetone.
For a substance to be classified as an alcohol it must posses the -OH functional group. Compounds that posses this -OH functional group usually have the ending -ol.
Acetone is a ketone, this is evidenced by the ending -one. It has the functional group -C=O.
Hence, acetone is not alcohol. The structure of acetone is shown in the image attached.
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Which type of energy would running be?
Thermal
Light (solar)
Kinetic
Potential
Answer:
so here is the answer
Explanation:
Kinetic is the answer.
Gas A: 5 liters at 20 °C
Gas B: 5 liters at 10 °C
Gas C: 5 liters at 40 °C
Gas D: 5 liters at 30 °C
Which gas has the greatest average molecular kinetic energy?
Gas A
Gas B
Gas C
Gas D
Answer:
Gas D
Explanation:
liters at 30 °C
At a certain temperature, the solubility of aluminum hydroxide is (8.1x10^-13) M. What is the Ksp at this temperature?
Answer:
4.2x10⁻⁴ M or 0.032 g/L.
Explanation:
Hello!
In this case, for solubility product problems, we apply the concepts of equilibrium because an insoluble salt is ionized until a certain point limited by the solubility product constant, Ksp. Thus, we first write the ionization reaction of aluminum hydroxide at equilibrium:
[tex]Al(OH)_3(s)\rightleftharpoons Al^{3+}(aq)+3OH^-(aq)[/tex]
Next, we write the corresponding equilibrium expression:
[tex]Ksp=[Al^{3+}][OH^-]^3[/tex]
Which in terms of [tex]x[/tex], the reaction extent, is:
[tex]Ksp=x*(3x)^3[/tex]
Because [tex]x[/tex] also represents the molar solubility of aluminum hydroxide at the considered temperature; now, we can write:
[tex]8.1x10^{-13}=x*(3x)^3[/tex]
Which can be solved for x as follows:
[tex]x=\sqrt[4]{\frac{8.1x10^{-13}}{27} } \\\\x=4.2x10^{-4}M[/tex]
Thus, the solubility is 4.2x10⁻⁴ M or mol/L and in g/L we have:
[tex]4.2x10^{-4}\frac{mol}{L}*\frac{78g}{1mol} =0.032\frac{g}{L}[/tex]
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200.0 grams of an organic compounds known to contain 98.061 grams of carbon, 10.381 grams of hydrogen, 32.956 grams of oxygen and the rest is nitrogen. what is the empirical formula of the compound? what is the molecular formula of the compound if its molar mass is 194.101?
Answer:
1. The empirical formula is C₄H₅N₂O
2. The molecular formula is C₈H₁₀N₄O₂
Explanation:
The following data were obtained from the question:
Mass of compound = 200 g
Carbon (C) = 98.061 g
Hydrogen (H) = 10.381 g
Oxygen (O) = 32.956 g
Empirical formula =?
Molecular formula =?
Next, we shall determine the mass of nitrogen in the compound. This can be obtained as follow:
Nitrogen (N) = 200 – (98.061 + 10.381 + 32.956)
Nitrogen (N) = 200 – 141.398
Nitrogen (N) = 58.602 g
1. Determination of the empirical formula of the compound.
C = 98.061 g
H = 10.381 g
O = 32.956 g
N = 58.602 g
Divide by their molar masses
C = 98.061 /12 = 8.172
H = 10.381 /1 = 10.381
O = 32.956 /16 = 2.060
N = 58.602 /14 = 4.186
Divide by the smallest
C = 8.172 /2.060 = 4
H = 10.381 / 2.060 = 5
O = 2.060 / 2.060 = 1
N = 4.186 / 2.060 = 2
Thus, the empirical formula of the compound is C₄H₅N₂O
2. Determination of the molecular formula of the compound.
Empirical formula of the compound => C₄H₅N₂O
Molar mass of compound = 194.101 g/mol
Molecular formula =.?
[C₄H₅N₂O]n = 194.101
[(12×4) + (1×5) + (14×2) + 16]n = 194.101
[48 + 5 + 28 + 16]n = 194.101
97n = 194.101
Divide both side by 97
n = 194.101 /97
n = 2
Molecular formula => [C₄H₅N₂O]n
=> [C₄H₅N₂O]2
=> C₈H₁₀N₄O₂